Dimenzionisanje - plitko temeljenje

8/18/2019 Dimenzionisanje - plitko temeljenje

1/13

Dimenzionisanje temeljne konstrukcijeTemeljna traka (kraća strana)

Vg = 127,65 'm

kN

Vp = 25,66 'm

kN

,31,153

mkN V V V P g =+=

γ=17 KN/m3

c=3 Mpa

Φ=25〫

pretpostavimo

! = 1,2 m

DOPUŠTENA NOSIVOST TA "

( ) #i$%N&tg#ci%Nγ2

1( ccccmmγγγ$op +⋅⋅⋅⋅⋅++⋅⋅⋅⋅⋅=

22,1

5,2

3

m

kN

F

ccc

m ===

45,2;9,12269,1731,05,1

25==→=→===

°

γ φ φ

φ N N tg

F

tg tg cmm

11;4,202

===⋅= γ γ iim

kN Dq c f

0,14,01;0,12,01 =⋅−==⋅+= L

BS

L

BS c γ

0,135,00,1 =⋅+= B

Dd

f

c

( )2

29,1184,201119,1231,04,202,1m

kN dop =+⋅⋅⋅⋅⋅+=σ

O!re"i#anje $irine temelja %

&'Iteracija

2795,92252,185,029,118

m

kN D B f dopn =⋅⋅−=⋅⋅−= γ β σ σ

m B B

m N An

07,165,0

65,1795,9231,153

1 =→⋅

===σ

0,14,01;0,12,01 =⋅−===⋅+= L

BS

L

BS c γ

35,107,1

2,135,00,135,00,1 =⋅+=⋅+=

B

Dd

f

c

( )2

6,1604,20135,10,19,1231,04,202,11145,207,172

1

m

kN dop =+⋅⋅⋅⋅⋅++⋅⋅⋅⋅⋅=σ

2) *teraci+a


2/13

21,135252,185,06,160

m


m Bm N

Bn

2,113,11,135

31,153=→===

σ

135,12

07,12,1=

+= B

m

us#ojena $irina temelja &*+m

¿∑V A

=153,31

1,2=127,75 kN /m 2

$re-iva.+e visi.e teme+.e trake

0,25 1)2

1,2

0,6

(.et=127,75kN/m2

ma, -net./'0+1++2kNm1m3

38,15,135,1

=+

⋅+⋅=

p g

p g

sr V V

V V γ

M s$ = Mma %4 =16,25 1,3 =31,7 'm

kNm

=a/2 = 7,5/2=23,75

us#ojeno 4+5 cm=$8Φ/28c 99: $= 21,5cm

98,0024,0667,15,215,21120

100232

=→=⋅⋅⋅

⋅=⋅⋅

= ρ µ cd

sd sd

f d b M

;sva+a.+e armat


3/13

ptere?e.+e " 153,31 kN

Vastita [email protected] teme+a " 1,2 ∙

0,25 ∙

25= 7,5 kN

ptere?e.+a ta" 0,A5･0,A5･17= 15,3 KN

Bo$.a o>oga parket $=2 " 0,1･0)A5=0)133KN

Koris.o optere?e.+e " 0,A5･2=1,AKN

Bo$.a poCa " 0,A5･0,1･2=2,2KN

DermoiEoaci+a $=5 cm " 0,02･0,A5=0,01AKN

Feme.t.i estri $=5cm "1,05･0,A5=0,AAKN

∑V = 13,75 kN

22 6,160125,153

m

kN

m

kN

A

V


4/13

Temeljna sto8a

Vg = AA3,16 kN

Vp = 317,kN

kN V V V P g 96,1310=+=

;%VHM "

! = 1,2 m%t 3535

DOPUŠTENA NOSIVOST TA( ) #i$%N&tg#ci%Nγ

2

1( ccccmmγγγ$op +⋅⋅⋅⋅⋅++⋅⋅⋅⋅⋅=

22,1

5,2

3

m

kN

F

cc

c

m ===

45,2;9,12269,1731,0

5,1

25==→=→===

°

γ

ϕ

ϕ ϕ

φ N N tg

F

tg tg cmm

11;4,202,1172

===⋅=⋅= γ γ iim

kN Dq c f

6,04,01;2,12,01 =⋅−==⋅+= L

BS

L

BS c γ

O!re"i#anje $irine temelja&' IteracijaBretpostavimo " = 3,0 m

14,135,01 =⋅+=

B

Dd

f

c

( )2

29,1684,200,114,10,12,19,1231,04,202,10,16,045,2375,0m

kN xdop =+⋅⋅⋅⋅⋅+⋅⋅⋅⋅⋅=σ

m B B A

m N

potAn

03,318,9

;18,979,142

96,1310

1

2==→=

===σ

13,11,3

2,135,01 =+=cd

( ) 263,1674,20113,12,19,1231,04,202,116,01,3721

m

kN dop =+⋅⋅⋅⋅⋅++⋅⋅⋅⋅=σ

213,142252,185,063,167

m


m N

potAn

22,913,142

96,1310===

σ

m B B A 03,322,922

==→= us#ojeno % 2*& m

O!re"i#anje #isine temelja%


5/13

( )kNm

b BV M M II I 64,450

8

)35,01,3(96,1310

8=

−⋅=

−⋅==

( )kN

B

b BV T T II I 47,581

1,32

)35,01,3(96.1310

2=

⋅

−⋅=

⋅

−⋅==

39,15,135,1

=+

⋅+⋅=

p g

p g

sr V V

V V γ

kNm M M sr sd 38,62664,45039,1 =⋅=⋅= γ

kN T V sr sd 24,80847,58139,1 =⋅=⋅= γ

eto. F25/30

MBa67,165,1

25! c$ ==

I rmat s$r$ VV 1 .i+e potre>.a $o$at.a armat


6/13

:ontrola na8ona

1)2

0)3

3)1

Analiza opterećenja

;k


7/13

23 420 420 23

S1 S2 S1

V1=Vg18V#1=173,7381,36=1,0AkN

V2=Vg28V#2=6A,018113,6=02,7kN

∑V =2V 1+V 2=1178,65kN

¿4,2m

a= b

2+5 cm=

35

2+5=23cm

=a8ξ O ∙2=2∙ (0,23+4,2)=8,86m

( ) #i$%Ntg#ci%Nγ2

1( ccccmmγγγ$op +⋅⋅⋅⋅⋅++⋅⋅⋅⋅⋅=

26,15,2

4

m

kN

F

c

cc

m ===

9,1;1283,212968,05,1

24==→=→===

°

γ ϕ ϕ

ϕ N N tg

F

tg tg cmm

1;1 == γ iic

pretpostavimo

f D =1,2m I =1,0m

26,212,118 m

kN

Dq f =⋅=⋅= γ

95,086,8

0,14,014,01;02,1

86,8

00,12,012,01 =⋅−=⋅−==⋅+=⋅+=

L

BS

L

BS c γ

35,10,1

2,135,00,135,00,1 =⋅+=⋅+=

B

Dd

f

c

( )2

19,1616,21135,102,1122968,06,216,1195,09,10,182

1

m

kN dop =+⋅⋅⋅⋅⋅++⋅⋅⋅⋅⋅=σ

&' Iteracija


8/13

269,13525185,019,161

m


m Bm L

N B

n

198,069,13586,8

65,11781 =→=

⋅=

⋅=σ

95,086,8

14,014,01;02,1

86,8

12,012,01 =⋅−=⋅−==⋅+=⋅+=

L

BS

L

BS c γ

( )2

19,1616,21135,102,1122968,06,216,1195,09,1182

1

m

kN dop =+⋅⋅⋅⋅⋅++⋅⋅⋅⋅⋅=σ

269,13525185,019,161

m


+' Iteracija

m Bm L

N B

n

198,069,13586,8

65,11782 =→=

⋅=

⋅=σ

us#ojeno & m#isina 8resjeka us#ojena


9/13

+

+

--

41,86

214,21

550,175

41,86

214,21

550,175

T

4,81

121,24

710,35

4,81

121,24

-

+

-

M

Prora=un 8otre9ne armature

Izna! oslonca%Ms$ = 710,35 kNm

975,0032,0667,1114100

10035,71022

=→=⋅⋅

⋅=

⋅⋅= ρ µ

cd

sd

sd f d b

M

262,145,43114975,0

10035,7101

cm f d

M A

yd

sd s pot =

⋅⋅

⋅=

⋅⋅= ρ

2

min,1,140015,0

1cmd b A s =⋅⋅= us#ojeno 06 ∅18 As &5*+> cm+


10/13

U 8olju %Ms$ = 121,2kNm

992,0005,0667,1114100

10024,12122

=→=⋅⋅

⋅=

⋅⋅= ρ µ

cd

sd sd

f d b

M

246,25,43114992,0

10024,1211

cm f d

M A

yd

sd

s pot =⋅⋅

⋅=

⋅⋅= ρ

2

min,1,140015,0

1cmd b A s =⋅⋅= us#ojeno 06 ∅18 As &5*+>cm+

O!re"i#anje 8o8re=ne armature %Vs$ = 550,175kN

τ

r$ = 0,03 2cm

kN

k = 1,6 P$ = 1,69 1,1 = 0,6

0025,0120100

27,1527,15=

⋅

+= ρ

005,0min = ρ

( ) ( ),

248,220114100005,0402,146,003,0402,11 m

kN d bk V ! rd rd =⋅⋅⋅+⋅⋅=⋅⋅+⋅⋅= ρ τ

→< s$r$ VV 1 potre>.a +e $o$at.a armat


11/13

UV = 1205,05 kN

22 19,16155,154

m

kN

m

kN

A

V


12/13

45,2;9,12269,1731,05,1

25==→=→===

°

γ φ φ

φ N N tg

F

tg tg cmm

11;4,202

===⋅= γ γ iim

kN Dq c f

0,14,01;0,12,01 =⋅−==⋅+= L

BS

L

BS c γ

0,135,00,1 =⋅+=

B

Dd

f

c

( )2

29,1184,201119,1231,04,202,1m

kN dop =+⋅⋅⋅⋅⋅+=σ

O!re"i#anje $irine temelja %

&'Iteracija

279,92252,185,029,118

m


m B B

m N

Bn

05,165,0

61,1

79,92

07,150

1 =→⋅

===

σ

0,14,01;0,12,01 =⋅−===⋅+= L

BS

L

BS c γ

35,105,1

2,135,00,135,00,1 =⋅+=⋅+=

B

Dd

f

c

( )2

4,1604,20135,10,19,1231,04,202,11145,205,172

1

m

kN dop =+⋅⋅⋅⋅⋅++⋅⋅⋅⋅⋅=σ

2) *teraci+a

294,134252,185,04,160

m


m N

Bn

11,185,133

07,150===

σ

089,12

05,112,1=

+= B

m

us#ojena $irina temelja &*&m

¿∑V

A=150,07

1,1=136,42 kN /m2

$re-iva.+e visi.e teme+.e trake

0,25 1)2


13/13

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Dimenzionisanje - plitko temeljenje