Drvene konstrukcije 1Programski zadatak br 1Predmetni nastavnik:
Student: Arnel Hori (R 27/11)Doc.Dr. ana DuburZenica, novembar
2014.Univerzitet u ZeniciPolitehniki fakultetDrvene konstrukcije
1as.Dino TrtakProgramski zadatak br. 10.2H=3.5 cm ; 0.5H=8.75 cm ;
0.7H=12.25cmA= A1 + A2 + A3 = 61,25+107,187+61,25=229,687cm2Xt1=
-6,125 cmYt1= 0 cmIx1= bh312 = 3,517,5312 = 1563,155 cm4;Iy1= hb312
= 17,53,5312 = 62,526 cm4
Xt2= 0Yt2= 0Ix2=8,7512,25312 = 1340,40 cm4;Iy2= 12,258,75312 =
683,878 cm4
Xt3= 6,125 cm; Yt3= 0 cmIx3= Ix1 = 1563,155cm4Iy3= Iy1
=62,526cm4
Koordinat t!i"ta#Xt= Xt 1A1+Xt 2A 2+Xt 3A3A1+A2+A3 =
375,156+0+375,156229,687 = 0 cmYt= Yt 1A 1+Yt 2A2+Yt 3A 3A1+A2+A3 =
0 cm$omnti inrci%Ix= Ix1+ (Yt 1Yt )2& A1 + Ix2+ (Yt 2Yt )2&
A2 + Ix3+ (Yt 3Yt )2&A3 =1563,155 + (00)2&61,25 +1340,40+
(00)2& 107,187 + =
1563,155+(00)2&61,25=1563,155+1340,40+1563,155=4466,7cm4Iy=Iy1
+ (Xt 1Xt )2& A1 + Iy2+ (Xt 2Xt )2& A2 + Iy3+ (Xt 3Xt
)2&A3 =62,526+ (0+6,125)2&61,25 + 683,878 + (00)2&
107,187+ 62,526
+(0+6,125)2&61,25=2360,36+683,878+2360,36=5404,59cm4A'(i%a)ni
ot*orni momnti+x= IxYmax = 4466,78,75 = 510,48 cm3+y= IyXmax =
5404,597,875 = 686,297 cm3,o)-*r.nici inrci%ix= IxA = 4466,7229,687
= 4,409 cmiy= IyA = 5404,59229,687 = 4,851 cm0.15H=2.625cm ;
0.1H=1.75cm ; 0.8H=14cmA= A1+ A2= 36,75+26,03= 62,78 cm2 Xt1= 0 cm
Ix1= bh312 = 142,625312 = 21,10 cm4Yt1= 1,3125 cm Iy1= hb312 =
2,62514312 = 600,25 cm4Xt2= 0 cm Ix2= 1,7514,875312 = 47/,/8
cm4Yt2= -7,4375 cm Iy2= 14,8751,75312 = 6,64 cm4Koordinat
t!i"ta#Xt= 0 cmYt= 1,312536,75+(7,437526,03)A1+A2 =
48,23193,5962,78 = -2,315 cm$omnti inrci%Ix=Ix1+ (Yt 1Yt )2&A1+
Ix2+ (Yt 2Yt )2&A2= 21,10 + (1,3125+2,315)2&36,75+ 47/,/8 +
(7,4375+2,315)2& 26,03= 504,684+346,65=1667,69cm4Iy= Iy1+ ( Xt
1Xt )2& A1 + Iy2+ (Xt 2Xt )2&A2= 600,25 + (00)2&A1+
6,64 + (00)2&A2= 600,25+6,64=606,89 cm4A'(i%a)ni ot*orni momnti
,o)-*r.nici inrci%+x1= IxYmax= 1667,6912,56 = 132,778 cm3ix=
IxA=1667,6962,78= 5,15 cm+x2= IxYmax 2= 1667,694,94= 337,589 cm3+y=
IyXmax= 606,897= 86,69 cm iy= IyA=606,8962,78= 3,11 cm0.05H=0.875
cm ; 0.1H=1.75 cm A= 4&A1= 4&3,06=12,24cm2
Xt1=Xt2= -7 cm Yt1=Yt4= 7 cmXt3=Xt4= 7 cm Yt2=Yt3= -7 cm0!i"t
)i'a Xt= 0,Yt= 0 %r % )i' (imtri.an - odno(- na X i Y o(-1$omnti
inrci%#Ix1=Ix2=Ix3=Ix4= 1,751,75312= 0,781 cm4Iy1=Iy2=Iy3=Iy4=
hb312= 1,751,75312= 0,781 cm4Ix=Ix1+ (Yt 1Yt )2&A1 + Ix2+ (Yt
2Yt )2&A1+ Ix3+ (Yt 3Yt )2&A1+ Ix4+(Yt 4Yt )2&A1
=0,781+ (70)2&3,06+ 0,781+ (70)2&3,06+0,781+(70)2&
3,06+0,781+ (70)2& 3,06=602.884cm4Iy= Iy1+ ( Xt 1Xt )2&A1 +
Iy2+ (Xt 2Xt )2&A1+ Iy3+ (Xt 3Xt )2&A1+ Iy4+(Xt 4Xt
)2&A1 =0,781+ (70)2& 3,06+ 0,781+ (70)2&3,06+
+0,781+(70)2&3,06 + 0,781+ (70)23,06 =602.884 cm4A'(i%a)ni
ot*orni momnti+x=+y=IxYmax= 602.8847,875= 76,55 cm3,o)-*r.nici
inrci%ix=iy= IxA = 602.88412,24= 7,018 cm
