Bài tập_Thietke_DTCS (1)

Bi tp ln hc phn: Thit k h thng iu khin in t cng sut thng 09/2014

Bi tp c trnh by trong phm v 20 trang v sinh vin phi nh km nhim v trong bi tp ln np li

Bi tp 1: Thit k h truyn ng ng c mt chiu c tham s ch ra trong Bng 1, s dng chnh lu cu ba pha iu khin hon ton s dng Tiristor (c sn tham s ng c trong th vin simpower systems/electrical machines).

Tham s ng c mt chiu 200Hp kch t c lp

in tr phn ng Ra = 0.0597

in cm phn ng La =0.0009H

in tr phn kch t Rf = 150

in cm phn kch t Lf = 112,5H

in cm h cm Laf = 2,621

Moment qun tnh J = 5kgm2

in p kch t Uf = 150V

Tc nh mc 1750 vng/pht

in cm ni tip mch phn ng ng c

Lu =15e-3H

V3

V2

iu

V6

V5

a

b

c

V1

V4

ia

Ld

380V

/50H

z

DC CKTuu Uf

S mch lc chnh lu cu ba pha cho ng c mt chiu kch t c lp

Tnh chn mch lc.

iu khin vng h, s dung hai phng php pht xung sau y iu khin mch lc cu ba pha Tiristor.

o iu khin theo phng php xung kp (SV khng phi lm phng php ny).

o iu khin theo phng php xung chum (Tn s xung chm fx = 10kHz).

Tng hp mch vng dng in, tc m bo tc ng c bm theo tc t



Bi tp 2: Thit k b ngun dng dng chnh lu Tiristor, l u vo ca thit b bin i cho l nu thp trung tn M t: L nu thp trung tn c s dng rng ri ti Vit Nam, vi di cng sut nh t 100 n 750kW, cng sut ln c 1 n 10MW. B bin i thng dng cu trc chnh lu Tiristor cu 3 pha, cng vi cun khng mt chiu, to nn ngun dng, nghch lu cng hng ngun dng song song, tn s t 500Hz n 2400Hz (tn s thp ng di cng sut cao)

V3

V2

id

V6

V5

a

b

c

V1

V4

ia

Ld

C

Lt

Rt

ut

380V

/50H

z

S mch lc nghch lu cng hng ngun dng

S thay th tng ng b chnh lu cu ba pha to ngun ch ra nh , trong ngun sc

in ng e t th hin nh hng ca in p trn ti tc ng ngc li b chnh lu ngun

dng. Tn s ngun sc in ng e t bng 2 ln tn s in p ra (chnh lu cu Tiristor mt pha).

*

di PIG sdku Modulator

di

*

di PIG sdku

di

+-

dL

Ed r dku Ku

(a)

(b)

dL

e t

380 / 50V Hz

S thay th chnh lu cu ba pha to ngun dng



Yu cu: o Tnh chn tham s mch lc ca chnh lu cu ba pha to ngun dng cho

nghch lu cng hng, vi ti l cun dy l in cm ng vi cc tham s sau: Cng sut ti Pt = 300kW, in p nh mc trn cun dy: Ut = 800VAC v tn s lm vic l 1kHz, h s cng sut ti cos = 0,4.

o Tng hp tham s b iu khin dng in da vo s thay th 0. o M phng kim chng bng Phn mm Matlab.



Bi tp 3: Thit k b iu p xoay chiu ba pha khi ng ng c khng ng b c cng sut 215Hp, in p nh mc (pha-pha) t vo ng c 400V/50Hz, tc nh mc 1487 vng/pht (c sn tham s ng c trong th vin simpower systems/electrical machines).

IM

380V/50Hz

V1 V4 V3 V6 V5 V2

isa isb isc

S mch lc iu p xoay chiu ba pha khi ng ng c khng ng b rotor lng sc (soft

starter)

Yu cu: o Tnh chn tham s mch lc ca b iu p xoay chiu 3 pha. o Xy dng c tnh khi ng ca ng c m bo cho dng in khi ng

nm trong gii hn cho php (gii hn dng khi ng bng 3 ln dng nh mc).

o Thit k cu trc iu khin vng kn (gii hn dng khi ng bng 3 ln dng nh mc) .

o M phng kim chng bng phn mm Maltab.



Bi tp 4: Thit k cu trc iu khin b bin i Buck-Boost c thng s mch lc nh di dy:

Tham s b bin i Boost

in p uin = 24V, in p ra uo = 48V in cm L = 62H T in C = 300F v rC = 0,187 Tn s pht xung fx = 100kHz. Cng sut 100W

C

rC

iL

D

V

uouin

uc

L

B bin i Buck

C

rC

DVuo

iL

uin

uc

D

B bin i Boost

R R

C

rC

L

V

uouin

uc

D

R

B bin i Buck-boost

iL

S mch lc b bin i Boost

Yu cu: 1. Xy dng m hnh tn hiu trung bnh ca cc b bin i Boost 2. Thit k cu trc iu khin cho b bin i trn theo 2 ch :

a. iu khin in p. b. iu khin dng in (iu khin dng in nh v iu khin dng in

trung bnh). 3. Kim chng kt qu m hnh ha v thit k bng phn mm Matlab



Bi tp 5: Thit k cu trc iu khin b bin i Buck-Boost c thng s mch lc nh di dy:

Tham s b bin i Buck-Boost

in p uin = 24V, in p ra uo = 15V in cm L = 100H T in C = 697F v rC = 0,01 Tn s pht xung fx = 100kHz. Cng sut 100W

C

rC

iL

D

V

uouin

uc

L

B bin i Buck

C

rC

DVuo

iL

uin

uc

D

B bin i Boost

R R

C

rC

L

V

uouin

uc

D

R

B bin i Buck-boost

iL

S mch lc b bin i Buck-Boost

Yu cu: 1. Xy dng m hnh tn hiu trung bnh ca cc b bin i Boost 2. Thit k cu trc iu khin cho b bin i trn theo 2 ch :

a. iu khin in p. b. iu khin dng in (iu khin dng in nh v iu khin dng in

trung bnh). 3. Kim chng kt qu m hnh ha v thit k bng phn mm Matlab



Bi tp 6: Thit k cu trc iu khin cho b bin i PFC c tham s nh sau:

in p u vo xoay chiu (RMS) Us,rms = 220V

Tn s li in f= 50Hz

in p u ra b PFC 400V

Cng sut thit k 250W

Tn s switching fs = 100 kHz

T in u ra C = 220 F rC = 100m

Gi tr in cm L = 1mH

ud

L

L

ins

uu

su

di

C R

su

si

Li

Lisi

C ou

1 :1d t

Li di

R

su

Li

ud

d t

t

t

a)

b)

c)

d)

ins

uu

S mch lc b bin i PFC

Yu cu: o Tnh chn mch lc.

o Thit k mch vng dng in va mch vng in p theo mc (Theo ni dung trong bi ging)

o Tnh ton khu b in p u vo (Feedforward voltage). o M phng bng phn mm Matlab kim chng kt qu thit k.



Bi tp 7: Thit k cu trc iu khin cho nghch lu c lp ngun p mt pha c cng sut 2kVA lm vic ch chnh lu tch cc.

Tham s s mch lc nghch lu ngun p mt pha

Lng t in p mt chiu trn t Cdc Udc = 400V

Tham s in cm pha li Ls = 2mH

Tn s pht xung mch nghch lu 5kHz

S1 S3

S2S4

Cdc

a)

Ls

220V/

50Hzis

UdcTi

Li in

S mch lc nghch lu c lp ngun p mt pha lm vic ch chnh lu tch cc

Yu cu: 1. Tnh chn mch lc 2. Thit k khu iu ch rng xung theo phng php n cc. 3. Tng hp mch vng iu khin dng in theo kiu PI v PR (bi ging) 4. Tng hp mch vng in p Udc 5. M phng bng phn mm Matlab kim chng kt qu thit k.



Bi tp 8: Thit k cu trc iu khin cho nghch lu c lp ngun p mt pha c cng sut 2kVA lm vic ch cp ngun.

Tham s s mch lc nghch lu ngun p mt pha

in p mt chiu t vo mch nghch lu Udc = 400V

Tham s b lc LC Lf = 0,7mH Cf = 40 F


Lng t in p trn ti Ut(RMS) = 220V f = 50Hz

S1 S3

S2S4

Cdc

Lf

isUdc

Cf Ti

S mch lc nghch lu c lp ngun p mt pha lm vic ch c lp

Yu cu: 1. Tnh chn mch lc 2. Thit k khu iu ch rng xung theo phng php n cc. 3. Tng hp mch vng iu khin dng in theo kiu PI v PR (bi ging) 4. Tng hp mch vng in p trn ti. 5. M phng bng phn mm Matlab kim chng kt qu thit k.



Bi tp 9: Thit k cu trc iu khin cho nghch lu c lp ngun p ba pha c cng sut 5kVA lm vic ch chnh lu tch cc

Tham s s mch lc nghch lu ngun p ba pha

Lng t in p mt chiu trn t Cdc Udc = 700V

Tham s in cm pha li Ls = 2mH


S1 S3 S5

S2S6S4

Cdc

b)

Ls

isUdc

Ti

Li in

380 / 50V Hz

S mch lc nghch lu c lp ngun p mt pha lm vic ch chnh lu tch cc

Yu cu: 1. Tnh chn mch lc 2. Thit k khu iu ch rng xung theo nguyn l iu ch vector khng gian. 3. Thit k mch vng iu khin dng in theo nguyn l iu khin vector dng in is (la chn iu khin theo cu trc PR trn h ta tnh hoc PI trn h ta quay dq) . 4. Tng hp mch vng in p Udc 5. M phng bng phn mm Matlab kim chng kt qu thit k.



Bi tp 10: Thit k cu trc iu khin cho nghch lu c lp ngun p ba pha c cng sut 5kVA lm vic ch cp ngun.

Tham s s mch lc nghch lu ngun p ba pha

in p mt chiu t vo mch nghch lu Udc = 700V

Tham s b lc LC Lf = 0,7mH Cf = 40F


Lng t in p trn ti (pha-pha) Ut(RMS) = 380V f = 50Hz

S1 S3 S5

S2S6S4

Cdc

b)

Lf

isUdc

Cf

Ti

S mch lc nghch lu c lp ngun p ba pha lm vic ch c lp

Yu cu: 1. Tnh chn mch lc 2. Thit k khu iu ch rng xung theo phng php n cc. 3. Thit k mch vng iu khin dng in theo nguyn l iu khin vector dng in is (la chn iu khin theo cu trc PR trn h ta tnh hoc PI trn h ta quay dq). 4. Thit k mch vng iu khin in p trn ti theo nguyn l iu khin vector in p us (la chn iu khin theo cu trc PR trn h ta tnh hoc PI trn h ta quay dq). 5. M phng bng phn mm Matlab kim chng kt qu thit k.

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Bài tập_Thietke_DTCS (1)