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statika 1
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STATIČKI PRORAČUN
ČVOR A
∑ Y = 0 ∑ X = 0S2 x sin 23.96 = YA – 9 S2 x cos 23.96 = S1
S2 = 110.80 kN S1 = 101.25 kN
ČVOR 1
∑ X = 0 ∑ Y = 0S3 = S1 = 101.25 kN S9 = 0 kN
ČVOR 2
∑ X = 0S2 x cos 23.96 - S5 x cos 23.96 - S4 x cos 23.96 = 0S5 = S2 - S4 → S5 = 88.64 kN∑ Y = 0S2 x sin 23.96 - S5 x sin 23.96 + S4 x sin 23.96 - 18 = 02 x S4 = 44.32S4 = 22.16 kN
ČVOR 3
∑ Y = 0 ∑ X = 0S4 x sin 23.96 - S10 = 0 S3 - S4 x cos 23.96 - S6 = 0S10 = 9 kN S6 = 81 kN
ČVOR 4
∑ X = 0S5 x cos 23.96 - S8 x cos 23.96 - S7 x cos 41.63 = 0S8 = S5 - S7 → S8 = 66.48 kN∑ Y = 0S5 x sin 23.96 + S7 x sin 41.63 - S8 x sin 23.96 - 18 - S10 = 0S7 x ( sin 41.63 + sin 23.96 ) = 18 + 9S7 = 27.09 kN
ČVOR 5
∑ X = 0S8 x cos 23.96 - S12 x cos 23.96 = 0S12 = 66.48 kN∑ Y = 018 + S11 - S8 x sin 23.96 - S12 x sin 23.96 = 0S11 = 36 kN
Zbog simetričnosti sile u ostalim štapovima suvišno je računati, pa ćemo ih prepisati.