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From the reaction curve, we know that our process model is in the form of first order plus time delay (FOPTD); where You have to find K, τ and θ given in the questionYou have to find
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SOLUTIONS
ERT 321Process Control & Dynamics
Anis Atikah binti Ahmad
EXERCISE 3
In this question, a model is not given. Thus, we have to develop a process model from the experimental data.
Time (min) T2m(mA)
0 131 132 13.54 166 16.68 16.9
10 1712 1714 17
At time = 1 min, there is no change in temperature data. Thus, we know that time delay term should be included in our model.
From the reaction curve, we know that our process model is in the form of
first order plus time delay (FOPTD);
where
0 2 4 6 8 10 12 14 1613
13.5
14
14.5
15
15.5
16
16.5
17
17.5
T2m
Time
min6.1 min0.36.16.4
1~
sKeG
s
mpvIP KKKKK pmKKpsipsimApsi 9.075.0
You have to find K, τ and θ
given in the question You have to find
psimApsimAKK mp 2
16181317
mpvIP KKKKK mpKKpsipsimApsi 9.075.0
Process output (Temperature, ° C)
Process input (Pressure, psi)
pK mKTransmitter output (Temperature, mA)
Transmitter input (Temperature, °C)
mp KKProcess output (Temperature, ° C)
Process input (Pressure, psi)
Transmitter output (Temperature, mA)
Transmitter input (Temperature, °C)
Transmitter output (Temperature, mA)
Process input (Pressure, psi)
mpvIP KKKKK
psimApsipsimApsi
161813179.075.0
13
35.1 6.1
sesG
s
35.1
Thus,
12
cKK 916.0586.0
772.036.1586.035.11 916.0
cK
I 165.003.1
min18.336.1165.003.1
3
I
(a)ITAE (setpoint change)From ITAE Performance Index Table,
PI controller
(b) Direct Synthesis method with τc= τ/3From Table 12.1,
c
cKK min3 I
85.06.11
335.111
cc KK
PI controller
(c) Ziegler Nichols
01 GGc
13
35.1 6.1
sesG
s
013
35.116.1
seG
s
c
013
35.116.1
seK
s
c
01 OLG
1. Use characteristic equation.
2. Use proportional only controller, Gc= Kc
Using 1/1 Padé Approximation, substitute e-1.6s = into (1) s
s26.1126.11
(1)
013
35.116.1
seK
s
c
08.018.01
1335.11
ss
sKc
Substituting and
08.0135.18.0113 sKss c
008.135.18.014.23 2 sKKsss cc
035.1108.18.34.2 2 cc KsKs
cuc KK js u
0035.1108.18.34.2 2 jKjK cuucuu Equating imaginary and real coefficients;
008.18.3 ucuK 035.114.2 2 cuu K
52.3cK min548.1 radu
Direct substitution method
min06.42
uuP
584.152.345.045.0 cuc KK
min38.32.106.42.1 uI P