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SOLUTIONS ERT 321 Process Control & Dynamics Anis Atikah binti Ahmad EXERCISE 3

SOLUTIONS ERT 321 Process Control & Dynamics Anis Atikah binti Ahmad EXERCISE 3

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From the reaction curve, we know that our process model is in the form of first order plus time delay (FOPTD); where You have to find K, τ and θ given in the questionYou have to find

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Page 1: SOLUTIONS ERT 321 Process Control & Dynamics Anis Atikah binti Ahmad EXERCISE 3

SOLUTIONS

ERT 321Process Control & Dynamics

Anis Atikah binti Ahmad

EXERCISE 3

Page 2: SOLUTIONS ERT 321 Process Control & Dynamics Anis Atikah binti Ahmad EXERCISE 3

In this question, a model is not given. Thus, we have to develop a process model from the experimental data.

Time (min) T2m(mA)

0 131 132 13.54 166 16.68 16.9

10 1712 1714 17

At time = 1 min, there is no change in temperature data. Thus, we know that time delay term should be included in our model.

Page 3: SOLUTIONS ERT 321 Process Control & Dynamics Anis Atikah binti Ahmad EXERCISE 3

From the reaction curve, we know that our process model is in the form of

first order plus time delay (FOPTD);

where

0 2 4 6 8 10 12 14 1613

13.5

14

14.5

15

15.5

16

16.5

17

17.5

T2m

Time

min6.1 min0.36.16.4

1~

sKeG

s

mpvIP KKKKK pmKKpsipsimApsi 9.075.0

You have to find K, τ and θ

given in the question You have to find

Page 4: SOLUTIONS ERT 321 Process Control & Dynamics Anis Atikah binti Ahmad EXERCISE 3

psimApsimAKK mp 2

16181317

mpvIP KKKKK mpKKpsipsimApsi 9.075.0

Process output (Temperature, ° C)

Process input (Pressure, psi)

pK mKTransmitter output (Temperature, mA)

Transmitter input (Temperature, °C)

mp KKProcess output (Temperature, ° C)

Process input (Pressure, psi)

Transmitter output (Temperature, mA)

Transmitter input (Temperature, °C)

Transmitter output (Temperature, mA)

Process input (Pressure, psi)

Page 5: SOLUTIONS ERT 321 Process Control & Dynamics Anis Atikah binti Ahmad EXERCISE 3

mpvIP KKKKK

psimApsipsimApsi

161813179.075.0

13

35.1 6.1

sesG

s

35.1

Thus,

Page 6: SOLUTIONS ERT 321 Process Control & Dynamics Anis Atikah binti Ahmad EXERCISE 3

12

cKK 916.0586.0

772.036.1586.035.11 916.0

cK

I 165.003.1

min18.336.1165.003.1

3

I

(a)ITAE (setpoint change)From ITAE Performance Index Table,

PI controller

Page 7: SOLUTIONS ERT 321 Process Control & Dynamics Anis Atikah binti Ahmad EXERCISE 3

(b) Direct Synthesis method with τc= τ/3From Table 12.1,

c

cKK min3 I

85.06.11

335.111

cc KK

PI controller

Page 8: SOLUTIONS ERT 321 Process Control & Dynamics Anis Atikah binti Ahmad EXERCISE 3

(c) Ziegler Nichols

01 GGc

13

35.1 6.1

sesG

s

013

35.116.1

seG

s

c

013

35.116.1

seK

s

c

01 OLG

1. Use characteristic equation.

2. Use proportional only controller, Gc= Kc

Using 1/1 Padé Approximation, substitute e-1.6s = into (1) s

s26.1126.11

(1)

Page 9: SOLUTIONS ERT 321 Process Control & Dynamics Anis Atikah binti Ahmad EXERCISE 3

013

35.116.1

seK

s

c

08.018.01

1335.11

ss

sKc

Substituting and

08.0135.18.0113 sKss c

008.135.18.014.23 2 sKKsss cc

035.1108.18.34.2 2 cc KsKs

cuc KK js u

0035.1108.18.34.2 2 jKjK cuucuu Equating imaginary and real coefficients;

008.18.3 ucuK 035.114.2 2 cuu K

52.3cK min548.1 radu

Direct substitution method

Page 10: SOLUTIONS ERT 321 Process Control & Dynamics Anis Atikah binti Ahmad EXERCISE 3

min06.42

uuP

584.152.345.045.0 cuc KK

min38.32.106.42.1 uI P