Proracun prelaznih krivina

I – Krivina R=60m V=40km/h A=35 α=700

Lpk= A2

R=352

60=20,42m

τ= Lpk2∗R

=20,422∗60

=9,1890

Lkk= Rπ180

(α−2 τ ¿=60 π180

(700−2∗9,189)=45,05m

∆ R= Lpk2

24∗R= 20,422

24∗60=0,289m

B = (R+∆ R ¿(secα2−1¿+∆R=¿

(60+0,289 )(sec 702

−1)+0,289=13,59m

d= Lpk2

− Lpk3

240∗R2=20,42

2− 20,423

240∗602=10,21m

Tg=(R+∆ R ) tg α2+d=(60+0,289 ) tg 70

2+10,2=52,41m