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Algebra JeopardyKristina Anderson
March 25, 2009
EXIT
Factor Simplify Find x Potpourri
100 100 100 100
200 200 200 200
300 300 300 300
400 400 400 400
What is the factored form of…
121 77x
SOL A.12
11(11 – 77x)
11(11 – 7x)
11(11 + 7x)
–11(11 + 7x)
0% 0%0%0%
A. 11(11 – 77x)B. 11(11 – 7x) C. 11(11 + 7x)D. –11(11 + 7x)
What is the factored form of…
–7(4x + 3)
–7(4x + 21)
7(4x + 3)
–7(4x – 3)
0% 0%0%0%
28 21x A. –7(4x + 3)B. –7(4x + 21) C. 7(4x + 3)D. –7(4x – 3)
SOL A.12
What is the factored form of…
x2(5x – 1)
x2(5x + 1)
x2(5x + x)
x2(5x – x)
0% 0%0%0%
SOL A.12
A. x2(5x – 1) B. x2(5x + 1)C. x2(5x + x)D. x2(5x – x)
5x3 – x2
What is the factored form of…
6x(4x + 9)
6x(–4x – 9)
6x(–4x + 9)
6x(4x – 9)
0% 0%0%0%
SOL A.12
–24x2 + 54x A. 6x(4x + 9)B. 6x(–4x – 9)C. 6x(–4x + 9)D. 6x(4x – 9)
What is the simplified form of…
20x – 8
–20x – 8
–9x – 2
20x – 2
0% 0%0%0%
SOL A.3
–4(–5x + 2) A. 20x – 8B. –20x – 8 C. –9x – 2 D. 20x – 2
What is the simplified form of…
–18x – 11
–18x – 33
–3x – 11
–3x – 33
0% 0%0%0%
SOL A.3
–6(3x + 4) – 9 A. –18x – 11 B. –18x – 33 C. –3x – 11 D. –3x – 33
What is the simplified form of…
3x + 17
–22x + 6
3x + 6
–22x + 17
0% 0%0%0%
SOL A.3
6x + 4(5 – 7x) – 3A. 3x + 17 B. –22x + 6 C. 3x + 6 D. –22x + 17
What is the simplified form of…
5x + 47
12x + 32
–2x + 31
5x + 31
0% 0%0%0%
SOL A.3
3(9 – 2x) + 5(3x + 4) – 4x
A. 5x + 47 B. 12x + 32 C. –2x + 31 D. 5x + 31
Solve the equation for x…
1 –3 3 9
0% 0%0%0%
SOL A.1
–3(4 + 2x) = 6A. 1B. –3 C. 3 D. 9
Solve the equation for x…
–29 –2
1 23/35 2
0% 0%0%0%
SOL A.1
7(–5x + 2) – 5 = –61
A. –29 B. –2 C. 58/35 D. 2
Solve the equation for x…
15/2 12.5 0 2
0% 0%0%0%
SOL A.1
–6x + 4(x – 5) = –20A. 15/2B. 12.5C. 0D. 2
Solve the equation for x…
5
–38/13 1
–12/13
0% 0%0%0%
SOL A.1
–6(4 – 2x) + 5(–x + 2) = 21
A. 5B. –38/13C. 1D. –12/13
What is the simplified form of…
4x + 56
4x + 7
4x – 7
–4x – 56
0% 0%0%0%
SOL A.11
32 568x
A. 4x + 56B. 4x + 7C. 4x – 7D. –4x – 56
Evaluate the following…
10 –2 1 –9
0% 0%0%0%
SOL A.3
6 45 2 5
A. 10B. –2 C. 1D. –9
The line –3x + 3y = 12 is equal to…
y = x + 4
y = –x – 4
y = x – 4
y = 3x +
4
0% 0%0%0%
SOL A.1
A. y = x + 4B. y = –x – 4 C. y = x – 4D. y = 3x + 4
The equation of the line through (2,4) and m= –3 is _________.
y = –3x + 4
y = –3x + 10
y = –3x + 2
y = –3x – 10
0% 0%0%0%
SOL A.8
A. y = –3x + 4B. y = –3x + 10 C. y = –3x + 2D. y = –3x – 10
