of 10 /10
Rešenje: 1. a) ( ) ( ) o o 41 . 57 cos arcsin 46 . 76 arcsin 2 1 1 2 = = = = θ α θ n n n m c b) ( ) o 94 . 71 2 cos 2 cos arctan 2 arctan 2 1 2 2 1 2 2 2 1 = = = β π β π γ φ n n n n k E 33 . 3 sin 2 sin 2 tan 1 2 2 1 = = c s n Z θ β π β π π λ c) ( ) 91 . 6 2 4 2 cos 2 cos arctan 2 2 tan 1 2 2 1 2 2 2 1 = + = = π β π β π γ n n n n kd k kd 015 . 5 2 tan 2 2 = = kd kd d γ 891 . 0 = Γ 2. a) OT2_talasovodi_09.pdf, slajdovi 6, 10 b) OT2_talasovodi_09.pdf, slajd 22 c) OT3_opticka_vlakna_09.pdf, slajdovi 19, 25, 26 d) OT2_opticka_vlakna_09.pdf, slajd 37 3. a) GHz L d f v tot s gr 46 . 3 187 . 0 = = σ

Ispitni Rokovi 2008 2011-Ispit-Opticke Telekomunikacije-Telekomunikacije 3 PDF

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  • Reenje:

    1.

    a)

    ( )( ) o

    o

    41.57cosarcsin

    46.76arcsin

    21

    1

    2

    ==

    =

    =

    n

    n

    n

    m

    c

    b)

    ( )o

    94.71

    2cos

    2cos

    arctan2arctan2

    1

    22

    1

    2

    2

    2

    1

    =

    =

    =

    n

    nnn

    kE

    33.3

    sin2

    sin

    2tan

    1

    221

    =

    =

    c

    s

    n

    Z

    c)

    ( )91.6

    24

    2cos

    2cos

    arctan22

    tan

    1

    22

    1

    2

    2

    2

    1

    =+

    ==

    n

    nnnkd

    k

    kd

    015.52

    tan22

    =

    =kdkdd

    891.0=

    2. a) OT2_talasovodi_09.pdf, slajdovi 6, 10 b) OT2_talasovodi_09.pdf, slajd 22 c) OT3_opticka_vlakna_09.pdf, slajdovi 19, 25, 26 d) OT2_opticka_vlakna_09.pdf, slajd 37

    3.

    a) GHzLd

    fvtots

    gr 46.3187.0

    ==

  • b)

    216

    318

    1

    1017.1

    67.1

    104.1

    28.164

    cmdn

    dg

    ps

    cmn

    cmg

    p

    th

    th

    =

    =

    =

    =

    c) ( ) 12

    0

    1

    +

    =

    p

    pp

    pppj

    qdJ

    ( ) ( )

    ( )314

    2

    22

    1047.232

    2412=

    = cm

    f

    ff

    pgr

    pgr

    p

    pgr

    p

    2

    0/183.3 cmkAJ =

    d) nstd 21.2=

    4.

    a) OT4_disperzija_09.pdf, slajd 21 b) OT4_disperzija_09.pdf, slajdovi 26, 27 c) OT4_disperzija_09.pdf, slajd 30 d) OT4_disperzija_09.pdf, slajd 29 e) OT5_izvori_09_deo3.pdf, slajdovi 4, 5

    5. a) kmLmaz 017.35=

    b) kmLmaz 691.24=

    c) dBm

    kmL

    61.12

    24

    =

    =

    d) 91029.1 =BER e) dB3=

    6. a) OT6_fotodetektori_09.pdf, slajdovi 4, 7, 8 b) OT6_fotodetektori_09.pdf, slajd 10 c) OT6_fotodetektori_09.pdf, slajd 33 d) OT6_prijemnici_09.pdf, slajdovi 6, 7, 8 e) OT6_prijemnici_09.pdf, slajdovi 9, 10 f) OT6_izvori_09_deo3.pdf, slajdovi 25, 26

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