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Group Work 1. A 10-kg box slides on a level floor. a. Make a force diagram for it. b. What is its weight? c. Its coefficient of kinetic (sliding) friction against the floor is k = 0.5. What is the force of friction between box and floor? d. What is the acceleration of the box? 2. What would the answer to d be if the box’s mass were 20 kg?

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Group Work. A 10-kg box slides on a level floor. Make a force diagram for it. What is its weight ? Its coefficient of kinetic (sliding) friction against the floor is m k = 0.5 . What is the force of friction between box and floor? What is the acceleration of the box? - PowerPoint PPT Presentation

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Page 1: Group Work

Group Work

1. A 10-kg box slides on a level floor.a. Make a force diagram for it.

b. What is its weight?

c. Its coefficient of kinetic (sliding) friction against the floor is k = 0.5. What is the force of friction between box and floor?

d. What is the acceleration of the box?

2. What would the answer to d be if the box’s mass were 20 kg?

Page 2: Group Work

Announcements

• Exam 1 on Moodle today– Opened 6 AM– Closes midnight

• 1.5-hour time limit

• Open-note, open-book, etc.

• No consultation or collaboration permitted

Page 3: Group Work

Momentum

the quantity of motion

Page 4: Group Work

Objectives

• Define momentum.

• Define impulse and describe its relationship to momentum.

Page 5: Group Work

What’s the point?

• Nature keeps careful account of momentum.

Page 6: Group Work

Think Question

Which process requires more time?

A. Pulling as hard as you can to accelerate a little red wagon from rest to a speed of 1 m/s.

B. Pulling as hard as you can to accelerate a horse trailer from rest to a speed of 1 m/s.

C. The two take the same amount of time.

Page 7: Group Work

Think Question

Which process requires more force?

A. Accelerating a little red wagon from rest to a speed of 1 m/s in ten seconds.

B. Accelerating a horse trailer from rest to a speed of 1 m/s in ten seconds.

C. The two take the same force.

Page 8: Group Work

Example Problem

Show that when a constant net force F is applied to an object of mass m for a time t, its change in velocity is

Strategy: We can find acceleration using Newton’s second law a = F/m. Then we can find v using the definition of acceleration a = v/t.

v = Ftm

Page 9: Group Work

Group Work

3. From mass m, net force F, and duration t, find acceleration a and velocity change v.

1 kg 10 N 1 s

1 kg 10 N 10 s

1 kg 1 N 10 s

10 kg 10 N 10 s

m F t va J p

Page 10: Group Work

Impulse

where

t is duration

F Is net force

Impulse is a vector.

Impulse = Ft

Page 11: Group Work

Think Question

Two objects of different masses move at the same speed. Which one is harder to stop?

A. The lighter object.

B. The more massive object.

Page 12: Group Work

Think Question

Two objects with the same mass move at different speeds. Which one is harder to stop?

A. The faster object.

B. The slower object.

Page 13: Group Work

Momentum

Formula

momentum is a vector.

p = mv

Page 14: Group Work

Think Question

Two spaceships have the same velocity, with one’s mass twice the other’s. The heavy one’s momentum is:

A. more than twice the light one’s momentum.

B. twice the light one’s momentum.

C. the same as the light one’s momentum.

D. half the light one’s momentum.

E. less than half the light one’s momentum.

Page 15: Group Work

Think Question

Two spaceships have the same mass, but one’s speed is twice the other’s. The faster one’s momentum is:

A. more than twice the slower one’s momentum.

B. twice the slower one’s momentum.

C. the same as the slower one’s momentum.

D. half the slower one’s momentum.

E. less than half the slower one’s momentum.

Page 16: Group Work

Group Work

4. From m, F, t, v, find impulse J and momentum changep.

1 kg 10 N 1 s

1 kg 10 N 10 s

1 kg 1 N 10 s

10 kg 10 N 10 s

m F t J p

Page 17: Group Work

Group Work

5. Show that when a net force F is applied to an object of mass m for a time t, its change in momentum is

Hint: You can find its momentum change from its mass and its velocity change.

p = Ft

Page 18: Group Work

Impulse-Momentum Theorem

• Impulse = Ft.

• Ft = mv= mat

• So impulse = change in momentum

= mv) = p

Page 19: Group Work

Poll Question

Which changes its momentum the most?

A. A moving object that stops when it hits a barrier.

B. A moving object that bounces back from a barrier.

Hints: How is p defined? Momentum is a vector.Which receives the greater impulse?

Page 20: Group Work

Rebound and Momentum

initial p final p

final p – initial p

initial p final p = 0

final p – initial p

p

p

Page 21: Group Work

Reading for Next Time

• Newton’s third law

• Conservation of momentum

• Big ideas:– Forces are always between objects– Objects trade momentum when they interact