Finite Element

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using abaqus 2D

Text of Finite Element



A sign of dimensions 2.0 m x 1.2 m is supported by a hollow circular pole having outer diameter 220 mm and inner diameter 180 mm as shown in Figure 1. The sign is offset 0.5 m from the centerline of the pole and its lower edge is 6.0 m above the ground. Determine the Principle stress and maximum shear Stress due to a wind pressure of 2.0 kPa against sign.




it use for modelling and analyze beam selection

In the Create Part dialog box (shown above) name the part and Select 2D Planar Select Deformable Select Wire Set approximate size = 20


1)Material selection

The technique to create material based on the question it use steel with the young moduulus 200GPA or 200e9


Double click on the Profiles node in the model tree Name the profile and select T for the shape Note that the T shape is one of several predefined crosssections Enter the values for the profile

3. Section and section assignment Name the section BeamProperties and select Beam for both the category and the type Leave the section integration set to During Analysis Select the profile created above (TSection) and select the material created above (Steel). Assign the section will be selected the entire geometry and then select the section beam properties

5. Assemly and step The assembly for the modelling technique.choose create instance and the dependent mode Step is the general procedure to choose the name load .In this case i choose the static general load. Edit the output variable will be choose and i choose stress,displacement and force.


Users need to identify the location of the loads and types of load to be applied on nodes/ keypoints. Also the location of the constraints.Boudary condition is one of the load procedure. In this case we are fixed and encastre the bottom. The force will put on the sign as shown in the figure.

Distributed loadEncastre(fixed)


The process of applying and controlling nodes and elements to the model.

Highlight all members in the viewport and select Done Select Standard for element type Select Linear for geometric order Select Beam for family In the toolbox area click on the Seed Part icon a. Set the approximate global size to 0.02


a) Von misses

b) Maximum principle of stress

C)Minimum principle stress

The minimum principal stress is simply the eigenvalue that has the lowest magnitude.Based on the result the red colour mean the mininum principle stress it can gived. Based on the result minimum stress it can gived .The result show the minimum stress it can gived until 0.It mean until no stress have.The maximum principal stress is the most tensile (least compressive) and the minimum principal stress is the least tensile (most compressive).


A tubular post of square cross section supports a horizontal platform as shown in Figure 2. The tube has outer dimension b=6 in. and wall thickness t=0.5 in. The platform has dimensions 6.57 in. x 24.0 in. supports a uniformly distributed load of 20 psi acting over its upper surface. The resultant of this distributed load is a vertical force P1. Determine Principle stress and maximum shear Stress.

2) MODELLING TEHNIQUEi. PARTIn the Create Part dialog box (shown above) name the part and Select 2D Planar Select Deformable Select Wire Set approximate size = 100ii. PROPERTY Create material Name : steel Select a mechanical, elasticity and elastic Young modulus E= 200Kpsi Poissons ratio = 0 Create section Assign section Assign beam orientation

iii. ASSEMBLY Create instance Independent OK

iv. STEP Step manager Create Field Output Check: MISES,MISEMAX,E,UT,RTv. LOAD Create boundry condition Create load Load : 20Kpsi Moment: 29160

vi. MESH-Highlight all members in the viewport and select Done-Select Standard for element type-Select Linear for geometric order-Select Beam for family-in the toolbox area click on the seed part icon-set a approximate global by number 4

vii. JOB

3) RESULTi. Mises

ii. Maximum Principal Stress