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Announcements. Homework for tomorrow… (Ch . 26 CQs 3 & 4, Probs. 9 & 10) CQ15: 3 F /2 25.60: E 1 =(1.0 x 10 5 N/C) jhat , E 2 =(2.9 x 10 4 N /C) i hat +(2.2 x 10 4 N /C) jhat , E 3 =(5.6 x 10 4 N/C) ihat 25.67: 14° Office hours… MW 12:30-1:30 pm TR 9-10 am - PowerPoint PPT Presentation
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Announcements Homework for tomorrow…
Ch. 25: Prob.66, Ch. 26: CQ 5, Probs. 8 & 41 CQ14: a) 250 N/C b) 4,000 N/C
25.61: E1= 1.8 x 105 N/C @ 60o, E2= 1.8 x 105 N/C @ 120o
25.62: E1= (4.0 x 104 N/C) ihat +(8.0 x 104 N/C) jhat E2= (4.5 x 105 N/C) ihat E3= (4.0 x 104 N/C) ihat -(8.0 x 104 N/C) jhat
Office hours…MW 12:30-1:30 pm TR 9-10 am F 1-2 pm
Tutorial Learning Center (TLC) hours:MW 8-10am, 12-6pm R 8-12pm, 2-6pm
T 8-1pm, 2-6pm F 8-10am, 2-5pm
Chapter 26
The Electric Field(The E-Field of a Continuous
Charge Distribution)
Dipole Moment…
E-field of a dipole on the dipole axis…
E-field of a dipole in the bisecting plane…
Notice: r is distance measured from the center of dipole.
Last time…
-q
+q
s
Two ways:1. Electric Field Vectors2. Electric Field Lines
Picturing the E-Field…
1. Lines start on + charges and end on – charges.2. As lines get closer, fields get stronger.3. Arrows point in direction of force on a positive test
charge.4. Force is tangent to field lines.5. Field lines CAN’T cross.
Electric Field Line Rules:
The diagram shows the electric field lines due to two charged metal plates. We can conclude that:
1. The upper plate is positive and the lower plate is negative.2. A + charge at X would experience the same force if it were
placed at Y.3. A + charge X experiences a greater force than if it were
placed at Z.4. A + charge at X experiences less force than if it were placed
at Z.5. A - charge at X could have it’s weight balanced by the
electrical force.
Quiz Question 1
Y Z
X
++ ++ + + ++ + ++++++ + + ++
Point Charge
Line Charge
Surface Charge
Charge Densities
+++ +
+++++
+++
+ ++++++
+++
+ ++++++
+
L
Area A
+
Figure 26.11 shows a thin, uniformly charged rod of length L with total charge Q. Find the electric field strength at radial distance r in the plane that bisects the rod.
i.e. 26.3E-field of a line of charge..
++
++
++
++
++
++
++
++
+++Lr
P
Figure 26.11 shows a thin, uniformly charged rod of length L with total charge Q. Find the electric field strength at radial distance r in the plane that bisects the rod.
Q: What if the rod becomes infinitely long?
i.e. 26.3E-field of a line of charge..
++
++
++
++
++
++
++
++
+++Lr
P
E-field of a line of an infinite line charge..