Structural Design and Analysis of Products

7/29/2019 Structural Design and Analysis of Products

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ME 3307 Structural Designand Analysis of Products

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Lecture 3: Shear stress & Strain (Part I

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Shear Stress, Strain and Modulus


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Shear stress and shear force


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Average Shear Stress: Direct Shear

a. Lap splice b. Free-body diagram c. Average shear

stress distribution


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Free body diagramFree body diagram


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Based on the free-body diagrams:

Therefore, if the applied load P is 100 kN, and the diameters of the pin andbolt are 100 mm. The average shear stresses in the pin and bolt are 6.367MPa and 12.73 MPa, respectively. In fact, it is recommended using thedouble lap-joint design for structural design applications in order to

minimize any unbalance and moment induced at the joint region.


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Two bolts are used to form a joint connecting rectangularbars in tension, as shown below. Determine the required

diameter of the bolts if the average shear stress for thebolts is not to exceed 140 MPa for the given loading.

Self-study problem

Ans: d=13.49 mm


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Shear Failure at glued bonded joints


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Design examples of adhesively bonded joints


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Pure ShearEquilibrium Requirements:


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Stresses on an inclined plane in an axially loaded

member (rectangular cross section)


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In-class exercise:


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Example 3


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Structural Design and Analysis of Products