Sluryy Tank Report

7/21/2019 Sluryy Tank Report

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Page 1essar - NEW J OB 1

TANK REPORT: Pr i nt ed - 11/ 15/ 2013 11: 06: 23 PM

ETANK FULL REPORT - NEW J OB 1nk2000 Ful l 1. 9. 14 ( 26 Oct 2010)

E OF CONTENTS PAGE 1

NK SETTI NGS SUMMARY PAGE 2

MARY OF DESI GN DATA AND REMARKS PAGE 3

MARY OF RESULTS PAGE 4

DESI GN PAGE 5

L COURSE DESI GN PAGE 12

OM DESI GN PAGE 22

MI C MOMENT PAGE 27

ACI TI ES AND WEI GHTS PAGE 42

& MAWV SUMMARY PAGE 43





NK SETTI NGS SUMMARY

Change These ETank Set t i ngs, Go To Tool s- >Opt i ons, Behavi or Tab.- - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - -

No 650 Appendi x F Cal cs when Tank P = 0 - > Def aul t : Fal seRepad 650 Desi gn Basi s

- > Def aul t f or Tank Roof Nozzl es : Use API Def aul t 1/ 4 i n.- > Thi s Tank : t - Basi s = Roof t - Cal c

how MAWP / MAWV Cal cs : Tr uenf orce API Mi ni mum t hi cknesses : True

nf orce API Maxi mum Roof t hi ckness : Truenf orce Mi ni mum Sel f Supp. Cone Pi t ch ( 2 i n 12) : Trueor ce Non- Annul ar Bt m. t o Meet API - 650 5. 5. 1 : Fal seet t . actual t o t . r equi r ed Val ues : Fal se

Maxi mum 650 App. S or App. M Mul t i pl i er i s 1 : Tr uenf orce API Maxi mum Nozzl e Si zes : True

Max. Sel f Suppor t ed Roof t hi ckness : 0. 5 i n.Max. Tank Corr . Al l owance : 0. 5 i n.xter nal pr essur e cal cs subt r act C. A. per V. 5 : Tr ue

Use Gauge Materi al f or mi n t hi cknesses : Fal senf orce API Mi ni mum Li ve Load : Truenf orce API Mi ni mumAnchor Chai r Desi gn Load= Bol t Yi el d Load : Tr ue





MARY OF DESI GN DATA and REMARKS

: NEWJ OB 1 of Cal cs. : 11/ 15/ 2013 , 11: 06 PMor I nsp. Date : 11/ 15/ 2013

gner : Vi j ay Pat elect : RI L- Sl ur r y dr um t ankt : RI L

nt Locat i on : J amnagargn Basi s : API - 620 10t h Edi t i on, Feb 2002

- - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - -ANK NAMEPLATE I NFORMATI ON

- - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - -er at i ng Rat i o: 0. 4si gn St andard:I - 620 10t h Edi t i on, Feb 2002 -I - 650 Appendi ces Used: F. 1. 3 -of : A- 36: 0. 375i n. -el l ( 3) : A- 36: 0. 25i n. -el l ( 2) : A- 36: 0. 25i n. -el l ( 1) : A- 36: 0. 25i n. -t t om : A- 36: 0. 375i n. -

- - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - -

gn I nternal Pressure = 7. 1069 PSI or 196. 96 I N. H2Ogn Ext ernal Pressure = - 0. 0939 PSI or - 2. 60 I N. H2O

= 10. 2429 PSI or 283. 87 I N. H2OV = - 0. 3499 PSI or - 9. 70 I N. H2O

f Tank = 11. 1549 f tl Hei ght = 13. 7795 f tof Cont ent s = 1. 23Li q. Level = 13. 779 f t

gn Temperat ure = 200 °F

J oi nt Ef f i ci ency = 1

nd Snow Load = 0 l bf / f t 2Li ve Load = 20 l bf / f t 2

gn Roof Dead Load = 20 l bf / f t 2

c Wi nd Vel oci t y = 112 mphd I mpor t ance Fact or = 1. 2g Sei smi c Met hod: API - 650 10th Ed.

ei smi c Zone = 1t e Ampl i f i cat i on Fact or = 1. 5

mpor t ance Fact or = 1

GN NOTES

OTE 1 : Per API - 650 F. 7. 6 - Hydr o t est pr essure = 1. 25 * P= 8. 8836 PSI or 246. 20 I N. H2O





MARY OF RESULTS

l Materi al Summary ( Bot t om i s 1)- - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - -l Wi dt h Materi al St s Sca Wei ght CA

( f t ) (psi ) (psi ) ( l bf ) ( i n)- - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - -

Rat i o = ( t - CA) / R= ( 0. 25 - 0. 125) / 66. 9294= 0. 0019

4. 593 A- 36 16, 000 1, 868 1, 639 0. 125Rat i o = ( t - CA) / R

= ( 0. 25 - 0. 125) / 66. 9294= 0. 0019

4. 593 A- 36 16, 000 1, 868 1, 639 0. 125Rat i o = ( t - CA) / R

= ( 0. 25 - 0. 125) / 66. 9294= 0. 0019

4. 593 A- 36 16, 000 1, 868 1, 639 0. 125- - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - -l Wei ght 4, 917

l API 620 Summary ( Bot t om i s 1)- - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - -l t . i nt 620 t . ext 620 t . r equi r ed t . actual

( i n. ) ( i n. ) ( i n. ) ( i n. )- - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - -

0. 165 0. 1968 0. 3125 0. 250. 1752 0. 1968 0. 3125 0. 250. 1854 0. 1968 0. 3125 0. 25

- - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - -

Suppor t ed Domed Roof ; Mat er i al = A- 36

r equi r ed = 0. 1284 i n.act ual = 0. 375 i n.of J oi nt Ef f i ci ency = 0. 85

i ght = 1, 608 l bf

om Type: Fl at Bot t om: Non- Annul art t om Fl oor Mater i al = A- 36r equi r ed = 0. 375 i n.act ual = 0. 375 i n.t t om J oi nt Ef f i ci ency = 1

ot al Wei ght of Bot t om = 1, 586 l bf

HOR BOLTS: ( 6) 1. 387i n. UNC Bol t s, A- 193 Gr B7

END STI FFENER: L2x2x1/ 4, A- 36, 113. l bf





f Desi gn Per API 620>

D ROOF: A- 36

= Roof J oi nt Ef f i ci ency = 0. 85= Ent ered Roof Li ve Load = 20 l bf / f t 2 = Comput ed Roof Li ve Load, i ncl udi ng Ext ernal Pressure

= Lr + External _Pr essur e= 20 + 0. 0939*144 = 33. 5216 l bf / f t 2

_Load = Snow_Load + I nsul at i on + R. Wei ght + Added_Dead_Load= 0 + ( 8) ( 0/ 12) + 15. 30 + 20= 35. 2982 l bf / f t 2

Radi us ( Rs) = 11. 1549 f t

ha = 60. 0000 degrees ( angl e bet ween t he Normal t o the r oof anda hor i zont al l i ne at t heroof - t o- shel l j unctur e)

a = 30. 0000 degrees ( angl e bet ween t he Normal t o the r oof anda vert i cal l i ne at t heroof - t o- shel l j unctur e)

= R1 = R2 = 133. 86 i n.

= R3 = OD/ 2 = 66. 9294 i n.

ght , Sur f ace Ar ea, and Proj ect ed Ar eas of Roof >

R = Hei ght of Roof = R - SQRT[ R 2 - ( OD/ 2) 2]= 11. 1549 - SQRT[ 11. 1549 2 - ( 11. 1549/ 2) 2]= 1. 482 f t

_i ns = Thi ckness of Roof I nsul at i on= 0 f t

Ap_Vert = Vert i cal Proj ect ed Ar ea of Roof = PI *( [ R + t _i ns] 2) ( Al pha/ 360) - OD*( [ R + t _i ns] - hR) / 2= PI *( 11. 1549 2) ( 59. 9360/ 360) - 11. 1549*( 11. 1549 - 1. 482) / 2

= 11. 1327 f t 2

Hor i zont al Pr oj ect ed Ar ea of Roof ( Per API - 650 5. 2. 1. f )

Xw = Moment Ar m of UPLI FT wi nd f or ce on r oof = 0. 5*OD= 0. 5*11. 1549= 5. 5775 f t

Ap = Proj ect ed Ar ea of r oof f or wi nd moment= PI *R 2= PI *5. 5775 2= 97. 728 f t 2

Roof _Area = 288*PI *R*hR= 288*PI *11. 1549*1. 476= 15, 139 i n 2





Wei ght = ( Densi t y) ( t ) ( Roof _Ar ea)= ( 0. 2833) ( 0. 375) ( 15, 139)= 1, 608 l bf ( New)= 1, 338 l bf ( Corr oded)





I - 620 >

ual Par t i ci pat i ng Ar ea of Roof - t o- Shel l J unct ur e>

From API - 620 5. 12. 4. 2 Eqn. 25)Wc = 0. 6 * SQRT[Rc * ( t - CA) ] ( Top Shel l Cour se)

= 0. 6 * SQRT[66. 9294 * ( 0. 25 - 0. 125) ]= 1. 7355 i n.

From API - 620 5. 12. 4. 2 Eqn. 24)Wh = 0. 6 * SQRT[R2 * ( t - CA) ] ( Roof Pl ate)

= 0. 6 * SQRT[133. 86 * ( 0. 375 - 0. 063) ]= MI N( 3. 8776, 12)= 3. 8776 i n.

Top End St i f f ener : L2x2x1/ 4Aa = ( Cr oss- sect i onal Ar ea of Top End St i f f ener )

= 0. 938 i n 2

Usi ng API - 620 Fi g. 5- 6, Det ai l b End St i f f ener Det ai l

Ashel l = Cont r i but i ng Ar ea due t o shel l pl ates= Wc*( t _shel l - CA)= 1. 7355 * ( 0. 25 - 0. 125)= 0. 217 i n 2

Ar oof = Cont r i but i ng Ar ea due t o r oof pl ates= Wh*( t _r oof - CA)= 3. 8776 * ( 0. 375 - 0. 063)= 1. 21 i n 2

A = Act ual Par t . Area of Roof - t o- Shel l J unct ur e ( per API - 620)= Aa + Aroof + Ashel l= 0. 938 + 1. 21 + 0. 217= 2. 365 i n 2

R3 = 66. 9294 i n.

At = PI *OD 2/ 4*144= PI *11. 1549 2/ 4*144= 14, 073 i n 2 ( Cr oss- Sect i onal Ar ea of Roof at Shel l )

t ernal Pressure - Top- Head Edge >

W = - ( wei ght r oof pl ates) = - 1, 608 l bf W/ At = ( - 1, 608 / 14, 073)

= - 0. 1143 PSIW/ At ' = - 0. 1062 PSI

= 7. 1069 PSI or 196. 96 I N. H20

<Mer i di onal and Lat i t udi nal For ces>





At t he Edge of Top Head)T1 = Rs/ 2*( P + W/ At )

= 133. 86/ 2*( 7. 1069 + - 0. 1143)= 468. 01 l bf / i n

T2 = Rs*[ P + W/ At *SI N( Al pha) ] - T1= 133. 86*[ 7. 1069 + - 0. 1143*COS(60. 0000) ] - 468. 01= 470. 07 l bf / i n

< API - 620 >Mi ni mum t hi ckness ( t ) r equi r ement :

Per 5. 10. 3. 2)T = MAX( T1, T2) = 470. 1 l b. / i n.

t s = 16, 000 PSI ( Al l owabl e Tensi l e St r ess per API - 620 Tabl e 5- 1)

- Cal c = T/ ( St s*E) + CA = 470. 1/ ( 16, 000*0. 85) + 0. 063 = 0. 0976 i n.

- Cal c = 0. 0976 i n.

t ernal Pressure - Top- Head Cent er >

= 7. 1069 PSI or 196. 96 I N. H20

At t he Cent er of Top Head)T1' = ( Rs/ 2) *( P + W/ At )

= ( 133. 86/ 2) *( 7. 1069 + ( - 0. 1062) ) = 468. 56 l bf / i nT2' = Rs*( P + W/ At ) - T1'

= 133. 86*( 7. 1069 + ( - 0. 1062) ) - 468. 56 = 468. 55 l bf / i n


Per 5. 10. 3. 2)T = MAX( T1, T2) = 468. 6 l b. / i n.


- Cal c = T/ ( St s*E) + CA = 468. 6/ ( 16, 000*0. 85) + 0. 063 = 0. 0974 i n.

- Cal c = 0. 0974 i n.

i nce t . actual > T620,Back- Cal cul ati ng Pmax usi ng t . act ual as t ar get, and T620 r out i ne. . .Ent r y Condi t i on: P_x = 7. 1079, t - 620 = 0. 0976Exi t Condi t i on: P_x = 39. 31, t - 620 = 0. 256

NOTE: Tank Li mi t ed t o 15 PSI ( per API - 620)

P_max_i nt = 15 PSI , or 415. 7 I N. H2O( l i mi t ed by Roof Pl at e)

i mum Par t i ci pat i ng Ar ea>

T2s = P*R3 = ( 7. 1069) ( 66. 9294) = 475. 66 l bf / i n

Q = ( T2) ( Wh) + ( T2s) ( Wc) - ( T1) ( Rc) ( SI N( Al pha) )= ( 470. 07) ( 3. 8776) +( 475. 66) ( 1. 7355) - ( 468. 01) ( 66. 9294) ( SI N( 60) )= - 24, 479 l bf





A_mi n = Mi ni mum Par t i ci pat i ng Ar ea ( per API - 620 5. 12. 4. 3 Eq. 27)= - Q/ Scs= - 24, 479/ 15, 000= 1. 632 i n 2

Back- Cal cul at i ng PmaxQ usi ng Act ual Ar ea ( A- 620) as t arget . . .Ent r y Condi t i on: P_x = 8. 1069, A- 620 = 1. 632Exi t Condi t i on: P_x = 10. 2429, A- 620 = 2. 365

_max_i nt_Q = 10. 2429 PSI , or 283. 87 I N. H2O( l i mi t ed by Act ual Par t i ci pat i ng Ar ea)

_max_i nt = MAX[ MI N( 15, 10. 2429) , 0]= 10. 2429 PSI or 283. 87 I N. H2O

xt ernal Pressur e - Top- Head Edge >

W = - ( Lr + Dead_Load) * Roof _Area= - ( 20 + 35. 2982) * 105. 1319= - 5, 814 l bf

W/ At = ( - 5, 814 / 14, 073)= - 0. 4131 PSI

W/ At ' = - 0. 384 PSI

= PV_Entered = - 0. 0939 PSI or - 2. 60 I N. H20


At t he Edge of Top Head)T1 = Rs/ 2*( P + W/ At )

= 133. 86/ 2*( - 0. 0939 + - 0. 4131)= - 33. 93 l bf / i n

T2 = Rs*[ P + W/ At *SI N( Al pha) ] - T1= 133. 86*[ - 0. 0939 + - 0. 4131*COS( 60. 0000) ] - - 33. 93= - 26. 53 l bf / i n

< API - 620 >

Mi ni mum t hi ckness ( t ) r equi r ement :

Tp = MAX( ABS( T1) , ABS( T2) )= 33. 9 l b/ i n.

Tpp = MI N( ABS( T1) , ABS( T2) )= 26. 5 l b/ i n.

Rp = R2 = 133. 86 i n.Rpp = R1 = 133. 86 i n.

_18 = SQRT[ ( Tp + 0. 8*Tpp) *Rp] / 1342 + CA= 0. 127 i n.

_19 = SQRT[Tpp*Rpp] / 1000 + CA= 0. 1226 i n.

t _18 - CA) / Rp = 0. 0005t _19 - CA) / Rpp = 0. 0004





- Cal c = MAX( t _18, t _19)Rat i o = ( t - CA) / R

= ( 0. 375 - 0. 063) / 133. 86= 0. 0023

ca = 10 6*Rat i o ( Per 5. 5. 4. 3)= 2, 331 PSI ( Al l owabl e Compr essi ve St r ess)

- Cal c = 0. 127 i n.

t ernal Pressure - Top- Head Cent er >

= PV_Entered = - 0. 0939 PSI or - 2. 60 I N. H20

At t he Cent er of Top Head)T1' = ( Rs/ 2) *( P + W/ At )

= ( 133. 86/ 2) *( - 0. 0939 + ( - 0. 384) ) = - 31. 99 l bf / i nT2' = Rs*( P + W/ At ) - T1'

= 133. 86*( - 0. 0939 + ( - 0. 384) ) - - 31. 99 = - 31. 98 l bf / i n


& T2 Negat i ve and Equal

T = MAX( ABS( T1) , ABS( T2) ) = 32 l b. / i n.o < . 00667

- Cal c = SQRT[ T*R/ 10 6] + CA= SQRT[ ( 32) ( 133. 86) / 10 6] + 0. 063= 0. 1284 i n.

ngr uent t / R r at i o r esul t s per API - 620 5. 5. 4. 3Rat i o = ( t - CA) / R

= ( 0. 375 - 0. 063) / 133. 86= 0. 0023


- Cal c = 0. 1284 i n.

i nce t . actual > T620,Back- Cal cul ati ng Pmax usi ng t - Cal c as t ar get , and T620 r out i ne. . .Ent r y Condi t i on: V_x = - 0. 0939 PSI , t - 620 = 0. 1284Exi t Condi t i on: V_x = - 10. 484, t - 620 = 0. 375

P_max_ext = - 10. 484 PSI , or - 290. 55 I N. H2O( due t o Roof Pl at e)

i mum Par t i ci pat i ng Ar ea>

T2s = P*R3 = ( - 0. 0939) ( 66. 9294) = - 6. 28 l bf / i n

Q = ( T2) ( Wh) + ( T2s) ( Wc) - ( T1) ( Rc) ( SI N( Al pha) )= ( - 26. 53) ( 3. 8776) +( - 6. 28) ( 1. 7355) - ( - 33. 93) ( 66. 9294) ( SI N( 60) )= 1, 853 l bf





A_mi n = Mi ni mum Par t i ci pat i ng Ar ea ( per API - 620 5. 12. 4. 3 Eq. 27)= Q/ St s= 1, 853/ 16, 000= 0. 116 i n 2

Back- Cal cul at i ng PmaxQ usi ng Act ual Ar ea ( A- 620) as t arget . . .Ent r y Condi t i on: P_x = - 1. 0939, A- 620 = 0. 116Exi t Condi t i on: P_x = - 10. 3619, A- 620 = 2. 365

_max_ext_Q = - 10. 3619 PSI , or - 287. 17 I N. H2O( due t o Act ual Par t i ci pat i ng Ar ea)

_max_ext = MAX( - 10. 484, - 10. 3619)= - 10. 3619 PSI or - 287. 17 I N. H2O

- Cal c = MAX( 0. 0976, 0. 1284 )= 0. 1284 i n.

. r equi r ed = 0. 1284 i n.

OOF DESI GN SUMMARY >

r equi r ed = 0. 1284 i n.act ual = 0. 375 i n.

max_i nt ernal = 10. 2429 PSI or 283. 87 I N. H2Omax_ext ernal = - 10. 3619 PSI or - 287. 17 I N. H2O





LL COURSE DESI GN ( Bot t om Course i s #1)

Cr i t er i a ( per API - 650 5. 6. 4. 1) = ( 6*D*( t - ca) ) 0. 5= ( 6*11. 1549*( 0. 25- 0. 125) ) 0. 5= 2. 8924

H = Max Li qui d Level =13. 779 f t/ H <= 2

se # 1Materi al : A- 36; Wi dt h = 4. 5932 f t .Corr osi on Al l ow. = 0. 125 i n.oi nt Ef f i c i ency = 1

I - 620 >

R = R2 = Rc = 66. 9294 i n.At = 14, 073 i n 2

nt er nal Pr essur e - Ful l >

W = - ( r oof pl at es + shel l ) = - 6, 534 l bf W/ At = ( - 6, 534 / 14, 073)

= - 0. 4643 PSI

x = P + P_l i qui d = 7. 1069 + 7. 3386 = 14. 4455 PSI


T1 = Rc/ 2*( P + W/ At )= 66. 9294/ 2*( 14. 4455 + - 0. 4643)= 467. 88 l bf / i n

T2 = P*Rc= 14. 4455*66. 9294= 966. 83 l bf / i n

< API - 620 >

Mi ni mum t hi ckness ( t ) r equi r ement :

Per 5. 10. 3. 2)T = MAX( T1, T2) = 966. 8 l b. / i n.


- Cal c = T/ ( St s*E) + CA = 966. 8/ ( 16, 000*1) + 0. 125 = 0. 1854 i n.

- Cal c = 0. 1854 i n.



_shel l _i nt = 15 PSI ( due t o Shel l Cour se, wi t hout Li qui d Head)





xt ernal Pressure - Empt y >

r _shel l ( Tot al Roof Li ve Load wei ght support ed by shel l )= Ar * Lr / 144= 15, 139 * 20 / 144= 2, 103 LBF

W = - ( Roof Pl ates + Shel l + Lr _shel l + Dead Load)= - ( 1, 608 + 4, 926 + 2, 103 + 0)= - 8, 637 l bf

W/ At = ( - 8, 637 / 14, 073)= - 0. 6137 PSI

V = - 0. 0939 PSI


T1 = Rc/ 2*( P + W/ At )= 66. 9294/ 2*( - 0. 0939 + - 0. 6137)= - 23. 68 l bf / i n

T2 = P*Rc= - 0. 0939*66. 9294= - 6. 28 l bf / i n




Rp = R2 = 66. 9294 i n.Rpp = R1 = 66. 9294 i n.


_19 = SQRT[Tpp*Rpp] / 1000 + CA= 0. 1455 i n.

t _18 - CA) / Rp = 0. 0005t _19 - CA) / Rpp = 0. 0003


= ( 0. 25 - 0. 125) / 66. 9294= 0. 0019


- Cal c = 0. 1577 i n.






_shel l _ext = - 4. 312 PSI ( due t o Shel l Cour se)


I - 620 >

R = R2 = Rc = 66. 9294 i n.

At = 14, 073 i n 2



= - 0. 3476 PSI

x = P + P_l i qui d = 7. 1069 + 4. 8923 = 11. 9992 PSI


T1 = Rc/ 2*( P + W/ At )= 66. 9294/ 2*( 11. 9992 + - 0. 3476)= 389. 92 l bf / i n

T2 = P*Rc= 11. 9992*66. 9294= 803. 1 l bf / i n


Per 5. 10. 3. 2)T = MAX( T1, T2) = 803. 1 l b. / i n.


- Cal c = T/ ( St s*E) + CA = 803. 1/ ( 16, 000*1) + 0. 125 = 0. 1752 i n.

- Cal c = 0. 1752 i n.











W/ At = ( - 6, 995 / 14, 073)= - 0. 4971 PSI

V = - 0. 0939 PSI


T1 = Rc/ 2*( P + W/ At )

= 66. 9294/ 2*( - 0. 0939 + - 0. 4971)= - 19. 78 l bf / i n

T2 = P*Rc= - 0. 0939*66. 9294= - 6. 28 l bf / i n




Rp = R2 = 66. 9294 i n.Rpp = R1 = 66. 9294 i n.


_19 = SQRT[Tpp*Rpp] / 1000 + CA= 0. 1455 i n.

t _18 - CA) / Rp = 0. 0005t _19 - CA) / Rpp = 0. 0003

- Cal c = MAX( t _18, t _19)

Rat i o = ( t - CA) / R= ( 0. 25 - 0. 125) / 66. 9294= 0. 0019


- Cal c = 0. 1554 i n.








I - 620 >

R = R2 = Rc = 66. 9294 i n.At = 14, 073 i n 2



= - 0. 2309 PSI

x = P + P_l i qui d = 7. 1069 + 2. 446 = 9. 5529 PSI


T1 = Rc/ 2*( P + W/ At )= 66. 9294/ 2*( 9. 5529 + - 0. 2309)= 311. 96 l bf / i n

T2 = P*Rc= 9. 5529*66. 9294= 639. 37 l bf / i n


Per 5. 10. 3. 2)T = MAX( T1, T2) = 639. 4 l b. / i n.


- Cal c = T/ ( St s*E) + CA = 639. 4/ ( 16, 000*1) + 0. 125 = 0. 165 i n.

- Cal c = 0. 165 i n.







W/ At = ( - 5, 353 / 14, 073)= - 0. 3804 PSI

V = - 0. 0939 PSI






T1 = Rc/ 2*( P + W/ At )= 66. 9294/ 2*( - 0. 0939 + - 0. 3804)= - 15. 87 l bf / i n

T2 = P*Rc= - 0. 0939*66. 9294= - 6. 28 l bf / i n




Rp = R2 = 66. 9294 i n.Rpp = R1 = 66. 9294 i n.


_19 = SQRT[Tpp*Rpp] / 1000 + CA= 0. 1455 i n.

t _18 - CA) / Rp = 0. 0004t _19 - CA) / Rpp = 0. 0003


= ( 0. 25 - 0. 125) / 66. 9294= 0. 0019


- Cal c = 0. 1529 i n.



- 650 APPENDI X V FOR EXTERNAL PRESSURE>

W ( Wi nd Pressure) = 31*( V/ 120) 2= 31*( 112/ 120) 2= 27 l bf / f t 2





e ( Ext ernal Pressure) = 0. 0939 PSI , OR 2. 60 I n. H2O= 13. 5216 l bf / f t 2

s ( Shel l Desi gn Pressure) = MAX( Pe, W + 0. 4*Pe)= MAX( 13. 5216, 27 + 0. 4*13. 5216)= MAX( 13. 5216, 32. 4086)= 32. 41 l bf / f t 2

Wt r = Transposed Wi dth of each Shel l Cour se= Wi dt h*[ ( t - ca) _t op / ( t - ca) _cour se ] 2. 5

Transf ormi ng Cour ses ( 1) t o ( 3)

Wt r ( 1) = 4. 5932*[ 0. 125/ 0. 125 ] 2. 5 = 4. 5932 f tWt r ( 2) = 4. 5932*[ 0. 125/ 0. 125 ] 2. 5 = 4. 5932 f tWt r ( 3) = 4. 5931*[ 0. 125/ 0. 125 ] 2. 5 = 4. 5931 f tHt s ( Hei ght of t he Transf ormed Shel l )

= SUM{Wt r } = 13. 7795 f t





* SHELL STI FFENI NG PER API - 650 APP. V. 8 * * *

D ( Tank OD) = 11. 1549 f tHELL MATERI AL ( t hi nnest cour se) : A- 36s1 ( Top Shel l Thi ckness) = 0. 125 i n.sn ( Bot t omShel l Thi ckness) = 0. 125 i n.smi n ( Smal l est Act ual Shel l Thi ckness) = 0. 125 i n.Er ( Roof J oi nt Ef f i c i ency) = 0. 85Es ( Top Shel l J oi nt Ef f i ci ency) = 1

Ht s ( Transf ormed Shel l Hei ght ) = 13. 7795 f t

_shel l ( Al l owabl e St r ess f or t hi nnest Shel l ) = 23, 200 psiy_shel l ( Yi el d St r ess f or t hi nnest Shel l ) = 36, 000 psi ( Mod. of El ast i ci t y f or t hi nnest Shel l ) = 28, 799, 999 psi

TOP STI FFENER MATERI AL : A- 36_st i f f ( Al l owabl e St r ess f or St i f f ener ) = 23, 200 psiy_st i f f ( Yi el d St r ess f or St i f f ener ) = 36, 000 psiHELL STI FFENER MATERI AL : N/ A_sti f f (Al l owabl e St r ess f or St i f f ener ) = N/ Ay_sti f f (Yi el d St ress f or St i f f ener) = N/ A

BOTTOM STI FFENER MATERI AL :_sti f f ( Al l owabl e St r ess f or St i f f ener ) = 0 psiy_sti f f ( Yi el d St ress f or St i f f ener) = 0 psi

BOTTOM PLATE MATERI AL : A- 36_bt m ( Al l owabl e St r ess f or Bot t om Fl oor ) = 23, 200 psiy_shel l ( Yi el d St r ess f or Bot t om Fl oor ) = 36, 000 psiEn ( Bot t om Shel l J oi nt Ef f i c i ency) = 1Eb ( Bot t om J oi nt Ef f i c i ency) = 1

Bot t om Fl oor OD = 11. 4882 f t

<V. 8. 1 UNSTI FFENED SHELLS>

e ( Exter nal Pr essur e) = 13. 5216 l bf / f t 2s ( Shel l Desi gn Pressur e) = 32. 41 l bf / f t 2

V. 8. 1. 1 Cr i t er i a ( El ast i c Fai l ur e when EFC >= 0. 19,other wi se must use ASME Sect i on VI I I )

FC = ( D/ t smi n) 0. 75*[ ( Ht s/ D) *( Fy/ E) 0. 5]= ( 11. 1549/ 0. 125) 0. 75*[ ( 13. 7795/ 11. 1549) *( 36, 000/ 28, 799, 999) 0. 5]= 1. 2681

i nce EFC >= 0. 19, usi ng App. V met hod.

i t i on 1: Wi nd pl us speci f i ed ext ernal ( vacuum) pr essur ei nce Pe <= 15, PSI 1 = ( Pe + 15) / 20 = 1. 4261

<V. 8. 1. 2 Max Ext ernal Pressure>S_Max = 0. 6*E/ [ PSI 1*( Ht s/ D) *( D/ t smi n) 2. 5]

= 0. 6*28, 799, 999/ [ 1. 4261*( 13. 7795/ 11. 1549) *( 11. 1549/ 0. 125) 2. 5]= 130. 3896 l bf / f t 2= 0. 9055 psi

V_max1 = Mi n( PS_Max, [ PS_Max - W/ 144] / 0. 4)= Mi n(0. 9055, 1. 795)= 0. 9055 psi

i t i on 2: Speci f i ed exter nal ( vacuum) pr essur e onl ySI 2 = 3





<V. 8. 1. 2 Max Ext ernal Pressure>V_Max2 = 0. 6*E/ [ PSI 2*( Ht s/ D) *( D/ t smi n) 2. 5]

= 0. 6*28, 799, 999/ [ 3*( 13. 7795/ 11. 1549) *( 11. 1549/ 0. 125) 2. 5]= 61. 982 l bf / f t 2= 0. 4304 psi

V_Max = Mi n( PV_Max1, PV_Max2)= Mi n(0. 9055, 0. 4304)= 0. 4304 psi

e PSI 1*Ps >= 3*Pe, PSI = PSI 1 & Ps = Ps

<V. 8. 1. 3 Mi n t hi ckness due t o Desi gn Pressure>_mi n_ext = 1. 23*[ ( PSI *Ht s*Ps) 0. 4] *( D 0. 6) / ( E 0. 4) + CA

= 0. 1968 i n.

8. 2 CI RCUMFERENTI ALLY STI FFENED SHELLS>

<V. 8. 2. 1. 2 Maxi mum Unst i f f ened Shel l Hei ght >Hs = 0. 6*( t smi n 2. 5) *( E) / [ ( D 1. 5) *Ps*PSI ]

= 0. 6*( 0. 125 2. 5) *( 28, 799, 999) / [ ( 11. 1549 1. 5)*32. 41*1. 4261]= 55. 44 f t .

<V. 8. 2. 1. 3 Number of St i f f eners Requi r ed>Ns = Ht s/ Hs - 1 ( Rounded Up)

= 13. 7795/ 55. 44 - 1= - 0. 7515, Rounded Up => 0

Act ual Number of St i f f eners = 0

<V. 8. 2. 1. 4 Maxi mum St i f f ener Spaci ng on t r ansposed shel l >

Lx = Ht s/ ( Ns + 1)= 13. 7795/ ( 0 + 1)= 13. 7795 f t

Si nce no I nt . Wi nd Gi r der s ar e speci f i ed,St i f f ener Spaci ng ( Ls) = N. A.t _mi n_ext _st i f f = N. A.

<V. 8. 2. 2 I nt er medi at e St i f f ener Ri ng Desi gn>

No cal cul ati ons perf or med si nce no st i f f eners are r equi r ed.

HELL COURSE #1 SUMMARY- - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - -

_mi n_ext governs. See t he STI FFENI NG RI NGS Cal cul at i ons.

- Cal c = MAX( t - Cal c_620, t _mi n_ext , t . sei smi c)= MAX( 0. 1854, 0. 1968, 0)= 0. 1968 i n.

. mi n620 per 5. 10. 4. 1. c = 0. 1875 i n.

. mi n620 per 5. 10. 4. 1. a = 0. 3125 i n.

equi r ed = MAX( t . desi gn, t . mi n620)= MAX( 0. 1968, 0. 3125) = 0. 3125 i n.

ct ual = 0. 25 i n.





ght = Densi t y*PI *[ ( 12*OD) - t ] *12*Wi dt h*t= 0. 2833*PI *[ ( 12*11. 1549) - 0. 25] *12*4. 5932*0. 25= 1, 639 l bf ( New)= 820 l bf ( Cor r oded)




. mi n620 per 5. 10. 4. 1. c = 0. 1875 i n.

. mi n620 per 5. 10. 4. 1. a = 0. 3125 i n.

equi r ed = MAX( t . desi gn, t . mi n620)= MAX( 0. 1968, 0. 3125) = 0. 3125 i n.

ct ual = 0. 25 i n.





. mi n620 per 5. 10. 4. 1. c = 0. 1875 i n.

. mi n620 per 5. 10. 4. 1. a = 0. 3125 i n.

equi r ed = MAX( t . desi gn, t . mi n620)

= MAX( 0. 1968, 0. 3125) = 0. 3125 i n.ct ual = 0. 25 i n.






T BOTTOM: NON- ANNULAR PLATE DESI GN

Bot t om Pl at e Mat er i al : A- 36Annul ar Bot t om Pl at e Mat er i al : A- 36

ght of Bot t om Pl ate>

Bot t om_Ar ea = PI / 4*( Bot t om_OD) 2= PI / 4*( 137. 8588) 2= 14, 927 i n 2

Wei ght = Densi t y * t . act ual * Bot t om_Area= 0. 2833 * 0. 375 * 14, 927= 1, 586 l bf ( New)= 1, 057 l bf ( Corr oded)

I - 620 >

_mi n = 0. 25 + CA = 0. 25 + 0. 125 = 0. 375 i n. ( per Sect i on 5. 9. 4. 2)

- Cal c = t _mi n = 0. 375 i n.Cal cul at i on of Hydr ost at i c Test St r ess & Pr oduct Desi gn St r ess

( per API - 650 Sect i on 5. 5. 1)

_1 : Bot t om ( 1st ) Shel l Cour se t hi ckness.

H' = Max. Li q. Level + P( psi ) / ( 0. 433)= 13. 779 + ( 7. 1069) / ( 0. 433) = 30. 1922 f t

t = Hydr ost at i c Test St r ess i n Bot t om ( 1st ) Shel l Cour se= ( 2. 6) ( OD) ( H' - 1) / t _1= ( 2. 6) ( 11. 1549) ( 30. 1922 - 1) / ( 0. 25)= 3, 387 PSI . ( Wi t hi n 24900 PSI l i mi t f or Non- Annul ar Bot t om)

d = Product Desi gn St r ess i n Bot t om ( 1st ) Shel l Cour se= ( 2. 6) ( OD) ( H' - 1) ( G) / ( t _1 - ca_1)= ( 2. 6) ( 11. 1549) ( 30. 1922 - 1) ( 1. 23) / ( 0. 125)= 8, 331 PSI . ( Wi t hi n 23200 PSI l i mi t f or Non- Annul ar Bot t om)

- - - - - - - - - - - - - - - - - - - - - - -

cuum Cal cul at i ons > ( per ASME Sect i on VI I I Di v. 1)

Wei ght of Cor r . Bott om Pl ate Resi st i ng Exter nal Vacuum

_btm = 0. 2833 * 0. 25= 0. 0708 PSI or 1. 96 I N. H2O

_ext = PV + P_bt m = - 0. 0939 + 0. 0708 = - 0. 0231 PSI or - 0. 64 I N. H2O= - 0. 0231 PSI

d_ext = ( t - Cal c - CA) ( 1st cour se)= ( 0. 1968 - 0. 125)= 0. 0718 i n.

s = ( t . act ual - CA) ( 1st cour se)= ( 0. 25 - 0. 125)= 0. 125 i n.





C = 0. 33 * t d_ext / t s= 0. 33 * 0. 0718 / 0. 125= 0. 1896

i nce C < 0. 2, set C = 0. 2

- Vac = OD*SQRT( C*P_ext / SE) + CA= ( 133. 86) *SQRT[ ( 0. 2) ( - 0. 0231) / ( 16, 000) ( 1) ] + 0. 125= 0. 1969 i n.

- Cal c = MAX( t - Cal c, t - Vac)= MAX( 0. 375, 0. 1969)= 0. 375 i n.

_max_exter nal ( Vacuum l i mi t ed by bot t ompl at e t hi ckness)= - ( [ ( t - CA) / OD] 2*( S*E/ C) + P_btm)= - ( [ ( 0. 375 - 0. 125) / 133. 86] 2*( 16, 000*1/ 0. 2) + 0. 0708)= - 0. 3499 PSI or - 9. 70 I N. H2O

- - - - - - - - - - - - - - - -

AT BOTTOM: NON- ANNULAR SUMMARY >

Bot t om Pl at e Mat er i al : A- 36. r equi r ed = 0. 375 i n.. act ual = 0. 375 i n.





UPLI FT DUE TO I NTERNAL PRESSURESee r oof repor t f or cal cul at i ons)

Net_ Upl i f t = 96, 217 l bf Anchorage REQUI RED f or i nt ernal pressure.Bol t Spaci ng = 10 f t , Mi n # Anchor Bol t s = 6

D MOMENT ( Usi ng API - 650 SECTI ON 5. 11)

vs = Wi nd Vel oci t y = 112 mphvf = Vel oci t y Fact or = ( vs/ 100) 2 = ( 112/ 100) 2 = 1. 2544

Wi nd_Upl i f t = I w * 30 * vf = 1. 2 * 30 * 1. 2544= 45. 1584 l bf / f t 2

API - 650 5. 2. 1. k Upl i f t CheckP_F41 = WCt oPSI ( 0. 962*Fy*A*TAN( Thet a) / D 2 + 8*t _h)P_F41 = WCt oPSI ( 0. 962*36, 000*2. 365*0. 9296/ 11. 1549 2 + 8*0. 312)

= 22. 1685 PSILi mi t Wi nd_Upl i f t / 144+P t o 1. 6*P_F41Wi nd_Upl i f t / 144 + P = 7. 3682 PSI1. 6*P_F41 = 35. 4696 PSI

Wi nd_Upl i f t / 144 + P = MI N( Wi nd_Upl i f t / 144 + P, 1. 6*P_F41)Wi nd_Upl i f t / 144 = MI N( Wi nd_Upl i f t / 144, 1. 6*P_F41 - P)Wi nd_Upl i f t = MI N( Wi nd_Upl i f t , (1. 6*P_F41 - P) * 144)

= MI N( 45. 1584, 4, 084)= 45. 1584 l bf / f t 2

hR = Hei ght of Roof = R - SQRT[R 2 - ( OD/ 2) 2]= 11. 1549 - SQRT[ 11. 1549 2 - ( 11. 1549/ 2) 2]= 1. 482 f t

t _i ns = Thi ckness of Roof I nsul at i on= 0 f t

Ap_Vert = Vert i cal Proj ected Ar ea of Roof = PI *( [ R + t _i ns] 2) ( Al pha/ 360) - OD*( [ R + t _i ns] - hR) / 2= PI *( 11. 1549 2) ( 59. 9360/ 360) - 11. 1549*( 11. 1549 - 1. 482) / 2

= 11. 1327 f t 2

Hor i zont al Pr oj ect ed Ar ea of Roof ( Per API - 650 5. 2. 1. f )

Xw = Moment Ar m of UPLI FT wi nd f or ce on r oof = 0. 5*OD= 0. 5*11. 1549= 5. 5775 f t

Ap = Proj ect ed Ar ea of r oof f or wi nd moment= PI *R 2= PI *5. 5775 2= 97. 728 f t 2

M_r oof ( Moment Due t o Wi nd For ce on Roof )= ( Wi nd_Upl i f t ) ( Ap) ( Xw)= ( 45. 1584) ( 97. 728) ( 5. 5775) = 24, 615 f t - l bf

Xs ( Moment Ar m of Wi nd Force on Shel l )= H/ 2 = ( 13. 7795) / 2 = 6. 8898 f t





As ( Pr oj ect ed Ar ea of Shel l )= H*( OD + t _i ns / 6)= ( 13. 7795) ( 11. 1549 + 0/ 6) = 153. 7089 f t 2

M_shel l ( Moment Due t o Wi nd Force on Shel l )= ( I w) ( vf ) ( 18) ( As) ( Xs)= ( 1. 2) ( 1. 2544) ( 18) ( 153. 7089) ( 6. 8898) = 28, 694 f t - l bf

Mw ( Wi nd moment )= M_r oof + M_shel l = 24, 615 + 28, 694

= 53, 309 f t - l bf

W = Net wei ght ( PER API - 650 5. 11. 3)( For ce due t o cor r oded wei ght of shel l andshel l - suppor t ed r oof pl at es l ess40% of F. 1. 2 Upl i f t f orce. )

= W_shel l + W_r oof - 0. 4*P*( PI / 4) ( 144) ( OD 2)= 2, 460 + 1, 338 - 7. 1069*( PI / 4) ( 144) ( 11. 1549 2)= - 35, 708 l bf

NOTE: Ther e i s net upl i f t on t he t ank.

STANCE TO OVERTURNI NG ( per API - 650 5. 11. 2)

An unanchor ed Tank must meet t hese t wo cr i t er i a:1) 0. 6*Mw + MPi < MDL/ 1. 52) Mw + 0. 4MPi < ( MDL + MF) / 2

Mw = Dest abi l i zi ng Wi nd Moment = 53, 309 f t - l bf

MPi = Dest abi l i zi ng Moment about t he Shel l - t o- Bot t omJ oi nt f r om Desi gn «Pressure.

= P*( PI *OD 2/ 4) *( 144)*( OD/ 2)= 7. 1069*( 3. 1416*11. 1549 2/ 4)*( 144)*( 5. 5775)= 557, 827 f t - l bf

MDL = St abi l i zi ng Moment about t he Shel l - t o- Bot t om J oi nt f r om t he Shel l and «Roof wei ght suppor t ed by t he Shel l .

= ( W_shel l + W_r oof ) *OD/ 2= ( 2, 460 + 1, 338)*5. 5775= 21, 183 f t - l bf

b = Bot t omPl at e t hi ckness l ess C. A. = 0. 25 i n.

wl = Ci r cumf er ent i al l oadi ng of cont ent s al ong Shel l - To- Bot t om J oi nt .= 4. 67*t b*SQRT( Sy_bt m*H_l i q)= 4. 67*0. 25*SQRT( 36, 000*13. 779)= 822. 27 l bf / f t

wl = 0. 9 * H_l i q * OD ( l esser val ue t han above)= 0. 9*13. 779*11. 1549= 138. 33 l bf / f t

MF = Stabi l i zi ng Moment due t o Bot t om Pl ate and Li qui d Wei ght .= ( OD/ 2)*wl *PI *OD= ( 5. 5775) ( 138. 33) ( 3. 1416) ( 11. 1549)= 27, 038 f t - l bf





Cr i ter i a 1. 6*( 53, 309) + 557, 827 < 21, 183/ 1. 5i nce 589, 812 >= 14, 122, Tank must be anchored.

Cr i ter i a 23, 309 + 0. 4 * 557, 827 < ( 21, 183 + 27, 038) / 2i nce 276, 440 >= 24, 111, Tank must be anchored.

STANCE TO SLI DI NG ( per API - 650 5. 11. 4)

F_wi nd = vF * 18 * As= 1. 2544 * 18 * 153. 7089= 3, 471 l bf

F_f r i ct i on = Maxi mum of 40% of Wei ght of Tank= 0. 4 * ( W_Roof _Cor r oded + W_Shel l _Cor r oded +

W_Bt m_Cor r oded + W_mi n_Li qui d)= 0. 4 * ( 1, 338 + 2, 460 + 1, 057 + 0)

= 1, 942 l bf

Bol t Shear Ar ea Req' d = 0. 025 i n 2

horage Requi r ement >hor age requi r ed si nce Cr i t er i a 1, Cr i t er i a 2, or Sl i di ngNOT accept abl e.Spaci ng = 10 f t , Mi n # Anchor Bol t s = 6





MI C MOMENT ( API - 650 APPENDI X E & API - 620 APPENDI X L)

Ms ( Sei smi c Moment )Ms = Z*I *( C1*Ws*Xs + C1*Wr *Ht + C1*W1*X1 + C2*W2*X2)

Z = 0. 075 Zone coef f i ci ent f or zone 1 ( f r om Tabl e E- 2)I = 1 I mpor t ance Fact orS = 1. 5 Si t e ampl i f i cat i on f act or ( f r om Tabl e E- 3)

C1 = 0. 6 = Lateral eart hquake f orce coef f i ci ent

k = 0. 59 ( f act or f or D/ H = 0. 8096 f r om f i gur e E- 4)

T = Natur al Per i od of Fi r st Sl oshi ng Mode= k*SQRT( OD) = 0. 59*SQRT( 11. 1549) = 1. 971

C2 = Lat eral Eart hquake For ce Coef f i ci ent= 0. 75( S) / T = . 75( 1. 5) / ( 1. 971) = 0. 5708

From Fi gur es E- 2 & E- 3X1_H = X1/ H char t f act orX2_H = X2/ H char t f act orW1_Wt = W1/ Wt char t f act orW2_Wt = W2/ Wt char t f act orWt = Wei ght of t ank cont ent s @ Max. Li qui d Level

X1 = ( X1_H) *H = ( 0. 4207) *13. 779 = 5. 7972X2 = ( X2_H) *H = ( 0. 7623) *13. 779 = 10. 5034W1 = ( W1_Wt ) *Wt = ( 0. 8586) *102, 534 = 88, 037W2 = ( W2_Wt ) *Wt = ( 0. 2041) *102, 534 = 20, 926Ws = W_shel l + W_I nsul at i on ( New Condi t i on)

= 4, 917 + 0 = 4, 917Wr = W_r oof + Snow Load + W_I nsul at i on ( New Condi t i on)

= 1, 608 + 0 + 0 = 1, 608

C1*Ws*Xs = 0. 6*( 4, 917) ( 6. 8898) = 20, 326C1*Wr *Ht = 0. 6*( 1, 608) ( 13. 7795) = 13, 294C1*W1*X1 = 0. 6*( 88, 037) ( 5. 7972) = 306, 220C2*W2*X2 = ( 0. 5708) ( 20, 926) ( 10. 5034) = 125, 455

Ms = Z*I *( C1*Ws*Xs + C1*Wr *Ht + C1*W1*X1 + C2*W2*X2)= ( 0. 075) ( 1) ( 20, 326 + 13, 294 + 306, 220 + 125, 455)= 34, 897 f t - l bf

W_shel l = Wei ght of Shel l (New Condi t i on)W_r oof 2 = Wei ght of Roof Pl at es Suppor t ed By Shel l ( New)

wt = ( W_shel l + W_r oof 2) / ( PI *OD) ( New Condi t i on)= ( 4, 917 + 1, 608) / ( PI *11. 1549)= 186. l bf / f t

RESI STANCE TO OVERTURNI NG ( per Sect i on E. 4. 1, E. 4. 2,assumi ng no anchors)

wl = 7. 9*( t b1) *SQRT( Sy*G*H)= 7. 9*( 0. 25) *SQRT( 36, 000*1. 23*13. 779)= 1, 543 l bf / f t

wher e t b1 = t - CA = 0. 25 i n. ( f or Bot t om Pl at e)





1. 25*G*H*OD = 1. 25( 1. 23) ( 13. 779) ( 11. 1549)= 236 l bf / f t

si nce wl > 1. 25*G*H*OD, wl = 1. 25G*H*ODwl = 236 l bf / f t

UNANCHORED TANKS ( Sect i on E. 5. 1)

Ms/ [ OD 2( wt +wl ) ] = 34, 897/ [ ( 11. 1549 2) ( 186. + 236) ] = 0. 6643

b = wt + 1. 273( Ms) / OD 2 = max l ongi t udi nal compressi ve f or ce= 186. + 1. 273( 34, 897) / ( 11. 1549) 2 = 543. 2 l bf / f t

MAXI MUM ALLOWABLE SHELL COMPRESSI ON ( Sect i on E. 5. 3)

b/ ( 12t ) = Max Longi t udi nal Compress i ve St r ess= 543. 2/ ( 12*( 0. 25 - 0. 125) ) = 362 PSI

G*H*OD 2/ t 2 = ( 1. 23) ( 13. 779) ( 11. 1549 2) / ( 0. 25 - 0. 125) 2 = 134, 969

Fa = 10 6*t / ( 2. 5*OD) + 600*SQRT( G*H)= ( 10 6) ( 0. 25 - 0. 125) / ( 2. 5*11. 1549) + ( 600) SQRT[ ( 1. 23) ( 13. 779) ]= 6, 952 PSI

t = 0. 25 - 0. 125 = 0. 125 i n. ( OK si nce b/ ( 12t ) <= Fa)

ANCHORED TANKS ( Sect i on E. 5. 2)

b = wt + 1. 273( Ms) / OD 2 = Max Longi t udi nal Compress i ve For ce= 186. + 1. 273( 34, 897) / ( 11. 1549) 2 = 543 l bf / f t

MAXI MUM ALLOWABLE SHELL COMPRESSI ON ( Sect i on E. 5. 3)

b/ ( 12t ) = Max Longi t udi nal Compress i ve St r ess= 543/ ( 12*( 0. 25 - 0. 125) ) = 362 PSI

G*H*OD 2/ t 2 = ( 1. 23) ( 13. 779) ( 11. 1549 2) / ( 0. 25 - 0. 125) 2 = 134, 969

Fa = 10 6*t / ( 2. 5*OD) + 600*SQRT( G*H)

= ( 10 6) ( 0. 25 - 0. 125) / ( 2. 5*11. 1549) + ( 600) SQRT[ ( 1. 23) ( 13. 779) ]= 6, 952 PSI

t = 0. 25 - 0. 125 = 0. 125 i n. ( OK si nce b/ ( 12t ) <= Fa)

ANCHORAGE OF TANKS ( Sect i on E. 6. 1)

N = 6 Number of Anchor sD = 11. 4829 f t Di amet er of Anchor Ci r cl e

Net _Upl i f t = Net upl i f t due t o i nt er nal pr essur e

MAR = mi ni mum anchorage r esi st ance due t o sei smi c moment= 1. 273(Ms) / OD 2 + Net _Upl i f t / Ci r cumf erence= 1. 273(34, 897) / 11. 1549 2 + 96, 217/ ( PI *11. 1549)= 3, 103 l bf / f t ci r cumf er ence

bt sei s = anchor t ensi on r eq' d t o r esi st sei smi c moment= MAR*D*PI / ( N)= ( 3, 103) ( 11. 4829) ( PI ) / ( 6) = 18, 657 l bf





HOR BOLT DESI GN

Bol t Mat er i al : A- 193 Gr B7Sy = 105, 000 PSI

l i f t Load Cases, per API - 650 Tabl e 5- 21b >

D ( t ank OD) = 11. 1549 f t ( desi gn pressure) = 196. 96 I NCHES H2Ot ( t est pressur e per F. 7. 6) = 1. 25 * P = 246. 2 I NCHES H2O

f ( f ai l ur e pr essur e per F. 6) = N. A. ( see Upl i f t Case 3 bel ow)_h ( r oof pl at e t hi ckness) = 0. 375 i n.

Mw ( Wi nd Moment ) = 53, 309 f t - l bf Mr w ( Sei smi c Ri ngwal l Moment ) = 34, 897 f t - l bf W1 ( Dead Load of Shel l mi nus C. A. and Any

Dead Load mi nus C. A. ot her t han Roof Pl at e Act i ng on Shel l )

W2 ( Dead Load of Shel l mi nus C. A. and AnyDead Load mi nus C. A. i ncl udi ng Roof Pl at e mi nus C. A. Act i ng on Shel l )

W3 ( Dead Load of New Shel l and AnyDead Load ot her t han Roof Pl at e Act i ng on Shel l )

or Tank wi t h Sel f Support ed Roof ,W1 = Corr oded Shel l + Shel l I nsul at i on

= 2, 460 + 0= 2, 460 l bf

W2 = Corr oded Shel l + Shel l I nsul at i on + Cor r odedRoof Pl at es + Roof Dead Load

= 2, 460 + 0+ 1, 338 + 15, 139 * 35. 2982/ 144

= 7, 509 l bf W3 = New Shel l + Shel l I nsul at i on

= 4, 917 + 0= 4, 917 l bf

Upl i f t Case 1: Desi gn Pressure Onl yU = [ ( P - 8*t _h) * D 2 * 4. 08] - W1U = [ ( 196. 96 - 8*0. 375) * 11. 1549 2 * 4. 08] - 2, 460

= 96, 010 l bf bt = U / N = 16, 002 l bf

Sd = 15, 000 PSIA_s_r = Bol t Root Ar ea Req' dA_s_ r = bt / Sd

= 16, 002/ 15, 000 = 1. 067 i n 2

Upl i f t Case 2: Test Pr essur e Onl yU = [ ( Pt - 8*t _h) * D 2 * 4. 08] - W1U = [ ( 246. 2 - 8*0. 375) * 11. 1549 2 * 4. 08] - 2, 460

= 121, 008 l bf bt = U / N = 20, 168 l bf





Sd = 20, 000 PSIA_s_r = Bol t Root Ar ea Req' dA_s_ r = bt / Sd

= 20, 168/ 20, 000 = 1. 008 i n 2

Upl i f t Case 3: Fai l ur e Pr essur e Onl yNot appl i cabl e si nce i f t her e i s a knuckl e on t ank r oof ,or t ank r oof i s not f r angi bl e.Pf ( f ai l ur e pr essur e per F. 6) = N. A.

Upl i f t Case 4: Wi nd Load Onl yPWR = Wi nd_Upl i f t / 5. 208

= 45. 1584/ 5. 208= 8. 671 I N. H2O

PWS = vF * 18= 1. 2544 * 18= 22. 5792 l bf / f t 2

MWH = PWS*( D+t _i ns/ 6) *H 2/ 2= 22. 5792*( 11. 1549+0/ 6) *13. 7795 2/ 2= 23, 912 f t - l bf

U = PWR * D 2 * 4. 08 + [ 4 * MWH/ D] - W2= 8. 671*11. 1549 2*4. 08+[ 4*23, 912/ 11. 1549] - 7, 509= 5, 468 l bf

bt = U / N = 911 l bf

Sd = 0. 8 * 105, 000 = 84, 000 PSIA_s_r = Bol t Root Ar ea Req' dA_s_ r = bt / Sd

= 911/ 84, 000 = 0. 011 i n 2

Upl i f t Case 5: Sei smi c Load Onl yU = [ 4 * Mr w / D] - W2*( 1- 0. 4*Av)U = [ 4 * 34, 897 / 11. 1549] - 7, 509*( 1- 0. 4*0)

= 5, 005 l bf bt = U / N = 834 l bf


= 834/ 84, 000 = 0. 01 i n 2

Upl i f t Case 6: Desi gn Pressure + Wi nd LoadU = [ ( 0. 4*P + PWR - 8*t _h) * D 2 * 4. 08] + [ 4 * MWH / D] - W1

= [ ( 0. 4*196. 96+8. 671- 8*0. 375) *11. 1549 2 * 4. 08]+[ 4*23, 912 / 11. 1549] - «2, 460

= 48, 991 l bf bt = U / N = 8, 165 l bf

Sd = 20, 000 = 20, 000 PSIA_s_r = Bol t Root Ar ea Req' dA_s_ r = bt / Sd

= 8, 165/ 20, 000 = 0. 408 i n 2

Upl i f t Case 7: Desi gn Pressure + Sei smi c LoadU = [ ( 0. 4*P - 8*t _h) *D 2 * 4. 08] + [ 4*Mr w/ D] - W1*( 1- 0. 4*Av)

= 48, 528 l bf bt = U / N = 8, 088 l bf






= 8, 088/ 84, 000 = 0. 096 i n 2

Upl i f t Case 8: Fr angi bi l i t y Pr essur eNot appl i cabl e si nce i f t her e i s a knuckl e on t ank r oof ,or t ank r oof i s not f r angi bl e.Pf ( f ai l ur e pr essur e per F. 6) = N. A.

NCHOR BOLT SUMMARY >

Bol t Shear Ar ea Req' d = 0. 025 i n 2

Bol t Root Ar ea Req' d = 1. 067 i n 2

= Bol t Di amet er = 1. 387 i n. = Threads per i nch = 6

A_s = Act ual Bol t Root Ar ea= 0. 7854 * ( d - 1. 3 / n) 2= 0. 7854 * ( 1. 387 - 1. 3 / 6) 2= 1. 0757 i n 2

xcl usi ve of Cor r osi on,Bol t Di amet er Req' d = 1. 382 i n. ( per ANSI B1. 1)

Act ual Bol t Di amet er = 1. 387 i n.

Bol t Di amet er Meet s Requi r ement s.

CHORAGE REQUI REMENTS>

Mi ni mum # Anchor Bol t s = 6NOTE: API - 620 has no mi ni mumspaci ng r equi r ement , but

per API - 650 5. 12. 3, maxi mum spaci ng i s 10 f t i f anchorage r equi r ed.

al # Anchor Bol t s = 6or age Meet s Spaci ng Requi r ements.

HOR BOLT CHAI RS NOT SPECI FI ED.





MAL & EMERGENCY VENTI NG ( API - 2000)

nt ent s : Sl ur r ynk OD = 11. 1549 f tnk Shel l Hei ght = 13. 7795 f tnk Desi gn Temp. = 200 °F

NBREATHI NG - VACUUM RELI EF>

Q1 ( Maxi mum Movement Out of Tank) ( per Sect i on 4. 3. 2. 1. 1)

= 5. 6 CFH Ai r per 42 GPH out f l ow= ( 5. 6/ 42) *498*60= 3, 984 CFH, or 66 CFM f r ee ai r

Q2 ( Thermal I nbr eat hi ng) ( per Sect i on 4. 3. 2. 1. 2)

= 253. 2619 CFH, or 4. CFM f r ee ai r ( Tabl e 2A Col umn 2)

Tot al Vacuum Rel i ef Requi r ed = Q1 + Q2 = 4, 237 CFH, or 71. CFM

OUTBREATHI NG - PRESSURE RELI EF>

Q1 ( Maxi mum Movement I nto Tank) ( per Sect i on 4. 3. 2. 3. 1)

= 12 CFH Ai r per 42 GPH i nf l ow= ( 12/ 42)*454*60 = 7, 783 CFH, or 130. CFM f r ee ai r

Q2 ( Thermal Out br eat hi ng) ( per Sect i on 4. 3. 2. 3. 2)

= 252 CFH, or 4 CFM f r ee ai r ( Tabl e 2A Col umn 4)

Total Pressur e Rel i ef Requi r ed = Q1 + Q2 = 8, 035 CFH, or 134. CFM

MERGENCY VENTI NG>

W = 13. 7795 f t .For f l at bot t om t anks, onl y shel l i s consi der ed f or Wet t ed Ar ea.

Wet t ed Ar ea = 483 f t 2

( Sect i on 4. 3. 3. 2. 2, Desi gn Pr essur e > 1 PSI )

Qe = 346, 860 CFH, or 5781. CFM f r ee ai r (Tabl e 3A Col umn 2)

x1 = 1 ( Envi r onment Fact or f or Dr ai nage)x2 = 1 ( Envi r onment Fact or f or I nsul at i on)

Qe = x1*x2*Qe = ( 1) ( 1) ( 346, 860)= 346, 860 CFH





E 1: NOZZLES & MANWAYS

- - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - -TYPE SI ZE FLANGE SCH. ELEV. WEI GH REPAD REPAD REPAD REPAD

FACI NG ON t Do W CASHELL or L

( i n) ( f t ) l bf ( i n) ( i n) ( i n) ( i n)- - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - -

RFNZ 24 RFSO STD N. A. N. A. Not e SHNZ 8 RFLJ STD 2 N. A. 0. 25 19 0 0

RFNZ 24 RFWN 10S N. A. N. A. Not eSHNZ 6 RFWN STD 2 N. A. 0. 25 15. 75 0 0SHNZ 3 RF STD 2 N. A. 0. 25 10. 5 0 0SHNZ 3 RF STD 3 N. A. 0. 25 10. 5 0 0SHNZ 36 FF STD 1 N. A. 0. 312 72. 75 0 0RFNZ 6 RFWN STD N. A. N. A. - - - -

- - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - -E 1: The Nozzl e or Manway Si ze i s t oo l arge f or r epad t o be si zed per API .

Roof St s = 16, 000 PSI ( Al l owabl e Tensi l e St r ess per API - 620 Tabl e 5- 1)





zzl e A Rei nf or cement Requi r ement s >er API - 650 and ot her r ef erences bel ow)

OZZLE Descr i pt i on : 24i n. STD RFSO

OUNTED ON ROOF; El evat i on = 0 f t .ROOF PARAMETERS:( Per User Set t i ng, t- Basi s = Roof t- Cal c)t _cr = 0. 1284 i n. ( Roof t - Cal c)t _c = 0. 312 i n. ( Roof t l ess C. A. )

t _Basi s = 0. 1284 i n.

OR ROOF NOZZLE,REF. API - 650 FI G 5- 19, TABLE 5- 14 AND FOOTNOTE A OF TABLE 5- 14,r API - 650 FI G 5- 20, TABLE 5- 15 AND FOOTNOTE A OF TABLE 5- 15)

E: Roof Nozzl e Si ze i s Too Lar ge Based on API Ref erences.

hel l St s = 16, 000 PSI ( Al l owabl e Tensi l e St r ess per API - 620 Tabl e 5- 1)





zzl e B1- 2 Rei nf or cement Requi r ements >er API - 650 Sect i on 3. 7. 2 and other r ef erences bel ow)

OZZLE Descr i pt i on : 8i n. STD RFLJ

OUNTED ON SHELL COURSE 1 ; El evat i on = 2 f t .COURSE PARAMETERS:t _cr = 0. 1968 i n. ( Cour se t - Cal c)t _c = 0. 125 i n. ( Cour se t l ess C. A. )t _Basi s = 0. 1968 i n.

HELL NOZZLE REF. API - 650 TABLE 5- 6, AND FOOTNOTE A OF TABLE 5- 7)

_r pr ( Repad Requi r ed Thi ckness)_r pr = NOMI NAL( A_r pr / D)

A_r pr = ( Requi r ed Ar ea - Avai l abl e Shel l Ar ea- Avai l abl e Nozzl e Neck Ar ea)

Requi r ed Ar ea = t _Basi s * D= 0. 1968 * 8. 25= 1. 624 i n 2

Avai l abl e Shel l Ar ea = ( t _c - t _Basi s) * D= ( 0. 125 - 0. 1968) * 8. 25= - 0. 592 i n 2

Avai l abl e Nozzl e Neck Ar ea = [ 4 * ( t _n- ca) + t _c] * ( t _n- ca) * «MI N( Sd_n/ Sd_s , 1)

= [ 4 * ( 0. 322) + 0. 125] * ( 0. 322) * 1= 0. 455 i n 2

A_r pr = 1. 624 - - 0. 592 - 0. 455= 1. 761 i n 2

_r pr = NOMI NAL( 1. 761/ 8. 25)= 0. 25 i n.

d on Shel l Nozzl e Si ze of 8 i n. ,d Si ze ( OD) Must be 19 i n.






zzl e C Rei nf or cement Requi r ement s >er API - 650 and ot her r ef erences bel ow)

OZZLE Descr i pt i on : 24i n. 10S RFWN


t _Basi s = 0. 1284 i n.


E: Roof Nozzl e Si ze i s Too Lar ge Based on API Ref erences.






zzl e D Rei nf or cement Requi r ement s >er API - 650 Sect i on 3. 7. 2 and other r ef erences bel ow)

OZZLE Descr i pt i on : 6i n. STD RFWN








= [ 4 * ( 0. 28) + 0. 125] * ( 0. 28) * 1= 0. 349 i n 2

A_r pr = 1. 23 - - 0. 449 - 0. 349= 1. 33 i n 2

_r pr = NOMI NAL( 1. 33/ 6. 25)= 0. 25 i n.

d on Shel l Nozzl e Si ze of 6 i n. ,d Si ze ( OD) Must be 15. 75 i n.






zzl e L1 Rei nf or cement Requi r ement s >er API - 650 Sect i on 3. 7. 2 and other r ef erences bel ow)

OZZLE Descr i pt i on : 3i n. STD RF








= [ 4 * ( 0. 216) + 0. 125] * ( 0. 216) * 1= 0. 214 i n 2

A_r pr = 0. 64 - - 0. 233 - 0. 214= 0. 659 i n 2

_r pr = NOMI NAL( 0. 659/ 3. 25)= 0. 25 i n.







zzl e L2 Rei nf or cement Requi r ement s >er API - 650 Sect i on 3. 7. 2 and other r ef erences bel ow)

OZZLE Descr i pt i on : 3i n. STD RF








= [ 4 * ( 0. 216) + 0. 125] * ( 0. 216) * 1= 0. 214 i n 2

A_r pr = 0. 64 - - 0. 233 - 0. 214= 0. 659 i n 2

_r pr = NOMI NAL( 0. 659/ 3. 25)= 0. 25 i n.







zzl e M Rei nf or cement Requi r ement s >er API - 650 Sect i on 3. 7. 2 and other r ef erences bel ow)

OZZLE Descr i pt i on : 36i n. STD FF








= [ 4 * ( 0. 375) + 0. 125] * ( 0. 375) * 1= 0. 609 i n 2

A_r pr = 7. 134 - - 2. 603 - 0. 609= 9. 128 i n 2

_r pr = NOMI NAL( 9. 128/ 36. 25)= 0. 3125 i n.

ed on Shel l Nozzl e Si ze of 36 i n. ,d Si ze ( OD) Must be 72. 75 i n.






zzl e V Rei nf or cement Requi r ement s >er API - 650 and ot her r ef erences bel ow)

OZZLE Descr i pt i on : 6i n. STD RFWN


t _Basi s = 0. 1284 i n.


i nce Roof Nozzl e si ze <= 6 NPS,_r pr = 0 i n.

Repad Requi r ed per FOOTNOTE A, Tabl e 5- 14





ACI TI ES and WEI GHTS

Maxi mum Capaci t y ( t o upper TL) : 9, 999 galDesi gn Capaci t y ( t o Max Li qui d Level ) : 9, 998 galMi ni mum Capaci t y ( t o Mi n Li qui d Level ) : 0 galNetWorki ng Capaci t y ( Desi gn - Mi n. ) : 9, 998 gal

New Condi t i on Cor r oded- - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - -el l 4, 917 l bf 2, 460 l bf

of Pl at es 1, 608 l bf 1, 338 l bf t t om 1, 586 l bf 1, 057 l bf i f f ener s 113 l bf 113 l bf zzl e Wgt 0 l bf 0 l bf sc Roof Wgt 0 l bf 0 l bf sc Shel l Wgt 500 l bf 500 l bf sul at i on 0 l bf 0 l bf - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - -t al 8, 724 l bf 5, 468 l bf

ht of Tank, Empt y : 8, 724 l bf ht of Tank, Ful l of Product ( SG=1. 23) : 111, 362 l bf ht of Tank, Ful l of Water : 92, 170 l bf Worki ng Wei ght , Ful l of Product : 111, 352 l bf Worki ng Wei ght , Ful l of Water : 92, 161 l bf

dat i on Ar ea Req' d : 98 f t 2

dat i on Loadi ng, Empt y : 89. 02 l bf / f t 2dat i on Loadi ng, Ful l of Product ( SG=1. 23) : 1, 136 l bf / f t 2dat i on Loadi ng, Ful l of Wat er : 940. 51 l bf / f t 2

ACE AREAS105 f t 2

l 483 f t 2om 98 f t 2

d Moment 53, 309 f t - l bf mi c Moment 34, 897 f t - l bf

CELLANEOUS ATTACHED ROOF I TEMS

CELLANEOUS ATTACHED SHELL I TEMSer : 3 : 500 l bf





& MAWV SUMMARY FOR NEW J OB 1

MUM CALCULATED I NTERNAL PRESSURE

MAWP = 15 PSI or 415. 7 I N. H2O ( per API - 620)

MAWP = Maxi mum Cal cul ated I nternal Pr essure ( due t o shel l )= 15 PSI or 415. 7 I N. H2O

MAWP = Maxi mum Cal cul ated I nternal Pr essure ( due t o r oof )

( Roof al so Per F. 1. 3 and F. 7. 5. c)= 10. 2429 PSI or 283. 87 I N. H2O

ANK MAWP = 10. 2429 PSI or 283. 87 I N. H2O

MUM CALCULATED EXTERNAL PRESSURE

MAWV = Maxi mumCal cul at ed Ext ernal Pressur e ( due t o shel l )= - 0. 4304 PSI or - 11. 93 I N. H2O

MAWV = Maxi mumCal cul at ed Ext ernal Pressur e ( due t o r oof )= - 10. 3619 PSI or - 287. 17 I N. H2O

MAWV = Maxi mum Cal cul ated Ext ernal Pr essure ( due t o bot t om pl ate)= - 0. 3499 PSI or - 9. 7 I N. H2O

ANK MAWV = - 0. 3499 PSI or - 9. 7 I N. H2O

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Sluryy Tank Report