Slide môn Mạng Giảng viên Đỗ Trọng Tuấn

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  • 8/10/2019 Slide mn Mng Ging vin Trng Tun

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    1. Mt s khi nim

    Tnh ton dung lng

    trong mng GSM

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    Khi nim lu lng

    Lu lng - traffic:

    L thng tin (ngi s dng/bo hiu) mang trncc knh truyn dn

    Lu lng gi bn (Busy hour traffic):

    Thi gian chim knh trong gi bnA = C*t/T = C*t/3600

    [Erlangs = (Calls/busy hour)*(mean call holding time) ]

    Trong : A: lu lng [Erl]C: s cuc gi trong gi bn

    t: thi gian trung bnh ca mt cuc gi (s)

    T: thi gian kho st = 1h = 3600 s

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    Gi bn B.H - Busy Hour

    B.H l gi c lu lng trao i qua cc knh ln nht trong ngy v

    c xc nh theo s liu thng k.(Busy hour is that continuous 60 minutes time span of the day during

    which the highest usage occurs).

    Note:

    may not occur at the same time every day

    weekly variation

    week day /weekend variation

    seasonal variation

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    V d

    Cho bit ti lu lng ca MS l bao nhiu khi thu bao di ng

    tin hnh 2 cuc gi trong gi bn vi thi gian trung bnhl 90 s.

    Ti lu lng Lu lng gi bn (Busy hour traffic):

    A = C*t/T = C*t/3600 = 2*90/3600 = 50 mErl

    ngha: thi gian chim knh ti gi bn ca MS l 180 s

    tng ng vi ti lu lng 50 mErl

    Thi gian trung bnh 1 cuc gi ca MS trong gi bn khong50 s90 s

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    Traffic Density / Intensity

    Mt lu lng - Traffic Density is defined as the number

    of simultaneous calls at a given moment.

    Cng lu lng - Traffic Intensity represents the

    average traffic density (occupancy) during any one hour

    period.

    Chim knh- occupancy is any use of of a traffic resource

    regardless of whether or not a connection (call) is completed.

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    Quan h gia cc loi lu lng

    Thit lp cuc gi

    (knh bo hiu)

    Knh

    lu lng

    Ao

    Ab

    Ac= Ao Ac

    Ab

    Ao= Ac+ Ab

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    Cp dch v GoS (Grade of Service)

    Khi nim:GoS l thng s nh gi xc sut lu lngnghn (Ab) i vi mt s knh xc nh:

    GoS = Ab/ Ao

    Quan h gia lu lng v cp dch v GoS:Ab= GoS * Ao

    Ac= (1 - GoS) * Ao

    Gi tr GoS in hnh ca mng PLMN = 2%

    -> lu lng nghn = 2% ; lu lng thc hin = 98%

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    Quan h gia lu lng v GoS

    Thit lp cuc gi

    (knh bo hiu)

    Knh

    lu lng

    Ao

    Ab

    Ac= Ao Ac

    Ab

    A

    c= f(Ao) = ?

    Ac= (1-GoS)Ao = (1-GoS)*(1-GoS)*Ao

    GoS GoS

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    Loss and Delay Systems

    H thng tn tht- A Loss System is one in which a callattempt is rejected when there is no idle resource to serve

    the call. (GSM system)

    Blocked callscuc gi b nghn

    Resource = signalling channels + traffic channels

    H thng tr- A Delay System is one in which call

    attempts are held in a waiting queue until resource are

    available to serve the calls.

    Delayed calls

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    M hnh Erlang B

    L m hnh h thng thng tin theo kiu tn tht.

    M hnh Erlang B c s dng tnh ton dung lng cho mng

    thng tin di ng GSM.

    Bng Erlang B: tra cu thng s theo m hnh Erlang B

    * Th hin mi quan h gia 3 i lng:- S knh c s dng N

    - Cp dch v GoS

    - Lu lng yu cu Ao

    * Khi bit 2 thng s => tra cu thng s th 3

    [*] V d:

    Hy xc nh lu lng thc hin ca 6 knh c GoS = 2%

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    Bng Erlang B

    Ao = 2,2759 Erl

    Ac = (1-GoS)Ao = (1 - 0,02)*2,2759 = 2,2304 (Erl)

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    Hiu sut s dng knh

    Khi nim: L t s gia lu lng p ng v s knh

    c s dng:

    = Ac*100/ N (%)

    Vi v d trn: N = 6, GoS = 2% ; Ac = 2,2304 Erl

    = Ac/ N = 2,2304*100/6 = 37%

    = ? Khi GoS = 10%

    = Ac/ N = 3,3826*100/6 = 56%

    Nhn xt: Hiu sut s dng knh thp -> xc sut nghn

    nh -> GoS nh -> cht lng tt.

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    2. Tnh ton vng ph sng

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    Bi ton

    Cn quy hoch vng ph sng cho th trn C, s dng cng ngh

    GSM900, dng 3 cp tn s cho mi cell vi cu hnh cp pht knh

    bo hiu chun. Yu cu GoS = 2% vi mc lu lng d on c

    th hin nh hnh v. Gi thit mi thu bao tin hnh 2 cuc gi

    trong gi bn vi thi gian trung bnh ca mt cuc gi l 90 s.[*] Hy xc nh:

    - Lu lng gi bn d kin trn 1 km2

    - Dung lng ca 1 cell.

    - Bn knh cc i ca cell (din tch cell hnh lc gic S = 2,6 R2)

    - S cell cn thit ph sng cho c th trn C.

    - Lp li cc php tnh trn khi cp pht 4 tn s cho mi cell.

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    Mc lu lng d on th trn C

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    Li gii

    1. T hnh v ta c MS tch cc trong B.H l: 40 MS/km2

    - Ti lu lng ca 1 MS l A = 2*90/3600 = 0,05 (Erl) Lu lng d kin trn 1 km2 trong gi bn l:

    40 MS/km2* 0,05 Erl/MS = 2 Erl/km2

    2. Mi cell c cp pht 3 cp tn s, s dng cu hnhknh bo hiu chun ti C0 , nh sau:

    TS1TS0 TS3TS2 TS5TS4 TS7TS6

    BCCH/CCCH SDCCH/8 TCH

    TS1TS0 TS3TS2 TS5TS4 TS7TS6

    TS1TS0 TS3TS2 TS5TS4 TS7TS6

    RFC1

    RFC2

    RFC3

    Sngmang

    C0

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    Bng Erlang B

    Ao = 14,896 Erl

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    - S knh lu lng ti mi cell l: 3*8 2 = 22 (TCH)

    - Khi GoS = 2%, lu lng yu cu ca 1 cell l: 14,896 Erl

    - Khi ti lu lng ca 1 MS l 33 mErl, s thu bao c th c

    phc v trong 1 cell l: 14,896/0,033 451 MS

    3. Din tch 1 cell l:

    S = lu lng c cell / lu lng trn 1 km2

    = 14,896 (Erl) / 2 (Erl/km2) = 7,448 (km2)

    => Bn knh cc i ca cell : R = (7,448/2,6)0,5 = 1,69 (km)

    4. S cell ph sng c th trn C:

    Ncell = Din tch th trn/Din tch 1 cell=35/7,448 5 (cell)

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    B mnK thut Thng tin

    H ni, 9 - 2007

    Email: [email protected]

    Ging vin Trng Tun

    Trng i Hc Bch Khoa H NiKhoa in t -Vin thng

    Mn hc:Thng tin di ng

    ( Mobile Communications )