SKEMA PRAKTIS BESTARI JUJ KIMIA SET 2 KERTAS 1, 2 & 3

4541 Set 2 © Hak Cipta JUJ Pahang 2017 1

SKEMA JAWAPAN KERTAS 1

JUJ KIMIA SET 2 - 2017

1 D 11 C 21 A 31 D 41 C

2 C 12 B 22 D 32 C 42 A

3 C 13 B 23 C 33 A 43 B

4 C 14 B 24 D 34 A 44 B

5 A 15 C 25 A 35 A 45 A

6 B 16 C 26 C 36 B 46 D

7 B 17 C 27 C 37 A 47 A

8 C 18 A 28 B 38 D 48 B

9 C 19 D 29 D 39 B 49 B

10 B 20 B 30 B 40 C 50 C

SKEMA PRAKTIS BESTARI JUJ KIMIA SET 2 KERTAS 1, 2 & 3

4541 Set 2 © Hak Cipta JUJ Pahang 2017 2

MARKING SCHEME PAPER 2 SET 2 JUJ CHEMISTRY 2017

Question No Mark Scheme Sub

Mark

Mark

1 (a) (i) smallest neutral particles 1 1

(ii)

1

1

(iii) electron 1 1

(iv) 1. One similarity

2. one different

Sample answer :

1. Same number of proton /proton number // same number of

electron

2. Different number of neutron / nucleon number

1

1

2

(b) (i) 70 / 70oC 1 1

(ii) 1. Heat energy absorbed

2. is used to overcome the forces of attraction between particles

1

1

2

(iii) Correct arrangement (at least 3x3 with same size & do not

overlapping each other)

1 1

Total marks 9

Question No Mark Scheme Sub

Mark

Mark

2 (a) (i) The chemical formula that shows the simplest ratio of atoms of each

element in the compound

1 1

(ii) C2H4O 1 1

(b) 1. value of n

2. Molecular formula

Sample answer :

(CH2) n = 42 // (12+ 2(1))n = 42 // 14n = 42 // n = 3

Molecular formula = C3H6

1

1

2

(c) (i) Mass 1 1

(ii) 64 + 2(14)+ 6(16) // 188 1 1

(iii) Correct value with unit

Answer : 1.2 X 188 g // 225.6 g

1 1

(iv) 1. Correct formula of reactants and product

2. balanced

Answer : 2Cu(NO3)2 2CuO + 4NO2 + O2

1

1

2

Total marks 9

SKEMA PRAKTIS BESTARI JUJ KIMIA SET 2 KERTAS 1, 2 & 3

4541 Set 2 © Hak Cipta JUJ Pahang 2017 3

Question No Mark scheme Sub

mark

mark

3 (a) (i) Chlorine/Cl 1 1

(ii) Aluminium 1 1

(iii) Argon atom has achieved stable octet electron arrangement 1 1

(b) (i) Cl 1 1

(ii) The forces of attraction between nucleus and electron in Cl

atoms is stronger than Na atom.

1 1

(c) (i) Ionic bond 1 1

(ii)

1.Correct number of ion and nucleus is labelled

2.Correct electron arrangement and charged

1

1

2

(iii) 1. Soluble in water//

2. High melting and boiling point//

3. Conduct electricity in aqueous and molten state

Any two

1 + 1

2

Total marks 10

Question No Mark scheme Sub

mark

mark

4 (a) (i) Silicon dioxide / silica 1 1

(ii) stabiliser /emulsifier 1 1

(iii) Flavouring agent//thickening agent//colouring agent 1 1

(iv) Analgesic // paracetamol 1 1

(b) (i) N2+3H2 2NH3

1. Correct formula of reactants and products

2. Balanced equation

1

1

2

(ii) 1. Type of fertilizer

2. % of N in urea

3. % of N in ammonium sulphate

4. Conclusion

Answer:

Urea.

% of N in urea %of N in ammonium sulphate

=(28/60) x100% =(28/132) x 100%

=46.67% = 21.21%

% of nitrogen atom by mass for urea is higher than

ammonium sulphate

1

1+1

1

4

Total marks 10

+ -

Na Cl

SKEMA PRAKTIS BESTARI JUJ KIMIA SET 2 KERTAS 1, 2 & 3

4541 Set 2 © Hak Cipta JUJ Pahang 2017 4

Question No Mark Scheme Sub

Mark Mark

5 (a) (i) Increase of hydrogen gas per unit time // decrease of mass of

zinc per unit time

1 1

(b) (i) 1. draw the triangle

2. calculation

43.5-29 cm3

// 14.5 cm3 // 0.242 cm

3 s

-1

120-60 s 60 s

1

1

2

(ii) 41-26 cm3 s

-1 // 15 cm

3 s

-1 // 0.25 cm

3 s

-1

120-60 60

1 1

(iii) Because the concentration of acid decrease with time 1 1

(c) (i) Volume of gas / cm3

Set II

Set I

Time / s

1

1

(ii) 1. size of zinc is smaller

2. remain the volume and concentration of hydrochloric acid.

1

1

2

(d) (i) Put 5 g/a packet of fine sugar in hot water and cold water in two

cups. Sugar in hot water dissolve faster.

1

1

(ii) 1. temperature higher in hot water

2. water particles has higher kinetic energy

1

1

2

Total Marks 11

Question No Mark Scheme Sub

Mark Mark

6(a) (i) Na+ , NO3

- , H

+ , OH

- (accept name of ions) 1 1

(ii) 1. hydrogen ions 1 1

(iii) 1. put glowing wooden splinter into a test tube

2. The wooden splinter lights up

1

1

2

(iv) 1. Suggest the suitable electrode (can infer from diagram)

2. functional diagram

3. correct label :

Anode : silver electrode ; Cathode : iron spoon

Electrolyte : silver nitrate solution

1

1

1

3

silver

Silver nitrate

solution

Iron

spoon

SKEMA PRAKTIS BESTARI JUJ KIMIA SET 2 KERTAS 1, 2 & 3

4541 Set 2 © Hak Cipta JUJ Pahang 2017 5

Question No Mark Scheme Sub

Mark Mark

(b) (i) 1. Anode : Zn Zn2+

+ 2e

2. Cathode : Cu2+

+ 2e Cu

1

1

2

(iii) 1. Change copper electrode to silver electrode // change zinc

electrode to magnesium electrode// any suitaible pair of

electrodes

2. Reason :

Distance between Ag and Zinc / Mg and Cu in

electrochemical series is further

1

1

2

Total Marks 11

Question No Mark Scheme Sub

Mark Mark

7 (a) (i) 1. structural formula

2. name

*

*Any two isomer

1+1

1+1

4

(ii) 1. Reaction I = esterification

Functional

group

Homologous

series

name

X //

Carbon-carbon

double bond

Alkene But-1-ene

Y

//

Carboxyl group

Carboxylic acid Butanoic acid

z

//

carboxylate

group

ester Butyl

etanoate

1

1+1+1

1+1+1

1+1+1

10

Butan -2-ol

2-methylpropan-1-ol

2-methylpropan-2-ol

SKEMA PRAKTIS BESTARI JUJ KIMIA SET 2 KERTAS 1, 2 & 3

4541 Set 2 © Hak Cipta JUJ Pahang 2017 6

Question No Mark Scheme Sub

Mark Mark

(b) 1. Correct formula of reactants and product

2. balanced

C3H8 + 5O2 3CO2 + 4H2O

3 & 4. Calculation

Propene

Propane

% of carbon 3(12) x 100

42

= 85.71%

3(12) x 100

44

= 81.81%

5. % of carbon atom by mass in propene is higher than

propane.

6. Propene produces more soot than propane

1

1

1+1

1

1

6

Total Marks 20

Question No Mark scheme Sub

mark

mark

8 (a) 1. V = sodium carbonate

2. W= copper(II) sulphate

3. X = nitric acid

4. Y = copper(II) oxide

5. Z= Carbon dioxide

1

1

1

1

1

10

6. Double decomposition reaction // precipitation reaction 1

Correct formula of reactants

7 & 8. Reaction I : Na2CO3 + CuSO4 CuCO3 + Na2SO4

9& 10. Reaction II : CuCO3 + HNO3 Cu(NO3)2 + CO2 +H2O

2+2

(b) Compare and contrast :

Similarities :

1. Both experiment produce black residue

2. Both experiment released gas when heated

Differences:

3. Exp I produced colourless gas and Exp II produced brown gas

4. Exp 1 turns the limewater chalky and Exp II turns moist blue

litmus paper to red

* Choose any 3

1+1+1

6

4. mole

5. ratio mole

6. correct answer with unit

Answer :

Mol = 6.2/124 // 0.05

Ratio : 1 mol CuCO3 : 1 mol CO2

0.05 mol CuCO3 : 0.05 mol CO2

Answer : 0.05 x 24 dm3 // 1.2 dm

3

1

1

1

SKEMA PRAKTIS BESTARI JUJ KIMIA SET 2 KERTAS 1, 2 & 3

4541 Set 2 © Hak Cipta JUJ Pahang 2017 7

Question No Mark scheme Sub

mark

mark

(c) 1.Egg shells contain calcium carbonate

2. Calcium carbonate can react with acid

3. Calcium carbonate can dissolved in acid

4. Egg shell becomes soft//easier to insert in the bottle

1

1

1

1

4

Total Marks 20

Question

No

Mark scheme Sub

mark

mark

9 (a) Elephant Toothpaste Cold Pack

Types

of

reaction

Exothermic Endothermic

Energy

profile

diagram

-Correct level and label

energy

-correct equation & H

-Correct level and label

energy

-correct equation & H

Total

energy

content

Total energy content of the

reactants is higher than

products

Total energy content of

the products is higher

than reactants

1+1

1+1

1+1

1+1

8

(b) (i) 1. State solution A,

2. solution B

3. precipitate D (can infer from procedure)

4-9. procedure

10. data

11-12. calculation

Sample answer :

1. Solution A = sodium chloride solution

2. solution B silver nitrate solution,

3. Precipitate D = silver chloride

Procedure :

4. Measure [20 – 100 cm3] of sodium chloride [any suitable

solution] [0.5 – 2.0 moldm-3

] solution and pour the solution into a

plastic/polystryrene cup

5.Measure [20 – 100 cm3] of silver nitrate [any suitable solution]

[0.5 – 2.0 moldm-3

] solution and pour the solution into another

plastic/polystryrene cup

6. record initial temperature for both solutions

1

1

1

1

1

1

SKEMA PRAKTIS BESTARI JUJ KIMIA SET 2 KERTAS 1, 2 & 3

4541 Set 2 © Hak Cipta JUJ Pahang 2017 8

Question

No

Mark scheme Sub

mark

mark

7. pour sodium chloride solution quickly into the silver nitrate

solution

8.stir the mixture

9. record the highest temperature reached

10. Initial temperature of sodium chloride solution = T1oC

Initial temperature of silver nitrate solution = T2 o

C

Average Initial temperature = (T1+ T2)/2 = Ta oC

Highest temperature = Tb oC

11. heat given out = mc = 200 x 4.2 x (Tb – Ta)

1000

= w kJ

12. number of mol = 50 x 1 /1000 = 0.05

13. Heat of precipitation = - w/0.05 = -X kJmol-1

1

1

1

1

1

1

1

max12

Total Marks 20

Question Answer Sub

mark

marks

10 (a)(i) 1. suitable metal R : Zn/Mg

Zn/Mg CuSO4

Types of

reaction

2. oxidation 3. reduction

Half

equation

4. Zn Zn2+

+ 2e 5. Cu2+

+ 2e Cu

6. Name the ion present in the colourless solution = copper(II) ions

1

1+1

1+1

1

6

(a)(ii)

Zn/Mg CuSO4

Change in

oxidation

number

1. 0 +2 2. +2 0

Role 3. Reducing agent 4. Oxidizing agent

1+1

1+1

4

(b) Sample answer :

1. Metal : Zn/Al

Procedure :

2. Clean Zn/Al strip and iron nail with sand paper

3. Coil Zn/Al strip around the iron nail and put in a test tube

4. Put the iron nail only into another test tube.

5. Pour the hot agar-agar/jelly solution that has been mixed with

potassium hexacyanoferrate(III) and phenolphthalein indicator until

the iron nail immersed into both test tube.

1

1

1

1

1

SKEMA PRAKTIS BESTARI JUJ KIMIA SET 2 KERTAS 1, 2 & 3

4541 Set 2 © Hak Cipta JUJ Pahang 2017 9

Question Answer Sub

mark

marks

6. Leave the test tubes aside for a few days.

7. Observation

Pair of metal Observation

Zn/Al and iron nail pink spot form

Iron nail Blue spot form

Half equation for oxidation of metals

8. Test tube I : Zn Zn2+

+ 2e

9. Test Tube II : Fe Fe2+

+ 2e

10. Conclusion

When a more electropositive metal is in contact with iron, the metal

inhibits rusting //

iron does not rust when in contact with a more electropositive metal

1

1

1

1

1

10

Total marks 20

END OF MARKING SCHEME PAPER 2

SKEMA PRAKTIS BESTARI JUJ KIMIA SET 2 KERTAS 1, 2 & 3

4541 Set 2 © Hak Cipta JUJ Pahang 2017 10

PERATURAN PEMARKAHAN KIMIA KERTAS 3 JUJ SET 2 2017

Question Rubric Score

1(a)

Able to state the colour change correctly

Answer:

Pink colour change to colourless

3

Able to state the colour change less correctly

Sample answer:

Purple to colourless

2

Able to state an idea of colour

Sample Answer:

Pink // Colourless// Purple

1

No response or wrong response 0

Question Rubric Score

1(b)

Able to record all burette readings accurately to 2 decimal

places

Answer:

Titration Initial reading (cm3) Final reading (cm

3)

I 0.00 26.00

II 0.50 24.50

III 5.50 30.50

3

Able to record all the burette readings correctly to 1 decimal

places or able to record at least 4 reading correctly // uniform

decimal places

2

Able to record at least 2 burette reading correctly without

decimal places

1

No response or wrong response 0

SKEMA PRAKTIS BESTARI JUJ KIMIA SET 2 KERTAS 1, 2 & 3

4541 Set 2 © Hak Cipta JUJ Pahang 2017 11

Question Rubric Score

1(c)

Able to consruct a table that contains the following information.

1. Hading in the table : Set, Initil reading/cm3, Final reading/cm

3,

Volume of acid/cm3

2. Transfer all the burette readings from 1(b) correctly

3. With unit at the heading

Sample answer:

Titration Initil reading/cm3

Bacaan awal/cm3

Final

reading/cm3

Bacaan

akhir/cm3

Volume of

acid/cm3

Isipadu asid/cm3

I 0.00 26.00 26.00

II 0.50 24.50 24.00

III 5.50 30.50 25.00

3

Able to construct a table less correctly

2

Able to construct a table that contains the following information

1. Headings in the table : suitable heading

2. 2 column with heading without data/

2 column only

Sample answer:

Initial reading

Final reading

1

No response or wrong response 0

SKEMA PRAKTIS BESTARI JUJ KIMIA SET 2 KERTAS 1, 2 & 3

4541 Set 2 © Hak Cipta JUJ Pahang 2017 12

Question Rubric Score

1(d)

Able to calculate the average volume and concentration of

hydrochloric acid with unit correctly

Answer:

Average volume of hydrochloric acid

= 26.00 + 24.00 + 25.00

---------------------------- = 25.00 cm3 --- p1

3

Concentration of hydrochloric acid

MHCl VHCl = 1

MNaOH VNaOH 1

MHCl X 25.00 = 1

1.0 X 50.00 1 ---- p2

// 25.00 MHCl = 50.00

MHCl = 50.00

25.00

= 2.0 mol dm-3

---- p3

3

Able to calculate the average volume and concentration of

hydrochloric acid correctly without unit

2

Able to calculate volume of acid OR concentration of acid

correctly

1

No response or wrong response 0

Question Rubric Score

1(e)

Able to classify all the acids into strong and weak acid correctly

Strong acids

Asid kuat

Weak acids

Asid lemah

Sulfuric acid

Nitric acid

Citric acid

Ethanoic acid

3

Able to classify at least 3 acids correctly 2

Able to classify at least 2 acids correctly/reverse 1

No response or wrong response 0

SKEMA PRAKTIS BESTARI JUJ KIMIA SET 2 KERTAS 1, 2 & 3

4541 Set 2 © Hak Cipta JUJ Pahang 2017 13

Question Rubric Score

2(a)

Able to state all inferences correctly

Test tube A B C D

Inference Iron nail

does not

rust //Fe2+

does not

present

Iron nail

rust // Fe2+

Present /

formed

Iron nail

does not

rust // Fe2+

does not

present

Iron nail

rust // Fe2+

Present /

formed

3

Able to state 3 inferences correctly 2

Able to state 2 inferences correctly 1

No response or wrong response 0

Question Rubric Score

2(b)

Able to state the relationship between manipulated varible and

responding variable with direction correctly

Sample answer:

When a more/less electropositive metal / higher/lower than iron

in Electrochemical series is in contact with iron, iron (nail) does

not rust/rust

3

Able to state the hypothesis less correctly

Sample answer:

The rusting of iron is faster / slower, if a less / more

electropositive metal is in contact with iron/Fe

2

Able to give an idea of hypothesis

Sample answer:

Iron rust when in contact with other metal // other metal affect

the rusting of iron.

1

No response or wrong response 0

Question Rubric Score

2(c)

Able to state all the variables correctly

Sample answer:

Manipulated variable : Type / different electropositive metal

Responding variable : Rusting // presence of blue sport

Constant variable : Type of iron nail // iron //medium in

which the iron are kept

3

Able to state any two of variables in this experiment correctly 2

Able to state any two of variables in this experiment correctly 1

No response or wrong response 0

SKEMA PRAKTIS BESTARI JUJ KIMIA SET 2 KERTAS 1, 2 & 3

4541 Set 2 © Hak Cipta JUJ Pahang 2017 14

Question Rubric Score

2(d)

Able to give one operational definition of the experiment

correctly with the following aspects:

i) what you do

ii) what you observe

Sample answer:

1. when iron nail is coiled/in contact with a less

electropositive metal (copper)/metal located below iron in

electrochemical series

2. Rusting of iron is the formation of blue spot/colouration

3

Able to state at least two criteria correctly

Sample answer:

Rusting of iron is the formation of blue spot /colouration

or

when iron nail is coiled/in contact with a less electropositive

metal

2

Able to state an idea of operational definition

Sample answer:

Blue spot/rusting occur

1

No response or wrong response 0

Question Rubric Score

2(e)

Able to predict the observation correctly

Answer:

The intensity of blue spot/colouration is very high//higher than

test tube B.

3

Able to predict the observation

Sample answer:

The intensity of blue spot/colouration is high

2

Able to predict the observation

Sample answer:

Blue spot/colour

1

No response or wrong response 0

SKEMA PRAKTIS BESTARI JUJ KIMIA SET 2 KERTAS 1, 2 & 3

4541 Set 2 © Hak Cipta JUJ Pahang 2017 15

Question Rubric Score

2(f)

Able to state the relationship correctly between the time taken

and the amount of rust form correctly

1. Time taken

2. Formation of rust

3. Comparison

Sample answer:

The longer the time taken, the bigger/greater/larger the rust form

//the longger the time taken, more rust is form

//the rust form is greater/bigger/larger when the time taken is

longer

//the rust form in one week is more/bigger/greater/larger than one

day

3

Able to state the relationship between the time taken and the

amount of rust form less correctly

1. Time taken/Formation of rust

Sample answer:

The rust form is bigger/greater/larger

//the form is directly proportional to the time taken

2

Able to state any idea of relationship

Sample answer:

The rust is form/change//rust is small/less

1

No response or wrong response 0

SKEMA PRAKTIS BESTARI JUJ KIMIA SET 2 KERTAS 1, 2 & 3

4541 Set 2 © Hak Cipta JUJ Pahang 2017 16

Question Rubric Score

3(a)

Able to give the problem statement correctly

Sample answer:

How does the effectiveness of cleansing action of two different

types of cleansing agent in hard water?

// What is the difference in effectiveness of cleansing action in

hard water using soap and detergent?

3

Able to give the problem statement less correctly

Sample answer:

How does different type of cleansing agent affect the

effectiveness of cleansing action in hard water?

// To investigate the effectiveness of different type of cleansing

agent in hard water.

2

Able to give an idea of statement of the problem

Sample answer:

To study the effectiveness of cleansing action in hard water

1

No response or wrong response 0

Question Rubric Score

3(b)

Able to state all variables correctly

Sample answer:

Manipulated variable :Types of cleansing agent//soap and

detergent

Responding variable : Effectiveness of cleansing agent//ability

to remove the oily stains on cloth

Constant variable : Hard water//Cloth with oily stains//Size

of cloth

3

Able to state any two variables correctly 2

Able to state any one variable correctly 1

No response or wrong response 0

SKEMA PRAKTIS BESTARI JUJ KIMIA SET 2 KERTAS 1, 2 & 3

4541 Set 2 © Hak Cipta JUJ Pahang 2017 17

Question Rubric Score

3(c)

Able to state the relationship between the manipulated variable

and the responding variable correctly

Sample answer:

Detergent is more effective than soap in hard water.

// Detergent in hard water can remove the oily stains on cloth

while soap cannot.

3

Able to state the relationship between the manipulated variable

and the responding variable incorrectly

Sample answer:

Detergent is more effective

// Soap is less effective

// Detergent in hard water can remove the oily stains on

cloth

//soap cannot remove stain on cloth.

2

Able to state an idea of hypothesis 1

No response or wrong response 0

Question Rubric Score

3(d)

Able to give the completely list of the apparatus and materials

Answer:

Apparatus:

Beakers, measuring cylinder, glass rod

Material:

Soap, detergent, [cleansing agent X dan cleansing agent Y],

0.5 - 1 mol dm-3

magnesium sulphate solution/[sea water/hard

water], 2 pieces of cloth with oily stains.

3

Able to give the list of the apparatus and materials correctly but

not completely

Answer:

Apparatus:

Any containers, glass rod

Material:

Cleansing agent, cloth with oily stains.

2

Able to give two materials and at least one apparatus

Answer :

Material:

Soap solution / detergent, hard water

[any container]

1

No response or wrong response 0

SKEMA PRAKTIS BESTARI JUJ KIMIA SET 2 KERTAS 1, 2 & 3

4541 Set 2 © Hak Cipta JUJ Pahang 2017 18

Question Rubric Score

3(e)

Able to state all procedures correctly

Sample answer :

1. Label 2 beakers as A and B respectively

2. Fill all the beakers with [50 - 100 cm3 ]of hard water /

magnesium sulphate solution

3. Add cleansing agent X/detergent in beaker A and

cleansing agent Y/soap in bikar B.

4. Place a piece of cloth with oily stain into each beaker

5. Stir the solution in each beaker using glass rod until no

change can be observed

6. Wash the oily stain on each piece of cloth using the

solution in each beaker

7. Record the observation.

3

Able to state three steps of procedures correctly

Steps 2, 3, 5, 6,

2

Able to state two steps of procedures correctly

Steps 2, 3, 6

1

No response or wrong response 0

PERATURAN PEMARKAHAN TAMAT

Question Rubric Score

3(f)

Able to exhibit the tabulation of data that includes the following

information.

1. Headings

Sample answer :

Beaker Observation

A

B

2

Able to tabulate the data incompletely

1. Titles without unit

Sample answer:

Beaker

1

No response given / wrong response 0