Dimenzionalna analiza, Mehanika fluida M

Embed Size (px)

DESCRIPTION

Predavanja iz mehanike fluida M, Masinski fakultet.

Citation preview

  • 5/21/2018 Dimenzionalna analiza, Mehanika fluida M.

    1/10

    CFD

    CD

    CD =CD(Re)

    http://-/?-
  • 5/21/2018 Dimenzionalna analiza, Mehanika fluida M.

    2/10

    n

    Qi i= 1, 2, . . . , n

    F(Q1, Q2, . . . , Qn) = 0,

    F

    Qi

    m

    F(1, 2, . . . , m) = 0.

    p = n m Qi

    Q Qj Qk Ql

    i=Qxj Q

    yjQ

    zl Qi i= n 3.

    x , y, z

    [i] = [Qxj ] [Q

    yj ] [Q

    zl ] [Qi].

    n

    n

    p

    p

    n

    p

    p

    Qi

    Qi = Qj = Qk =U Ql =D

    =xUyDz

    http://-/?-
  • 5/21/2018 Dimenzionalna analiza, Mehanika fluida M.

    3/10

    = UD

    =Re1

    =xUyDz 1

    = UD

    = Re

    x,y,z

    SI

    MLT

    m kg M

    L m L

    t s T

    A m2 L2

    V m3 L3

    U m/s LT1

    a m/s2 LT2

    F N MLT1

    M Nm ML2T2

    E

    W J ML2T2

    P W ML2T3

    kg/m3 ML3

    m kg/s MT1

    V m3/s LT1

    p

    Pa ML1T2

    Sij s1 T1

    rad

    rad/s T1

    Pa s ML1T1

    m2/s L2T1

  • 5/21/2018 Dimenzionalna analiza, Mehanika fluida M.

    4/10

    p= f(U,,,L,D).

    D [mm] L [m] V [m3/h] p [Pa] [kg/m3] [Pa s]

    2.92 104

    2.92 104

    2.92 104

    1 103

    1 103

    1 103

    1.56 103

    1.56 103

    1.56 103

    p

    L

    n = 6

    F(p, U, , , L, D) = 0

    p

    =M L1T2

    U

    =LT1

    =M L3

    =M L1T1

    L

    =L

    D

    =L

    {MLT}

    m = n p = 6 3 = 3

  • 5/21/2018 Dimenzionalna analiza, Mehanika fluida M.

    5/10

    pU

    ,,D

    p=xyDz p, U=

    abDc U, L = deDf L

    p

    M0L0T0 = (ML3)x (ML1T1)y Lz ML1T2

    x + y+ 1 = 03x y+ z 1 = 0y 2 = 0

    x= 1y= 2z= 2

    ,

    p =D2 p

    2

    U

    M0L0T0 = (ML3)a (ML1T1)b Lc LT1

    a+ b= 03a b+ c 1 = 0b 1 = 0

    a= 1b= 1c= 1

    ,

    U= UD

    =

    UD

    =Re

    L

    M0L0T0 = (ML3)e (ML1T1)f Lg L

    e + f= 03e f+ g+ 1 = 0b= 0

    e= 0f= 0

    g= 1,

    L= L

    D

    F1(p, U, L) = 0 F1D2 p

    2

    , Re, L

    D = 0

    D2 p

    2 =F

    Re,

    L

    D

  • 5/21/2018 Dimenzionalna analiza, Mehanika fluida M.

    6/10

    D L V p 104 U 104Re 109p L/D

    [mm] [m] [m3/h] [Pa] [kg/m3] [Pa s] m/s

    2.92

    2.471 3.732

    2.92

    4.942 17.78

    2.92

    8.236 56.46

    10

    1.765 0.8303

    10 3.53 4.192

    10

    15.6

    15.6

    log p log Re

    L/D

    L/D

    log p log Re

    1e+06

    1e+07

    1e+08

    1e+09

    1e+10

    1e+11

    10000 100000

    logRe

    log

    p

    log

    (p

    /L

    )

    p Re p/L Re

    L

    D= 200

    0.155Re1.75

  • 5/21/2018 Dimenzionalna analiza, Mehanika fluida M.

    7/10

    D3 p

    2L =f(Re)

    p L

    log

    pL

    = 1.75log Re 0.8097,

    pL

    = 0.155 Re1.75 D3 p

    2L = 0.155 Re1.75

    D3 p

    2L = 0.155

    UD

    1.75

    p U1.75

    U

    D

    FDU2D2

    =f

    UD

    w

    U

    D

    wU2

    =f

    UD

    ,

    L

    D

    P

    V

    D

    P

    3D5 =f

    V

    D3,D2

  • 5/21/2018 Dimenzionalna analiza, Mehanika fluida M.

    8/10

    D

    U

    H/L

    H L N

    D

    U =f

    N,

    H

    L

    Re 1

    U

    L

    Cc c

    FD/(0.5U2A)

    d

    FD = 3Ud Cc

    FD = const U L; Cc= FDU L

    = const;

    Cc= 3

  • 5/21/2018 Dimenzionalna analiza, Mehanika fluida M.

    9/10

    m

    Um = U

  • 5/21/2018 Dimenzionalna analiza, Mehanika fluida M.

    10/10

    50km/h

    350N

    35 m

    11 m/s

    1 m

    p0m= 0.2kPa