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8/10/2019 Bi Tp Ln Tng Hp H Thng in C
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- Gim dng in lm vic I xung di gi tr dng in duy tr IH.
- t mt in p ngc ln Tiristor (bin php thng dng)Khi t in p ngc ln Tiristor UAK< 0, hai mt ghp J1v J3b phn cc
ngc, J2by gi c phn cc thun. Nhng in t, trc thi im o cctnh U
AK, ang c mt ti P
1,N
1, P
2by gi o chiu hnh trnh, to nn dng in
ngc chy t katt v ant, v cc m ca ngun in p ngoi.Lc u ca qu trnh, t t0n t1, dng in ngc kh ln, sau J1ri J3
tr nn cch in. Cn li mt t in t b gi li gia hai mt ghp J 1v J3, hintng khuch tn s lm chng t dn i cho n ht v J2khi phc li tnh chtca mt ghp iu khin.
Trong cc s chnh lu trn, gi tr in p trung bnh mt chiu ra tiph thuc vo gc iu khin m ca Tiristor:
Ud= Ud0.cos
Do , khi thay i gc iu khin th ta s thay i c gi tr in p
trung bnh ra ti. Nu tng gi tr gc iu khin th in p trung bnh s gim,ngc li, gim th in p trung bnh s tng. Gi tr ln nht ca in p trungbnh ra ti l Ud0, ng vi gc =0.
Dng in trung bnh qua ti:
d
d
Z
UI vi 22 RXZ Ld
Trng hp trong mch ti c thm sut in ng phn khng:
d
d
Z
EUI
1.2 Gii thiu ng c mt chiuTrong nn sn xut hin i, ng c mt chiu vn c coi l mt loimy quan trng mc d ngy nay c rt nhiu loi my mc hin i s dngngunin xoay chiu thng dng.
Do ng c in mt chiu c nhiu u im nh kh nng iu chnh tc rt tt, kh nng m my ln v c bit l kh nng qu ti. Chnh v vy mng c mt chiu c dng nhiu trong cc nghnh cng nghip c yu cu c aov iu chnh tc nh cn thp, hm m, giao thng vn ti,cc nghnh cngnghip hay i hi dng ngun in mt chiu...
Bn cnh , ng c in mt chiu cng c nhng nhc im nht nhca n nh so vi my in xoay chiu th gi thnh t hn ch to v bo qunc gp in phc tp hn (d pht sinh tia la in)... nhng do nhng u im nitri ca n nn ng c in mt chiu vn c mt tm quan trng nht nh trongsn sut.1.2.1 Cu to ca ng c in mt chiu
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ng c in mt chiu c th phn thnh hai phn chnh: phn tnh v phnng.1.2.1.1. Phn tnh
y l ng yn ca my, bao gm cc b phn chnh sau:+ Cc t chnh: l b phn sinh ra t trng gm c li st cc t v dy
qun kch t lng ngoi li st cc t. Li st cc t lm bng nhng l thp kthut in hay thp cacbon dy 0,5 n 1mm p li v tn cht. Trong ng c innh c th dng thp khi. Cc t c gn cht vo v my nh cc bulng. Dyqun kch t c qun bng dy ng bc cch in v mi cun dy u c
bc cch in k thnh mt khi tm sn cch in trc khi t trn cc cc t.Cc cun dy kch t c t trn cc cc t ny c ni tip vi nhau.
+ Cc t ph: Cc t ph c t trn cc cc t chnh v dng cithin i chiu. Li thp ca cc t ph thng lm bng thp khi v trn thncc t ph c t dy qun m cu ro ging nh dy qun cc t chnh. Cc t
ph c gn vo v my nh nhng bulng.+ Gng t: Gng t dng lm mch t ni lin cc cc t, ng thi lm v
my. Trong ng c in nh v va thng dng thp dy un v hn li. Trongmy in ln thng dng thp c. C khi trong ng c in nh dng gang lmv my.
+ Cc b phn khc:-Np my: bo v my khi nhng vt ngoi ri vo lm h hng dy
qun v an ton cho ngi khi chm vo in. Trong my in nh v va npmy cn c tc dng lm gi bi. Trong trng hp ny np my thng lm
bng gang.- C cu chi than: a dng in t phn quay ra ngoi. C cu chi
than bao gm c chi than t trong hp chi than nh mt l xo t chy ln cgp. Hp chi than c c nh trn gi chi than v cch in vi gi. Gi chithan c th quay c iu chnh v tr chi than cho ng ch. Sau khi iuchnh xong th dng vt c nh li.1.2.1.2. Phn quay
Bao gm nhng b phn chnh sau :+ Li st: L phn ng dng dn t. Thng dng nhng tm thp k
thut in dy 0,5mm ph cch in mng hai mt ri p cht li gim tn
hao do dng in xoy gy nn. Trn l thp c dp hnh dng rnh sau khi pli th dt dy qun vo.
Trong nhng ng c trung bnh tr ln ngi ta cn dp nhng l thng gi khi p l thnh li st c th to c nhng l thng gi dc trc.Trong nhng ng c in ln hn th li st thng chia thnh nhng on nh,gia nhng on y c mt khe h gi l khe h thng gi. Khi my lm vicgi thi qua cc khe h lm ngui dy qun v li st.
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Trong ng c in mt chiu nh, li st phn ng c p trc tip vo trc.Trong ng c in ln, gia trc v li st c t gi rto. Dng gi rto c thtit kim thp k thut in v gim nh trng lng rto.
+ Dy qun phn ng: Dy qun phn ng l phn pht sinh ra sut inng v c dng in chy qua. Dy qun phn ng thnglm bng dy ng c
bc cch in. Trong my in nh c cng sut di vi kw thng dng dy ctit din trn. Trong my in va v ln thng dng dy tit din ch nht. Dyqun c cch in cn thn vi rnh ca li thp. trnh khi quay b vng ra do lc li tm, ming rnh c dng nm chthoc ai cht dy qun. Nm c lm bng tre, g hay bakelit.
+ C gp: dng i chiu dng in xoay chiu thnh mt chiu. C gpgm nhiu phin ng c c m cch in vi nhau bng lp mica dy t 0,4n 1,2mm v hp thnh mt hnh trc trn. Hai u trc trn dng hai hnh phnh ch V p cht li. Gia vnh p v tr trn cng cch in bng mica. ui
vnh gp c cao ln mt t hn cc u dy ca cc phn t dy qun v ccphin gp c d dng.
+ Cc b phn khc:- Cnh qut: dng qut gi lm ngui my. My in mt chiu
thng ch to theo kiu bo v. hai u np my c l thng gi. Cnhqut lp trn trc my , khi ng c quay cnh qut ht gi t ngoi vong c. Gi i qua vnh gp, cc t li st v dy qun ri qua qut gi rangoi lm ngui my.
- Trc my: trn t li st phn ng, c gp, cnh qut v bi.Trc my thng lm bng thp cacbon tt.
1.2.2 ng c mt chiu kch t c lp1.2.2.1 S nguyn l:
Hnh 1.2: S nguyn l ng c mt chiu kch t c lp
Rf
Uu
C
CKTD
+_
_+
RKT
UKT
I
IKT
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Ta c phng trnh c tnh c: 2
K
RR
K
U fuu
T phng trnh c tnh c ta thy C ba thng s nh hng n c tnhc l:
- T thng ng c ().- in p phn ng (U).- in tr phn ng.Sau y ta s ln lt i xt nhng nh hng ca tng tham s :
1.2.2.2 nhhng ca in tr phn ng:Gi thit : U=Um=const
= m=const
Khi ta i in tr mch phn ng ta c tc khng ti l tng:
0 = Const
K
U
dm
dm
cng c tnh c:
= VarRR
KM
fu
2)(
Khi Rf cng ln, cng nh ngha l c tnh c cng dc. ng vi Rf = 0Ta c c tnh c t nhin:
tn= -uR
K 2)(
tnc gi tr ln nht nn c tnh c t nhin c cng hn tt c cc
ng c tnh c in tr ph. Nh vy khi thay i in tr ph Rf ta c mth c tnh bin tr c dng nh hnh 1.4. ng vi mt ph ti M cno , nu Rfcng ln th tc ng c cng gim, ng thi dng in ngn mch v mmenngn mch cng gim. Cho nn ngi ta thng s dng phng php ny hnch dng in v iu chnh tc ng c pha di tc c bn.
Hnh 1.3: Cc c tnh ca ng c mt chiu kch t c lp
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khi thay i in tr ph mch phn ng1.2.2.3 nh hng ca in p phn ng:
Gi thit : = dm= constR= const
Khi thay i in p phn ng : U
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Hnh1.5:c tnhc in (a)v c tnh c (b)khi thay i t thngTa nhn thy rng khi thay i t thng:
Dng in ngn mch: ConstR
UI
U
dmnm
M men ngn mch: Mnm= KxInm= varCc c tnh c in v c tnh c ca ng c khi gim t thng c biu dintrn hnh 1.6.
Vi dng mmen ph ti Mcthch hp vi ch lm vic ca ng c thkhi gim t thng tc ng c tng ln (Hnh 1.5b)1.3 H truyn ng chnh lu ng c mt chiu1.3.1 Khi nim chung v h truyn ng chnh lu ng c mt chiu
L b chnh lu lin h ngun xoay chiu vi ti mt chiu, ngha l iin p xoay chiu ca ngun thnh in p mt chiu trn ph ti.
in p mt chiu trn ti khng c l tng nh in p ca c quy mc cha cc thnh phn xoay chiu cng vi mt chiu.u ra ca cc s chnh lu c coi l mt chiu nhng thc s l in
p p mch. Tr s in p mt chiu, hiu p sut nh hng ca chng do ngunxoay chiu rt khc nhau.
B bin i Thyristor vi chuyn mch t nhin c in p (dng in) ra l1 chiu l cc thit b bin ngun in xoay chiu 3 pha thnh in p 1 chiu iukhin ngc.
Hot ng ca mch do ngun in xoay chiu quyt nh v nh m cth thc hin c cc chuyn mch dng in gia cc phn t lc.
Vic phn loi chnh lu ph thuc nhiu yu t:- Theo s pha c: Chnh lu 1 pha, chnh lu 3 pha...- Theo s ni c: Chnh lu na chu k, chnh lu 2 na chu k, chnh
lu hnh cu, chnh lu hnh tia...- Theo s iu khin c: Chnh lu khng iu khin, chnh lu c iu
khin, chnh lu bn iu khin.
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1.3.2 Gii thiu s
Hnh 1.6: S h thng chnh lu ng c mt chiuTrong :
+ : ng c mt chiu kch t c lp, thc hin chc nng bin nnglng in mt chiu thnh c nng truyn ng cho c cu sn xut
+ BB: l b bin i van c iu khin, thc hin chc nng bin nnglng in xoay chiu thnh nng lng in mt chiu cung cp cho ng c
+ Utn hiu in p t+ FT my pht tc thc hin chc nngkhu phn hi m tc
+TH & K l khi tng hp v khuych i tn hiu+ FX l mch pht xung1.3.2.1 Hot ng ca h thng
Gi s ban u h thng c ng vo li vi in p thch hp, lcny ng c vn cha lm vic. Khi ta t vo h thng mt in p t Ungvi mt tc no ca ng c. Thng qua khu TH & KH v mch FX s suthin cc xung a ti cc chn iu khin ca cc van ca b bin i, nu lc nynhm van no ang c t in p thun, van s m vi gc m . u raca BB c in p Udt nn phn ng ng cng c quay vi tc ng
vi Uban u.Trong qu trnh lm vic, nu v mt nguyn nhn no lm cho tc ng c gim th qua biu thc : UK= U- n.khi n gim UKtng gim Udtng n tng v im lm vic yu cu.Khi n tng qu mc cho php th qu trnh din ra ngc li. y l nguyn l nnh tc .* c tnh c ca h thng truyn ng:
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Ch dng in lin tc:Dng in chnh lu Idchnh l dng phn ng.Da vo s thay th (hnh 2.2) vit c s c tnh.
c tnh c c cng
Xk: c trng cho st p do chuyn mch gia cc van.Thay i gc iu khin:
+ Khi s chnh lu bin thin t Edon - Edov ta c mth c tnh song song nhau nm na bn phi mt phng to do cc
van khng cho dng in phn ng i chiu.Cc c tnh c ca h T - mm hn cc c tnh c ca h F - bithnh phn st p do hin tng chuyn mch gia cc van bn dn gy nn.
Hnh 1.7: H c tnh c ca h
+ Khi : B bin i lm vic ch chnh lu, ng c c th
lm vic ch ng c nu s E > 0 v ch hm ngc nu s E ichiu.
+ Khi : B bin i lm vic ch nghch lu ph thuc,
bin c nng ca ti thnh in nng xoay chiu cng tn s li v tr v liin. ng c lm vic ch hm ti sinh khi ti c tnh th nng.
Dng in trung bnh ca mch phn ng:
IK
XR
K
En
dm
K
dm
do
..
cos.
MK
XR
K
En
dm
K
dm
do
2).(.
cos.
K
dm
XR
K
2)(
0 M,
kU
20
ma x2
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Phng trnh c tnh:
- Ch dng in gin on:Trong thc t tnh ton h T - ch cn xc nh bin gii vng dng
in gin on, l ng phn cch gia vng dng in lin tc v dng in ginon. Trng thi bin lin tc l trng thi m gc dn = /p v gc chuynmch .
ng bin lin tc gn l ng elip. gim ln ca trc nh elip, tng s pha ca chnh lu. Tuy nhin
khi tng s pha chnh lu s s phc tp.1.3.2.2 nh gi cht lng ca h thng- u im:+ Tc nhanh,khng gy ting n v d t ng ho do cc van bn
dn c h s khuch i cng sut cao.+ Cng sut tn ho nh, kch thc v trng lng nh+ Gi thnh r, d bo dng sa cha.
-Nhc im:+ Mch iu khin phc tp, in p chnh lu c biu p mch cao,
gy n tn tht ph ng k trong ng c v h thng.
+ Chuyn mch lm vic kh khn do ng c tnh nm trong mtphng to .
+ Trong thnh phn ca h bin i c MBA nn h s cos thp.+ Do vai tr ch dn dng mt chiu nn vic chuyn i ch lm vic
kh khn vi cc h thng o chiu.+ Do c vng lm vic gin on ca c tnh nn khng ph hp truyn
ng c ti nh.
K
d
XR
EEI
I
K
XR
K
E
dm
K
dm
do .cos.
2
0
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CHNG II: XY DNG S CU TRC CA H
2.1 Xy dng cu trc ca h thng:T s nguyn l ca h truyn ng T- ta c s cu trc trng thi n
nh:
- Trong :
- R: Biu chnh tc quay.
- Ri : B iu chnh dng in.- U: in p ch o.- U: in p phn hi tc - Ui : in p phn hi m dng in.- Ki : H s phn hi m dng in.- K : H s phn hi m tc .
Km
K
Ki
R Ri BB Km 1Jp
1 R1 + p T
UiU U
Ui
-
U
-
McSi
S
-E
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2.2. Xc nh cc tham s ca s cu trc h truyn ng.
P =14Kw U=400Vn = 0.9 nm= 955(vng/pht)
+ Im =
=
= 38.88(A)
+ R=0,5(1-n). =0,5(1-0,9).
= 0,514()
+ m= = = 100(Rad/s)
+ Km = =
= 3.8
+ J =
= 6.18kg.m2
Kcl = 9, Ki = 0.04, K= 0.01
Tvo + Tk = 0.0015s
T = 0.07s, Ti = 0.003sTc = 0.22s , T= 0.05s
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CHNG III: XY DNG CU TRC
V THAM S B IU CHNH DNGTHEO TIU CHUNMODUL TI U
3.1. Tng hp b iu chnhTrong cc h truyn ng t ng cng nh cc h chp hnh th mch vng
iu chnh dng in l mch vng cbn. Chc nng c bn ca mch vng dng
in l trc tip hoc gin tip xc nh m men ko ca ng c, ngoi ra n cn
c chc nng bo v, iu chnh gia tc...Do qun tnh c hc ln hn rt nhiu so vi qun tn in t (Tc >> T ) cho
nn bin i tc chm hn bin i tc dng in.
Trong mch vng dng in c th coi 0E .Lc ny mch vng dng in c
dng:
Hnh 3-1. S khi mch vng dng in
Trong :
Rip- hm truyn ca b iu chnh dng in (cn tm)B(p) - hm truyn ca b bin i, c dng nh sau:p K1 + p T1+pT
Vi: K- h s chnh lu
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T- hng s chuyn mch chnh luT- hng s thi gian mch iu khin chnh lu
A(p) - hm truyn ca ng c khng tnh n sut in ng phn ng
p 11 + p T R
Vi: T - hng s thi gian phn ng.Kp- hm truyn ca khu phn hi dng in, c dng nh sau:Kp Ki1 + p Ti
Vi: Ti - hng s thi gian ca sensor dng in
Ki=0.04 - h s phn hi mch vng dng inTa chuyn i mch phn hi dng in v mch phn hi n v, ta c s tng ng nh sau:
Hnh 3-2 : S tng ng .
- Ta c hm truyn h kn ca s khi cha chuyn i:
Sip U Rippp
1 + RipKppp- Ta c hm truyn h kn ca s khi chuyn i:
Si
p UiU
RipKppp1 + RipKppp
Mt khc: Ui Kp - Vy p dng tiu chun ti u mun cho hm truyn s chuyn
i:
Rip B(p) A(p) KpU Ui I Ui
-
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Si p Kp
U K Sip
Sip Kp
Rippp1 + RipKppp Kp
Rip 1 Kppp- Thay cc hm truyn tng ng vo Ripvi:
11 + p + p
Rip 1 + Tip1 + Tp1 + Tp1 + p TKKiR p1+ p
Mt khc, cc hng s thi gian T T Tirt nh so vi hng s thigian in t T. t T T + T + Tith Ripc th vit li dnggn ng nh sau:
Rip 1 + Tc1 + Tp
KKi
R
p1+ p
Trong T T, ta chn Tthay vo Ripta c:Rip 1 + TKKiR Tp
Vy hm truyn ca mch vng kn s l:
Sip 1Ki1
1 + Tp + Tp
3.2. Tnh ton thng s b iuchnh- H s bin i dng in:
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Hnh 3-3 S my bin dng.- Ta s dng mch bin dng, o dng trc tip t ngun 3 pha a qua
b chnh lu it c lc ly phn hi dng in v cho ng c.Ti
- H s chnh lu
K U- in p iu khin a vo mch chnh lu (chn U 1 V)T T + T + Ti=0,0015+0,003=0.0045 (s)
- Hm truyn
p K1 + p T1+pT
1+1p
p 1
R 1 + Tp
1+p
Kp Ki1 + p Ti
1+p
Rip 1 + TpKKiR Tp 1+pp
Sip 1Ki
11 + Tp + Tp
1+p+1p
- Thit k mch iu chnh dng in
Rip 1+p 1
p +1
Vy mch iu chnh dng ca ta s b iu chnh PI
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CHNG IV: XC NH CU TRCV THAM S B IU CHNH TC
THEO TIU CHUN MODUL TI U I XNG
4.1. Tng hp b iu chnhV ng c cn b nh hng bi yu t thay i ca ti trng nn trong
trng hp ny chng ta s tng hp mch vng iu chnh tc theotiu chun ti u i xng c th t c yu cu v sai cp cao
S khi ca mch vng iu chnh tc :
Hnh 4-1 : S khi mch vng iu chnh tc .
Trong :
Rp- Hm truyn b iu chnh tc Sip- Hm truyn h kn ca vng iu chnh dng in
Sip 1Ki 1
1 + Tp + TpKp- Hm truyn khu phn hi tc
Kp K1 + Tp
Vi: K- H s phn hi ca my pht tcT- Hng s thi gian ca my pht tc
Mc
U
U Rp Sip Km C(p)
Kp
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C(p) - Hm truyn c hc ca ng c khi b qua ma st trntrc ng c
p 1JpVi: J - Mmen quan tnh ca ng c
- p dng hm chun ti u i xng (v tnh n Mcnn tng hp theo
tiu chun ti u i xng sai s ca h thng c gim thiu):
- Hm truyn h kn ca s trn
S RpSippKm
1 + RpSipKppKm- p dng hm chun ti u i xng (s dng cchbin i s ging
nh phn thit k mch vng dng in) ta c:S Kp
RpSipKppKm1 + RpSipKppKm
Rp 1 SipKppKm- Thay cc hm truyn tng ng vo
R
p
1 + p1 + p + p + pVy:
Rp p1 + p1 + Tp + Tp 1 + Tp
p1 + pKKmKi J
Mt khc, ta c th b qua thnh phn Tpv l v cng b vcc hng s thi gian Tv Trt nh nn t T
T + T ,ta c hm truyn gn ng nh sau:Rp
1 + p 1 + T pp1 + pKKmKi J
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V T l tng cc hng s thi gian v cng nh nn ta chn T , ta c:
Rp (1 + T p)
T
K
K
mKi J p
Vy hm truyn ca mch vng kn s l
Sp 1K 1 + Tp
1 + Tp + Tp + Tp4.2. Tnh ton thng s b iu chnh
- H s phn hi ca my pht tc:
Ta c s ca my pht tc nh sau:
Hnh 4-2 : S my pht tc .
Ta c:U K K=0.01
Mt khc T ,Ts=0,059 (s)- Hm truyn
Rp (1 + T p)
T K
K
mKi J p 1+p
p 1
p+1
p 1Jp 1
1p
Kp K1 + Tp 1
1+p
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+ Hm truyn ca cc khu tm cnh sau:
Rp 1p +1
Kp 1
1+pRip 1p +
1
Kip 1+p
1+1p1 R
1 + Tp 1
1p+1
p 1Jp 1
1pKm (Wb)
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CHNG V: KHO ST C TNH NG HC CA H
5.1. M phng trn Matlab Simulink
A.Lc khng ti
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1.Mch vng iu chnh dng in.
+Mc=Mt=0
+thi gian t ti trng thi n nh:4.2s
+sai lch tnh:1%
Nhn xt:
Hthng t trng thi n nh kh nhah.
2.Mch vng tc .
+Mc=Mt=0
+qu iu chnh 85%
+thi gian t ti trng thi n nh:3.5s
+thi gian t ti tn hiu t:0.857s
+sai lch tnh:1%
B.Lc c ti
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A.Khng ti
1.Mch vng dng in.
+I=0;
+Thi gian tn hiu t trng thi n nh:1.25s
Nhn xt:thi gian t ti trng thi n nh kh nhanh
2.Mch vng tc .
+Mc=Mt=0
+qu iu chnh 8.5%
+thi gian t ti trng thi n nh:1.25s
+thigian t ti tn hiu t:0.857s
+sai lch tnh:1%
B. Trng hp c ti
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1.Mch vng dng in.
+I=38.8A;
Nhn xt: dng in tng ln gi trnh mc
2.Mch vng tc .
+Mc=Mt=147.4
+khi c ti tc gim nhng nhanh chng n nh lai tc nh mc
+sai lch tnh:1%
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CHNG VI: XY DNG S NGUYN LV TNH CHN THIT B
6.1. S nguyn l
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Hnh 6-1 S nguyn l
6.2. Tnh chn mch ng lc.
6.2.1. S mch ng lc h chnh lu cu ba pha thyristor.
Trongphn ny ta chn b truyn ng dng hai b bin i ni song song
ngc iu khin chung , bi n dng cho di cng sut va v ln c tn s o
chiu cao v thc hin o chiu m hn .Trong s ny ng c khng nhng
o chiu c m cn c th hmti sinh .
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Hnh 6-2 : S mch ng lc ca bchnh lu cu ba pha thyristor h T-
.
6.2.2. Cc thng s ca ng c.
- ng c mt chiu kch t c lp c cc thng s sau:
Pdm= 14 Kw Udm= 400 V
Lc
Lc Lc
Lc
L
BAL
T1T4
T3T6
T5T2
FG
T4T1
T6T3
T2T5
+ -Ckt
M
Ikt
u2au2bu2c
C B A
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Idm= 40 A ndm= 955 vng/pht
6.23. Tnh chn thyristor:
Tnh chn thyristor da vo cc yu t c bn nh : dng in ti , s
chnh lu , iu kin tn nhit , in p lm vic .- in p ngc ln nht m thyristor phi chu :
Unmax= Knv.U2= Knv.u
d
K
U=
6.3.6 dU
=3
.400 = 418.89 V ;
Trong : Knv= 6 ; Ku=
63;
- in p ngc ca van cn chn :Unv= Kdtu.Unmax= 1,8 .418,89 = 754 V ;
Trong : Kdtu: H s d tr in p , thng chn Kdtu= 1,8 ;
- Dng in lm vic ca van c tnh theo dng hiu dng :
Ilv= Ihd= khd.Id =3
dmI =3
40= 23,09 A ;
( do trong s cu ba pha , h s dng in hiu dng : khd= 3
1
) .
- Chn thyristor lm vic vi iu kin c cnh tn nhit v din tch tn
nhit , khng c qut i lu khng kh , vi iu kin c dng in nh mc ca
van cn chn :
Idm= ki.Ilv = 3,2 . 23,09 = 73,9 A ;
ki: H s d tr dng in , chn ki= 3,2 .
chn thyristor lm vic vi cc tham s nh mc c bn trn , ta tra bngthng s van , chn cc van c thng s in p ngc , dng in nh mc ln
hn gn nht vi thng s tnh . Vy ta chn thyristor cho mch ng lc loi
TF440-06X c cc thng s sau :
- Dng in nh mc ca van: Idm= 400 (A) ;
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- in p ngc cc i ca van: UnT= 600 (V) ;
- nh xung dng in : Ipk= 4000 (A) ;
- st p trn thyrisor : UT= 2,0 (V) ;
-
Dng in ca xung iu khin : Ig= 200 (mA) ;- in p ca xung iu khin : Ug = 3,0 (V) ;
- Dng in r : Ir= 25 (mA) ;
- Nhit lm vic cc i : Tmax= 1250C ;
- Dng in duy tr : Ih = 70 mA ;
- Tc bin thin in p :
dt
du = 200 (V/s) ;
-
Thi gian chuyn mch : tcm= 15 (s) ;
6.2.4. Tnh ton my bin p chnh lu:
chn cc thit b trong mch ng lc cng nh mch bo v , trc ht
cn xc nh in p ra ca b bin i Thysitor .
Chn my bin p ba pha ba tr c s ni dy /Y , lm mt t nhin bng
khng kh .
My bin p l mt b phn quan trng ca h thng in , thc hin ccchc nng sau .
- Bin i in p ngun cho ph hp vi yu cu s ph ti .
- Bo m s cch ly gia ph ti vi li in vn hnh an ton v thun
tin
- Bin i s pha cho ph hp vi s pha ca s ph ti .
- To im trung tnh cho s hnh tia .
- Hn ch dng in ngn mch trong chnh lu v hn ch mc tng dng
Ant bo v van .
- Ci thin hnh dng sng in li lm cho n bin dng so vi hnh sin ,
do nng cao cht lng in p li .
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* Tnh cc thng s c bn :
- Tnh cng sut biu kin ca my bin p :
SBA= Ks.Pdm= 1,05.14000 = 14700 (VA) ;
- in p pha s cp my bin p :U1 = 380 V ;
- in p pha th cp my bin p :
Phng trnh cn bng in p khi c ti :
Ud0.cosmin = Ud+ 2UV+ 2Udm+ UBA
Trong :
min
= 00l gc d tr khi c suy gim in p li ;
UV= 21 V l st p trn thyristor ;
Udm 0 l st p trn dy ni :
UBA= Ur+ Ux l st p trn in tr v in khng trn my bin
p;
Chn s b :
UBA= 6%.Ud = 0,06. 400 = 24 V ;
T phng trnh cn bng in p khi c ti ta c :
Ud0=mincos
22
BAVd UUU =00
24.221.2400
Cos
= 490 V ;
in p pha th cp my bin p :
U2=u
d
k
U=
63
490= 209 V ;
- Dng in hiu dng th cp my bin p :
I2=3
2.Id=
3
2.40 = 32,6 A ;
- Dng in hiu dng s cp my bin p :
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I1= kBA.I2=1
2
U
U.I2 =
380
209 .32,6 = 17,93 A ;
* Xc nh kch thc ca mch t .
- Tit in s b tr .
QFe = kQ.fm
SBA.
;
Trong : kQ: H s ph thuc phng thc lm mt , ly kQ= 6 .
m : S tr ca my bin p , m = 3 .
f : Tn s ca ngun xoay chiu , f = 50 Hz .
Thay vo ta c : QFe = 6 .50.3
14700 = 59,4 cm2.
- ng knh tr :
d =
FeQ.4 =
4,59.4 = 8,7 cm .
Chun ha ng knh tr theo tiu chun : d = 11 cm .
- Chn loi thp k thut in , cc l thp c dy 0,5 mm .
Chn s b mt t cm trong tr BT = 1 T .
- Chn t s m =d
h = 2,3 . Suy ra h = 2,3d = 2,3 . 11 = 25,3 cm .
( Thng thng m = 2 2,5 ) .
Chn chiu cao tr h = 25 cm .
* Tnh ton dy qun .
- S vng dy mi pha s cp my bin p :
W1=0,1.10.4,59.50.44,4
380
...44,4 41
TFe BQf
U = 288 vng .
Ly W1 = 290 vng .
- S vng dy mi pha th cp my bin p :
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W2=1
2
U
U.W1 =
380
209 .290 = 159,5 vng .
Ly W2 = 160 vng .
- Chn s b mt dng in trong mybin p :Vi dy dn bng ng , my bin p kh , chn J1 = J2 = 2,75 A/mm
2.
- Tit din dy dn s cp my bin p :
S1 =1
1
J
I =
75,2
15,29 = 10,6mm2.
Chn dy dn thit din hnh ch nht , cch in cp B .
Chun ho tit din theo tiu chun : S1 = 14,2 mm2.
Kch thc ca dy c k n cch in l : S1cd = a1 b1 = 1,68 8,6 mm .
- Tnh li mt dng in trong cun s cp :
J1 =1
1
S
I=
2,14
93,17 = 1,26 A/mm2.
- Thit din dy dn th cp my bin p :
S2 =2
2
J
I =75,2
6,32 = 11,85 mm2.
Chn dy dn c tit din ch nht , c cch in cp B .
Chun ho tit din theo chun : S2 = 50,1 mm2
Kch thc ca dy c k n cch in l : S2cd = a2 b2 = 5,1 10 mm .
- Tnh lai mt dng in trong cun th cp :
J2 = 2
2
S
I
= 1,50
6,32
= 0,65 A/mm2
.
* Kt cu dy qun s cp .
Thc hin dy qun kiu ng tm b tr theo chiu dc trc .
- Tnh s b s vng dy trn mt lp ca cun s cp :
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W11 = 95,0.86,0
5,1.225.
2
1
c
gk
b
hh = 24 vng .
Trong : kc: L h s p cht , ly kc= 0,95 .
h : Chiu cao tr h = 25 cm .hg: Khong cch t gng cun dy s cp .
Chn s b khong cch cch in gng hg = 1,5 cm .
- Tnh s b s lp dy cun s cp :
n11=24
290
11
1 W
W = 12,08 lp .
Chn s lp n11 = 12 lp .
Nh vy c 290 vng chia thnh 12lp , vy 11 lp u c 24 vng v lp
th 12 c 26 vng
- Chiu cao thc t ca cun s cp :
h1 =95.0
86,0.24. 111 ck
bW = 21,726 cm .
- Chn ng qun dy lm bng vt liu cch in c b dy :S01 = 0,1 cm .
- Khong cch t tr ti cun s cp :
a01 = 1 cm .
- ng knh trong ca ng cch in :
Dt= dFe+ 2a012S01 = 11 + 2 . 12 . 0,1 = 12,8 cm .
- ng knh trong ca ca cun s cp :
Dt1= Dt + 2S01 = 12,8 + 2 . 0,1 = 13 cm .
- Chn b dy cch in gia cc lp cun s cp :
cd11 = 0,1 mm .
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- B dy cun s cp :
Bd1= ( a1+ cd11 ).n11 = ( 1,68 + 0,1 ).8 = 14,24 mm = 1,424 cm .
- ng knh ngoi ca cun s cp :
Dn1 = Dt1+ 2Bc1= 13 + 2 . 1,424 = 15,848 cm .
- ng knh trung bnh ca cun s cp :
Dtb1 =2
848,1513
211
nt DD = 14,424 cm.
- Chiu di dy qun s cp :
l1 = W1..Dtb = . 290 . 14,424 = 13141,156 cm = 131,41 m .
- Chn b dy cch in gia hai cun s cp v th cp :
cd0 = 1 cm .
* Kt cu dy qun th cp .
- Chn s b cun chii cao cun th cp :
h2 = h1 = 21,726 (cm) .
- Tnh s b s vng dy trn mt lp :
W12 = ckb
h.
2
2 = 95,0.1
726,21 = 20 vng .
- Tnh s b s lp dy qun th cp:
nl2 =20
160
2
2 lW
W = 8 lp .
chn n12 = 8 lp .
- Chiu cao thc t ca cun th nht :
h2=95,0
1.2022 c
l
k
bW= 21,05 cm .
- ng knh trong ca cun th cp :
Dt2 = Dn1+ 2a12 = 15,848 + 2 . 1 = 17,848 cm .
- Chn b dy cch in gia cc lp dy cun th cp :
cd22 = 0,1 mm .
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- B dy cun th cp :
Bd2 = ( b2 + cd22 ). nl2= ( 1 + 0,01 ) . 3 = 3,03 cm .
- ng knh ngoi ca cun th cp :
Dn2 = Dt2+ 2.Bd2 = 17,848 + 2 . 3,03 = 23,908 cm .
- ng knh trung bnh ca cun th cp :
Dtb2 =2
908,23848,17
222
nt DD = 20,878 cm .
- Chiu di dy qun th cp:
l2 = .W2.Dtb2 = . 160 . 20,878 = 10494 cm = 104,94 m .
- ng knh trung bnh ca cc cun dy :
D =2
908,2313
2
21
nt
DD = 18,454 cm .
Suy ra : r =2
454.18
2
D = 9,227 cm .
* Cc thng s ca my bin p :
- in tr trong ca cun s cp my bin p 75oC :
R1 = .1
1
s
l = 0,02133.
14
41,131 = 0,2 .
Trong : = 0,02133 .mm2/m.
- in tr trong ca cun th cp my bin p 75oC :
R2 = .2
2
s
l = 0,02133.
1,50
94,104 = 0,045 .
- in tr my bin p quy i v th cp :
RBA = R2+ R1.(1
2
W
W)2= 0,045 + 0,2.(
290
160 )2 = 0,06 .
- St p trn in tr my bin p :
ur = RBA.Id = 0,06 . 40 = 2,4 V .
- in khng my bin p quy i v th cp :
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XBA= 8.2.(W2)
2.(qh
r)(a12+
3
21 dd BB )..10-7.
XBA= 8 . 3,142 . 1602. (
726,21
227,9) . (0,01 + 210.
3
03,3424,1 ) . 314 . 10-7
XBA= 0,67 .
- in cm my bin p quy i v th cp :
LBA =
BAX =
314
67,0 = 2,13.10-3H = 2,13 mH.
- St p trn in khng my bin p :
ux =
3 .XBA.Id =
3 .0,67.40 = 25,6 V .
- in p ngn mch tc dng :
Unr = 100.209
6,32.06,0100
2
2 U
IRBA = 0,93 % .
- in p ngn mch phn khng:
Unx = 100.209
6,32.67,0100
2
2 U
IXBA = 10,5 % .
- in p ngn mch phn trm :
Un = 2222
5,1093,0 nxnr UU = 10,54 % .
Cng sut my bin p biukin
SBA = 14,7 kVA
in p pha s cp U1 = 380 V
in p pha th cp U2 = 209 V
Dng in hiu dng s cp I1 = 17,93 A
Dng in hiu dng th cp I2 = 32,6 A
S vng dy mi pha s cp W1 = 290 vng
S vng dy mi pha th cp W2 = 160 vng
in tr quy i v th cp RBA = 0,06
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Bng thng cc thng s ca my bin p ng lc .
6.3. Mch iu khin .
6.3.1. S nguyn l :
Hnh 6-3 : S khi iu khin thyristor .
6.3.2. Nguyn tc iu khin :
Trong thc t ngi ta thng dng hai nguyn tc iu khin sau : Thng
ng tuyn tnh v thng ng arccos , thc hin v tr xung trong na chu k
dng ca in p t trn thyristor .
in khng quy i v th cp XBA = 0,67
in cm quy i v th cp LBA = 2,13 mH
in p ngn mch phn trm Un = 10,54 %
IN P TA
K XUNG
P
SSUc
T
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6.3.2.2. Nguyn tc iu khin thng ng arccos:
Theo nguyn tc ny ngi ta dng hai in p :
- in p ng b Us, vt trc UAK= UmSint ca thyristor mt gc2
Us= UmCost .
- in p iu khin Ucml in p mt chiu , c th iu chnh c bin
theo hai chiu dng v m .
Hnh 6-5 : Nguyn tc iu khin thng ng arcoss
Nu t Usvo cng o v Ucmvo cng khng o ca khu so snh th :
Khi Us= Ucm, ta s nhn c mt xung rt mnh u ra ca khu so snh
khi khu ny lt trng thi .
UmCos = Ucm; (3-1)
Do = arcos(m
cm
U
U) ; (3-2)
Khi Ucm= Um th = 0 ;
Khi Ucm= 0 th =2
;
Khi Ucm= - Um th = ;
Ucmt
UAK
0
Us
UAK
Us
2
Um
-Um
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Di y ta gi thiu mt s khu ng pha c bn
Hnh 6-6 Mt s khu ng pha in hnh.
u1 u1ura
u2D1
D2R1
R2
C
-E
A B C
Hnh-a
R2
R1
D1
A
C ura
Tr
Hnh-b
+E
Ghp quanguv
R1
D
R2
uraC
-E
Ura
u1D1
A2
R1A B
R2Tr
C
C
Hnh-d
A1
-12
+12+12
-12_
++
_
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Hnh 6-7 : Gin ca khu ng pha
6.3.2. Khu so snh :
xc nh c thi im cn m thyristor , cn so snh hai tn hiu Udkv
Urc, vic so snh hai tn hiu c th c thc hin bng tranzitor (Tr) nh trn
hnh 3-6a . Ti thi im Udk= Urcu vo Tr lt trng thi kho sang m ( hay
ngc li t m sang kho ) , lm cho in p ra cng b lt trng thi , ti tanh du c thi im cn m thyristor .
Vi mc m bo ho ca Tr ph thuc vo hiu Udk Urc= Ub, hiu ny
c mt vng in p nh hng vi mV , lm cho Tr khng lm vic ch ng
UA
t
t
UC1
2 3 4
UA
UB
Uk1
Urc
1
t
UC2Uk2
Urc2 2
1
t
32
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ct nh mong mun , do nhiu khi lm thi im m thyristor b lch kh xa so
vi im cn m ti Udk= Urc.
Khch i thut ton c h s khch i v cng ln , ch cn mt tn hiu rt
nh (c V) u vo , u ra c in p ngun nui , nn vic ng dngkhch i thuc ton lm khu so snh l hp l . Cc s so snh dng khch
i thut ton nh hnh 3-6b, c rt thng gp trong ccs hin nay . u im
hn hn ca cc s ny l c th pht xung iu khin chnh xc ti Udk= Urc
Mt s s khu so snh thng gp nh sau.
Hnh 6-8 : Cc khu so snh thng gp.
a ) Bng tranzitor ; b ) Bng mt cng o ca khch i thut ton ;
c ) Hai cng khch i thut ton ;
R1
R2
urc
udkUra
A3
Hnh - b
+
_
-12
+12
Hnh - a
-E
R3
R1
R2
urc
udkUra
R1
R2
urc
udk
Hnh - c
Ura
A3
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Hnh 6-13 : a ) S to xung chm dng vi mch 555 .
b ) S to xung chm a hi bng khch i thut ton .
c ) S to xung chm to bng mch khch i thut ton .
6.4. S mch iu khin v nguyn l hot ng.
T cc khu gi thiu trn ta chn c s iu khin mt knh nh
hnh 3-13 .
Hot ng ca mch iu khin hnh 3-13 c gii thch nh sau :
in p vo ti im A (UA) c dng hnh sin , trng phavi ant ca
thyristor , qua khch i thut ton A1cho ta chui xung ch nht i xng UB.
Uc
R2
R1
_
+
+12
-12
A
R2
R3
R1
R3
A1A2
R4
C
a )
a )
b ) c )
C
+U
+Urc
C2C1
R2
R1
555
7
2 1
38 4
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Phn in p dng ca in p ch nht UBqua it D1ti A2tch phn thnh
in p ta Urc. Phn p m ca in p UBlm m thng Tranzitor Tr1, kt qu
l A2b ngn mch
( Vi Urc= 0 ) trong vng UBm . Trn u ra ca A2ta c chui in p rng caUrcgin on .
in p Urcc so snh vi in p iu khin Udkti u vo ca A3. Tng
i s Urc+ Udkquyt nh du in p u ra ca khch i thut ton A3. Trong
khong thi gian t 0 t1vi Udk> Urc, in p UD m . Trong khong t1 t2,
in p Udkv Urci ngc li , lm cho UDlt ln dng . Cc khong thi gian
tip theo gii thch in p UDtng t .
Mch a hi to xung chm A4cho ta chui xung tn s cao , vi in p UE
trn hnh 3-13 . Dao ng a hi c tn s hng chc kHz , y ch m t nh
tnh .
Hai tn hiu UDv UEcng c a ti khu AND hai cng vo . Khi
ng thi c c hai tn hiu dng UD , UE ( Trong cc khong t1 t2, t4 t5)
ta s c xung UFlm m thng cc Tranzitor, kt qu l ta nhn c chui xungnhn Xdktrn bin p xung , a ti m thyristor T .
in p Uds sut hin trn ti t thi im c xung iu khin u tin , tai
cc thi im t2 , t4trong chui xung iu khin , ca mi chu k in p ngun
cp , cho ti cui bn k in p dng ant .
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Sau y l s iu khin chnh lu cu 3 pha s dng cc khu trn:
Hnh 6-14 s iu khin chnh lu cu 3 pha
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Hnh 6-15 :TCA 785
Hnh 6-16 Vi mch TCA785
Hin nay c nhiu hng ch to cc vi x l chuyn dng iu khin cc
thyristor rt tin li . Sau y xin gii thiu v IC TCA 785 do Simens ch to c
chc nng iu khin m cc van Thyristor, Triac.... Trong n ny em s dng
TCA 785 iu khin m van thyristor.
6.5 Tng quan v TCA 785
6.5.1 Gii thiu
6.5.2 S vi mch TCA 785
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+To xung ra.
6.5.3)M t chc nng
Tn hiu ng b c c qua tr khng cao t in p dy(V5).B pht hin
in p khng s xc nh cc in p khng v chuyn chng n thanh ghi ng
b.
Thanh ghi ng b ny iu khin b to dc(lm dc xung tn hiu
khin),t C10trong b to dc c np vi dng c nh (xc nh bi R9).Nu
in p dc (in p rng ca,tam gic) V10 vt qu in p iu khin V11(gc
m ) th tn hiu in chuyn thnh dng Logic ph thuc vo ln ca in p
iu khin V11m gc m c th c dch chuyn trong khong (00 1800)
Vi mi 1/2 phn sng mt xung dng c 30 s li xut hin ti cc u ra
Q1,Q2 Gi s tn ti xung c th t ti 1800qua tC12.Nu chn 12 ni mass cc
xung trong khong gc ( 1800) s xut hin .
Cc u ra 1, 2 cung cp tn hiu ngc vi Q1,Q2 .Tn hiu ti +1800c th
c dng iu khin mt b Lgic ngoi c ti chn 3.
Mt tn hiu tng ng vi lin kt NOR ca Q1,Q2 c sn ti ca ra QZ
(chn 7)
Cng vo hn ch c th c dng loi tr hot ng ca cc cng ra Q1,Q2
1, 2.
Chn 13 c th dng m rng cc u ra 1, 2 nhm lp y rng xung
(1800- )
Q
Q
Q
Q
Q
Q
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10
10
V
V
11V
10V
V0
2.15QV
1.14QV
2.15QV
1.14QV
2.2QV
1.4QV
QUV .3
QZV .7
5V in p ng b
in p nh dc
in p dc in p iu khin
in p dc min
Chn 12 t i t
Chn 12 t i t
Chn 13 t i t
Chn 13 t i t
Hnh 6-17 Gin in p
C th iu chnh gc m t 0
0
n 180
0
in.-Thng s ch yu ca TCA 785:
in p nui: Vs= - 0.5- 18V
Dng in tiu th: IS= 10 mA
Dng in ra: I = 50 mA
in p rng ca: Vr max= (VS2) V
in tr trong mch to in p rng ca: R9= 20 k - 500 k
in p iu khin: V11= -0,5(Us2) V
T in: C10= 0,5 F
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Tn s xung ra:f = 10500 Hz
Dng in u ra ti chn 14 15 : IQ = - 10 -400 mA
in p cm : V6 = - 0.5 VS
Dng in ra ng b : Isync= - 200 + 200 A
Dng in ra ti chn 2,3,4,7 : IQ = 10 mA
in p ra ti chn 2,3,4,7 : VQ = VS (V)
Nhit tip gip : TJ = 1500C
Nhit lm vic : TSTG = - 550C n 1250C
Nhit xung quanh : TA = - 25oC n 850oC
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Tnh chn thng s mch:
Thng tin t nh sn xut cung cp ta c:
Vi R9bng khong 200K. Ta chn R9= 220K.
Vi C10= 22nF.
Khi t = t0, U10= Ucm= U11Ngi ta nhn c xung ra chn 15 nu V(t) > 0
hoc mt xung ra chn 14 nu V(t) < 0.
t0= C10.
gc
T C12khuch i rng xung ra. C th chn C 12= 0 n 330pF rng
xung t30 . Ta chn C12=330pF.
6.6. Tnh ngun nui .
Ta cn to ra ngun in p U 12 V cp cho my bin p xung, nui
IC........
Ta chn mch chnh lu cu ba pha khng iu khin dng 12 con it to
ra in p 12 V , v + 12 V nh hnh 3-17 .
in p th cp my bin p ngun nui l :
U2 =34,2
12= 5,1 V , ta chn U2= 9 V ;
Vic xy dng ngun n p mt chiu bng thyristor c nhc im l chn
v tnh ton phc tp i hi phi c k thut chuyn mn cao . S ra i ca cc
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vi mch n p h 7812 v 7912 cho php n gin ho qu trnh ny , v vy n
c s dng rng ri trong thc t .
Vi mch IC 7812 thng c ba chn , chn u vo , chn u ra v chn ni
t. Do c nhiu hng sn xut ra loi IC ny do hnh dng bn ngoi v th tca cc chn c khc nhau .
Hnh 6-19 : S nguyn l to ngun nui 12 V .
V vy n nh in p ra ca ngun nui , ta dng hai vi mch n p l
7812 v 7912 , cc thng s chung ca vi mch ny nh sau :
470F
A B C
220
V
a b c*a *b *c
** *
C5 C4
470F
C7
470F
C6
470F
7812
7912
0 +12 V-12 V
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in p u vo : UV= 7 35 V ;
in p ra : Vi IC 7812 th Ura= + 12 V ;
Vi IC 7912 th Ura= - 12 V ;
Dng in u ra : Ira = 0 1 A ;T in C4 , C5, C6, C7dng lc thnh phn sng hi bc cao .
Chn C4= C5= C6= C7= 470 F ; U = 35 V .
6.7. Tnh ton my bin p ngun nui v ng pha.
- Ta thit k my bin p dng cho c vic to in p ng pha v to ngun
nui . Chn kiu my bin p ba pha ba tr , trn mi trc ba cun dy , mt
cun s cp v hai cun th cp .
- in p ly ra th cp my bin p lm in p ng pha , v lm in p
ca ngun nui .
U2 = U2ph = UN = 9 V ;
- Dng in th cp my bin p ng pha .
I2ph = 1 mA ;
- Cng sut ngun nui cp cho my bin p xung .
Pph = 6.U2ph.I2ph = 6.9.1.10-3 = 0,054 W ;
- Cng sut my bin p xung cp cho cc iu khin thyristor .
Px = 6.Udk.Idk = 6.3.0,2 = 3.6 W ;
- Cng sut s dng cho vic to ngun nui .
PN= Pph+ P8IC+ Px
PN= 0,054 + 5,12 + 3,6 = 8,774 W ;
- Cng sut ca my bin p c k n 5% tn tht trong my .S = 1,05(Pph+ PN) = 1,05(0,054 + 8,774) = 9,269 VA ;
- Dng in th cp my bin p .
I2 =9.6
269,9
.62
U
S= 0,172 A ;
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Hnh 6-20Mch ng lc c thit b bo v .
T1T
T T6
T T
FG
T4T1
T6T
T2T5
+ -Ckt
Ikt
M
L
Lc
u2c
CBA
u2bu2a
1cc 1cc 1cc
Lc
Lc
Lc
R R
R
RR
R
R R
R
RR
R
C C
C
CC
C
C C
C
CC
C
2cc
2cc
2cc
2cc
2cc
2cc
2cc2cc
2cc 2cc
2cc2cc
3cc
Ap
BAL
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6.9.2. Bo v qu nhit cho cc van bn dn
Khi lm vic vi dng in chy qua , trn van c s st p , do c tn hao
cng sut P , tn hao ny sinh ra nhit t nng van bn dn . Mt khc van bn
dn ch c php lm vic di nhit cho php TCPno , nu qu nhit cho php th cc vanbn dn s b ph hng . van bn dn lm vic an ton ,
khng b chc thng v nhit , ta phi chn v thit k h thng tn nhit hp l .
Tnh ton cnh tn nhit :
- Tn tht cng sut trn mt thyristor .
P = U.Ilv= 2.23,09 = 46,18 W ;
- Din tch b mt to nhit .
Sm =.mK
P ;
Trong :
P : Tn hao cng sut ( W ) ;
: chnh lch nhit so vi mi trng .
Km: H s to nhit bng i lu v bc x . Chn Km= 8 W/m2.0C .
Tlv,Tmt: Nhit lm vic v nhit ca mi trng (0C) .
Chn nhit mi trng Tmt= 400C . Nhit lm vic cho php ca
thyristor Tcp = 1250C . Chn nhit trn cnh tn nhit Tlv = 80
0C .
= Tlv - Tmt = 80 - 40 = 400C ;
Vy : Sm =40.8
18,46 = 0,144 m2 ;
Chn loi cnh tn nhit c 12 cnh , kch thc mi cnh l
a b = 16 16 (cm cm ) .
Tng din tch ca cnh tn nhit .
S = 12 . 2 . 16 . 16 = 0,6144 m2 ;
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6.9.3. Bo v qu dng cho van .
Aptomat dng ng ct mch ng lc , t ng bo v khi qu ti v
ngn mch thyistor , ngn mch u ra b bin i , ngn mch th cp my
bin p , ngn mch ch nghch lu .- Chn aptomat c :
Idm= k.I = 1,1. 3 .I1 = 1,1 . 3 . 17,93 = 34,16 A ;
Vi I1: l dng in s cp my bin p .
k : H s an ton .
Udm = 400 V ;
Aptomat c ba tip im chnh , c th ng ct bng tay hoc bng namchm in .
Chnh nh dng ngn mch .
Inm = 2,5.I = 2,5. 3 .17,93 = 77,64 A ;
Dng qu ti .
Iqt = 1,5 .I = 1,5 . 3 . 17,93 = 46,58 A ;
- Chn cu dao c dng nh mc .
ICD = IdmAP = 34,16 A ;
Cu dao dng to khong cch an ton khi sa cha h truyn ng .
- Dng dy chy tc ng nhanh bo v ngn mch cc thyristor ,
ngn mch u ra ca b chnh lu .:
Nhm 1CC :
Dng in nh mc dy chy nhm 1CC l :I1CC = 1,1.I2 = 1,1 . 32,6 = 35,86 A ;
Nhm 2CC :
Dng in nh mc dy chy nhm 2CC l :
I2CC = 1,1.IhdV = 1,1 . 23,09 = 25,399 A ;
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Nhm 3CC :
Dng in nh mc dy chy nhm 3CC l :
I3CC = 1,1.Idm = 1,1 . 40 = 44 A ;
Vy chn cu chy nhm :1CC loi 100 A ; 2CC loi 100 A ; 3CC loi 100 A ;
6.9.4. Bo v qu in p cho van .
Linh kin bn dn ni chung v linh kin bn dn cng sut ni ring ,
rt nhy cm vi s thay i ca in p . Nhng yu t nh hng ln nht
ti van bn dn m ta cn c phng thc bo v l :
- in p t vo van ln qu thng s ca van .
- Xung in p do chuyn mch van .
- Xung in p t pha li in xoay chiu , nguyn nhn thng gp l
do ct ti c in cm ln trn ng dy .
- Xung in p do ct t ngt my bin p non ti .
- bo v cho van lm vic di hn khng b qu in p , th ta phi
chn ng cc van bn dn theo in p ngc .
- bo v qu in p ca xung in p do qu trnh ng ct cc van
thyristor c thc hin bng cch mc R C song song vi thyristor . Khi c s
c chuyn mch , cc in tch tch t trong cc lp bn dn phng ra ngoi to ra
dng in ngc trong khong thi gian ngn . S bin thin nhanh chng ca
dng in ngc gy ra sc in ng cm ng rt ln trong cc in cm , lm
cho qu in p gia ant v catt ca thyristor . Khi c mch R C mc songsong vi thyristor , to ra mch vng phng in tch trong qu trnh chuyn mch
nn thyristor khng b qu in p .
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Theo kinh nghim R1= ( 5 30 ) ; C1= ( 0,25 4 ) F ;
Ta chn : R1= 5,1 ; C1= 0,25 F ;
Hnh 6-20 : Mch R C bo v qu in p khi van chuyn mch .
- bo v cho xung in p li t in p li , ta mc song song vi ti
u vo mt mch R C nhm lc xung . Khi xut hin xung in p trn ng
dy , nh c mch lc ny m nh xung gn nh nm li hon tan trn in tr
ng dy .
Tr s R , C ph thuc nhiu vo ti .
Theo kinh nghim R2= ( 5 30 ) ; C2= 4 F ;
Ta chn : R1= 12,5 ; C1= 4 F ;
Hnh 6-21 : Mch R C bo v xung in p t li.
R1 C1
R2 R2C2 C2
C2R2
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6.10 Thit k cun khng lc :
6.10.1Xc nh gc m cc tiu v cc i in p iu khin cc tiu, cc i
Khi gc m nh nht = min th in p trn ti ln nht :
Ud max = Ud0.Cosmin = Ud.dmv lc ny tng ng vi tc ng c sln nht nmax= ndm.
min= arccos( ) =
= arc
= 35
o
in p iu khin tng ng gc m 350
= 1,95V (Urcmax= Us2V = 12- 2 = 10V)
Ta c:
D =m in
m ax
n
n=
,,
,,
.
.
.m in.
..
udmud
udmudmd
RIU
RIU
Ud.min= dmudmud RIDUD ..m in. ,, ..1
1
Ud.min = dtBAudmu RRRIDUD ,, ..1cos..34,2
1.m in2
Ud.min =
BABAudmu XRRIU
3..120cos..34,2
20
1,, .min2
Thay svo ta c :
Ud.min =
67,0.
306,001,0.40.120cos.209.34,2
20
1min
Vy : Ud.min= 53,25 V .
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Thay Ud.minvo cng thc ( 3-3 ) ta c :
max = arcos(0
m in.
d
d
U
U) = arcos(
209.34,2
25,53) = 780 .
= 4,33V (Urcmax= Us2V = 12- 2 = 10V)
6.10.2. Xc nh cc thnh phn sng hi
thun tin cho vic khai trin chui Fourier , ta chuyn gc to sang 1,
khi in p tc thi trn ti khi thyristor T1v T4dn :
Ud= Uab= 6 .U2cos( -6
+ ) ; Vi = .t ;
in p tc thi trn ti Udkhng sin v tun hon vi chu k :
=36
22
p;
Trong p = 6 l s xung p mch trong mt chu k inp li .
Khi khai trin chui Fourier ca in p Ud:
Ud= ).2
sin.2
cos.(2 1
0
kbka
an
K
n
;
Hay :
Ud= ).6sin..6cos.(2 1
0 kbkaa
n
K
n
=
=
1
.0 )6sin(2 K
mn kkUa
Trong :
*an=
0 0
2 .6cos)6
cos(66
.6cos2
dkUdkUd ;
an =
cos
1)6(
)2(63cos
6sin2.
1)6(
)2(.
632222
kU
kU ;
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*bn=
0 0
2 .6sin)6
cos(66
.6cos2
dkUdkUd ;
bn =
sin
1)6(
)2(.
63sin
6sin2.
1)6(
)2(632222
kU
kU ;
Ta c :
cos63
2 2
0 Ua ;
Vy ta c bin ca in p :Uk.n =
22nn ba ;
Uk,n =
222
22 sin)6(cos
1)6(
163k
kU
;
Uk.n = 2 22
2
0 )6(11)6(
tgkk
Ud
;
Ud n nkU )6sin(cos63 1.
;
6.10.3.Xc nh in cm cun khng lc :
T phn tch trn ta thy rng , khi gc m cng tng th bin thnhphn sng hi bt cao cng ln , c ngha p mch ca in p , dng in tngln .S p mch ny lm xu ch chuyn mch ca vnh gp , ng thi gy ratn hao ph di dng nhit trong ng c . hn ch s p mch ny , ta phimc ni tip vi ng c mt cun khng lc ln Im 0,1.Idm .
Ngoi tc dng hn ch thnh phn sng hi bt cao ,cun khng lc cnc tc dng hn ch vng dng in gin on .
in khng lc cn c tnh khi gc m = max.Ta c :
Ud+ u~= E + R.Id+ R.I~+ Ldt
di
Cn bng hai v :
u~ = R.i~ + Ldt
di v R.i~
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i = 11 6cos.
..2.
1
Lf
Udtu
L
m = Im.cos ( 6 + 1)
Vy :
Im =Lf
U m
..2.6
1
0,1.Idm
Suy ra : L dmu
m
If
U
,.1,0..2.6
1
Trong : = 6 l s xung p mch trong mt chu k in p .
U1m = 2.
max22
2
max0 6116
cos.
tg
Ud
U1m = 2.
0222
78.61.16
78cos.209.34.2tg
o
= 166,55 .
Thay s trn ta tnh L :
L =dmu
m
If
U
,.1,0..2.6
1
=
40.1,0.50..2.6
55,166
= 0,02H .
in cm mch phn ng c :Lc = L+ 2LBA
Trong :Ll in cm mch phn ng ca ng c v c tnh theo cng thc
UmanxkiLindvil :
L = .dmdm
dm
Inp
U
...2
60.
Trong = 0,25 l h s ly cho ng c c cun b .
L= dmdm
dm
Inp
U
...2
60.
= 0,25.
40.955.4.2
60.400
= 6,25.10-3H = 6,25 mH .
Ta c in cm phn ng c :Lc= L+ 2LBA= 6,25 + 2 . 2,13 = 10,51 mH .
in cm cun khng lc :Lk = LLc = 0,02.10
310,51 = 9,49 mH .6.11. Thit k kt cu cun khng lc .
Cc thng s ban u :
in cm yu cu ca cun khng lc : Lk= 9,49 mH .Dng in nh mc chy qua cun khng lc : Im= 40 A .Bin dng in xoay chiu bt 1 : I1m= 10%.Idm= 4 A .- Do in cm cun khng ln v in tr rt b , ta c th coi tng tr cun
khng xp x bng in khng ca cun khng .Zt = Xk = 2.f.Lk = 2.50.9,49.10
-3= 2,98 .- in p xoay chiu ri trn cun khng lc .
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U = Zk.2
1mI = 2,23.2
4 = 6,307 V .
- Cng sut ca cun khng lc .
S = U.2
1mI = 10,249.2
4 = 28,42 VA .