Chapter 22
CHAPTER: 22 BEARING 22.1 Compass Directions
22.2 The Bearing
Bearing is written as a three digit number from 000( to 360(.
The bearing of point Q from point P is the angle between the north direction through P and the line PQ, measured in a clockwise direction.a)The bearing of Q from P = 060(b)The bearing of Q from P = 130(
c)The bearing of Q from P = 250(d)The bearing of Q from P =300(
To find the bearing of P from Q, given that the bearing of Q from P is ((,Bearing of Q from PRange value of (Bearing of P from Q
(0( ( < 180(
(180( ( 360(
Example 1 ( State the bearing of point A from point B based on the given information )
a) Point K, L and M are on level ground. Find the bearing of
i) K from N.
ii) M from K.
Solutioni)
ii)
Bearing of K from N
Bearing of M from K
= 060(
= 115( + 180(
= 295(b)
In a diagram, R is due north of P. Find the bearing of P from Q. Solution
( NPQ ( or (RPQ ) = 50(
The bearing of Q from P = 050(
The bearing of P from Q
= 50( + 180(
= 230(Example 2 ( solve problem )
a) ( With a diagram )In the diagram, points P, Q and R are on horizontal ground. PQR is an isosceles triangle. Given that PR = QR and P is due north of Q, find the bearing of
i) R from Q
ii) P from RSolution
i) ( PQR = 35(
The bearing of R from Q = 035(
ii) The bearing of P from R
= 360( - 35(
= 325(b) ( Without a diagram )
The bearing of Q from P is 150( and R is due west of Q. Given that PQ = PR = 30 m. Calculate the bearing of
i) P from R
ii) R from PSolution
(1) Sketch a diagram
(2) Answer the question(s) based on your sketch.
(i)
(ii)The bearing of P from R = 030(
The bearing of R from P = 360( - 150(
= 210(Questions Base On Examination Format
In the diagram, find the bearing of M from N.
A. 068(B. 136(C. 248(D. 280(2) In the diagram, D is due north of E and F is due south-east of E.
The bearing of F from E is
A. 045(B. 090(C. 135(D. 180(3) In the diagram, points P, Q and R are on horizontal ground. The bearing of R from P isA. 110(B. 250(C. 280(D. 300(
In the diagram, points K, M and N are on level ground. Find the bearing of K from N.
E. 010(F. 040(G. 060(H. 065(4) The bearing of R from P is
A. 038(B. 047(C. 052(D. 125(5) The bearing of B from C is
A. 120(B. 160(C. 260(D. 270(6) In the diagram, points P, Q and R are on the horizontal ground. R is due north of P. The bearing of Q from R is 148(. The bearing of P from Q isA. 032(B. 116(C. 148(D. 212(
In the diagram, T is due north of S. The bearing of T from R is 025( and bearing R from S is 250(. The bearing of S from R isE. 060(F. 065(G. 070(H. 075(
In the diagram above, points M, N and P are on the horizontal level. The bearing of P from M is 062(. Bearing M and N is
I. 152(J. 208(K. 298(L. 302(7) Points K, L and M are on the horizontal plane. L is due east of K. The bearing of M from K is 070( and bearing of L from M is 140(. Find ( KML.A. 110(B. 120(C. 130(D. 140(8) In the diagram, G is due east of F. The bearing of H from G is
A. 202(B. 212(C. 302(D. 312(
In the diagram, poits X, Y and Z are on the horizontal plane. Y is due north of X and the bearing of Y from Z is 062(.E. 078(F. 242(G. 282(H. 294(
In the diagram, P, Q and R are on the horizontal ground. Given that the bearing of point R from point Q is 030( and the bearing of point P from Q is 300(. Find the bearing of point P from R.I. 040(J. 220(K. 240(L. 250(9) In the diagram, Q is due east of R and the bearing of P from R is 030(. The bearing of P from Q is
A. 128(B. 218(C. 308(D. 318(
In the diagram, R is due east of P and Q is due south of P. The bearing of R from Q is 080(. The bearing of Q from R isE. 010(F. 090(G. 100(H. 260(10) In the diagram, L is due south of N. The bearing of M from L is
A. 080(B. 100(C. 240(D. 260(11) In the diagram, E, F and G are on the level ground. EFG is an isosceles. Find the bearing of G from F.
A. 015(B. 105(C. 205(D. 255(
In the diagram, P, Q and R are on the horizontal ground. PQ = QR . The bearing of R from P is 250( and the bearing of Q from P is 160(. Find the bearing of Q from R.E. 045(F. 070(G. 115(H. 330(12) In the diagram, E, F, G and H are on the horizontal ground. EFG is a straight line and HE = HF = FG. Find the bearing of H from G.
A. 022.5(B. 045(C. 135(D. 202.5(
In the diagram above, P, E, F and G are on the horizontal plane. E is due north of P and the bearing of G from P is 134(. Find the bearing of P from G.A. 046(B. 104(C. 224(D. 314(Past Year SPM Questions.Nov 2003, Q14
In the diagram, E lies to the north of G. The bearing of G from F is
A. 110(B. 250(C. 290(D. 310(July 2004, Q18
2. Diagram 11 shows three points P, Q and R which forms an equilateral triangle on a horizontal plane.
The point P is due north of the point Q. The bearing of the point Q from the point R isA. 060oB. 120oC. 240oD. 300oNov 2004, Q18
3. Points P, Q and R lie on a horizontal plane. P is due south of Q. The bearing of R from Q is 150( and the bearing of P from R is 300(. Which of the following diagrams shows the position of P, Q and R?
A. C.B.
D.Nov 2005, Q16
In the above diagram shows the position of points P and Q. Find the bearing of point P from point Q.A. 035(B. 055(C. 125(D. 215(July 2005, Q17
4. Diagram 9 shows three points, K, L and M on a horizontal plane.
The bearing of L from K is 250o and = 120o.
Find the bearing of M from K.
A. 040oB. 050oC. 130oD. 140oNov 2006, Q17
5. Points M and N lie on a horizontal plane. The bearing of M from N is 060o. Which of the following diagrams shows the positions of M and N?A.
B.
. C. D. Nov 2007, Q16
7. Diagram 10 shows three points, P,Q and R, on a horizontal plane.
It is given that Q lies due north of P and the bearing of R from Q is 0750. Find the bearing of P from R.
A. 049oB. 101oC. 229oD. 281oJun 2007, Q18
8. In Diagram 11, P,Q and R are three points on a horizontal plane such that PR=RQ=QP.
Given that Q is due east of P, Find the bearing of Q from R.
A. 330oB. 150oC. 120oD. 060oNov 2008, Q179. Diagram 10 shows three points, P,Q and R, on a horizontal plane.
It is given that P is due north of Q. Find the bearing of R from P.
A. 052oB. 076oC. 104oD. 128oJun 2008, Q17
10. Points P and Q lie on a horizontal plane. The bearing of P from Q is 220o. Which diagrams shows the locations of P and Q?
A.
B.
.
C.
D.
ANSWERS
Chapter 22 Bearing
22.3 Questions According to Examination Format
1. D
2.C
3.B
4. C
5. D
6.D7. D
8. C
9. C 10. A
11. C
12. C 13. D
14. C
15. D 16. D
17. D
18. C
19. C
20. D
21. D 22.4 SPM Past Year Questions
1) C
2) C
3) C
4) D
5) C
6) A
7) C
8) B
9) B
10) A
North
000(/360(
North-east
045(
East
090(
South-east
135(
South
180(
South-west
225(
West
270(
North-west
315(
North
P
P
North
P
North
P
North
Q
Q
Q
Q
60(
130(
250(
300(
P
(
N
N
Q
( + 180(
Q
P
( - 180(
N
N
North
North
M
N
K
60(
115(
K
60(
115(
N
115(
60(
North
K
180(
M
North
North
P
Q
R
100(
30(
30(
100(
R
Q
P
North
50(
50(
180(
110(
110(
Q
P
R
Q
P
R
North
North
35(
35(
35(
P
R
Q
North
150(
150(
North
P
150(
R
30(
D
150(
E
North
P
R
F
North
P
Q
RP
110(P
115(
55(
M
N
K
North
North
P
Q
R
48(
80(
North
C
BC
AC
North
40(
140(
60(
M
NM
North
North
68(
P
QP
RP
North
North
TRP
SQP
RP
North
N
P
M
56(
H
FH
GH
120(
28(
40(
Y
Z
X
P
Q
R
50(
P
Q
R
82(
P
Q
R
M
LM
NM
20(
60(
250(
North
R
Q
P
North
E
F
GE
85(
North
G
FG
EG
HG
North
E
FE
GE
F
E
G
20(
50(
North
North
P
Q
145(
North
North
North
North
Q
P
R
Q
P
R
Q
Q
P
R
P
R
EMBED Equation.3
P
Q
R
260
R
R
Q
P
380
Q
P
2200
2200
2200
2200
P
P
P
P
Q
Q
Q
Q
North
North
North
North
Bearing 7
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