Chapter 22

CHAPTER: 22 BEARING 22.1 Compass Directions

22.2 The Bearing

Bearing is written as a three digit number from 000( to 360(.

The bearing of point Q from point P is the angle between the north direction through P and the line PQ, measured in a clockwise direction.a)The bearing of Q from P = 060(b)The bearing of Q from P = 130(

c)The bearing of Q from P = 250(d)The bearing of Q from P =300(

To find the bearing of P from Q, given that the bearing of Q from P is ((,Bearing of Q from PRange value of (Bearing of P from Q

(0( ( < 180(

(180( ( 360(

Example 1 ( State the bearing of point A from point B based on the given information )

a) Point K, L and M are on level ground. Find the bearing of

i) K from N.

ii) M from K.

Solutioni)

ii)

Bearing of K from N

Bearing of M from K

= 060(

= 115( + 180(

= 295(b)

In a diagram, R is due north of P. Find the bearing of P from Q. Solution

( NPQ ( or (RPQ ) = 50(

The bearing of Q from P = 050(

The bearing of P from Q

= 50( + 180(

= 230(Example 2 ( solve problem )

a) ( With a diagram )In the diagram, points P, Q and R are on horizontal ground. PQR is an isosceles triangle. Given that PR = QR and P is due north of Q, find the bearing of

i) R from Q

ii) P from RSolution

i) ( PQR = 35(

The bearing of R from Q = 035(

ii) The bearing of P from R

= 360( - 35(

= 325(b) ( Without a diagram )

The bearing of Q from P is 150( and R is due west of Q. Given that PQ = PR = 30 m. Calculate the bearing of

i) P from R

ii) R from PSolution

(1) Sketch a diagram

(2) Answer the question(s) based on your sketch.

(i)

(ii)The bearing of P from R = 030(

The bearing of R from P = 360( - 150(

= 210(Questions Base On Examination Format

In the diagram, find the bearing of M from N.

A. 068(B. 136(C. 248(D. 280(2) In the diagram, D is due north of E and F is due south-east of E.

The bearing of F from E is

A. 045(B. 090(C. 135(D. 180(3) In the diagram, points P, Q and R are on horizontal ground. The bearing of R from P isA. 110(B. 250(C. 280(D. 300(

In the diagram, points K, M and N are on level ground. Find the bearing of K from N.

E. 010(F. 040(G. 060(H. 065(4) The bearing of R from P is

A. 038(B. 047(C. 052(D. 125(5) The bearing of B from C is

A. 120(B. 160(C. 260(D. 270(6) In the diagram, points P, Q and R are on the horizontal ground. R is due north of P. The bearing of Q from R is 148(. The bearing of P from Q isA. 032(B. 116(C. 148(D. 212(

In the diagram, T is due north of S. The bearing of T from R is 025( and bearing R from S is 250(. The bearing of S from R isE. 060(F. 065(G. 070(H. 075(

In the diagram above, points M, N and P are on the horizontal level. The bearing of P from M is 062(. Bearing M and N is

I. 152(J. 208(K. 298(L. 302(7) Points K, L and M are on the horizontal plane. L is due east of K. The bearing of M from K is 070( and bearing of L from M is 140(. Find ( KML.A. 110(B. 120(C. 130(D. 140(8) In the diagram, G is due east of F. The bearing of H from G is

A. 202(B. 212(C. 302(D. 312(

In the diagram, poits X, Y and Z are on the horizontal plane. Y is due north of X and the bearing of Y from Z is 062(.E. 078(F. 242(G. 282(H. 294(

In the diagram, P, Q and R are on the horizontal ground. Given that the bearing of point R from point Q is 030( and the bearing of point P from Q is 300(. Find the bearing of point P from R.I. 040(J. 220(K. 240(L. 250(9) In the diagram, Q is due east of R and the bearing of P from R is 030(. The bearing of P from Q is

A. 128(B. 218(C. 308(D. 318(

In the diagram, R is due east of P and Q is due south of P. The bearing of R from Q is 080(. The bearing of Q from R isE. 010(F. 090(G. 100(H. 260(10) In the diagram, L is due south of N. The bearing of M from L is

A. 080(B. 100(C. 240(D. 260(11) In the diagram, E, F and G are on the level ground. EFG is an isosceles. Find the bearing of G from F.

A. 015(B. 105(C. 205(D. 255(

In the diagram, P, Q and R are on the horizontal ground. PQ = QR . The bearing of R from P is 250( and the bearing of Q from P is 160(. Find the bearing of Q from R.E. 045(F. 070(G. 115(H. 330(12) In the diagram, E, F, G and H are on the horizontal ground. EFG is a straight line and HE = HF = FG. Find the bearing of H from G.

A. 022.5(B. 045(C. 135(D. 202.5(

In the diagram above, P, E, F and G are on the horizontal plane. E is due north of P and the bearing of G from P is 134(. Find the bearing of P from G.A. 046(B. 104(C. 224(D. 314(Past Year SPM Questions.Nov 2003, Q14

In the diagram, E lies to the north of G. The bearing of G from F is

A. 110(B. 250(C. 290(D. 310(July 2004, Q18

2. Diagram 11 shows three points P, Q and R which forms an equilateral triangle on a horizontal plane.

The point P is due north of the point Q. The bearing of the point Q from the point R isA. 060oB. 120oC. 240oD. 300oNov 2004, Q18

3. Points P, Q and R lie on a horizontal plane. P is due south of Q. The bearing of R from Q is 150( and the bearing of P from R is 300(. Which of the following diagrams shows the position of P, Q and R?

A. C.B.

D.Nov 2005, Q16

In the above diagram shows the position of points P and Q. Find the bearing of point P from point Q.A. 035(B. 055(C. 125(D. 215(July 2005, Q17

4. Diagram 9 shows three points, K, L and M on a horizontal plane.

The bearing of L from K is 250o and = 120o.

Find the bearing of M from K.

A. 040oB. 050oC. 130oD. 140oNov 2006, Q17

5. Points M and N lie on a horizontal plane. The bearing of M from N is 060o. Which of the following diagrams shows the positions of M and N?A.

B.

. C. D. Nov 2007, Q16

7. Diagram 10 shows three points, P,Q and R, on a horizontal plane.

It is given that Q lies due north of P and the bearing of R from Q is 0750. Find the bearing of P from R.

A. 049oB. 101oC. 229oD. 281oJun 2007, Q18

8. In Diagram 11, P,Q and R are three points on a horizontal plane such that PR=RQ=QP.

Given that Q is due east of P, Find the bearing of Q from R.

A. 330oB. 150oC. 120oD. 060oNov 2008, Q179. Diagram 10 shows three points, P,Q and R, on a horizontal plane.

It is given that P is due north of Q. Find the bearing of R from P.

A. 052oB. 076oC. 104oD. 128oJun 2008, Q17

10. Points P and Q lie on a horizontal plane. The bearing of P from Q is 220o. Which diagrams shows the locations of P and Q?

A.

B.

.

C.

D.

ANSWERS

Chapter 22 Bearing

22.3 Questions According to Examination Format

1. D

2.C

3.B

4. C

5. D

6.D7. D

8. C

9. C 10. A

11. C

12. C 13. D

14. C

15. D 16. D

17. D

18. C

19. C

20. D

21. D 22.4 SPM Past Year Questions

1) C

2) C

3) C

4) D

5) C

6) A

7) C

8) B

9) B

10) A

North

000(/360(

North-east

045(

East

090(

South-east

135(

South

180(

South-west

225(

West

270(

North-west

315(

North

P

P

North

P

North

P

North

Q

Q

Q

Q

60(

130(

250(

300(

P

(

N

N

Q

( + 180(

Q

P

( - 180(

N

N

North

North

M

N

K

60(

115(

K

60(

115(

N

115(

60(

North

K

180(

M

North

North

P

Q

R

100(

30(

30(

100(

R

Q

P

North

50(

50(

180(

110(

110(

Q

P

R

Q

P

R

North

North

35(

35(

35(

P

R

Q

North

150(

150(

North

P

150(

R

30(

D

150(

E

North

P

R

F

North

P

Q

RP

110(P

115(

55(

M

N

K

North

North

P

Q

R

48(

80(

North

C

BC

AC

North

40(

140(

60(

M

NM

North

North

68(

P

QP

RP

North

North

TRP

SQP

RP

North

N

P

M

56(

H

FH

GH

120(

28(

40(

Y

Z

X

P

Q

R

50(

P

Q

R

82(

P

Q

R

M

LM

NM

20(

60(

250(

North

R

Q

P

North

E

F

GE

85(

North

G

FG

EG

HG

North

E

FE

GE

F

E

G

20(

50(

North

North

P

Q

145(

North

North

North

North

Q

P

R

Q

P

R

Q

Q

P

R

P

R

EMBED Equation.3

P

Q

R

260

R

R

Q

P

380

Q

P

2200

2200

2200

2200

P

P

P

P

Q

Q

Q

Q

North

North

North

North

Bearing 7

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