Upload
amroabdh
View
217
Download
0
Embed Size (px)
Citation preview
8/10/2019 Wireless Com 31st March Lec13
1/35
8/10/2019 Wireless Com 31st March Lec13
2/35
Wireless Communications:
System Design
Dr. Mustafa Shakir
8/10/2019 Wireless Com 31st March Lec13
3/35
8/10/2019 Wireless Com 31st March Lec13
4/35
What is power control ?
Both the BS and MS transmitter powers are adjusteddynamically over a wide range.
Typical cellular systems adjust their transmitter powersbased on received signal strength.
TYPES OF POWER CONTROLo Open Loop Power Control
It depends solely on mobile unit, not as accurate asclosed loop, but can react quicker to fluctuation in signalstrength. In this there is no feed back from BS.
o Closed Loop Power ControlIn this BS makes power adjustment decisions andcommunicates to mobile on control channels
8/10/2019 Wireless Com 31st March Lec13
5/35
Why power control ?
Near-far effect
Mechanism to compensate for channel
fading
Interference reduction,
prolong battery life
8/10/2019 Wireless Com 31st March Lec13
6/35
Improving Capacity in Cellular Systems
Cost of a cellular network is proportional to the numberof Base Stations. The income is proportional to thenumber of users.
Ways to increase capacity:
New spectrum expensive. PCS bands were sold for$20B.
Architectural approaches: cell splitting, cell sectoring,microcell zones.
Dynamic allocation of channels according to load inthe cell (non-uniform distribution of channels).
Improve access technologies.
8/10/2019 Wireless Com 31st March Lec13
7/35
Cell Splitting
Cell Splitting is the process of subdividing thecongested cell into smaller cells (microcells), Eachwith its own base station and a correspondingreduction in antenna height and transmitter power.
Cell Splitting increases the capacity since number ofclusters over coverage region would be increased thusincreasing the number of channels.
New cells added having smaller radius than originalcells and by installing these smaller cells (calledmicrocells ) between existing cells , capacity increasesdue to additional number of channels per unit area.
8/10/2019 Wireless Com 31st March Lec13
8/35
Cell splitting diagram 1
8/10/2019 Wireless Com 31st March Lec13
9/35
8/10/2019 Wireless Com 31st March Lec13
10/35
An Example
The area covered by a circle with radius R isfour times the area covered by the circle withradius R/2 The number of cells is increased fourtimes
The number of clusters the number of channelsand the capacity in the coverage area are
increased Cell Splitting does not change the co-channel re-use ratio Q =D/R
8/10/2019 Wireless Com 31st March Lec13
11/35
Transmit Power
New cells are smaller, so the transmit power ofthe new cells must be reduced
How to determine the transmit power? The transmit power of the new cells can be
found by examining the received power at thenew and old cell boundaries and setting themequal
Pr(at the old cell boundary) is proportional to
Pt1 * R-n Pr(at the new cell boundary) is proportional to
Pt2 * (R/2)-n
8/10/2019 Wireless Com 31st March Lec13
12/35
Transmit Power
Take n=4, we get
Pt2 = Pt1/16
We find that the transmit power must bereduced by 16 times or 12 dB in order to usethe microcells to cover the original area.While maintaining the same S/I.
8/10/2019 Wireless Com 31st March Lec13
13/35
Application of cell splitting
When there are two cell sizes one cant simply use
the same transmit power for all cells. If larger transmit power used for all cells some smaller cellswould not be sufficiently separated from co channelcells. Using smaller Pt the larger cells might be left
unserved. So old channel broken to two channel groups
corresponding to smaller and larger cell reuse.
Larger cell for less frequent hand off.
Antenna down tilting focusing radiated energy frombase station to the ground to limit radio coverage ofnewly formed cells.
8/10/2019 Wireless Com 31st March Lec13
14/35
8/10/2019 Wireless Com 31st March Lec13
15/35
Cell Sectoring Co channel interference may be reduced by replacing
omni directional antenna by several directional antennas. Given cell will receive interference and would transmit
with fraction of available co channel cells.
Each sector uses directional antenna at the B.S and
assigned a set of channels. Partitioning into three 120 deg. sectors or six 60 deg.
sectors.
Amount of CCI reduced by number of sectors.
Reduced Tx Power
15
8/10/2019 Wireless Com 31st March Lec13
16/35
Cell Sectoring
8/10/2019 Wireless Com 31st March Lec13
17/35
Example for sectoring
8/10/2019 Wireless Com 31st March Lec13
18/35
Explanation For Cell Sectoring
8/10/2019 Wireless Com 31st March Lec13
19/35
Effects of Sectoring Reduction in interference offered by sectoring would
enable to reduce the cluster size N and additionaldegree of freedom in channel assignment.
Increased number of antennas with shrinking cluster sizeand decrease in trunking efficiency due to channel
sectoring at base station.
Since sectoring reduces the coverage area of aparticular group of channels the number of handoffsincreases
Available channels subdivided and dedicated to aspecific antenna thus making up of several smaller poolscontributing to decrease in trunking efficiency.
8/10/2019 Wireless Com 31st March Lec13
20/35
Repeaters
To provide dedicated coverage for hard to reachareas
Radio retransmitters for range extension.
Upon receiving signals from base station
forward link the repeater amplifies andreradiates the base station signals to specificcoverage region.
In building wireless coverage by installingDistributed Antenna Systems.
Repeaters must be provisioned to match theavailable capacity from the serving base station.
8/10/2019 Wireless Com 31st March Lec13
21/35
Repeaters For Range Extension
8/10/2019 Wireless Com 31st March Lec13
22/35
Microcell Zone The increased number of handoff as a result of sectoring
would result in an increased load on switching andcontrol link elements of the mobile system.
Division into microcell zones and each of the three areconnected to a single base station and share the same
radio equipment. Zones connected by a coaxial cable, fiber optic cable or
microwave link to the base station.
Handoff not required while mobile travels between zones
within cell. Channel switching and a channel active only within zone
of travelling.
8/10/2019 Wireless Com 31st March Lec13
23/35
8/10/2019 Wireless Com 31st March Lec13
24/35
8/10/2019 Wireless Com 31st March Lec13
25/35
Scenario
In Micro cell zone scenario each hexagonrepresents a zone while the group of threehexagons represent a cell.
Zone Radius Rz is one hexagon radius.
Capacity of Microcell is directly related todistance betw. Cochannel cells and notzones.
No handoffs is required at the MSC.
The base station radiation is localized andinterference is reduced
8/10/2019 Wireless Com 31st March Lec13
26/35
Trunking & Grade Of Service
8/10/2019 Wireless Com 31st March Lec13
27/35
Trunking and Grade of Service (GOS)
Trunking A means for providing access to users on
demand from available pool of channels. With trunking, a small number of
channels can accommodate largenumber of random users. Telephone companies use trunking
theory to determine number of circuitsrequired.
Trunking theory is about how a populationcan be handled by a limited number of servers.
8/10/2019 Wireless Com 31st March Lec13
28/35
Terminologies Erlang:
One Erlang:When a circuit is busy for one hour it handled a traffic of one erlang.
Grade of Service (GOS):
probability that a call is blocked (or delayed).
Set-Up Time:
Traffic intensity is measured in Erlangs:
time to allocate a channel.
Blocked Call:
Call that cannot be completed at time of request
due to congestion. Also referred to as Lost Call.
8/10/2019 Wireless Com 31st March Lec13
29/35
Terminologies
Contd. Holding Time: (H)Average duration of typical call.
Load:
Traffic intensity across thewhole system.
Request Rate: ()
Average number of call requests per unittime.
8/10/2019 Wireless Com 31st March Lec13
30/35
Traffic Measurement (Erlangs)
Traffic per userAu = H where is the request rate
and H is the holding time. For U users the load isA= UAu If traffic is trunked in C channels, then the traffic
intensity per channel isAc= UAu /C
Erlang B:
8/10/2019 Wireless Com 31st March Lec13
31/35
The Erlang B Chart
8/10/2019 Wireless Com 31st March Lec13
32/35
Example Example : An urban area has 2 million
residents. Three competing cellular systemsprovide service:
System A 394 cells x 19 channels/cell. System B 98 cells x 57 channels/cell. System C 49 cells x 100 channels/cell. For each user = 2 calls/hr, H= 3min, GOS
= 2% blocking. Find the number of users thatcan be supported by each system. Note thatthese are not simultaneous users.
System A: Au= H= 2 x 3/60 = 0.1 Erlangs. From the curve for GOS = 0.02 and C = 19 => A = 12 Er. Users per cell (U) =A/Au= 12/0.1 = 120 users 120 users/cell x 394 cells = 47,280 users can be served.
Market penetration = 2.36%.
8/10/2019 Wireless Com 31st March Lec13
33/35
No. of subscribers System C: Prob Blocking = 2% = 0.02 C =100 Au = H= 2 x 3/60 = 0.1 Erlangs. From table,A = 88 Erlangs. Users per cell U =A/Au = 88/0.1 =880 users 880 users/cell x 49 cells = 43,120.
Market penetration = 2.156%.
System B: Prob Blocking = 2% = 0.02 C =57 Au = H= 2 x 3/60 = 0.1 Erlangs. From table,A = 45 Erlangs Users per cell U =A/Au= 45/0.1 = 450 users
450 users/cell x 98 cells = 44,100. Market penetration = 2.21%.
8/10/2019 Wireless Com 31st March Lec13
34/35
Total No. of supported users = 47,280 + 44,100
+ 43,120
= 134,500 users.
Total market penetration for 3 systems =6.725%
8/10/2019 Wireless Com 31st March Lec13
35/35