Tinh Toan Cong Nghe Cho Mot Nha May Loc Dau Www.thuvien247

8/2/2019 Tinh Toan Cong Nghe Cho Mot Nha May Loc Dau Www.thuvien247

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L I M U

Mc tiu ca n cng nghII nhm trang b cho sinh vin cc k nng cnthit khi vn dng nhng kin thc hc thit k s cng nghca mt nhmy lc du v i ngun nguyn liu cho tr c. T , cc em tin hnh tnh tontnh cht c tr ng ca cc sn phm i ra t cc phn x ng khc nhaucuicngi phi tr n cc sn phm cui cng theo nhu cu cho tr c v m bo thamn cc yu cu k thut cc sn phm theo tiu chun quc t.

c ththc hin tt n ny, sinh vin cn phi nm vng cc kin thcc bn ca cc mn chuyn ngnh: Ha hc du m, cc qu trnh chuyn ha hahc trong cng nghlc du, sn phm du m th ng phm. c bit, cc em cn phi vn dng nhun nhuyn phn mm Exceltnh ti u cc bi ton phi liu,sau phi tnh l p nhiu ln c ththit k mt nh my lc du v i cc phnx ng vn hnh theo nng sut viu kin ti u.

C thni, n cng nghII sgip cho sinh vin nm cui nm vng vh thng li ton b cc kin thc chuyn ngnh hc, chun b tt cho cc emthc hin b c cui cng ln tt nghi p.

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TR NGI HC BCH KHOAKhoa Ha K Thut

Bmn Cng NghHa Hc - Du &Kh---o-o---

N CNG NGH II NG DNG DU TH

Nhm sinh vin thc hin :L p :

I- bi:Tnh ton cng nghcho mt nh my lc du v i nguyn liu l du th ARABELGER.Sliu banu Nng sut nh my, 103 t/nm: 8600Ti thp chng ct kh quyn thu c cc phnon sau:Phnon Khong nhit si (toC)

GAZ: Kh < 20GAS: Xng nh 20 85BZN: Xng nng 85 190KER: Kerosen 190 240GO: Gasoil 240 370RDA: Phn cn kh quyn >370+ RSV: Phn cn chn khng >540+

S cng nghca nh my c th g m c:- Mt phn x ng chng ct kh quyn (DA) tch kh v cc phnon du th.- Mt phn x ng chng ct chn khng xl phn cn kh quyn (RA) nhm thu

2 loi nguyn liu:- Phn ct chn khng cung c p cho FCC,- Phn cn chng ct chn khng cung c p cho Visbreaking (VB) v sn xut

bitum.- Mt phn x ng Reforming xc tc (RC), v i ngun nguyn liu c thl:

- Phnon xng nng (BZN) thu c tDA,- Xng thu c tqu trnh gim nh t (VB).

- Mt phn x ng cr cking xc tc tng si (FCC) xl phn ct chn khng.- Mt phn x ng gim nh t (VB) xl phn cn chng ct chn khng.- Mt phn x ng HDSx l cc loi nguyn liu nu cn thit. II- Yu cu v ni dung nS dng phn mm Excel l p ch ng trnh tnh ton v Word son tho thuytminh. N i dung n:

- ti


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- Mc lc- Ch ng I: M U: Gi i thiu chung vdu th v cc loi sn phm, chc

nng v nhim v ca nh my lc du, nhim v ca n v h ng giiquyt . . .

- Ch ng II: TNH CN B NG VT LIU: Tnh cn bng vt liu cho micng on, cho mi phn x ng v cho ton bnh my (Yu cu m trrng cc ph ng php tnh ton, tra ti liu, ch thch ti liu tham kho, k tthc mi phn phi c bng tng h p cn bng vt liu).

- Ch ng III: TNH PHI LIU S N PHM cung c p nhng sn phm sautheo nhu cu ca th tr ng (Yu cu sdng phn mm Excelphi liu tiu bo m c s l ng v cht l ng ca sn phm, t xcnh nngsut ca mi phn x ng v s cng nghca nh my):Sn phm K hiu Sl ng (103 t/n)Propan PR 190Butan BU 250 Nguyn liu cho ha du PC 550Xng super khng ch 98/88 SU 98 850Xng super khng ch 95/85 SU 95 1080Jet A1 JA1 850Du Diezel GOM 1100Du t dn dng FOD 1300 Nhin liu t l N02 FO2 1050Bitum BI 230

- Ch ng IV: TNH CN B NG NHIT L NG CHO NH MY.- Ch ng V: K T LU N: Tk t qutnh ton c, nhn xt vph ng php

tnh ton, tnh kh thi khi xem xt cc mt: Tiu chun k thut, nhu cu th tr ng, cng ngh, thit b, cn bng nhin liu t ...

- Ti liu tham kho.- Ph lc (01 s dy chuyn cng nghca ton nh my khA3 gn km

theon v cc phlc khc nu c).Mi nhm n p 01 bn thuyt minh v 01 a mm gm 3 file: Word (thuyt minh),Excel (tnh ton) v ACAD (bn v).Bn v: 01 s dy chuyn cng nghca ton nh my khA1, III- Th i gian ti n hnh

- Ngy giaon:- Ngy hon thnh v n p:

Ttr ng Bmn

TS. Nguy n nh Lm

Gio vin h ng dn

GVC. ThS. L TH NH


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Theo nguyn tc bo ton khi l ng, ta c :m = m1 + m2

dm2.Vm2 = d1.V1 + d2.V2

hay : dm2.vm2 = d1.v1 + d2.v2Suy ra :

2

112m2m2 v

vdvdd .. =

T ng t, ta c :3

11223m3m3 v

vdvdvdd ... =

Cnhvy, ta stnh ton c t tr ng ca tt ccc phnon.i v i KER, GO,xcnh t tr ng, ta sdng cc s liu trong bng phn tch du th ARABIAN LIGHT ;

i v i phnon cn RA,xcnh t tr ng, ta sdng biu d415 -hiu sut thu cn theo % khi l ng (Hnh 2)

1.1.1 T trng tiu chun S (densit standard)S = 1,002 d415

1.1.2 API

5,131S

5,141API0 =

1.2 Nhit si trung bnh ca phn on1.2.1 Nhit si trung bnh hiu chnh (tv - temprature moyenne

pondre)tv c tnh ton da vo ng cong ASTM hoc TBP ;

Nu sdng ng cong ASTM, tv c tnh theo cng thc :

4tt2tt 905010v

++=

Nu sdng ng cong TBP, tv c tnh theo cng thc :

3tttt 805020v

++=

1.2.2 Nhit si trung bnh tiu chun tmav (temperature meanaverage)

- Tnhdc s ca ng cong chng ct : C)/th tch(% o60

tts 1070 =

- Da vo(Hnh 3), ta suy ratmav.- tmav = tv + tmav

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1.3 Hs c tr ng K UOP (K W) Ng i ta c thxcnh K UOP ca cc phnon du mtheo 2 cch :- Dng biu P2 tra ra ga tr ca K UOP nu bit t tr ng d415 v nhit sitrung bnh tiu chun tmav ca phnon ;

- Ap dng cng thc :S

T81K

3mav

UOP

=,

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1.4 Hm l ng l u hunhDa vo biu % L u hunh theo khi l ng - hiu sut thu xng C5+ theo %khi l ng (Hnh 1), ta tra c hm l ng lu hunh c trong phnon nh utin (xng nh) ;Sau , da vo biu trn v biu % L u hunh theo khi l ng - hiusut thu cn theo % khi l ng (Hnh 2), dng ph ng phpcng tnh theo khil ng, ta tnh c hm l ng lu hunh c trong cc phnon ti p theo.

Ngh a l :2

112m2m2 m

msmss .%.%% =

1.5 Khnng chng kch nca cc sn phm xng

xcnh gi tr ca RON c pha 0,15g Ttrathyl Ch /l :- Xcnh gi tr ca RON khng pha Ch v RON 0,5o/oo, bng cch sdng biu NO thyl 0,5o/oo - NO clair - hiu sut thu xng ;- Sau, dngP4 xc nh gi tr ca RON c pha 0,15g TEP/l (0,15g TEP/l 0,54cc TEP/gallon 0,142o/oo) bng cch ni 2 gi tr ca RON khng pha Ch vRON 0,5o/oo, sau thm l ng 0,15g TEP/l ging ln sct ng thng trn timt im. T im ny ging ngang qua, ta xcnh c gi tr ca RON c pha0,15g TEP/l.

Sau khi xc nh RON ca xng nh, ta s tin hnh xcnh RON caxng nng theo ph ng phpcng tnh vthtch.

1.6 Hm l ng hydrocarbure Aromatique xc nh hm l ng Aromatique cho xng nh, ta tra trn biu %Aromatique - hiu sut thu xng theo % thtch ;Hm l ng Aromatique ca xng nng v Krosne s c xcnh theo ph ng php cng tnh vthtch.%Ar . %v = % Ar 1. %v1 + % Ar 2 . %v2 + + %Ar n . %vnV i : %Ar , % Ar 1, % Ar 2, , %Ar n : hm l ng Aromatique ca phnon hnh p v ca cc phnon thnh phn ;

%v, %v1, %v2, , %vn : hiu sut th tch thu c ca phnon hnh p v ca cc phnon thnh phn ;

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1.7 nh t1.7.1 nh t ng hc (viscosite cinematique)

Mi lin hgia nh t ng lc v nh t ng hc :=

V i : - khi l ng thtch Ng i ta c thtnh gn ng gi tr ca nh t da vo cc cng thc ca Abbottv Al (1971) :

( )( )W

W222

W

W2242

WW

K 782314364250AAK 8602180A10506639A994310K 1716170

AK 10182461A1026293K 127690K 947331393714

,,,.,,,

.,.,,,,log 100

++++

++=

( )( )W

2W

W324

210

K 6296278626AA197680A248991K

AK 10489958A10134475A16653204636340

,,,,8,0325.10

.,.,,,log2-

++++

+=

V i : 210 - nh t ng hc 210F, mm2/s hay cSt ;100 - nh t ng hc 100F, mm2/s hay cSt ;

Ch :- Cc cng thc tnhnh t trn khng p dng c nu K W < 10 v A


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1.8 Khi l ng phn t xc nh khi l ng phn t cho xng nh, ta tra trn biu Masse

molaire - hiu sut thu xng C5+ theo % khi l ng ; Khi l ng phn t ca xng nng v Krosne s c xcnh theo ph ng

php cng tnh vkhi l ng . Nu ta gi :M, M1, M2, , Mn : khi l ng phn t ca phnon

hn h p v ca tng phnon thnh phn ;m, m1, m2, , mn : khi l ng ca phnon hn h p v ca

tng phnon thnh phn ;%m, %m1, %m2, , %mn: khi l ng ca phnon hn h p v ca

tng phnon thnh phn ;Ta c :

n

n

2

2

1

1n21Mm

Mm

Mm

mnnn

mnmM

+++=

+++==

......

Hay :

n

n

2

2

1

1

Mm

Mm

Mm

mM %%%%

+++=

Cni v i nhng phnon c t tr ng tiu chun S < 0,97 v nhit si T b 600K, ng i ta th ng sdngcng thc ca Lee v Kesler :

( ) ( )

( )

++

+++=

b

23

b

b

2

b

7

b

T335417322840S022260S8088201

T

T

46622274650S020580S7708401T

10S9917537418TS49486612272M

,,,,10

,,,,,,,,

12

Trong : M - khi l ng phn t, kg/kmol ;

T b - nhit si trung bnh tiu chun ca phnon, K;S - t tr ng tiu chun ca phnon.

Sai strung bnh khi tnh ton theo 2 cng thc trn khong 5 %.

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Khi l ng phn t cng c th c xc nh t ng i chnh xci v inhng phnon khng xcnh c nhit si trung bnh tiu chun m ch xcnh c nh t 100oF v 210oF theo cng thc sau :

M = 223,56100(1,1228S - 1,2435) 210(3,4758 - 3,038S)S-0,6665

V i : M - khi l ng phn t, kg/kmol ;100 - nh t ng lc 100oF (37,8oC)210 - nh t ng lc 210oF (98,9oC)S - t tr ng tiu chun ca phnon.

Sai strung bnh khi tnh ton theo cng thc trn khong 10 %.

1.9 p sut h i bo ha xc nh p sut h i bo ha Reid (TVR) ca Xng nh sdng biu

TVR - % khi l ng ca xng. TVR ca Xng nng c xcnh theo ph ng php cng tnh vphn mol :

BZN

BZNGAS

GAS

GASBZN m%

MTVR Mm%TVR

Mm%TVR

=

Chuyn i t p sut h i bo ha Reid (TVR) sang p sut h i bo ha thc(TVV) :

TVR TVVR =

Gi tr ca hschuyn i c cho trong bng 4.13 (I - 162)

1.10 im ch p chy c xcnh theo cng thc [4.102] c a ra b i API (I - 164) :

1010

e T00342540T

849472024210

1T ln,,, ++=

V i : T10 - nhit si t ngng v i ct 10% thtch theo ng cong ASTM[K]Sai strung bnh ca cng thc trn khong 5 oC chuyn T10 (TBP) sang T10 (ASTM) p dng cng thc [4.104] ca Riazi

(I - 165) :T = a T b

V i : T - nhit xcnh theo ng ASTM D86 [K]

16/35 T - nhit xcnh theo ng TBP [K]


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a, b - cc hs, phthuc vo thnh phn % chng ct c, gi tr c tratheo bng [4.16] (I - 166)

1.11 Ch sCtane (IC) c xc nh theo cng thc c a ra b i cng ty ETHYL theo ph ng

php ASTM D 976 (I - 222):IC = 454,74 - 1641,416 + 774,742 - 0,554 (T50) +97,083 (log T50)2

V i : - khi l ng ring ca nhin liu 15 oC [kg/l]T50 - nhit si t ng ng v i 50%ct theo ph ng php ASTM D86[K]

1.12 im chy i v i cc phnon trung gian nh GO xc nh im chy theo biu

im chy ( oC) - % khi l ng ca phn on im u, % khi l ngca phn on im cui.

i v i RA xc nh im chy theo biu im chy ( oC) - % khil ng ca cn RA.

i v i KER, ta p dng cng thc [4.113] c a ra b i API (I - 174) :( ) ( )S3330310

100

S474061209712

ECMS47130T .,,.,,,, =

Sai sca cng thc trn khong 5oC. Cng thc ch p dng c i v i cc phnon cim chy < 60oC.

2 CN BNG VT CHT CHO CC PHN X NGKHC

2.1 Phn x ng ch ng ct chn khng Theobi, khong phnon ca RSV l 565 +oC, t ta c bng sau :

Khong phnon, oC

Phn khi l ng,%

Hiu sut %khi l ngchung

Hiu sut % khil ng i v i RA

DSVRSV

370 - 565565 +

53,67 83,6783,67 100

30,0016,33

64,7535,25

Charge : RA 53,67 100 46,33 100

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Nguyn liu l RA v i nng sut 3845,39.103 T/n sn l ng ca DSV thu c l :

DSV : 3845,39.103 x 64,75 % = 2489,89.103 T/n Nhng phn x ng FCC theo d liu banu ch t nng sut theo nguyn liu

l 240 T DSV/h, tc l 1920.103 T/n khnga ht RA lm nguyn liu chothp chng ct chn khng, m ch a mt l ng l :

1920.103 x 100 / 64,75 = 2965,25.103 T/n. Vy l ng RA cn li l :3845,39.103 - 2965,25.103 = 880,13.103 T/n s c dngphi liu sn phm

sau ny. L ng RSV thu c l :

1920.103

/ 64,75 x 35,25 = 1045,25.103

T/n. RSV thu c, mt phn ss dng sn xut Bitum v i nng sut 320.103 T/n.

L ng RSV cn li l :1045,25.103 - 320.103 = 725,25.103 T/n dng lm nguyn liu cho qu trnh gim

nh t t cc yu cu cho vic phi liu sn phm sau ny. xc nh t tr ng ca DSV v RSV sdng cc s liu trong bng phn

tch du th ARABIAN LIGHT.

Ta c bng cn bng vt cht cho phn x ng chng ct chn khng :

Hiu sut %khi l ng iv i RA

Sn l ng theokhi l ng x 103 T/n

d415 Sn l ng theoth tch x 103 T/n

DSVRSV

64,7535,25

19201045,25

0,9221,025

2082,431019,76

Charge : RA 100 2965,25 0.956 3102,19

2.2 Cracking xc tc tng sithit l p bng cn bng vt liu cho qu trnh FCC Tnguyn liu l DSV c : d415 = 0,922 APIo = 21,94

Tmav = 467,5 K UOP = 11,87 Sdng biu 1 ca FCC : Tgi tr ca APIo v K UOP ca nguyn liu, ta suy

ra c :Hiu sut chuyn ha theo % thtch ca nguyn liu = 67,8 % thtch% khi l ng cc to thnh = 6,1% thtch gasoil sn phm LCO = 13,6

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Cn HCO = 100 - hiu sut chuyn ha theo % vol nguyn liu - % vol gasoil

sn phm

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= 100 - 67,8 - 13,6= 18,6 % thtch

Theo d liu banu, sn phm xng ca phn x ng FCC c RON claire = 92

Nhvy, tgi tr RON cl v hiu sut chuyn ha theo % thtch ca nguyn liu,ta sdng biu 2 ca FCC v suy ra c :hiu sut thu xng 10 RVP = 56,4 % thtchthnh phn kh kh = 6,9 % khi l ng

Sdng biu 3, t% khi l ng ca kh kh thnh phn ca kh nhsau :C2- = 1,65C3= = 3,90C3 = 1,40C4= = 2,84iC4 + nC4 = 4,34

Xng 10 RVP l xng c p sut h i bo ha 0,69 bar Xc nh % S trong cc sn phm ca qu trnh FCC i t hm l ng lu

hunh ca nguyn liu DSV l 2,47 % v suy ra c :% S ca xng = 0,222 % khi l ng% S ca LCO = 3,102 % khi l ng

% S ca HCO = 4,338 % khi l ng Xcnh ch sOctane ca xng sn phm :

Theo ch tiu vcng ngh RONCL = 92Tcng thc trnh by trn biu 2 ca FCC :

RON3cc = RONCL + 7 + 0,5 ( 92 - RONCL)= 92 + 7 + 0,5 ( 92 - 92 )= 99

Sdng biu P4 xcnh c : RON0,15g TEL/l= 95,4

2.3 Reforming xc tc Nguyn liu : l xng nng BZN ca qu trnh chng ct tr c ti p.Cc sliu tnh c : Nng sut yu cu : 31380 bbl/sd

sd = standard day, c 330 sd/ year ; cd = calendar day, c 365 cd/ year. Nhvy, nng sut ca phn x ng Reforming xc tc l :


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31383 330 159 l = 1646,67. 106 l/n = 1646,67. 103 m3/n.

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Theo cn bng vt liu ca phn x ng chng ct kh quyn, lu l ng thtchca BZN thu c l : 1646,67. 103 m3/n a ton bBZN thu c tqutrnh chng ct tr c ti p lm nguyn liu cho phn x ng Reforming xc tc.

c tr ng ca nguyn liu BZN : d415 = 0,747Tmav = 130oC

K UOP = 12,06 Theo ch tiu vcng ngh, sn phm xng (Reformat C5+) c RONCL = 97,5K t h p v i K UOP ca nguyn liu = 12,06, s dng biu 1 ca qu trnhReforming xc tc hiu sut thu Reformat C5+ l : 78,6 T hiu sut thu Reformat C5+ = 78,6, s dng biu 2 ca qu trnhReforming xc tc, hiu sut thu cc loi kh hydrocarbure v H2 :

C1 = 1,45 % khi l ngC2 = 2,7 % khi l ngC3 = 3,8 % khi l ngC4 = 5,5 % khi l ng

V H2 = 4,90 - 0,2 K UOP = 4,90 - 0,2 12,06 = 2,488 % khi l ng

2.4 Qu trnh kh l u hunh (hydrodsulfuration - HDS) iu kin vn hnh ca cc thit b kh lu hunh v i cc loi nguyn liu khc

nhau :

Khong phn Hm l ng lu iu kin vn hnh Nguyn liu on, oC hunh ppH2, bars VVH, h-1 Nhit ,

oC

XngKrosneGO nh GO nngGO chn khngRARSV

70 - 170160 - 240240 - 350300 - 390350 - 550350+

550+

0,5 - 1 ppm50 - 100 ppm0,05 - 0,2 %0,1 - 0,3 %0,1 - 0,3 %0,5 - 1 %0,2 - 0,5 %

5 - 88 - 1210 - 2015 - 2530 - 4090 - 11060 - 70

5 - 84 - 63 - 62 - 41,5 - 30,3 - 10,5 - 1,5

330 - 370330 - 370340 - 390350 - 400360 - 400370 - 400370 - 400

Xcnh l ng H2

tiu th : bao gm :1- H2 dng kh l u hunh :


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- Da vo biu 1 ca qu trnh HDS, c khi l ng thtch ca nguynliu, ta tra c l ng H2 dng kh lu hunh (m3 H2 tiu chun / m3 nguyn liu /%lu hunh b kh).

- Ty thuc vo loi nguyn liu, ta c gi tr ca VVH t ngng ph h p

theo bng sliu thc nghim sau:

Nguyn liu Khong nhit si (0C) VVH (h-1) Naphta 70 180 4 10Kerosene 160 240 2 4Gasoil 230 350 1 3VGO 350 550 1 2.5

RA 350+ 0.3 0.5RSV 550+ 0.15 0.3

- t , da vo biu 3 ca qu trnh HDS, ta xcnh c hiu sutkhlu hunh.

- T hiu sut kh lu hunh, ta xcnh c hm l ng lu hunh casn phm, t tnh c % lu hunh b khv suy ra l ng H2 cn thitcho qu trnh (m3 H2 tiu chun / m3 nguyn liu ).

2- H2 lm no vng th m :Bit nhit si cui PF ca nguyn liu, da vo biu 2 ca qu trnhHDS, ta tra c l ng H2 lm no vng th m (m3 H2 tiu chun / m3 nguyn liu ).

L ng H2 tiu th= L ng H2 dngkh lu hunh + L ng H2 lm novng th m.

V d : Tnh qu trnh HDS cho gasoil : Chn VVH = 2, da vo biu 3 ca qu trnh HDS % HDS = 96,4 %Hm l ng lu hunh banu trong Gasoil l : 1,39 % Hm l ng lu hunh cn li trong Gasoil sn phm l :

1.39 - 1.39 x 96,4 % = 0,05 % Hm l ng lu hunh b khl : 1.39 - 0,05 = 1.34 % T tr ng ca gasoil l : 0,854

Da vo biu 1 ca qu trnh HDS l ng H2 tiu th kh 1% luhunh l 13,8 m3 H2 tiu chun / m3 gasoil /%lu hunh b kh.

L ng H2 tiu th kh lu hunh l : 13,8 x 1,34 = 18,5 sm3 H2 / m3 gasoil.


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Nhit si cui ca gasoil l 370oC, da vo biu 2 ca qu trnhHDS :

L ng H2 lm no vng th m 9 sm3 H2 / m3 gasoil. Vy tng l ng H2 tiu thcho qu trnh khlu hunh cho Gasoil l :

18,5 + 9 = 27,5 sm3 H2 / m3 gasoil1 sm3 l 1m3 iu kin tiu chun : P = 1 atm

t = 15oC.Sau , ta suy ra tng khi l ng H2 tiu th cho 1 Tn nguyn liu (T H2 / Tnguyn liu)

27,5 x 2 : (22,4 x 0,854) = 2,875 .10-3 T/T GassoilHay khi l ng H2 tiu th/ nm l : 2,875 .10-3 x 1816,87 = 5,22 T / n

2.5 Phi liu cc sn phm Mt sn phm xng du trn th tr ng th ng l hn h p ca nhiu sn phm

ca qu trnh lc du nhm png c cc yu cu k thut c ra. V d: Theo nhu cu ca th tr ng, ng i tai hi 4 loi xng :

Xng super khng ch 98/88 : 300.103T/nXng super khng ch 95/85 : 210.103T/n

Xng super c ch 98/88 : 1350.103T/nXng t : 165.103T/n

pha chXng super khng ch 98/88, ta phi dng loi xng c RON caonht v hm l ng lu hunh th p nht, c thdng xng Reformat C5+ ca qutrnh Reforming xc tc, nhng xng ny cng ch t c RONCL = 97,5. Vvy, chng ta phi pha chthm MTBE (MthylTertioButylEther)

MTBE c RON = 117 v % S = 0. Nhvy, chng ta sphi liu 2 cu t l Reformat C5+ v MTBE nh th

no hn h p sn phm tha mn c tt ccc yu cu k thut cn thitnh: t tr ng, hm l ng lu hunh, RON, TVV.pha chXng super khng ch 95/85, ta c thphi liu Reformat C5+ v ixng ca qu trnh FCC. Nu cc yu cu k thut cn thit nh: hm l ng luhunh v RON khngt, ta c th pha thm mt t MTBE.

Ch : Khi phi liu, cc ch tiu k thut ca hn h p pha ch c c tnhton theo thnh phn khi l ng hoc thtch hoc phn mol th ty thuc votng ch tiu.

V d :T tr ng ca hn h p sn phm c tnh theo thnh phn % thtch ca cccu tthnh phn.


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Hm l ng lu hunh ca hn h p sn phm c tnh theo thnh phn % khil ng ca cc cu tthnh phn.RON ca hn h p sn phm c tnh theo thnh phn % thtch ca cc cutthnh phn.

PM ca hn h p sn phm c tnh theo thnh phn % khi l ng ca cc cutthnh phn.TVR ca hn h p sn phm c tnh theo thnh phn % mol ca cc cu t thnh phn.

L u : xc nh im ch p chy cng nh im chy ca hn h p, ta pdng ph ng php hn h p theo khi l ng nhng qua mt i l ng trunggian l ch s im ch p chy hoc ch s im chy I c tra theo biu Point dclair des mlange - Loi de mlange v biu Pointdcoulement des mlange - Loi de mlange .

c bit, nh t ca hn h p sn phm c th c tnh theo :- Thnh phn % khi l ng ca cc cu tthnh phn :

PM.IM = Pi.IiV i IM, Ii : ch s nh t ca hn h p v ca cu ti ;

PM,Pi : khi l ng ca hn h p v ca cu ti.Da vo nh t ca cu t i, tra bng Viscosit des mlange - Loi de

mlange massique, ta tra ra c gi tr ca ch s nh t Ii ca tng cu t i.

Sau , da vo cng thc trn, ta tnh c ch s nh t IM ca hn h p. Cuicng, tIM m i tm c, ta li tra bng Viscosit des mlange - Loi de mlangemassique, ta tra ra c gi tr ca nh t ca hn h p sn phm.

- Thnh phn % thtch ca cc cu t thnh phn.VM.IM = Vi.Ii

V i IM, Ii : ch s nh t ca hn h p v ca cu ti ;VM,Vi : thtch ca hn h p v ca cu ti.

Da vo nh t ca cu t i, tra bng Viscosit des mlange - Loi demlange volumique, ta tra ra c gi tr ca ch s nh t Ii ca tng cu t i.Sau , da vo cng thc trn, ta tnh c ch s nh t IM ca hn h p. Cuicng, tIM m i tm c, ta li tra bng Viscosit des mlange - Loi de mlangevolumique, ta tra ra c gi tr ca nh t ca hn h p sn phm.


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3 CN BNG NNG L NG CA NH MY

Trong nh my Lc du, thng th ng ng i ta tnh ton sao cho sau khipng cc yu cu vsn phm cho th tr ng, phn sn phm c gi tr kinh t th p cn li c dng lm nhin liu cho cc phn x ng trong nh my.

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Cc sn phm c em lm nhin liu tiu thni b th ng l cc phnon C1, C2, H2 tha sau khi cung c p cho cc phn x ng kh lu hunh, RA,RSV.

Tr c ht, ng i ta tnh ton nng l ng cn thit cung c p cho cc phn

x ng trong nh my da vo l ng tiu tn nhin liu tiu chun trn 1 Tnnguyn liu i v i tng phn x ng. L ng nhin liu tiu tn bao gm nhin liucung c p cho cc l gia nhit ca cc phn x ng v nhin liu tiu tn cung c ph i n c vin.

3.1 Nng l ng cn thit cung cp cho cc phn x ng Nng l ng cn thit cung c p cho cc phn x ng (tn nhin liu

chun/KT nguyn liu) v i ngun du th l Arabe nh:- Phn x ng DA : 19

- Phn x ng DSV : 18- Phn x ng RC: k cx l nguyn liu, l ng nhin liu tiu tn ph

thuc vo RON ca xng Reformat sn phm:

RON 90 92 94 95 96 97 98Tn nhin liu/KT

nguyn liu 50 52 55 57.5 60 63.5 67

- Phn x ng FCC : 2- Phn x ng VBR : 23- Phn x ng HDS : 18

3.2 L ng nhin liu tiu thni b Bng quii cc loi nhin liu tha ra nhin liu tiu chun

Cc phnon nh - H2- C2- C3

- C4

2.751.221.18

1.16

Cc phnon sn phm ca phn x ng DA

- GAS- BNZ- KER - GOL- GOH- RDA

1.111.111.101.071.051.00

Phn x ng DSV - DSV

- RSV1.001.00

Phn x ng FCC - LCO

- HCO

1.00

1.00VBR RVB 0.85


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T , ta tnh ton xem l ng nhin liu tha ny sau khi quii ra theonhin liu tiu chun c png cho vic tiu thni b trong nh my khng,nu hoc tha mt t ( 10 %) l c.

(Nhin liu tiu chun c PCI = 10.000 kcal/kg)

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