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Solving Equations A Stand-ALONE INSTRUCTIONAL RESOURCE

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Solving Equations A Stand-ALONE INSTRUCTIONAL RESOURCE. Click the ‘NEXT’ button to continue. NEXT. introduction. - PowerPoint PPT Presentation

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Page 1: Solving Equations  A Stand-ALONE INSTRUCTIONAL RESOURCE

NEXT

Click the ‘NEXT’ button to continue

Page 2: Solving Equations  A Stand-ALONE INSTRUCTIONAL RESOURCE

Today, in Ms. Stechschulte’s 7th grade class, we will be learning how to solve one-step equations. To navigate through this presentation, click on the arrows and buttons at the bottom of the screen. The arrow labeled ‘NEXT’, will take you to the next slide. The arrow labeled ‘BACK’, will take you back to the previous slide. When you get to the Main Menu, click on the first link to begin the lesson. If you need to go back to the previous lessons to clarify concepts, please do so.

Click the arrow below to continue.NEXT

Page 3: Solving Equations  A Stand-ALONE INSTRUCTIONAL RESOURCE

Your goal is to learn the concept of solving equations so you are successful answering the quiz questions. You must know the concepts well enough to solve two-step equations for tomorrow’s class. When you are finished with the first 2 Lessons, go to Lesson 3 and play the online math games for the remainder of the class period.

Good luck and have fun NEXTBACK

Page 4: Solving Equations  A Stand-ALONE INSTRUCTIONAL RESOURCE

“An equation is a written statement indicating the equality of two expressions”

It consists of a sequence of symbols that are split into left and right sides joined by an equal sign.

For example, 2 + 4 = 6 is an equation.

http://dictionary.reference.com/browse/equation

NEXT

Left side Right side

BACK

Page 5: Solving Equations  A Stand-ALONE INSTRUCTIONAL RESOURCE

* Remember *

2x + 3 = 5

NEXT

Coefficient: the number that is in front of the x. This means that 2 and x are multiplied.

Variable: the letter you are solving for; it needs to be isolated on one side of the equation. A variable can be any letter.

Left side Right side

BACK

Page 6: Solving Equations  A Stand-ALONE INSTRUCTIONAL RESOURCE

Lesson 1: Using adding & subtracting

Lesson 2: Using multiplication & division

Lesson 3: Online Math Games

Click on the link for Lesson 1 to begin.When finished with Lesson 1, continue with Lesson 2

then 3.

Page 7: Solving Equations  A Stand-ALONE INSTRUCTIONAL RESOURCE

Hoop Shoot

Equation Buster

Easy Algebra Equations

Say the ‘2 – steps’: Rags to Riches

BACK

Page 8: Solving Equations  A Stand-ALONE INSTRUCTIONAL RESOURCE

1x

=

111

x + 1 = 3To solve an equation you must get x

by itself on one side of the equal sign, while keeping the scale balanced

NEXTBACK

Page 9: Solving Equations  A Stand-ALONE INSTRUCTIONAL RESOURCE

=

x

1

111

NEXT

To get x by itself you have to take away (subtract) 1. However, this will cause the scale to become

unbalanced, so you also have to take away 1 from the other side of the equal sign.

BACK

Page 10: Solving Equations  A Stand-ALONE INSTRUCTIONAL RESOURCE

1

x

=

11

1

x + 1 = 3 -1 -1 x = 2

NEXT

After you subtract 1 from both sides of the equal sign, you are left with x = 2

BACK

Page 11: Solving Equations  A Stand-ALONE INSTRUCTIONAL RESOURCE

NEXT

“Two operations are said to be inverse to each other if one operation undoes the effect of the other operation.”

Addition and Subtraction are inverse operations

Multiplication and Division are inverse operations

http://www.icoachmath.com/Sitemap/InverseOperation.html BACK

Page 12: Solving Equations  A Stand-ALONE INSTRUCTIONAL RESOURCE

NEXT

Inverse operations must be used when solving equations.

In the previous example we SUBTRACTED to undo the ADDITION to get x by itself.

To solve x – 5 = 3,

what operation must you use to get x by itself?

BACK

Page 13: Solving Equations  A Stand-ALONE INSTRUCTIONAL RESOURCE

MORE EXAMPLES

If you said ADDITION you are correct! To undo SUBTRACTION you must ADD.

To solve

x – 5 = 3 +5 +5 x = 8

Add 5 to both sides to keep the equation balanced.

Begin Quiz

1BACK

Page 14: Solving Equations  A Stand-ALONE INSTRUCTIONAL RESOURCE

1x

=

111

x + 2 = 4To solve an equation get rid of whatever is with the

variable (x). What you do to one side, you must also do to the other side.

NEXT

11

Page 15: Solving Equations  A Stand-ALONE INSTRUCTIONAL RESOURCE

1

x

=

11

1

x + 2 = 4Subtract 2 from both sides to keep the scale

balanced

1 1

x = 2

To Quiz 1

NEXTBACK

Page 16: Solving Equations  A Stand-ALONE INSTRUCTIONAL RESOURCE

Since 2 is SUBTRACTED from x, you must ADD 2 to both sides to solve

x – 2 = 3 +2 +2 x = 5

Add 2 to both sides to keep the equation balanced.

To Quiz 1 NEXTBACK

Page 17: Solving Equations  A Stand-ALONE INSTRUCTIONAL RESOURCE

-1 = 7 + x is the same as saying 7 + x = -1 Since 7 is ADDED to x, you must SUBTRACT 7 from both sides to solve

-1 = 7 + x -7 -7

-8 = xx = -8

Subtract 7 from both sides to keep the equation balanced.

To Quiz 1BACK

Page 18: Solving Equations  A Stand-ALONE INSTRUCTIONAL RESOURCE

Question 1:

Solve x + 4 = 9

A. x = 13B. x = 5C. x = 9

Click on a letter to continue.

Page 19: Solving Equations  A Stand-ALONE INSTRUCTIONAL RESOURCE

Question 2:

Solve x – 5 = 2

A. x = -3B. x = 2C. x = 7

Click on a letter to continue.

Page 20: Solving Equations  A Stand-ALONE INSTRUCTIONAL RESOURCE

Question 3:

Solve – 5 = 4 + x

A. x = -9B. x = -1C. x = 9

Click on a letter to continue.

Page 21: Solving Equations  A Stand-ALONE INSTRUCTIONAL RESOURCE

Correct!!

Nice Work! NEXT

Page 22: Solving Equations  A Stand-ALONE INSTRUCTIONAL RESOURCE

Correct!!

Great Job! NEXT

Page 23: Solving Equations  A Stand-ALONE INSTRUCTIONAL RESOURCE

Correct!!

Fabulous! NEXT

Page 24: Solving Equations  A Stand-ALONE INSTRUCTIONAL RESOURCE

IncorrectTry Again

Let’s look at another example NEXT

Page 25: Solving Equations  A Stand-ALONE INSTRUCTIONAL RESOURCE

1x

=

111

x + 2 = 4To solve an equation get rid of whatever is with the

variable (x). What you do to one side, you must also do to the other side.

NEXT

11

Page 26: Solving Equations  A Stand-ALONE INSTRUCTIONAL RESOURCE

1

x

=

11

1

x + 2 = 4Subtract 2 from both sides to keep the scale

balanced

1 1

x = 2

To Quiz 1

BACK

Page 27: Solving Equations  A Stand-ALONE INSTRUCTIONAL RESOURCE

IncorrectTry Again

Let’s look at another example NEXT

Page 28: Solving Equations  A Stand-ALONE INSTRUCTIONAL RESOURCE

Since 2 is SUBTRACTED from x, you must ADD 2 to both sides to solve

x – 2 = 3 +2 +2 x = 5

Add 2 to both sides to keep the equation balanced.

To Quiz 1

Page 29: Solving Equations  A Stand-ALONE INSTRUCTIONAL RESOURCE

IncorrectTry Again

Let’s look at another example NEXT

Page 30: Solving Equations  A Stand-ALONE INSTRUCTIONAL RESOURCE

-1 = 7 + x is the same as saying 7 + x = -1 Since 7 is ADDED to x, you must SUBTRACT 7 from both sides to solve

-1 = 7 + x -7 -7

-8 = xx = -8

Subtract 7 from both sides to keep the equation balanced.

To Quiz 1

Page 31: Solving Equations  A Stand-ALONE INSTRUCTIONAL RESOURCE

What is the inverse operation of

MULTIPLICATION?

NEXTBACK

Page 32: Solving Equations  A Stand-ALONE INSTRUCTIONAL RESOURCE

The answer is…

DIVISION

NEXTBACK

Page 33: Solving Equations  A Stand-ALONE INSTRUCTIONAL RESOURCE

What is the inverse operation of DIVISION?

NEXTBACK

Page 34: Solving Equations  A Stand-ALONE INSTRUCTIONAL RESOURCE

The answer is…

MULTIPLICATION

NEXTBACK

Page 35: Solving Equations  A Stand-ALONE INSTRUCTIONAL RESOURCE

When you have an equation with

multiplication or division, you will do the

inverse operation to solve!

NEXTBACK

Page 36: Solving Equations  A Stand-ALONE INSTRUCTIONAL RESOURCE

Since 6 and x are multiplied, to solve, we divide by 6.

6x = 48 6x = 48

6 6x = 8

Divide by 6 on both sides to keep the equation balanced.

BACK NEXTReminder: When a number is divided by itself, it equals 1.

Page 37: Solving Equations  A Stand-ALONE INSTRUCTIONAL RESOURCE

Since x is divided by 4, to solve, we multiply by 4.

x = 5 4

(4)x = 5(4) 4

x = 20

Multiply by 4 on both sides to keep the equation balanced.

To Quiz 2BACK

MORE EXAMPLES

Page 38: Solving Equations  A Stand-ALONE INSTRUCTIONAL RESOURCE

The inverse operation of MULTIPLICATION is DIVISION, so we

divide by 10.

10x = 30 10x = 30

10 10x = 3

Divide by 10 on both sides to keep the equation balanced.

NEXTTo

Quiz 2BACK

Page 39: Solving Equations  A Stand-ALONE INSTRUCTIONAL RESOURCE

The inverse operation of DIVISION is MULTIPLICATION, so we multiply by -5.

x = 3 -5

(-5)x = 3(-5) -5

x = -15

Multiply by -5 on both sides to keep the equation balanced.

NEXT

To Quiz 2

** Remember: Negative times a positive = negative

BACK

Page 40: Solving Equations  A Stand-ALONE INSTRUCTIONAL RESOURCE

The inverse operation of MULTIPLICATION is DIVISION, so we

divide by -2.

-2x = -10 -2x = -10

-2 -2x = 5

Divide by -2 on both sides to keep the equation balanced.

To Quiz 2

** Remember: Negative times a negative = positive

BACK

Page 41: Solving Equations  A Stand-ALONE INSTRUCTIONAL RESOURCE

Question 1:

Solve 5x = 35

A. x = 175B. x = 30C. x = 7

Click on a letter to continue.

Page 42: Solving Equations  A Stand-ALONE INSTRUCTIONAL RESOURCE

IncorrectTry Again

Let’s look at another example NEXT

Page 43: Solving Equations  A Stand-ALONE INSTRUCTIONAL RESOURCE

Correct!!

Super! NEXT

Page 44: Solving Equations  A Stand-ALONE INSTRUCTIONAL RESOURCE

Question 2:

Solve x = 4

-2A. x = -8B. x = 6C. x = -2

Click on a letter to continue.

Page 45: Solving Equations  A Stand-ALONE INSTRUCTIONAL RESOURCE

IncorrectTry Again

Let’s look at another example NEXT

Page 46: Solving Equations  A Stand-ALONE INSTRUCTIONAL RESOURCE

Correct!!

Fantastic! NEXT

Page 47: Solving Equations  A Stand-ALONE INSTRUCTIONAL RESOURCE

Question 3:

Solve -3x = 6

A. x = 2B. x = -2C. x = -18

Click on a letter to continue.

Page 48: Solving Equations  A Stand-ALONE INSTRUCTIONAL RESOURCE

IncorrectTry Again

Let’s look at another example NEXT

Page 49: Solving Equations  A Stand-ALONE INSTRUCTIONAL RESOURCE

Correct!!

Great Job! NEXT

Page 50: Solving Equations  A Stand-ALONE INSTRUCTIONAL RESOURCE

The inverse operation of MULTIPLICATION is DIVISION, so we

divide by 10.

10x = 30 10x = 30

10 10x = 3

Divide by 10 on both sides to keep the equation balanced.

To Quiz 2

Page 51: Solving Equations  A Stand-ALONE INSTRUCTIONAL RESOURCE

The inverse operation of DIVISION is MULTIPLICATION, so we multiply by -5.

x = 3 -5

(-5)x = 3(-5) -5

x = -15

Multiply by -5 on both sides to keep the equation balanced.

To Quiz 2

** Remember: Negative times a positive = negative

Page 52: Solving Equations  A Stand-ALONE INSTRUCTIONAL RESOURCE

The inverse operation of MULTIPLICATION is DIVISION, so we

divide by -2.

-2x = -10 -2x = -10

-2 -2x = 5

Divide by -2 on both sides to keep the equation balanced.

To Quiz 2

** Remember: Negative times a negative = positive