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Solving Equations A Stand-ALONE INSTRUCTIONAL RESOURCE. Click the ‘NEXT’ button to continue. NEXT. introduction. - PowerPoint PPT Presentation
Citation preview
NEXT
Click the ‘NEXT’ button to continue
Today, in Ms. Stechschulte’s 7th grade class, we will be learning how to solve one-step equations. To navigate through this presentation, click on the arrows and buttons at the bottom of the screen. The arrow labeled ‘NEXT’, will take you to the next slide. The arrow labeled ‘BACK’, will take you back to the previous slide. When you get to the Main Menu, click on the first link to begin the lesson. If you need to go back to the previous lessons to clarify concepts, please do so.
Click the arrow below to continue.NEXT
Your goal is to learn the concept of solving equations so you are successful answering the quiz questions. You must know the concepts well enough to solve two-step equations for tomorrow’s class. When you are finished with the first 2 Lessons, go to Lesson 3 and play the online math games for the remainder of the class period.
Good luck and have fun NEXTBACK
“An equation is a written statement indicating the equality of two expressions”
It consists of a sequence of symbols that are split into left and right sides joined by an equal sign.
For example, 2 + 4 = 6 is an equation.
http://dictionary.reference.com/browse/equation
NEXT
Left side Right side
BACK
* Remember *
2x + 3 = 5
NEXT
Coefficient: the number that is in front of the x. This means that 2 and x are multiplied.
Variable: the letter you are solving for; it needs to be isolated on one side of the equation. A variable can be any letter.
Left side Right side
BACK
Lesson 1: Using adding & subtracting
Lesson 2: Using multiplication & division
Lesson 3: Online Math Games
Click on the link for Lesson 1 to begin.When finished with Lesson 1, continue with Lesson 2
then 3.
Hoop Shoot
Equation Buster
Easy Algebra Equations
Say the ‘2 – steps’: Rags to Riches
BACK
1x
=
111
x + 1 = 3To solve an equation you must get x
by itself on one side of the equal sign, while keeping the scale balanced
NEXTBACK
=
x
1
111
NEXT
To get x by itself you have to take away (subtract) 1. However, this will cause the scale to become
unbalanced, so you also have to take away 1 from the other side of the equal sign.
BACK
1
x
=
11
1
x + 1 = 3 -1 -1 x = 2
NEXT
After you subtract 1 from both sides of the equal sign, you are left with x = 2
BACK
NEXT
“Two operations are said to be inverse to each other if one operation undoes the effect of the other operation.”
Addition and Subtraction are inverse operations
Multiplication and Division are inverse operations
http://www.icoachmath.com/Sitemap/InverseOperation.html BACK
NEXT
Inverse operations must be used when solving equations.
In the previous example we SUBTRACTED to undo the ADDITION to get x by itself.
To solve x – 5 = 3,
what operation must you use to get x by itself?
BACK
MORE EXAMPLES
If you said ADDITION you are correct! To undo SUBTRACTION you must ADD.
To solve
x – 5 = 3 +5 +5 x = 8
Add 5 to both sides to keep the equation balanced.
Begin Quiz
1BACK
1x
=
111
x + 2 = 4To solve an equation get rid of whatever is with the
variable (x). What you do to one side, you must also do to the other side.
NEXT
11
1
x
=
11
1
x + 2 = 4Subtract 2 from both sides to keep the scale
balanced
1 1
x = 2
To Quiz 1
NEXTBACK
Since 2 is SUBTRACTED from x, you must ADD 2 to both sides to solve
x – 2 = 3 +2 +2 x = 5
Add 2 to both sides to keep the equation balanced.
To Quiz 1 NEXTBACK
-1 = 7 + x is the same as saying 7 + x = -1 Since 7 is ADDED to x, you must SUBTRACT 7 from both sides to solve
-1 = 7 + x -7 -7
-8 = xx = -8
Subtract 7 from both sides to keep the equation balanced.
To Quiz 1BACK
Question 1:
Solve x + 4 = 9
A. x = 13B. x = 5C. x = 9
Click on a letter to continue.
Question 2:
Solve x – 5 = 2
A. x = -3B. x = 2C. x = 7
Click on a letter to continue.
Question 3:
Solve – 5 = 4 + x
A. x = -9B. x = -1C. x = 9
Click on a letter to continue.
Correct!!
Nice Work! NEXT
Correct!!
Great Job! NEXT
Correct!!
Fabulous! NEXT
IncorrectTry Again
Let’s look at another example NEXT
1x
=
111
x + 2 = 4To solve an equation get rid of whatever is with the
variable (x). What you do to one side, you must also do to the other side.
NEXT
11
1
x
=
11
1
x + 2 = 4Subtract 2 from both sides to keep the scale
balanced
1 1
x = 2
To Quiz 1
BACK
IncorrectTry Again
Let’s look at another example NEXT
Since 2 is SUBTRACTED from x, you must ADD 2 to both sides to solve
x – 2 = 3 +2 +2 x = 5
Add 2 to both sides to keep the equation balanced.
To Quiz 1
IncorrectTry Again
Let’s look at another example NEXT
-1 = 7 + x is the same as saying 7 + x = -1 Since 7 is ADDED to x, you must SUBTRACT 7 from both sides to solve
-1 = 7 + x -7 -7
-8 = xx = -8
Subtract 7 from both sides to keep the equation balanced.
To Quiz 1
What is the inverse operation of
MULTIPLICATION?
NEXTBACK
The answer is…
DIVISION
NEXTBACK
What is the inverse operation of DIVISION?
NEXTBACK
The answer is…
MULTIPLICATION
NEXTBACK
When you have an equation with
multiplication or division, you will do the
inverse operation to solve!
NEXTBACK
Since 6 and x are multiplied, to solve, we divide by 6.
6x = 48 6x = 48
6 6x = 8
Divide by 6 on both sides to keep the equation balanced.
BACK NEXTReminder: When a number is divided by itself, it equals 1.
Since x is divided by 4, to solve, we multiply by 4.
x = 5 4
(4)x = 5(4) 4
x = 20
Multiply by 4 on both sides to keep the equation balanced.
To Quiz 2BACK
MORE EXAMPLES
The inverse operation of MULTIPLICATION is DIVISION, so we
divide by 10.
10x = 30 10x = 30
10 10x = 3
Divide by 10 on both sides to keep the equation balanced.
NEXTTo
Quiz 2BACK
The inverse operation of DIVISION is MULTIPLICATION, so we multiply by -5.
x = 3 -5
(-5)x = 3(-5) -5
x = -15
Multiply by -5 on both sides to keep the equation balanced.
NEXT
To Quiz 2
** Remember: Negative times a positive = negative
BACK
The inverse operation of MULTIPLICATION is DIVISION, so we
divide by -2.
-2x = -10 -2x = -10
-2 -2x = 5
Divide by -2 on both sides to keep the equation balanced.
To Quiz 2
** Remember: Negative times a negative = positive
BACK
Question 1:
Solve 5x = 35
A. x = 175B. x = 30C. x = 7
Click on a letter to continue.
IncorrectTry Again
Let’s look at another example NEXT
Correct!!
Super! NEXT
Question 2:
Solve x = 4
-2A. x = -8B. x = 6C. x = -2
Click on a letter to continue.
IncorrectTry Again
Let’s look at another example NEXT
Correct!!
Fantastic! NEXT
Question 3:
Solve -3x = 6
A. x = 2B. x = -2C. x = -18
Click on a letter to continue.
IncorrectTry Again
Let’s look at another example NEXT
Correct!!
Great Job! NEXT
The inverse operation of MULTIPLICATION is DIVISION, so we
divide by 10.
10x = 30 10x = 30
10 10x = 3
Divide by 10 on both sides to keep the equation balanced.
To Quiz 2
The inverse operation of DIVISION is MULTIPLICATION, so we multiply by -5.
x = 3 -5
(-5)x = 3(-5) -5
x = -15
Multiply by -5 on both sides to keep the equation balanced.
To Quiz 2
** Remember: Negative times a positive = negative
The inverse operation of MULTIPLICATION is DIVISION, so we
divide by -2.
-2x = -10 -2x = -10
-2 -2x = 5
Divide by -2 on both sides to keep the equation balanced.
To Quiz 2
** Remember: Negative times a negative = positive