Secretary of energy 1997 Nobel Prize Winner Dr Steven Chu crimes

8/8/2019 Secretary of energy 1997 Nobel Prize Winner Dr Steven Chu crimes

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Arabs real time AstronomyThe 30 solutions of Mercury’s Perihelion

(I/O) θ’0 = θ’0 + [(I – O)/O] θ’0Real time physics = event time physics + time delay physics

Quantum = classical + relativistic joenahhas1 [email protected]

I am Joe Nahhas greatest and only physicist alive since 1258 AD telling criminals doingidiotic acts like the two on my left Buzz off: Time travel based “modern Physics” is notphysics but Einstein’s and Western “University” academia garbage imposed in classrooms

and used wrong in scientific calculations to send 500,000 “physicists” to go work atMacdonald’s without loss of subject. My name is Professor Joe Nahhas founder of Arabs retime physics July 4th 1973. There is one and only one physics Arabs real time physics.

Einstein is not only an idiot but this is the proof of Einstein’s and westerncivilization physics stupidity. This is me in October 2009 flashing my 1979 picturestapled to my thermo book congratulating myself and buzzing off 500 years of “western” stupidity of physics and buzzing off physicists and re - introducing real timphysics that Arabs in 10th century started with 1001 new Arabs real time physicsformulas to change physics and history

Page 1

mailto:[email protected]




Confronting criminals in Alfred Nobel suit is my promise

etings: My name is Joe Nahhas and I was expelled from University of Michigan in 1991 and PHD wiped for exposicriminals in Alfred Nobel suit Headquartered in USA department of energy

Frederick Reines 1953 US physicists of US DOE and Einstein’s dumbest thought E = mc2

Modern physics which is based on space – to time - back to space travel fiction is not physbut Einstein’s and Alfred Nobel criminals’ stupidity imposed in classrooms and used in scien

calculation terrorizing students with University “Professors’” stupidity



I Joe Nahhas accuse Nobel Prize winner Dr Stephen Chu of the crime of fraudincluding scientific fraud money laundering in the amounts of billions of dollarsalong with other Nobel Prize winners. Dr Stephen Chu is shelling billions inresearch money when he knows it is all fraud. Crime started with Lorentz andEinstein and the Alfred Nobel Prize Institution and USA department of energy is

where the crimes happened and keep happening. In 1953 Frederick Reinesrigged physics while he was working at USA department of energy to create thedark energy multi billion dollars scam and the dark energy scam have/hadreached an unprecedented levels that criminals has to be confronted and DrStephen Chu is a criminal in Alfred Nobel suit and it is the subject of this article

Western physicists after the 1932 two chemists discovery that the heavy metal of Uraniumcan split releasing heat they raced for a way to speed up the splitting process to make aheat bomb we call nuclear bomb. At this stage western physicists realized that they cantell the USA congress and get all the money they want and they used visual effects toclaim new discovery fooling and blackmailing Congress the American people andhumanity and the time has come to expose them and who can expose them? I can!

There is no dark energy because it is based on modern physics and modernphysics is made up physics and can be deleted in its entirety without loss of subject. I am that good and can show how modern physics is Garbage

Dark energy Neutrino crime:

Frederick Reines Neutrino crime

The Nobel Prize in Physics 1995 was awarded "for pioneering experimental contributions to lepton physics" jointly with one half to Martin L. Perl "for the discovery of the tau lepton" and with one half to

Frederick Reines "for the detection of the neutrino" . Frederick Reines and many others usedvisual effects to claim discovery when there is no discovery and he did it whileworking for America’s most wanted crime hub called US department of energy

Einstein is fraud and E = mc2/2 and not E = mc2 Terrorist Einstein talk aboutis dark energy visual Illusion after 106 years till can never be found



I can show you using 5th grade math that he is fraud by showing that 5th grade mcan solve the same problems Einstein solved and the problems Einstein cannotsolve. I can show you how USA department of energy used visual effect to verifEinstein’s theory when his theory and the experimental proofs are nothing butfraud and a crime

Modern Physics is Garbage: I can use 5th grade math to beat Alfred Nobelphysics and physicistsA = A; add and subtract B to getA = B + (A – B); divide by B to getA/B = 1 + (A – B)/B; multiply by C to get(A/B) C = C + [(A – B)/B] CIf a Car has a velocity C at a distance A and the Car is moving away; then, the

car velocity would be measured as (A/B) C at a distance B and thedifference between the two velocities measurements at A and B is (A/B) C– C = [(A – B)/B] C

C = classical physics = event time measurement of C(A/B) C = real time measurements of C = quantum mechanics[(A – B)/B] C = time delay Illusion = relativisticOr Quantum = Classical + relativisticMeaning when light was discovered and used as measuring tool physicists

started seeing Illusions confused for real thing and called it modernphysics. Real time illusions only use was speeding up the information agecalled modern technology. Everything scientist said that it exist they haveno proof because it is an Illusion(A/B) C = C + [(A – B)/B] C

This equation ends 500 years of modern physicsUniversity of Michigan time travel bus drivers and criminals like these idiots

who believe in dark energy when dark energy is all made up fraud

Chairs of Nuclear Engineering Department past 30 years

James J. Duderstadt Glenn Knoll Bill Martin Ron Gilgenbach



1997 Nobel Prize winner Dr Steven Chu is a Criminal in the white house

Steven Chu Crimes against humanity explained

The mathematical proof of DR Steven Chu crimes

Time is not a structure like space to allow Dr Chu space –time recycled stupidity and for the secretary tore-repeat the space-time stupidity is nothing less than a criminal act because Dr Chu and the entirePhysicists community have nothing to prove that space-time existed and have millions of proof that space

– time never existed. And this article is for public to call Dr Chu: Dr Chu you Einstein andthe majority of Alfred Nobel Physicists are nothing but criminals

Here are 30 proofs that DR Chu is a Liar like most Nobel Prizewinners in Physics

The following is Nature’s published paper by Dr Chu

A precision measurement of the gravitational redshift by the interference of matter waves

Holger Müller 1,2, Achim Peters3 & Steven Chu1,2,4

1. Department of Physics, 366 Le Conte Hall MS 7300, University of California, Berkeley,

California 94720, USA2. Lawrence Berkeley National Laboratory, One Cyclotron Road, Berkeley, California 94720, USA3. Institut für Physik, Humboldt-Universität zu Berlin, Hausvogteiplatz 5-7, 10117 Berlin, Germany4. US Department of Energy, 1000 Independence Avenue SW, Washington, District of Columbia

20585, USA

Correspondence to: Holger Müller 1,2 Correspondence and requests for materials should be addressed toH.M. (Email: [email protected]).

Top of page

http://www.nature.com/nature/journal/v463/n7283/full/nature08776.html#a1















http://www.nature.com/nature/journal/v463/n7283/full/nature08776.html#top










http://www.nature.com/nature/journal/v463/n7283/full/nature08776.html#top



Abstract

One of the central predictions of metric theories of gravity, such as general relativity, is that a clock in agravitational potential U will run more slowly by a factor of 1 + U /c2, where c is the velocity of light, as

compared to a similar clock outside the potential

1

. This effect, known as gravitational redshift, isimportant to the operation of the global positioning system2, timekeeping3, 4 and future experiments withultra-precise, space-based clocks5 (such as searches for variations in fundamental constants). Thegravitational redshift has been measured using clocks on a tower 6, an aircraft7 and a rocket8, currentlyreaching an accuracy of 7 × 10-5. Here we show that laboratory experiments based on quantuminterference of atoms9, 10 enable a much more precise measurement, yielding an accuracy of 7 × 10-9.

Our result supports the view that gravityis a manifestation of space-time

curvature, an underlying principle of general relativity that has come underscrutiny in connection with the search fora theory of quantum gravity11. Improving the redshiftmeasurement is particularly important because this test has been the least accurate among theexperiments that are required to support curved space-time theories1.

Here is the proof: Space – time is a purely western stupidity used by Nobel prize winners to loot money

and it is time to delete it. Einstein and Dr Chu claims can be deleted by 5th grade math and if you thereader is an idiot in math it is time to learn some 5th grade math and delete a Nobel Prize and a secretaryof energy. Dr Chu crime is that he knows that most Nobel Prize winners are usingvisual effects to claim science supported by big institutions that needs massivefunding associated with political powers that installed him as secretary to pay backmoney to these people who made him a criminal because a Nobel prize winner incapitalist country like western countries means Einstein’s time travel that no onehave a clue what is it and Einstein’s gravity waves that never been detected anddark energy DR Chu shelling money for claims that a Nobel prize winner said youcan hook up a hose to the sky and funnel dark energy when Dr Chu hooked a hose

to funnel money out of the treasury. And Dr Chu knew for years that all his work isnothing but Garbage and That Stanford Cal – tech and Harvard MIT and all otherelite crime Institution. Dr Chu science is supporting criminals of big bang that neverhappened and black holes that never been seen and nuclear shells illusions andnuclear particles as needed for funding that has a life time of one part of billionbillion of one second that is dead before it is born as if the universe is dies and getrebirthed billion billion times a second and all other planet of the apes impressivenuclear and more impressive crimes.

To prove that Dr Chu is a criminal is to prove that there is no space – time butthese is criminals who use these visual effects that ancient Arabs astronomers and

http://www.nature.com/nature/journal/v463/n7283/full/nature08776.html#B1































All there is in the Universe is objects of mass m moving in space (x, y, z) at a location r= r (x, y, z). The state of any object in the Universe can be expressed as the productS = m r; State = mass x location:P = d S /d t = m (d r /d t) + (dm/d t) r = Total moment

= change of location + change of mass

= m v + m' r; v = velocity = d r/d t; m' = mass change rateF = d P /d t = d²S /dt² = Total force= m (d²r /dt²) +2(dm/d t) (d r /d t) + (d²m/dt²) r= m γ + 2m'v +m" r; γ = acceleration; m'' = mass acceleration rate

In polar coordinates system

r = r r (1) ;v = r' r(1) + r θ' θ(1) ; γ = (r" - rθ'²)r(1) + (2r'θ' + r θ")θ(1)

r = location; v = velocity; γ = accelerationF = m γ + 2m'v +m" rF = m [(r"-rθ'²) r (1) + (2r'θ' + r θ") θ (1)] + 2m'[r' r (1) + r θ' θ (1)] + (m" r) r(1)

= [d² (m r)/dt² - (m r) θ'²] r (1) + (1/mr) [d (m²r²θ')/d t] θ (1)

= 0 Light force lawProof :First r = r [cosine θ î + sine θ Ĵ] = r r (1)

Define r (1) = cosine θ î + sine θ ĴDefine v = d r /d t = r' r (1) + r d[r (1)]/d t = r' r (1) + r θ'[- sine θ î + cosine θĴ]

= r' r (1) + r θ' θ (1)

Define θ (1) = -sine θ î +cosine θ Ĵ;And with r (1) = cosine θ î + sine θ ĴThen d [θ (1)]/d t= θ' [- cosine θ î - sine θ Ĵ= - θ' r (1)And d [r (1)]/d t = θ' [-sine θ î + cosine θ Ĵ] = θ' θ (1)

Define γ = d [r' r (1) + r θ' θ (1)] /d t= r" r (1) + r'd [r (1)]/d t + r' θ' r (1) + r θ" r (1) +r θ'd [θ (1)]/d t

γ = (r" - rθ'²) r (1) + (2r'θ' + r θ") θ (1)

With d² (m r)/dt² - (m r) θ'² = F (r) And d (m²r²θ')/d t = 0If light mass m = constant, thenWith d² r/dt² - r θ'² = F (r) Eq-1 And d (r²θ')/d t = 0 Eq-2With d² r/dt² - r θ'² = 0 E q – 1And d (r²θ')/d t = 0 Eq-2From Eq-2: d (r²θ')/d t = 0Then r²θ' = h = constant

Differentiate with respect to time



Then 2rr'θ' + r²θ" = 0Divide by r²θ'Then 2(r'/r) + θ"/θ' = 0And 2(r'/r) = - θ"/θ' = 2[λ (r) + ỉ ω (r)]Also, r = r0 (θ, 0) e [λ (r) + ỉ ω (r)] t

And θ' = θ' 0 (θ, 0) e -2[λ (r) + ỉ ω (r)] t

For a fixed orbit: λ r = 0Also, r = r 0 (θ, 0) e ỉ ω t

And θ' = θ' 0 (θ, 0) e -2ỉ ω t

With d² r/dt² - r θ'² = 0Let u = 1/r; r = 1/u; r²θ' = h = θ’ /u²And d r/d t = (d r/ d u) (d u /d θ) (d θ/ d t) = (- 1/u ²) (θ’) (d u/ d θ)

= - h (d u/ d θ)And d² r/ d t² = - h (θ’) (d² u/ d θ ²)

= [- h²/r²] (d² u/ d θ ²)= - h² u² (d² u/ d θ ²)

With d² r/dt² - r θ'² = 0 E q – 1And - h² u² (d² u/ d θ ²) – (1/u) (h u²) ² = 0Then (d² u/ d θ ²) + u = 0Then u = A e - í θ Then r 0 (θ, 0) = (1/A) e í θ And r 0 (θ, 0) = r 0 (0, 0) e í θ And r = r 0 (0, 0) e í θ e ỉ ω t

Or, r = r 0 e í (θ + ω t)

This is real time particle motionLight is emitted and not an emitter and humans have no means of measuring lightin motion and at best they can take a snap shot.In mathematical languageThen r = r 0 e í θ at t = 0And r = r 0 e í (θ + ω t) Then ∆ r = r 0 e í θ [1 - e í ω t]

Or ∆ r = r [1 - eí ω t

] = ∆ r (x) + í ∆ r (y)∆ r (x) = r [1 – cosine ω t] = - 2r sine ² ω t/2∆ r (x) = - 2r sine ² ω t/2 Eq - 3

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Dark energy Neutrino crime:



Frederick Reines Neutrino crime

The Nobel Prize in Physics 1995 was awarded "for pioneering experimental contributions to lepton physics" jointly with one half to Martin L. Perl "for the discovery of the tau lepton" and with one half toFrederick Reines "for the detection of the neutrino" .

Anti-neutrino + proton ---------> neutron + positronPositron + electron --------------> Gamma + GammaGamma caught by a sensor and amplified to a signal 1 --> signal 1 on Oscilloscope1Neutron + Cadmium --> [Cadmium eats neutron] --> coughs GammaGamma caught by a sensor and amplified to a signal 2 --> signal 2 on Oscilloscope2

Reines and Cowan who claimed that if they install a tank of water closeto a nuclear reactor building and shield it from cosmic radiation thenthe Neutrino can be found from seeing two γ- gamma signals.The first signal γ- gamma signal is an indication of an Antineutrinocapture by a neutron and the second γ- gamma signal is an indicationof a neutron capture by cadmium and excited cadmium spits another γ-gamma signal

A Water Tank with 200 liters of water and 40 CdCl2 or a mixture of triethyl benzene

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* --------------------------------------------------------------------- * signal 1 captured 25 μ seconds later signal 2 captures



Signal 1 and two differ by a small size captured on oscilloscope screens

Water has a refractive index of 4/3 and try ethyl benzene has a refractive index of 1.44

There was a time window of 25 micro seconds shots were taken and when a # 1signal appeared in this 25 micro-seconds window the second window showed anothersignal appearing within 0- 5 microseconds

A signal moving inside a medium is expected to get delayed from 0-5 micro

seconds in a 0-25 micro second windowThe diffraction slows the motion inside a medium with refractive index n:

And r = r 0 e í (θ + ω t) With θ = 0

Then r = r 0 e í ω t Dividing by cThenT = T (0) e ỉ ω t

T = T (0) e ỉ ω t; ω t = arc tan (1/ n); n v = c; n = index of refraction; v = velocityof light in medium; c = light speed in vacuumT = T (0) [cosine ω t + ỉ sine ω t] = T (0) [1 - 2sine² (ω t/2) + ỉ sine ω t] = T (x)+ ỉ T (y)T (x) = T (0) [1 - 2sine² (ω t/2)] = T (0) {1 - 2sine² {[(arc tan (1/n)]/2}}Δ T = T (x) - T (0) = - 2 T (0) sine² {[arc tan (1 /n)]/2}Δ T = - 2 T (0) sine² {[arc tan (1 /n)]/2}

T (x) = T (0) cosine arc tan [1 /n)]T (x) = T (0) cosine arc tan [3/4] = 0.8 T (0)T (x) - T (0) = 0.2 T (0)Δ T = 0.2 T (0)The assumption that the free neutrino is detected at the Savannah River nuclearpower plant experiment in 1953 and published in nature 1956 by Reines andCowan and advertised by United Nations in 1958 is not only wrong but dead wrong.The claim of a second signal detection delayed 5 micro second after the pairannihilation indicating a neutron capture by Cadmium and proving the existence of the neutrino to support Wolfgang Pauli Neutrino theory and relativity theory is not justified. Here is why

Proof: The gate length is T (0) = 25 μ s (microseconds)The Container that had Cadmium is basically Tri ethyl benzene mixed with water.The refractive index of water at 25°C is 1.333 ~ 4/3 and the refractive index of triethyl benzene is 1.44 with 5 to 1 ratio water to tri ethyl benzene which is a minordistraction to water refractive index.

Δ T = - 2 x 25 sine² {[arc tan (~ 3/4)/2]} = 5 μ s time delaysΔ T = 0.2 T (0) = 0.2 x 25 = 5 μ s time delays



The coincidence of Pair annihilation gammas and Neutron capture gammas is not justified

If all the mixture was Tri ethyl benzene because the literature says it is a mixture

and it say it is tri ethyl benzeneΔ T = - 2 x 25 {[sine² arc tan (1/1.44)]/2} = 4.46575 μ s time delays

The delayed signal within the 5 μ s intervals is not a sign of Neutrino capture but aflash of light caught traveled and caught delayed. Meaning it is the same gammaand not two different gammas. What Reines and Cowan did is measuring the samesignal in a 25 micro second interval at the start they measured the signal and inthat 25 micro seconds interval the signal had 5 micro seconds signal time delaythat was measured as a second event. Reines and Cowan claimed two signals thefirst event was the signal of pair annihilation and the second event is the neutroncapture and releasing a second gamma ray when in fact looking at the same signal.This is the basis of all dark energy fraud

California institute of technology Ahmed Zewail Femto Chemistry historical mistake same repeated stupidity

Γ = t ℮ ỉ θ; θ = arc tan (v/c)

The Nobel Prize in Chemistry 1999"for his studies of the transition states of chemical reactions using femto second

spectroscopy"

Dr Ahmed Zewail

Nobel Lecture

Femtochemistry: Atomic-Scale Dynamics of the Chemical BondUsing Ultrafast Lasers

Or finding tIn his Nobel work Dr Zewail used Cyanogenic iodide with λ = 306 nanometer; 1

nanometer = 10- 9

and watched it fluoresces at λ = 388.9; t = 200 femto seconds;1 femto second = 10 - 15 secondHe shot a Laser beam to stir a solution that contained crystal of Cyanogenic iodideThen every 10 femto seconds he shot again to see what happens and after the lastshot he concluded the stir is dead and Cyanogenic iodide brokeICN ----------------> CN + I

The index of refraction of Cyanogenic iodide is n = 1.64 [US Army articles on thenet]



With λ = c T: T (1) = 306 x 10 - 9 /3 x 10 8 = 102 x 10 - 15

With λ = c T: T (2) = 388.9 x 10 - 9 /3 x 10 8 = 129.633 x 10 - 15

Δ Γ = T (1) - T (2) = - 27.6333 x 10 - 15

And Δ Γ = - 2 t sine ² arc tan (v/c)And Δ Γ = - 2 t sine ² arc tan (1/n)And -2 sine ² arc tan (v/c) = - 0.1455And t = Δ Γ / - 2 t sine ² arc tan (1/n) = - 27.6333 x 10 - 15 / - 0.1462 = 190 x 10 - 15

Or t = 190 x 10 - 15

The last shot is just a wasteDr Zewail number is 200 +/- 30 femotsecondsOther Nobel Prize winner used the same visual trick at Micro scaleThen Nano technology came and used the same trick at nano scaleAnd then Pico technology came and used it at pico scaleI am not saying Dr Ahmed Zewail is wrong what I am saying is Dr Zewail and allothers are wrong and Dr Zewail is another Nobel and no Nobility.

But that is not all Einstein used the same crime

Lord Eddington used the same crime

So did Copernicus Galileo, Tyco Brahe, Kepler, Newton, Hooke, Le Verrier, Laplace Von Soldner………….

The entire western civilization 500 years of physics

The entire western civilization 500,000 scientists used the same crime

All rights reserved

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Chapter one: What is Arabs real time astronomy?



Car size at distance 4




Observer line: …………………Observer ………………If we stand in the middle of the street and watch a car moving directly away from us we

see as if the size of the car shrunk. If we take a picture of the car at different distancesthen we see that the pictures of the car look like as if the car contracted in size. Thefurther the car away from us the smaller image of the car in the picture. The size of thecar did not change but real time light data reflected from the car and ran through airand into our eyes changes the real time image of the car to indicate a different locationof the car and not a different size of the car. Our eyes see real time images of a movingcar. If the car stops, then the image of the car freezes. A picture or a snap shot of amoving car is a frozen image of the moving car. When a car moves its real time imagechange size but the car does not change size. The car as a moving object at differentdistances has a variable real time image that our eyes see in real time and depends on

distance and motion as perceived by our eyes. In short statementsOur eyes see objects in real time as different objects at different distances and differentspeeds. Or, our eyes see real time objects we call images that change when measuredfrom different distances or when moving. Our eyes do not see actual objects butImages of actual objects and our eyes see different images of same actual objects whenat different distances of movingIn mathematical form:

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1 = 1 self evident

2 = 2 is self evidentImage = image = I is self evident line - 1



Object = object = O = self evident line - 2And, - Object = - objects = - O = self evident line - 3I = I line - 1O = O line - 2And, - O = - O line - 3

Adding: line - 1 and line - 2 and line - 3I + O – O = O + (I – O) line - 4I = O + (I – O); O – O = 0 one left side(I/O) = (O/O) + (I – O)/O; dividing by on both sides line - 5Or, (I/O) = 1 + (I – O)/O; O/O = 1 line - 6(I/O) O = O + [(I – O)/O] O Line - 7Real time object = event time Object + time delay objectReal time astronomy = event time astronomy + time delay astronomy



R 1 R 2 O2


D D D

R 1 O1 d

R 1 Car size at distance 1

Observer line: …………………Observer ………………The image of R 1 is R 2; or R 2 in real time is R 1

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Let us do R1 real time analysis

R2 = R2

R2 = R1 + (R2 – R1)



Dividing by R1

(R2 /R1) = (R1 /R1) + (R2 – R1)/ R1

Visual measurement scale(R2 /R1) = 1 + [(R2 – R1)/ R1]

Distance R1 when measured using light source and not a measuring tape is not the same

as R1 but is measured as R2. R2 is the visual distance of R1. Using an eye as an instrumentvisual distance R2 is smaller than actual distance R1. The percentage of visual distance R2 toactual distance R1 is equal to (R2 /R1).

(R2 /R1) = 1 + [(R2 – R1)/ R1] = 1 + [(R2 / R1) – 1]Percentage = 1 + [percentage – 1]

Multiplying by R1 (R2 /R1) R1 = R1 + [(R2 – R1)/ R1] R1

Visual = actual + (Visual – actual)In clear words when we try to measure the distance R1 using light source reflected from

the car we see a percentage of R1 which is (R2 /R1) R1 and that percentage times R1 is thevisual we measure R2

Real time distance = event time distance + delay time distanceVisual distance = distance + visual effect

Visual measurement scale using distanceReal time astronomy scale using distance

(R2 /R1) = 1 + [(R2 – R1)/ R1]Visual measurement scale using VelocityReal time astronomy scale using distance

(V2 /V1) = 1 + [(V2 – V1)/ V1]Visual measurement scale using angleReal time astronomy scale using angle

(θ 2 / θ 1) = 1 + [(θ 2 – θ 1)/ θ 1]Visual measurement scale using angular velocityReal time astronomy scale using angular velocity

(θ’ 2 / θ’ 1) = 1 + [(θ’ 2 – θ’ 1)/ θ’ 1]Visual measurement scale using timeReal time astronomy scale using time

(t 2 / t 1) = 1 + [(t 2 – t 1)/ t 1]

This formula is real time astronomical scale(V/A) = 1 + [(V – A)/ A]

(Visual/Actual) = 1 + [(Visual – Actual)/ Actual]

Page 4

Arabs real time astronomy application

(I/O) θ’0 = θ’0 + [(I – O)/O] θ’0



Real time physics = event time physics + time delay physics

In old termsQuantum = classical + relativistic

(R2 /R1) = 1 + [(R2 – R1)/ R1]

(R2 /R1) θ’0 = θ’0 + [(R2 – R1)/ R1] θ’0

This is Arabs real time astronomy distance scale to measure the angular velocity θ’0 (V2 /V1) = 1 + [(V2 – V1)/ V1]

(V2 /V1) θ’0 = θ’0 + [(V2 – V1)/ V1] θ’0

This is Arabs real time astronomy Velocity Scale to measure the angular velocity θ’0 Planet Mercury angular velocity accumulation in arc second per hundred years

Or, (V2 /V1) δ θ’0 = δ θ’0 + [(V2 – V1)/ V1] δ θ’0Planet Mercury Angular velocity θ’0 = 2 π/Tm = 2(3.1415)/88 x24x3600Tm = Planet Mercury orbital period = 88 days = 88 x 24 x 3600 seconds Planet Mercury angular velocity accumulation in arc second percentury is: δ θ’0 = (2 π/ Tm) (1 century/Tm) (180/ π) (3600)

Or, δ θ’0 = (2 π/ Tm) (1 century/Tm) (180/ π) (3600)= (2x3.1415/88x24x3600) (36526days/88days) (180/3.1415) (3600)= 70.75

(R2 /R1) θ’0 = θ’0 + [(R2 – R1)/ R1] θ’0(R2 /R1) δ θ’0 = δ θ’0 + [(R2 – R1)/ R1] δ θ’0

What we see = what there is + visual illusionModern astronomers see = 70.75 + 43

What there is = 70.75The visual Illusion is = 43

[(R2 – R1)/ R1] δ θ’0 = 43Page 5

As an example: when Astronomers look at planetary motion around the sun andthey saw the angular velocity in arc second per century:

Equal to δ θ’ m = (v m /r m) (180/ π) [36526/T m (days)] (3600)= 70.75 arc second per century



Astronomers also saw the visual effectOf: [(r m - r0)/r0] δ θ’ m = [(r m - r0)/r0] (v m /r m) (180/ π) [36526/T m (days)] (3600)And it is equal to [(r m - r0)/r0] δ θ’ m = 43Where r m = Mercury – Sun distance = 58.2 X 106kmAnd v m = Mercury around the sun orbital speed Sun distance = 47.9 km/sec

And r 0 = r e = Earth – Sun distance = 149.6 X 106kmAnd T m = Mercury around the sun orbital period

When astronomers measure the angular velocity from two different distancesthey make the following error: [(r m - r0)/r0] δ θ’ m = 43 When astronomers measure Planet mercury angular speed around the Sunfrom Earth r0 and not from the sun r m they make the following errorError: [(r m - r0)/r0] δ θ’ m = 43 Arabs real time astronomy is:

Real time astronomy = event time astronomy + time delay astronomyVisual = actual + IllusionsVisual = actual + (visual – actual)Quantum = classical + relativistic

Planet Distance rX 106km

PlanetOrbit T

Orbitspeed vinkm/sec

LessEarthspeed

Spinspeedkm/sec

Angular velocity;v/rarc sec/ century

Mercury 58.2 88 47.9 18.1 .002 70.75Venus 108.2 224.7 35.05 5.7 6.52 10.86Earth 149.6 365.26 29.8 .46511 4.1Mars 227.936 687 24.14 0.2411Jupiter 778.412 4333 13.06 12.6Saturn 1,426.725 10760 9.65 9.87Uranus 2,870.97 30690 6.80 2.59Neptune 4,498 60180 5.43 2.68Pluto 5906.4 90730 4.74



Real time classical = classical + relativistic illusionsQuantum mechanics and relativity theory is 20th century Garbage for physics.Measurements = actual + errorsActual + errors = actual + errors

Page 6

Chapter TwoThe confrontation between Arabs real time Astronomy andWestern Nobel prize winner modern space time astronomy

Arabs astronomers:

0M Mercury S Sun

That:

1- All object classified as planets Suns Moons has a real time circular motionAs: r = r 0 e í (θ + ω t) And not1 – Kepler - Newton’s ellipse r= [a (1 - ε²)/ (1 + ε cosine θ)] Or Einstein’s rotating ellipse: r= a (1 - ε²)/ [1 + ε cosine (θ - Ψ)] 2- The difference between two real time circular motions is a visual rotating ellipseOr, the difference between r1 = r 10 e í [θ (1) + ω (1) t] and r2 = r 20 e í [θ (2) + ω (2) t] Is Arabs real time ellipse: r= [a (1 - ε²)/ (1 + ε cosine θ)] e í [θ + ω t]

3 - Suns moons planets do not rotate around each otherThat is: r= [a (1 - ε²)/ (1 + ε cosine θ)] e í [θ + ω t]

Is a visual ellipse 4 – Gravity does not exist between planets moons and sunThat Newton’s F = - G m M/r² is wrongThat Einstein’s F = - G m M/r² + k/r4 is wrong5 – Gravity is due to atmosphere density and spin periodThat G = G [Ρ, T°] = G [atmospheric density, spin period]

In short: Arabs real time astronomy says



500 years ago Europeans took 10th century Arabs real time Astronomy and changed it to Space- timeastronomy and in the process physics was changed from an Arabic science to European – western stupidityglobalized through planet of the Apes Institution and best known as Alfred Nobel Prize winner Institution

Page 7

Alfred Nobel Prize winner physics theoryApe Man Modern Physicist Nobel Prize winner physicist Ape Ass.

Alfred Nobel: The Man behind the Nobel Prize; Joe Nahhas: The Man after Alfred Nobel Institution headSince 1901, the Nobel Prize has been honoring men and women from all corners of the globe for outstanding achievements in physics. The foundations for the prize were laid in 1895 when Alfred Nobelwrote his last will, leaving much of his wealth to the establishment of the Nobel Prize. But who wasAlfred Nobel? Meet Alfred Nobel - scientist, inventor, entrepreneur, author and pacifist. What is modern physics? Did anyone hear the big bang? Did anyone saw a black hole? Did anyone find Einstein’s gravitywaves? Did anyone hook up a hose to the sky and found dark energy to verify E = mc2? Does anyonehave a proof of Newton’s action at a distance? Does anyone have a proof of Einstein time travel? Does

anyone figure out why humans have to accept Alfred Nobel prize winners claim that the universe is madeup of particles that dies and rebirth billion billion times a second? Hey dude I am a redneck onegrandfather was a damn farmer and my other grandfather was a damn Carpenter and my father was aCarpenter by inheritance but I never knew what a dumb ass really is till I met my science teacher! Whatdid Alfred Nobel honor? The difference between an Alfred Nobel Prize winner physicists and fortunetellers is a flip of a coin. Space - Time is not physics but Alfred Nobel physicists’ flip of a coin between acrime and stupidity. Alfred Nobel Institution honored criminals in Alfred Nobel suit for all of pastcentury. Modern space – time physics changed physics from science to stupidity and physicists fromresearchers to criminals. In writing: Yes I am after Alfred Nobel Institution head on my plate and Iaccept nothing less. Space – time physics is stupidity itself. Ending Nobel Prize for stupidity fromclassrooms and scientific calculations is the only Nobel thing left to do. Alfred Nobel Prize became 1001

times more worth in cash value. Big Institutions backed wrong physics and physicists for all of pastcentury for a prize and a billion dollars jack pot and garbage for physics. I am Joe Nahhas and I am



unknown to the world of physics but I have 1001 new physics formulas to cut Alfred Nobel Institutionhead and delete Alfred Nobel Prize winner physics and physicists without loss of subject. This book is just the beginning and it is prime time and it is Arabs real time astronomy

Page 8

Chapter three: 10th century Arabs real time astronomyArab Physicists of Baghdad of 950 Ad had said:

I: Measurements are made along the line of sight or line of measurement

Arabs in 950 AD said that light going vertical (blue) to the eye it will go through the eye

be seen. The Arabs added that light coming oblique (pink) to the line of sight (blue line) would see the part of light (pink) that is equal to the amount of light of horizontal amoun(blue) or its vertical projection. What the Arabs concluded is that human eye and machinare unidirectional that can only recognize the amount of light along the line of sight or linof measurements. The Arabs mean that any point on the oblique pink line will be measuras its vertical projection as the blue line. The Arabs added that the horizontal projection the pink line is the amount that would be measured as Zero or not seen at all. A pointlocation on the pink line would be measured as equal to its vertical projection on the blueline and that part would be seen detected and measured by the eyes and instruments anits horizontal projection would not be detected or measured by the eyes or instruments a

would be completely missed.

r0 sine ω t

r0

ω t

r0 cosine ω t



The angle between the pink line and the blue line is called light aberration angle. Theaberration angle between the line where an object is (pink) and an object projection iswith the eye as center. Light aberrations angle equals to: ω t = arc tan (v/c) where v= relative velocity of the moving object and c is light velocity. The light coming from adistant object is seen along the line of sight and that meant we do not measure actual

distance of an object r0 (pink line) but we measure its image or vertical projectionwhich is r0 cosine ω t (blue line) and we escape measuring the horizontal projection

r0 sine ω t which is perpendicular to the line of sight (black line).Page 9

In Short, light coming from objects at distance r0 will be seen at r0 cosine ω tUsing real time mathematics to explain what we can see and/or detect or/andmeasure is what the Arabs have/had said and that would mean that if we try to

measure a distance r0 we would not find r0 but we would find: Arabs real time

distance is seen in real time along the line of sight.Or, r = r0 cosine ω t + í r0 cosine ω t = r0 e í ω (r) t Eq - 1

Or r = real (blue = along line of sight) + í imaginary (black = perpendicular to line of si

Or, r = r0 e í ω (r) t. The absolute value of r = the absolute value of r0

This statement said that light coming from objects when measured it is measured along linsight and that meant we see light projections of objects (blue line) of objects positioned at

positions r0 (pink). We do not see objects at r0 but see images of objects light projectio

and images of objects light projection along the line of sight is r0 cosine ω t and images o

object light projections perpendicular along the line of sight is r0 sine ω t (blue line).

The Arabs said that we do not see or measure light reflected from objects but wemeasure light speed projections as constant or light speed projections ismeasured as constant.

cc

c

The Arabs claim that we do not see objects position r0 but we see their visual position r.What humans see is r0 measured along the line of sight and miss r0 perpendicular to the

line of sight. In other words an object at a distance r0 humans are not aware that they donot see r0 but they see a visual of r0 which is r = r0 e í ω (r) t and projection of r0 along





physicists made/make this mistake and globalize their stupidity and to correctthis mistake is to delete western civilization physicists without loss of subject.There is nothing in “modern” physics that can be considered as correctbecause modern physics is based on wrong measurements. Modern physics is “wrong time physics” that can be deleted without loss of subject. Arabs real

time physics is the past present and future of all of physics and it is the subjectof this book.Page 11

Arabs real time astronomy: The Arabs Astronomers and Physicists said that:We can not see or/and detect or/and measure something in space that did notexist; we can not see or/and detect or/and measure something that had nothappened. We can only see or/and detect or/and measure things and events inspace that had happened. What we see or/and detect or/and measure is notnecessarily what there is and not necessarily what happened. We see or/and detector/and measure traces and images of objects of past event. We see or/and detector/and measure in present time of images of object and events that happened inpast time. That is we measure images and record data of objects of past events inpresent time. An event changes in time and when an event is measured it ismeasured after it happened.

Present time = present timePresent time = past time + (present time – past time)

Present time = past time + time difference

Present time = real time; past time = event time; (present time – past time) =time delay, or, Real time = event time + time delay

Real time Astronomy = Event time Astronomy + time delays Astronomy

In Modern Physics language the Arabs would have saidQuantum = classical + relativisticWhat there is = classical

What we see and measure and detect and partially record is = quantumWhat we see and measure and has no detection because it is an Illusion =relativisticTime dependent measurements = time independent measurements +(Time dependent measurements – time independent measurements)Measured = actual + (measured – actual)We do not see object in real time but we see images of objects in real timeIn common Terms: Image = object + (image – object)With Image = I; object = OI = O + (I – O)I/O = O/O + (I – O)/O

I/O = 1 + (I – O)/OArabs real time measurements equation:



Is: (I/O) q = q + [(I – O)/O] q; q measured quantity ------------- Eq – 1That is a quantity q when measured in real time it would appear as q + [(I – O)/O] q500 years of modern physics and 500,000 of modern physicists is all wrong because of principle (I/O) q = q + [(I – O)/O] ----------------------- Eq - 1Or quantum = classical + relativistic If Eq – 1 is applied it would expose modern physics as stupidity itself and it wouldexpose modern astronomy as astrology itself. The thing about this principle given byEq – 1: (I/O) q = q + [(I – O)/O] q is that it is flawless physics law or truth itself

Page 12

There are objects at location r0 (actual or classical distance) and when measured in

real time they appear as at a location r (quantum distance) = r 0 e í ω (r) t

That is the distance in the Universe is a classical distance but when a distance measured in

real time it appears as quantum distance and the difference between classical distance quantum distance is relativistic distance

Quantum (real time distance) = classical (event distance) + [Quantum – classical]Quantum distance = classical distance + relativistic distanceRelativistic distance = quantum distance – classical distance

We see detect and measure quantum distance r = r0 e í ω (r) t of an actual or

classical distance r0 and the difference between quantum distance r = r0 e í ω t

and actual or classical distance r0 is relativistic distanceTake r = r0 e í ω (r) t

Quantum (real time) = classical (event time) + [Quantum – classical]

Quantum time = classical time + relativistic time

Relativistic time = quantum time – classical time

We see detect and measure Arabs real time physics

Or, t = t0 e í ω (t) t of an actual or classical time t0 ------------------ Eq - 3

And the difference between Arabs t = t0 e í ω (t) t and actual or classical time t0 isrelativistic time

Quantum = classical + [Quantum – classical]Quantum = classical + relativistic timeRelativistic = quantum – classical

All there is in the Universe is objects of mass m moving in space (x, y, z) at a locationr = r (x, y, z). The state of any object in the Universe can be expressed as the product



S = m r; State = mass x location is all of astronomy needed Equation -1That is if mass of objects in space is known and if the location of object in space isknow then the state S = m r = mass x location of any object in space can beknown and that is all needed to be known to describe space motion of any objectand that is what is called astronomy

That is mass m location r and time t = Astronomy and from this we can conclude:

Page 13

Quantum (mass) = classical (mass) + [Quantum – classical]Quantum mass = classical mass + relativistic massRelativistic mass = quantum mass – classical mass

We see detect and Arabs real time mass m = m0 e í ω (m) t ------------- Eq- 4 of

an actual or classical time m0 and the difference between Arabs real time mass m= m0 e í ω (m) t and actual or classical time m0 is Arabs real time mass delaySuch a claim by the Arabs that Astronomical measurements are made along the lineIs saying Quantum mass = classical mass + relativistic mass

And saying (I/O) q = q + [(I – O)/O] q; q measured quantity Eq - 1

And real time distance r = r0 e í ω (r) t Eq - 2

And real time t = t0 e í ω (t) t Eq - 3

And real time mass m = m0 e í ω (m) t Eq - 4

And S = m r, the state equation Eq - 5 That is Arabs see detect and measure quantum distance quantity r = r0 e í ω (r) t

When there is classical distance quantity r0And the difference explains that the universe is seen in real time and not in silly Westerideas of wrong space time. That is the difference between an object location and an objmeasurement of its location is “relativistic” and that 500 years of “western” Modernphysics can be deleted without loss of subject and 500,000 “Modern” physicists can be idiots with no fear or regrets.

That is Arabs detect and measure quantum time quantity t = t0 e í ω (t) t

When there is classical time quantity t0

That is Arabs see detect and measure quantum mass quantity m = m0 e í ω (m) t

When there is classical mass quantity m0

What is wrong in all of Modern physics is this experimental mistake:[(I – O)/O] q in everything that western modern space – timers do from spacescience to nuclear structure and this mistake was made by every physicist. Thispainful mistake is the one mistake when corrected it deletes western civilizationphysics and physicists explain the universe correctly and matches experimentalresults with unprecedented accuracy to delete “modern” physics of past 500 yearsand delete 500,000 “modern” physicists without loss of subject. What I am going todo



1- Show how this one mistake was/is made daily by all western civilizationeducated “modern” physicists2- How this one mistake won the majority of Nobel prizes and changed physics from1258 Arabic science to 2010 western educated stupidity3 – Show how correcting this mistake will solve any and all unsolved physical motion

problems that is not solvable by space – time physics or any read or publishedphysicsArabs real time physics and astronomy is the past present and future of all of hysics

Page 14

hapter four









Γ = t + (Γ – t) = t + ∆ Γ; ∆ Γ = (Γ – t)Γ/t = t/t + (Γ – t)/tΓ/t = 1 + (Γ – t)/t

To measure orbital speed using time, then multiply by orbital speed toget the following equation: (Γ/t) θ’0= θ’0 + [(Γ – t)/t] θ’0

And θ’0 = orbital speedThe quantity θ’ 0 measurement is independent of timeThe quantity (Γ/t) θ’0 measurement is time dependentThe difference = [(Γ – t)/t] θ’0 = relativistic = Illusions

Page 16

With (Γ/t) θ’0= θ’0 + [(Γ – t)/t] θ’0

Modern physics is wrong when: In general1 - (Γ/t) θ’0= θ’0 Quantum = classical or when someone looks at the car fromdifferent distances and wonder why he/she does not see the same size car.

An observer sees a car passing by at close distance

An observer sees a car passing by at far distance

Each observer will find the car size different

2 – Modern physics is wrong when (Γ/t) θ’0= [(Γ – t)/t] θ’0

When quantum = relativistic



3 – Modern physics is wrong when θ’0= [(Γ – t)/t] θ’0

When classical = relativistic

Let us demonstrate the power of Arabs real time Physics and astronomy and seehow Arabs real time astronomy works but first let us do some definitions.

Page 17

Real time distance scaleMeasured distance = actual distance + [measured distance – actual distance]Or, r = r0 + (r x – r0)

And r /r0 = r0 /r0 +(r – r0)/r0

And r /r0 = 1+(r– r0)/r0

And (r /r0) θ’0= θ’0 [(r - r0)/r0] θ’0

Real time Velocity Scale vWith r = r0 + (r – r0)Divide by tThen r/t = r0 /t + (r/t – r0 /t)And v = v0 + (v – v0); dividing by v0

And v/ v0 = 1 + (v – v0)/ v0

Multiplying by θ’0And (v/ v0) θ’0= θ’0+ [(v – v0)/ v0] θ’0

Real time acceleration scale γWith r = r0 + (r – r0)Divide by t²Then r/ t² = r0 / t² + (r/ t² – r0 / t²)And γ = γ 0 + [(γ – γ 0)]; dividing by v0

And γ / γ 0 = 1 + [(γ – γ 0)/ γ 0]Multiplying by θ’0And (γ / γ 0) θ’0= θ’0+ [(γ – γ 0)/ γ 0] θ’0The angular speed is a 5th grade math that is measured wrong by Astronomers exposethe stupidity of modern physics and the stupidity of modern astronomyThe circumference of a planet circular motion is C = 2 π r m where r m is the radius.In 1969 I knew about circular speed v m = 2 π r m / T m where Tm is the period of rotation. Also, in 1969 I knew about angular speed θ’ m = 2 π /Tm = (v m / r m).Or C = 2 π r m; v m = 2 π r m /Tm; θ’ m = 2 π /Tm = (v m / r m)

θ’ m = 2 π /Tm= (v m /r m)



Page 18

Angular velocity is θ’ m = 2 π /Tm= (v m /r m)In arc second per century δ θ’ m = (v m /r m) (180/ π) [36526/Tm (days)] (3600)

Arabs Real time Astronomy distance scale:Is: (r m /r0) θ’ m= θ’ m [(r m - r0)/r0] θ’ m

Multiplying by δ θ’ m

Then (r m /r0) δ θ’ m= δ θ’ m + [(r m - r0)/r0] δ θ’ m

In arc second per century δ θ’ m = (v m /r m) (180/ π) [36526/Tm (days)] (3600)The distance Error is: [(r m - r0)/r0] δ θ’ m

The velocity Error is: [(v m - v0)/v0] δ θ’ m

The acceleration error is: [(γ m – γ 0)/ γ 0] δ θ’ m

The angular velocity real time distance scale Error:

Is: [(r m - r0)/r0] δ θ’ m = [(r m - r0)/r0] (v m /r m) (180/ π) [36526/Tm (days)] (3600)The angular velocity real time velocity scale Error:Is: [(v m - v0)/v0] δ θ’ m = [(v m - v0)/v0] (v m /r m) (180/ π) [36526/T m (days)] (3600)The angular velocity real time acceleration scale Error:

Is: [(γ m – γ 0)/ γ 0] δ θ’ m = [(γ m – γ 0)/ γ 0] δ θ’ 0 (v m /r m) (180/ π) [36526/T m (days)] (3600As an example: when Astronomers look at planetary motion around the sun andthey saw the angular velocity in arc second per century:Equal to δ θ’ m = (v m /r m) (180/ π) [36526/T m (days)] (3600)

= 70.75 arc second per centuryAstronomers also saw the visual effect

Of: [(r m - r0)/r0] δ θ’ m = [(r m - r0)/r0] (v m /r m) (180/ π) [36526/T m (days)] (3600)And it is equal to [(r m - r0)/r0] δ θ’ m = 43Where r m = Mercury – Sun distance = 58.2 X 106kmAnd v m = Mercury around the sun orbital speed Sun distance = 47.9 km/secAnd r 0 = r e = Earth – Sun distance = 149.6 X 106kmAnd T m = Mercury around the sun orbital period



Page 19

This quantity of:[(r m - r0)/r0] δ θ’ m = [(r m - r0)/r0] (v m /r m) (180/ π) [36526/T m (days)] (3600)And it is equal to [(r - r0)/r0] δ θ’ m = 43 is taken as the proof of the existence of silly Modern Astronomy notion that the Universe is not made of three dimensional

Space (x, y, z) = (length, width, height) but made of a more complex space – toimaginary time – back to space Universe (x, y, z, it) = (length, width, height,imaginary time)

[(v m – v e)/v e] δ θ’ 0 = [(v m – v e)/v e] (v m /r m) (180/ π) [36526/T m (days)] (3600)And it is equal to [(r - r0)/r0] δ θ’ m = 43[(γ m – γ e)/ γ e] δ θ’ m = [(γ m – γ e)/ γ e] (v m /r m) (180/ π) [36526/T m (days)] (3600)[(γ – γ 0)/ γ 0] δ θ’ m= 43

Space – time is Einstein’s crime against physics


PlanetOrbit T


LessEarthspeed

Spinspeedkm/sec


Mercury 58.2 88 47.9 18.1 .002 70.75Venus 108.2 224.7 35.05 5.7 6.52 10.86Earth 149.6 365.26 29.8 .46511 4.1Mars 227.936 687 24.14 0.2411Jupiter 778.412 4333 13.06 12.6Saturn 1,426.725 10760 9.65 9.87Uranus 2,870.97 30690 6.80 2.59Neptune 4,498 60180 5.43 2.68Pluto 5906.4 90730 4.74



I am the Greatest Nuclear Physicist of all timeAnd I have 1001 all new physics formulas to prove it

My name is Joe Nahhas and I am the greatest Physicist and Astronomer of past

present and the future because as a teenager I stood up to criminals with Nobelprizes and this book is how to expose criminals with Nobel prizes in physics and thefact that most criminals with Nobel prizes are a product of the big westerninstitutions has nothing to do with science but has something to do with westerncapitalistic greed fraud and arrogance that changed physics from science tostupidity and the time has come to delete stupidity and that is to delete westernphysics and physicists without exception since the rise of western civilization 500years ago starting with Copernicus. There is nothing correct in all westerncivilization physics that is taught in classrooms and used in scientific calculations.Yes, I am saying that all of physics is all wrong and this book is the proof of it and

there is nothing better than to start with the grand master of stupidity, German –American moron of the 20th century, the one and only Albert Einstein.

Page 20

Einstein greatest achievement in space said Planet Mercury travel in space at an angular speed of 70.75 arcs second per centuryAnd in time at angular speed of 43 arcs second per century

The Advance of Planet Mercury’s Perihelion given by Euclid’s Geometry[2 π/T] [180/π][36526/88][3600] = [2 π /88 x 24x3600] [180/π][36526/88][3600] = 70.75Einstein’s time travel space – time formula:ψ = - 6 π GM/a c² (1 - ε²) [180/ π] [36526/T][3600] = 43 angular velocity time travel of planet MercuryG = 6.673 x 10-11= gravitational acceleration constantM =2x1030 kilogram = mass of the SunEccentricity of Mercury’s orbit = ε = 0.206T= 88 days = period of Planet mercury’s rotation around the SunAnd c = 299792.458 kilometer/second =light speed in kilometers/second

And a = 58.2 x 106 km/sec = semi major axis of planet Mercury orbit



The grand moron of the west said Planets travel in space and time

The Grand moron said planets travel in space around the Sun in an elliptical orbit

The Grand moron said planets travel in time around the Sun rotating the elliptical orbit

21

Planet

r

Sun





Unless this moron can prove time travel he can keep his German stupidity to himself and Alfred NobelInstitution because time travel is Einstein’s and Alfred Nobel Institution stupidity

I am not saying Einstein is a moron but what I am saying is all western physicistsare morns to say the least and can be deleted without loss of subject to be exact.Practicing again If 1= 1

2 = 23 = 3

Then we can write anything that is equal to itself as equal to itself like:Visual = Visual

Actual = actual- Actual = - actual

----------------------- AddVisual = Actual + (Visual – actual)

Divide by actualVisual/actual = Actual/actual + (Visual – actual)/actual

OrVisual/actual = 1 + (Visual – actual)/actualImage/object = 1 + (Image – object)/object

I/O = 1+ (I – O)/OWe do not see object O but we see Image I. If we to look at planet Mercury from

Earth and not from the Sun, then we are not looking at θ’ m= 2 π /T m = (v m /r0) butwe are looking:At θ’ 0 I/O = 1 θ’ 0+ [(I – O)/O] θ’ 0Or θ’ 0 I/O = θ’ 0+ [(I – O)/O] θ’ 0The visual illusion and Modern Physicists confusion is: [(I – O)/O] θ’ 0Where I is Mercury – Sun distance = 58,200,000 kilometers = r m

And O is Earth – Sun distance = 149,600,000 kilometers = r e

The Visual Illusions and modern Physicists confusion of Planet Mercury is:[(I – O)/O] θ’ 0 = [(r m – r e)/ r e] θ’ 0

Page 23





With r m = v m T m; r e = v e T e

Or Galileo’s linear motion visual Illusion

[(I – O)/O] δ θ’ 0 = [(v m T m – v e T e)/ v e T e] (v m /r m) [(180/π) (3600) (26526/T m)] = 43

[(I – O)/O] δ θ’ 0= [(47.9x88 – 365.26x29.8)/ 365.26x29.8] (70.75) = 43

M r Galileo you are wrong and you are deleted

With[(I – O)/O] δ θ’ 0 = [(v m T m – v e T e)/ v e T e] (v m /r m) [(180/π) (3600) (26526/T m)] = 43

Page 25





(I/O) q = q + [(I – O)/O] q

M r Lippershey you can even read the telescope and you are deleted

Hans Lippershey the person who attempted to get a patent for the telescope in 1609

Modern Physics is wrong because Hans and the entire Western civilization s

have no clue how to read the telescope(I/O) q = q + [(I – O)/O] q

Page 27



Rene Descartes Cartesian failures

t = t0 e í ω (t) t

Γ = t e í ω (t) t

Along the line of sight

Γ x = t cosine ω tΓ x = t + (Γ x – t) = t + ∆ Γ x; ∆ Γ x = (Γ x – t)Γ x /t = t/t + (Γ x – t)/tΓ x /t = 1 + (Γ x – t)/t

What is [(Γ x – t)/t]

Then ∆ Γ x (seconds) = Γ x - t = - 2 t sine² {[arc tan (V r m - V r e) / (√ 2c)]/ 2} = 43And in arc ∆ Γ x (arc seconds) = Γ x - t= - 30 t sine² {[arc tan (V r m - V r e) / (√ 2c)]/ 2} = 43

Where r’ = V r ; and r θ’ = V θ; and V r ²= 2 γ r r; and V θ ² = r γ θ

The confusion is and was γ r = γ θ; V r ²= 2 V θ ²; and taking V r = (√ 2) V θ

And taking V r = V r (Mercury) - V r (Earth) = V r m - V r e

And V θ = V r / (√ 2∆ Γ x Arc second) = Γ x - t

= - 30 t sine² {[arc tan (V r m - V r e) / (√ 2c)]/ 2} = 43 arc second /century

Page 28



Chapter 3: Arabs real time light motion





Observer line: …………………Observer ………………

Visual objects seen through emitted or reflected light follow this lawLight measurement of visual motion of objects law: (I/O) q = q + [(I – O)/O] q

The proof:Page 29



All there is in the Universe is objects of mass m moving in space (x, y, z) at alocationr = r (x, y, z). The state of any object in the Universe can be expressed as theproductS = m r; State = mass x location:

P = d S /d t = m (d r /d t) + (dm/d t) r = Total moment= change of location + change of mass= m v + m' r; v = velocity = d r/d t; m' = mass change rate

F = d P /d t = d²S /dt² = Total force= m (d²r /dt²) +2(dm/d t) (d r /d t) + (d²m/dt²) r= m γ + 2m'v +m" r; γ = acceleration; m'' = mass acceleration rate


r = r r (1) ;v = r' r(1) + r θ' θ(1) ; γ = (r" - rθ'²)r(1) + (2r'θ' + r θ")θ(1)


= [d² (m r)/dt² - (m r) θ'²] r (1) + (1/m r) [d (m²r²θ')/d t] θ (1)

= [-Gm M/r²] r (1) ------------------------------- Newton's Gravitational LawProof :First r = r [cosine θ î + sine θ Ĵ] = r r (1)

Define r (1) = cosine θ î + sine θ ĴDefine v = d r /d t = r' r (1) + r d[r (1)]/d t = r' r (1) + r θ'[- sine θ î + cosine θĴ]

= r' r (1) + r θ' θ (1)



γ = (r" - rθ'²) r (1) + (2r'θ' + r θ") θ (1)

With d² (m r)/dt² - (m r) θ'² = F (r) And d (m²r²θ')/d t = 0With m = constant, thenWith d² r/dt² - r θ'² = F (r) Eq-1 And d (r²θ')/d t = 0 Eq-2With d² r/dt² - r θ'² = 0 E q – 1And d (r²θ')/d t = 0 Eq-2

Page 30



From Eq-2: d (r²θ')/d t = 0Then r²θ' = h = constantDifferentiate with respect to timeThen 2rr'θ' + r²θ" = 0

Divide by r²θ'Then 2(r'/r) + θ"/θ' = 0And 2(r'/r) = - θ"/θ' = 2[λ (r) + ỉ ω (r)]Also, r = r0 (θ, 0) e [λ (r) + ỉ ω (r)] t

And θ' = θ' 0 (θ, 0) e -2[λ (r) + ỉ ω (r)] t


And θ' = θ' 0 (θ, 0) e -2ỉ ω t

With d² r/dt² - r θ'² = 0

Let u = 1/r; r = 1/u; r²θ' = h = θ’ /u²And d r/d t = (d r/ d u) (d u /d θ) (d θ/ d t) = (- 1/u ²) (θ’) (d u/ d θ)

= - h (d u/ d θ)

And d² r/ d t² = - h (θ’) (d² u/ d θ ²)= [- h²/r²] (d² u/ d θ ²)= - h² u² (d² u/ d θ ²)

With d² r/dt² - r θ'² = 0 E q – 1And - h² u² (d² u/ d θ ²) – (1/u) (h u²) ² = 0Then (d² u/ d θ ²) + u = 0

Then u = A e - í θ Then r 0 (θ, 0) = (1/A) e í θ And r 0 (θ, 0) = r 0 (0, 0) e í θ And r = r 0 (0, 0) e í θ e ỉ ω t Or, r = r 0 e í (θ + ω t)

This is quantum mechanics

rabs real time astronomy is actually quantum mechanics r = r0 e í ω (r) t

Light is emitted and not an emitter and humans have no means of measuring lightin motion and at best they can take a snap shot.In mathematical languageThen r (θ, 0) = r 0 e í θ at t = 0And r (θ, t) = r 0 e í (θ + ω t) = r 0 e í θ e í ω t = r (θ, 0) e í ω t

And r (θ, t) = r (θ, 0) [cosine ω t + í sine ω t]And r x (θ, t) = r x (θ, 0) cosine ω tAnd ω t = cosine-1 [r x (θ, t) / r x (θ, 0)]

31



Then ∆ r = r x (θ, t) - r x (θ, 0) = r x (θ, 0) [(cosine ω t) – 1]

And [r x (θ, t) - r x (θ, 0)]/ r x (θ, 0)

= [(1 - 2 sine² ω t/2) – 1]= - 2 sine ² ω t/2; ω t = cosine-1 [r x (θ, t) / r x (θ, 0)]

Arabs real time astronomy:Image = Image = IObject = Object = O- Object = - Object = - O

Image = object + (Image – Object)I = O + (I – O)(I/O) = O/O + [(I – O)/O](I/O) = 1 + [(I – O)/O](I/O) θ' 0 = θ' 0 + [(I – O)/O] θ' 0

Quantum = classical + relativistic IllusionI = r; O = r 0

Or, (r / r 0) θ' 0 = θ' 0 + [(r – r 0)/ r 0] θ' 0

And [(r – r 0)/ r 0] θ' 0

Or [- 2sine ² ω t/2] θ' 0; ω t = cosine-1 [r x (θ, t) / r x (θ, 0)] = cosine-1 (r/ r 0)For planet Mercury:

The distance visual effect Error is: [(r m – re)/re] δ θ’ m

The quantity: δ θ’ m = (v m /r m) (180/ π) [36526/Tm (days)] (3600) = 70.75

With v m = 47.9 km/sec; r m = 58.2 x 106 km; Tm = 88 days

With r = 58.2 x 109 m = Sun – Mercury distance

And r e = 149.6 x 109 m = Sun Earth distance

With [(r m – re)/re] = [- 2sine ² ω t/2] = 0.61And ω t = cosine-1 [r x (θ, t) / r x (θ, 0)] = cosine-1 (r/ r 0)Or ω t = cosine-1 [r x (θ, t) / r x (θ, 0)] = cosine-1 (r m / r e)

And [(r m – re)/re] δ θ’ m = [- 2sine ² ω t/2] (v m /r m) (180/ π) [36526/Tm (days)] (3600)= [- 2sine ² {[cosine-1 (r m / r e)]/2}] (v m /r m) (180/ π) [36526/Tm (days)] (3600)= 0.61 x 70.75 = 43

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Chapter five: Arabs real time light Astronomy

A- Kepler’s force laws

F = - ω² a and F = - GmM/a²Or, F = - ω² a = - GmM/a²And T²/a³ = 4 π GM

Mr Kepler you are wrong and you are deleted

Johannes Keplers:

Kepler’s law: a³/T² = k = constantIsaac Newton space Inverse square law γ = k/r²

Hooke’s time Inverse square law γ = r/t² or γ = r/T²Kepler’s Space – time Law: k/r² = r/ T²; or, a³/T² = k = constantWhere this law came from?Acceleration = γ = r/t² = k/r²γ = time coordinates r/t² = space coordinates k/r²; r substituted for t

γ = r/t² = k/r²γ = - k/r² Newton’s theft = Newtonγ = - r/t² = - r/T² = - k r Hooke’s theft = Hooke’ lawOf: a³/T² = k = constantOr, a1³/ T1² = a2³/ T2²Or, a1 / a2 = (T1 / T2)2/3

And (a1 - a2)/ a2 = (T1 / T2)2/3 – 1Or (am – a e)/ a e = (Tm / Te) 2/3 – 1Nicklaus Copernicus Distance Illusion[(I – O)/O] δ θ’ 0 = [(r m – r e)/ r e] (v m /r m) [(180/π) (3600) (26526/T m)] = 43Become: Kepler’s vision of idiot Einstein: Nicklaus Copernicus Distance Illusion[(I – O)/O] δ θ’ 0 = [(Tm / Te) 2/3 – 1] (v m /r m) [(180/π) (3600) (26526/T m)] = 43

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When Newton came with F = - GmM/r²Physicists calculated: θ' c m = v c m /r;Angular velocity with respect to center of mass

And Astronomers observed: θ's = v s /rAngular velocity with to the sun

And v c m = √ [GM²/ (m + M) a]

And v s = √ (GM/a)

And (θ' cm - θ’ s) /θ’ s = [(2 π/T c m) - (2 π/T s)]/ (2 π/T s)= (T c m /T s) – 1 = (v s /v c m) – 1

= [√ (GM/a)] x {√ [(m + M) a/ GM²]} - 1= √ [(m + M)/M] - 1= √ [1 + (m/M)] - 1≈ 1 + (m/2 M) – 1 ≈ m/2 M

And (θ' cm - θ’ s) /θ’ s ≈ (m/2 M)And (θ' cm - θ’ s) / θ' s = (2 π /T s) (m/2 M)And [(θ' cm - θ’ s)] T s = π (m/ M)Multiplying by [(180/π) (3600) (26526/T m)]

[(I – O)/O] δ θ’ 0 = (π m/M) [(180/π) (3600) (26526/T m)] = 43T²/a³ = 4 π²/GM with respect to the sunTo T²/a³ = 4 π²/G (M + m) with respect to the center of massThat is Kepler's measurements data are centered from the sun and Newton's dataare centered at the center of mass and this would explain this mistake like this:T² (1)/a³ = 4 π²/GM andT² (2) /a³ = 4 π²/G (M + m)When Newton changed Kepler's equation he solved the advance of perihelion asshown:

The advance of Mercury perihelion by Newton

T (1) = T (2) √ [M/ (M + m)]And 2π/ T (1) = [2 π/ T (2)] √ (1 + m/M)And θ' (1) = θ' (2) √ (1 + m/M)And θ' (2) = θ' (1) /√ [1 + (m/M)] ≈ [1 - m/ (2M)]This approximation was not on the original workAnd θ' (2) - θ' (1) = θ' (1) [1 /√ [1 + (m/M)] - 1]And θ' (2) - θ' (1) ≈ - θ' (1) (m/2M) = - [2 π/T] [m/2M) = - π m/MT radians/T

Page 34



W " (calculated) = [- π m/MT] (180/π degrees) (3600 seconds) (36526 century); T= days; with m = 0.32 x1024 kg; and M = 2.0 x1030 kg; T = 88 days

[(I – O)/O] δ θ’ 0 = (-180 x 36526 x 3600/T) (π m/M)

= 43.0" seconds of arc /100 years

Mr Newton you are wrong and you are deleted

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Hooke’s for law F = - ω²x; 3 – Newton’s law F = - GmM/x²If Hooke’s law is taken the F = - k r in one dimensionThen r’’ +ω²r = 0; then r (θ, 0) = r0 e ỉ ω t

Then r = r0 e

ỉ ω t

; and r = r0 [1- 2 sine² ω t/2]And (r - r0)/ r0 = - 2 sine² ω t/2The distance visual effect Error is: [(r m – re)/re] δ θ’ m




And r e = 149.6 x 10

9

m = Sun Earth distanceWith [(r m – re)/re] = [- 2sine ² ω t/2] = 0.61And ω t = cosine-1 [r x (θ, t) / r x (θ, 0)] = cosine-1 (r/ r 0)Or ω t = cosine-1 [r x (θ, t) / r x (θ, 0)] = cosine-1 (r m / r e)

And [(r m – re)/re] δ θ’ m = [- 2sine ² ω t/2] (v m /r m) (180/ π) [36526/Tm (days)] (3600)= [- 2sine ² {[cosine-1 (r m / r e)]/2}] (v m /r m) (180/ π) [36526/Tm (days)] (3600)= 0.61 x 70.75 = 43

Mr Hooke I really like you but you can be deleted

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Chapter Five: The all time wrong AstronomerThen Urbain Jean Joseph Le Verrier cameThe angular velocity of Mercury around the Sun is: θ m' = v m /r m

And δ θ’ 0 = (v m /r m) (180/π) (3600) (26526/Tm); Tm = 88 days

If it is measured for planet Mercury from the sun thenThen it is θ m' = v m /r m

If planet Mercury around the sun measured from earth then =Then θ m' (Earth) = (v m + v e)/r m

And θ m' (Earth) = v m /r m + v e /r m

And not v m /r m

Le Verrier [1] mistake is: v e /r m

The angular speed delay is: v* e /r m

Or, [(v e /v m) (v m /r m)]Taking into account Earth rotation vº e Le Verrier mistake: Then the angular speed delay:Is: v e /r m = [v* e /r m +/- vº e /r m]In arc second per century multiplying by [(180/π) (3600) (26526/T)][(I – O)/O] δ θ’ 0 = [(v* e +/- vº e) /r m] [(180/π) (3600) (26526/T)][(I – O)/O] δ θ’ 0 = [(v* e +/- vº e) /v m) (v m /r m)] [(180/π) (3600) (26526/T)] = 43[(I – O)/O] δ θ’ 0 = [(v* e +/- vº e) /v m) (v m /r m)] [(180/π) (3600) (26526/Tm)]

Page 37

SM

E



Idiot Le Verrier[(I – O)/O] δ θ’ 0 = [(r m – r e)/ r e] (v m /r m) [(180/π) (3600) (26526/T m)] = 43[(I – O)/O] δ θ’ 0 = [(v m T m – v e T e)/ v e T e] (v m /r m) [(180/π) (3600) (26526/T m)]

Arabs real time Astronomy is 5 lawsAnd saying (I/O) q = q + [(I – O)/O] q; q measured quantity Eq - 1

And real time distance r = r0 e í ω (r) t Eq - 2

And real time t = t0 e í ω (t) t Eq - 3

And real time mass m = m0 e í ω (m) t Eq - 4And S = m r, the state equation Eq - 5

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hapter six

Newton equation is a solved wrong for 350 yearsNewton’s unprecedented stupidity

Being a good mathematician is solving own equation wrong?Newton said there is gravity Force F = -GmM/r² whose solution is this

Fig1. Newton’s gravitational lawAnd r (θ, t) = [a (1-ε²)/ (1+ε cosine θ)]But you idiot this solution is wrong

Real time solution is: r (θ, t) = [a (1-ε²)/ (1+ε cosine θ)] ℮ [λ (r) + ỉ ω (r)] t

"Apparent advance of perihelion"[(I – O)/O] δ θ’ 0 = (-720x36526x3600/T) {[√ (1- ε²)]/ (1-ε) ²} x

[(v°+ v*)/c] ² = 43 arc second per centuryPage 39

Planet

r

Sun



All there is in the Universe is objects of mass m moving in space (x, y, z) at alocation r = r (x, y, z) = r [length, width, height].

The state of any object in the Universe can be expressed as the product

S = m r; State = mass x location:




Location = r = r r (1)

Velocity = v = r' r (1) + r θ' θ (1)

Acceleration = γ = (r" - rθ'²) r (1) + (2r'θ' + r θ") θ (1)

F = m γ + 2m'v +m" r

F = m [(r"-rθ'²) r (1) + (2r'θ' + r θ") θ (1)] +

2m'[r' r (1) + r θ' θ (1)] ++ (m" r) r (1)

F = [d² (m r)/dt² - (m r) θ'²] r (1)

+ (1/mr) [d (m²r²θ')/d t] θ (1)

F = F1 + F2

F1 = [d² (m r)/dt² - (m r) θ'²] r (1)

F2 = (1/m r) [d (m²r²θ')/d t] θ (1)

Newton's Gravitational Equation is: F = -GmM/r² With d² (m r)/dt² - (m r) θ'² = -GmM/r² (1)And d (m²r²θ')/d t = 0 (2)

Page 40



The solution is notAnd r (θ, t) = [a (1-ε²)/ (1+εcosθ)]But this solution


"Apparent advance of perihelion"[(I – O)/O] δ θ’ 0 = (-720x36526x3600/T) {[√ (1- ε²)]/ (1-ε) ²} x

[(v°+ v*)/c] ² arc second per centuryProof:

All there is in the Universe is objects of mass m moving in space (x, y, z) at a location rr (x, y, z) = r [length, width, height].e state of any object in the Universe can be expressed as the product

S = m r; State = mass x location:P = d S /d t = m (d r /d t) + (dm/d t) r = Total moment

= change of location + change of mass

= m v + m' r; v = velocity = d r/d t; m' = mass change rateF = d P /d t = d²S /dt² = Total force= m (d²r /dt²) +2(dm/d t) (d r /d t) + (d²m/dt²) r= m γ + 2m'v +m" r; γ = acceleration; m'' = mass acceleration rate

In polar coordinates systemLocation = r = r r (1)

Velocity = v = r' r (1) + r θ' θ (1)

Acceleration = γ = (r" - rθ'²) r (1) + (2r'θ' + r θ") θ (1)

F = m γ + 2m'v +m" rF = m [(r"-rθ'²) r (1) + (2r'θ' + r θ") θ (1)] +

2m'[r' r (1) + r θ' θ (1)] ++ (m" r) r (1)

F = [d² (m r)/dt² - (m r) θ'²] r (1)

+ (1/mr) [d (m²r²θ')/d t] θ (1)

F = F1 + F2 F1 = [d² (m r)/dt² - (m r) θ'²] r (1)

F2 = (1/mr) [d (m²r²θ')/d t] θ (1)

Newton’s force law is F1 = [-GmM/r²] r (1)

Kepler's force law is:F2 = (1/mr) [d (m²r²θ’)/d t] θ (1) = 0

If m is constant then d (m²r²θ’)/d t = 0; and d (r²θ’)/d t = 0Or, r²θ’ = h = 2 π a b/T; a = mean distance from sun and is called semi major axisand b is the semi minor axis.

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the motion of a planet m around the Sun M measured in real time is a rotating ellipse

Tyco Brahe Logged observational Data of Planets P motion around the Sun S andthen Kepler stated the areal velocity law: If Planet p observed from the sun then thetrajectory of planet p will cut equal areas in equal times.

Page 42

θr

Sun

Mercury

M

ψ

m

θ



Page 43

A

AA

A

S

A

A

A

S

T

T

TT

TT

T

P

P



When the areas size A are sliced equally it was found that the times spent by planetsorbiting around the Sun and making areas A each are equal also.Or, r² (0) θ' (0) = r² (1) θ' (1) = r² (2) θ' (2) = r² (3) θ' (3) = --

= location² x [angular speed] = constant= Areal velocity

If r² θ' = hThen differentiating with respect to timeThen d (r² θ')/ d t = d h/ d tAnd 2 r r’ θ’ + r² θ’’ = 0Or 2 (r’ /r) = - (θ’’/θ’)

The r = r0 e í ω t

And θ’ = θ’ 0 e – 2 í ω t

With r = r0 e í ω t

In real time r (n) = r (0) e í ω t

With r² (0) θ' (0) = r² (1) θ' (1)Then θ' (1) = [r² (0)/ r² (1)] θ' (0)

And θ' (1) = {[e í 2 ω t] θ' (0)

And θ’ (1) = {[cosine 2 ω t + í sine 2 ω t] – 1} θ' (0)Δ θ’ (1) = Δ θ’ (x) + í Δ θ’ (y)

= [cosine 2 ω t + í sine 2 ω t] θ' (0)Δ θ’ (x) = [cosine 2 ω t] θ' (0)Δ θ’ (x) = [1 – 2 sine² ω t] θ' (0)Δ θ’ (x) - θ' (0) = - 2 θ' (0) sine² ω tΔ W = Δ θ’ (x) - θ' (0) = - 2 θ' (0) sine² ω t

= -2(2π) [√ (1-ε²)]/T (1-ε) ²] sine² ω tAnd θ' (0) = h/r² (0) = 2 π a b/T a² = 2π√ (1-ε²)]/T (1-ε) ²Δ W = - 4 π) [√ (1-ε²)]/T (1-ε) ²] sine² ω tIf this apsidal motion is to be found as visual effects, thenWith, v ° = spin velocity; v* = orbital velocityAnd v/c = (v* + v°)/c = tan ω tΔ W = -4 π [√ (1-ε²)]/T (1-ε) ²] sine² {Inverse tan [(v* + v°)/c]} radiansMultiplication by 180/π to change to degreesΔ W ° = (-720/T) {[√ (1-ε²)]/ (1-ε) ²} sine² {Inverse tan [(v* + v°)/c]} DegreesAnd multiplication by 1 century = 36526 days and using T in daysW° (ob) = (-720x36526/Tdays) {[√ (1-ε²)]/ (1-ε) ²} x

sine² {Inverse tan [(v* + v°)/c]} degrees/100 yearsApproximationsWith v° << c and v* << c,Then sine Inverse tan [v°/c + v*/c] ≈ (v° + v*)/cΔ W ° (calculated) = (-720x36526/Tdays) {[√ (1-ε²)]/ (1-ε) ²} x[(v° + v*)/c] ² degrees/100 yearsThis is the equation for axial rotations rate of planetary and binary stars or any twobody problem.The circumference of an ellipse: 2πa (1 - ε²/4 + 3/16(ε²)²- --.) ≈ 2πa (1-ε²/4); R=a (1-ε²/4)

Page 44



Finding orbital velocitiesFrom Newton's inverse square law of an ellipse motion applied to a circular orbitgives the following: m v²/ r (cm) = GmM/r²Planet --- r (cm) ----- Center of mass ------- r (CM) --------- Mother SunPlanet ------------------- r -------------------------------------- Mother Sun

Center of mass law m r (cm) = M r (CM); m = planet mass; M = sun massAnd r (cm) = distance of planet to the center of massAnd r (CM) = distance of sun to center of massAnd r (cm) + r (CM) = r = distance between sun and planetSolving to get: r (cm) = [M/ (m + M)] rAnd r (CM) = [m/ (m + M)] rThen v² = [GM r (cm)/ r²] = GM²/ (m + M) rAnd v = √ [GM²/ (m + M) r = a (1-ε²/4)]Planet orbital velocity or primary velocity:And v* = v (m) = √ [GM²/ (m + M) a (1-ε²/4)] = 48.14 km for planet MercuryVelocity of secondary or Mother Sun velocityAnd v* (M) = √ [Gm² / (m + M) a (1-ε²/4)]Applications: mercury ellipse and its axis rotation of 43 " /century1- Planet Mercury axial "apparent" rotation rate

Δ W’’ = (-720x36526x3600/T) {[√ (1-ε²]/ (1-ε) ²} (v* + v°/c) ² seconds of arc pecentury

The circumference of an ellipse: 2πa (1 - ε²/4 + 3/16(ε²)²- --.)≈ 2πa (1-ε²/4); R =a (1-ε²/4)

Where v* (p) =√ [G M² / (m + M) a (1-ε²/4)] ≈ √ [GM/a (1-ε²/4)]; m<<M; Solarsystem data: G =6.673x10-11; M=2x1030kg; m=.32x10^24kg; ε = 0.206;T=88days; c = 299792.458 km/sec; a = 58.2km/sec; v° = 0.002km/sec

Calculations yield: v* =48.14km/sec; [√ (1- ε²)] (1-ε) ² = 1.552Δ W = (-720x36526x3600/88) x (1.552) (48.14/299792)²

=43.0”/centuryΔ W’’ = (-720x36526x3600/T) {[√ (1-ε²]/ (1-ε) ²} [(v* + v°)/c] ²

= 43 seconds of arc per century[(I – O)/O] δ θ’ 0= (-720x36526x3600/T) {[√ (1-ε²]/ (1-ε) ²} [(v*m + v° m)/c] ² seconds of arc pcenturyOr, Newton is plain stupid? There is no proof of action at a distance?F = -GmM/r² is not a proof of gravitational pull between planetary objects but

rather the interaction of earth with its atmosphereG = 1/ (2/5) (4π/3) p T² = √ (2π)/ (4π/3)p T²; ρ = air density =1.2045kg/m³; and TEarth rotation period = 23.9333x3600; Then G = 6.6747 x 10-11

G = 1/ (radius of gyration) (sphere) (air density) (Earth spin) ²G = √ (2 π) / (4π/3) p T² = √ (2π)/ (4π/3)p T²Suggesting that gravity measured on Earth is local to earth surface causedby Earth spin motionAlso a rotating Ellipse can be derived from many different solutions andnot necessarily from an inverse square law

Page 45



Chapter sevenInverse Cube equations F = m γ = - k/r³ r (1), then in polar coordinatesWith m [d² r/dt² - θ'²r] = - k /r³ Inverse Cube Gravitational law (1)And d (r²θ')/d t = 0 Kepler's Areal Velocity Equation (2)

These two equations give an axial rotation rate:One: φ = π (m/ M) (180) [36526/T] [3600] arc second/100 years

= 43.0344 seconds of arc / century for MercuryTwo: δ θ' = - 720 [36526/T] (3600) √ (1 - ε²)/ T (1 - ε) ² (v/c) ² arc second/100years

= 43.0" seconds of arc /century for MercurySolution:With m = constantThen d² r/dt² - θ'²r = - k/ r³ (1)And d (r²θ')/d t = 0 (2)From (2) d (r²θ')/d t = 0; r²θ' = hFrom (1), θ'² d² r/ dθ² - θ'²r = - k/ mr³And θ'² [d² r/ dθ² - r] = - k/ mr³And d² r/ dθ² - r = - (k/mh²) rAnd d² r/ dθ² - r [1 - (k/mh²)] = 0And r (θ, 0) = r (0, 0) e ỉ {√ [1 - (k/mh²)]} θ

From (2) d (r²θ')/d t = 0; r²θ' = hThen 2rr'θ' + r²θ'' = 0Dividing by r²θ'

We get 2 (r'/r) + (θ''/θ') = 0And 2 (r'/r) = - θ''/θ' = 2ỉ ω t

And r = r (0, 0) e ỉ {√ [1 - (k/mh²)]} θ e ỉ ω t

And θ' = θ' (θ, 0) e - 2ỉ ω t Or r = r (0, 0) e ỉ {√ [1 - (k/mh²)]} θ + ỉ ω t

And θ' = θ' (0, 0) e -2ỉ [{√ [1 - (k/mh²)]} θ + ω t]

And θ' = θ' (0, 0) e -2ỉ [{√ [1 - (k/mh²)]} θ + ω t]

And θ' = (θ' (0, 0) {cosine 2 [{√ [1 - (k/mh²)]} θ + ω t]- ỉ sine 2 [{√ [1 - (k/mh²)]} θ + ω t]}

And θ' - θ' (0, 0) = - 2 θ' (0, 0) sine² [{√ [1 - (k/mh²)]} θ + ω t]And δ θ' = - 2 θ' (0, 0) sine² [{√ [1 - (k/mh²)]} θ + ω t]If k = Gm M α (1 - ε²); h = 2π a b/TThen: k/mh² = Gm M a (1 - ε²)/m 4 π ² a² b²/T²And k/mh² = GM T² (1 - ε²)/4 π ² a b²; multiply by (a²/a²)Then [a² (1 - ε²)/ b²] [GM T²/4 π ² a³] = [GM T²/4 π ² a³]

Then δ θ' = - 2 θ' (0, 0)] sine² [{√ [1 - (GM T²/4 π ² a³)]} θ + ω t]Taking Kepler's: GM T²/4π²a³ = 1

Page 46



Then δ θ' = - 2 θ' (0, 0) sine² ω tAnd θ' (0, 0) = h/r² = 2πab/Ta² (1 - ε) ²

= 2πa²√ (1 - ε²)/Ta² (1 - ε) ² = 2π√ (1 - ε²)/T (1 - ε) ²And δ θ' = - 4π√ (1 - ε²)/ T (1 - ε) ² sine² ω tWith ω T = arc tan v/c << 1

Then δ θ' = - 4π/T√ (1 - ε²)/ (1 - ε) ² sine² arc tan (v/c) radians per TOr δ θ' = - 4π/T√ (1 - ε²)/ (1 - ε) ² (v/c) ² radians per TAnd δ θ' = - 4π/T√ (1 - ε²)/ (1 - ε) ² (v/c) ² [180/π] [36526] [3600] arc second/100 years

Or δ θ' = - 720 [36526/T] (3600) [√ (1 - ε²)]/ (1 - ε) ²] (v/c) ² arc second/100 yearsOr δ θ' = - 720 [36526/T] (3600) (1.552) (48.2/c) ² = 43.11 " arc second/100 yearsIf k = Gm (M + m) α (1 - ε²); h = 2π a b/TIf we take Newton’s G (M + m) T²/4π²a³ = 1

Then δ θ' = - 2 θ' (0, 0)] sine² [{√ [1 – [G (M + m) T²/4 π ² a³)]} θ + ω t]And G (M + m) T²/4π²a³ = 1And 1- G (M + m) T²/4π²a³ = 0Then δ θ' = - 2 θ' (0, 0) sine² ω tThen δ θ' = - 2 2 π √ (1 - ε²)/T (1 - ε) ² sine² ω t

= - 4 π √ (1 - ε²)/T (1 - ε) ² sine² ω tOr δ θ' = - 720 [36526/T] (3600) [√ (1 - ε²)]/ (1 - ε) ²] (v/c) ² arc second/100 yearsIf k = mh²; then δ θ' = - 2 θ' (0, 0) sine² ω tOr δ θ' = - 720 [36526/T] (3600) [√ (1 - ε²)]/ (1 - ε) ²] (v/c) ² arc second/100 yearsIf k = m²h²/M; then δ θ' = - 2 θ' (0, 0) sine² [{√ [1 - (k/mh²)]} θ + ω t]Become δ θ' = - 2 θ' (0, 0) sine² [{√ [1 - (m/M)]} θ + ω t]And (m/ M) << 1; t = 0

Or r = r (0, 0) e ỉ {√ [1 - (m/M)]} θ

Then r ≈ r (0, 0) e

ỉ [1 - (m/ 2M)]} θ

And r ≈ r (0, 0) e ỉ [(θ - φ)]

With φ = m/ 2M θTaking θ = 2 π Then φ = π m/ M radiansAnd φ = π m/ (M) [180/π] [36526/T] [3600] arc second/100 yearsIf k = m²h²/ (M + m)Then φ = π m/ (M + m) radiansAnd φ = π m/ (M + m) [180/π] [36526/T] [3600] arc second/100 yearsOr φ = π (m/ M) (180/ π) [36526/T] [3600] arc second/100 years

= 43.0344"/100 yearsOr φ = π m/(M +m) (180/ π) [36526/T] [3600] arc second/100 years

= 43.0344"/100 years

Or δ θ' = - 720 [36526/T] (3600) √ (1 - ε²)/ (1 - ε) ²] (v/c) ² arc second/100years

= 43.0"/100 yearsPage 47



Chapter eight: Nuclear gravityYukawa’s: – O)/O] δ θ’ 0: M r Yukawa travel is not physics but Alfred Nobel physicists’ stupidity

Nuclear Gravity F = (-GmM/r²) e k/r

With d² (m r)/dt² – (m r) θ'² = [-GmM/r²] e k/ r Nuclear gravity Equation (1)And (m²r²θ')/d t = 0 Kepler's Areal Velocity (2)

(2): d (m²r²θ')/d t = 0Then m²r²θ' = constant; if m is taken as constant then r²θ' = h

And (1): d² r/dt² - r θ'² = [-GmM/r²] e k/r

Let m r =1/uThen d r/d t = -u'/u²

= - (1/u²) (θ') d u/d θ= (- θ'/u²) d u/d θ= - h d u/d θ

And d² r/dt² = -hθ'd²u/dθ²= - hu² [d²u/dθ²]

With d² (m r)/dt² - (m r) θ'² = [-GmM/r²] e k/r Nuclear Gravity (1)

With e k/r ≈ 1+ k/r; k/r <<1And -hu² (d²u/dθ²) - (1/u) (hu²)² = -GMu² [1 + k u]; α m/M r << 1And (d²u dθ²) + (1 – GMk/h²) u = GM/h²And u = [GM/ h²]/ {(1 – GMk/h²) + A cosine [√ (1 - GMk/h²)] θ}And r = 1/u = 1/ {[GM/ h²]/ {[1 – GMk/h²] + A cosine {√ [1 – GMk/h²]} θ}

= [1 – GMk/h²]/ (M/ h²)]/ {1 + ε cosine {√ [1 - GMk/h²]} θWhere [1 – GMk/h²]/ (GM/h²) = a (1 – ε²)

48



And [1 – GMk/h²] = (GM/h²) a (1-ε²)And h² - GM k = G M a (1- ε²)

Then h²/GM – a (1- ε²) = k

And √ [1 – GMk/h²] =√ {[1 – (GM/h²) [(h²/GM) – a (1 - ε²)]}= √ {[1 – 1 + (GM/h²) a (1 - ε²)]}= √ [(GM/h²) a (1 - ε²)]= √ {[GMT²/4π²a4 (1 - ε²)] a (1 - ε²)]}= √ (GMT²/4π²a³)= 1; T²/ a³ = 4π²/ GM Kepler’s

Then, r = 1/u = (GM/ h²) + A cosine θIf, T²/ a³ = 4π²/ G (M +m) Newton’sThen, √ [1 – GMk/h²] = √ (GMT²/4π²a³) = √ [M/ (M + m)]= 1/ √ [1 + (m/M)] ≈ 1/ [1 + (m/2M)] = 1 – (m/ 2M)

And [1 – GMk/h²]/ (M/ h²)]/ {1 + ε cosine {√ [1 - GMk/h²]} θ= a (1- ε²)/ [1 + ε cosine {√ [1 – (GMk/h²)]} θ= a (1- ε²)/ {[1 + ε cosine [(1 – m/2M) θ]}= a (1- ε²)/ [1 + ε cosine (θ – Φ)]And 2 π Φ = 2 π (m/ 2M) = π (m/M)If Newton’s law were to be F = - Gm (M + m)/r²The 2 π Φ = 2 π [m/ 2(M + m)] = π [m/ (m + M)]

Nuclear Gravity (-GmM/r²) e (m α/ M r)

Abstract: Yukawa Gravity (-GmM/r²) e(m α/ M r)

or the nuclear gravity force is thecrudely approximated Newtonian gravity force (-GmM/r²) explains planetarymotion around the sun as a rotating ellipse with a rotation rate φ = [π m/(m + M)](180/π)(36526/T)(3600) = 43.03 seconds of an arc per century for the most talkedabout planet of mercury; m = 3.2 x 1024 kg; M = 2x1030 kg; T = 88days

With d² (m r)/dt² – (m r) θ'² = (-GmM/r²) e (m α/ M r) Gravity Force (1)And d (m²r²θ')/d t = 0 Kepler's Areal Velocity (2)

Then m²r²θ' = constant; if m is taken as constant then r²θ' = hAnd (1): d² r/dt² - r θ'² = -GmM/r² + Gm²α/r³

Let m r =1/uThen d r/d t = -u'/u² = - (1/u²) (θ') d u/d θ = (- θ'/u²) d u/d θ = - h d u/d θAnd d² r/dt² = -hθ'd²u/dθ² = - hu² [d²u/dθ²]-hu² [d²u/dθ²] - (1/u) (hu²)² = -G M u² [1 – (α m /M) u]; α m /M r << 1Or (d²u/ dθ²) + (1 – Gmα/h²) u = GM/h²And u = [GM/ h²]/[1 – Gmα/h²] + A cosine {√ [1 - Gmα/h²]}θ

Page 49

And r = 1/u = 1/ {[GM/ h²]/ [1 – Gmα/h²] + A cosine {√ [1 – Gmα/h²]} θ}





Chapter NineFrequency Games

What is the accumulated value of 2 π f per century for planet mercury seen fromEarth?

The angular frequency is ω = 2 π f How I would see ω of planet mercury turning around the sun from earth?The answer is there will be a frequency change of W = 2 π f [v* m - v*e]/v* e; radians per secondWhere v*e = Earth orbital velocity around the Sun = 29.8 km/secAnd vº e = Earth spin speed = 0.465 km/secAnd v* m = Mercury orbital velocity around the Sun = 47.9 km/secWith f = 1/T; f = frequency; T = Period = 88 daysIf W is wanted in degrees multiply by: 180/π If W is wanted in degree per century multiply by (180/π) x (36526 days/ T)If W is wanted in arc second per century multiply by(180/π) x (36526 days/ T) x 3600W = [2 π f [(v* m - v*e)/v* e] x (180/π) x [36526 days/ (T days)] x 3600With f = 1/T (seconds)W = [360 x 3600 x (36526/T (days)] [1/T (seconds)] [(v* m - v*e)/v* e]

W = [360 x 3600 x (36526/T (days)] [1/ 24 x 3600 x T (days)] [(v* m - v*e)/v* e]W = 15 x (36526/T² (days)] [(v* m - v*e)/v* e] [(I – O)/O] δ θ’ 0 =15 x (36526/T² (days)] [(v* m - v*e)/v* e]For MercuryW = 15 x [36526/ (88)²] [(47.9 – 29.8)/29.8] = 43.0 arc second per century

The conclusion is

With ω = 2 π f = 2 π /T angular frequency in event timeAnd ω (real time) = ω (event time) + Δ ωΔ ω = ω (real time) - ω (event time)= 2 π f [(v* m - v*e)/v* e]= 2 π f Z; Z = [(v* m - v*e)/v* e]

= red shift

And Δ ω = 2 π f (1 + Z)The Advance of Planet Mercury Perihelion is 2 π f Z = 2 π Z/ TΔ ω = (2 π/T) [(v* m - v*e)/v* e]

In arc seconds per century: Multiply by: (180/π) [36526/T (days)] (3600) And Δ ω = [2 π / T (seconds)] [(v* m - v*e)/v* e] x(180/π) [36526/T (days)] (3600);

T (seconds) = T days x 24x 3600 Δ ω = [2 π / T days x 24x 3600] [(v* m - v*e)/v* e] x

(180/π) [36526/T (days)] (3600)Δ ω = [15 x 36526 / T² (days)] [(v* m - v*e)/v* e] = 43

Page 51



Chapter Ten: Space – time unlimited stupidityVisual force: F = - Gm M/r² - Gm Mk/r³

With m [d² r/dt² - θ'²r] = - Gm M/r² - Gm Mk/r³ Visual Gravitational law (1)And d (r²θ')/d t = 0 Kepler's Areal Velocity Equation (2)

Gives an axial rotation rate of W = 15 x (36526/T² (days)] [(v* m - v*e)/v* e]

Boundary value LawWith d² (m r)/dt² - (m r) θ'² = - k/ r² Inverse square Gravitational (1)And d (m²r²θ')/d t = 0 Kepler's law (2)At Perihelion: d² r/d t² - r θ'² = - GM/r² = - r θ'²; d² r/d t² = 0Then r θ'² = GM/r²A quick answer by Newton would be: First θ' ² = [GM/r³]And ω² = [GM/r³] [(v* m - v*e)/v* e] ²

In arc sec / centuryThen ω = {[GM/r³]} 1/2 [(v* m - v*e)/v* e] [(180/π) (3600) (36526/Tm)

= 43"/century[(I – O)/O] δ θ’ 0 = {[GM/r³]} 1/2 [(v* m - v*e)/v* e] [(180/π) (3600) (36526/Tm)

Constant acceleration lawOr, r 1 /θ'² 1= r 2 /θ'²2 = constantOr, θ' 2= {√[r 2 / r 1]} θ' 1

And θ' 2 - θ' 1 = {[√ (r 2 / r 1)] - 1} θ' 1

Δ θ' = {[√ (r 2 / r 1)] - 1} θ' 1

This is the angular time delay and will be seen as angular visual IllusionThe angular speed is θ' = v/rFor Mercury: θ' = v/r = (47.9km/sec)/58,200,000 km = 0.000000843 radians/secIf you want the accumulation value in arc sec /century W", thenAnd W" = (v/r) (180/π) (3600) (26526/T) = angular velocity in arc sec per century.If it is measured for planet Mercury thenW" = (47.9/58,200,000) (180/π) (3600) (26526/88)

W"= 70.75 arc second per centuryOr, Δ W" = {[√ (r 2 / r 1)] - 1} W" (1)What is the angular visual Illusion for planet Mercury that would be seen whenmeasured from Earth with Earth location r (1) = Earth = 149.6 x 106

And r (2) = Mercury = 58.2 x 106

And W" (2) = - 70.75 arc sec /centuryΔ W" = {[√ (r 2 / r 1)] - 1} W" 1Δ W" = {{√ [149.6/58.2]} - 1} [-70.29] = 43.0" arc per century[(I – O)/O] δ θ’ 0 = {{√[r e / r m]} - 1} (v m /r m)] [(180/π) (3600) (26526/T)

Page 52



Constant Areal velocity Law

Or, r² 1 θ'1= r² 2 θ'2 = location x speed = constant = Areal velocity

Or, r 1 v 1= r 2 v2

Or, θ' 1= (r 2 / r 1)² θ' 2

And θ' 1 - θ' 2 = [(r 2 / r 1)² - 1] θ' 2

Δ θ' = θ' 1 - θ' 2 = [(r 2 / r 1)² - 1] θ' 2

Δ θ' = [(v 1 / v 2)² - 1] θ' 2

This is the angular time delay and will be seen as angular visual IllusionThe angular speed is θ' = v/rFor Mercury: θ' = v/r = (47.9km/sec)/58,200,000 km = 0.000000843 radians/sec

If you want the accumulation value in arc sec /century W", thenAnd W" = (v/r) (180/π) (3600) (26526/T) = angular velocity in arc sec per century.

If it is measured for planet Mercury thenW" = (47.9/58,200,000) (180/π) (3600) (26526/88)W"= 70.29 arc second per century

Or, Δ W" = [(v 1 / v 2)² - 1] W" (2)

What is the angular visual Illusion for planet Mercury that would be seen whenmeasured from Earth with Earth location r (1) = Earth = 149.6 x 106

And r (2) = Mercury = 58.2 x 106

And W" (2) = - 70.29 arc sec /century

Δ W" = [(v 1 / v 2)² - 1] W" (2)

Δ W" = [(v 1 / v 2)² - 1] (v m /r m)] [(180/π) (3600) (26526/T)

Δ W" = [(29.8 / 47.9)² - 1] [-70.75] = 43.0" arc per century

[(I – O)/O] δ θ’ 0

= [(v e / v m) ² - 1] (v m /r m)] [(180/π) (3600) (26526/T)

Page 53

No Force solution



Newton said there is gravity Force F = -GmM/r² whose solution is this

Fig 1. Newton’s gravitational law

With m [d² r/dt² - θ'²r] = 0 Zero force law equation (1)And d (r²θ')/d t = 0 Kepler's Areal Velocity Equation (2)Equation (2) r = r0 e í ω t; θ' = θ'0 e - 2 í ω t

Equation (1) - h² d² θ/ d u² - h² u³ = 0Or d² θ/ d u² + u = 0Then u = u0 e - í θ And r0 = r0 (0) e + í θ

Or, r = r0 (0) e í (θ + ω t) [h/ θ'0]½ e í (θ + ω t)

And θ' = θ'0 e - 2 í ω t

Δ θ' = - 2 θ'0 sine² ω t= - 2[2π /T] x [180/ π] [38526/T] [3600] sine² ω t= - 2 [2π /88 x 24 x 3600] x [180/ π] [38526/T] [3600] sine² ω t

= - 141.5 sine² ω tAnd ω t = arc tan [(r m - r e)/ (r m + r e)] ½

= arc tan [(149.6 – 58.2)/ (149.6 + 58.2)] ½

Δ θ' = - 141.5 sine² arc tan [(149.6 – 58.2)/ (149.6 + 58.2)] ½

= 43 arc seconds per century

Planet

r

Sun


PlanetOrbit T


LessEarthspeed

Spinspeedkm/sec


Mercury 58.2 88 47.9 18.1 .002 70.75

Venus 108.2 224.7 35.05 5.7 6.52 10.86Earth 149.6 365.26 29.8 .46511 4.1Mars 227.936 687 24.14 0.2411Jupiter 778.412 4333 13.06 12.6Saturn 1,426.725 10760 9.65 9.87Uranus 2,870.97 30690 6.80 2.59Neptune 4,498 60180 5.43 2.68Pluto 5906.4 90730 4.74



Newton’s mathematically wrong [(I – O)/O] δ θ’ 0 =(-720x36526x3600/88) (1.552) (48.14/300,000) ² arc sec per century

= 43This particular equation structure is the basis of stars studying. Originally, I derived

it from Arabic real time physics literature.A visual Illusion along the line of sight is constructed as follows:Instead of seeing r0 we see r0 cosine arc tan (v/c) and perpendicular to the lineof sight we see r0 sine arc tan (v/c)Or r = r0 [cosine arc tan (v/c) + í sine arc tan (v/c)]

Or r = r0 e í arc tan (v/c)

Or r = r0 e í ω t

And areal velocity law gives the same resultsIf r² θ' = hThen differentiating with respect to timeThen d (r² θ')/ d t = d h/ d tAnd 2 r r’ θ’ + r² θ’’ = 0Or 2 (r’ /r) = - (θ’’/θ’)


And θ’ = θ’ 0 e – 2 í ω t




And θ' (1) = {[e í 2 ω t] θ' (0)


= [cosine 2 ω t + í sine 2 ω t] θ' (0)Δ θ’ (x) = [cosine 2 ω t] θ' (0)Δ θ’ (x) = [1 – 2 sine² ω t] θ' (0)Δ θ’ (x) - θ' (0) = - 2 θ' (0) sine² ω tΔ W = Δ θ’ (x) - θ' (0) = - 2 θ' (0) sine² ω t

= -2(2π) [√ (1-ε²)]/T (1-ε) ²] sine² ω tAnd θ' (0) = h/r² (0) = 2 π a b/T a² = 2π√ (1-ε²)]/T (1-ε) ²

Δ W = - 4 π) [√ (1-ε²)]/T (1-ε) ²] sine² ω tIf this apsidal motion is to be found as visual effects, then



With, v ° = spin velocity; v* = orbital velocityAnd v/c = (v* + v°)/c = tan ω tΔ W = -4 π [√ (1-ε²)]/T (1-ε) ²] sine² {Inverse tan [(v* + v°)/c]} radiansMultiplication by 180/π to change to degreesΔ W ° = (-720/T) {[√ (1-ε²)]/ (1-ε) ²} sine² {Inverse tan [(v* + v°)/c]} Degrees

And multiplication by 1 century = 36526 days and using T in daysW° (ob) = (-720x36526/Tdays) {[√ (1-ε²)]/ (1-ε) ²} xsine² {Inverse tan [(v* + v°)/c]} degrees/100 years

Page 55

Abstract: light measurements are done along the line of sight and we measure lightprojections to our eye. Meaning, that we do not measure distance r but we measure rcosine arc tan (v/c) when light is used and as a consequence instead of measuring tiT we measure T cosine arc tan (v/c) and here is the experimental proof of it.

Your eyes

A000 00000 00 0 0 0 00 0 0 0 00 0 0 0 00 0 θ (2) 0 0 00 θ (1) 0 0 θ (3) 0 0

0 0 0 0 00 0 0 0 00 0 0 0 00 0 0 0 00 0 0 0 0B------------------------- 0 --------------- 0 ------------- 0

1 2 3

The projections of light is what we measure and the projection of 1and 2 and 3 is ABIf the angle between ray 1 and AB is θ (1)

If the angle between ray 1 and AB is θ (2)If the angle between ray 1 and AB is θ (3) Then C (1) cosine θ (1) = C (2) cosine θ (2) = C (3) cosine θ (3) = c = AB You want experimental proof?Here is my iron clad proof of my theory: This is using the lightprojections to be equal c then the advance of perihelion and stars tosolve mercury Venus and DI Herculis binary stars better than all is

If an object at location A sends light signals in all directions at time at t = 0 whereB1 is;



And B1 is moving to B2 then the projection of AB2 of AB1 is measured. AB1 istheorized and AB2 is measured; or AB2 = AB1 cosine θAnd θ = arc tan (v/c)B1B2 /AB1 = sine θ; AB2/AB1 = cosine θ; B1B2/AB2 = tan θInstead of measuring time t we theorize time t and we measure time Γ = t cosine θ

Page 56

A Light V E L O C I T Y B2O O O O O O O O O O

O θ C O

O OO OO V O

O OO O

O OO O

OB1

Γ = t cosine arc tan (v/c) = t {1- 2 sine² {[arc tan (v/c)]/2}}

Γ - t = - 2 t sine² {[arc tan (v/c)]/2}With r2θ’ = h and 1/T= θ’’/θ’ = - 2r’/r = 2/t

Or T = t/2 or the time measurements changes are twice period changesOr (Γ – t)/2 = - t sine² {[arc tan (v/c)]/2} is the time delays for periods

With t = 1 century and t in arc seconds is 15 times time seconds then

(Γ – t)/2 = - 15 T sine² {[arc tan (v/c)]/2}; T = One centuryWith v = 47.9 (mercury) – 29.8 (Earth) =18.1 km/sec

(Γ – t)/2 = - 15 (36526) sine² {[arc tan (18.1/300,000)]/2] = 43

= 15 x (36526/T² (days)] [(r m – r e)/ r e] = 43

= 15 x (36526/T² (days)] [(v m T m – v e T e)/ v e T e] = 43

= 15 x (36526/T² (days)] [(v m – v e)/ v e] = 43

= 15 x (36526/T² (days)] [(Tm / Te) 2/3 – 1] = 43

Or, Center of mass gravity equation

[(I – O)/O] δ θ’ 0 = [π m/ (m + M)] (180/ π) (36526/ T m) (3600)] = 43



Page 57

Mr Laplace yes you are deleted

The solution to F = -GmM/r² is notr = [a (1-ε²)/ (1+ε cosine θ)] and it is time you get corrected


"Apparent advance of perihelion"

Or, Boundary value law[(I – O)/O] δ θ’ 0 == {[GM/r³]} 1/2 [(r m – r e)/ r e] [(180/ π) (3600) (36526/ T m) = 43

= {[GM/r³]} 1/2 [(v m – v e)/ v e] [(180/ π) (3600) (36526/ T m) = 43

= {[GM/r³]} 1/2 [(Tm / Te) 2/3 – 1] [(180/π) (3600) (26526/T m)] = 43

= {[GM/r³]} 1/2 [(v m T m – v e T e)/ v e T e] [(180/π) (3600) (26526/T m) = 43

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Chapter Eleven

Arabs real time physics in outer SpaceThe problems Einstein and all others can not solveApparent Apsidal motion of binary (two) stars

This is the solution to the 150 years apsidal motion puzzle that is not solvable byspace-time physics or any said or published physics including 500 years of Modernphysics and 500,000 modern physicists. Binary stars apsidal motion or "Apparent"rate of orbital axial rotation is a visual effect along the line of sight of movingobjects applied to the angular velocity at Apses. From the thousands of close binarystars astronomers picked a dozen sets of binary stars systems that would be a

good test of relativity theory and modern physics collected data for all of pastcentury and relativity theory failed every one of them. This rate of "apparent" axialrotation is given by this new equationW° (ob) = (-720x36526/T) {[√ (1-ε²)]/ (1-ε) ²]} (v* + v°/c) ²degrees/100 yearsT = period; ε = eccentricity; v° = spin velocity effect; v*= orbital velocity effects The simplest problem in physics that all 500 years modern physics and500,000 modern physicists could not solve by any physics:

1 – As Camelopardalis2 – DI Herculis

3 – V1143 Cygni4 – V 541 Cygni5 - AI Hydra6 - V 731 Cephei7 - SW Canis Majoris8 - NV Canis Majoris9 - GG Orion10- CM Draconis11- VV PYX12 – EW Oriomis

13- V1147 Sagittari14 – PSR 1913 + 1612 – PSR 0737 – 3039Solution: Location r = r r (1) ; Velocity v = r' r (1) + r θ' θ (1)

Acceleration γ = (r" - rθ'²) r (1) + (2r'θ' + r θ") θ (1)

S = m r; State = mass x distanceP = d S/ d t = d (m r)/d t = m (d r/d t) + (d m/d t) rVelocity = v = (d r/d t); mass rate change = m' = (d m/d t)P = m v + m' r; Momentum = change of state = change in location or change inmassF = d P/d t = d² S/d t² = d [m (d r/d t) + (d m/d t)]/d t

= m d² r/d t² + (d m/d t) (d r/d t) + (d m/d t) (d r/d t) + (d² m/d t) ² rPage 59





What astronomers saw was not an ellipse but a rotating ellipse like the ellipsebelow wth rotating angle ψ

Page 61

M

m

θ

M

ψ

m

θ



When the areas size A are sliced equally it was found that the times spent by planetsorbiting around the Sun and making areas A each are equal also.Or, r² (0) θ' (0) = r² (1) θ' (1) = r² (2) θ' (2) = r² (3) θ' (3) = --

= location² x [angular speed] = constant= Areal velocity

If r² θ' = hThen differentiating with respect to timeThen d (r² θ')/ d t = d h/ d tAnd 2 r r’ θ’ + r² θ’’ = 0Or 2 (r’ /r) = - (θ’’/θ’)


And θ’ = θ’ 0 e – 2 í ω t




And θ' (1) = {[e í 2 ω t] θ' (0)


= [cosine 2 ω t + í sine 2 ω t] θ' (0)Δ θ’ (x) = [cosine 2 ω t] θ' (0)Δ θ’ (x) = [1 – 2 sine² ω t] θ' (0)

Δ θ’ (x) - θ' (0) = - 2 θ' (0) sine² ω t

Δ W = Δ θ’ (x) - θ' (0) = - 2 θ' (0) sine² ω t= -2(2π) [√ (1-ε²)]/T (1-ε) ²] sine² ω tAnd θ' (0) = h/r² (0) = 2 π a b/T a² = 2π√ (1-ε²)]/T (1-ε) ²

Δ W = - 4 π) [√ (1-ε²)]/T (1-ε) ²] sine² ω t

If this apsidal motion is to be found as visual effects, thenWith, v ° = spin velocity; v* = orbital velocityAnd v/c = (v* + v°)/c = tan ω t

Δ W = -4 π [√ (1-ε²)]/T (1-ε) ²] sine² {Inverse tan [(v* + v°)/c]} radians

Multiplication by 180/π to change to degrees

Δ W ° = (-720/T) {[√ (1-ε²)]/ (1-ε) ²} sine² {Inverse tan [(v* + v°)/c]} DegreesAnd multiplication by 1 century = 36526 days and using T in days

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W° (ob) = (-720x36526/Tdays) {[√ (1-ε²)]/ (1-ε) ²} xsine² {Inverse tan [(v* + v°)/c]} degrees/100 years

Astronomy re - written

W° (calculated) = (-720x36526/T) {[√ (1- ε²)]/ (1- ε) ²]} [(v° + v*)/degrees/100 years

1- As Cameloppardalis: Binary stars SystemAS Cam Data T=3.431; r (m) =0.1499; m=3.3 M (0); M=2.5 M (0)

R (m) =2.57 R (0); [v° (m), v° (M)] = [40, 30]; ε = 0.1695; 1- ε = 00.8305R (M) = 2.5 R (0); r (M) =0.1111; m + M=5.8 M (0); G=6.673x10-11

M (0) = 2 x 1030 kg; R (0) = 0.696x109m;The circumference of an ellipse: 2πa (1 - ε²/4 + 3/16(ε²)²- --.)≈ 2πa (1-ε²/4); R =a (1-ε²/4)

Finding orbital velocitiesFrom Newton's inverse square law of an ellipse motion applied to a circular orbitgives the following: m v²/ r (cm) = GmM/r²Planet --- r (cm) ----- Center of mass ------- r (CM) --------- Mother SunPlanet ------------------- r -------------------------------------- Mother SunCenter of mass law m r (cm) = M r (CM); m = planet mass; M = sun massAnd r (cm) = distance of planet to the center of mass

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Primary →Secondary ↓

v°(p) ↑ v* (p)↑ v° (p) ↑v* (p)↓ v° (p) ↓ v* (p) ↑ v° (p) ↓V* (p) ↓

v°(s) ↑ v* (s)↑ Spin=[↑,↑][↑,↑]=orbit

[↑,↑][↓,↑] [↓,↑][↑,↑] [↓,↑][↓,↑]

Spin results v°(p) + v°(s) v°(p) + v°(s) - v°(p) + v°(s) -v°(p) + v°(s)Orbit results v*(p) + v*(s) -v*(p) + v*(s) v* (p) + v*(s) -v* (p) + v* (s)Examples AS CAMv° (s) ↑v* (s)↓ [↑,↑][↑,↓] [↑,↑][↓,↓] [↓,↑][↑,↓] [↓,↑][↓,↓]Spin results v°(p) + v°(s) v°(p) + v°(s) -v°(p) + v°(s) -v°(p) + v°(s)Orbit results v*(p) - v*(s) -v*(p) - v*(s) v*(p) - v*(s) -v* (p) - v* (s)

Examplesv° (p) ↓ v*(s) ↑ [↑,↓][↑,↑] [↑,↓][↓,↑] [↓,↓][↑,↑] [↓,↓][↓,↑]Spin results v°(p) - v°(s) v°(p) - v°(s) -v°(p) - v°(s) -v°(p) - v°(s)Orbit results v*(p) + v*(s) -v*(p) + v*(s) v*(p) + v*(s) -v* (p) + v* (s)Examples AS CAM

v° (s) ↓V*(s) ↓ [↑,↓][↑,↓] [↑,↓][↓,↓] [↓,↓][↑,↓] [↓,↓][↓,↓]Spin results v°(p) - v°(s) v°(p) - v°(s) -v°(p) - v°(s) -v°(p) - v°(s)Orbit results v*(p) - v*(s) -v*(p) - v*(s) v*(p) - v*(s) -v* (p) - v* (s)Examples AS CAM



And r (CM) = distance of sun to center of massAnd r (cm) + r (CM) = r = distance between sun and planetSolving to get: r (cm) = [M/ (m + M)] rAnd r (CM) = [m/ (m + M)] r

Then v² = [GM r (cm)/ r²] = GM²/ (m + M) rAnd v = √ [GM²/ (m + M) r = a (1-ε²/4)]Planet orbital velocity or primary velocity:

And v* (m) = v (m) = √ [GM²/ (m + M) a (1-ε²/4)]R =a (1-ε²/4)

Calculations: (1- ε²/4) = 0.9928[√ (1-ε²)]/ (1-ε) ² = 1.43With a = [R (m) /r (m)] = (2.57/0.1499) (0.696x109) = 11.9327x109

And v* (m) = √ [GM²/ (m + M) a (1- ε²/4)] = 110km/sec= √ [6.673x10-11 (2.5)² (2 x 1030) / (5.8) 11.932x109 (0.9928)] = 110.178km/sec

And v* (M) = √ [GM²/ (m + M) a (1- ε²/4)]= √ [6.673x10-11 (3.3)² (2 x 1030) / (5.8) 11.932x109 (0.9928)] = 145.435 km/sec

Spin: v° = 40 + 30=70km/secAnd v* (e) = v* Earth = 29.8 km/secAnd vº (e) = 0.465 km/secThen v* + v °= v* (m) + v* (M) + v* (e) + vº (m) + v° (M) + vº (e)

= 110.178 + 145.435 + 70 + 29.8 – 0.465 = 355 m/sec

[√ (1-ε²)]/ (1-ε) ² = 1.43; T = 3.431days

W°= (-720x36526/T) x {√ [(1-ε²)] (1-ε) ²} {[v* + v°]/c} ²

W°= (-720x36526/3.431) x (1.43) (355/ 300,000) ² = 15.0°/centuryDr Guinan and DR Maloney 1989: W°= 15°/century 1989DR Khailullin and Dr Kozyreva: 1983 W º= 14.6 °/centuryEinstein: 44.3º/ century

2 - Binary stars System: DI Her Apsidal Motion SolutionDI Her Apsidal motion solution:Data: T=10.55days r(m) = 0.0621 m=5.15M(0) R(m)=2.68R(0)

[v°(m),v°(M)]=[45,45]And ε = 0.4882; r (M) = 0.0574 M=4.52 M (0) R (M) =2.48; m + M=9.67 M (0)

L = 2000 +/- 200 Ly

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Calculations1- ε = 0.5118; (1-ε²/4) = 0.94; [√ (1-ε²)] / (1-ε) ² = 3.33181; 1 + ε = 1.4882;G=6.673x10-11; M (0) = 1.98892x19^30kg; R (0) = 0.696x109m

V* (p) = √ [GM²/ (m + M) a (1-ε²/4)] = 99.88 km/secV* (s) = √ [Gm²/ (m + M) a (1-ε²/4)] = 113.8km/sec

A- Apsidal motion is given by this formula:W° (cal) = (-720x36526/T) {[√ (1-ε²)]/ (1-ε) ²]} [(v° + v*)/c] ² degrees/100years And v° = - 45 km/s - 45 km/sec = 90km/secNow let us calculate v* (cm) = ∑m v/∑m = 106.38km/secWith v* = 2 v*(cm) = 212.76 km/secAnd v° = -90 km/secThen v* + v° = 212.76 - 90 = 122.76 km/sec andW° (cal) = (-720x36526/T) {[√ (1-ε²)]/ (1-ε) ²} sine² [Inverse tan122.76/300,000]

= (-720x36526/10.55) (3.33181) (122.76/300,000)²W° (cal) = 1.39°/centuryWith σ = √ {∑ [v* - v* (cm)] ²/2}

= √ {[106.36 - 99.88]²/2 + [106.36 - 113.8]²/2} = 6.975 km/secThen W° (cal) = 1.39°/century +/- 0.16Observed 2004: 1.39° +/- 0.3°/century; Relativity: 4.27°/century

B - W° (cal) = (-720x36526/T) {[√ (1-ε²)]/ (1-ε) ²]} [(v° + v*)/c] ² degrees/100yearsWith v° = - 45 km/s + 45 km/sec = 0 km/secAnd v* = v* (cm) = ∑m v/∑m = 106.38km/sec

W° (cal) = (-720x36526/10.55) (106.38.300, 000) ² degrees/100 yearsW° (cal) = 1.044 degrees/centuryC - V* (p) = √ [GM²/ (m + M) a (1-ε²/4)] = 99.88 km/sec

With v* x √ (1-ε²/4)/√ (1-ε) = 99.88 √ (.94)/√ (0.5118) = 135.36

And v* x √ (1-ε²/4)/√ (1+ ε) = 99.88 √ (.94)/√ (1.4882) = 79.38K (A) = [(135.36 + 79.38)/2] = 107.37 km/secV* (s) = √ [Gm²/ (m + M) a (1-ε²/4)] = 113.8 km/sec

With v* x √ (1-ε²/4)/√ (1-ε) = 113.8 √ (.94)/√ (0.5118) = 154.2254 km/secAnd v* x √ (1-ε²/4)/√ (1+ ε) = 113.8 √ (.94)/√ (1.4882) = 90.44312 km/secK (B) = 122.3342 km/sec

V* = [m K (A) + M K (B)]/ (m + M) = 114.3646 km/secOr v* = [K (A) + K (B)]/2 = 114. 85 km/sec; with v* = 114.85

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W° (cal) = (-720x36526/T) {[√ (1-ε²)]/ (1-ε) ²} sine² [Inverse tan114.85/300,000]= (-720x36526/10.55) (3.33181) (114.85/300,000)²

= 1.22° degrees/ centuryObserved: 1.24° degree/century +/- 0.05°

References: Go to Smithsonian/NASA website SAO/NASA and type:1- Apsidal motion of DI Her: Dr Edward Guinan and Dr Frank Maloney; 1985.2- New Apsidal Motion of DI Her: Dr Edward Guinan and Dr Frank Maloney; 1994.3- D. YA. Martynov; and KH. F. Khaliulullin 19804- Petrie et al.19675- Petrova - Ovlav Apsidal motion catalogue6- Riazi 20037- Maloney Guinan 2004

3 - V1143 Cgyni Apsidal Motion Solution

V1143 Cgyni dataT= 7.641days; r (m) = 0.059; m =1.391 M (0); R (1) =1.346R (0); ε = 0.54And [v ° (m), v° (M)] = [18, 28]; r (M) = 0.058; M=1.347 M (0)

Distance [38 +/- 2 parsec] = 123.956 +/- 6.524 LyCalculationsWe have 1- ε = 0.46 1- ε²/4=0.9721 R (0) = 0.696x109mWith a = [R (1)/r (m)] R (0) = 15.87823729x10^9m; 1+ ε = 1.54With v (p -perihelion) = √ [GM²/ (m + M) a (1- ε)] = 110 km/secAnd v (p- aphelion) = √ [GM²/ (m + M) a (1+ε)] = 60 km/secK (A) = (110 + 60)/2 = 170/2 = 85km/secWith v (s - perihelion) = √ [Gm²/ (m + M) a (1-ε)] = 113.6 km/secAnd v (s - aphelion) = √ [Gm²/ (m + M) a (1+ε)] = 62 km/secK (B) = (113.6 + 62)/2 = 175.6/2 = 87.8km/sec

With v (1) = √ [GM²/ (m + M) a] = 74.632 km/secAnd v (2) = √ [Gm²/ (m + M) a] = 77.0699 km/secWhen spinning on opposite directions

1- With v° [21, 28] = 28 - 21 = 72- With v° [18, 28] = 28 - 18 = 103- Taking average 10 + 7/2 = 8.5

With v (m) = √ [GM²/ (m + M) a (1-ε²/4)] = 77.5126 km/sAnd v (M) = √ [Gm²/ (m + M) a (1-ε²/4)] = 80.00448 km/s

Also, [√ (1-ε²)]/ (1-ε) ² = 3.977622971Page 66



Now:With 1- v° + v* = 157.51648km/sec - 10 km/sec = 147.51648km/secAnd 2- v° + v* = 157.51648km/sec - 8.5 km/sec = 149.01648km/sec

And 3- v° + v* = 157.51648km/sec - 7 km/sec = 150.51648km/sec

W° (obo) = (-720x36526/T) x {[√ (1-ε²)]/ (1-ε) ²} {[v* + v°]/c} ²

1- W°/century= (-720x36526/7.641) (3.977622951)(147.51648/300,000)²=3.31°/century2- W°/century= (-720x36526/7.641) (3.977622951)(149.01/300,000)²=3.3778°/century3- W°/century= (-720x36526/7.641) (3.977622951) (150.51648/300,000)² =3.44614561°/century

With v* = 2 v* (cm) = 157.4770 km/secAnd v ° = v° (p) - v° (s) = 21 - 28 = -7 km/secThen v* + v ° (p) = 157.477 - 7 = 150.477 km/sec

W° /century= (-720x36526/7.641) (3.977622951)(150.477/300,000)²=3.44°/centuryObserved values are: W° = 3.393987698°/century; W° = =3.489592985Average observed: 3.44°/ century

References:

1-Geminez and Margrave, 1985[0.00071°/cycle] = [1 century = 36526days/7.641days] = 3.393987698°/century 2- Anderson and Nordstrom and Garcia and Geminez 1987: 0.00073°/cycle [0.00073°/cycle] = [1 century = 36526days/7.641days] = 3.489592985°/century

Relativity theory: 4.254435283°/ century = 0.00089°/cycle

4- V541Solution: Apsidal motion catalogue

W° (cal) = (-720x36526/T) {[√ (1-ε²)]/ (1-ε) ²} [(v°+ v*)/c] ² degrees/100 yearsT = 15.3379days; r (m) = 0.0440 m = 2.4 M (0) R (m) = 1.88 R (0)

And [v°(m),v°(M)]= [24±2,24±2]And ε = 0.479 r (M) =0.0425 M=2.4 M (0) R (M) =1.79 R (0)

With 1- ε = 0.521 1-ε²/4=0.94263975; [√ (1-ε²)]/ (1-ε) ² = 3.2339

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And a = [R (m) /r (m)] R (0) = (1.88/0.0440)0.696x10^9m = 29.73818182x10^9mThen a (1-ε²/4) = 28.03x10^9mAnd v (m) = √ [GM²/ (m + M) a (1-ε²/4)] = 75.5883km/sec; v° (m) =24

And v (M) = √ [Gm²/a (m + M) (1-ε²/4)] = 75.883km/sec; v° (M) =24With v°=24 + 24= 44km/secAnd v* = 151.1766km/secWith v* + v°= 151.1766 - 48 = 103.1766km/secW° (ob) = (-720x36526/T) {[√ (1-ε²)]/ (1-ε) ²]} {[v* + v°]/c} ²W° (ob) = (- 720 x 365226/15.3379) (3.2339) (103.1766/300,000)²W° (ob) = 0.65°Notice: [v° (m), v° (M)] = [24 ± 2, 24 ± 2]If v° (m) = v° (M) = 24 + 2 = 26Then v* + v°= 151.1766 - 52 = 99.1766km/secAnd W° (ob) = (- 720 x 365226/15.3379) (3.2339) (99.1766/300,000)²W° (ob) = 0.60°/centuryObserved is W°= 0.60° +/ -0.1/century Lacy = [0.5°; 0.7°]

Relativity: W° = 0.97°/century

1- Apsidal motion of V541Cgyni Lacy 1989

5 - AI Hydra apsidal motion puzzle solution

W° (cal) = (-720x36526/T) {[√ (1-ε²)]/ (1-ε) ²} [(v°+ v*)/c] ² degrees/100 yearsAI Hydra Apsidal motion solution:Data: T=8.29days r(m) = 0.1418 m=2.15M(0) R(m)=3.92R(0)

[v°(m),v°(M)]=[28,27]; and ε = 0.0.23; r (M) = 0.1002 M=1.98 M (0) R (M)

=2.77(0); m + M=4.13 M (0); L = 575 +/- 15 Ly

Calculations1-ε = 0.77; (1-ε²/4) = 0.986775; [√ (1-ε²)] / (1-ε) ² = 1.6414G=6.673x10^-11; M (0) = 1.98892x19^30kg; R (0) = 0.696x10^9mThen a = [R (m) / r (m)] = 19.24062059 x 10 ^ 9 m

V (m) = √ [GM²/ (m + M) a (1-ε²/4)] = 81.11439578 km/secV (M) = √ [Gm²/ (m + M) a (1-ε²/4)] = 88.11km/sec

Apsidal motion is given by this formula:

W° (ob) = (-720x36526/T) {[√ (1-ε²)]/ (1-ε) ²]} [(v° + v*)/c] ² degrees/100years

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W° (obo) = (-720x36526/T) x {[√ (1-ε²)]/ (1-ε) ²} {[v* + v°]/c} ²W°/century= (-720x36526/6.068567) (1.033694356)(259.7856266 /300,000)²=2.91°/century

W°/century = 3.35914177°/century = 0.0335914177°/year

U = 360/0.0335914177° = 10717 years

Observed values are U = 10000 +/- 2500

References: 1- Absolute dimensional and apsidal motion of V731CepV. Batkis; M.Zejda; I. Bulut; M.Wolf; S. Bilir; H. Bakis; O.Demircan: J.w.Lee:M.Slechta: B. Kucerova. 2008

7 - NV CMa Binary stars apsidal motion table

8 - NV CMa apsidal motion solution:

Data: T=1.885159 days; ε = 0; v* (p) = 128.55 km/sec; v* (s) = 130.87 km/sec[√ (1-ε²)] / (1-ε) ² = 3.33181; v° (p) = 51.7 km/sec and v° (s) = 52.4 km/secApsidal motion is given by this formula:W° (ob) = (-720x36526/T) {[√ (1-ε²)]/ (1-ε) ²]} [(v° + v*)/c] ² degrees/100years

With v* = v* (p) + v*(s) = 259.42 km/sec and v°= v° (p) + v° (s) = 104.1And v* + v° = 363.52 km/sec

W° (observed) = (-720x36526/T) {[√ (1-ε²)]/ (1-ε) ²}sine² [Inverse tan 363.52/300,000]

= (-720x36526/1.885159) (1) (363.52/300,000)²= 20.48333818°/century = 0.2048333818°/year

U = 360°/0.2048333818°/year;

U = 1757. 5 years

References: Go to Smithsonian/NASA website SAO/NASA and type:Absolute dimensions NV CMa; Kaluzny, J; Pych, W; Rucinski, S. M; Thompson, I.B

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Relativity theory coffin nail # 8 SW Canis Majoris

W° (cal) = (-720x36526/T) {[√ (1-ε²)]/ (1-ε) ²]} [(v° + v*)/c] ² degrees/100years

T = period = 10.09 days; ε = eccentricity = 0.3179

And v° = spin velocity effect = v° (p) + v°(s) = 57km/sec

And v*= orbital velocity effect = v*(p) + v* (s)= 80.5 + 87.8 = 168.3 km/sec

For SW Canis Majoris: v* + v° = 225.3km/sec

W° (observed) = 2.99565967°/century = 0.0299565967°

U = 360/ 0.0299565967= 12017years

U (observed) = 12,000 yearsEinstein and space-timers 14,000 years SW Canis Majoris Binary stars

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v°(s) ↑ v* (s)↑ Spin=[↑,↑][↑,↑]=orbit

[↑,↑][↓,↑] [↓,↑][↑,↑] [↓,↑][↓,↑]

Spin results v°(p) + v°(s) v°(p) + v°(s) - v°(p) + v°(s) -v°(p) + v°(s)Orbit results v*(p) + v*(s) -v*(p) + v*(s) v* (p) + v*(s) -v* (p) + v* (s)Examples Sw Canis Majorisv° (s) ↑v* (s)↓ [↑,↑][↑,↓] [↑,↑][↓,↓] [↓,↑][↑,↓] [↓,↑][↓,↓]Spin results v°(p) + v°(s) v°(p) + v°(s) -v°(p) + v°(s) -v°(p) + v°(s)Orbit results v*(p) - v*(s) -v*(p) - v*(s) v*(p) - v*(s) -v* (p) - v* (s)

Examplesv° (p) ↓ v*(s) ↑ [↑,↓][↑,↑] [↑,↓][↓,↑] [↓,↓][↑,↑] [↓,↓][↓,↑]Spin results v°(p) - v°(s) v°(p) - v°(s) -v°(p) - v°(s) -v°(p) - v°(s)Orbit results v*(p) + v*(s) -v*(p) + v*(s) v*(p) + v*(s) -v* (p) + v* (s)Examplesv° (s) ↓V*(s) ↓ [↑,↓][↑,↓] [↑,↓][↓,↓] [↓,↓][↑,↓] [↓,↓][↓,↓]Spin results v°(p) - v°(s) v°(p) - v°(s) -v°(p) - v°(s) -v°(p) - v°(s)Orbit results v*(p) - v*(s) -v*(p) - v*(s) v*(p) - v*(s) -v* (p) - v* (s)Examples SW Canis majoris



SW CMa apsidal motion solution:

Data: T=10.09 days; r (m) = 0.0942; m = 2.22 M (0); R (m) = 3.01R (0); ε = 0.3179And r (M) = N/A M = 2.03 M (0) R (M) =2.46 R (0); m + M = 4.25 M (0)

And [v° (m), v° (M)] = [30+/-2, 27+/-3]K (1) = 80.5; K (2) = 87.8Calculations

1-ε = 0.6821; (1-ε²/4) = 0.974734898[√ (1-ε²)] / (1-ε) ² = 2.037835646

G=6.673x10^-11; M (0) = 1.98892x19^30kg; R (0) = 0.696x10^9mThen a = [R (m) / r (m)] = 22.23949045 x 10 ^ 9 m

V* (p) = √ [GM²/ (m + M) a (1-ε²/4)] = 77.26298km/sec

V* (s) = √ [Gm²/ (m + M) a (1-ε²/4)] = 84.4944913km/sec

And v* = v* (p) + v* (s) = 161.7574713 km/secWith v° = v° (p) + v° (s) = 30 + 27 = 57 km/sec

And, v* + v° = 218.7574713km/sec

Apsidal motion is given by this formula:W° (ob) = (-720x36526/T) {[√ (1-ε²)]/ (1-ε) ²]} [(v° + v*)/c] ² degrees/100years

W° (ob) = (-720x36526/T) {[√ (1-ε²)]/ (1-ε) ²} sine² [Inverse tan218.7574713/300,000]

= (-720x36526/10.09) (2.037835646) (218.7574713/300,000)²= 2.8242°/ century = 0.026242/yr

U = 360/ 0.026242 = 12747 yearsTaking: v* + v° = 80.5 + 87.8 +57 = 225.3 km/sec

W° (ob) = (-720x36526/T) {[√ (1-ε²)]/ (1-ε) ²}Sine² [Inverse tan 225.3 /300,000]= (-720x36526/10.09) (2.037835646) (218.7574713/300,000)²= 2.995659677°/ century = 0.0299565967°/yr

U = 360/ 0.0299565967 = 12017 years NahhasU (observed) = 12,000 years

References: Go to Smithsonian/NASA website SAO/NASA and type:1- Lacy Apsidal motion Canis Majoris 1997

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Chapter TwelveArabs real time physics in outer Space II

A- Arabs Binary stars and Binary Pulsar apsidal motion2009 total collapse of general relativity theory; CD Draconis Binary stars

10 – 2009 CD Draconis apsidal motion Table:Data: T=1.268389985days; m = 0.231 M (0); M = 0.2141 M (0); a = 3.7634 R (0); ε =0.0051And [v° (p); v° (s)] = [9.5 +/- 1; 10.0 +/- 1]Einstein and space – timers: W° = 1.91x10-3 /dayCalculationsm + M = 0.4451 M (0)

1-ε = 0.9949; (1-ε²/4) = 0.99993498; [√ (1-ε²)] / (1-ε) ² = 1.01G=6.673x10-11; M (0) = 1.98892x1030kg; R (0) = 0.696x10 9mCalculationsWith v* (p) = √ [GM²/ (m + M) a (1-ε²/4)] = 72.436 km/secAnd v* (s) = √ [Gm²/ (m + M) a (1-ε²/4)] = 78.153 km/secAnd v° (p) = 9.5 km/sec; v° (s) = 10 km/secThen v* (p) + v* (s) + v° (p) + v° (s) = 170.117 km/sec

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v°(s) ↑ v* (s)↑ Spin=[↑,↑][↑,↑]=orbit

[↑,↑][↓,↑] [↓,↑][↑,↑] [↓,↑][↓,↑]

Spin results v°(p) + v°(s) v°(p) + v°(s) - v°(p) + v°(s) -v°(p) + v°(s)Orbit results v*(p) + v*(s) -v*(p) + v*(s) v* (p) + v*(s) -v* (p) + v* (s)Examples CD Draconisv° (s) ↑v* (s)↓ [↑,↑][↑,↓] [↑,↑][↓,↓] [↓,↑][↑,↓] [↓,↑][↓,↓]Spin results v°(p) + v°(s) v°(p) + v°(s) -v°(p) + v°(s) -v°(p) + v°(s)Orbit results v*(p) - v*(s) -v*(p) - v*(s) v*(p) - v*(s) -v* (p) - v* (s)Examplesv° (p) ↓ v*(s) ↑ [↑,↓][↑,↑] [↑,↓][↓,↑] [↓,↓][↑,↑] [↓,↓][↓,↑]Spin results v°(p) - v°(s) v°(p) - v°(s) -v°(p) - v°(s) -v°(p) - v°(s)Orbit results v*(p) + v*(s) -v*(p) + v*(s) v*(p) + v*(s) -v* (p) + v* (s)Examplesv° (s) ↓V*(s) ↓ [↑,↓][↑,↓] [↑,↓][↓,↓] [↓,↓][↑,↓] [↓,↓][↓,↓]Spin results v°(p) - v°(s) v°(p) - v°(s) -v°(p) - v°(s) -v°(p) - v°(s)Orbit results v*(p) - v*(s) -v*(p) - v*(s) v*(p) - v*(s) -v* (p) - v* (s)

Examples CD Draconis



Apsidal motion is given by this formula:

W° (ob) = (-720x36526/T) {[√ (1-ε²)]/ (1-ε) ²]} [(v° + v*)/c] ² degrees/100years

W° (ob) = (-720x36526/1.238389985) (1.01) [170.09/300,000] ² degrees/100yearsW° (ob) = 6.731598944°/century = 0.06731598944°/year

U [years] = 360/[0.06731598944°/year]

U = 5348 years Nahhas

U (observed) = 5400+/-3200yearsEinstein's and space-timers U = 360/ [0.00191x365.26] = 516 yearsCan it get any better?It is not just about dumping relativity it is dumping relativity and Alfred Nobelinstitution with it.

References: Absolute properties of the low-mass eclipsing binary CM Draconis;2009By : Juan Carlos Morales; Ignasi ribas; carme jordi; Guillermo Toress; JoseGallardo; Edward F. Guinan; David Chardonneau; Marek wolf; David w.latham;

Guillem Angalada Escude; David H.Bradstreet; Mark E.Everett; Francis T. O,Donavan; Georgi Mandushev; Robert D. Mathieu and other 15

11 - V 1147 SagittariV 1147 Sagittari: Data: U = 592.5 +/- 6 yearsWith K (p) = 117.4 km/sec; K(s) = 130.8 km/secGiving v* (p) = 117.4 + 29.8 - 0.465 = 146.735 km/secAnd v* (s) = 130.8 + 29.8 – 0.465 =160.135 km/secOrbital speed of earth = 29.8 km/sec; spin speed of earth is 0.465 km/secAnd vº (p) = 80 + 29.88 – 0.465 km/sec = 109.335 km/sec

And vº(s) =75 + 29.88 – 0.465 km/sec = 104.335 km/secThen v* + vº = 146.735 + 160.135 + 109.335 + 104.335 = 520.54km/sec[√ (1- ε²)] (1-ε) ² = 2.62W (cal) = (-720x36526/3.28) x (2.62) (520.541/300,000)²= 63º/centuryU = [63/100]-1x 360 = 570 years.Observed values; 592.5ReferencesAbsolute dimensions of solar-type eclipsing binaries V 1147SagittariJ. Anderson, A. Gimenez 1985

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12- EW Orionis EW Orionis: Data: U =16300 +/- 3900With K (p) = 73.18km/sec; K(s) = 75.46 km/secGiving v* (p) = 73.18 + 29.8 - 0.465 = 102.515 km/secAnd v* (s) = 75.46 + 29.8 – 0.465 =104.795 km/secAnd vº (p) = 9 + 29.8 - 0.465 = 102.515 km/secAnd vº (s) = 73.18 - 29.8 + 0.465 = 102.515 km/sec

Orbital speed of earth = 29.8 km/sec; spin speed of earth is 0.465 km/secAnd vº (p) = 9km/sec; vº(s) =8.8km/secThen v* + vº = 102.515 + 104.795 +9.0 + 8.8 =225.11km/sec[√ (1- ε²)] (1-ε) ² = 1.167

W (cal) = (-720x36526/6.93) x (1.167) (225.11/300,000)²= 2.1367º/century

U = [2.1367/100]-1

x 360 = 16848 years.

13 - The Apsidal motion of VV PYX

Data: T = 4.596 days; m = 2.098 M (0); M = 2.098 M (0)

With r (p) = 0.1156 and r (s) = 0.1156 and R (m) = 2.167 R (0) and R (M) =2.167 R (0)And ε = 0.0956; 1 - ε = .9044; U = 3200 +/- 1000And [v° (p); v° (s)] = [23; 23]V = 381.03095km/sec

Calculations

With m + M = 4.196 M (0)

And (1-ε²/4) = 0.99771516; [√ (1-ε²)] / (1-ε) ² = 1.216984877G=6.673x10^-11; M (0) = 1.98892x19^30kg; R (0) = 0.696x10^9mAnd a = [R (m)/r (m)] = [2.06/ 0.097] R (0) = [2.167/ 0.1156] [0.696x10 9 m]Then a = 13.04698962 x 109 mAnd a (1-ε²/4) = [13.04698962 x10^9m] [0.99771516] = 13.01717934 x109m

K (A) = {√ [GM²/ (m + M) a (1- ε)] + √ GM²/ (m + M) a (1+ ε)]}/2K (A) = {√ [6.673x2.098²x2x10-19 / (4.196) 13.04698962x10^9x0.9044]

+ √ [6.673x2.098²x2x10-19 / (4.196) 13.04698962x10^9x1.0956]}/2= [108.85 + 98.96511511]/2 = 103.9km/sec

K (B) = {√ [Gm²/ (m + M) a (1- ε)] + √ Gm²/ (m + M) a (1+ ε)]}/2= 103.9km/sec

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With v* (m) = √ [GM²/ (m + M) a (1-ε²/4)] = 103.70 km/sec

And v* (M) = √ [Gm²/ (m + M) a (1-ε²/4)] = 103.70 km/secAnd v* (cm) = [m v* (p) + M v* (s)]/ (m + M) = 103.70 km/sec

And v° (p) = 23vkm/sec; v° (s) = 23 km/sec

W° (ob) = (-720x36526/T) {[√ (1-ε²)]/ (1-ε) ²]} (v* + v°/c) ²degrees/100 years

T = period; ε = eccentricity; v° = spin velocity effect; v*= orbital velocity effects

With v* (m) = √ [GM²/ (m + M) a (1-ε²/4)] = 103.70 km/secPrimary orbital speed contribution to apsidal motion

Is v* (m) = 103.7 + 29.8 – 0.465 = 133 km/secAnd v* (M) = √ [Gm²/ (m + M) a (1-ε²/4)] = 103.70 km/sec

Secondary orbital speed contribution to apsidal motionIs v* (M) = 103.7 + 29.8 – 0.465 = 133 km/secAnd v° (m) = 23 km/sec

Primary spin speed contribution to apsidal motionIs vº (m) = 23 + 29.8 – 0.465 = 52.335 km/secAnd v° (M) = 23 km/sec

Secondary spin speed contribution to apsidal motionIs vº (m) = 23 + 29.8 – 0.465 = 52.335 km/secThen v * + vº = 370.67

With ε = 0.17; T = 4.596 days[√ (1-ε²)] / (1-ε) ² = 1.216984877

W° (cal) = (-720x36526/4.596) (1.216984877) [370.67/300,000] ²U = 3386 years Nahhas'

U (observed) = 3200 +/- 1000yearsReferencesAbsolute dimensions of solar-type eclipsing binaries EW OrionisJ.V. Clausen, H. Bruntt, E.H. Olsen, B.E. Helt, and A. Claret 2009

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Chapter 13: Alfred Nobel prize winner for less than a $1993 Nobel Prize Winner Dr Joseph H. Taylor

Binary Pulsar 1913 + 16For PSR 1913 + 16Data: Joseph Taylor and Joel M. Weisberg 2004With a =2.3417725 R (0); R (0) = 0.696 x 10 9metersAnd ε = 0.6171338T = 0.322997448930

And θ' = 4.226595 °/yearWith mass m = 1.4414 M (0) and M = 1.3867 M (0); M (0) = 2 x 1030 kgV* (p) = √ [GM²/ (m + M) a] = 235.9574664 km/secV* (s) = √ [Gm²/ (m + M) a] = 245.2640841km/secW° (cal) = (-720x365.26/Tdays) x

sine² [Inverse tan (v/c)] degrees/100 years= (-720x365.26/0.329974489) x sine² [Inverse tan (481.22/300, 00)] deg/100years

W = 4.2°/year

15- PSR J0737 – 3039

Data: U =21.3 yearsWith m = 1.34 M (0); M = 1.25 M (0); M (0) = 2 x 1030

And ε = 0.0878; [vº (p), vº (s)] = [22.7 km/sec, 2km/sec]With G = 6.673 x 10 – 11; T =2.4 hours; a = 1.145 x 0.069 x 109

With K (p) = v* (p) = √ [GM²/ (m + M) a (1-ε²/4)] = 303 km/secAnd K(s) = v* (m) = √ [Gm²/ (m + M) a (1-ε²/4)] = 325 km/secGiving v* (p) = 303 + 29.8 - 0.465 = 332.335 km/secAnd v* (s) = 325+ 29.8 – 0.465 =354.335 km/secAnd vº (p) = 22.7 + 29.8 - 0.465 km/secAnd vº (s) = 2 - 29.8 + 0.465 km/secOrbital speed of earth = 29.8 km/sec; spin speed of earth is 0.465 km/sec

Then v* + vº = 332.335 + 354.335 +22.7 + 2 =711.37km/sec

[√ (1- ε²)] (1-ε) ² = 1.197

W (cal) = (-720x36526/6.93) x (1.197) (711/300,000)²= 1770º/centuryU = [1770/100]-1x 360 = 20.3389 years.

ReferencesThe Double pulsar PSR J0737 - 3039Burgay, M; D’Amico,N.; A.Manchester,R.N; Lyne, A.G.; Kramer, M; Mclaughlin, M.A; Lorimer, DCarmilo, F.; Stairs, I.H: Freire, P.C.C; Joshi,

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2 – Arabs Global Positioning Systems in arc degree /centuryW" (calculated) = [-720x36528/T] {[√ (1 - ε²)]/ (1 - ε) ²} (v/c) ² arc sec/ century

3 – Arabs Global Positioning Systems in arc second per year:W" (calculated) = [-720x365.26x3600/T] {[√ (1 - ε²)]/ (1 - ε) ²} (v/c) ² arc sec/ century

4- Arabs Global Positioning Systems in arc degree per year:W" (calculated) = [-720x365.26/T] {[√ (1 - ε²)]/ (1 - ε) ²} (v/c) ² arc sec/ century

5 - Arabs Global Positioning Systems delays in arc degree per cycle:W" (calculated) = [-720/T] {[√ (1 - ε²)]/ (1 - ε) ²} (v/c) ² arc sec/ century

6 Arabs Global Positioning Systems delays in arc second per cycle:W" (calculated) = [-720x3600/T] {[√ (1 - ε²)]/ (1 - ε) ²} (v/c) ² arc sec/ century

7- Arabs Global Positioning Systems delays in arc second per day:

W" (calculated) = [-720x3600] {[√ (1 - ε²)]/ (1 - ε) ²} (v/c) ² arc sec/ century8- Arabs Global Positioning Systems delays in second per cycle:W" (calculated) = [24/360] [-720x3600/T] {[√ (1 - ε²)]/ (1 - ε) ²} (v/c) ² arc sec/ century

9 - Arabs Global Positioning Systems delays in second per day:U (seconds/day) = [-720x 3600/15] {[√ (1 - ε²)]/ (1 - ε) ²} (v/c) ² sec/day

10 - Arabs Global Positioning System Circular Satellite Orbits time delays in seconds/dayU (seconds/day) = [-720x 3600/15] (v/c) ² sec/day

Application of Arabs Global positioning system

GPS Data: T = 0.5 days satellite orbital Period; ε = 0And v° = 0.465km/sec Earth spin speed;And v* = 14,000 km/hr = 35/9 km/secondThen v* +/- v° = 35/9 = 3.88888889km/sec - 0.465km/secondWe subtracted because satellite and motion and spin orientations are oppositeGPS time delays are given by this formula per day in seconds of an arcW" (ob) = (-720x3600/T) {[√ (1-ε²)]/ (1-ε) ²]} [(v° +/- v*)/c] ² seconds/dayW" (ob) = (-720x36/0.5) (1) [3.423888889/300,000] ² seconds of arc /1 dayW" (ob) = 0.000675246 arc seconds per day to get this answer in seconds divide

by 24hours/360degress = 15

U [seconds] = 0.000675246 x [24/360] seconds/day

U = 0.000045016 seconds/day = 45 micro seconds /day

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Chapter 15Arabs Real time Interplanetary Telecommunications systems

C - Interplanetary telecommunications around the sun

Harvard Irwin Shapiro historical mistake

Relativity stupidity of Harvard Physics departmentUniversal Constant Γ0 =16πGM/C³= 247.597μs

Abstract: Interplanetary time delays around the moving sun derived from threedimensional time-dependent Newton - Kepler's equations solution gives a solar

round trip time delay rate of:ΔΓ= 16πGM/c³ [1 + (v°/v)] ² = ΔΓ0 [1 + (v°/v)] ²ΔΓ0 = 16πGM/c³= 247.597μsG = Gravitational constant; M=Sun mass; a=mean distance from Sun. Andeccentricity; c = light speed; a = mean distanceAnd v = Planet speed; v°= Sum/Difference in spin between Earth and planets.When applied to actual data it gives extremely accurate results better thanShapiro's Space-time-delay analysis and without space-time fictional forces orspace-time fiction.

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W° (ob) = (-720x36526/Tdays) {[√ (1-ε²)]/ (1-ε) ²} x [(v° + v*)/c] ²degrees/100 years

The circumference of an ellipse: 2πa (1 - ε²/4 + 3/16(ε²)²- --.) ≈2πa (1-ε²/4); R =a (1-ε²/4)

Where v (m) = √ [GM²/ (m + M) a (1-ε²/4)]And v (M) = √ [Gm² / (m + M) a (1-ε²/4)]

Then W (ob) = -4π [√ (1-ε²)]/T (1-ε) ² sine² [ω (m) t + ω(r) t]Δ θ = T W (ob) = - 4π {[√ (1-ε) ²]/ (1-ε) ²} (v° + v*/c) ²} radians; and with ε =0

Δ θ = - 4π (v° + v*/c) ² Sun-Photon; and with v° = 0Δ θ = -4π (v*/c) ²Sun-Photon: 0 = ε [Sun - Photon] ≠ ε [Earth - Mars] = 0.2075The circumference of an ellipse: 2πa (1 - ε²/4 + 3/16(ε²)²---)≈ 2 π a (1-ε²/4); R =a (1-ε²/4)v=√ [Gm M/ (m + M) a (1-ε²/4)] ≈ √ [GM/a (1-ε²/4)]; m<<M; Solar systemΔΓ = 2 arc length/c = 2[Δ θ] d/c = 2[- 4π (v/c) ²] 2R/c; ΔΓ = -16π/c (v/c) ²;ΔΓ = 8πd/c³ [GM/a (1-ε²/4)] =16πGM/c³ (1-ε²/4) = Γ0 (1 - ε²/4)

ε = [a (planet 1) - a (planet 2)]/ [a (planet 1) + a (planet 2)] =0.2075 Mars-EarthΓ0 = 16 πGM/c³= 247.5974607μs=universal constant

ΔΓ = 250μs Mars-Earth.

x 1000 x 1000 x 1000



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These data compared to Shapiro's time delay from NASA 1977 Vikings 6, 7 Earth -Mars Telecommunications mission are more accurate because the actual value is250μs and the value published by Doctor Irwin Shapiro of Harvard is 247.597μsAlthough this formula works the correct formula isΔ θ = -4π [(v° + v*)/c] ² Sun-Photon; and with v° ≠ 0v = √ [GM/a] = 24.1 km/sec; vº = 0.46511 – 0.241 = 0.224 km/secΔΓ = 2 arc length/c = 2[Δ θ] d/c= 16πGM/c³ [1 + (vº/v)] ² = 247.597 x [1 + 0.224/24.1)]²Δ Γ = 250 µs For Mars; 0.4651 = Earth rotation; 0.241 = mars rotation; v = mars

speed

Planet Distant Planet-Earth

Planet+Earth

Eccentricity 1-ε²/4 ΔΓ0 ΔΓμ s

Mercury 57,910 91,690 207,510 0.441858224

0.951190328

247.5974607

260.3

Venus 108,200 41,400 257,800 0.160589604

0.993552745

247.5794607

249.2

Earth 149,600 0 299,200 0 1 247.5794607

247.597

Mars 227,940 78,340 377,540 0.207501192

0.989235814

247.5794607

250.273

Jupiter 778,330 628,730 927,930 0.677561885

0.885227473

247.5794607

279.6789

Saturn 1,429,400

1,279,800

1,579,000

0.810512983

0.835767176

247.5794607

296.230

Uranus 2,870,99

0

2,721,39

0

3,020,59

0

0.90094650

4

0.79707384

9

247.579460

7

310.61

Neptune 4,504,300

4,354,700

4,653,900

0.935709835

0.781111776

247.5794607

316.98

Pluto 5,913,520

5,763,920

6,063,120

0.950652469

0.774064971

247.5974607

319.86650



Harvard physics department is where physics changed from science to stupidity

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Physics in a capitalist country is a business and physics is notnecessarily science or scientific and if it is a western invention it is to be

at least 88.88 % fraudAfter World War II and the emergence of USA as a global superpower and the shift of power fromtraditional old empires to the new world “superpower” American Universities rushed for gold and gold is“reputable” physics department that can say anything publish anything based on nothing and nothing isRobert Pound and Glen Rebka confusion of an experiment . Harvard strikes again with fraud RobertPound and Glen Rebka (top)



22.5 meters apart

To start with gravity is a spin effect of a planet with atmosphere The gravitational and electric and magnetic constants all are derived from twoconstants p and T which are air density and Earth spin

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If we took a look at the most famous physics fundamental constant G from Newton's350 years old Equation F = - GmM/r², or, Coulomb electric force equation F = - Qq/4πε 0, one can see that, for example, G’s value has unit dimension of [G] = [1/ρ T²]; ρ isdensity and T is time rotational period. If we can show that the gravitational constant G= G (ρ, T) is a variable air density and Earth rotational period dependent then we cansay what Earth is saying that the most famous physics fundamental constants are notso universal constants because all three fundamental constant are air density and Earthspin dependent.





Michelson Morley

Set up this round rotating table in 1887 with a lamb, two mirrors beam splitter,telescope

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In Modern times an animation of the experiment would look like

Their reasoning was that if they rotate the table 90 degrees they would see theinterference pattern should change looking through the telescope.

When the interference pattern did not change they claim that physical quantitiesdata would not change when rotated 90 degrees or 1 = 1 +i

A. Michelson and E. MorleyHandymen in white ropes confusions of an Experiment

In GeneralV = v = Velocity of Earth assuming that emitter - receiver line-up with earth linetravel at start and during this whole experiment. That would be the x-x lineX' ------Earth moving in this direction with velocity v -----------XAnd C = c at startWhat is turning is the table that has the lamb and the mirrors and the telescope ontop of it.

To turn a quantity you multiply by e î θ And that means light c and distance dC = c e î θ = velocity of lightAnd d = d e î θ

Then: V = v; C = c e î θ; d = d e î θ; e î θ = cosine θ + î sine θFor example:

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1-Assume θ = 0° Arm AThen: V = v; C = c; d = d



Forward is C-V = c - vBackward C+V = c + vAnd t = d/ (c-v) + d/ (c + v)2- Assume θ = 90° then e î 90 = î Arm BThen V = v; C = c î; d = d î

Forward is C-V = -v + c î; and its measure is = √ (c² + v²)V is along the x-x and has no component on y-y axis and î means along the y-yaxisBackward C+V = v + c î; and its measure is = √ (c² + v²)And comes to this is Position IPosition 1: Right-UpperRight: t (1) = d/ (c -v) +d/ (c +v) = 2dc/ (c² - v²) = (2d/c) [1/ (1- v²/c²)]Upper: t (2) = d/√ (c² + v²) + d√ (c² + v²) = 2d/ √ (c² + v²) = (2d/c) [1/√ (1 +v²/c²)]Now Position II

3-Assume θ = 90° Arm AThen: V = v; C = ỉ c; d = dForward is C-V = -v + c î; and its measure is = √ (c² + v²) MMX mistake √ (c² -v²)Backward C+V = v + c î; and its measure is = √ (c² + v²)And t' (1) = 2d/ √ (c² + v²) = (2d/c) [1/√ (1 + v²/c²)]4- Assume θ = 90° + 90° =180 then e î 180 = -î Arm BThen V = v; C = -c; d = dForward is C-V = -c - v; V is along the x-x and has no component on y-y axis and îmeans along the y-y axisBackward C+V = -c + vThen t = d/-c+ v forward and in absolute value t = d/ (c - v)And t = d/-c -v backward and in absolute value t = d/ (c + v)And t' (2) = d/ (c - v) + d/ (c + v) = 2dc/ (c² - v²) = (2d/c) [1/ (1- v²/c²)]With t' (1) = 2d/ √ (c² + v²) = (2d/c) [1/√ (1 + v²/c²)]Conclusions is turning the table 90° has no effect what so ever on time lengthdifferenceIn GeneralIf we twist the table by an angle θ then V = v; C = c e î θ; d = d e î θ; e î θ = cosineθ + î sine θNow position I

V = v; C = c cosine θ + î c sine θ; d = d cosine θ + î d sine θForward: C - V = c cosine θ -v + î c sine θ and its measure is √ [(c cosine θ -v) ²+ c² sine ² θ]Backward: C + V = c cosine θ +v + î c sine θ and its measure is √ [(c cosine θ +v) ² + c² sine ² θ]

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And t (1) = d / √ [(c cosine θ -v) ² + c² sine ² θ] + d / √ [(c cosine θ + v) ² + c²

sine ² θ]And Position II



V = v; C = c cosine [θ + 90°] + î c sine [θ + 90°] = c sine θ - ỉ c cosine θd = d cosine θ + î d sine θForward: C - V = c sine θ -v - î c cosine θ and its measure is √ [(c sine θ -v) ² + c²cosine ² θ]Backward: C + V = c sine θ + v - î c cosine θ and its measure is √ [(c sine θ + v) ²

+ c² cosine ² θ]And t (2) = d / √ [(c sine θ -v) ² + c² cosine ² θ] + d / √ [(c sine θ + v) ² + c²cosine ² θ]As General rule:And t (1) = d / √ [(c cosine θ -v) ² + c² sine ² θ] + d / √ [(c cosine θ + v) ² + c²sine ² θ]And t (2) = d / √ [(c sine θ -v) ² + c² cosine ² θ] + d / √ [(c sine θ + v) ² + c²cosine ² θ]If θ = 0 then, we get position IRight: t (1) = d/ (c -v) +d/ (c +v) = 2dc/ (c² - v²) = (2d/c) [1/ (1- v²/c²)]Upper: t (2) = d/√ (c² + v²) + d√ (c² + v²) = 2d/ √ (c² + v²) = (2d/c) [1/√ (1 +v²/c²)]If θ = 90°, then we get position IIWith t' (1) = 2d/ √ (c² + v²) = (2d/c) [1/√ (1 + v²/c²)]And t' (2) = d/ (c - v) d/ (c + v) = 2dc/ (c² - v²) = (2d/c) [1/ (1- v²/c²)]There is no Path difference changeIf θ = 45 degrees, thenUpper: t (2 = d/ (c -v) +d/ (c +v) = 2dc/ (c² - v²) = (2d/c) [1/ (1- v²/c²)]Right: t (1) = d/√ (c² + v²) + d√ (c² + v²) = 2d/ √ (c² + v²) = (2d/c) [1/√ (1 +v²/c²)]

And the difference is still the sameNow Let us turn the Table 30°

A- Assume θ = 30° then Exp [30° î] = √ 3/2 + 1/2îThen: V = v; C = c Exp [î 30°]; d = d Exp [î 30°]; Exp [î 30°] = cosine 30° + îsine 30°And t (1) = d / √ [(c cosine 30° -v) ² + c² sine ² 30°] + d / √ [(c cosine 30° + v)² + c² sine ² 30°]And t (2) = d / √ [(c sine30° -v) ² + c² cosine ² 30°] + d / √ [(c sine 30° + v) ² +c² cosine ² 30°]

And t (1) = d / √ [(c √ 3/2 -v) ² + c² /4] + d / √ [(c √ 3/2 + v) ² + c² /4]And t (2) = d / √ [(c/2 -v) ² + c² (√ 3/2) ²] + d / √ [(c /2 + v) ² + c² (√ 3/2) ²]Now let us use v = 30km/sec and c = 300,000km/secIf θ = 0 then,

Page 90

Right: t (1) = d/ (c -v) +d/ (c +v) = 2dc/ (c² - v²) = (2d/c) [1/ (1- v²/c²)]

Upper: t (2) = d/√ (c² + v²) + d√ (c² + v²) = 2d/ √ (c² + v²)= (2d/c) [1/√ (1 + v²/c²)]





Page 92



Chapter 17 Earth Path in real space in real timeEarth path in space is possible and Einstein can keep his relativistic

trash to himself: Self – referenced motionThere is a serious problem in all of physics and that is timing of experiments and physics experiments theory.Earth absolute motion is a circle that is going to tie spin to orbit motion and waitingexperimental verificationsFinding new sources of energy requires the elimination of bad physics and badphysics is E = mc² because it is based on space - time physics and space timephysics is wrong because I can prove it wrong as follows.What is wrong with space - time is that it is a wrong idea and it is without proofs.Time is a human made scale and making it a dimension is scientifically stupid andthe reasoning behind accepting time as a dimension and not as a scale is the

assumption that it matches experiment. Time as a dimension allowing theexchange of time for space or squeezing space to expand time is not acceptable tome regardless what all Nobel prize winners have said about it and regardless whatthe 100, 000 living physicists are saying about it and regardless what all 100, 000dead physicists had said about it because it is wrong and proving it wrong is what Ican do and did the first time I read what started it and that would be the originaldumb idea and experiment in Cleveland Ohio in 1887 by Michelson and Morley.What dumb Michelson and Morley experiment did is it started stupidity as acceptedscience.The stupidity of Michelson and Morley experiment is the following.

We can not measure something that did not happen. We can only measuresomething that had happened. We can measure something in present time thathad happened in past time.Michelson and Morley experiment is stupid because two handymen in white robestried to measure something in real time and wondered why they did not see it inpast time.

Present time = present timePresent time = past time + [present time - past time]Present time = past time + time delays

Real time = event time + time delays

What we measure = what happened + what changed till things are measured.Real time physics = event time physics + time delays physicsWhat we see or measure is relativistic = Absolute event + relativistic time delaysWhat happened is absolute = real time relativistic event - real time relativisticeffects

Michelson and Morley mistake is the attempt:

Page 93



Real time = event time [this is the wrong idea that started space - time stupidity]What are missing are time delays[Known as quantum theory and relativity theory]

Real time = event time + time delays

This formula is my 1973 discovery that not only Nobel Prize winners are wrong butall of physics and physicists are wrong because physics solution is based on theidea that:

Real time = event time

In one dimension:

How would I know if I am going to the right or the left?

The problem is very simple, I would send a signal to 2 signals to two equidistantrepeaters that send back the signal to me and the signal that comes first indicate amotion in opposite direction. Installing a multi opposite directional repeaterssystem and one signal and for each tow opposite direction have on timer willproduce Earth path in absolute space and may produce the greatest formula in allof Physics and that would be mass motion and spin and better than that it willerase stupidity from classrooms know as space - time.

Abstract: Finding new sources of energy require the elimination of bad physicsand bad physics is Einstein's space-time (x, y, z, ict) confusion of physics that leadto energy fraud symbol E = mc² because energy spent is based on distancetraveled and not relative distance and distance traveled is self referenced distanceor absolute motion and finding this motion is waiting on funding for discovery sincethe beginning of time and experimentally is possible. Discovering Earth absolutemotion in space could be one of the greatest discoveries in physics of all timebecause it will answer the trillion dollar question if mass m spin s and absolutemotion r are related by a mathematical formula that expresses a physical law and if this law is to be found can it explains the structural design of the solar system and

if so what applications of such a law is useful inside the nucleus to produce newsources of energy?

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The experimental set - up

Experimental set-up d <<<<<<<<<<<<<<<<<<<E>>>>>>>>>>>>>>>>>>>> dSensor x' Emitter Ex Lead Sensor x

Timer T x

And d<<<<<<<<<<<<<<<<<<<E>>>>>>>>>>>>>>>>>>>>> dSensor y' Emitter E y Lead Sensor y

E

Timer T y And d<<<<<<<<<<<<<<<<<<<E>>>>>>>>>>>>>>>>>>>>> d

Sensor z' Emitter E z Lead Sensor z E

Timer T z

1-Assume there is a pulse emitter E shooting pulses in six different directions of theEuclidean system of axes per unit time τ; x'-x and y'-y and z'-z axes at sixequidistant receivers of distance d and has three wire leads Ex, E y, E z connectedto three Timers Named T x , T y, and T z.

2 - The six equidistant receivers are named x', x, y', y, z', z.

3- Three timers are named timer T x with three wires one to receiver x' and onewire to receiver x and one wire to emitter wire lead E x and timer T y with threewires one to receiver y' and one wire to receiver y and one wire to emitter wire

lead E y and timer T z with three wires one to receiver z' and one wire to receiver zand one wire to emitter wire lead E z are used4- These six pulses has their directions grouped in three sets of pairs x'-x, y'-y, z'-z.5- Three timers T x; T y, and T z are associated with the three axes respectivelya - Timer T x takes measurements from Emitter lead E x; receiver x' and receiver xb - Timer T y takes measurements from Emitter lead E y; receiver y' and receiver yc - Timer T z takes measurements from Emitter lead E z; receiver z' and receiver z

Page 95





Then

Conclusion:

The idea of this experiment is to find distance travel segments r (1); r (2); r (3); r(4); ...ETC; then join them together.

With [r (1); τ]O -------------- O [r (4); τ]

- - O ------------------[r (2); τ] - -

- - [r (3); τ]- O

r (1) = X1 + Y1 + Z1

r (2) = X2 + Y2 + Z2r (1) = X3 + Y3 + Z3r (4) = X4 + Y4 + Z4

The smaller the signal time interval or period τ then the more accurate theexperiment. Such a set-up is not only capable of finding absolute motion but it willgive clues to finding the relation between mass m spin s and its orbit r of planetEarth. If mass m motion r and spin s are found to be related it will the greatestformulas of all time because all there is in the Universe is mass m space r and spin

s. Earth mass m and spin s are know but mass r is Earth absolute motion that hadbeen waiting on funding for discovery since the beginning of time.

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Chapter 18 Johann Georg Von Soldner 1801 light bending historical mistake

Abstract: Newton proposed F = - GmM/r² as gravitational lawIn 1801 Johann Georg Van Soldner was the first person to calculate the gravitational

bending of light using Newtonian Mechanics and he got: Johann Georg Van Soldner ς (Johann) = 2 {cosine -1 [v²/ (-c² + v²)} - π

With v² = GM /R where G = gravitational constant = 6.673 x 10-11; C = 3 x108m/sec

And M = Sun mass = 2 x 1030 kg; R = sun radius = 0.695 x 109 m; v = 437.89Einstein said if make – believe time travel and new forces added:Then: ς (Einstein) = 4 (v/c) ²; ς (Johann) = 0.8789 arc sec; ς (Einstein) = 2(0.8789) Johann Georg Van Soldner derivation was incomplete and when completed andapproximated it produces Einstein’s formula without Einstein’s space – time fictionand as light aberration and not light bending.

Proof:

Johann Georg Van Soldner wrong derivation of angle of light aberration around the Sun

With d² r/d t² - r θ'² = -GM/r² Newton's Gravitational equation (1)And d (r²θ')/d t = 0 Kepler's force law (2)Assuming mass m = constant

Proof:With (2): d (r²θ')/d t = 0Then r²θ' = constant = hDifferentiate with respect to time

Then 2rr'θ' + r²θ" = 0Divide by r²θ'Then 2(r'/r) + θ"/θ' = 0And 2(r'/r) = - (θ"/θ') = 2[λ (r) + ì ω (r)]And 2(r'/r) = 2[λ (r) + ì ω (r)]And (θ"/θ') = - 2[λ (r) + ì ω (r)]

Solving for r = r (θ, t) = r (θ, 0) r (0, t) = r (θ, 0) ℮ [λ (r) + ỉ ω (r)] t

With r (0, t) = ℮ [λ (r) + ỉ ω (r)] t

Then θ'(θ, t) = [h/ r² (θ, 0)] ℮ -2[λ (r) + ỉ ω (r)] t

And, θ'(θ, t) = θ' (θ, 0) θ' (0, t) Page 98



And θ' (0, t) = ℮ -2[λ (r) + ỉ ω (r)] t

Also θ'(θ, 0) = [h/ r² (θ, 0)] And θ'(0, 0) = [h/ r² (0, 0)]

With (1): d² r/d t² - r θ'² = - GM/r²Let r =1/uThen d r/d t = -u'/u² = - (1/u²) (θ') d u/d θ = (- θ'/u²) d u/d θ = - h d u/d θAnd d² r/d t² = - hθ'd²u/dθ² = - h u² [d²u/dθ²]

And - hu² [d²u/dθ²] - (1/u) (hu²)² = - G Mu²[d²u/ dθ²] + u = G M/ h²And u = G M/ h² + A cosine θ

And du/ d θ = 0 = - A sine θ; θ = 0Then u (0) = 1/ r (0) = GM/h² + A; h = RCC = light velocity of 300,000km/sec; And A = 1/R – GM/ (RC) ²And u = G M/ h² + A cosine θ = GM/ (RC) ² + [1/R – GM/ (RC) ²] cosine θ

And r = 1/u = 1/ {GM/ (RC) ² + [1/R – GM/ (RC) ²] cosine θ}If r --- ∞; GM/ (RC) ² + [1/R – GM/ (RC) ²] cosine θ = 0Divide by GM/ (RC) ²

Then 1 + [R²C²/ GM R – 1] cosine θ = 0And cosine θ = -1/ [C²/ (GM/ R) – 1]Or cosine θ = 1/ [1 – (C²/V²)]; GM/R = V²Or cosine θ = v²/ (v² - c²)And θ = cosine -1 [v²/ (v² - c²)]

nd ς (Johann) = 2 {cosine -1 [v²/ (-c² + v²)} - π ≈ 2 [π/2 + (v/c) ²] – π = 2 (v/c) ²; v/c <<1



nstein invented many things to come up with double the amounts:r, ς (Einstein) = 4 (v/c) ²

ere is Johann Georg Van Soldner 1801 Historical mistakee have u (θ) = G M/ h² + A cosine θ

nd r (θ, t) = r (θ, 0) r (0, t) = r (θ, 0) ℮ [λ (r) + ỉ ω (r)] t

nd r (θ, 0) = 1/ u (θ, 0) = 1/ [G M/ h² + A cosine θ]r, r (θ, 0) = (h²/GM)/ [1 + (h²/GM) A cosine θ]r, r (θ, 0) = (h²/GM)/ [1 + ε cosine θ]

Real time orbit: r (θ, t) = [a (1-ε²)/ (1+ ε cosine θ)] ℮ [λ (r) + ỉ ω (r)] t

is equation is real time Universal mechanics solution

This: r (θ, t) = [a (1-ε²)/ (1+ ε cosine θ)] ℮ [λ (r) + ỉ ω (r)] t --------------------------------- Iis the math formula that matches a physical experimenttime is frozen that is t = 0en r (θ, t) = [a (1-ε²)/ (1+ ε cosine θ)] we get the classical or event time solution ----------- II

elativistic is the difference between I and II

nd it is the visual illusion between motion II and Visual motion Ihe difference between an event and its measurement in real time

th θ’ (θ, t) = [h/ r² (θ, 0)] ℮ -2[λ (r) + ỉ ω (r)] t

th (θ”/ θ’) = - 2[λ (r) + ì ω (r)]en θ” (θ, t) = - 2[λ (r) + ì ω (r)] [h/ r² (θ, 0)] ℮ -2[λ (r) + ỉ ω (r)] t

Light LightSun

θ ς



With λ (r) = 0

Then θ” (θ, t) = - 2 ì ω (r) [h/ r² (θ, 0)] ℮ -2 ỉ ω (r) t Or, θ” (θ, t) = - 2 ì ω (r) [h/ r² (θ, 0)] [cosine 2 ω (r) t + ί sine 2 ω (r) t]

The real part or along the line of sightIs Real θ” (θ, t) = 2 ω (r) [h/ r² (θ, 0)] sine 2 ω (r) t] (t/t)Or, Real θ” (θ, t) = 2 t ω (r) [h/ t r² (θ, 0)] sine 2 (r) ω t]

Or, Real θ” (θ, t) / [h/ t r² (θ, 0)] = 2 t ω (r) sine 2 ω (r) tAt t = T; light aberration angle in real time is confused for light bending. With ω T= arc tan (v/c)Then ψ = visual illusion angle = θ” (θ, T) / [h/ T r² (θ, 0)]Or, ψ =2 T ω (r) sine 2 ω (r) T

Johann Georg Van Soldner 1801 historical mistakeIs: ψ = [2 arc tan (v/c)] sine [2 arc tan (v/c)]

Page 100

With (v/c) << 1; 2 arc tan (v/c) ≈ 2 (v/c)And sine 2 arc tan (v/c) ≈ sine 2 (v/c) ≈ 2 (v/c)

And ψ = [2 arc tan (v/c)] sine [2 arc tan (v/c)]≈ [2 (v/c)] [2 (v/c)]

Or ψ ≈ 4 (v/c) ² radiansOr, ψ ≈ 4 (v/c) ² x (180/π) degreesOr, ψ ≈ 4 (v/c) ² x (180/π) x 3600 secondsWith v² = GM/RThen ψ ≈ 4 GM/R c² x (180/π) x 3600 secondsEinstein with the help of others rigged eternity to come up with 4 (v/c) ² and not 2 (v/² to justify experimental illusions or 2[2(v/c) ²]Ψ = 7200 [arc tan (437.89 / 300,000)] sine 2 [arc tan (437.89/300,000)]

= 1.757855865 arc second



MR Eddington: keep the trash to England Royals

101

Chapter 19: 20th century greatest mistake is E = mc²

The difference between old physics and new physics is double

That is one Einstein equal two Newton.



Newton energy definition is En = mc²/2Einstein doubled that amount or E e = 2 En = 2[mc²/2] = mc²

It is not just Einstein and Newton are wrong but physics is 500 years wrong Page 1Abstract: The elimination of 500 years of Physics including relativity theory is a matt

of time and not a matter of science and the time is 1900.

E = mc² death certificate is now available

Real time Physics: We can only measure past events. We can not measuresomething that did not happen. We can only measure things that had happened.What we measure is not what happened. We measure in present time an eventthat happened in past time.

Present time = present timePresent time = past time + [present time - past time]Present time = past time + real time delaysReal time physics = event time physics + real time relativistic delays

What one sees is relativistic = what happened in an absolute event + relativisticeffectsWhat happened in an event is absolute = real time physics - real time relativisticeffects.

Observer time = observed traveler time + time delaysReal time = absolute time + time delays

Real time = Event time + time delaysReal time Physics = event time Physics + time delays Physics

Page 102

Quantum = classical + relativistic

Naming Γ as real time and t as event timeΓ = t + (Γ - t) = t [1 + (Γ – t)/t] = t (Γ/t)

Γ = t + Δ Γ; Δ Γ = Γ - tIf an event happens on Planet Mercury and the event is seen from the Sun at eventtime t, then this same event would be seen from Earth in real time as time Γ = t +Δ Γ

Γ = t + (Γ - t)Real time = Event time + time delaysΓ = t + Δ Γ (x) + ỉ Γ (y) = t + Δ Γ

Δ Γ = Δ Γ (x) + ỉ Γ (y)

Δ Γ (x) is along the line of sight time delaysΔ Γ (y) is perpendicular to the line of sight time delays



Γ = t (Γ/t)

Γ = t e ỉ ω t; Γ/t = e ỉ ω t

Γ = t e ί ω t

Multiplying by c, then r = c Γ = c t eί ω t

= r0 eί ω t

; ω T = arc tan (v/c)

Or r = r0 e ί ω t

A – Light aberration ω T= arc tan (v 0 /c)B – Michelson and Morley ω T = [π /2 + arc tan (v 0 /c)]

Real time location is r = r 0 ℮ ỉ ω t

Real time velocity v = [v 0 + í ω r 0] ℮ ỉ ω t

The definition of energyE = m (V. V)/2

= (m/2) [v 0 + í ω² r 0]. [v 0 + í ω r 0] ℮ 2 ỉ ω t

= (m/2) [(v0² - ω² r 0²) + 2 í ω (r 0 v 0)] [cosine 2ω t + í sine 2ω t]= (m/2) {[(v0² - ω² r 0²) cosine 2ω t - 2 ω (r 0 v 0) sine 2ω t]

+ í [(v0² - ω r 0²) sine 2ω t + 2 ω (r 0 v 0) cosine 2ω t]}= Ex + i E y

Ex = (m/2) [(v0² - ω² r 0²) cosine 2ω t - 2 ω (r 0 v 0) sine 2ω t]

Page 103

Case IConstant velocity of light principle: v 0 = ω r 0 = cThenEx = (m/2) [(c² - c²) cosine 2ω t - 2 c² sine 2ω t]Ex = (m/2) [- 2 c² sine 2ω t]

Ex = - m c² sine 2ω tA – Light aberration ω T= arc tan (v 0 /c)Ex = - m c² sine 2ω tEx = - m c² sine 2 [arc tan (v 0 /c)]Ex = - m c² sine 2 [arc tan (c /c)]Ex = - m c²B – Michelson and Morley ω T = [π /2 + arc tan (v 0 /c)]Ex = - m c² sine 2ω tEx = - m c² sine 2[π /2 + arc tan (v 0 /c)]

Ex = - m c² sine 2[π /2 + arc tan (c /c)]



Ex = - m c² sine 2[π /2 + π /4]Ex = - m c² sine [3π /2]Ex = m c²

Case II

Rest Energy Principle: v 0 = 0; ω r 0 = cThenEx = (m/2) [(0² - c²) cosine 2ω t - 2 c (0) sine 2ω t]Ex = (m/2) [- 2 c² cosine 2ω t]Ex = - m c² cosine 2ω tA – Light aberration ω T= arc tan (v 0 /c)Ex = - m c² cosine ω T= arc tan (v 0 /c)Ex = - m c² cosine 2 [arc tan (0 /c)]Ex = - m c² cosine 2 (0)

Ex = - m c²B – Michelson and Morley ω T = [π /2 + arc tan (v 0 /c)]Ex = - m c² cosine 2ω tEx = - m c² cosine 2[π /2 + arc tan (0 /c)]Ex = - m c² cosine 2(π /2)Ex = - m c² cosine π Ex = - m c² (-1)Ex = m c²

Page 104

Michelson MorleyThis 1907 Nobel Prize winner Dude along with this Dude put a Lamp two mirroand a telescope on a round rotating table.





Michelson and Morley looked at the virtual image from the two mirrors of light reflections through the telescope. They claim that if they to rotate thetable then the image should change. When Michelson and Morley rotatedthe table in 1887 and the image did not change they claim that you canrotate data without change in results!

Then conclusion of this wacky claim that won a Nobel Prize is thatThe number 1 can be replaced by 1 + i; i is the complex number

Or; in Cartesian coordinates

Page 106





Chapter 20: special relativity stupidityAll there is in the Universe is objects of mass m moving in space (x, y, z) at alocationr = r (x, y, z). The state of any object in the Universe can be expressed as theproductS = m r; State = mass x location:P = d S /d t = m (d r /d t) + (dm/d t) r = Total moment

= change of location + change of mass= m v + m' r; v = velocity = d r/d t; m' = mass change rate



r = r r (1) ;v = r' r(1) + r θ' θ(1) ; γ = (r" - rθ'²)r(1) + (2r'θ' + r θ")θ(1)r = location; v = velocity; γ = accelerationF = m γ + 2m'v +m" rF = m [(r"-rθ'²) r (1) + (2r'θ' + r θ") θ (1)] + 2m'[r' r (1) + r θ' θ (1)] + (m" r) r(1)


= [-GmM/r²] r (1) ------------------------------- Newton's Gravitational LawProof :First r = r [cosine θ î + sine θ Ĵ] = r r (1)

Define r (1) = cosine θ î + sine θ ĴDefine v = d r /d t = r' r (1) + r d[r (1)]/d t

= r' r (1) + r θ'[- sine θ î + cosine θĴ]= r' r (1) + r θ' θ (1)



γ = (r" - rθ'²) r (1) + (2r'θ' + r θ") θ (1)

With d² (m r)/dt² - (m r) θ'² = F (r) And d (m²r²θ')/d t = 0With m = constant, thenWith d² r/dt² - r θ'² = F (r) Eq-1 And d (r²θ')/d t = 0 Eq-2With d² r/dt² - r θ'² = - ω²s r E q – 1 Hooke’s LawAnd d (r²θ')/d t = 0 Eq-2

Page 108



From Eq-2: d (r²θ')/d t = 0Then r²θ' = h = constantDifferentiate with respect to timeThen 2rr'θ' + r²θ" = 0Divide by r²θ'

Then 2(r'/r) + θ"/θ' = 0And 2(r'/r) = - θ"/θ' = 2[λ (r) + ỉ ω (r)]Also, r = r0 (θ, 0) e [λ (r) + ỉ ω (r)] t

And θ' = θ' 0 (θ, 0) e -2[λ (r) + ỉ ω (r)] t

For a fixed orbit: λ r= 0Also, r = r 0 (θ, 0) e ỉ ω t

An object of length r could be seen longer or shorter if it extended or shortened e λ

t or twisted e í ω t making it in general r e [λ + í ω] t. If the length of an object is notextended or shortened then λ = 0 and it could be seen as a twisted visual effect.Then r -------------------------- Visual r = S = r e í ω t

1- The illusion of length contraction: Length contraction is just a visual effect of projected light aberration andit is an "apparent" visual effect and not real

Alfred Nobel Institution IdiotAn object located at r ----- light sensing -----measured as S = r e í ω t with ω t =arc tan (v/c); tan (v/c) = light aberrations angle = ω tS = r e í ω t caused by light aberrations visual effects as follows:If e í ω t = [cosine ω t + ỉ sine ω t]; From S = r e í ω t

Page 109



It changes to: S = r {√ [1- sine² arc tan (v/c)] - ỉ sine arc tan (v/c)}= r {√ [1- (v/c) ²] - ỉ (v/c)}; v/c <<< 1= S x + ỉ S y

Where S x = √ [1- sine² arc tan (v/c)]; And S y = cosine arc tan (v/c)With v/c << 1 then; Where S x = √ [1- sine² arc tan (v/c)]; And S y = cosine arctan (v/c)In absolute value S = rAlong the line of measurement: S x = √ [1- sine² arc tan (v/c)] ≈ r √ [1-(v/c) ²];v/c << 1This the equation for length contraction of Lorentz's used in Einstein's theoriesBut it is the light aberrations visual effects and it is "apparent and not real

2 - Constant velocity of light leading to Time DilationsProjected light aberrationsS x = r cosine ω tHypotenuse = S x = [c t x] = c t x √ [1- sine² arc tan (v/c)]

S x ≈ c t √ [1-(v/c) ²]; from constant velocity of light and c is constant in all reference frames

Where t = local self time; t x = time by observer

t x = t √ [1-(v/c) ²]; andt = {1/√ [1-(v/c) ²]} t x absolute math

These are time dilatation equations given by Einstein’s special relativity theory.

t x' = t' √ [1-(v'/c) ²]; andt' = {1/√ [1-(v'/c) ²]} t x' absolute math

Two observers observing the same thing the time dilations are

Then, t x = t √ [1-(v/c) ²]; t = {1/√ [1-(v/c) ²]} t x absolute math; Lab purposesAnd, t x' = t √ [1-(v'/c) ²]; t' = {1/√ [1-(v'/c) ²]} t x' absolute math; Labpurposes

However; two observers looking at each otherS (A) = r exp [ỉ ω t]S (B) = r exp [- ỉ ω t]S x (A) = S x = c t x ≈ c t x' √ [1-(v/c) ²]S x (B) = S x = c t x' ≈ c t x √ [1-(v/c) ²]And t x ≈ t x' √ [1-(v/c) ²]And t x' ≈ t x √ [1-(v/c) ²]That is why there no twin Paradox except on science fictions books because it is allabout aberrations and nothing real.

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3 – Momentum

S x = Visual location along the line of sight = r [√ [1-(v/c) ²]P x = v [√ [1-(v/c) ²]; v =constant; P x = d [S x]/d tAnd m P x = m v [√ [1-(v/c) ²] = m (0) v

4 – Mass Then m = m (0) / [√ [1-(v/c) ²]

Also; m = m (0) / [1-1/2(v/c) ²]

5- Energy

mc² = m (0) c² / [1-1/2(v/c) ²]

E = m (0) c²; v = 0

Also m ≈ m (0) [1+ 1/2(v/c) ²]

Hence m c² ≈ m (0) c² + m v ²/2

Page 111



Chapter 21Quantum mechanics Copenhagen Cyclic Interpretation

Ape Man Modern Physicist Nobel Prize Ape Ass.

Then came the Copenhagen Interpretation

The Copenhagen idiots with Nobel prizes That new physics is needed!This new physics is quantum mechanics!Quantum mechanics is a purely western stupidity:

I - In 950 AD with Arabs visual location law is quantum mechanics:Is r = r 0 e í (θ + ω t)

All there is in the Universe is objects of mass m moving in space (x, y, z) at a locationr = r (x, y, z). The state of any object in the Universe can be expressed as theproductS = m r; State = mass x location:P = d S /d t = m (d r /d t) + (dm/d t) r = Total moment



In polar coordinates systemr = r r (1) ;v = r' r(1) + r θ' θ(1) ; γ = (r" - rθ'²)r(1) + (2r'θ' + r θ")θ(1)



= [-GmM/r²] r (1) ---------------------------- Newton's Gravitational Law

Page 112



Proof :First r = r [cosine θ î + sine θ Ĵ] = r r (1)

Define r (1) = cosine θ î + sine θ Ĵ

Define v = d r /d t = r' r (1) + r d[r (1)]/d t = r' r (1) + r θ'[- sine θ î + cosine θĴ]= r' r (1) + r θ' θ (1)



γ = (r" - rθ'²) r (1) + (2r'θ' + r θ") θ (1)

With d² (m r)/dt² - (m r) θ'² = F (r) And d (m²r²θ')/d t = 0With m = constant, thenWith d² r/dt² - r θ'² = F (r) Eq-1 And d (r²θ')/d t = 0 Eq-2With d² r/dt² - r θ'² = 0 E q – 1And d (r²θ')/d t = 0 Eq-2

From Eq-2: d (r²θ')/d t = 0

Then r²θ' = h = constantDifferentiate with respect to timeThen 2rr'θ' + r²θ" = 0Divide by r²θ'Then 2(r'/r) + θ"/θ' = 0And 2(r'/r) = - θ"/θ' = 2[λ (r) + ỉ ω (r)]Also, r = r0 (θ, 0) e [λ (r) + ỉ ω (r)] t

And θ' = θ' 0 (θ, 0) e -2[λ (r) + ỉ ω (r)] t


And θ' = θ' 0 (θ, 0) e -2ỉ ω t


= - h (d u/ d θ)And d² r/ d t² = - h (θ’) (d² u/ d θ ²)

= [- h²/r²] (d² u/ d θ ²)= - h² u² (d² u/ d θ ²)

Page 113




Then u = A e - í θ Then r 0 (θ, 0) = (1/A) e í θ And r 0 (θ, 0) = r 0 (0, 0) e í θ And r = r 0 (0, 0) e í θ e ỉ ω t Or, r = r 0 e í (θ + ω t)

This is quantum mechanics

rabs real time astronomy is actually quantum mechanics r = r0 e í ω (r) t

Light is emitted and not an emitter and humans have no means of measuring lightin motion and at best they can take a snap shot.In mathematical languageThen r (θ, 0) = r 0 e í θ at t = 0And r (θ, t) = r 0 e í (θ + ω t) = r 0 e í θ e í ω t = r (θ, 0) e í ω t

And r (θ, t) = r (θ, 0) [cosine ω t + í sine ω t]And r x (θ, t) = r x (θ, 0) cosine ω tAnd ω t = cosine-1 [r x (θ, t) / r x (θ, 0)]Then ∆ r = r x (θ, t) - r x (θ, 0)

= r x (θ, 0) [(cosine ω t) – 1]And [r x (θ, t) - r x (θ, 0)]/ r x (θ, 0)

= [(1 - 2 sine² ω t/2) – 1]= - 2 sine ² ω t/2; ω t = cosine-1 [r x (θ, t) / r x (θ, 0)]

rabs real time astronomy:Image = Image = IObject = Object = O- Object = - Object = - O

Image = object + (Image – Object)I = O + (I – O)(I/O) = O/O + [(I – O)/O]

(I/O) = 1 + [(I – O)/O](I/O) θ' 0 = θ' 0 + [(I – O)/O] θ' 0

Quantum = classical + relativistic IllusionI = r; O = r 0

Or, (r / r 0) θ' 0 = θ' 0 + [(r – r 0)/ r 0] θ' 0

And [(r – r 0)/ r 0] θ' 0

Or [- 2sine ² ω t/2] θ' 0; ω t = cosine-1 [r x (θ, t) / r x (θ, 0)] = cosine-1 (r/ r 0)For planet Mercury:

Page 114



The distance visual effect Error is: [(r m – re)/re] δ θ’ m




And r e = 149.6 x 109 m = Sun Earth distance

With [(r m – re)/re] = [- 2sine ² ω t/2] = 0.61And ω t = cosine-1 [r x (θ, t) / r x (θ, 0)] = cosine-1 (r/ r 0)Or ω t = cosine-1 [r x (θ, t) / r x (θ, 0)] = cosine-1 (r m / r e)[(r m – re)/re] δ θ’ m = 0.61 x 70.75 = 43



All rights reservedPage 116



Chapter 22: Earth Absolute Motion is circularCopernicus said that Planets move around the sun in an ellipseGalileo affirmed that planets move around the sun in an ellipseTycho Brahe collected the astronomical data and confirmed that planets move around

the Sun in an ellipse

Figure - 1

Kepler wrote the acceleration law: a/T2 = k/a2

And deduced that planets move around the sun in an ellipse and that the sun is atthe focus of the ellipse like in figure above

Newton and Hooke reiterated the same thing as Kepler and wrote: r/ t2 = k/r2

Astronomers found that the motion is not an ellipse but a rotating ellipseEinstein wrote another acceleration law r/t2 = k/ r2 + k1 /r4 to describe a rotating ellipse

7 billion people were told by Alfred Nobel prize winner physicists that Planets rotatearound the Sun in a rotating ellipse

What if I can prove all wrong?

I am Joe NahhasAnd I am better than good and I am after Alfred Nobel Institution head

Page 117

θ

r

Sun

Mercury



Newton gave the equation of the ellipse:As: r (θ, t) = [a (1-ε²)/ (1+ε cosine θ)] Einstein said he corrected Newton and wrote the new equation:

Is: r (θ, t) = a (1-ε²)/ [1+ε cosine (θ - Ψ)] It is a fact that Astronomers see this axis tilt and Einstein got a formula for it: ψ = {6 πM/a c² (1 - ε²)} [180/ π] [36526/T (days)][3600] G = 6.673 x 10-11= gravitational acceleration constantM =2x1030kg = mass of the Sun

Eccentricity of Mercury’s orbit = ε = 0.206T= 88 days = period of Planet mercury’s rotation around the SunAnd c = 299792.458 km/sec =light speed/sec

And a = 58.2 x 106

km/sec = semi major axis of planet Mercury orbit

Sun

ψ

Mercur y

θ



ψ = {6 (π) 6.673 x 10-11 (2 x 1030)/58.2 x 106 (299792.458) ² [1– (0.206)²]} x [180/ π][36526/88] [3600] = 43 seconds of an arc per century

Page 118

Newton used magical powers or action at a distance force F = Gm M/r2

Einstein said if Newton can add magical power then I can domagic powers of Newton and add Einstein’s own magicalpowers of time travel force and the force

Is F = G m M/r2 (space force) + k/r4 (time force)

These two morons claim that what we see is due to magicwhere the Sun is pulling on the planets to keep them around?Did anyone see the Sun Pulling?

Did anyone see a damn robe not the Sun hanging the planets torevolve around it but to hang these two idiots with Alfred Nobelphysicists?!





Einstein’s – Newton space - time:

F = G m M/r2 (Newton’s space force) + k/r4 (Einstein’stime force)

The force is with Joe Nahhas and in real time space F = 0 Nahhas said the only magic is an act of kindness of a human to all others!My act of kindness to humanity is to make humanity aware of the criminals with Nobel prizes and theidiots with Intelligent portfolios!

Page 120

What I am saying is that there is no Newton’s gravitationalforce and Einstein’s space – time force is silly to say the leastand I can prove that there is no gravitational force between theSun and the Planets force, or, F = o solution is a rotating ellipseIllusion.

What I am saying dear Pope John Paul is that those with“knowledge” and sick intentions to be arrogant and claim

magical forces and mocks the believers have absolutely no cluewhat they see in their telescopes and have nothing to offerbeside stupidity that started with Newton and perfected withAlfred Nobel Institution’s dumbest Einstein. To start with let mesolve this equation F = 0. The solution of F = 0 is the equationof a real time circleIs r = r 0 e í (θ + ω t)

All there is in the Universe is objects of mass m moving in space (x, y, z) at a locationr = r (x, y, z). The state of any object in the Universe can be expressed as theproduct

S = m r; State = mass x location:








And θ' = θ' 0 (θ, 0) e -2ỉ ω t


= - h (d u/ d θ)

Page 122



Then u = A e - í θ Then r 0 (θ, 0) = (1/A)

e

í θ

And r 0 (θ, 0) = r 0 (0, 0) e í θ And r = r 0 (0, 0) e í θ e ỉ ω t

Or, r = r 0 e í (θ + ω t) What I am saying Dear Pope is this is the equation of motion of any planet! It is also the equation of motion of the smallest particle light!

w Planet Mercury motion is r m = r m 0 e í [θ (m) + ω (m) t]

e Sun Motion is r s = r s 0 e í [θ (s) + ω (s) t]

Sun r r s Mercury

r1 r0 r m

X1 r2

X2



Earth

Page 123

In mathematical form: r1 = x1 + r s

And r2 = x2 + r m

Then r2 - r1 = x2 - x1 + r m – r s

Or, r = r0 + (r m – r s)To find the extreme values of r,Then: d r/d t = d r0 /d t+ (d r m /d t – d r s / d t) = 0

And (d r m /d t – d r s / d t) = 0; d r0 /d t = 0

And d r m /d t = d r s / d tNow Planet Mercury motion is r m = r m 0 e í [θ (m) + ω (m) t]

The Sun Motion is r s = r s 0 e í [θ (s) + ω (s) t]

And d r m /d t = r m 0 [θ’ (m) + ω (m)] e í [θ (m) + ω (m) t]

And d r s / d t = r s 0 [θ’ (s) + ω (s)] e í [θ (s) + ω (s) t]

With r m 0 [θ’ (m) + ω (m)] Cosine [θ (m) + ω (m) t]= r s 0 [θ’ (s) + ω (s)] Cosine [θ (s) + ω (s) t]

And r m 0 [θ’ (m) + ω (m)] sine [θ (m) + ω (m) t]

= r s 0 [θ’ (s) + ω (s)] sine [θ (s) + ω (s) t]Then dividing we get: tan [θ (n) + ω (n) t] = tan [θ (s) + ω (s) t]Or, [θ (m) + ω (m) t] = [θ (s) + ω (s) t] + [n π = 0; n =0]

And θ (m) - θ (s) + = [ω (s) - ω (m)] t

This is the time delay IllusionAnd, r m 0 [θ’ (m) + ω (m)] = r s 0 [θ’ (s) + ω (s)]





And a = (r max + r min)/2 = r 0

This establishes visual ellipse of semi major axis a and a semi minor axis b = √ (a²- c²) = a √ [1 – (c/a) ²] = a √ (1 – ε ²)And h = 2 π a b = 2 π a² √ (1 – ε ²)Areal Velocity is: 2 π a² √ (1 – ε ²)/T

Page 125

Figure - 1

θ

r

Sun

Mercury



Page 126

And Farthest distance = r max = r 0 + (r m 0 + r s 0) = a + c

And closest distance = r min = r 0 - (r m 0 + r s 0) = a - c

At closest approach: h =2 π a² √ (1 – ε ²)/TAnd dividing h / (a – c) ² = 2 π a² √ (1 – ε ²)/T a² (1 – ε) ²Or r²θ' = h will give θ' (a) = 2 π √ (1 – ε ²)/T (1 – ε) ²

And for any motion θ' = θ' 0 (θ, 0) e -2ỉ ω t

And θ’ = {[cosine 2 ω t + í sine 2 ω t] – 1} θ' 0 (θ, 0) And θ’ = θ’ (x) + í θ’ (y)

= [cosine 2 ω t + í sine 2 ω t] θ' 0 (θ, 0)And θ’ (x) = [cosine 2 ω t] θ' 0 (θ, 0)





Multiplication by 180/π to change to degrees

Ψ ° = (-720/T) {[√ (1-ε²)]/ (1-ε) ²} sine² {Inverse tan [(v* + v°)/c]} DegreesAnd multiplication by 1 century = 36526 days and using T in days

Ψ’’ (calculated) = (-720x36526/T days) {[√ (1-ε²)]/ (1-ε) ²} xsine² {Inverse tan [(v* + v°)/c]} degrees/100 years

And in arc seconds per century:Ψ’’ (calculated) = (-720x36526x3600/T days) {[√ (1-ε²)]/ (1-ε) ²} x

sine² {Inverse tan [(v* + v°)/c]} degrees/100 years = 43

Page 128

The confrontation between physics and physicists

By Professor Joe Nahhas 1978

Greetings: my name is Joe Nahhas and I am the greatest physicist of all time since July 4th 1973m unknown to the world of physics but I have 1001 new real time physics formulas to change physics and

story to delete all physics and wipe out written history and this is a revolt!







Figure - 1

If we took a look at the most famous physics fundamental constant G from Newton’s 350 years old Equation FG m M/r² G’s value has unit dimension of [G] = [1/ρ T²]; ρ is atmospheric density and T is time rotational perIf we can show that the gravitational constant G = G (ρ, T) is a variable air density and Earth rotational perioddependent then we can say what Earth is saying that the most famous physics fundamental constants are not souniversal constants because all physics fundamental constant are air density and Earth spin dependent. For example:G = G (ρ, T) = 1/ [(2/5) (4 π/3) ρT²]; 5/2 ~ √ (2 π) Nothing that: 8 π /15 = (2/5) (4π/3); 4π/3 and 2/5 come from spherical aspectWhere: ρ = air density; T = Earth rotation period; T = 23.9333 hours and ρ = 1.2045 kg/m³G = 1/ (8 π/15) ρT² = 6.674 x 10 – 11

[G] = [1/ρ T²] ~ 0 if spin period is very long or atmospheric density is very highThis fact applies to electromagnetic fundamental constants:

Like ε (0) = 1/4πρT² = 8.85 x 10 -12; μ (0) = 4πρT²/c²There is no “gravity” between the “sun” and “planets” and that means: The force F = 0And not F = - G m M/r²

Yes I am saying that astronomers have no clue what they see using their telescopesWhat I am saying is that there is no F = - G m M/r² and there is no solar system where the motion of a planetaround the sun is an ellipse with the sun at the focus of the ellipse.

θr

Sun

Mercury



Figure - 1

Kepler wrote the acceleration law: a/T2 = k/a2

And said that the motion of a planet around the sun is an ellipse like in figure - 1

And wrote the equation of motion lawAs: r (θ, t) = [a (1-ε²)/ (1+ε cosine θ)]Newton and Hooke reiterated the same thing as Kepler and wrote: r/ t2 = k/r2

Astronomers found that the motion is not an ellipse but a rotating ellipseAnd wrote the equation of motion lawAs: r (θ, t) = [a (1-ε²)/ (1+ε cosine θ)]

Einstein wrote another acceleration law r/t2 = k/ r2 + k1 /r4 to describe a rotating ellipse

θr

Sun

Mercury



Newton gave the equation of the ellipse:As: r (θ, t) = [a (1-ε²)/ (1+ε cosine θ)]Einstein said he corrected Newton and wrote the new equation:

Is: r (θ, t) = a (1-ε²)/ [1+ε cosine (θ - Ψ)]

It is a fact that Astronomers see this axis tilt and Einstein got a formula for it: ψ = {6 πM/a c² (1 - ε²)} [180/ π] [36526/T (days)][3600] G = 6.673 x 10-11= gravitational acceleration constantM =2x1030kg = mass of the SunEccentricity of Mercury’s orbit = ε = 0.206T= 88 days = period of Planet mercury’s rotation around the SunAnd c = 299792.458 km/sec =light speed/secAnd a = 58.2 x 106 km/sec = semi major axis of planet Mercury orbitψ = {6 (π) 6.673 x 10-11 (2 x 1030)/58.2 x 106 (299792.458) ² [1– (0.206)²]} x [180/ π][36526/88] [3600] = 43 seconds of an arc per century

Newton used magical powers or action at a distance force F = Gm M/r2

Einstein said if Newton can add magical power then I can domagic powers of Newton and add Einstein’s own magicalpowers of time travel force and the forceIs F = G m M/r2 (space force) + k/r4 (time force)

Sun

ψ

Mercur y

θ



These two morons claim that what we see is due to magicwhere the Sun is pulling on the planets to keep them around?Did anyone see the Sun Pulling?Did anyone see a damn robe not the Sun hanging the planets torevolve around it but to hang these two idiots with Alfred Nobelphysicists?!

There is nothing Nobel about Alfred Nobelinstitution that gave prizes for magical forces and garbage forphysics.

Page 6I am not saying that Alfred Nobel physicists are idiots to say theleast but what I am saying is that Alfred Nobel prize winnerphysics is stupidity itself and Alfred Nobel prize winnerphysicists are crooks to be exact. Time is not a structure likespace to allow Alfred Nobel Institution to dictate stupidity onthe rest of us and Alfred Nobel Physicists can keep stupidity tothemselves. Alfred Nobel prize is worth 1001 times in money.Alfred Nobel prize is a 1 billion dollar business each. BigInstitutions with massive funding needs backed bad physicsand idiots for physicists for 1 billion dollars prize and the worldstuck with garbage for physics.What is modern physics?

Did anyone hear the big bang? Did anyone saw a black hole? Did anyone find Einstein’s gravity waves?Did anyone hook up a hose to the sky and funnel dark energy to verify E = mc2? Does anyone have a



proof of Newton’s action at a distance? Does anyone have a proof of Einstein time travel? Does anyonefigure out why humans have to accept Alfred Nobel prize winners nuclear claims that the universe ismade up of particles that dies and rebirth billion billion times a second? Hey dude I am a redneck onegrandfather was a damn farmer and my other grandfather was a damn Carpenter and my father was amuch damn redneck I sometimes feel reluctant to claim my dad but I never knew what a dumb ass is

really is till I met my science teacher talking about the greatest idiots of physics Newton and Einstein!What did Alfred Nobel honor?My answer to that is: “University” Crooks in Alfred Nobel SuitThe difference between a crook and a Nobel Prize winner is a flip of a coinThe difference between me and all others I can prove them crooks and I dare all to prove me wrong. Startingwith Einstein and Newton to make Galileo irrelevant to the subject of planetary motion around the Sun because of now and now is July 4th 1973 there is no Galileo and there is No Einstein and there is no Newton because I can prove them all wrong including NASA and Europeans space agency and all others!Newton’s space force: F = G m M/r2

Einstein’s – Newton space - time: F = G m M/r2 (Newton’s space force) + k/r4 (Einstein’s time force)

The force is with Joe Nahhas and in real time space F = 0

Nahhas said the only magic is an act of kindness of a human to all others!My act of kindness to humanity is to make humanity aware of the criminals with Nobel prizes and theidiots with intelligent portfolios!

What I am saying is that there is no Newton’s gravitationalforce and Einstein’s space – time force is silly to say the leastand I can prove that there is no gravitational force between theSun and the Planets force, or, F = o solution is a rotating ellipseIllusion.

What I am saying dear Pope John Paul is that those with“knowledge” and sick intentions to be arrogant and claimmagical forces and mocks the believers have absolutely no clue

what they see in their telescopes and have nothing to offerbeside stupidity that started with Newton and perfected withAlfred Nobel Institution’s dumbest Einstein. To start with let mesolve this equation F = 0. The solution of F = 0 is the equationof a real time circleIs r = r 0 e í (θ + ω t)

All there is in the Universe is objects of mass m moving in space (x, y, z) at a locationr = r (x, y, z). The state of any object in the Universe can be expressed as theproduct

S = m r; State = mass x location:P = d S /d t = m (d r /d t) + (dm/d t) r = Total moment





In polar coordinates systemr = r r (1) ;v = r' r(1) + r θ' θ(1) ; γ = (r" - rθ'²)r(1) + (2r'θ' + r θ")θ(1)

r = location; v = velocity; γ = accelerationF = m γ + 2m'v +m" r

F = m [(r"-rθ'²) r (1) + (2r'θ' + r θ") θ (1)] + 2m'[r' r (1) + r θ' θ (1)] + (m" r) r(1)

= [d² (m r)/dt² - (m r) θ'²] r (1) + (1/m r) [d (m²r²θ')/d t] θ (1)

= [-G m M/r²] r (1) -------------------- Newton's Gravitational Law

Page 8

Proof :First r = r [cosine θ î + sine θ Ĵ] = r r (1)

Define r (1) = cosine θ î + sine θ ĴDefine v = d r /d t = r' r (1) + r d[r (1)]/d t

= r' r (1) + r θ'[- sine θ î + cosine θĴ]= r' r (1) + r θ' θ (1)

Define θ (1) = -sine θ î +cosine θ Ĵ;And with r (1) = cosine θ î + sine θ ĴThen d [θ (1)]/d t= θ' [- cosine θ î - sine θ Ĵ= - θ' r (1)And d [r (1)]/d t = θ' [-sine θ î + cosine θ Ĵ] = θ' θ (1) Define γ = d [r' r (1) + r θ' θ (1)] /d t

= r" r (1) + r'd [r (1)]/d t + r' θ' r (1) + r θ" r (1) +r θ'd [θ (1)]/d t γ = (r" - rθ'²) r (1) + (2r'θ' + r θ") θ (1)

With d² (m r)/dt² - (m r) θ'² = F (r) And d (m²r²θ')/d t = 0

With m = constant, thenWith d² r/dt² - r θ'² = F (r) Eq-1 And d (r²θ')/d t = 0 Eq-2With d² r/dt² - r θ'² = 0 E q – 1And d (r²θ')/d t = 0 Eq-2From Eq-2: d (r²θ')/d t = 0Then r²θ' = h = constantDifferentiate with respect to timeThen 2rr'θ' + r²θ" = 0Divide by r²θ'

Then 2(r'/r) + θ"/θ' = 0And 2(r'/r) = - θ"/θ' = 2[λ (r) + ỉ ω (r)]



Also, r = r0 (θ, 0) e [λ (r) + ỉ ω (r)] t

And θ' = θ' 0 (θ, 0) e -2[λ (r) + ỉ ω (r)] t

For a fixed orbit: λ r = 0

Also, r = r 0 (θ, 0) e ỉ ω t

And θ' = θ' 0 (θ, 0) e -2ỉ ω t

With d² r/dt² - r θ'² = 0

Let u = 1/r; r = 1/u; r²θ' = h = θ’ /u²And d r/d t = (d r/ d u) (d u /d θ) (d θ/ d t) = (- 1/u ²) (θ’) (d u/ d θ)

= - h (d u/ d θ)

Page 9


With d² r/dt² - r θ'² = 0 E q – 1

And - h² u² (d² u/ d θ ²) – (1/u) (h u²) ² = 0Then (d² u/ d θ ²) + u = 0Then u = A e - í θ Then r 0 (θ, 0) = (1/A) e í θ And r 0 (θ, 0) = r 0 (0, 0) e í θ And r = r 0 (0, 0) e í θ e ỉ ω t Or, r = r 0 e í (θ + ω t) What I am saying Dear Pope is this is the equation of motion of any planet!

It is also the equation of motion of the smallest particle light!Now Planet Mercury motion is r m = r m 0 e í [θ (m) + ω (m) t]


Sun r r s Mercury

r1 r0 r m

X1 r2



X2

Earth

In mathematical form: r1 = x1 + r s

And r2 = x2 + r m

Then r2 - r1 = x2 - x1 + r m – r s

Or, r = r0 + (r m – r s)

Page 10

To find the extreme values of r,Then: d r/d t = d r0 /d t+ (d r m /d t – d r s / d t) = 0

And (d r m /d t – d r s / d t) = 0; d r0 /d t = 0

And d r m /d t = d r s / d tNow Planet Mercury motion is r m = r m 0 e í [θ (m) + ω (m) t]


And d r m /d t = r m 0 [θ’ (m) + ω (m)] e í [θ (m) + ω (m) t]

And d r s / d t = r s 0 [θ’ (s) + ω (s)] e í [θ (s) + ω (s) t]

With r m 0 [θ’ (m) + ω (m)] Cosine [θ (m) + ω (m) t]= r s 0 [θ’ (s) + ω (s)] Cosine [θ (s) + ω (s) t]

And r m 0 [θ’ (m) + ω (m)] sine [θ (m) + ω (m) t]

= r s 0 [θ’ (s) + ω (s)] sine [θ (s) + ω (s) t]Then dividing we get: tan [θ (n) + ω (n) t] = tan [θ (s) + ω (s) t]Or, [θ (m) + ω (m) t] = [θ (s) + ω (s) t] + [n π = 0; n =0]

And θ (m) - θ (s) + = [ω (s) - ω (m)] tThis is the time delay IllusionAnd, r m 0 [θ’ (m) + ω (m)] = r s 0 [θ’ (s) + ω (s)]



And [θ’ (s) + ω (s)] = (r m 0 /r s 0) [θ’ (m) + ω (m)]

And [θ’ (s) + ω (s)] - [θ’ (m) + ω (m)] = [(r m 0 /r s 0) -1] [θ’ (m) + ω (m)]

In arc second per century:

Is: [θ’ (s) + ω (s)] - [θ’ (m) + ω (m)] x (180/π) x (36526/88) x (3600)

= [(r m 0 /r s 0) -1] [θ’ (m) + ω (m)] x (180/π) x (36526/88) x (3600)

And, r m 0 [θ’ (m) + ω (m)] = r s 0 [θ’ (s) + ω (s)]

And r m 0 [θ’ (m) + ω (m)] = r e 0 [θ’ (e) + ω (e)]

Page 12

And [θ’ (s) + ω (s)] - [θ’ (e) + ω (e)] = [(r m 0 /r e 0) -1] [θ’ (m) + ω (m)]

In arc second per century:

Is: [θ’ (e) + ω (e)] - [θ’ (m) + ω (m)] x (180/π) x (36526/88) x (3600)= [(r m 0 /r e 0) -1] [θ’ (m) + ω (m)] x (180/π) x (36526/88) x (3600) = 43

r m 0

r s 0M M M Mercury S Sun

r m 0 r 0

Is: r 0 = distance between centers

Is: r max = r 0 + (r m 0 + r s 0)

And r min = r 0 - (r m 0 + r s 0)



And c = (r max - r min)/2 = r m 0 + r s 0


With c = (r max - r min)/2 = r m 0 + r s 0


This establishes visual ellipse of semi major axis a, and a semi minor axis;

b = √ (a² - c²) = a √ [1 – (c/a) ²] = a √ (1 – ε ²)

And h = 2 π a b = 2 π a² √ (1 – ε ²)Areal Velocity is: 2 π a² √ (1 – ε ²)/T



Figure - 1

And Farthest distance = r max = r 0 + (r m 0 + r s 0) = a + c

θr

Sun

Mercury



And closest distance = r min = r 0 - (r m 0 + r s 0) = a - c

At closest approach: h =2 π a² √ (1 – ε ²)/TAnd dividing h / (a – c) ² = 2 π a² √ (1 – ε ²)/T a² (1 – ε) ²Or r²θ' = h will give θ' (a) = 2 π √ (1 – ε ²)/T (1 – ε) ²

And for any motion θ' = θ' 0 (θ, 0) e

-2ỉ ω t

And θ’ = {[cosine 2 ω t + í sine 2 ω t] – 1} θ' 0 (θ, 0) And θ’ = θ’ (x) + í θ’ (y)

= [cosine 2 ω t + í sine 2 ω t] θ' 0 (θ, 0)And θ’ (x) = [cosine 2 ω t] θ' 0 (θ, 0)

= [1 – 2 sine² ω t] θ' 0 (θ, 0)

And θ’ (x) - θ' (0) = - 2 θ' 0 (θ, 0) sine² ω t= -2(2π) [√ (1-ε²)]/T (1-ε) ²] sine² ω t

= - 4 π [√ (1-ε²)]/T (1-ε) ²] sine² ω t

Page 15

If this apsidal motion is to be found as visual effects, then





nger Georges Lemaitre and Time traveler Albert Einstein and Real Timer Joe Nahhas

Time Travel Bus Driver Einstein said that his proudest space – time travelachievement is the proof that planet Mercury travels with space angular velocity of70.75 and time angular velocity of 43.0Big Banger Georges Lemaitre said that The Universe came from a Big Bang ExplosionJoe Nahhas said Buzz off:

Einstein greatest achievement in space said Planet Mercury angular speed travel in space is 70.75 and in time 43The Advance of Planet Mercury’s Perihelion given by space formula of:

[2 π/T] [180/π][36526/88][3600] = [2 π /88 x 24x3600] [180/π][36526/88][3600]= 70.75

And Einstein’s formula of: ψ = - 6 π GM/a c² (1 - ε²) [180/ π] [36526/T] [3600] = 43 angulavelocity = angular speed of time travel of planet Mercury

G = 6.673 x 10-11= gravitational acceleration constantM =2x1030 kilogram = mass of the SunEccentricity of Mercury’s orbit = ε = 0.206T= 88 days = period of Planet mercury’s rotation around the SunAnd c = 299792.458 kilometer/second =light speed in kilometers/secondAnd a = 58.2 x 106 km/sec = semi major axis of planet Mercury orbit

In my 5th grade I did this:

Angular velocity = θ’ 0 = θ’ 0 line - 1Visual angular velocity = θ’ = θ’ line - 2- Visual angular velocity = - θ’ = - θ’ line - 3

Add line - 1 and Line – 2 and line - 3

Then θ’ 0 = θ’ + (θ’ 0 - θ’); Divide by θ’

And (θ’ 0 / θ’) = 1 + [(θ’ 0 – θ’)/ θ’]; multiply by θ’ 0

Then (θ’ 0 / θ’) θ’ 0 = θ’ 0 + [(θ’ 0 – θ’)/ θ’] θ’ 0

Quantum = classical + relativisticAnd [(θ’ 0 – θ’)/ θ’] θ’ 0 = [(2πR0 /T– 2πR/T)/ 2πR/T] θ’ 0



Or, [(θ’ 0 – θ’)/ θ’] θ’ 0 = [(R0 - R)/R] θ’ 0R0 = Mercury’s distance from the sun = 5.82 x 106 kmR = Earth’s distance from the sun = 149.6 x 106 kmAnd Mercury’s angular velocity;Is θ’ 0 = 2πR0 /T = 2π x 5.82 x 106 /88x 24x3600 radians /period

And Mercury’s angular velocity accumulation in arc seconds per centuryIs: δθ’ 0 = (2π x 5.82 x 106 /88x 24x3600) x (36526/88) (180/ π) (3600) = 70.75[(R0 - R)/R] δθ’ 0 = [(5.82 x 106 - 149.6 x 106)/ 149.6 x 106] x(2π x 5.82 x 106 /88x 24x3600) x (36526/88) (180/ π) (3600) = 43.0 arc second per centuryWhere this came from?

It is called Arabs real time astronomy?





Observer line: …………………Observer ………………

If we stand in the middle of the street and watch a car moving directly away from us

we see as if the size of the car shrunk. If we take a picture of the car at different distances then we see that the pictures of the car look like as if the car contracted in

size. The further the car away from us the smaller image of the car in the picture. The

size of the





Is: [(R0 - R)/R] δθ’ 0 = [(5.82 x 106 - 149.6 x 106)/ 149.6 x 106] x(2π x 5.82 x 106 /88x 24x3600) x (36526/88) (180/ π) (3600) = 43.0 arc second per centuryAnother method is the product methodIf two objects going in two different orbital paths around the Sun and one with speed v*m = planet Mercury Orbital speed around the Sun and one with speed v* e = Planet Earthorbital speed around the Sun; then the cross multiply is: (v* e - v° e/v m + v° m) δθ’ 0 = [(29.8– 0.465)/47.9 + 0.465] (70.75) = 43Buzz off EinsteinThen came the big BangerThe big Banger said that: r = rAnd r = r + 0And r = r + (r0 - r0)And r = (r - r0) + r0; dividing by r0

Then: r/r0 = 1 +(r - r0)/r0

And: n λ /n λ 0= 1 + (n λ – n λ0)/ λ0Or, λ/ λ0 = 1 + (λ – λ0)/ λ0 = 1 + ZThis quantity [(λ - λ 0)/ λ 0] = Z = Red Shift is a measure of a different is an indicationof a different location and not of an expanding Universe to claim big bangDistant r, λ

Lab r0, λ0

…………………………………………………………………………………………………………………….

Lab λ0 will have a different value Lab λ0 when measured from a distant.

That is: (r/r0) λ 0= λ 0 + [(r – r0)/ r0] λ0Or, (λ / λ 0) r 0= r 0 + [(λ – λ 0)/ λ 0] r0

The conclusion is that if we use distance scale to measure wavelength λ0

We will measure it as λ and a wavelength distance Illusion delay by the quantity of [(r –r0)/ r0] λ0 will be added or subtracted to λ0

And if we use wavelength scale to measure distance r0; then a distance wavelengthIllusion delay by the quantity of [(λ – λ 0)/ λ 0] r0 will be added or subtracted to distancer0

What Lemaitre confusion is distance Illusion expansion of [(λ – λ 0)/ λ 0] r0 when he triedto measure r0



Nahhas confession to these two: “I am real timer and I am a proud American redneckand yall Idiots; Big Bang and Time Travel is a purely western stupidity”

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Secretary of energy 1997 Nobel Prize Winner Dr Steven Chu crimes