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 INSTITUTO POLITÉCNICO NACIONAL ESCUELA SUPERIOR DE CÓMPUTO  ANALOG ELECTRONICS PRACTICE #2 RECTIFIERS PROFESSOR: JOSE ALFREDO MARTINEZ GUERRERO GROUP: 2CV5  AURIOLES DELGA DILLO, MAURICIO JOEL JIMENEZ SANDOVAL, EDUARDO SCHOOL CYCLE 2013-2014/2 FEBRUARY 27 OF 2014

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INSTITUTO POLITÉCNICO NACIONAL

ESCUELA SUPERIOR DE CÓMPUTO

ANALOG ELECTRONICS

PRACTICE #2

RECTIFIERS

PROFESSOR: JOSE ALFREDO MARTINEZ GUERRERO

GROUP: 2CV5

AURIOLES DELGADILLO, MAURICIO JOEL

JIMENEZ SANDOVAL, EDUARDO

SCHOOL CYCLE2013-2014/2

FEBRUARY 27 OF 2014

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OBJECTIVES

The objectives of this practice are:

Analyze how rectifiers work with different diodes.

Analyze the behavior of different rectifiers with integration filter. Make an interpretation of the obtained values and the theoretical ones.

MATERIAL AND EQUIPMENT

MATERIAL1 Proto board4 1N4003 diodes112V @ 1A Transformer with central derivation1 100Ω @ 10W Resistance

1 22Ω @ 25W Resistance 1 470µF @ 50V Electrolytic Capacitor1 2200µF @ 50V Electrolytic Capacitor

EQUIPMENT1 Digital multimeters1 General purpose Oscilloscope2 BNC-Alligator cables for oscilloscope6 alligator-alligator cables

INTRODUCTION

Most of the electronic devices, televisions, stereo equipment and computers needa DC voltage to run continuously.

As voltage lines are alternate, the first thing to do is to convert the alternatingvoltage into DC voltage.The circuits that allow current to flow in one direction are called rectifiers.Now, the analysis of diodes should be extended to include the variable functions intime, such as the sine wave shape.

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HALF-WAVE RECTIFIER

Half-wave rectifier is a circuit that eliminates half of thereceived signal at the entrance, depending on how is

polarized the diode: If the polarization is direct, eliminatethe negative part of the signal, and if the polarization isreverse, remove the positive part.

HALF-WAVE RECTIFIER WITH INTEGRATIONFILTER

A RC circuit serves as a filter to make the alternating voltage become direct almostlike a battery, this is thanks to the small oscillations the output voltage has, whichare practically nil.The first part of the circuit consists of an AC voltage source, followed by a diodethat on this occasion will be ideal (simply to facilitate the understanding of theoperation) and finally the RC filter.The circuit works in the following way:1. enter the AC signal to the circuit, which is

rectified with diode. (Only allows passing a semi-cycle of the signal, which in this case is thepositive semi-cycle)

2. at the moment coming voltage diode capacitorbegins to charge and the voltage drop is receivedin the resistance.

3. to understand what is happening and howcalculate the filter.

WAVE RECTIFIER COMPLETE WITH CENTER TAPFull-wave rectifier used both halves of the wave input senoid; for unipolar output,inverts the negative semiciclos of the sine wave. In this application used for thecentral winding of the transformer with the purpose of obtaining two voltages vs.equal, in parallel with the two halves of the secondary winding with the indicatedpolarities.The most important thing is that the current flowing through the load always goesthrough the same direction and voltage Vo is unipolar. The output waveform isobtained by assuming that a conductive diode has a constant drop of voltage VDO,i.e., you despise the effect of load.

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FULL WAVE BRIDGE RECTIFIERIt is a rectifier full wave in which, unlike the previous, only necessary transformer ifthe output voltage should be a value other than the input voltage.In order to facilitate the explanation of the operation of this circuit, we are going tocall D-1 diode located above and D-2, D-3 and D-4 the following in descendingorder.

o During the half cycle in which the upper point of the secondary of thetransformer is positive with respect to the lower secondary said, the currentflows through the following way:

Top point of the secondary - > diode D-1 - > (+) R(-) load resistance - > diode D-4 -

> bottom point of the secondary.o In the next half-cycle, when the upper point of the secondary is negative and

the positive bottom it will do this by:Lowest point of the secondary - > diode D-2 - > (+) R (-) load resistance - > diodeD-3 - > upper point of the secondary.In this case, we see how current it circulates by charging, in the same sense, thetwo semiciclos, which both take advantage and gets a ground current more uniformthan in the case of the half-wave rectifier, where during a half-cycle the current flowis interrupted by the load.

In both types of full-wave rectifiers, the rectified output current waveform, is likely tobe a continuous pulse current, but with a frequency of double pulse of current ACpower.

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TYPE BRIDGE FILTER INTEGRATION WITH FULL-WAVE RECTIFIER.The C is always put in parallel with the RL. The circuit and the graphs are asfollows:

It is similar to the previous one, it changes the value of i T. Drive D1 and D3 positiveand lead D2 and D4 in the negative half-cycle. On the transformer the same windingsuffers the intensity, then has to endure all the intensity, but sometimes up andothers down. You have to design the winding of the secondary thread so that they

can withstand those positive and negative peaks.

PRACTICE DEVELOPMENT

Transformer Assemble the following circuit:

Place a resistance of load according to the table and place the meter in terminals 1and 2 of the circuit and measure voltage at the AC option.

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100Ω 15.10v22 Ω 14.35v

Half-wave rectifier Assemble the following circuit:

Place a resistance of 100 Ω.

Connect the multimeter terminals 2 and 3 of the circuit and measure CD optioncurrent (I0) and the output voltage V0 rectifier circuit

and calculate

Then place the channel 1 of oscilloscope in terminals 1 and 3 and channel 2 in

points 2 and 3.

Draw both channels

10 V/div channel 1

10V/div channel 2

10 mseg/div

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Get the voltage peak of the channel 1 signal transformer

Get the peak voltage less channel 2 diode voltage

With integration filter half-wave rectifier

Assemble the following circuit:

Place a 100 Ω resistor and capacitor according to the table. Connect the meter in terminals 1 and 2 of the circuit, measure in the current CD

option and voltage of the circle rectifier with filter

Capacitor 470µF 17.30v .163A 1.063v2200 µF 18.24v .78A 0.0606v

Then place the channel 1 of oscilloscope in terminals 1 and 2 on the AC option

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Get the ripple voltage of the output signal and record it in the table above

Full-wave rectifier with two diodes Assemble the following circuit:

Place a 100 Ω resistor and capacitor according to the table. Connect the multimeter terminals 2 and 3 of the circuit, measure in thecurrent CD option and voltage the signal output rectifier circuit

and calculate

Draw cannel 1 with the 470µF capacitor Draw cannel 1 with the 2200µF capacitor

2 V/div canal 1

10 mseg/div

0.5 V/div canal 1

10 mseg/div

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Then replace the channel 1 of oscilloscope in terminals 1 and 3 and channel 2 inpoints 2 and 3, draw both channels

Get the voltage peak of the channel 1 signal transformer

Get the peak voltage less channel 2 diode voltage

Full-wave rectifier with two diodes with filter integration

Assemble the following circuit

Place a 100 Ω resistor and capacitor according to the table. Connect the meter in terminals 1 and 2 of the circuit, measure in the current

CD option and voltage of the circle rectifier with filter

5 V/div canal 1

5 V/div canal 1

5 mseg/div

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Capacitor 470µF 9.59v 89.7mA 0.0203v2200 µF 9.86v 92mA 0.2656v

Then place the channel 1 of oscilloscope in terminals 1 and 2 on the AC option

Get the ripple voltage of the output signal and record it in the table above

Wave rectifier full bridge Assemble the following circuit:

Draw cannel 1 with the 470µF capacitor Draw cannel 1 with the 2200µF capacitor

100mV/div channel 1

2 mseg/div

500mV/div canal 1

2 mseg/div

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Place a 100 Ω resistor and capacitor according to the table. Connect the meter in terminals 3 and 4 of the circuit, measure in the current CD

option and voltage of the circle rectifier with filter

and calculate

Then place the channel 1 of oscilloscope in terminals 1 and 3 and channel 2 inpoints 2 and 3.

Get the voltage peak of the channel 1 signal transformer

Get the peak voltage less channel 2 diode voltage

10 V/div channel 1

5 V/div channel 1

5 mseg/div

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Full-wave rectifier type bridge integration filter Assemble the following circuit:

Place a 100 Ω resistor and capacitor according to the table.

Connect the meter in terminals 1 and 2 of the circuit, measure in the currentCD option and voltage of the circle rectifier with filter

Capacitor 470µF 18.03v 17.02mA 2.216v2200 µF 18.48v 172.1mA 0.1006v

Then place the channel 1 of oscilloscope in terminals 1 and 2 on the AC option

Get the ripple voltage of the output signal and record it in the table above

Draw cannel 1 with the 470µF capacitor Draw cannel 1 with the 2200µF capacitor

1V/div channel 1

5 mseg/div

0.2V/div channel 1

5 mseg/div

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CALCULATIONS

QUESTIONNAIRE

CONCLUSIONS

Eduardo JimenezEn esta práctica, observamos cada una de las gráficas de los distintos diodosrectificadores y su voltaje de rizo, con respecto a las gráficas vimos como era suvoltaje de entrada y al pasar por el rectificador, su grafica en el voltaje de salidacambiaba.

Mauricio AuriolesEn la segunda práctica, usamos los diferentes tipos de rectificadores. Armamosdiferentes circuitos para reconocer las gráficas que nos daba en el osciloscopio.

Es importante aprender cada una de sus graficas porque la mayoría nos dabanuna de entrada y una de salida, por lo que conectamos los circuitos en los doscanales del osciloscopio. Medimos voltajes en las diferentes resistencias de cargay corrientes de salida de cada uno de los circuitos; y finalmente, calculamos losvoltajes de rizo utilizando los valores obtenidos.