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7/31/2019 Module 8A - Circular Measure
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CIRCULAR MEASURE FORM 4
PROGRAM KECEMERLANGAN AKADEMIK (szk smkpn) Page 1
MODULE 8(A)ADDITIONAL MATHEMATICS
TOPIC : CIRCULAR MEASURE
1.
The diagram shows a circle with centre O. The reflex angle POQ is 1.2π rad and thelength of the minor arc PQ is 16π cm. Find the radius of the circle.
[3 marks][Answer : 20cm ]
2.
The diagram shows a circle PAQ with centre O, of radius 8 cm. SR is an arc of a circlewith centre O. The reflex angle POQ is 1.6π radians. Given that P and Q are midpointsof OS and OR respectively, find the area of shaded region, giving your answer in termsof π
[3 marks][Answer : 38.4π ]
3.
Diagram shows sectors OAB and OXY with centre O. It is given that OA = 8 cm, OX =4 cm, ∠ AOB = 1.2 radians and the length of arc XY = 3.2 cm. Calculatea) the value of θ, in radian,
b) the area, in cm², of the shaded region. [4 marks]
O
P
Q
1.2π 16π cm
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[Answer :a) 0.8 b) 32 ]
4.
Diagram shows two sectors in which the arcs PQ and RS are arcs of two concentriccircles with centre O. Given that PR = QS = 4 cm, the length of arc PQ = 10 cm and
∠ POQ =1
2radian. Calculate
a) the length of arc RS, in cm,
b) the perimeter, in cm, of the shaded region.[4 marks]
[Answer :a) 17 b) 30 ]
5.
Diagram shows two sectors OBC and OAD with common centre O. The length of thearc BC is 6 cm and OA : AB = 3 : 1, finda) the length of OB,b) the perimeter of the shaded region.
[3 marks][Answer :a) 8 b) 14.5 ]
6.
Diagram shows sector of a circle with centre O and OAC is a right-angled triangle.Given that OA = 10 cm and BC = 4 cm, calculatea) the value of θ, in radian,
b) the area, in cm², of the shaded region. [4 marks]
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[Answer :a) 0.9273 b) 22.37 ]
7.
Diagram shows a circle with centre O. It is given that the radius of the circle is 5 cmand the length of the chord AB is 7 cm. Find
a) ∠ AOB in radians,
b) the area of the shaded segment[4 marks]
[Answer :a) 1.5508 b) 6.888 ]
8.
Diagram shows a sector of a circle with centre A. Given that the ratio of the length ofarc PQ to radius is 2:3, find the value of θ in radians and the radius of the sector whenthe area of sector APQ is 19.45 cm².
[4 marks]
[Answer : 2
3 ]
9.
Diagram shows a circle with centre O. Given the length of the major arc AB is 54.32cm. Find the length, in cm of the radius. (use π=3.142)
[4 marks][Answer : 9.311 ]
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10.
Diagram shows a semicircle with centre O. Given the diameter POR = 8 cm and thelength of arc PQ is 3.87 cm. Find
a) the value of θ, in radian,b) area of the sector OQR.
[4 marks][Answer :a) 0.9675 b) 17.4 ]
11.
Diagram shows sector PAQ with centre A. The length of radius is 5.8 cm and theperimeter of the sector is 18 cm. Find the value of θ, in radians.
[3 marks][Answer :1.103 ]
12.
Diagram shows a semicircle with centre O. Given the length of AC is 20.5 cm. Find thelength of the diameter AB correct to two decimal places.
[3 marks][Answer : 17.90 ]
13.
Diagram shows a circle with centre O. PR and QR are tangents to the circle at points Pand Q respectively. Given OR = 12 cm and ∠ PRQ = 0.8 radian . Find
(a) the radius, in cm , of the circle(b) the area , in cm 2 , of the shaded region
[ 4 marks ]
[Answer :a) 4.673 b) 25.57 ]
Q
P
O R
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14.
Diagram shows a circle with centre O and radius 5 cm. Given that AB is a tangent tothe circle at A and the length of OB is 10 cm, find
a) the angle θ in radians,b) the area of the shaded region.
[3 marks]
[Answer :a)
3
π b) 8.56 ]
15.
Diagram shows two sectors OAD and OBC with centre O. Given that OD=5 cm, DC=3
cm and ∠ BOC=6
πradians, find the area of the shaded region in terms of π .
[3 marks]
[Answer : 13
4
π ]
16.
Diagram shows two sectors with centre O. Given that OC=5cm, CB=x cm,
∠ AOB= ∠ COD and AB:CD = 3:1, find the value of x.[3 marks]
θ 5 cm
O A
C
B
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[Answer :10 ] 17.
Diagram shows the semicircle ABCD with centre O and radius 7 cm. If the length ofarcs AB, BC and CD are the same, find the perimeter of the shaded region.
[4 marks][Answer : 26.45 ]
18.
Diagram shows a circle with centre O and radius 8.5 cm. Given that the area of theminor sector OPQ is 64 cm², find the length of the major arc PQ.
[4 marks][Answer : 38.35 ]
19.
Diagram shows a sector LOM with centre O. The length of arc LM is 14.25 cm and theperimeter of the sector LOM is 34.25 cm. Calculate the value of θ, in radian.
[3 marks][Answer :1.425 ]
20.
Diagram shows a circle with centre O. Given that the length of the major arc is 48.24cm, find the radius, in cm. (use π = 3.142)
[3 marks]
[Answer : 8.249 ] END OF MODULE
25˚
P
O
Q
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ANSWERSMODULE 8(A)
ADDITIONAL MATHEMATICSTOPIC : CIRCULAR MEASURE
1. 2 1.2 0.8
16 (0.8 )
20
r
r cm
π π π
π
− =
=
=
2.
2 2
2 1.6 0.4
1 116 0.4 8 0.4
2 2
38.4
π π π
π π
π
− =
= × × − × ×
=
3. a) 3.2 4
3.2
4
0.8
θ
θ
=
=
=
b)2 21 1
8 1.2 4 0.82 2
32
= × × − × ×
=
4. a)
( )
1020
12
120 14
2
17
OP
RS
= =
= + ×
=
b) =10 + 4 + 12 + 4=30
5. a) 6 0.75
6
0.75
8
r
r
=
=
=
b) =2 + 6 + 2 + 6(0.75)=14.5
6. a) 6cos
10
0.9273
θ =
=
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b)21 1
10 0.9273 6 82 2
22.37
= × × − × ×
=
7. a) 3.5sin
5
0.7754
2(07754) 1.5508
COB
COB
AOB
∠ =
∠ =
∠ = =
b)
2
OC 5 cos0.7754 3.57071
1 15 1.5508 7 3.570712 2
6.888
= × =
= × × − × ×
=
8. 2(19.45)
23
7.639
2
3
2
3
r
r
r
θ
θ
=
=
=
=
9. 2 0.45
5.834
s r
r(5.834) 54.32
r 9.311
θ = π −
=
= θ
=
=
10. a)
3.87 4
0.9675
s r
rad
θ
θ
θ
=
=
=
b)( ) ( )
214 2.175
2
17.4
A =
=
A
B
C
O
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11. ( )PQ 18 2 5.8
6.4
s
j6.4
5.8
1.103
= −
=
θ =
=
=
12. AOC 0.85
2.29rad
20.5 j
2.29
8.95
AOB 2(8.95)
17.90
∠ = π −
=
=
=
=
=
13. a) OP = Sin 22.92º (12)= 4.673 cm
b)A = 21
(4.673) (2.342)2
= 25.57 cm²
14. a) 5 1Cos10 2
rad3
θ = =
πθ =
b)
( )
2
2
2
2
1Areaof OAB 5 10 sin
2 3
21.65cm
1Areaof sector OAC 5
2 3
13.09cm
Areaof shadedregion 21.65 13.09
8.56cm
π= × × ×
=
π =
=
= −
=
15.
2
1 1A 8 8 5 5
2 6 2 6
13units
4
π π = × × × − × × ×
π=
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16.
( )
AB :CD 3 :1
5 x 3
5 1
x 10cm
=
+ θ=
θ
=
17. 7ArcBC 7 cm
3 3
CQsin
3 7
7 3CQ cm
2
OQCos
3 7
7OQ cm
2
Perimeter of shadedregion
7 7 3 72 2
3 2 2
26.45cm
π π= × =
π=
=
π=
=
∴
π = + +
=
18.
( )
21 8.5 642
1.772rad
PQ 8.5 2 1.772
38.35cm
× × θ =
θ =
= π −
=
19. 34.25 14.25r OL OM 10cm
2
14.251.425rad
10
−= = = =
θ = =
20. Angle subtend by major arc PQ=360˚ - 25˚ = 335˚
335180
5.848rad
s r
sr
48.248.249cm
5.848
π= ° ×
°
=
= θ
=θ
= =
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END OF MODULE