Mer 3 Kelompok 1 2mrk 1 (Kestibu)

8/17/2019 Mer 3 Kelompok 1 2mrk 1 (Kestibu)

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KELOMPOK1

Konstruksi Rangka Batang

Metode Kesetimbangan Titik Buhul

MER 3

Achmad Rizki Hidayatullah (1441320088)BayuPratama (1441320100)

Hidayatur Rahmatillah Arifn (1441320119)

Nurul ntan !una"arah (144132000#)


2/22

► SUMBER ◄

http://www.kaskus.co.id/thread/5271f908fcca17813e000004/tempat-

o!kro!"a-pamerhati-mekaika-tekik-aa#isis-struktur/17


3/22

$otoh &oa# $%ntukanlah &%'araya &atan

(m%td% k%'ti&u)aki&at &%&an yan

di*ikul 'trukturt%r'%&ut


4/22

PENYELESAIAN

1+ 'ecari (eaksi

)'* + 0

,1 315 ,2 912 1 4812 (.1 + 0

4 . 18 . 27 15 . 24 1 ( + 0

,H - 0RAH - 2.1 / 3.2

- 2 + 4 / 3 + - 2 $ ()

, - 0RA / RB - 3P1

RA / 3#12 - 3 + 1RA - #8# (5)

125.37

1

594↑== T RBV


5/22

) + 0

1 &1 si + 0

15 &1 . 069 + 0

&1 + -156527 eka

&i + $os +

$os + &i +

) + 0

,1 & &1 cos + 0

4 & 156527 . 06257 + 0

& + -76990 eka

•


6/22

) + 0

1 &27 si + 0

15 &27 . 069 + 0

&27 + -156527 eka

) + 0

- &17 &27 cos + 0

- &17 - 156527 . 06257 + 0

&17 + -36990 eka


7/22

) + 0

1 &7 cos &18 cos + 0

15 &7 . 06529 &18 . 06529 + 0

&7 &18 + -286355 ;

-6 7 6# 'in / 618 'in / 61# - 0

7,990–6# + 084# / 618 + 084# 7

3990 - 0-0,8476# / 084# 618 - 42

6# 7 618 - 4#22 ()

∑H - 0

6# / 618 - 283

6# 7 618 - 4#22

26# - 2333

6# - 1181 $ ($%kan)

618 - 139 $ ($%kan)

:limina'i P%r'amaan dan

&i + $os +

$os + &i +


8/22

) + 0

-&1 cos < &7 si < &2 si + 0

156527 . 069 11681 . 06529 &2 069 +

0

&2 + -216997 eka

.2 / 68 / 6# c' ; / 61 'in


9/22

) + 0

-&18 si < &27 cos < &28 si + 0

16539 . 06529 156527 . 069 &28 . 069 + 0

&28 + -246584 eka

-619 7 618 c' ; 7 62# 'in


10/22

) + 0

&9 cos = &10 cos = + 0

&9 &20 + 0 ;;;

-68 7 69 'in = / 620 'in = / 619 - 0

-2,345–69 + 0881 / 620 + 0881 /1180 - 0

-0,88169 / 0881 620 - 933A

69 7 620 - 109 ( )

∑H - 0


69 / 620 - 0

69 7 620 - 109

269 - 109

69 - 29# $ ($arik )

620 - 29# $ ($%kan)

&i = + $os = +

$os = + &i = +


11/22

) + 0-&2 cos &9 si = &3 si + 0

216997 . 069 56297 . 06472 &3 . 069

+ 0

&3 + -196408 eka

.2 / 62 'in / 69 c' => / 610 7 63 c' < - 0

6–21,997.0,257+5,297.0,881+610 / 19408 +

02# - 0610 - 10001 $ ($%kan)

∑H - 0


12/22

) + 0

-&28 si &20 si = &29 si + 0

246584 . 069 56297 . 06472 &29 . 069 + 0

&29 + -276172 eka

-628 'in 7 620 c' => 7 621 / 629 c' < - 0

24,584.0,257+5,297.0,881–621 7 2#1#2 + 02# - 0

621 - 4001 $ ($arik )

∑H - 0


13/22

) + 0

&11 cos a &22 $>& a + 0

&11 &22 + 0

-610 7 611 'in a / 622 'in a / 62110,001–611 + 090 / 622 + 090 /

4001 - 0-0,905)611 / 622( = -14,002

611 7 622 - 14#1 ( )

∑H - 0

611 / 622 - 0

611 7 622 - 14#1

2611 - 1 4#1

611 - ##3 $ ($arik )

622 - ##3 ($%kan)


&i a + $os a +

$os a + &i a +


14/22

) + 0

-&3 cos &11 si a &4 si + 0

196408 . 069 76735 . 06424 &4 . 069 + 0

&4 + -16012 eka

.2 / 612 / 611 c' a> / 63 'in 7 64 c' < - 0

6+612 / ##3 + 090 7 19408 + 02# /1012 + 02# - 0612 - 1212# ($%kan)

∑H - 0


15/22

) + 0

-&22 si a &29 cos &30 si + 0

76735 . 06424 276172 . 069 &30 . 069 + 0&30 + -30657 eka

-623 7 622 c' a> 7 629 'in / 630 c' < - 0

-623 / ##3 + 090 / 2#1#2 + 02# 7 30# + 02# - 0

623 - 12# $ ($arik )

∑H - 0


16/22

) + 0

&13 cos ? &24 cos ? + 0

&13 &24 + 0 ;;

-612 7 613 'in & / 624 'in & / 623 -

012,127–613 + 0923 / 624 + 0923 /

12# - 0-0,923)613 7 624( = -18,254

613 7 624 - 19## ( )

∑H - 0

613 / 624 - 0613 7 624 - 19##

2613 - 19##

613 - 9888 $ ($arik )

624 - 9888 $ ($%kan)


&i ? + $os ? +

$os ? + &i ? +


17/22

) + 0

-&4 cos &13 si ? &5 si + 0

16012 . 069 96888 . 06384 &5 . 069 + 0

&5 + -126081 eka

.1 / 614 / 613 c' &> / 64 'in 7 6 c' < - 0

4+614 / 9888 + 0923 7 1012 + 02# / 12 081 +

02# - 0614 - 12 11 $ ($%kan)

∑H - 0


18/22

) + 0

-&30 cos &24 si ? &31 si + 0

30657 . 069 96888 . 06384 &31 . 069 + 0&31 + -346497 eka

-62 7 624 c' &> 7 630 'in / 631 c' < - 0-62 / 9888 + 0923 / 30# + 02# 7 3449# +

02# - 062 - 811 $ ($arik )

∑H - 0


19/22

) + 0

&15 cos c &2 cos c + 0

&15 &2 + 0 ;@

-614

7 61

'in c / 62

'in c / 62

- 0

12,116–61 + 093 / 62 + 093 /

811 - 0-0,936)61 7 62( = -20,232

61 7 62 - 211 (?)

∑H - 0

61 / 62 - 061 7 62 - 211

261 - 211

61 - 1080# $ ($arik )

62 - 1080# $ ($%kan)

:limina'i P%r'amaan ? dan ?

&i c + $os c +

$os c + &i c +


20/22

) + 0

( *

&1

&15

cos c &5

si + 0

2 &1 106807 . 0693 126081 . 06257 + 0

&1 + -336010 eka


21/22

a?e# Aesimpu#a erhitu!aNomer batang Besar gaya batang (ton Nomer batang Besar gaya batang (ton

$arik (/) $%kan () $arik (/) $%kan ()!1 12# 61 33010

!" 2199# 61# 3990

!3 19408 618 1+39

!# 1012 619 1180

!$ 12081 620 29#

!% #990 621 4001 0

!& 1181 622 ##3

!' 234 623 12#

! 29# 624 9888

!1) 10001 62 811

!11 ##3 62 1080#!1" 1212# 62# 12#

!13 9888 628 2484

!1# 1211 629 2#1#2

!1$ 1080# 630 30#

631 3449#


22/22

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Mer 3 Kelompok 1 2mrk 1 (Kestibu)