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Mathcad rezolvari probleme biotehnologii
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Nr . 1.
Rezolvare prob. 1.
Vm 0.250:= m3
Transformare concentratie 1M (2pct)
m 1080:=kg
m3 Macid 12 2 4+ 16 2+:=
g
mol
kgacid
kmolacid
cfgl 0.2:=apa 1000:=
kg
m3cigl 0.5:= considerata densitatea solutiei de acid
cfacid0.7
100:=
ciacidmolar 1:=mol
L
kmolacid
m3
ciacidciacidmolar Macid
apa:=
kg acid
kgsolutie
mm m Vm:= kg
mm 270= Kg
Bilant partial pe glucoza (3pct) Bilant partial pe acid (3pct)
mgl mmcfgl
cigl:= macid mm
cfacid
ciacid:=
mgl 108= Kg macid 31.5= kg
Bilant Total (1pct)
mapa mm mgl macid:=
mapa 130.5= Kg
Rezolvare prob. 2 (1.5 pct pentru fiecare randament stoechiometric calculat corect)
Ms 6 12 12+ 6 16+:=g
mol
Mn 14 3+:=g
molgCs 0.85 230:=
Mx 12 1.737+ 14 0.2+ 16 0.451+:=g
molCn
Mn 0.118 Cs
Ms:=
Mp2 3 12 8+ 3 16+:=g
mol
CxMx 0.59 Cs
Ms:=
Mco 12 16 2+:= g
mol
Mp1 12 2 6+ 16+:=g
mol Cp20.432 Mp2 Cs
Ms:=
Mw 2 16+:=g
molCco
1.54 Mco Cs
Ms:=
YsxCx
Cs:=
Ysx 0.078=Cp1
1.3 Mp1 Cs
Ms:=
Ysp1Cp1
Cs:=
Ysp1 0.332=Cw
0.036 Mw Cs
Ms:=
Ysp2Cp2
Cs:=
Ysp2 0.221=
YscCco
Cs:=
Ysc 0.376=
YswCw
Cs:=
Ysw 3.6 103
=
Ynp2Cp2
Cs:=
Ynp2 0.221=
Rezolvare prob. 3
M 500:= kg
T0 20 273+:= K
cpm 0.88 4.186:=kJ
kg K0.5 pct
H 2735:=kJ
kg
D190
3600:=
kg
s0.5 pct
25 60:= s 0.5 pct
H D
cpm M T0:=
2.675 104
= 2 pct
D
M:=
2 pct 1.056 10
4=
Ts T0 1
1 ++
:= 3 pct
Ts 394.488= K
ts Ts 273:=
ts 121.488= o C 0.5 pct