Nr . 1.

Rezolvare prob. 1.

Vm 0.250:= m3

Transformare concentratie 1M (2pct)

m 1080:=kg

m3 Macid 12 2 4+ 16 2+:=

g

mol

kgacid

kmolacid

cfgl 0.2:=apa 1000:=

kg

m3cigl 0.5:= considerata densitatea solutiei de acid

cfacid0.7

100:=

ciacidmolar 1:=mol

L

kmolacid

m3

ciacidciacidmolar Macid

apa:=

kg acid

kgsolutie

mm m Vm:= kg

mm 270= Kg

Bilant partial pe glucoza (3pct) Bilant partial pe acid (3pct)

mgl mmcfgl

cigl:= macid mm

cfacid

ciacid:=

mgl 108= Kg macid 31.5= kg

Bilant Total (1pct)

mapa mm mgl macid:=

mapa 130.5= Kg

Rezolvare prob. 2 (1.5 pct pentru fiecare randament stoechiometric calculat corect)

Ms 6 12 12+ 6 16+:=g

mol

Mn 14 3+:=g

molgCs 0.85 230:=

Mx 12 1.737+ 14 0.2+ 16 0.451+:=g

molCn

Mn 0.118 Cs

Ms:=

Mp2 3 12 8+ 3 16+:=g

mol

CxMx 0.59 Cs

Ms:=

Mco 12 16 2+:= g

mol

Mp1 12 2 6+ 16+:=g

mol Cp20.432 Mp2 Cs

Ms:=

Mw 2 16+:=g

molCco

1.54 Mco Cs

Ms:=

YsxCx

Cs:=

Ysx 0.078=Cp1

1.3 Mp1 Cs

Ms:=

Ysp1Cp1

Cs:=

Ysp1 0.332=Cw

0.036 Mw Cs

Ms:=

Ysp2Cp2

Cs:=

Ysp2 0.221=

YscCco

Cs:=

Ysc 0.376=

YswCw

Cs:=

Ysw 3.6 103

=

Ynp2Cp2

Cs:=

Ynp2 0.221=

Rezolvare prob. 3

M 500:= kg

T0 20 273+:= K

cpm 0.88 4.186:=kJ

kg K0.5 pct

H 2735:=kJ

kg

D190

3600:=

kg

s0.5 pct

25 60:= s 0.5 pct

H D

cpm M T0:=

2.675 104

= 2 pct

D

M:=

2 pct 1.056 10

4=

Ts T0 1

1 ++

:= 3 pct

Ts 394.488= K

ts Ts 273:=

ts 121.488= o C 0.5 pct