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ACI 318 RECTANGULAR BEAM DESIGN DESIGN OF REINFORCED CONCRETE BEAM TABLE OF CONTENTS PAGE CONTENTS 2 A. INPUT DATA 4 B. DESIGN LOADS 5 C. ANALYSIS RESULTS 7 D. SUMMARY Design of Reinforced Concrete Beam Page 1 of 7 LNT4 - Dec.2011

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  • ACI 318RECTANGULAR BEAM DESIGN

    DESIGN OF REINFORCED CONCRETE BEAMTABLE OF CONTENTS

    PAGE CONTENTS2 A. INPUT DATA

    4 B. DESIGN LOADS

    5 C. ANALYSIS RESULTS

    7 D. SUMMARY

    Design of Reinforced Concrete Beam Page 1 of 7 LNT4 - Dec.2011

  • ACI 318RECTANGULAR BEAM DESIGN

    A. INPUT DATA

    A.1 MATERIAL PROPERTIESConcrete:

    Compressive Strength fc' 21MPa:=Modulus of Elasticity Ec 4700 fc' MPa:= Ec 21538MPa=Concrete strain c 0.003:=

    Reinforcing Steel:

    Yield Strength of Steel fy 275MPa:=Modulus of Elasticity Es 2 10

    5MPa:=

    Capacity Reduction Factor

    Shear v 0.85:=Flexure f 0.90:=

    A.2 BAR DESIGNATIONS, SIZES AND AREASTableNo 0 1 2 3 4 5 6 7 8 9 10db (mm) 0 0 8 10 12 16 20 22 25 28 30As (mm) 0 0 50 100 127 200 300 387 500 616 700

    No NoT:= dia dbT mm:= As AsT mm2:=

    Example for bar at bar 4:= Nobar 4=Bar diameter is: diabar 12mm=Area of bar is: Asbar 127mm

    2=

    A.3 BEAM DIMENSIONSBeam width b 200mm:=Beam height h 300mm:=

    A.4 BEAM REINFORCEMENTSCONCRETE COVER TO STIRRUPS cc 40mm:=STIRRUPS

    3Tie bar designation no.

    Tie diameter diaTies 10mm=

    Area of one (1) tie bar AsTies 100mm2=

    Design of Reinforced Concrete Beam Page 2 of 7 LNT4 - Dec.2011

  • ACI 318RECTANGULAR BEAM DESIGN

    TENSILE REINFORCEMENTS

    3No. of bars

    5Bar designation no.

    Bar diameter diabarT 16mm=Area of one (1) bar AsbarT 200mm

    2=

    Total area of tension bars As NT AsbarT:= As 600mm2=

    Depth to tensile reinforcements d h cc diaTies+diabarT

    2+

    := d 242mm=

    COMPRESSION REINFORCEMENTS

    2No. of bars

    5Bar designation no.

    Bar diameter diabarC 16mm=Area of one (1) bar AsbarC 200mm

    2=

    Total area of compression bars As' NC AsbarC:= As' 400mm2=

    Depth to compression reinf. d' cc diaTies+diabarT

    2+:= d' 58mm=

    A.5 CROSS SECTION

    BASIC SKETCH

    Beam Width, b

    Beam

    Hei

    ght,

    h

    Design of Reinforced Concrete Beam Page 3 of 7 LNT4 - Dec.2011

  • ACI 318RECTANGULAR BEAM DESIGN

    B. DESIGN LOADS Beam "RB1":=From STAAD Analysis and Design Output STAAD_File "2-Storey Residential.std":= Member 50:=

    LC 200,201,202,203,204...

    End Axial Shear-Y Shear-Z Torsion Mom-Y Mom-Z MsagposJoint kN kN kN kNm kNm kNm Msagneg

    1.4D 200 27 5.19 31.51 -0.02 1.14 -0.14 21.38 -21.32

    1.4D 200 158 -5.19 -18.72 0.02 -1.14 0.17 21.32 21.38

    1.2D + 1.6L + 0.5Lr 201 27 5.78 34.47 -0.22 1.39 -0.03 24.06 -25.21

    1.2D + 1.6L + 0.5Lr 201 158 -5.78 -23.50 0.22 -1.39 0.41 25.21 24.06

    1.2D + 1.6Lr + 0.5L 202 27 4.86 29.34 -0.08 1.10 -0.09 20.12 -20.44

    1.2D + 1.6Lr + 0.5L 202 158 -4.86 -18.38 0.08 -1.10 0.23 20.44 20.12

    1.2D + 1.6Lr + 0.8Wx 203 27 6.40 27.61 0.06 0.99 -0.22 19.33 -18.29

    1.2D + 1.6Lr + 0.8Wx 203 158 -6.40 -16.64 -0.06 -0.99 0.11 18.29 19.33

    1.2D + 1.6Lr + 0.8Wz 204 27 4.02 29.22 -3.91 0.23 2.44 20.06 -20.30

    1.2D + 1.6Lr + 0.8Wz 204 158 -4.02 -18.26 3.91 -0.23 4.20 20.30 20.06

    1.2D + 1.3Wx + 0.5L + 0.5Lr 205 27 8.04 30.31 0.04 1.12 -0.25 21.75 -20.46

    1.2D + 1.3Wx + 0.5L + 0.5Lr 205 158 -8.04 -19.35 -0.04 -1.12 0.18 20.46 21.75

    1.2D + 1.3Wz + 0.5L + 0.5Lr 206 27 4.18 32.93 -6.41 -0.10 4.07 22.93 -23.74

    1.2D + 1.3Wz + 0.5L + 0.5Lr 206 158 -4.18 -21.97 6.41 0.10 6.82 23.74 22.93

    0.9D + 1.3Wx 207 27 6.51 21.23 0.11 0.75 -0.25 15.37 -13.72

    0.9D + 1.3Wx 207 158 -6.51 -13.00 -0.11 -0.75 0.06 13.72 15.37

    0.9D + 1.3Wz 208 27 2.65 23.85 -6.34 -0.47 4.07 16.56 -17.00

    0.9D + 1.3Wz 208 158 -2.65 -15.63 6.34 0.47 6.71 17.00 16.56

    1.2D + 1.0Ex + 0.5L 209 27 6.93 33.05 -3.56 1.22 -0.12 22.81 -24.07

    1.2D + 1.0Ex + 0.5L 209 158 -6.93 -22.09 3.56 -1.22 6.17 24.07 22.81

    1.2D + 1.0Ez + 0.5L 210 27 4.34 32.11 -4.95 0.18 3.11 22.28 -22.98

    1.2D + 1.0Ez + 0.5L 210 158 -4.34 -21.14 4.95 -0.18 5.30 22.98 22.28

    0.9D + 1.0Ex 211 27 5.40 23.97 -3.49 0.84 -0.12 16.43 -17.33

    0.9D + 1.0Ex 211 158 -5.40 -15.75 3.49 -0.84 6.05 17.33 16.43

    0.9D + 1.0Ez 212 27 3.76 19.36 2.95 1.16 -2.24 12.96 -12.97

    0.9D + 1.0Ez 212 158 -3.76 -11.14 -2.95 -1.16 -2.76 12.97 12.96

    Combination for Strength Design

    Load Comb

    Design of Reinforced Concrete Beam Page 4 of 7 LNT4 - Dec.2011

  • ACI 318RECTANGULAR BEAM DESIGN

    C. ANALYSIS RESULTSC.1 LIMITS OF REINFORCEMENTS

    Steel reinforcement ratio As

    b d:= 0.01240=

    Minimum steel reinforcement ratioNSCP Section 410.6.1

    min maxfc' MPa4 fy

    1.4fy

    MPa, := min 0.00509=

    Whitney stress block factorNSCP Section 410.3.7.3

    1 if fc' 30MPa 0.85, max 0.85 0.057

    fc'MPa

    30 0.65,

    ,

    :=

    1 0.85=

    Balanced steel reinforcement ratiofor singly reinforced beam

    b 0.85fc'fy

    1 600MPa600 MPa fy+

    := b 0.03783=

    Maximum steel ratio for singly reinforcedbeam max 0.75b:= max 0.02837=

    Analyse_as "SINGLY REINFORCED BEAM" 0.75bif"DOUBLY REINFORCED BEAM" otherwise

    :=

    Analyse_as "SINGLY REINFORCED BEAM"=

    C.2 SINGLY REINFORCED BEAM ANALYSISGuess values

    c

    a

    0.3 h

    1 c

    := fs fy:=

    T C=

    Given As fs 0.85 fc' a b=

    where fs min fy 600 MPad c

    c,

    =c

    a1

    =

    Solve for a and c

    fs

    c

    a

    Find fs c, a, ( ):=

    Hence c 54.4mm=a 46.2mm=fs 275.0MPa=

    Solve for moment capacity of beam:

    C 0.85fc' a b:= C 165.0kN=Mu.SRB f C d a

    2

    := Mu.SRB 32.5kN m=

    Design of Reinforced Concrete Beam Page 5 of 7 LNT4 - Dec.2011

  • ACI 318RECTANGULAR BEAM DESIGN

    C.3 MOMENT CAPACITY CHECK

    The ultimate moment capacity of beam is equal to Mu.cap 32.5kN m=Check positive moment

    Mu.pos min Musag( ):= Mu.pos 25.21 kN m=if Mu.cap Mu.pos "Beam is SAFE for Positive Bending", "REDESIGN", ( ) "Beam is SAFE for Positive Bending"=

    Check negative moment

    Mu.neg max Musag( ):= Mu.neg 24.06kN m=if Mu.cap Mu.neg "Beam is SAFE for Negative Bending", "REDESIGN", ( ) "Beam is SAFE for Negative Bending"=

    C.4 SHEAR REINFORCEMENTArea of shear reinforcement provided:

    Av 2 AsTies:= Av 200mm2=Factored shear force:

    Vu max Vuy( ):= Vu 34.47kN=

    Shear strength provided by concrete:

    Vc16

    fc' MPa b d:= Vc 36.97kN=

    Design of Reinforced Concrete Beam Page 6 of 7 LNT4 - Dec.2011

  • ACI 318RECTANGULAR BEAM DESIGN

    Calculate required spacing of shear reinforcement:

    S

    sAv fy dVuv

    Vc

    s min sd2

    , 600mm,

    Vuv

    Vc 13

    fc' MPa b dif

    s min sd4

    , 300mm,

    Vuv

    Vc 13

    fc' MPa b d>if

    Vuv

    Vc 23

    fc' MPa b d( )if

    "Adjust the size of beam"Vuv

    Vc 23

    fc' MPa b d( )>if

    Vu v Vc>if

    s3

    fyMPa

    Avb

    s min sd2

    , 600mm,

    12v Vc Vu< v Vc