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March 23, 2015

March 23, 2015 - SecV chemistrysciencehip.weebly.com/uploads/4/8/6/3/48637575/free_fall.pdf · March 23, 2015 y = (-9,8 m/s2) t2 1 2--> inverted half-parabula as position / time graph-->

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Page 1: March 23, 2015 - SecV chemistrysciencehip.weebly.com/uploads/4/8/6/3/48637575/free_fall.pdf · March 23, 2015 y = (-9,8 m/s2) t2 1 2--> inverted half-parabula as position / time graph-->

March 23, 2015

Page 2: March 23, 2015 - SecV chemistrysciencehip.weebly.com/uploads/4/8/6/3/48637575/free_fall.pdf · March 23, 2015 y = (-9,8 m/s2) t2 1 2--> inverted half-parabula as position / time graph-->

March 23, 2015

Free fall - motion of an object which is only subject to gravitational force (no friction / air resistance considered)

acceleration due to Earth's gravitational pull:

g = 9.80 m/s2

sign convention:

axis of reference is y-axis pointing upwards --> falling object is subject to acceleration of -9.80 m/s2 and has a negative velocity:

y

a = -9.8 m/s2v < 0

v > 0

same equations as for other accelerated motions hold true:

Page 3: March 23, 2015 - SecV chemistrysciencehip.weebly.com/uploads/4/8/6/3/48637575/free_fall.pdf · March 23, 2015 y = (-9,8 m/s2) t2 1 2--> inverted half-parabula as position / time graph-->

March 23, 2015

y = (-9,8 m/s2) t212

--> inverted half-parabula as position / time graph

--> in the second second of movement object is 9.8 m/s faster than in first second and so on.

--> mass of object does not appear in formula - what does that mean?

Strobe phtograph of a falling ballhttps://www.youtube.com/watch?v=xQ4znShlK5A

https://www.youtube.com/watch?v=AV-qyDnZx0A

Page 4: March 23, 2015 - SecV chemistrysciencehip.weebly.com/uploads/4/8/6/3/48637575/free_fall.pdf · March 23, 2015 y = (-9,8 m/s2) t2 1 2--> inverted half-parabula as position / time graph-->

March 23, 2015

Do heavy and light objects fall with the same speed?

http://video.mit.edu/watch/feather-and-coin-in-a-vacuum-6407/

compare styrofoam and rubber ball, feather and ball

Page 5: March 23, 2015 - SecV chemistrysciencehip.weebly.com/uploads/4/8/6/3/48637575/free_fall.pdf · March 23, 2015 y = (-9,8 m/s2) t2 1 2--> inverted half-parabula as position / time graph-->

March 23, 2015

motion of a ball thrown into the air:

- ascend and descend take the same amount of time

- final velocity same magnitude as initial velocity (but opposite sign)

Page 6: March 23, 2015 - SecV chemistrysciencehip.weebly.com/uploads/4/8/6/3/48637575/free_fall.pdf · March 23, 2015 y = (-9,8 m/s2) t2 1 2--> inverted half-parabula as position / time graph-->

March 23, 2015

Example:

From a hight of 15m an object is thrown into the air with a velocity of 10 m/s. What is the objects flight time and what will its final velocity be?

(vf2 = vi2 + 2a y)

15 m

y = yfinal - yinitial = 0m - 15m = -15m

Page 7: March 23, 2015 - SecV chemistrysciencehip.weebly.com/uploads/4/8/6/3/48637575/free_fall.pdf · March 23, 2015 y = (-9,8 m/s2) t2 1 2--> inverted half-parabula as position / time graph-->

March 23, 2015

Page 8: March 23, 2015 - SecV chemistrysciencehip.weebly.com/uploads/4/8/6/3/48637575/free_fall.pdf · March 23, 2015 y = (-9,8 m/s2) t2 1 2--> inverted half-parabula as position / time graph-->

March 23, 2015

Page 9: March 23, 2015 - SecV chemistrysciencehip.weebly.com/uploads/4/8/6/3/48637575/free_fall.pdf · March 23, 2015 y = (-9,8 m/s2) t2 1 2--> inverted half-parabula as position / time graph-->

March 23, 2015

A  car  travels  at  a  velocity  of  5  m/s  for  five  seconds  and  then  accelerates  to  a  velocity  of  10  m/s  within  5  sec.  What  is  the  average  velocity  over  the  course  of  this  movement?

Page 10: March 23, 2015 - SecV chemistrysciencehip.weebly.com/uploads/4/8/6/3/48637575/free_fall.pdf · March 23, 2015 y = (-9,8 m/s2) t2 1 2--> inverted half-parabula as position / time graph-->

March 23, 2015

Isaac's  house  lies  at  a  distance  of  1500  m  from  school.  Kyle  lives  on  the  same  street  as  Isaac  but  750  m  further  from  school.  On  Friday  morning  they  both  head  out  the  door  at  the  same  time.  Isaacs  strolls  to  school  at  a  velocity  of  1  m/s.  Kyle  however  has  an  urgent  question  to  ask  his  math  teacher  before  his  quiz  and  therefore  hurries  to  school  at  a  velocity  of  2  m/s.  At  what  point  in  time  after  leaving  the  house  does  Kyle  overtake  Isaac?

Page 11: March 23, 2015 - SecV chemistrysciencehip.weebly.com/uploads/4/8/6/3/48637575/free_fall.pdf · March 23, 2015 y = (-9,8 m/s2) t2 1 2--> inverted half-parabula as position / time graph-->

March 23, 2015

Air resistance increases with velocity

Page 12: March 23, 2015 - SecV chemistrysciencehip.weebly.com/uploads/4/8/6/3/48637575/free_fall.pdf · March 23, 2015 y = (-9,8 m/s2) t2 1 2--> inverted half-parabula as position / time graph-->

March 23, 2015

"Real" fall and terminal velocity

initially:

not much air resistance --> skydiver accelerates

later:

the greater the velocity, the greater the air resistance --> drag created by air resistance becomes equal to acceleration due to gravity --> terminal velocity reached.

B

Free Fall: air resistance is not considered (either negligable, or we pretend there is no air). Acceleration formulas hold true, an object will continue accelerating untill it hits the ground.

Real Fall: air resistance increases with velocity and will slow acceleration. A terminal velocity will be reached.

The more massive the object, the greater the gravitational force pulling it down. Therefore a massive object has to reach a higher speed compared to a lighter object, before air resistance counteracts the gravitational pull.

In total: the more massive the object, the greater the terminal velocity.

Page 13: March 23, 2015 - SecV chemistrysciencehip.weebly.com/uploads/4/8/6/3/48637575/free_fall.pdf · March 23, 2015 y = (-9,8 m/s2) t2 1 2--> inverted half-parabula as position / time graph-->

March 23, 2015

An object, initially at rest, falls from a height of 12 metres. What will its height be when it reaches half of its maximum speed?

Page 14: March 23, 2015 - SecV chemistrysciencehip.weebly.com/uploads/4/8/6/3/48637575/free_fall.pdf · March 23, 2015 y = (-9,8 m/s2) t2 1 2--> inverted half-parabula as position / time graph-->

March 23, 2015

The graph below shows the speeds of two cars.

At time 0 car B passes car A, which is starting from rest.

1.) what will the distance be between the two cars after 60 sec.?

2.) At what time will car A pass car B?