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CM3230 Lecture 11 Page 1 CM 3230 Thermodynamics, Fall 2014 Lecture 11 1. Equation of State (EOS) - An equation relating the values of , and (e.g. ideal gas law, etc.) 2. Ideal Gas Law = - Assumptions: the molecules are so far apart so that a) compared to spaces between molecules, the molecules does not occupy significant volume b) there are no intermolecular forces ( any collision is also considered perfectly elastic ) CM3230 Lecture 11 Page 2 3. The Van der Waals Equation - Adds simple corrections to ideal gas law to approach real gas behavior a) Correction to volume: replace by (−), b) Correction to pressure: replace by (+/ ) + (−)= - Parameters and could be obtained experimentally. - If not available, then use the two assumption of Van der Waals at the critical point: slope is 0 at critical point: critical point =0 inflection point at the critical point: critical point =0

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CM3230 Lecture 11 Page 1

CM 3230 Thermodynamics, Fall 2014

Lecture 11

1. Equation of State (EOS)

- An equation relating the values of �, � and � (e.g. ideal gas law, etc.)

2. Ideal Gas Law

�� = ��

- Assumptions: the molecules are so far apart so that

a) compared to spaces between molecules, the molecules does not occupy

significant volume

b) there are no intermolecular forces ( any collision is also considered perfectly

elastic )

CM3230 Lecture 11 Page 2

3. The Van der Waals Equation

- Adds simple corrections to ideal gas law to approach real gas behavior

a) Correction to volume: replace � by (� − �),

b) Correction to pressure: replace � by (� + �/� )

�� + �� � (� − �) = ��

- Parameters � and � could be obtained experimentally.

- If not available, then use the two assumption of Van der Waals at the critical point:

slopeis0atcriticalpoint: ����� criticalpoint = 0

inflectionpointatthecriticalpoint: #� ��� $criticalpoint

= 0

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CM3230 Lecture 11 Page 3

Solving the conditions at �%, �% and �% would yield two equations with two unknown

� and �. This yields:

� = 2764

(��%) �% and� = 18��%�%

v

P

cT

cv

cP

CM3230 Lecture 11 Page 4

- After substituting these values to the Van der Waals model once again,

�- = 8�-3�- − 1 − 3�-

where, �- = �/�% (reduced pressure), �- = �/�% (reduced temperature),

�- = �/�%(reduced molar volume)

� an equation that do not depend on substance parameters � or �.

� this suggests that real gas behavior could described be described more

generally without having to specify which gas is being considered, i.e. we

arrive at Van der Waals’s Principle of Corresponding States:

“Substances behave alike at the same reduced states. Substances at

same reduced states are at corresponding states.”

� If we plot the “compressibility factor” using reduced pressure and reduced

temperature, many similar substances should follow the same trends.

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CM3230 Lecture 11 Page 5

Image from http://www.mae.wvu.edu/~smirnov/mae320/notes.html

CM3230 Lecture 11 Page 6

4. Cubic Equations of State

- Van der Waals equation can be rearranged to be

�/ − �� + ��� � + ���� � − ���� = 0

� for fixed � and � there are three roots possible.

i) One real root, 2 complex roots � only one value for �

ii) Three equal roots � critical point

iii) Three real roots: �0 > � > �/ � yields �234 = �/ and �567 = �0

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CM3230 Lecture 11 Page 7

� can use Antoine equation to find saturated pressure for a given �, then use the

cubic equation to find the roots

� Alternatively, we can use Maxwell’s equal area principle to find �869, �234 and

�567,

�869:�567 − �234; = < �5=>?5@AB

C�

vliq vapv v

P

T<Tc

satP

CM3230 Lecture 11 Page 8

- Improvements to Van der Waals: replace the term 1/� by other approximation

a) Redlich-Kwong

� = ��� − � − � 1

(� + �)�√�

� = E0.4275H�%I ���%

�%

� = 0.08664 ��%�%

b) Soave-Redlich-Kwong

� = ��� − � − � JKLM�� + ��

JKLM = N1 + �0.480 + 1.574O − 0.176O :1 − H�-;P

where O is the acentric factor (see appendix A for values of typical

substances)

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CM3230 Lecture 11 Page 9

c) Peng-Robinson

� = ��� − � − � JQL(� + �)� + �(� − �)

JQL = N1 + (0.37464 + 1.54226O − 0.26992O :1 − H�-;P

� = 0.457235 ���% �%

� = 0.077796 ��%�%

- Mixing Rules for S components

a) Van der Waals: let �3T = H�3�T , then

�U3V = WW�3TX3XTY

TZ0

Y

3Z0�U3V = W�3X3

Y

3Z0

b) Other cubic equation of state: let ��J3T = H��J3��JT , then

��JU3V = WW��J3TX3XTY

TZ0

Y

3Z0�U3V = W�3X3

Y

3Z0

CM3230 Lecture 11 Page 10

5. Virial Equation of State

Let [ be the “compressibility factor” defined as

[ = ����

- Then a series approximation is given in two forms:

a) “Explicit in molar volume” form

[ = 1 + \� + ]

� + ^�/ +⋯

Example: Beattie-Bridgeman equation of state (cf. page 241) for \, ] and ^

b) “Explicit in pressure” form

[ = 1 + \′� + ]a� + ^a�/ +⋯

- Mixing Rules for S components :

\U3V = WW\3TY

TZ0X3

Y

3Z0XT ; ]U3V = WWW]3Tc

Y

cZ0

Y

TZ0X3

Y

3Z0XTXc

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CM3230 Lecture 11 Page 11

6. Compressiblity Charts (e.g. Lee-Kesler) p. 245-246

[ = [(d) + O[(0)

Remarks:

i) Curves are based on reduced T isotherms.

ii) The horizontal axis is reduced pressures but on log scales.

iii) For subcritical values (i.e. �- < 1 and �- < 1), note whether the desired values are

for the vapor or liquid state

iv) Can also use tables given in Appendix C.1 and C.2

7. Equations of State for Liquids and Solids ( see table 4.4, p. 245, for values at 20°], 1 bar)

- Thermal expansion coefficient, g

g = 1� ����� Q

- Isothermal compressibility, h

h = −1� ����� i

CM3230 Lecture 11 Page 12