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Lecture 13. Diophantus and Diophantine equations Diophantus Diophantus of Alexandria, (about 200 - 284), was a Greek mathematician. He was sometimes called “the father of algebra,” a title some claim should be shared by a Persian mathematician al-Khw¯ arizm ¯ i (about 780 - 850). 1 Figure 13.1 Fall of Rome Because of catastrophic events such as the fall of Rome and the rise of Islam, and the burning of the library on Alexandria in 640, almost all details of Diophantus’ life and mathematical works were burned. The only clue to Diophantus’ life is a conundrum in the Greek Anthology (around 600 ), which is an algebraic problem: 2 1 See Lecture 17. 2 Victor J. Katz, A History of Mathematics - an introduction, 3rd edition, Addison -Wesley, p.172; or 2nd edition, p.168. 81

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Page 1: Lecture 13. DiophantusandDiophantine equationsshanyuji/History/h-13a.pdfDiophantine equations are usually algebraic equations with integer coefficients, for which integer solutions

Lecture 13. Diophantus and Diophantine

equations

Diophantus Diophantus of Alexandria, (about 200 - 284), was a Greek mathematician.He was sometimes called “the father of algebra,” a title some claim should be shared by aPersian mathematician al-Khwarizmi (about 780 - 850).1

Figure 13.1 Fall of Rome

Because of catastrophic events such as the fall of Rome and the rise of Islam, andthe burning of the library on Alexandria in 640, almost all details of Diophantus’ life andmathematical works were burned. The only clue to Diophantus’ life is a conundrum in theGreek Anthology (around 600 ), which is an algebraic problem: 2

1See Lecture 17.2Victor J. Katz, A History of Mathematics - an introduction, 3rd edition, Addison -Wesley, p.172; or 2nd

edition, p.168.

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Page 2: Lecture 13. DiophantusandDiophantine equationsshanyuji/History/h-13a.pdfDiophantine equations are usually algebraic equations with integer coefficients, for which integer solutions

This tomb holds Diophantus ... (and) tells scientifically the measure of his life.God granted him to be a boy for the sixth part of his life, and adding a twelfthpart to this. He clothed his cheeks with down. He lit the light of wedlock aftera seventh part, and five years after his marriage, he granted him a son. Alas!lateborn wretched child; after attaining the measure of half his father’s life, chillFate look him. After consoling his grief by this science of numbers for four years,he ended his life.

If this information is correct, by solving this algebraic problem, Diophantus married at33 and had a son who died at 43, four years before Diophantus himself died at 84.

Diophantus’ Arithmetica Diophantus was the author of three books, one is called theArithmetica that deals with solving algebraic equations, while the other two books arenow lost. For the Arithmetica, Diophantus tells us in his introduction that it is dividedinto thirteen books. The Arithmetica contains 189 problems. Only six have survived inGreek. Four were preserved by the Arabs and translated into Latin in the sixteenth century.Diophantus’ books had enormous influence on the development of number theory.

Figure 13.2 Diophantus’ Arithmetica.

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Page 3: Lecture 13. DiophantusandDiophantine equationsshanyuji/History/h-13a.pdfDiophantine equations are usually algebraic equations with integer coefficients, for which integer solutions

It is well-known that Pierre de Fermat studied Arithmetica and made a fateful note in themargin of his copy of the book that a certain equation similar to the Pythagorean equation

xn + yn = zn, n ≥ 3

considered by Diophantus has no solutions and he found “a truly marvelous proof of thisproposition. This is the celebrated Fermat’s Last Theorem (see Lecture 23). This led totremendous advances in number theory, and the study of Diophantine equations (“Diophan-tine geometry”) and of Diophantine approximations remain important areas of mathematicalresearch.

Diophantus studied algebra, which was avoided by many Greek mathematicians at thetime because of the discovery of irrational numbers and their inability to handle them.

Diophantus was the first Greek mathematician who recognized fractions as numbers;thus he allowed positive rational numbers for the coefficients and solutions. In modern use,Diophantine equations are usually algebraic equations with integer coefficients, for whichinteger solutions are sought. Diophantus also made advances in mathematical notation.

Figure 13.3 A map of Alexandria in 81 AD

Some of Diophantus’ mathematical work

• All of Diophantus’ symbols are abbreviations, which is one of his important achieve-ments. Before him, people used words. For example, he called “unknown” as thenumber of the problem, used ψ to denote “-”, and τ to denote “=”, and used algebraicsymbols to denote “square” and “cube” of numbers.

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Page 4: Lecture 13. DiophantusandDiophantine equationsshanyuji/History/h-13a.pdfDiophantine equations are usually algebraic equations with integer coefficients, for which integer solutions

• Diophantus did know how to solve quadratic equations of the form ax2 + c = bx. Heonly took positive roots.

One example is: To find two numbers such that their sum and the sum of their squaresare given numbers. In modern notation, given a, b, it asked to find x, y such that

x+ y = a, x2 + y2 = b.

• He knew “negative times negative is positive.”

• Most of Diophantus’ problems are indeterminants, i.e., the number of equations ismore than the number of unknowns. For these problems, Diophantus generally givesonly one solution, but one may extend the method to obtain other solutions.

• He studied equations of higher degree. For example, in modern notation, to find x, yand z such that

(x2)2 + (y3)2 = z2.

Another example, to find x and y such that

x+ y = a, x3 + y3 = b.

• Diophantus knew the expansion of (x+ y)3.

Let us take look at one problem quoted from Diophantus 3:

Let it be required to divide 16 into two squares. And let the first square = x2;then the other will be 16−x2; it shall be required therefore to make 16−x2 = asquare. I take a square of the form (ax− 4)2, a being any integer and 4 the rootof 16; for example, let the side be 2x − 4, and the square itself 4x2 + 16 − 16x.Then 4x2 + 16 − 16x = 16 − x2. To add to both sides the negative terms andtake like from like, Then 5x2 = 16x, and x = 16

5. One number will therefore be

256

25, the other 144

25, and their sum is 400

25or 16, and each is a squre.

In other words, it is in fact an indeterminant problem: To find rational solutions of theequation x2+y2 = 16. Set y = ax−4. Substituting into the equation, we get x2+(ax−4)2 =16, i.e., x = 8a

1+a2 .

3Victor J. Katz, A History of Mathematics - an introduction, 3rd edition, Addison -Wesley, 2009, p.179;

or 2nd edition, p.177.

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