Lec 3 Fatigue Failure 031004_for_students_2

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    Chapter 6 Fatigue Failure

    Theories

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    Fatigue Failure Occurs when stresses are changing

    throughout the life of a part.

    _______________________ starts with a

    crack that propagates until a catastrophic

    failure occurs.

    This usually begins at a manufacturing defector stress concentration that is subjected to

    tensile stresses for part of its load cycle.

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    Fatigue-Failure Models Stress-Life - cyclic stresses are kept

    below fatigue strength or endurance

    limit. Most widely used.

    Strain-Life - complicated not often used.

    _________________ - sometimes

    used, gaining favor especially in the

    aircraft and aerospace industry.

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    Fatigue Stresses

    -10000

    -50000

    5000

    10000

    15000

    20000

    25000

    30000

    0 2 4 6 8 10

    Load Cycles

    Ap

    pliedStress

    -psi

    a

    a

    a

    m

    m

    Fully Reversed Repeated Fluctuating

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    Fully Reversed Failure Criteria Most data comes from R. R. Moore

    rotating-beam test.

    Highly polished specimen of 0.3 inches

    in diameter is subjected to pure bending

    stresses that are alternated by rotating

    the specimen.

    Rotation is at 1725 rpm.

    Takes 1/2 day to reach 106 cycles.

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    S-N Curve for Steel with Sut = 100 ksi

    10000

    100000

    1.0E+3 10.0E+3 100.0E+3 1.0E+6 10.0E+6 100.0E+6

    Cycles to Failure - N

    Fatigue

    Strength

    -Sf

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    Endurance Limit and Fatigue

    Strength Endurance Limit of a Material (Se) -

    stress below which fatigue failure does

    not occur regardless of the number of

    stress cycles.

    ____________________Strength of a

    Material (Sf) -stress below which fatiguefailure does not occur for a specified

    number of stress cycles.

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    Typical S-N Curve for Non-Ferrous Metals

    10000

    100000

    1.00E+03 1.00E+04 1.00E+05 1.00E+06 1.00E+07 1.00E+08 1.00E+09

    Cycles to Failure

    Fatigue

    Strength

    -psi

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    Estimating Se or Sf For ____________:

    Se= 0.5Sut for Sut200 ksi (1400 MPa)

    For ______________:

    Se= 0.4Sut for Sut60 ksi (400 MPa)

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    Estimating Se or Sf contd For __________________:

    Sf@5E8= 0.4Sut for Sut330 ksi (330 MPa)

    For _____________________:

    Se= 0.4Sut for Sut40 ksi (280 MPa)

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    Correction Factors to Endurance

    Limit and Fatigue Strength Se = CloadCsize CsurfCtempCreliab Se

    Sf= CloadCsize CsurfCtempCreliab Sf

    Se -corrected endurance limit for a part

    Sf-corrected fatigue strength for a part

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    Correction Factors to Endurance

    Limit and Fatigue Strength Cload - load factor see eq. 6.7a pg 348

    Csize - size factor see eqs. 6.7a,b,cpg 348-349

    Csurf- surface factor see Figs. 6-26,6.27, and eq. 6.7e pg 349-352

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    Correction Factors to Endurance

    Limit and Fatigue Strength Ctemp - temperature factor see eq. 6.7f

    pg 352-353

    Creliab - reliability factor see Table 6.4

    pg 353

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    Stress Concentration Kf= 1+q(Kt+ 1)

    Kt- geometric stress concentrationfactor

    Kf-___________________________

    q - notch sensitivity factor

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    Fluctuating Stresses

    Modified-Goodman Diagram

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    Failure Lines for Fluctuating Stress

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    Augmented Modified-Goodman

    Diagram

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    Stress ConcentrationApply Kfto the ______________

    components of stress.

    For __________ materials apply Kt to

    the mean components of stress.

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    Stress Concentration - contd If Kf|maxnom| < Sy then: Kfm = Kf

    If Kf|maxnom| > Sy then:Kfm = (Sy - Kfanom)/ |mnom|

    If Kf|maxnom - minnom| < 2Sy then: Kfm = 0

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    Factor of Safety for Fluctuating Stress -

    Case 1

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    Factor of Safety for Fluctuating Stress -

    Case 2

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    Factor of Safety for Fluctuating Stress -

    Case 3

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    Factor of Safety for Fluctuating Stress -

    Case 3

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    Factor of Safety for Fluctuating Stress -

    Case 4

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    Factor of Safety for Fluctuating Stress -

    Case 4

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    Fluctuating Stresses

    Multiaxial Stresses in Fatigue

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    Fully Reversed Simple

    Multiaxial Stresses

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    Fluctuating Simple Multiaxial Stresses

    Von Mises Method

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    General Approach to High Cycle

    Fatigue Design Generate Modified Goodman Diagram

    Calculate alternating and mean components

    of stress at areas of concern on the part.Include appropriate stress concentrationfactors.

    Convert alternating and mean appliedstresses to alternating and mean Von Mises

    Stresses. Plot these stresses on the Modified Goodman

    Diagram and find the factor of safety.

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    Example The figure pertains to the shaft of a disk

    sander that is made from steel havingSu=900 MPa, and Sy=750 MPa. The most

    severe loading occurs when an object is heldnear the periphery of the disk with sufficientforce to develop 12 N-m (which approachesthe stall torque of the motor).

    Assume a coefficient of friction between theobject and the disk is 0.6.

    What is the factor of safety with respect toeventual fatigue failure of the shaft?

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    Example