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Reference Books1. Modern Control Engineering,
Katsuhiko OgataPrentice Hall, 1992.
2. Modern Control Systems,Dorf R.C.,Seventh Edition, Addison-Wesley, 1995.
3. Automatic Control Systems,Benjamin C. Kuo
Sixth Edition, Prentice Hall India, 1996.
4. Feedback and Control Systems,Distefano III, Stubberud, Williams
Schaum Publishing Co., 1967.
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Laplace Transform in
Control EngineeringDr.P.V.Manivannan
Mechanical Engineering Department
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Definition of Laplace Transform
Complex variable:
- Real part
- Imaginary part
s j
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Graphical representation of s
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Laplace transforms of StandardFunctions (Input signals)
1. Unit step function: f(t) = u(t), 0 for t < 0, 1 for t 0
At t = , e-st approaches zero (0),
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Laplace transforms of StandardFunctions (Input signals)
Ramp function r(t) = t, for t 0;Unit
Integrating by parts and evaluating gives
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Laplace transforms of StandardFunctions (Input signals)
2. Exponential function: f(t) = eat, t 0
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Laplace transforms of Standard Functions
Find the Laplace transform of: sintandcost
cos sin
cos sin
j t
j t
e t j t
e t j t
1cos ( )
21
sin ( )
2
j j
j j
e e
e e
j
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0
2 2
2 2
( )
1 1 1 1
2 ( ) 2 ( )
( )
, :
cos
( )
j t j t ste e e dt
j s j j s j
s
Similarly we can write
st
s
1L(si n t ) =
2j
L
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Laplace transforms of StandardFunctions (Input signals)
Shifted unit step functionf(t) = u(t 3); 0 for t< 3 & 1 for t> 3
-as
-3s
L{f (t ) . u (t -a )} = e L {f (t )}
e
= s
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Laplace transform of Pulse function
-as
( ) ( ) ( )
e
A s
sin propert
bs
f t A u t a u t b
e
s
u g
-as
L f ( t )=
eL{u (t -a )} =
s
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Laplace Transform Theorms
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Laplace Transform theorms
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Laplace Transform theorms
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Inverse Laplace Transform
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Inverse Laplace Transform
Inverse Laplace of a function (inLaplace domain) can be found
easily by Partial Fraction method& Inverse Laplace Table
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Example Problem:1
( )u t a
-as-1 e
L s
3 42( ) ( )s sG s e es
We know that
3 4
2
s se e
s s
-1 -1
L L
2 ( 3) ( 4)u t u t
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Example Problem:2
Given Function:2
1( )( 5)
sG s es
2
1We also know that,
(s+a)
at
te
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Example Problem:2
Here,2
1( ) [ ( )]( 5)
g t G ss
-1L
and , as 'a'= 1as se e
5( 1)( 1) ( 1) tg t t e
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Example Problem:2
5( 1)
2
5( 1)
1( 1) . u(t-1)
( 5)
( ) ( 1) . u(t-1)
s t
t
e t es
g t t e
-1L
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Example Problem:3
Example problem:4
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Example problem:4(Simple Roots)
Example problem:4
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Example problem:4(Simple Roots)
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Example Problem:5
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Example Problem:5
E l P bl 6
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Example Problem:6
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S l i Diff ti l E ti
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Solving Differential Equation
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2 2
3 A Bs+C= +
s+1( 1)( 9) s 9
Y
s s
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Finding Solution for Electrical
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Finding Solution for ElectricalSystem
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Current waveform
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Example Problem:7
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Time Domain Response ofdifferent systems
First Order system time
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First Order system timeresponse for step input
First Order system time
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First Order system timeresponse
First Order system time
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First Order system timeresponse
First Order system time
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First Order system timeresponse
Second Order system time response
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Second Order system time response
Second Order system time
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Second Order system timeresponse
Second Order system time
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Second Order system timeresponse
Second Order system time
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Second Order system timeresponse
Example Problem:1
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Example Problem:1
E l P bl 2
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Example Problem:2
Find K and afor the closed-loop system below suchthat the transient response to a step input satisfies:%OS 5% & ts 4 seconds
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Laplace Transform of Periodic Function
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Laplace Transform of Periodic Function
Laplace Transform of Periodic Function
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Laplace Transform of Periodic Function
Laplace Transform of Periodic Function
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Laplace Transform of Periodic Function
( )=t.[u(t) - u(t-1)] , has period of T = 2f t
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Laplace Transform of Periodic
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p
Function
( ) sin . [ ( ) u(t- )], period (p) =f t t u t
Laplace Transform of Periodic
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p
Function
Inverse Laplace transform of
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pPeriodic function
(1 )1( ) (where T is a constant)( 1)(1 )
s T
sT
eGiven that G s s e
As we know that Laplace transform of Periodic wave will
have term:1/ (1-e
-sT
),we will consider remaining part alone
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Thank you