22
 Test 1 Review Professor Deepa Kundur University of Toronto Professor Deepa Kundur (University of Tor onto)  Test 1 Review  1 / 87 Test 1 Review Reference: Sections: 2.1, 2.2, 2.3, 2.4, 2.5, 2.6, 2.7 3.1, 3.2, 3.3, 3.4, 3.5, 3.6 4.1, 4.2, 4.3, 4.4, 4.6, 4.7, 4.8 of S. Haykin and M. Moher, Introduction to Analog & Digital Communicati ons, 2nd ed., John Wiley & Sons, Inc., 2007. ISBN-13 978-0-471-43222-7. Professor Deepa Kundur (University of Tor onto)  Test 1 Review  2 / 87 Chapter 2: Fourier Representation of Signals and Systems Professor Deepa Kundur (University of Tor onto)  Test 1 Review  3 / 87 Communication Systems: Foundational Theories  Modulation Theory: piggy-back information-bearing signal on a carrier signal  Detection Theory: estimating or detecting the information-bearing signal in a reliable manner  Probability and Random Processes : model channel noise and uncertainty at receiver  Fourier Analysis: view signal and system in another domain to gain new insights Professor Deepa Kundur (University of Tor onto)  Test 1 Review  4 / 87

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  • Test 1 Review

    Professor Deepa Kundur

    University of Toronto

    Professor Deepa Kundur (University of Toronto) Test 1 Review 1 / 87

    Test 1 Review

    Reference:

    Sections:2.1, 2.2, 2.3, 2.4, 2.5, 2.6, 2.73.1, 3.2, 3.3, 3.4, 3.5, 3.64.1, 4.2, 4.3, 4.4, 4.6, 4.7, 4.8 of

    S. Haykin and M. Moher, Introduction to Analog & Digital Communications, 2nded., John Wiley & Sons, Inc., 2007. ISBN-13 978-0-471-43222-7.

    Professor Deepa Kundur (University of Toronto) Test 1 Review 2 / 87

    Chapter 2: Fourier Representation ofSignals and Systems

    Professor Deepa Kundur (University of Toronto) Test 1 Review 3 / 87

    Communication Systems: Foundational Theories

    I Modulation Theory: piggy-back information-bearing signal on acarrier signal

    I Detection Theory: estimating or detecting theinformation-bearing signal in a reliable manner

    I Probability and Random Processes: model channel noise anduncertainty at receiver

    I Fourier Analysis: view signal and system in another domain togain new insights

    informationconsumption

    informationsource transmitter receiver

    channel

    Professor Deepa Kundur (University of Toronto) Test 1 Review 4 / 87

  • The Fourier Transform (FT)

    G (f ) =

    g(t)ej2pift

    g(t) =

    G (f )e+j2pift

    Notation:

    g(t) G (f )G (f ) = F [g(t)]

    g(t) = F1 [G (f )]

    Professor Deepa Kundur (University of Toronto) Test 1 Review 5 / 87

    Energy Signals

    I The energy of a signal g(t) is given by: |g(t)|2dt

    I If g(t) represents a voltage or a current, then we say that this isthe energy of the signal across a 1 ohm resistor.

    I Why? Because a current i(t) or voltage v(t) exhibits thefollowing energy over a R ohm resistor.

    E =

    i2(t)Rdt =

    v 2(t)

    Rdt

    Professor Deepa Kundur (University of Toronto) Test 1 Review 6 / 87

    Energy Signals and the Fourier Transform

    Practical physically realizable signals (e.g., energy signals) that obey: |g(t)|2dt

  • FT Synthesis Equation

    g(t) =

    G (f )e j2piftdt

    I g(t) is the sum of scaled complex sinusoids

    I e j2pift = cos(2pift) + jsin(2pift) complex sinusoid

    Professor Deepa Kundur (University of Toronto) Test 1 Review 9 / 87

    e j2pift = cos(2pift) + j sin(2pift)

    cos(2pift)

    0

    t

    sin(2pift)

    0

    t

    Professor Deepa Kundur (University of Toronto) Test 1 Review 10 / 87

    FT Analysis Equation

    G (f ) =

    g(t)ej2piftdt

    I The analysis equation represents the inner product between g(t)

    and e j2pift .

    I The analysis equation states that G (f ) is a measure of similarity

    between g(t) and e j2pift , the complex sinusoid at frequency f Hz.

    Professor Deepa Kundur (University of Toronto) Test 1 Review 11 / 87

    |G (f )| and G (f )

    g(t) =

    G (f )e j2pif tdf

    =

    |G (f )|e j(2pif t+G(f ))df

    I |G (f )| dictates the relative presence of the sinusoid of frequencyf in g(t).

    I G (f ) dictates the relative alignment of the sinusoid offrequency f in g(t).

    Professor Deepa Kundur (University of Toronto) Test 1 Review 12 / 87

  • Low, Mid and High Frequency Signals

    Q: Which of the following signals appears higher in frequency?

    1. cos(4 106pit + pi/3)2. sin(2pit + 10pi) + 17 cos2(10pit)

    A: cos(4 106pit + pi/3).

    Professor Deepa Kundur (University of Toronto) Test 1 Review 13 / 87

    Importance of FT Theorems and Properties

    I The Fourier transform converts a signal or system representationto the frequency-domain, which provides another way tovisualize a signal or system convenient for analysis and design.

    I The properties of the Fourier transform provide valuable insightinto how signal operations in the time-domain are described inthe frequency-domain.

    Professor Deepa Kundur (University of Toronto) Test 1 Review 14 / 87

    FT Theorems and PropertiesProperty/Theorem Time Domain Frequency DomainNotation: g(t) G(f )

    g1(t) G1(f )g2(t) G2(f )

    Linearity: c1g1(t) + c2g2(t) c1G1(f ) + c2G2(f )Dilation: g(at) 1|aG

    (fa

    )Conjugation: g(t) G(f )Duality: G(t) g(f )Time Shifting: g(t t0) G(f )ej2pift0Frequency Shifting: e j2pifc tg(t) G(f fc )Area Under G(f ): g(0) =

    G(f )df

    Area Under g(t): g(t)dt = G(0)

    Time Differentiation: ddtg(t) j2pifG(f )

    Time Integration : t g()d

    1j2pif

    G(f )

    Modulation Theorem: g1(t)g2(t)

    G1()G2(f )d

    Convolution Theorem: g1()g2(t ) G1(f )G2(f )

    Correlation Theorem: g1(t)g

    2 (t )dt G1(f )G2 (f )

    Rayleighs Energy Theorem: |g(t)|2dt =

    |G(f )|2df

    Professor Deepa Kundur (University of Toronto) Test 1 Review 15 / 87

    Time-Bandwidth Product

    time-duration of a signal frequency bandwidth = constant

    0 1/T

    2/T

    3/T

    4/T

    AT

    -1/T

    -2/T-3/T

    -4/T

    AT sinc(fT)

    T /2-T/2

    A

    Arect(t/T)

    t f

    T larger

    durationnull-to-nullbandwidth

    Professor Deepa Kundur (University of Toronto) Test 1 Review 16 / 87

  • Time-Bandwidth Product

    time-duration of a signal frequency bandwidth = constant

    I the constant depends on the definitions of duration andbandwidth and can change with the shape of signals beingconsidered

    I It can be shown that:time-duration of a signal frequency bandwidth 1

    4pi

    with equality achieved for a Gaussian pulse.

    Professor Deepa Kundur (University of Toronto) Test 1 Review 17 / 87

    LTI Systems and FilteringLTI System

    impulse response

    LTI System

    frequency response

    I For systems that are linear time-invariant (LTI), the Fourier transformprovides a decoupled description of the system operation on the input signalmuch like when we diagonalize a matrix.

    I This provides a filtering perspective to how a linear time-invariant systemoperates on an input signal.

    I The LTI system scales the sinusoidal component corresponding to frequencyf by H(f ) providing frequency selectivity.

    Professor Deepa Kundur (University of Toronto) Test 1 Review 18 / 87

    Dirac Delta Function

    Definition:

    1. (t) = 0, t 6= 02. The area under (t) is

    unity:

    (t)dt = 1

    Note: (0) = undefined

    t t

    Professor Deepa Kundur (University of Toronto) Test 1 Review 19 / 87

    Dirac Delta Function

    I can be interpreted as the limiting case of a family of functions ofunit area but that become narrower and higher

    t t

    all functions haveunit area

    T1T2T3

    T1T2T3

    1 1

    Professor Deepa Kundur (University of Toronto) Test 1 Review 20 / 87

  • Dirac Delta Function

    I Sifting Property:

    g(t)(t t0)dt = g(t0)

    I Convolution with (t):

    g(t) ? (t t0) = g(t t0)

    Professor Deepa Kundur (University of Toronto) Test 1 Review 21 / 87

    The Fourier Transform and the Dirac Delta(t) 1

    1 (f )e j2pif0t (f f0)

    cos(2pif1t) =e j2pif1t

    2+

    ej2pif1t

    2

    1

    2(f f1) + 1

    2(f + f1)

    sin(2pif1t) =e j2pif1t

    2j e

    j2pif1t

    2j

    1

    2j(f f1) 1

    2j(f + f1)

    0

    t

    0

    t

    f

    1/2 1/2

    f

    -0.5j

    0.5jsine

    -f1

    -f1f1

    f11

    f11

    cosine

    Professor Deepa Kundur (University of Toronto) Test 1 Review 22 / 87

    Fourier Transforms of Periodic Signals

    g(t) =

    n=cne

    j2pinf0t G (f ) =

    n=cn(f nf0)

    Professor Deepa Kundur (University of Toronto) Test 1 Review 23 / 87

    t

    g(t)

    A

    sinc

    k

    kc

    10 2-1-2

    -3 3 4 5-4-5

    sinc

    0 2-1-2

    -3 3 4 5-4-5

    Professor Deepa Kundur (University of Toronto) Test 1 Review 24 / 87

  • Transmission of Signals Through Linear Systems

    LTI System

    impulse response

    LTI System

    frequency response

    Time domain:

    y(t) = x(t) ? h(t) =

    x()h(t )d

    Causality: h(t) = 0 for t < 0Stability:

    |h(t)|dt B

    f

    f

    B

    B

    -B

    -B

    STOPBAND PASSBAND STOPBAND

    Professor Deepa Kundur (University of Toronto) Test 1 Review 27 / 87

    Ideal Low-Pass Filters

    hLP(t) = 2Bsinc(2B(t t0)) HLP(f ) ={

    ej2pif t0 |f | B0 |f | > B

    Professor Deepa Kundur (University of Toronto) Test 1 Review 28 / 87

  • Ideal Low-Pass Filters

    hLP(t) = 2Bsinc(2B(t t0))

    2B

    1/B

    t0t

    Professor Deepa Kundur (University of Toronto) Test 1 Review 29 / 87

    LTI Systems, Sinusoids and Ideal Lowpass FilteringQ: Suppose the following signals are passed through an ideal lowpass filter withcutoff frequency W such that f1

  • Amplitude Modulation

    I In modulation need two things:

    1. a modulated signal: carrier signal: c(t)2. a modulating signal: message signal: m(t)

    I carrier:I c(t) = Ac cos(2pifct); phase c = 0 is assumed.

    I message:I m(t) (information-bearing signal)I assume bandwidth/max freq of m(t) is W

    Professor Deepa Kundur (University of Toronto) Test 1 Review 33 / 87

    Amplitude Modulation

    Three types studied:

    1. Amplitude Modulation (AM)(yes, it has the same name as the class of modulation techniques)

    2. Double Sideband-Suppressed Carrier (DSB-SC)

    3. Single Sideband (SSB)

    Professor Deepa Kundur (University of Toronto) Test 1 Review 34 / 87

    Amplitude Modulation (the specific technique)

    sAM(t) = Ac [1 + kam(t)] cos(2pifct)

    % Modulation = 100max(kam(t))

    Suppose

    I |kam(t)| < 1 (% Modulation < 100%)I [1 + kam(t)] > 0, so the envelope of sAM(t) is always positive;

    no phase reversal

    I fc WI the movement of the message is much slower than the sinusoid

    Then, m(t) can be recovered with an envelope detector.

    Professor Deepa Kundur (University of Toronto) Test 1 Review 35 / 87

    Amplitude Modulation

    AMwave

    Output+

    -+

    -

    Professor Deepa Kundur (University of Toronto) Test 1 Review 36 / 87

  • Amplitude Modulation

    sAM(t) = Ac [1 + kam(t)] cos(2pifct)

    Professor Deepa Kundur (University of Toronto) Test 1 Review 37 / 87

    Double Sideband-Suppressed Carrier

    sAM(t) = Ac [1 + kam(t)] cos(2pifct)

    = Ac cos(2pifct) excess energy

    +ka Acm(t) cos(2pifct) message-bearing signal

    sDSB(t) = Acm(t) cos(2pifct)

    I Transmitting only the message-bearing component of the AMsignal, requires more a complex (coherent) receiver system.

    Professor Deepa Kundur (University of Toronto) Test 1 Review 38 / 87

    Double Sideband-Suppressed Carrier

    upper SSB

    lower SSB

    f

    S (f )

    f

    S (f )

    f

    S (f )

    f

    S (f )

    2W 2W

    2W 2W

    W W

    W W

    AM

    USSB

    LSSB

    DSB

    Professor Deepa Kundur (University of Toronto) Test 1 Review 39 / 87

    Double Sideband-Suppressed Carrier

    sDSB(t) = Acm(t) cos(2pifct)

    Professor Deepa Kundur (University of Toronto) Test 1 Review 40 / 87

  • carrier

    message

    amplitudemodulation

    DSB-SC

    Professor Deepa Kundur (University of Toronto) Test 1 Review 41 / 87

    carrier

    message

    amplitudemodulation

    DSB-SC

    Professor Deepa Kundur (University of Toronto) Test 1 Review 42 / 87

    carrier

    message

    amplitudemodulation

    DSB-SC

    Professor Deepa Kundur (University of Toronto) Test 1 Review 43 / 87

    Double Sideband-Suppressed Carrier

    I An envelope detector will not be able to recover m(t); it willinstead recover |m(t)|.

    I Coherent demodulation is required.

    ProductModulator

    Low-passlter

    Local Oscillaor

    DemodulatedSignal

    v (t)0s(t)

    Professor Deepa Kundur (University of Toronto) Test 1 Review 44 / 87

  • Costas Receiver

    -90 degreePhase Shifter

    Voltage-controlledOscillator

    ProductModulator

    Low-passFilter

    PhaseDiscriminator

    ProductModulator

    Low-passlter

    DSB-SC wave

    DemodulatedSignal

    Coherent Demodulation

    Circuit for Phase Locking

    v (t)0local oscillator output

    Professor Deepa Kundur (University of Toronto) Test 1 Review 45 / 87

    Costas Receiver

    -90 degreePhase Shifter

    Voltage-controlledOscillator

    ProductModulator

    Low-passFilter

    PhaseDiscriminator

    ProductModulator

    Low-passlter

    DSB-SC wave

    DemodulatedSignal

    Q-Channel (quadrature-phase coherent detector)

    I-Channel (in-phase coherent detector)

    v (t)I

    v (t)Q

    Professor Deepa Kundur (University of Toronto) Test 1 Review 46 / 87

    Multiplexing and QAM

    Multiplexing: to send multiple message simultaneously

    Quadrature Amplitude Multiplexing (QAM): (a.k.a quadrature-carriermultiplexing) amplitude modulation scheme that enables twoDSB-SC waves with independent message signals to occupy the samechannel bandwidth (i.e., same frequency channel) yet still beseparated at the receiver.

    Professor Deepa Kundur (University of Toronto) Test 1 Review 47 / 87

    Quadrature Amplitude Modulation

    s(t) = Acm1(t) cos(2pifct) + Acm2(t) sin(2pifct)

    ProductModulator

    Low-passFilter

    ProductModulator

    Low-passlter

    MultiplexedSignal

    -90 degreePhase Shifter

    Professor Deepa Kundur (University of Toronto) Test 1 Review 48 / 87

  • Quadrature Amplitude Modulation

    s(t) = Acm1(t) cos(2pifct) + Acm2(t) sin(2pifct)

    I Suppose m1(t) and m2(t) are two message signals both ofbandwidth W .

    I QAM allows two messages to be communicated withinbandwidth 2W .

    Professor Deepa Kundur (University of Toronto) Test 1 Review 49 / 87

    Quadrature Amplitude Modulation

    s(t) = Acm1(t) cos(2pifct) + Acm2(t) sin(2pifct)

    upper SSB

    lower SSB

    f

    S (f )DSB

    f

    S (f )

    f

    S (f )

    f

    S (f )

    2W 2W

    2W 2W

    W W

    W W

    USSB

    LSSB

    QAM

    Professor Deepa Kundur (University of Toronto) Test 1 Review 50 / 87

    Is there another way to gain this bandwidth efficiency?

    upper SSB

    upper SSBlower SSB

    lower SSB

    f

    S (f )

    f

    S (f )

    f

    S (f )

    2W 2W

    W W

    W W

    USSB

    LSSB

    QAM

    Professor Deepa Kundur (University of Toronto) Test 1 Review 51 / 87

    Single Sideband

    Modulation:

    sSSB(t) =Ac2m(t) cos(2pifct)Ac

    2m(t) sin(2pifct)

    where

    I the negative (positive) applies to upper SSB (lower SSB)

    I m(t) is the Hilbert transform of m(t)

    H(f ) = -j sgn(f )M(f ) M(f )

    f

    H(f )j

    -j

    h(t) = 1/( t)m(t) m(t)

    Professor Deepa Kundur (University of Toronto) Test 1 Review 52 / 87

  • Single Sideband

    Modulation:

    sSSB(t) =Ac2m(t) cos(2pifct) Ac

    2m(t) sin(2pifct)

    ProductModulator

    Band-passlter

    m(t) s(t)

    f

    H (f )BP

    fc-fc

    W W W Wupper SSBupper SSB

    lower SSB lower SSB

    Professor Deepa Kundur (University of Toronto) Test 1 Review 53 / 87

    Single Sideband

    Coherent Demodulation:

    ProductModulator

    Low-passlter

    Local Oscillaor

    DemodulatedSignal

    v (t)0s(t)

    Note: Costas receiver will work for SSB demodulation.

    Professor Deepa Kundur (University of Toronto) Test 1 Review 54 / 87

    Comparisons of Amplitude Modulation TechniquesAM:

    sAM(t) = Ac [1 + kam(t)] cos(2pifct)

    SAM(f ) =Ac2

    [(f fc) + (f + fc)] + kaAc2

    [M(f fc) + M(f + fc)]

    f

    S (f )

    f

    S (f )

    f

    S (f )

    f

    S (f )

    2W 2W

    2W 2W

    W W

    W W

    AM

    USSB

    LSSB

    DSB

    I highest power

    I BT = 2W

    I lowest complexity

    Professor Deepa Kundur (University of Toronto) Test 1 Review 55 / 87

    Comparisons of Amplitude Modulation TechniquesDSB-SC:

    sDSB(t) = Ac cos(2pifct)m(t)

    SDSB(f ) =Ac2

    [M(f fc) + M(f + fc)] f

    S (f )

    f

    S (f )

    f

    S (f )

    f

    S (f )

    2W 2W

    2W 2W

    W W

    W W

    AM

    USSB

    LSSB

    DSB

    I lower power

    I BT = 2W

    I higher complexity

    Professor Deepa Kundur (University of Toronto) Test 1 Review 56 / 87

  • Comparisons of Amplitude Modulation Techniques

    SSB:

    sUSSB(t) =Ac2m(t) cos(2pifct) Ac

    2m(t) sin(2pifct)

    SUSSB(f ) =

    {Ac2 [M(f fc) + M(f + fc)] |f | fc

    0 |f | < fcsLSSB(t) =

    Ac2m(t) cos(2pifct) +

    Ac2m(t) sin(2pifct)

    SLSSB(f ) =

    {0 |f | > fcAc2 [M(f fc) + M(f + fc)] |f | fc

    Professor Deepa Kundur (University of Toronto) Test 1 Review 57 / 87

    Comparisons of Amplitude Modulation TechniquesSSB:

    upper SSB

    lower SSB

    f

    S (f )

    f

    S (f )

    f

    S (f )

    f

    S (f )

    2W 2W

    2W 2W

    W W

    W W

    AM

    USSB

    LSSB

    DSB

    I lowest power

    I BT = W

    I highest complexity

    Professor Deepa Kundur (University of Toronto) Test 1 Review 58 / 87

    Chapter 4: Angle Modulation

    Professor Deepa Kundur (University of Toronto) Test 1 Review 59 / 87

    Angle Modulation

    I Consider a sinusoidal carrier:

    c(t) = Ac cos(2pifct + c angle

    ) = Ac cos(i(t))

    i(t) = 2pifct + c = 2pifct for c = 0

    fi(t) =1

    2pi

    di(t)

    dt= fc

    I Angle modulation: the message signal m(t) is piggy-backed oni(t) in some way.

    Professor Deepa Kundur (University of Toronto) Test 1 Review 60 / 87

  • Angle ModulationI Phase Modulation (PM):

    i (t) = 2pifct + kpm(t)

    fi (t) =1

    2pi

    di (t)

    dt= fc +

    kp2pi

    dm(t)

    dtsPM(t) = Ac cos[2pifct + kpm(t)]

    I Frequency Modulation (FM):

    i (t) = 2pifct + 2pikf

    t0

    m()d

    fi (t) =1

    2pi

    di (t)

    dt= fc + kfm(t)

    sFM(t) = Ac cos

    [2pifct + 2pikf

    t0

    m()d

    ]

    Professor Deepa Kundur (University of Toronto) Test 1 Review 61 / 87

    PM vs. FM

    sPM(t) = Ac cos[2pifct + kpm(t)]

    sFM(t) = Ac cos

    [2pifct + 2pikf

    t0

    m()d

    ]sPM(t) = Ac cos[2pifct + kp

    dg(t)

    dt]

    sFM(t) = Ac cos [2pifct + 2pikf g(t)]

    FMwave

    Modulatingwave Integrator

    PhaseModulator

    PMwave

    Modulatingwave

    Dieren-tiator

    FrequencyModulator

    Professor Deepa Kundur (University of Toronto) Test 1 Review 62 / 87

    carrier

    message

    amplitudemodulation

    phasemodulation

    frequencymodulation

    Professor Deepa Kundur (University of Toronto) Test 1 Review 63 / 87

    carrier

    message

    amplitudemodulation

    phasemodulation

    frequencymodulation

    Professor Deepa Kundur (University of Toronto) Test 1 Review 64 / 87

  • carrier

    message

    amplitudemodulation

    phasemodulation

    frequencymodulation

    Professor Deepa Kundur (University of Toronto) Test 1 Review 65 / 87

    Angle Modulation

    Integrator PhaseModulator

    m(t) s (t)FM

    Dierentiator FrequencyModulator

    m(t) s (t)PM

    Professor Deepa Kundur (University of Toronto) Test 1 Review 66 / 87

    Properties of Angle Modulation

    1. Constancy of transmitted power

    2. Nonlinearity of angle modulation

    3. Irregularity of zero-crossings

    4. Difficulty in visualizing message

    5. Bandwidth versus noise trade-off

    Professor Deepa Kundur (University of Toronto) Test 1 Review 67 / 87

    Constancy of Transmitted Power: PM

    Professor Deepa Kundur (University of Toronto) Test 1 Review 68 / 87

  • Constancy of Transmitted Power: FM

    Professor Deepa Kundur (University of Toronto) Test 1 Review 69 / 87

    Constancy of Transmitted Power: AM

    Professor Deepa Kundur (University of Toronto) Test 1 Review 70 / 87

    Nonlinearity of Angle Modulation

    Consider PM (proof also holds for FM).

    I Suppose

    s1(t) = Ac cos [2pifct + kpm1(t)]

    s2(t) = Ac cos [2pifct + kpm2(t)]

    I Let m3(t) = m1(t) + m2(t).

    s3(t) = Ac cos [2pifct + kp(m1(t) + m2(t))]

    6= s1(t) + s2(t) cos(2pifct + A + B) 6= cos(2pifct + A) + cos(2pifct + B)

    Therefore, angle modulation is nonlinear.

    Professor Deepa Kundur (University of Toronto) Test 1 Review 71 / 87

    Irregularity of Zero-Crossings

    I Zero-crossing: instants of time at which waveform changesamplitude from positive to negative or vice versa.

    Professor Deepa Kundur (University of Toronto) Test 1 Review 72 / 87

  • Zero-Crossings: PM

    Professor Deepa Kundur (University of Toronto) Test 1 Review 73 / 87

    Zero-Crossings: FM

    Professor Deepa Kundur (University of Toronto) Test 1 Review 74 / 87

    Zero-Crossings: AM

    Professor Deepa Kundur (University of Toronto) Test 1 Review 75 / 87

    Difficulty of Visualizing Message

    I Visualization of a message refers to the ability to glean insightsabout the shape of m(t) from the modulated signal s(t).

    Professor Deepa Kundur (University of Toronto) Test 1 Review 76 / 87

  • Visualization: PM

    Professor Deepa Kundur (University of Toronto) Test 1 Review 77 / 87

    Visualization: FM

    Professor Deepa Kundur (University of Toronto) Test 1 Review 78 / 87

    Visualization: AM

    Professor Deepa Kundur (University of Toronto) Test 1 Review 79 / 87

    Bandwidth vs. Noise Trade-Off

    I Noise affects the message signal piggy-backed as amplitudemodulation more than it does when piggy-backed as anglemodulation.

    I The more bandwidth that the angle modulated signal takes,typically the more robust it is to noise.

    Professor Deepa Kundur (University of Toronto) Test 1 Review 80 / 87

  • carrier

    message

    amplitudemodulation

    phasemodulation

    frequencymodulation

    Professor Deepa Kundur (University of Toronto) Test 1 Review 81 / 87

    AM vs. FM

    I AM is an older technology first successfully carried out in themid 1870s than FM was developed in the 1930s (by EdwinArmstrong).

    I FM has better performance than AM because it is lesssusceptible to noise.

    I FM takes up more transmission bandwidth than AM; Recall,

    BT ,FM = 2f + 2fm vs. BT ,AM = 2W or W

    I AM is lower complexity than FM.

    Professor Deepa Kundur (University of Toronto) Test 1 Review 82 / 87

    Narrow Band Frequency Modulation

    I Suppose m(t) = Amcos(2pifmt).

    fi (t) = fc + kf Amcos(2pifmt) = fc + f cos(2pifmt)

    f = kf Am frequency deviationi (t) = 2pi

    t0

    fi ()d

    = 2pifct +f

    fmsin(2pifmt) = 2pifct + sin(2pifmt)

    =f

    fmsFM(t) = Ac cos [2pifct + sin(2pifmt)]

    For narrow band FM, 1.

    Professor Deepa Kundur (University of Toronto) Test 1 Review 83 / 87

    Narrowband FM

    Modulation:

    sFM(t) Ac cos(2pifct) carrier

    Ac sin(2pifct) 90oshift of carrier

    sin(2pifmt) 2pifmAm

    t0 m()d

    DSB-SC signal

    Modulatingwave

    IntegratorNarrow-band

    FM waveProduct

    Modulator

    -90 degreePhase Shifter carrier

    +-

    Professor Deepa Kundur (University of Toronto) Test 1 Review 84 / 87

  • Transmission Bandwidth of FM Waves

    A significant component of the FM signal is within the followingbandwidth:

    BT 2f + 2fm = 2f(

    1 +1

    )I called Carsons Rule

    I f is the deviation of the instantaneous frequency

    I fm can be considered to be the maximum frequency of themessage signal

    I For 1, BT 2f = 2kfAmI For 1, BT 2f 1 = 2ff /fm = 2fm

    Professor Deepa Kundur (University of Toronto) Test 1 Review 85 / 87

    Generation of FM Waves

    Narrow bandModulator

    FrequencyMultiplier

    m(t) s(t) s(t)Integrator

    CrystalControlledOscillator

    frequency isvery stable

    Narrowband FM modulator

    widebandFM wave

    Professor Deepa Kundur (University of Toronto) Test 1 Review 86 / 87

    Demodulation of FM Waves

    Ideal EnvelopeDetector

    ddt

    I Frequency Discriminator: uses positive and negative slopecircuits in place of a differentiator, which is hard to implementacross a wide bandwidth

    I Phase Lock Loop: tracks the angle of the in-coming FM wavewhich allows tracking of the embedded message

    Professor Deepa Kundur (University of Toronto) Test 1 Review 87 / 87