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MINIT MESYUARAT 1 / 2014

TAJUK : Pembentukan AJK

TARIKH : 15/04/2014 (Selasa)

MASA : 5.00 ptg – 6.00 ptg

TEMPAT : Rumah Razman

KEHADIRAN : 3/3

CATATAN MESYUARAT

1. Pemilihan dan pembahagian tugasan dilakukan .

2. Perbincangan

tugasan yang telah diberikan oleh pensyarah.

3. Dua kumpulan dibentuk untuk memudahkan tugasan dilakukan.

4. Ketua kumpulan mengagihkan tugasan .

- Mohd Azhar : Menyelesaikan soalan kuiz kumpulan

- Mohamad Rizal : Mencari bahan untuk kuiz

Bil Nama No Matrik T/ Tangan

1 Mohd. Azhar Bin Ali DB 100201

2 Mohamad Rizal B. Hashim DB 100212

3 Muhd. Razman B. Razali DB 100206

Ketua : Mohd Azhar Ali

Setiausaha : Mohamad Rizal Hashim

Bendahari : Muhd. Razman Razali

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- Muhd Razman : Menyiapkan jadual FILA

5. Ketua kumpulan menetapkan tarikh perjumpaan kedua iaitu pada 22 April 2014 .

6. Mesyuarat ditangguhkan pada 10.00 p.m.

Disediakan oleh, Disemak oleh,

_______________ _______________

( Mohamad Rizal ) ( Mohd Azhar )

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MINIT MESYUARAT 2 / 2014

TAJUK : Pengisian FILA Table

TARIKH : 22/04/2014 ( Selasa)

MASA : 5.00 ptg – 6.00 ptg

TEMPAT : Restoran Mamak Iman Sg. Buloh

KEHADIRAN : 3/3

CATATAN MESYUARAT

1. Perbincangan bersama cara untuk mengisi Fila Table.

2. Setiap ahli memberi idea dan perbincangan untuk mengisi boring FILA

3. Setiausaha membuat catatan dan menaip isi jadual .

4. Ahli kumpulan menyemak dan membincangkan untuk diterima sebagai isi

5. Meyuarat ini ditangguhkan pada 6.00 ptg

Disediakan oleh, Disemak oleh,

_______________ _______________

Bil Nama No Matrik T/ Tangan

1 Mohd. Azhar Bin Ali DB 100201

2 Mohamad Rizal B. Hashim DB 100212

3 Muhd. Razman B. Razali DB 100206

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( Mohamad Rizal ) ( Mohd Azhar )

FILA Table

Facts Idea Learning Issues Action Plan / resources Needed

Display of can on glocery shelf.

Consists of 57 cans on the bottom.

53 cans in the next row, 49 cans in the next row and so on until the top row has 9 cans.

Reduced 4 cans by per row

Calculate the differences between the number of can.

Calculate the ratio of the number of can.

Make the conclusions based on the answer get

Using the knowledge of sequence and series to solve the questions.

Analysis the result and do the conclusions.

Learning the theory of sequence and series to make the conclusions.

Search some reliable reference books from internet and UTHM library.

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MINIT MESYUARAT 3 / 2014

TAJUK : Menyelesaikan Masalah soalan kuiz

TARIKH : 27/4/2014 (Sabtu )

MASA : 11.00 pg – 12.30 tgh

TEMPAT : Perpustakaan UTHM

KEHADIRAN : 3/3

CATATAN MESYUARAT

1. Perbincangan bersama ahli kumpulan

2. Semua ahli bekerjasama untuk mencari jawapan bagi soalan kuiz kumpulan .

3. Rujukan dibuat dari buku yang didapati dari perpustakaan UTHM .

4. Jawapan yang diperolehi akan dirujuk dengan nota dalam buku rujukan .

Disediakan oleh, Disemak oleh,

_______________ _______________

( Mohamad Rizal ) ( Mohd Azhar )

Bil Nama No Matrik T/ Tangan

1 Mohd. Azhar Bin Ali DB 100201

2 Mohamad Rizal B. Hashim DB 100212

3 Muhd. Razman B. Razali DB 100206

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Question 1:

A display of can on a grocery shelf consists of 57 cans on the bottom, 53 cans in the next row, 49 can in the next row ans so on until the top row has 9 cans.

(a) Referring to the first three rows:

(i) What the difference between the number of can in the 2nd row and the 1st row, the 3rd row and the 2nd row?

57, 53, 49 ……9

The difference between the number of can in the 2nd row and the 1st row.

d =53 – 57

= -4

The difference between the time spend for the 3rd week and the 2nd week.

d =49 – 53

= -4

(ii) What is the ratio of the number of can in the 2nd row and the 1st row, the 3rd

row and the 2nd row?

The ratio of the number of can in the 2nd row and the 1st row

r=5357

The ratio of the number of can in the 3rd row and the 2nd row

r=4957

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(iii) Base on (i) and (ii), what is your conclusion?

The difference between the two rows are constant. The ratio between the two rows

are different. Therefore, the cans are arranged according to Arithmetics

progressions.

(b) How many cans in total are in the display?

Tn = a+(n-1)d

9 = 57 + (n-1)(-4)

-4n + 4 = -48

n-1 = 12

n = 13

Sn = n2 [2a+(n-1)d]

S13 = 132 [2(57) + (13-1) (-4)]

= 429

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Question 2:

You are given a box with small blocks. You asked to put one marble in the 1st box, 2 marble in the 2nd box, 4 marble in the 3rd box and so on until you completed all the block in the box.

a) Referring to the first three measurement:

i) What is the different between the 2nd measurement and the 1st measurement, the 3rd

measurement dan the 2nd measurement?

i) d1 = 2 - 1

= 1

d2 = 4 - 2

= 2

ii) What is the ratio of the 2nd measurement and the 1st measurement, the ratio of the 2nd measurement?

(ii) r1 = 21

= 2

r2 = 42

= 2

iii) Base on ( i ) and ( i i ), what is your conclusion?

The difference between the two rows are different. The ratio between the two rows are constant. Therefore, the cans are arranged according to Geometry progressions.

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b) How many marbles are needed to fill up all the blocks in the box?

a=1, r=2 , n=20

=

= = 1048576 – 1 = 1048575

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