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sayısal yöntemler hatalı konum metodu ile ortalama bulma
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f(x)=x-2x-3x=2.0x=5.0f(x)f(x)= -36x=x-((f(x)(x-x))/(f(x)-f(x)))x= 2. 6E=((x-x)/x)100E= 23. 077
x=2.6f(x)f(x)= -17. 28x= 2. 8571E= 9.0
x=2.8571f(x)f(x)= -6. 6142x= 2. 9512E= 3. 1887
x=2.9512f(x)f(x)= -2. 3138x= 2. 9836E= 1. 0859
x=2.9836f(x)f(x)= -0.78397x= 2. 9945E= 0.36461
x=2.9945f(x)f(x)= -0.26364x= 2. 9982E= 0.12224
x=2.9982f(x)f(x)= -8. 636110x= 2. 9994E= 4. 000210
x=2.9994f(x)f(x)= -2. 879610x= 2. 9998E= 1. 333410
x=2.9998f(x)f(x)= -9. 599510x= 2. 9999E= 4. 444510
x=2.9999f(x)f(x)= -4. 799910x= 3. 0000E= 2. 222210a