22
Dr Andrew French. September 2020. TEACHER NOTES

Frequency response of a capacitor - Eclecticon response of...frequency range 0 to 3,000Hz. 5. Also record and plot the RMS current vs frequency. 6. Fixing the frequency at 200Hz, find

  • Upload
    others

  • View
    4

  • Download
    0

Embed Size (px)

Citation preview

  • Dr Andrew French. September 2020.

    TEACHER NOTES

  • Equipment Signal generator + mains cable kettle lead + BNC to 4mm converter

    Dual input oscilloscope + mains cable kettle lead + 2 x BNC to 4mm converter

    Capacitor block (non-electrolytic) range 0.220mF to 15mF.

    Fixed resistors (only 100ohm will be used)

    Multimeter (set in ACA mode i.e. gives RMS amplitude of (AC) current)

    4 x blue wires (main RC circuit loop)

    2x green wires (PD across AC input, connected to oscilloscope CH1)

    2x green wires (PD across capacitor, connected to oscilloscope CH2)

  • Kit list

    Signal generator + mains cable kettle lead + BNC to 4mm converter

    Dual input oscilloscope + mains cable kettle lead + 2 x BNC to 4mm converter

    Capacitor block (non-electrolytic) range 0.220mF to 15mF.

    Fixed resistors (only 100ohm will be used)

    Multimeter (set in ACA mode i.e. gives RMS amplitude of (AC) current)

    4 x blue wires (main RC circuit loop)

    2x green wires (PD across AC input, connected to oscilloscope CH1) 2x green wires (PD across capacitor, connected to oscilloscope CH2)

  • Suggested experiments 1. Fix Vin at about 3.0V (the middle value of the signal generator amplitude).

    2. Fix R at about 100W (measure it accurately with a multi-meter).

    3. Fix capacitances at 1.0mF, 2.2mF and 4.7mF. Do the middle value only if time permits.

    4. Record and plot gain |Vc/Vin| vs frequency f for ten to twenty measurements over the

    frequency range 0 to 3,000Hz.

    5. Also record and plot the RMS current vs frequency.

    6. Fixing the frequency at 200Hz, find the RMS current for the full range of capacitances. You should find that current is proportional to capacitance.

    7. For a 4.7mF capacitor, keep the frequency at 3,000Hz and switch to a square wave, and then a triangle wave output from the signal generator. Observe that the RC circuit integrates the input, if the output is taken across the capacitor. i.e. an output of triangle waves or parabolae, respectively.

    8. See if you can observe a differentiation effect for low frequencies (i.e. about 100Hz) when the output is taken across the resistor instead of the capacitor.

  • Channel 1 (CH1): Potential difference across output of signal generator (upper trace). Channel 2 (CH2): Potential difference across capacitor (lower trace).

    Dual channel oscilloscope

  • Input voltage from signal generator (CH1)

    Potential difference across the capacitor (CH2)

    Timebase = 0.5ms

    Voltage divisions = 2.0V

    2 1.4 2.0V

    1.4V

    c

    c

    V

    V

    2 3.4 2.0V

    3.4V

    in

    in

    V

    V

    3

    1

    2.95 0.5 10 s

    678Hz

    f

    f

    Phase difference

    o o0.30360 36.62.95

    0.3

    2.95

    3.4

    1.4

  • Gain reduces as frequency increases. 1

    2c

    fRC

    Characteristic frequency

  • Phase shift tends to 90o as frequency increases

    1

    2c

    fRC

    Characteristic frequency

  • Current is proportional to frequency (and capacitance) when frequencies are much less than the characteristic frequency.

    1

    2c

    fRC

    When frequencies are much greater than the characteristic frequency, current tends to a constant:

    2

    in

    RMS

    VI

    R

    2

    in

    RMS

    VI RC

    R

    Characteristic frequency:

  • 2

    in

    RMS

    VI

    R

    2

    in

    RMS

    VI RC

    R

    Current is proportional to capacitance when frequencies are much less than the characteristic frequency.

    When frequencies are much greater than the characteristic frequency, current tends to a constant:

  • C C

    in C R

    V Z

    V Z Z

    1

    R

    C

    Z R

    Zi C

    2 f

    2 2 2

    1 1 1

    1 1 1

    C

    in

    V i C i RC

    V i C R i RC R C

    1tan2 2 22 2 2

    11

    1

    i RCC

    in

    VR C e

    V R C

    i t i tC C in in

    V V e V V e

    2 2 2

    1

    1

    C

    in

    V

    V R C

    1tan RC

    1

    RC

    Mathematical model of voltage gain vs frequency

    Complex impedence Potential divider

    Capacitor

    Resistor ‘driving’ AC input inV RV

    I

    CV

    i t

    in inV V e

    Argand (phasor) diagram

    Assume steady state

  • 2 2 2

    1

    1

    C

    in

    V

    V R C

    2 f

    1tan RC

    1

    2c

    fRC

    Characteristic frequency

    Note linear phase response

    1

    RC

    RC

    if phase in radians

  • Finding the RMS current

    1

    1

    tan

    2 2 2

    tan

    2 2 2

    2 2 2

    2 2 2

    1

    1

    1

    2 1

    i t RCin

    C

    C C

    C C

    i t RCin

    in

    in

    RMS

    VV e

    R C

    V IZ

    V I i C I i CV

    i C VI e

    R C

    V RCI

    R R C

    V RCI

    R R C

    1

    2c

    fRC

    Characteristic frequency

    1

    22

    in

    RMS

    VI f

    RCR

    1

    22

    in

    RMS

    VI RC f

    RCR

    Low frequency limit: Current is proportional to frequency and capacitance.

    High frequency limit: Current tends to a constant, as one would expect for a DC circuit.

    2 f

  • 2 2 22 1

    in

    RMS

    V RCI

    R R C

    2 f

    1

    2c

    fRC

    Characteristic frequency

    1

    22

    in

    RMS

    VI f

    RCR

    1

    22

    in

    RMS

    VI RC f

    RCR

  • RC circuit as an integrator

    1

    2

    tan

    2 2 2

    1

    1

    1

    i t RCin

    C

    i tin in i t in

    C

    i t

    in in

    ini t i t

    in in

    RCC in

    VV e

    R C

    RC

    V V VV e e

    RC i RC i RC

    V V e

    VV dt V e dt e c

    i

    V V dt

    High frequency limit

    1

    2f

    RC

    So a square wave input will produce a ‘sawtooth’ (triangular wave) capacitor voltage.

    2

    2 1

    i

    i

    e i

    e i

  • 1RCC in

    V V dt High frequency limit

    1

    2f

    RC

    Square (ish!)-wave input

    Saw-tooth output Saw-tooth input

    Parabola output

    RC circuit as an integrator

    15μ

    107

    3.4V

    3,125Hz

    199Hz

    2

    in

    C F

    R

    V

    f

    RC

    W

  • RC circuit as an differentiator

    1 1

    1

    R

    in

    R in

    i t

    in in

    in

    in

    in

    R

    V R i RC

    V i C R i RC

    RC

    V i RCV

    V V e

    dVi V

    dt

    dVV RC

    dt

    Low frequency limit

    1

    2f

    RC

    So a ‘sawtooth’ (triangular wave) input will result in a square wave resistor potential difference.

    Note: For an unknown reason I couldn’t get this to work, even when using the 0.22mF capacitor and frequency turned down to 100Hz. In this case fc = 6,786Hz. AF 26/09/2020

  • Excel sheet of measurements taken using RC circuit setup

    As frequency and capacitance changes, the amplitude of the signal generator also changes slightly. In this example, the signal generator amplitude has to be changed for every measurement to ensure a consistent value of 3.4V. The latter was measured using the oscilloscope.

  • Experimental data underlaid with model curves

  • Model (line) vs measurement (+). R = 107W as measured.

    Model appears to be an overestimate. Internal resistance not accounted for?

  • Does the internal resistance of the signal generator change as capacitance increases? R increased to 120W as a guess.