Flexural Analysis and Design of Beamns

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    a n e n orceConcrete-1

    Flexural Behavior of Beams Under Service LoadWhen loads are applied on the beam stresses are producedin concrete and steel reinforcement

    If stress in steel bars is less than yield strength, steel is in

    elastic range If stress in concrete is less than 0.6fc concrete is assumed to

    be within elastic range

    Following are important points related to Elastic Range: Loads are un-factored

    Materials are in elastic range

    Analysis and design are close to allowable stress analysis anddesign

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    a n e n orceConcrete-1

    Assumption for the Study of Flexural Behavior

    Plane sections of the beam remains plane after bending.

    The material of the beam is homogeneous and obeys hooks law

    Stress Strain Perfect bond exists between steel & concrete so whatever strain

    is produced in concrete same is produced in steel

    All the applied loads up to to failure are in equilibrium with theinternal forces developed in the material

    At the strain of 0.003 concrete is crushed

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    a n e n orceConcrete-1

    Assumption for the Study of FlexuralBehavior(contd)

    When cracks appear on the tension face of beam itscapacity to resist tension is considered zero

    Stress and strain diagrams for steel and concrete aresimplified

    Strain

    Stress

    Steel

    Strain

    StressConcrete

    0.6fc

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    a n e n orceConcrete-1

    Flexural Behavior BeamsGeneral Procedure for the Derivation of Formula

    Step # 1 Draw the cross section of beam with reinforcement

    Step # 2 Draw the strain diagram for the cross section

    Step # 3 Draw the stress diagram

    Step # 4 Show location of internal resultant forces

    Step #5 Write down the equation for given configuration

    C

    Tla

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    a n e n orceConcrete-1

    Flexural Behavior Beams (contd)

    2. When Cracks are Appeared on tension Side

    C

    Tla

    N.A.

    fc

    c

    fs

    StrainDiagram

    StressDiagram

    ResultantForce Diagram

    When the tension side is cracked the concrete becomesineffective but the strains goes on increasing. The steelcomes in to action to take the tension.

    s

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    a n e n orceConcrete-1

    Flexural Behavior Beams (contd)

    3. When Compression StressesCross Elastic Range

    C

    Tla

    N.A.

    0.85f

    c

    c

    fs

    StrainDiagram

    StressDiagram

    ResultantForce Diagram

    It is clear that the stress diagram is infect obtained by rotatingthe stress strain diagram of concrete.Strains keeps on changing linearly in all three cases.

    s

    fc0.85fc

    Stress

    Strain

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    a n e n orceConcrete-1

    Flexural Behavior Beams (contd)

    Final Equation for Calculating Moment Capacity

    Mr= T x l

    a= C x l

    a

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    a n e n orceConcrete-1

    Flexural/Bending Stress Formula

    f = My/I (Valid in Elastic RangeOnly)

    f = M/(I/y)

    f = M/Sf = Flexural Stress

    S = Elastic Section Modulus

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    Shear Stress Formula

    = VAY/(Ib)(Valid in Elastic Range Only)

    = VQ/(Ib) = Shear StressQ = First moment of area

    First Moment of Shaded Area, Q = (b x d ) h

    a n e n orceConcrete-1

    b

    d

    h

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    a n e n orceConcrete-1

    Notationb As (Compression

    Face)

    As(TensionFace)

    h d, Effective Depth d

    bw

    b

    hf

    fc = concrete stress at any load level at any distance formthe N.A

    fc= 28 days cylinder strength

    c = Strain in concrete any load level

    cu = Ultimate concrete strain, 0.003

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    a n e n orceConcrete-1

    Notation(contd)fy = Yield strength of concrete

    fs = Steel stress at a particular load level

    s = strain in steel at a particular level, s = fs/Es

    y = Yield strain in steel

    Es = Modulus of elasticity of steel

    Ec = Modulus of elasticity of concrete

    ,Roh = Steel Ratio, = As/A

    c= A

    s/(bxd)

    T = Resultant tensile force

    C = Resultant compressive force

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    a n e n orceConcrete-1

    Notation(contd)

    N.A

    h c=k

    d

    d

    C

    T

    la = jd

    jd = Lever arm j =la /d (valid for elastic range)

    kd = Depth of N.A. from compression face, k = c/d

    j and k are always less than 1.

    b

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    Concluded