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8/13/2019 Differential form of Maxwell's equations
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8/13/2019 Differential form of Maxwell's equations
2/10
Courtesy of Krieger Publishing. Used with permission.
Courtesy of Krieger Publishing. Used with permission.
6.641, Electromagnetic Fields, Forces, and Motion Lecture 2Prof. Markus Zahn Page 2 of 10
8/13/2019 Differential form of Maxwell's equations
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= Ax (x,y,z dydz) Ax (x - )x,y,z dydz1 1'
+ Ay (x,y+ ) Ay )y,z dxdz (x,y,z dxdz2 2'
+ Az (x,y,z+ ) Az )z dxdy (x,y,z dxdy3 3'
( ) ( -x,y,z)A x,y,z A x x x x y z + x
( ) A x,y,z( )A x,y,z + z z z + z
Ax Ay Az V x
+y
+z
A dSi A A Adiv A = lim
S
=x
+y
+z
V 0 V x y z
Del Operator: = i
x+ i
y+ i
zx y z
Ax Ay Azdiv A= iA = + +x y z
2. Gauss Integral Theorem
A x,y + y,z A x,y,z y
y ( ) y ( )
Courtesy of Krieger Publishing. Used with permission.
6.641, Electromagnetic Fields, Forces, and Motion Lecture 2Prof. Markus Zahn Page 3 of 10
8/13/2019 Differential form of Maxwell's equations
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N
A dS = i ii A dSS i=1 dS
N i
N
= lim (iA)ViN V 0 i=1
n
= iA dVV
V iA dV = S A ida
3. Gauss Law in Differential Form0 E ida= i(0E dV =) dVS V V
i 0E = ( ) H ida= i H dV = 0 0 ( 0 )
S V
0H = 0i( )II. Stokes Theorem
1. Curl OperationA ds = Curl A( ) i i da
C S
A ds iCurl A = lim C( )
n n 0 dada n
6.641, Electromagnetic Fields, Forces, and Motion Lecture 2Prof. Markus Zahn Page 4 of 10
8/13/2019 Differential form of Maxwell's equations
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A ida = A idsS C
Courtesy of Krieger Publishing. Used with permission.
6.641, Electromagnetic Fields, Forces, and Motion Lecture 2Prof. Markus Zahn Page 5 of 10
8/13/2019 Differential form of Maxwell's equations
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x+x y+ y x A ids = A (x, y dx +) Ay x + ) A x, y + )( x, y dy + x ( y dxxC x x+ x y
1 2 3
y
+ x, y dy Ay ( )y+ y
4
A x, y( ) - A x, y + ) A x + x, y) - A x, y( ) x x ( y y ( y = x y + y x
Ay Ax =daz - x y A ds
xCurl A =( )z=
da
i A
x
y-
A
yz
By symmetry
( ) = A dsi A
-A
Curl A = x zy da z xy
Curl A = A dsi
=Az -
Ay( )x dax y z
A Ay A A Ay A Curl A = i
x z - + i y x - z + i z - x y z z x x y
i x i y i z
= det x y z Ax Ay Az
= A
6.641, Electromagnetic Fields, Forces, and Motion Lecture 2Prof. Markus Zahn Page 6 of 10
8/13/2019 Differential form of Maxwell's equations
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2. Stokes Integral Theorem
Courtesy of Krieger Publishing. Used with permission.
N
lim A dsi = A dsiiN i=1 dCi C
N = (A)idai
i=1
= (A)idaS
Courtesy of Krieger Publishing. Used with permission.
6.641, Electromagnetic Fields, Forces, and Motion Lecture 2Prof. Markus Zahn Page 7 of 10
8/13/2019 Differential form of Maxwell's equations
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3. Faradays Law in Differential Formi = (E)ida = - d H idaE ds dt 0C S S
HE = -0
t
4. Ampres Law in Differential Form
H ds = H ida = J da+ d 0 E idai i dtC S S SH = J+ 0 Et
III. Applications to Maxwells Equations
1. Vector Identitylim A ids =0 = A ida= i A dV ( ) ( )C 0
C S V
i(A)= 02. Charge Conservation
iH = J + 0 E t
0 = iJ + 0 E t
0 = iJ +
t
3. Magnetic Field H iE=-0 t
0 = -t
0 i(0H)= 0i H
6.641, Electromagnetic Fields, Forces, and Motion Lecture 2Prof. Markus Zahn Page 8 of 10
8/13/2019 Differential form of Maxwell's equations
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4. Vector Identity
b
E dl = a i ( ) ( ) ba
if a=b
i = ( ) (a)= 0E dl a C
E = idl = 0C
f d f d = f 0( ) i a= i l 0 ( )=S C
6.641, Electromagnetic Fields, Forces, and Motion Lecture 2Prof. Markus Zahn Page 9 of 10
8/13/2019 Differential form of Maxwell's equations
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IV. Summary of Maxwells Equations in Free Space
Integral Form Differential Form
Faradays Law
d H E dli = 0 H da E = 0idt tC S
Amperes Law
H dl J da+ 0 i 0i = i d E da H =J + Edt tC S S
Gauss Law E da ( 0 )i = dV i E = 0S V
0i 0 i(0H)= 0H da =S
Conservation of charge
d C
J da+ dt V
= 0 iJ +t
= 01. i dV
2. S
J + 0
E
t
ida = 0 i
J + 0
E
t
= 0
EQS Limit MQS Limit
H E 0, E = E = 0 t iE = i = = (Poissons Eq.) H =J
0( ) 2
( ) (x ',y ',z ') dx'dy'dz' x,y,z =x',y',z' 40
(x x ')2
+(y y ')2
+(z z ')2
i( H)= 0 H = A 0 02 A = 0 J, iA =0
0 J x ',y ', z' dx dy dzA x,y,z( )= ( ) ' ' '
x',y',z' 4 (x x ')2
+(y y ')2
+(z z ')2
12
12
6.641, Electromagnetic Fields, Forces, and Motion Lecture 2Prof. Markus Zahn Page 10 of 10