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Design of Concrete Stairs Concrete and reinforcing steel bar properties Concrete unit weight g C = 23.6 kN / m 3 Concrete strength f' C = 28 MPa Steel yield strength f y = 276 MPa Moment reduction factor f m = 0.9 Main bar diameter f bm = 16 mm Temperature bar diameter f bt = 10 mm Concrete stair properties Rise length r = 0.18 m Tread length t = 0.30 m Number of steps n = 10 Concrete slab properties Slab thickness t s = 0.125 m Concrete cover c = 20 mm Effective depth d = t S - c - (f bm / 2) 97 mm Weight of slab w S = g C t S (r 2 + t 2 ) 1/2 / t 3.44 kPa Weight of riser and tread w rt = g C r / 2 2.12 kPa Total dead load w D = w S + w rt 5.56 kPa Live load of stairs w L = 4.80 kPa Total load per meter width w U = 1.4w D + 1.7w L 15.95 kN/m Horizontal span L = nt 3.00 m Maximum moment M U = w U L 2 / 8 17.94 kN-m Main bar reinforcement m = 1.7 f' c / f y 0.17 n = m M U / (f m f y b d 2 ) 0.00118 Check for r max = 0.75 * 0.85 * (f' c / f y )*[600 / (600 + f y )] r max = 0.04430 Solve for r R using the formula r R 2 - mr R + n = 0 r R = 0.00712 Check for r min = 1.4 / f y r min = 0.00507 Use 0.00712 A s = r b d 690.47 mm 2 Main bar space s b = 1000 (p/4) f bm 2 / A s 291.20 say 200 mm

Concrete Design - Stairs

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Page 1: Concrete Design - Stairs

Design of Concrete Stairs

Concrete and reinforcing steel bar properties

Concrete unit weight gC = 23.6 kN / m3

Concrete strength f'C = 28 MPa

Steel yield strength fy = 276 MPa

Moment reduction factor f m = 0.9

Main bar diameter fbm = 16 mm

Temperature bar diameter fbt = 10 mm

Concrete stair properties

Rise length r = 0.18 m

Tread length t = 0.30 m

Number of steps n = 10

Concrete slab properties

Slab thickness ts = 0.125 m

Concrete cover c = 20 mm

Effective depth d = tS - c - (fbm / 2) 97 mm

Weight of slab wS = gC tS (r2 + t

2)1/2

/ t 3.44 kPa

Weight of riser and tread wrt = gC r / 2 2.12 kPa

Total dead load wD = wS + wrt 5.56 kPa

Live load of stairs wL = 4.80 kPa

Total load per meter width wU = 1.4wD + 1.7wL 15.95 kN/m

Horizontal span L = nt 3.00 m

Maximum moment MU = wU L2 / 8 17.94 kN-m

Main bar reinforcement

m = 1.7 f'c / fy 0.17

n = m MU / (f m fy b d2) 0.00118

Check for rmax = 0.75 * 0.85 * (f'c / fy)*[600 / (600 + fy)] rmax = 0.04430

Solve for rR using the formula rR2 - mrR + n = 0 rR = 0.00712

Check for rmin = 1.4 / fy rmin = 0.00507 Use 0.00712

As = r b d 690.47 mm2

Main bar space sb = 1000 (p/4) fbm2 / As

291.20 say 200 mm

Page 2: Concrete Design - Stairs

Temperature bar reinforcement

As = 0.002 b t 250.00 mm2

Temperature bar space sb = 1000 (p/4) fbt2 / As

314.16 say 300 mm

Provide 16-mm main reinforcement bars @ 200mm o.c.

Provide 10-mm main temperature bars @ 300mm o.c.

Shear rections from concrete stairs

Shear dead load VD = wD L / 2 8.35 kN/m (unfactored)

Shear live load VL = wL L / 2 7.20 kN/m (unfactored)