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Cavendish Experiment. Presented by Mark Reeher. Lab Partner: Jon Rosenfield For Physics 521. Presentation Overview. Historical Background Theory Experimental Setup and Methods Results Analysis of Results Uncertainties Conclusions. Brief Timeline of Gravitational Physics. - PowerPoint PPT Presentation
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Cavendish ExperimentCavendish Experiment
Presented by Mark ReeherPresented by Mark Reeher
Lab Partner: Jon RosenfieldLab Partner: Jon RosenfieldFor Physics 521For Physics 521
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Slide 2
Presentation OverviewPresentation Overview
Historical BackgroundHistorical Background
TheoryTheory
Experimental Setup and MethodsExperimental Setup and Methods
ResultsResults
Analysis of ResultsAnalysis of Results– UncertaintiesUncertainties
ConclusionsConclusions
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Slide 3
Brief Timeline of Gravitational Brief Timeline of Gravitational PhysicsPhysics
44thth Century B.C: Aristotle – tendency of Century B.C: Aristotle – tendency of objects to be pulled to Earthobjects to be pulled to Earth
1645: Ismael Bulliadus - inverse square 1645: Ismael Bulliadus - inverse square relationrelation
1665: Sir Isaac Newton - 1665: Sir Isaac Newton - 1798: Henry Cavendish – calculation of 1798: Henry Cavendish – calculation of
Universal Gravitation Constant, GUniversal Gravitation Constant, G Early 1900s: Einstein-Early 1900s: Einstein-
• Inertia-gravitation equivalenceInertia-gravitation equivalence• General relativityGeneral relativity
221
g r
MMG F
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Slide 4
Cavendish ExperimentCavendish Experiment
John Michell – conception of experimentJohn Michell – conception of experiment– Torsion BalanceTorsion Balance
Henry Cavendish – rebuilt balance and Henry Cavendish – rebuilt balance and ran experiment in ran experiment in 1797-17981797-1798
Basic Idea – directly Basic Idea – directly
measure Fmeasure Fgg, find G, find G Found:Found:G = G = 6.754 × 106.754 × 10−11−11 m m33kgkg-1-1ss-2-2
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Slide 5
Committee on Data for Science Committee on Data for Science and Technology’s Valueand Technology’s Value
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Theory – Experimental DesignTheory – Experimental Design
Large masses brought Large masses brought near small massesnear small masses
Gravitational force Gravitational force movement in torsion movement in torsion balancebalance
Study motion to determine Study motion to determine FFgg
With FWith Fgg, measure M, m, r, measure M, m, r– Newton’s gravitational Newton’s gravitational
equationequation– Result = calculated GResult = calculated G
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Slide 7
Derivation - 1Derivation - 1
FαFβ
22
22
11
2
2
22
rrGMmL
r
Mm
r
MmGL
FL
FL
FdFd
Top View
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Slide 8
Derivation - 2Derivation - 2
22
11
2 rrGMmL /2/2 IT
2 I
1
22
2
222
112
11
2
rrLMm
IG
Irr
GMmL
1
22
112
rrLMm
G
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Slide 9
Small Angle ApproximationSmall Angle Approximation
For simplicity, we assume θ is very For simplicity, we assume θ is very smallsmall– Torque dot productTorque dot product– Tan θ = θTan θ = θ
This assumption confirmed by finding This assumption confirmed by finding the largest possible angle of setupthe largest possible angle of setup– θθmaxmax = 0.03884 = 2.226º = 0.03884 = 2.226º– ~0.05% difference between tan θ and θ~0.05% difference between tan θ and θ
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Slide 10
Experimental SetupExperimental Setup
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Experimental SetupExperimental Setup
Large masses
Ametek plotter (converted)
He-Ne laser
Torsion balance enclosure
Vacuum pump (oil)
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Slide 12
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Slide 15
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Slide 16
Setup DiagramSetup Diagram
Laser
Plotter
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Slide 17
Setup DiagramSetup Diagram
So we need to keep in mind, the plotter reacts to 2θ
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Slide 18
Setup NotesSetup Notes
Torsion enclosure pumped to ~100 mTorrTorsion enclosure pumped to ~100 mTorr
Data recorded automatically in LabviewData recorded automatically in Labview– Photodiode position vs time (4 s intervals)Photodiode position vs time (4 s intervals)
Six total trialsSix total trials– 2 counter-clockwise (positive) torque2 counter-clockwise (positive) torque– 2 clockwise (negative)torque2 clockwise (negative)torque– 2 no mass2 no mass
Fα
FβFα
Fβ
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Slide 19
Given in lab manualGiven in lab manual– m = 0.019 kgm = 0.019 kg– MMrodrod = 0.031 kg (square cross section) = 0.031 kg (square cross section)– L/2 = 15.24 cmL/2 = 15.24 cm
Distance measurements (in inches)Distance measurements (in inches)
DDdd (mirror-diode) = 45 (mirror-diode) = 45 1/321/32”” ω and θ are found from Matlab dataω and θ are found from Matlab data
Results (Our Measurements)Results (Our Measurements)
1 2 3 4d 3.8756 3.9097 3.9517 3.9027D 0.382 0.163 0.278 0.263
d-tube 2.197 2.197 2.197 2.197
1 2
34
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Slide 20
700
750
800
850
900
950
1000
1050
1100
0 10000 20000 30000 40000 50000 60000 70000
Time (s)
Dio
de
Po
siti
on
(ar
b u
nit
s)
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Slide 21
AnalysisAnalysis Data from best fit:Data from best fit:
– General model:General model:
f(x) = a*exp(-x/b)*cos(c*x+d)+ef(x) = a*exp(-x/b)*cos(c*x+d)+e
– Coefficients (with 95% confidence bounds):Coefficients (with 95% confidence bounds): a = 131 (130.4, 131.6)a = 131 (130.4, 131.6) b = 1.029e+004 (1.006e+004, 1.051e+004)b = 1.029e+004 (1.006e+004, 1.051e+004) c = 0.007577 (0.007575, 0.007579)c = 0.007577 (0.007575, 0.007579) d = 0.004448 (0.0001244, 0.008771)d = 0.004448 (0.0001244, 0.008771) e = 682.1 (681.9, 682.3)e = 682.1 (681.9, 682.3)
– Goodness of fit:Goodness of fit: SSE: 1000SSE: 1000 R-square: 0.9986R-square: 0.9986 Adjusted R-square: 0.9986Adjusted R-square: 0.9986 RMSE: 1.002RMSE: 1.002
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Slide 22
AnalysisAnalysis I calculation I calculation
Κ calculationΚ calculation
Avg K = 2.60588 x 10Avg K = 2.60588 x 10-7-7 ++ 1.197 x 10 1.197 x 10-11-11 kg m/s kg m/s22
kg3
222
104.4
)4
1
5
2(2)2(
12
1
2
I
mLmrrLMI
III
mmrod
mrod
2 Iω δω K δK 1/δK 2̂ K/δK^2 I
CW1 0.007577 0.000001 2.52608E-07 3.33388E-11 8.99705E+20 2.27273E+14 4.40E-03
CW2 0.0075975 0.0000013 2.53977E-07 4.34577E-11 5.29501E+20 1.34481E+14
CCW1 0.00761 0.0000003 2.54813E-07 1.00452E-11 9.91021E+21 2.52525E+15
CCW2 0.007617 0.0000005 2.55282E-07 1.67574E-11 3.56112E+21 9.09091E+14
NM1 0.0076955 0.0000005 2.60571E-07 1.69301E-11 3.48884E+21 9.09091E+14NM2 0.007696 0.0000005 2.60605E-07 1.69312E-11 3.48839E+21 9.09091E+14
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Slide 23
AnalysisAnalysis rrii calculation (m) calculation (m)
θ calculationθ calculation
Avg eAvg eoo from “NM” values: from “NM” values:eeo o = 3.954” = 3.954” ++ 0.000177” 0.000177”
Define xDefine xii = e = eoo - e - eii
tubeiii dDdr2
1
2
1
r1 0.0868
r2 0.0817
r3 0.0852
r4 0.0841
δr 5.24E-03
03125.45tan
2
1
/)2tan(
01 iee
adjopp
e in inches δe X δxCW1 896.9 4.4845 0.0001 -0.53037 0.000203CW2 888.35 4.44175 0.00065 -0.48763 0.000674CCW1 682.1 3.4105 0.0005 0.543625 0.00053CCW2 682.75 3.41375 0.0004 0.540375 0.000437
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Slide 24
AnalysisAnalysis Now find θ from tanNow find θ from tan-1-1::
Finally… we find G (mFinally… we find G (m33ss-2-2):):
Avg G = (3.89829 x 10Avg G = (3.89829 x 10-10-10++ 1.7129 x 10 1.7129 x 10-11-11)/M)/M
θ dθ/dX dθ/dD δθ
CW1 -0.00589 0.022204 0.000262 4.67E-06
CW2 -0.00541 0.022204 0.00024 8.37E-06CCW1 0.006036 0.022204 -0.00027 7.23E-06CCW2 0.006 0.022204 -0.00027 6.4E-06
1
22
112
rrLMm
G
dG/dK dG/dθ dG/drα dG/drβ G δG sq'd δG
CW1 0.001569954 -6.94676E-08 4.62558E-09 4.8911E-09 4.09111E-10 1.24445E-21 3.53E-11CW2 0.0014434 -6.94676E-08 4.25272E-09 4.49683E-09 3.76133E-10 1.05216E-21 3.24E-11CCW1 0.001494708 6.45259E-08 -4.90547E-09 -4.49737E-09 3.89503E-10 1.21631E-21 3.49E-11CCW2 1.49E-03 6.45259E-08 -4.87614E-09 -4.47048E-09 3.87174E-10 1.20177E-21 3.47E-11
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Slide 25
UncertaintyUncertainty
Total Uncertainty relation for G:Total Uncertainty relation for G:
22
2
2
22
22
rr
Gr
r
GGGG iiii
1
22
112
rrLMm
Gi000000000000
1
22
112
rrLMm
Gi
2
223
114
rrLMmrr
Gi2
223
114
rrLMmrr
Gi
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Slide 26
UncertaintyUncertainty Each of the four variables also had combined Each of the four variables also had combined
uncertainty in their calculationuncertainty in their calculation– All type A aside from distance measurementsAll type A aside from distance measurements
In a few cases, values were averaged:In a few cases, values were averaged:
i i
i i
i i
i
x
x
x
2
2
2
11
1
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Slide 27
ConclusionsConclusions M = 5.701 kg M = 5.701 kg ††
– Gives us:Gives us:
– GGCavendishCavendish = = 6.754 × 106.754 × 10−11−11 m m33kgkg-1-1ss-2-2
– GGCODATA CODATA = 6.67428 = 6.67428 × 10× 10−11−11 m m33kgkg-1-1ss-2-2
Obvious setup interferenceObvious setup interference MMEarthEarth
† conversation with Jose
2131211 1000431083796 skgm-- ..G
kg242
2
1083.5
G
grM
r
mMGmgF
EarthEarth
Earth
Earthg
Accepted value = 5.97 x 1024 kg