BÁO CÁO THÍ NGHIỆM ĐIỆN TỬ CÔNG SUẤT cao... · BÁO CÁO THÍ NGHIỆM ĐIỆN TỬ CÔNG ... pha và linh kiện sử dụng tương ... điều khiển của các Thyristor

B GIO DC V O TO

BO CO TH NGHIM

IN T CNG SUT

Bin son: ThS. Bi Hu Hin

www.hutech.edu.vn Ti Liu Lu Hnh Ti HUTECH

BO CO TH NGHIM IN T CNG SUT

n bn 2015

BO CO TH NGHIM IN T CNG SUT 1

MC LC

MC LC ...................................................................................... 1

BI 1: TH NGHIM MCH KCH THYRISTOR V TRIAC ................................................. 2

BI 2: TH NGHIM B CHNH LU CU CNG SUT MT PHA .................................... 14

BI 3: TH NGHIM B CHNH LU CNG SUT BA PHA .............................................. 28

BI 4: TH NGHIM B BIN I IN P XOAY CHIU MT PHA .............................. 35

BI 5: TH NGHIM B BIN I NGUN DC - DC CNG SUT .................................... 44

BI 6: TH NGHIM B BIN TN KIU IU RNG XUNG .......................................... 53

BI 7: TH NGHIM B BIN TN THEO PHNG PHP BIN I IN TH .............. 65

2 BI 1: TH NGHIM MCH KCH THYRISTOR V TRIAC

BI 1: TH NGHIM MCH KCH

THYRISTOR V TRIAC

1.1 CU HI CHUN B BI:

1. Nhng iu kin Diode, Thyristor v Triac dn. Phng php ng Thyristor thng dng trong iu khin?

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2. im ging nhau v khc nhau v hot ng gia Thyristor v Triac?

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3. i vi mch iu khin Thyristor v Triac thng c nhng yu cu g?

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4. Sng ng b c ngha nh th no i vi vic kch ng Thyristor? C th chn nhng dng sng ng b no?

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BO CO TH NGHIM IN T CNG SUT 3 ..................................................................................................................

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5. Nhim v ca bin p ng vo TF5?

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1.2 KT QU TH NGHIM MCH KCH THYRISTOR V TRIAC IU KHIN NG B:

I. KHO ST HOT NG CA DIODE CNG SUT:

1. Kho st vi ngun in DC:

Trng thi ID VD Ghi ch

Phn cc ngc

Phn cc thun

2. Kho st vi ngun in AC:

a. Trng hp ti thun tr R:


CH1-X V/Div Time Base ms/Div

b. Trng hp ti cm L:


Nhn xt: .....................................................................................................

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II. IU KHIN SCR:

Ngun in p xoay chiu: U = [V], tn s f = [Hz]

Ngun in p mt chiu: U = [V]

Dao ng k: Tn s: Chnh = /2

1. Dng sng tn hiu sine iu khin ng b cung cp:


2. Tn hiu ti TP1:


6 BI 1: TH NGHIM MCH KCH THYRISTOR V TRIAC 3. Tn hiu ti TP2:


4. Tn hiu ti TP3:



5. Tn hiu ti TP4:


6. Tn hiu ti TP5:


8 BI 1: TH NGHIM MCH KCH THYRISTOR V TRIAC 7. Tn hiu trn ti R:


8. Gii thch s khc nhau tn hiu trn ti khi thay i ng ra OUT3 (PEC-502) cho OUT1.

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9. Gii thch s khc nhau tn hiu ra trn ti khi khi o ngc dy cp ngun 24V cho ng vo s iu khin ng b PEC-502.

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10. Tn hiu trn ti L:


11. Vn bin tr P3 trn PEC-502/1 thay i gc m =/5, v li dng sng trn ti tr v ti cm.

a. Tn hiu trn ti R:



b. Tn hiu trn ti L


III. IU KHIN NG B TRIAC:



Dao ng k: Tn s: Chnh = /2

1. Tn hiu trn ti R:



2. Tn hiu trn ti L:


3. Gii thch s khc nhau tn hiu ra trn ti khi thay ng ra OUT3 (PEC-502) cho OUT1.

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4. Gii thch s khc nhau tn hiu ra trn ti khi o ngc dy cp ngun 24V cho ng vo s iu khin ng b PEC-502.

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5. Vn bin tr P3 trn PEC-502/1 thay i gc iu khin =/5, v li dng sng trn ti tr v ti cm.


a. Tn hiu trn ti R:


b. Tn hiu trn ti L:


6. Gii thch s khc nhau v dng sng gia trng hp ti tr v ti cm cho mch kch SCR v Triac.

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BO CO TH NGHIM IN T CNG SUT 13 ................................................................................................................

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14 BI 2: TH NGHIM B CHNH LU CU CNG SUT MT PHA

BI 2: TH NGHIM B CHNH LU

CU CNG SUT MT PHA


1. Chc nng v ng dng ca b cu chnh lu cng sut 1 pha?

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2. Cc loi cu hnh chnh lu 1 pha v linh kin s dng tng ng?

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3. V dng sng in p v dng in chnh lu ca cc b chnh lu cu 1 pha?

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4. Dng in qua thun tr R ca b chnh lu cu 1 pha trong cc trng hp sau:

- B chnh lu cu iu khin bn phn c tnh: lin tc

gin on

- B chnh lu cu iu khin ton phn c tnh: lin tc

gin on

5. Tnh lin tc hoc gin on ca dng qua ti RL ca b chnh lu cu 1 pha ph thuc vo nhng yu t no?

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6. Phm vi thay i l thuyt cu gc iu khin (gc m) ?

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7. Trong bi th nghim, dao ng k dng o dng sng no?

a. Sng in p. b. Sng dng in. c. Sng p v dng.

8. theo di c dng sng dng in qua linh kin, qua ngun xoay chiu, trong bi thc hnh s dng bin php no?

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2.2 KT QU TH NGHIM B CHNH LU CU CNG SUT MT PHA:

IV. PHN 1: IU KHIN BN PHN

a. Ti tr R:

1. Dng sng ngun xoay chiu cung cp cho cu chnh lu:



Dao ng k: Tn s:



2. Tn hiu UDC trn ti R ng vi gc m = /2:



3. Dng sng trn R01 (Dng dng in ngun):


4. Dng sng trn SCR1 (in p trn SCR1):



5. Dng sng trn R02 (Dng dng in qua SCR2):


6. Bng kt qu gi tr o UDC() v tnh ton theo cng thc l thuyt UDC*():

[rad] 0 /5 2/5 3/5 4/5

UDC()

UDC*()

7. c tuyn UDC theo gc m :

UDC (V)

(rad)


b. Ti tr RL:

1. Dng sng in p UDC trn ti RL ng vi gc m = /2:





3. Dng sng trn SCR1 (Dng in p trn SCR1):






[rad] 0 /5 2/5 3/5 4/5

UDC()

UDC*()


V. PHN 2: IU KHIN TON PHN

a. Ti tr R:

1. Dng sng in p UDC trn ti R ng vi gc m = /2:


UDC (V)

(rad)


2. Dng sng trn R01 (Dng in ngun):


3. Dng sng trn SCR1 (Dng in p trn SCR1)






[rad] 0 /5 2/5 3/5 4/5

UDC()

UDC*()



b. Ti RL:

1. Dng sng in p UDC trn ti R ng vi gc m = /2:


UDC (V)

(rad)




3. Dng sng trn SCR1 (Dng in p trn SCR1):






[rad] 0 /5 2/5 3/5 4/5

UDC()

UDC*()


UDC (V)

(rad)


VI. NHN XT:

1. Hy gii thch s khc nhau tn hiu ra trn ti trong trng hp ti R v RL:

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2. Hy so snh v gii thch s khc nhau tn hiu ra trn ti vi hai dng iu khin BN PHN v TON PHN trong trng hp RL:

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28 BI 3: TH NGHIM B CHNH LU CU CNG SUT BA PHA

BI 3: TH NGHIM B CHNH LU

CU CNG SUT BA PHA


1. Chc nng v ng dng ca b chnh lu 3 pha?

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2. Cc loi cu hnh chnh lu 3 pha v linh kin s dng tng ng?

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3. Cng thc tnh trung bnh in p v dng in trong b chnh lu cu 3 pha? Gi s bin p ngun xoay chiu l 220 [V], R = 5, gc m = /6.

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4. Cc xung iu khin ln lt a n cc iu khin ca cc Thyristor theo th t 1, 2, 3, 4, 5, 6, 1 lch nhau mt gc:

a. /4 b. /3 c. /6 d. Ty tng loi Thyristor


5. V gin sng in p v tn hiu iu khin chnh lu cu 3 pha (6 Thyristor)?

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3.2 KT QU TH NGHIM B CHNH LU CU CNG SUT BA PHA:

1. Dng sng ngun xoay chiu (3 pha) cp cho cu chnh lu:



Dao ng k: Tn s:

Ch :

a. Dng cng lc hai que o ca dao ng k quan st tn hiu.

b. Dng sng v trn cc th phi c chn cng mt gc thi gian.



2. Tn hiu iu khin SCR1:





8. Dng sng trn ti R ng vi gc m = /3:


9. Dng sng trn ti R ng vi gc m = /3:



10. Gii thch s khc nhau tn hiu ra trn ti R v ti L:

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BI 4: TH NGHIM BIN I IN

P XOAY CHIU MT PHA


1. Chc nng v ng dng ca b bin i in p xoay chiu?

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2. Cc loi cu hnh b bin i in p xoay chiu 1 pha v linh kin s dng tng ng?

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3. Cng thc tnh tr hiu dng in p ti ca b bin i p xoay chiu 1 pha?

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4. H s cng sut ph thuc nh th no vo gc kch, trong t/hp ti R v RL?

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5. Phng php iu khin pha (Phase Control) p dng cho b bin i in p xoay chiu c biu din nh th no?

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7. Cc thnh phn sng hay xut hin trong b bin i in p xoay chiu?

36 BI 4: TH NGHIM BIN I IN P XOAY CHIU MT PHA

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8. Tnh lin tc ca dng ti b bin i in p xoay chiu ph thuc yu t no?

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9. Gc iu khin ti hn l g? Cng thc tnh?

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4.2 KT QU TH NGHIM B BIN I IN P XOAY CHIU MT PHA:

I. TI THUN TR R:

1. Dng sng ngun xoay chiu cp cho cu chnh lu:



Dao ng k: Tn s:

BO CO TH NGHIM IN T CNG SUT 37 CH1-X V/Div Time Base ms/Div

2. Tn hiu UZ trn ti R ng vi gc m = /2:


3. Dng sng IZ trn R (Dng dng in ti):



4. Bng kt qu gi tr o UZ() v tnh ton theo cng thc l thuyt UZ*():

[rad] 0 /5 2/5 3/5 4/5

UZ[V] (VOM)

UZ*()

5. c tuyn UZ() theo bng kt qu:

UZ*() [v]

(rad)

UZ() [V]


II. TI C TNH CM RL:

1. Dng sng in p UZ trn ti RL ng vi gc m = /2:


2. Dng sng IZ trn R (Dng dng in ti):


3. Bng kt qu gi tr o khi chnh P3 (gc m ) trn PEC-502:


(rad)

(Chnh dng sng

trn ti)

0 /5 2/5 3/5 4/5

(rad)

(c trn

dao ng k)

(rad)

(c trn

dao ng k)

UZ[V] (VOM)

(o bng VOM)

UZ*()

(Tnh bng

cng thc)

Cc gi tr UZ*() v tnh theo cng thc l thuyt.


4. c tuyn UZ() theo bng kt qu.

5. Kt qu o gc iu khin ti hn:

Bng 4.2

Gc ti hn th [rad]

*th (Cng thc)

Tr hiu dng

UZ [V] (VOM)

UZ* [V]

Cc gi tr *th tnh theo cng thc l thuyt v = 314 [rad/s]

R = . . . . . . . [], L = . . . . . [H]

UZ* [V] bng tr hiu dng p ti l tng (sau khi tr st p trn linh kin), c th

gi thit bng p ngun xoay chiu.

6. Dng sng p UZ khi gc m bng gc ti hn:


UZ*() [v]

(rad)

UZ() [V]


7. Dng sng dng IZ khi gc kch bng gc ti hn:


Nhn xt, nh gi kt qu th nghim:

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44 BI 5: TH NGHIM B BIN I NGUN DC - DC CNG SUT

BI 5: TH NGHIM B BIN I

NGUN DC - DC CNG SUT


1. Chc nng v ng dng ca b bin i ngun DC - DC cng sut?

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2. Cc loi cu hnh b bin i ngun DC - DC v linh kin s dng tng ng?

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3. Nhim v cun dy L1 v t in C2 trong mch th nghim?

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4. Khi ta thay i tn s my pht (thay i T(t1+t2)) in p ra Uo s thay i nh th no?

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5. H s cng sut ph thuc vo yu t no? C khc bit g trong trng hp ta

thay i gia hai loi ti R v RL?

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5.2 KT QU TH NGHIM B BIN I NGUN DC - DC CNG SUT: (SWITCHING DC TO DC CONVERTER)

III. KHO ST TN HIU TI BOARD IU KHIN:



Dao ng k: Tn s:

46 BI 5: TH NGHIM B BIN I NGUN DC - DC CNG SUT 1. Tn hiu xung ti TP1:


2. Tn hiu xung ti TP2:





4. Tn hiu xung ti G - S:



IV. IU KHIN NGUN DC DC VI XUNG VUNG GC RNG KHNG I:

1. Dng tn hiu G-S ca transistor T1 (PE-515):


2. Dng tn hiu S - U0:



Tn s 15kHz 20kHz 25kHz 30kHz

U0 (vung gc)

Quan st mp m th ra trn ti

= R1


= R1+R2


= R1+R2+R3

V. IU KHIN NGUN DC DC VI XUNG VUNG GC RNG THAY I:

1. Dng tn hiu G - S ca transistor T1 (PE-515):





rng xung W= % [T] 20% 50% 75% 90%

in p ra trn ti Uout [VDC]


= R1


= R1+R2


= R1+R2+R3

Nhn xt gi tr in p ra khi thay i rng xung:

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VI. IU KHIN NGUN DC DC VI XUNG VUNG GC RNG T THAY I NH H THNG HI TIP:

1. Dng tn hiu G - S ca transistor T1 (PE-515):




52 BI 5: TH NGHIM B BIN I NGUN DC - DC CNG SUT 3. Nhn xt gi tr in p ra khi thay i ti:

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4. Gii thch hot ng ca mch:

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BI 6: TH NGHIM B BIN TN

KIU IU RNG XUNG


1. K tn cc loi bin tn. Phn bit bin tn trc tip, bin tn gin tip?

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2. Th no l nghch lu dng v nghch lu p?

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3. Nu cc phng php iu khin b nghch lu?

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4. Trnh by s khi b bin tn iu khin theo phng php U/f = const?

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54 BI 6: TH NGHIM B BIN TN KIU IU RNG XUNG

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5. B pht sng sine chun c tc dng nh th no?

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6. Tc dng ca xung tam gic trong vic iu khin b bin tn theo phng php U/f = const?

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6.2 KT QU TH NGHIM B BIN TN KIU IU RNG XUNG: (PULSE WIDTH MODULATED INTERVER)

Ngun in p xoay chiu: U = [V], tn s: f = [Hz]


Dao ng k: Tn s:

I. Tn s sng SINE chun cc i Fmax (sine A) = (Hz).

II. Gin sng sine A, B, C v xung tam gic trn cng mt khung

th:


Ch :

a. Dng cng lc hai que o ca dao ng k quan st s lch pha nhau

gia cc tn hiu.

b. Dng sng v trn cc th phi c chn cng mt gc thi gian.




56 BI 6: TH NGHIM B BIN TN KIU IU RNG XUNG 2. Tn hiu xung ti TP2:




4. Tn hiu xung ti T1 T6:



5. Nhn xt v s ph thuc ca tn hiu ra ca b so snh (Comp 1-3) theo tn s v bin tn hiu sine chun:

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III. Gin sng ra trn ti 3 pha_ IN P PHA TRN TI THUN TR (o ring tng pha so vi trung tnh ti) trn cng mt khung th:

1. Dng sng in p pha trn ti R ti pha U:


2. Dng sng in p pha trn ti R ti pha V:



3. Dng sng in p pha trn ti R ti pha W:


IV. Gin sng ra trn ti 3 pha_IN P DY TRN TI THUN TR (o tng i mt hai pha so vi nhau) trn cng mt khung th:

1. Dng sng in p dy trn ti R ti U/V (PE 516)



2. Dng sng in p dy trn ti R ti V/W (PE 516)


3. Dng sng in p dy trn ti R ti W/U (PE 516)



V. Gin sng ra trn ti 3 pha_ IN P PHA TRN TI IN CM

(ch o DUY NHT trn mt pha U so vi trung tnh ti) ri i chiu vi dng sng ca mc [III.1]:

1. Dng sng in p pha trn ti L ti pha U:



2. Nhn xt v s khc nhau gia tn hiu in p pha trong trng hp ti tr v ti cm:

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VI. Gin sng ra trn ti 3 pha_IN P DY TRN TI IN CM (o tng i mt hai pha so vi nhau) ch o DUY NHT trn mt cp pha U-V ri i chiu vi dng sng ca mc [IV.1]:

1. Dng sng in p pha trn ti L ti pha U:


2. Nhn xt v s khc nhau gia tn hiu in p dy trong trng hp ti tr v ti cm:

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VII. Ni cc li ra U, V, W vi 3 ti tr R1 R2 R3. Gi Uo = 24V. Thay i bin tr SET VALUE. Xc nh mi quan h gia tn s sng sine chun vi dng trn ti:

F(sine A)

I(A)

VIII. Nhn xt, nh gi kt qu o:

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BI 7: TH NGHIM B BIN TN

THEO PHNG PHP BIN I IN

TH


1. Nu s khc bit gia phng php iu khin six - step v phng php iu rng xung.

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2. Trnh by s khi b bin tn theo phng php iu khin six - step

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3. Nu u v khuyt im b bin tn kiu six - step so vi b bin tn kiu iu rng xung

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66 BI 7: TH NGHIM B BIN TN THEO PHNG PHP BIN I IN TH 4. Nu u v khuyt im b bin tn kiu six - step khi xung kch 1200 so vi b

bin tn kiu six - step khi xung kch 1800.

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5. Trnh by u v khuyt im b nghch lu s dng Transistor hay Mosfet so vi b nghch lu s dng Thysistor.

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7.2 KT QU TH NGHIM B BIN TN KIU BIN I IN TH: (SIX STEP INTERVER)

I. Kho st hot ng ca b bin i in th DC DC:

1. Mi lin quan gia in th ra Uo vi rng xung T iu khin C1 Bng 1

U0 5V 7.5V 10V 15V 20V 25V

T(C1)

2. Mi lin quan gia dng ti vi rng xung T iu khin C1 (U0 = 20V)


Bng 2

I(R) R1 R1//R2 R1 // R2 // R3

T(C1)

3. Mi lin quan gia in th ra U0 vi xung li ra DIGITAL OUTPUT Bng 3

U0 5V 7.5V 10V 15V 20V 25V

T(Dig.Out)

II. Kho st b pht tn hiu 6 bc:

A. CNG TC V TR MODE V TR 1200:

1. Dng tn hiu D1 v T1 (PEC 504B)


68 BI 7: TH NGHIM B BIN TN THEO PHNG PHP BIN I IN TH 2. Dng tn hiu D2 v T2 (PEC 504B)




70 BI 7: TH NGHIM B BIN TN THEO PHNG PHP BIN I IN TH

7. Dng tn hiu in p pha U - Trung tnh ti (PE 516)

Ti tr R CH1-X V/Div Time Base ms/Div

8. Dng tn hiu in p pha V - Trung tnh ti (PE 516)



9. Dng tn hiu in p pha W - Trung tnh ti (PE 516)


10. Dng tn hiu in p dy U - V (PE 516)



11. Dng tn hiu in p dy V - W (PE 516)


12. Dng tn hiu in p dy W - U (PE 516)




Ti cm (motor) CH1-X V/Div Time Base ms/Div




17. Dng tn hiu in p dy V W (PE 516)


18. Dng tn hiu in p dy W U (PE 516)



B. CNG TC V TR MODE V TR 1800:






11. Dng tn hiu in p dy V - W (PE 516)


12. Dng tn hiu in p dy W - U (PE 516)



17. Dng tn hiu in p dy V W (PE 516)


18. Dng tn hiu in p dy W U (PE 516)



19. Mi quan h gia in p ra U0 v dng ti:

U0 5V 7.5V 10V 15V 20V 25V

I(A)

20. So snh s khc bit ca tn hiu in p pha v in p dy cc bc trn (vi ti thun tr):

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86 BI 7: TH NGHIM B BIN TN THEO PHNG PHP BIN I IN TH 21. Vn bin tr SET trn PEC 504A thay i in p DC cp cho b cng sut

MOSFET, quan st tn hiu ng vi s thay i ca in p pha v in p dy. Nhn xt.

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22. Nhn xt v nh gi kt qu th nghim

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BÁO CÁO THÍ NGHIỆM ĐIỆN TỬ CÔNG SUẤT cao... · BÁO CÁO THÍ NGHIỆM ĐIỆN TỬ CÔNG ... pha và linh kiện sử dụng tương ... điều khiển của các Thyristor