Bai Tap Lon Co Ket Cau

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1 Trng i hc Xy Dng BI TP LN C HC KT CU 2 Sinh vin thc hin : Nguyn c Phc Lp: 53CD4 Khoa:Xy Dng Cu ng H ni, ngy 20 thng 9 nm 2010 Bi 1: TNH H SIU TNH THEO PHNG PHP LC 2 1.Xc nh s n s, lp h c bn2.thit lp h phng trnh chnh tc, xc nh cc h s v cc s hng t do bng cch nhn biu . 3.v cc biu mmen un lc ct v lc dc. 4.kim tra biu mmen un (Mp) bng cch nhn biu . ( )( )0k pM M = v ( )( )0s pM M =5.xc nh chuyn v ng ti tit din A. Bi lm: 1.Xc nh s n s, chn h c bn. ta c:3V K =3.2 4 = 2 h c 2 bc siu tnh. Chn h c bn nh hinh 1.12.Thit lp phng trnh chnh tc, xc nh cc h s v s hng t do bng cch nhn biu . Gii h phng trnh chnh tc. 5m6m 4m 5m3mEA=82EI 2EI4EI4EI4EI30KN/m30KN/m180KN200KNm5m6m 4m 5m3mEA=82EI 2EI4EI4EI30KN/m30KN/m180KN200KNmX1X1X2X23 5m6m 4m 5m3mEA=82EI 2EIX1X1=1=1=1X2X2=1=15m6m 4m 5m3mEA=82EI5m6m 4m 5m3mEA=82.1. thit lp phng trnh chnh tcphng trnh chnh tc dng ch: 11 1 12 2 121 1 22 2 200PPX XX X + + A =+ + A = v biu mmen ( ) ( ) ( )01 2; ;PM M M

( ) 2M (M0P) (M0P)

Xc nh cc h s trong phng trnh chnh tc: ( )( ) 11 1 11 1 2 1 1 2 1 1 2 1 1 2 1703. 8.6 . .8 5.5 .5 3.5 . .3 8.8 .8 4 2 3 2 2 3 4 2 3 2 2 3 12M MEI EI EI EI EI| | | | | | | |= = + + + = ||||\ . \ . \ . \ . ( )( )( )22 2 21 1 2 1 1 2 1 1 2 1 15014.6 3 4.5 4 5.5 5 5.8 .54 2 3 4 2 3 4 2 3 2 12M MEI EI EI EI EI| | | | | |= = + + + = |||\ . \ . \ . 4 ( )( ) 12 21 1 21 1 2 1 1 2 1 1 595.8 4 3.5 4 8.8 54 2 3 4 2 3 2 2M MEI EI EI EI | | | | | |= = = + = |||\ . \ . \ . ( )( )1 11 1 2 1 1 2 1 1 25.8 1400 5.5 900 300.5 34 2 3 2 2 3 4 2 31 2 1 1 1 2 2 78055.75 3 960.8 8 240.8 44 3 2 2 2 3 3 4P PM MEI EI EIEI EI EI| || | | || | | || |A = = + + + | || || |\ .\ . \ .\ . \ .\ . | | | | | |+ = |||\ . \ . \ . ( )( ) ( )( )( )02 21 1 2 1 1 2 24.6 1400 300.5 4 75.5 24 2 3 4 2 4 31 9575+ 5.8 2402P PM MEI EIEI EI | || | | || | | |A = = + | || ||\ .\ . \ .\ . \ . = Phng trnh chnh tc: 1 21 21703 185 7805= 012 3 4185 15017975=03 12X XEIX X + 1252.75589.766XX== Biu (Mp), (Qp), (Np): ( Mp) 5m6m 4m 5m3mEA=8533,324616,55516,445897,075283,2265 ( Qp) ( Np) Biu ( ) ( ) ( )1 2 SM M M = + c dng nh hnh v: 5m6m 4m 5m3mEA=888,887123,313,3548116,645103,2956,69296,695m6m 4m 5m3mEA=8180135,59103,28956,69013,37816,6216

( Np) 4.Kim tra biu ( )( )11 1 2 1 1 2533,324.6 8 283, 226.5 34 2 3 4 2 31 2 1 1 2 1 1+ 75.5 1,5 616,55.5 5 1413,52.84 3 2 2 3 2 21 1 2 1* 8 240.8 4 897, 0753 2 3 2PM MEI EIEI EI EIEI EI | | | |= + ||\ . \ .| | | | | | |||\ . \ . \ .| | + |\ .( ) .8 4 0, 0451 = ( )( )( )21 1 2 1 1 2533,324.6 4 283, 226.5 44 2 3 4 2 31 2 1 1 1 275.5 4 516, 445.5 54 3 2 2 2 31 2 1 1240.8 5 897, 075 516, 445 8 52 3 2 2 PM MEI EIEI EIEI EI | | | |= + ||\ . \ .| | | |+ + ||\ . \ .| |+ + + | \ .( )1897, 075.8 5 0, 0222EI = 1275355m6m 4m 5m3mEA=87 5m6m 4m 5m3mEA=8P=1( )( )1 1 2 1 1 2533, 324.6 12 283, 226.5 74 2 3 4 2 31 2 1 1 1 2+ 75.5 7 616,55.5 54 3 2 2 2 31 1 2 1 1 1 516, 455.5 5 1413,52.8 74 2 3 2 2 3

S PM MEI EIEI EIEI EI | | | |= + ||\ . \ .| | | | ||\ . \ .| | | |+ + ||\ . \ .( )1 2 1 240.8 1 897, 075.8 1 0, 00192 3 2 EI EI| |+ = |\ . 5.Xc nh chuyn v ng ti A To trngthikhdKtrnhcbnbtk.t lc Pk =1 theo phng chuyn v cn tm

( )KM( )( )( )1 1 2 1 1516, 445.5 5 1413,52.8 54 2 3 2 21 2 1 469, 63240.8 5 897, 075.8 52 3 2A K Py M MEI EIEI EI EI| | | |= = + ||\ . \ .| |+ = |\ . BI 2: Tnh h siu tnh theo phng php chuyn v 1.Xc nh s n, lp h c bn. s chuyn v xoay cha bit l 1 ( ti nt ) s chuyn v thng cha bit l 1 ( ti khp A ) 8 H c bn chn nh hnh v 2. Thit lp h phng trnh chnh tc. xc nh h s v s hng t do. Gii h phng trnh chnh tc . h phng trnh chnh tc dng ch : 11 1 12 2 121 1 22 2 200pprZ rZ Rr Z r Z R+ + = + + = v biu ( ) ( ) ( )01 2; ;PM M M Z1=14EI 4EI2EI2EI2EI2EI5m 3m 3m2,5m2,5m125EIEI83EI 56EI 2 ( ) 1M30 KN/m180KN200 KN.m200 KN.m4EI 4EI2EI2EI2EI2EI5m 3m 3m2,5m2,5m3m9 4EI 4EI2EI2EI2EI2EI5m 3m 3m2,5m2,5m22,5202,520025270 33,75 ( ) 2M ( )PM ai lng Biu B phn tchKt qu r11 1M12EI/56EI/52EI8EI/3r11 12415EI r12=r21 2M r6EI/254EI/3 12 8275EI 4EI 4EI2EI2EI2EI2EI5m 3m 3m2,5m2,5m6EI/256EI/256EI/254EI/34EI/3Z=1210 r22 2M397 EI/9 6 EI/ 125 6 EI/ 125 6E I/12 5 rFFF397EI/96EI/1256EI/1256EI/125r22 11621125EI R1P MP0 4545R2P 425KNm R2P MP0 22,5200R1P 22,5 290PR = H phng trnh chnh tc 1 21 21 2124 . 82425 015 7582 116290 075 112546, 38 38, 0389

EI EIZ ZEI EIZ ZZ ZEI EI+ =+ = = = Biu mmen ( Mp); ( Np) ; ( Qp) 20015,8746,5269,13111,31227033,75109,74 11 140,65108,2971,711,8269,305243,17422,262450,65 43,1741,82671,71130,55 22,2624 Mi thc mc v bi tp ln C Hc Kt Cu xin gi v a [email protected] (Lp 53CD4-Khoa Xy Dng Cu ng -i hc Xy Dng) 12