4
G aa\ l''- / AIN SHAMS UNIVERSITY FACULTY OF ENGINEERTNG NEW PROGRAMS Tgrsi tr 500 \ 400 tsEa a fr- +U co a d a u7 o) JU (n -n^ 15 JUU {:* a $ U] a) {J\ e\ h) q "t) e) q = 15o A?^' ]"-'r,o , . A/ 4 So tlPq -r E(/hoJut,.Jtios[rE,t.il) = tY = [(:e -ioo'l-,- O .C,otg .o, C0 i ( , I i rts" '"t Z i: u,4iS 0,1 s.t,.,r,t]l_ b lr'u- ,n 3 cr(i' \, ]."'t- 5 -[fL" drt i2 t4, ,5 7 ,eL.t s 0 J,'

Assignment 8 Stress Strain Curve Ahmedawad

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1-The following graph Fig.1 is for a structure steel sample with 12.5 mm diameter and 60 mm lenghth .After fracture the diameter is 11.54 mm.Complete the following table.3-A low carbon steel bar 10 x 20 x 1000 mm is loaded in tension along its axis, with a force 20 kN. Calculate the change in length, width and thickness (E = 210x103 N/mm2, ν = 0.3)4-It is required to design a cable that must support a lift with a mass of 4530 Kg. The cable is made from an aluminum alloy. Calculate the minimum diameter of the cable required to support the lift without permanent deformation. (σy = 240 MPa)5-A 10-mm diameter Brinell hardness carbide indentor produced an indentation 1.62-mm in diameter in a steel alloy when a load of 500 Kg was applied. Compute the BHN of this material and estimate its tensile strength in MPa.

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Page 1: Assignment 8 Stress Strain Curve Ahmedawad

Gaa\

l''-/ AIN SHAMS UNIVERSITY

FACULTY OF ENGINEERTNG

NEW PROGRAMS

Tgrsi tr

500

\

400tsEa

afr-

+U coad

au7o)

JU (n

-n^15 JUU{:*a$U]a)

{J\

e\h)

q

"t)

e)

q = 15o A?^' ]"-'r,o ,

. A/ 4 So tlPq-r

E(/hoJut,.Jtios[rE,t.il) = tY= [(:e -ioo'l-,-

O .C,otg .o, C0 i (, I i rts" '"t

Z i: u,4iS0,1 s.t,.,r,t]l_

b lr'u-,n

3

cr(i'\, ]."'t- 5 -[fL"drt

i2t4,

,57

,eL.t s

0

J,'

Page 2: Assignment 8 Stress Strain Curve Ahmedawad

Stn"as 4ll

,Iq Vlrlurn 1 o.,-.( *htt[

F-A=

5 J,'

Sc^pk h.o cwr i*J:,

$S o A(",,.

(+s. ,((or) [8" * [' 2

55,1,LSw

P.*&<

AP,,,{:,^

r^LYY

, S*,.-1J

?\

ryA=

tr

f,a t.,rr\f, ^l%rq--u, Y 37 t

ry A=-

l.o.(*^d

Nf!Lo

L, 1 6o T "\ ---------:

o.jT = do

-.....-+ LC : 82.Zn,u

fln.:dulus -& ttu*0 r<q g^Jun th. cLtr{re ID

Lc LiLi

3,: (o

r)

k) P "i sS6n's ra-his

u=TI

€ tcrte'*l/>4ffi^

Lr = (o'e":)Lo *

= o),\/ - r/vl ^ v f

x- € ;.^1ftdo^e\r- i tJ

I ulr.. licritc \ r.Lo :.fu1*]l,-*-,L ltt , s

l!V ,:l'^['. 1?,t61,,

L. * Lnb, ,.....- d,031

a(*T*

Page 3: Assignment 8 Stress Strain Curve Ahmedawad

io KZo

F=Eitr:

Xt oos 'n'D\

2o kA/

2 to r (03

o,3N /^,*

\_I

AL6 X(f l6o flPa

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o,3 xo.o{-'lo.Gl2'1,

ft1'rrNW:

\MF :

t hick hess i

looo I to

cr=

e=F

)1ID

r r L tcteo^

etogaur-,t

DL la-ta,-^t =AwwUnif [*_*r =\

(o.otz)X\#/- ---Lq-S,-'

Qo rzo) X.to - b

Ioo= 0,64 '/

z to rt8

IOoo = O. +1 {64? 6l

looo + @= Iooo k76 ( '^^

(r2D n"-

/\

RJ

2o*- 9f5 :too

(J} 15,59?d ,"rn

Y o t.rn" e cs^ st oa (

Izo = looo'+76 x 1$'19?6 {tr,*

Page 4: Assignment 8 Stress Strain Curve Ahmedawad

loJ =

13 l-{ N:

Iom-

= l,6z r"tn

= toc k3

L?

or=A

d^,^ = ?l

q - 24 $d"/{P'

ttO

^@:FAf

, -6(-

=.LJ"t

4SBo xlo : 4 53oo N

t 53o; tE6'?S mnt

2+6

F. eX; I s'5 'a^

1)\ {'

Zx z+s

z

W)=dP

Hlu;

J

p:

D1J\

{D\uapp\id 1".* kq

d'.'o'^<l"r in ;tltto (f)

a(I"t^tkr "&

in'o(<nFo('i o^(^^)

r(r$(to245

wk1 l^*'

-l /V

+s)

rte,

R

(z5

3.4w3 "45

= (Gt,

Z

D ]