X 5 AB 3.45 Y 4 BC 4.7 2.35 Z 3 CD 2.86 11.01 m Ebeton 2100000 Ebaja 20000000 Angka Poison 0.134 P1 2.45 P2 8.35 b 40 0.4 P3 4.54 h 60 0.6 Q1 1.44 I 0.0072 Q2 2.45 M 4.33 a. Elemen 1 (arah orientasi AB) E = 2100000 ton/m^2 I = 0.0072 m^4 L = 3.45 m Day Raz Dby Rbz 4418.51 7621.93 -4418.51 7621.93 Day [k]1 7621.93 17530.43 -7621.93 8765.22 Raz -4418.51 -7621.93 4418.51 -7621.9282 Dby 7621.93 8765.22 -7621.93 17530.4348 Rbz b. Elemen 2 (arah orientasi BC) E = 2100000 ton/m^2 I = 0.0072 m^4 L = 4.7 m Dby Rbz Dcy Rcz 1747.59 4106.84 -1747.59 4106.84 Dby [k]2 4106.84 12868.09 -4106.84 6434.04 Rbz -1747.59 -4106.84 1747.59 -4106.8357 Dcy 4106.84 6434.04 -4106.84 12868.0851 Rcz c. Elemen 3 (arah orientasi CD) E = 2100000 ton/m^2 I = 0.0072 m^4 L = 2.86 m Dcy Rcz Ddy Rdz 7755.95 11091.01 -7755.95 11091.01 Dcy [k]3 11091.01 21146.85 -11091.01 10573.43 Rcz -7755.95 -11091.01 7755.95 -11091.007 Ddy 11091.01 10573.43 -11091.01 21146.8531 Rdz Langkah 3: Perakitan Matriks Kekakuan Struktur Tereduksi Kontribusi dari elemen 1 Raz Rbz [k]1 17530.43 8765.22 Raz 8765.22 17530.4348 Rbz Kontribusi dari elemen 2 Rbz Rcz [k]2 12868.09 6434.04 Rbz 6434.04 12868.09 Rcz Kontribusi dari elemen 2 3 Rcz Rdz [k]3 21146.85 0.00 Rcz 0.00 0.00 Rdz HASIL PERAKITAN MATRIKS [k] STRUKTUR-TEREDUKSI Raz Rbz Rcz [K] 17530.43 8765.22 0 Raz 8765.22 30398.52 6434.04 Rbz 0 6434.04 34014.94 Rcz Langkah 4: Menyusun Vektor Gaya-Luar q1= 1.44 AB 3.45 Q2= 2.45 P1= 2.45 BC= -2.484 Day -6.9825 Dby {fo}1 = -1.4283 Raz {fo}2 = -5.9494167 Rbz -2.484 Dby -6.9825 Dcy 1.4283 Rbz 5.94941667 Rcz b. Perakitan vektor "span loading" struktur tereduksi: -1.4283 Raz -2.484 Day a. Vektor "span loading" masing-masing elemen: (ingat rumus balok jepit-jepit)