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7/26/2019 TUGAS LENDUTAN BETON PRATEGANG
1/33
TUGAS BETON PRATEGANGNAMA : ACHMAD SUKUR
KELAS : 3MRK 1
NIM : 1341320014
ql = 1700
A
A
22 m
35
20
5!135
55
15
525
53!"7
25
35
POTONGAN A#A
NO
PENAMPANG
DIMENSI $%m& LUAS '% $'%! A(&
PENAMPANG )( *( $%m&
1 S+,( Em-./ 20 35 700 100!00 70000!00
$%m&
2
3
1
4 5
6 7
7/26/2019 TUGAS LENDUTAN BETON PRATEGANG
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S+,( T(,. 5 10 25!00 2!7 !7
7 S+,( T(,. 5 10 25!00 2!7 !7
UMLAH 250 142750
A) DATA PERENCANAAN :
T(/( B+./ $'*& = 53!"72453 %m
Mm+ I+6(. = 350""7!11
P.., B+/., $L& = 22 m
= 2200 %m
G!P+66/+66+8 $P& = 0 /
0000 ,
E6+/(6(/.6 $ + & = 25 %m
B+*. H(89- $ql& = 1700 ,m;
= 17 ,%m;
= 2400
= 0!0024 ,%m
B+*. M./( $q8& =
= !3 ,%m;
M9/9 B+/ = 40 M-.
400
K+)(l.,. P./+,., 15.l
= #72!712544
= 32!133001
2& K8(6( A)(
= #270!1242
= 221!47012
E) Kontrol Tengangan
S../ : T+,.,. '., /+.8( ? M9/9 B+/
270!1242 ? 400
F) Jarak ert!kal t!t!k e "an T!t!k P
,%m
,%m
,%m
,%m
,%m
,%m
,%m
,%m
,%m
,%m ,%m
_ ) 3 )=(85% . . .( (_ )" /
_ ) 3 )=(85% .( (_. . ) " /
_ ) 4 )=(( (_ _( .) )_ /
_ ) 4 )= _( . )( (_ ( )_ /
_ ) 1 2 3( #_ $_ $_
_ ) 1 2 3( #_ $_ $_
_ ) 1 2 3 4( #_ $_ $_ $_
_ ) 1 2 3+ 4( #_ $_ $_ _
_ )=(
=tan /2
7/26/2019 TUGAS LENDUTAN BETON PRATEGANG
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F) Ga#$ar Tegangan
#73!"7 #1!20 20
5!13
53!"7
70!" #1!20
#73!"7 #1!20 20
( - )
( + )
+
7/26/2019 TUGAS LENDUTAN BETON PRATEGANG
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53!"7
70!" #1!20
( + )
7/26/2019 TUGAS LENDUTAN BETON PRATEGANG
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,m;
110
8(
$%m&
23333!33 4!13 1513051!20
IO I//.l
$IO A( !8(&( 4)
( 4
)
7/26/2019 TUGAS LENDUTAN BETON PRATEGANG
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34!72 #27!20 1"532!43
34!72 #27!20 1"532!43
350""7!11
7/26/2019 TUGAS LENDUTAN BETON PRATEGANG
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%OK)
=
7/26/2019 TUGAS LENDUTAN BETON PRATEGANG
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#72!72
#1!53 32!1
#17!45 #270!1242
( -
)
( + )
( - )
+ =
( -
)
( + )
( + ) ( ( )
7/26/2019 TUGAS LENDUTAN BETON PRATEGANG
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#1!53 1"!4" 221!47012
( - )
( + )
( +
)
7/26/2019 TUGAS LENDUTAN BETON PRATEGANG
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TUGAS BETON PRATEGANGNAMA : ACHMAD SUKUR
KELAS : 3MRK 1
NIM : 1341320014
ql = 1"50
A
A
25 m
30
27
1!"10
45
15
1550
3!11
2"
2"
POTONGAN A#A
NOPENAMPANG
DIMENSI $%m& LUAS '% $'%! A(&
PENAMPANG )( *( $%m&
1 S+,( Em-./ 27 30 "10 111!50 0315!00
$%m&
2
3
1
4 5
6 7
( 4)
7/26/2019 TUGAS LENDUTAN BETON PRATEGANG
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S+,( T(,. 15 !5 4"!75 33!00 10"!75
7 S+,( T(,. 15 !5 4"!75 33!00 10"!75
UMLAH 2"17 17775"
A) DATA PERENCANAAN :
T(/( B+./ $'*& = 3!1132114 %m
Mm+ I+6(. = 44"1442!5
P.., B+/., $L& = 25 m
= 2500 %m
G!P+66/+66+8 $P& = 20 /
20000 ,
E6+/(6(/.6 $ + & = 30 %m
B+*. H(89- $ql& = 1"50 ,m;
= 1"!5 ,%m;
= 2400
= 0!0024 ,%m
B+*. M./( $q8& =
= !75 ,%m;
M9/9 B+/ = 3 M-.
30
K+)(l.,. P./+,., 12!500
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