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Lecture 32 Energy and momentum. Standing waves.

Lecture 32 energy and momentum. standing waves

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Page 1: Lecture 32   energy and momentum. standing waves

Lecture 32Energy and momentum.

Standing waves.

Page 2: Lecture 32   energy and momentum. standing waves

Energy in a EM wave

Energy density due to an electric field: 20

12

u Eε=

Energy density for an EM wave: 2 20

0

1 12 2

u E Bεµ

= +

but0 0

BE cBε µ

= =

2 20 0 0

0

1 12 2

u E Eε ε µµ

= +

20u Eε=

Energy density equallysplit between E, B fields

Energy density due to a magnetic field: 2

0

12

u Bµ

=

Page 3: Lecture 32   energy and momentum. standing waves

Energy transport

How much energy goes through a surface of area A in time dt ?

Energy in this “box”:

y

x

z

propagation

cdt

20dU udV E Acdtε= =

Energy flow per unit time and per unit area: 20

1 dUS cEA dt

ε= =0

EBµ

=

Definition: Poynting vector0

1S E Bµ

= ×r rr Energy flow per unit

time and per unit area

I S=Intensity:

Page 4: Lecture 32   energy and momentum. standing waves

ACT: Plane harmonic wave

z

x

y

Propagation• P

x

z

y

At the time shown, the magnetic field point P (on the y axis) is:

A. Bmax i

B. Bmax j

C. 0

E/B are the same at all points in each yz plane!

Propagation direction is ,so is in the direction and is in the direction

E BE x

B y

×r r

r

r

Page 5: Lecture 32   energy and momentum. standing waves

Energy in the harmonic wave

( ) ( )2max max

0 0

1 1 ˆˆcosS E B E B kx t j kωµ µ

= × = − ×rr

( )maxˆcosE E kx t jω= −

r

( )maxˆcosB B kx t kω= −

r

( )2max max

0

1 ˆcosE B kx t iωµ

= −

( )2max max max max

0 0

1 1cos2

I S E B kx t E Bωµ µ

= = − =

Direction +x (as expected…)

max max0

12

I S E Bµ

= =

Page 6: Lecture 32   energy and momentum. standing waves

ACT: Emax and distance

An isotropic radio transmitter emits power in all directions. What is the ratio of the amplitudes of the E field at distances of 100 m and 200 m from the source E max(100)/E max(200) ?

A. 1B. 2C. 4

Energy is uniformly distributed in a sphere of radius r (r = distance to source):

2

power powerarea 4

Irπ

= =

max max

02E BI S

µ= =Intensity is

max1Er

µ

max

max

E cB

=

2max

02Ecµ

=

Page 7: Lecture 32   energy and momentum. standing waves

Emission of EM waves

How does an EM wave begin? When a charge is accelerated.

Moving charged infinite sheet

Oscillating dipole

Whenever a charge is accelerated, it loses energy due to radiation.

→ Bad thing when you’re trying to accelerate a particle

→ Good thing when you can use the radiation!

• synchrotron radiation produces X-rays

• detection of black holes

• any emission antenna

Page 8: Lecture 32   energy and momentum. standing waves

Momentum

EM waves carry energy… and momentum. (And mechanical waves, too, btw.)

Basic idea of momentum: p = mv→ Mass m moving with speed v (say to the right)

→ (Kinetic) energy flows (to the right)

21 12 2

KE mv pv= =

A very hand-waiving trick to get momentum without the mass:

KEpv

:

Using the proper mathematical tools (special relativity), one obtains

lightKE pc=

Page 9: Lecture 32   energy and momentum. standing waves

Radiation pressure

If EM waves carry radiation, they can exert a force (and thus a pressure) when they hit a surface:

1pressure pFA A t

∆= =

∆Power

cA=

Ic

=

if radiation is completely absorbedlightKEp

c∆ =

1 KEcA t

=∆

Sc

=0

EBcµ

=

0

2 2If radiation is completely reflected, , so pressurelightKE EBpc cµ

∆ = =

Light pressure, though “light”, has noticeable effects comet’s tail →pushed away from the sun*.

*Note: The dust tail is pushed away by radiation; the ion tail is pushed away by the solar wind!

Page 10: Lecture 32   energy and momentum. standing waves

Standing electromagnetic waves

EM wave propagating between two plates of a perfect conductor:

Conducting wall ⇒ E-field must be zero there

⇒ original wave and reflected waves produce a standing wave with condition E = 0 on both ends:

( ) ( )max maxcos cosyE E kx t E kx tω ω= − − +

( ) ( )max2 sin sinE kx tω= −

E-field nodes:

nodes30, , , ...

2 2Ex λ λλ− =

( )( )

max

max

Original wave: cos

Reflected wave: cosy

y

E E kx tE E kx t

ω

ω

= −

= − + x

y E

λ

Page 11: Lecture 32   energy and momentum. standing waves

And the B field?

( )( )

max

max

Original wave: cos

Reflected wave: cosy

y

E E kx tE E kx t

ω

ω

= −

= − +

( )( )

max

max

cos cos

z

z

B B kx tB B kx t

ω

ω

⇒ = −

⇒ = +

Note: No minus sign for !We need propagation

BE B× =r r

( ) ( )( ) ( )

max max

max

cos cos 2 cos cos

zB B kx t B kx tB kx t

ω ω

ω

= − + +

= −

B-field nodes:

nodes3 5, , ...

4 4 4Bx λ λ λ− =

x

zB

λ

DEMO: Marshmallows and microwave

Page 12: Lecture 32   energy and momentum. standing waves

Doppler effect

Just like for mechanical waves, if the source or the observer of an EM are moving, the received frequency can be different from the emitted frequency.

The equations are different, though, because…

… nothing can go faster than light!

We can’t simply add velocities à la Galilean. We need relativity.

Spaceship moves with speed v Light from star travels at

c +v relative to spaceship???

Spaceship moves with speed v

The equations are different, though, because…

Spaceship moves with speed v

The equations are different, though, because…

Spaceship moves with speed v Light from star travels at

c +v relative to spaceship???

The equations are different, though, because…

Spaceship moves with speed v

Page 13: Lecture 32   energy and momentum. standing waves

No relativity in 222, so let’s forget about the math.

But here’s some examples of Doppler’s effect in EM radiation anyway:

• police speed radars

• weather radars (detect motion of rain droplets)

• in astronomy: red shift/blue shift

Most stars are made of H, so their spectrum must be the same

Spectrum of the sun (optical wavelengths)

Spectrum of object X

Lines are at λ larger than expected (red shift)

Object must be moving away from us

It turns out that all distant galaxies are moving away from us

The universe must be expanding!