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Trong s nghip cng nghip ho, hin i ho ca t nc, ngnh xy dng c bn ng mt vai tr ht sc quan trng. Cng vi s pht trin mnh m ca mi lnh vc khoa hc v cng ngh, ngnh xy dng c bn v ang c nhng bc tin ng k. p ng c cc yu cu ngy cng cao ca x hi, chng ta cn mt ngun nhn lc tr l cc k s xy dng c phm cht v nng lc, tinh thn cng hin tip bc cc th h i trc, xy dng t nc ngy cng vn minh v hin i hn.i vi cc trng i hc t nc ta hin nay, nhu cu nh k tc x cho sinh vin ang c u t pht trin mnh. Nh dng t hp cao tng l mt hng pht trin ph hp v c nhiu tim nng. Vic thit k kt cu v t chc thi cng mt ngi nh cao tng tp trung nhiu kin thc c bn, thit thc vi mt k s xy dng. Chnh v vy ti tt nghip ca em l cng trnh K tc x trng i hc Hng c c xy dng trong thnh ph, l t hp cc phng cho sinh vin, nhm p ng nhu cu nh cho sinh vin hin nay.Ni dung ca n gm 3 phn:- Phn 1: Kin trc cng trnh.- Phn 2: Kt cu cng trnh.- Phn 3: Cng ngh v t chc xy dng.Em xin chn thnh cm n cc thy c trng i hc Xy Dng tn tnh ging dy, truyn t nhng kin thc qu gi ca mnh cho em cng nh cc bn sinh vin khc trong sut nhng nm hc qua. c bit, n tt nghip ny cng khng th hon thnh nu khng c s tn tnh hng dn ca c on Qunh Mai - B mn cng trnh Btng ct thp v thy Nguyn Hng Cng - B mn cng ngh v t chc xy dng. Xin cm n gia nh, bn b h tr v ng vin trong sut thi gian qua em c th hon thnh n ngy hm nay. Thng qua n tt nghip, em mong mun c th h thng ho li ton b kin thc hc cng nh hc hi thm cc l thuyt tnh ton kt cu v cng ngh thi cng ang c ng dng cho cc cng trnh nh cao tng ca nc ta hin nay. Do kh nng v thi gian hn ch, n tt nghip ny khng th trnh khi nhng sai st. Em rt mong nhn c s ch dy v gp ca cc thy c cng nh ca cc bn sinh vin khc c th thit k c cc cng trnh hon thin hn sau ny.H Ni, ngy 1 thng 06 nm 2014. Sinh vin Trng Cng TRNG I HC XY DNG THUYT MINH N TT NGHIP KHOA XDDD&CN

SVTH: TRNG CNG MSSV: 0132018 LP: B18KX

PHN I

KIN TRC

(10%)

GING VIN HNG DN 1 : ON QUNH MAI GING VIN HNG DN 2 : NGUYN HNG CNGSINH VIN THC HIN : TRNG CNG MSSV : 0132018 LP : B18KX

Ni dung thit k:

I. iu chnh thit k c sn theo yu cu ca ngi hn dnII. Tm hiu dy truyn cng nng kin trc, nm vng cc thng s ch yu ca cng trnhIII. Tm hiu chc nng v cch b tr h thng k thut cng trnh (h thng c in)IV. Th hin mt bng , mt ng, mt ctV. Lp thuyt minh thit k kin trc

Cc bn v km theo:

KT 01: Bn v mt ng trc 1-9 v trc A-D KT 02: Bn v mt bng tng hm, tng 1 v tng 2 KT 03: Bn v mt bng tng 3-8 v tng mi KT 04: Bn v mt ct A-A v B-B

I. M T CNG TRNH1.1. Tn cng trnh: K tc x trng i hc Hng c1.2. a im: Nm trong khun vin thnh ph Thanh Ha, tnh Thanh HaTrc nhu cu nh cho sinh vin hin nay, vic xy dng cc khu k tc x cho sinh vin ang tr thnh mt vn cng rt cn thit. N lun i km vi quy hoch xy dng cc trng i hc.1.3. Quy m cng trnh:Cng trnh cao gm 9 tng ni, mt tng mi v mt tng hm dng lm Gara t, xe my. Din tch sn ca mt tng l 684,32m2, tng din tch sn 6843,2m2. H thng ng ni b bng b tng v gch l da m bo bn lu diH thng cy xanh c b tr nhm to mt trng cnh quan thin nhin hi haH thng giao thng; theo phng ng c cu thang b b tr trung tm v hai bn thang b c b tr thang my t tng 1 n tng trn cng. Theo phng ngang l hnh lang vi b ngang 2,8m nn to c s thng thong v thoi mi cho ngi s dng.H thng in nc, chiu sng c cung cp y v lin tc cho cc phng, h thng thng gi, che nng phi m bo tin nghi cht lng cao cho ngi sng & lm vic trong cng trnh.Kt lunNhn chung, cng trnh p ng c tt c nhng yu cu chc nng, thm m ca mt khu k tc x ca mt trng i hc ni ting.

II. GII PHP KIN TRC2.1. Gii php mt bngVi mt bng cng trnh l hnh ch nht cn xng, cng trnh c thit k theo dng cng trnh k tc x. Mt bng c thit k theo nhiu cng nng ca mt k tc x nh: Gara xem, phng c sch, kho sch, phng tin hc, phng sinh vin, phng vn ha vn ngh...+ Tng hm: Din tch xy dng 776m2Bao gm gara xe, phng k thut, trm bm, rnh thu nc, phng bo v. Tt c c bao bc xung quanh bi h thng vch tng hm, m bo tt kh nng chng m v chu lc x ca p lc t cho cng trnh.+ Tng 1v tng 2: Din tch xy dng 776m2 c thit k lm cc phng c sch, snh, cng tin v phng trc, phng bn hng. y l khu tng ginh cho sinh vin trong vic hc hnh, hc tin hc. H tr ti liu v lu tr sch bo. Kho sch c h tr t cc ngun ti tr, t th vin v ca nh trng.+ Tng 3-8: Din tch xy dng 776m2c thit k lm phng v sinh hot cho sinh vin. Gia cc phng hai bn l hnh lang rng 2.8m xuyn sut chiu di ngi nh. Vi 14 phng c din tch bng nhau l 36.9m2. Mi phng u c phng v sinh khp kn v trang b t c. Cc phng u c h thng ca chnh v ca s cung cp nh sang t nhin. Gia khi nh c b tr 1 thang my v 1 thang b bn cnh, ngoi ra cn b tr mt mt cu thang b gc ca ta nh nhm m bo vic i li. + Tng 9: Din tch xy dng 776m2c thit k lm phng vn ha vn ngh, l ni hi hp ni b hay vi ban lnh o nh trng. Ngoi ra cn b tr sn chi thong mt lm ni gii tr cho sinh vin sau cc gi hi hp.+ Tng mi: Tng mi ngoi 2 tum thang ln cn b tr 2 b cha nc. Hai lp gch l nem c tc dng chng nng, cch nhit v h thng ng thot nc c ng knh 110mm b tr cc gc mi. Trn mi cn b tr h ct st thu st nhm chng xt cho ngi nh. Bao quanh mt bng mi c h s n mi bng b tng ct thp dc 30% v rng ra mi bn 1.5m nhm chng t hay m do nc ma v thu nc vo ng thu nc.

+ Mt bng tng hm:

+ Mt bng tng 1:

+ Mt bng tng 2:

+ Mt bng tng in hnh t tng 3 n tng 8:

+ Mt bng tng 9:

+ Mt bng tng mi:

+ Mt ct A-A

+ Mt ct B-B:

2.2. Gii php thit k mt ng, hnh khi khng gian ca cng trnh: Mt ng cng trnh th hin kin trc bn ngoi, l b mt ca ta nh c xy dng. Mt ng cng trnh gp phn to nn qun th kin trc cc ta nh trong khun vin trng ni ring, v quyt nh nhp iu kin trc ton khu vc ni chung. Mc d l khu k tc x nhng c b tr kh khang trang. Mc d vy nhng phn kin trc khng trnh khi n iu do l thit k ca mt khu k tc x ginh cho sinh vin .Tng chiu cao ton nh l 34.2m. Trong chiu cao cc tng nh sau: Tng hm: 3.55m Tng 1: 4.5m Tng 3-9: 3.4m Tng mi: 2.5m

III. GII PHP KT CUVi cc yu cu k thut v gii php kin trc nh vy ta c gii php kt cu nh sau:- H kt cu c s dng cho cng trnh ny l h khung - H thng ct v dm to thnh cc khung cng chu ti trng thng ng trong din chu ti ca n v tham gia chu mt phn ti trng ngang tng ng vi cng chng un ca n.- H li l thang my c b tr chnh gia cng trnh sut dc chiu cao cng trnh chu ti trng ngang.IV. CC GII PHP K THUT KHC Gii php cung cp in:- Dng ngun in c cung cp t thnh ph, cng trnh c trm bin p ring.- H thng chiu sng hnh lang m bo ri t 20 40lux. i vi cc phng phc v nhu cu gii tr, phng a nng c thm yu cu chiu sng c bit th c trang b cc thit b chiu sng cp cao.- H thng dy in cung cp cho cc thit b tiu th in c chn ngm trong tng.- Cc bng in, cm, cng tc c b tr nhng ni thun tin, an ton cho ngi s dng, phng trnh tai nn in trong qu trnh s dng.- Ton cng trnh cn c b tr mt bung phn phi in v tr thun li cho vic t cp in ngoi vo v cp in cung cp cho cc thit b s dng in bn trong cng trnh. Bung phn phi ny c b tr tng k thut.- Trong bung phn phi, b tr cc t in phn phi ring cho tng khi ca cng trnh, nh vy d qun l, theo di s s dng in trong cng trnh.- Dng Aptomat khng ch v bo v cho tng ng dy, tng khu vc, tng phng s dng in. Gii php cp thot nc:Cp nc:- Ngun nc:Nc cung cp cho cng trnh c ly t ngun nc thnh ph.- Cp nc bn trong cng trnh:Theo qui m v tnh cht ca cng trnh, nhu cu s dng nc nh sau:+ Nc dng cho sinh hot.+ Nc dng cho phng chy, cu ho. m bo nhu cu s dng nc cho ton cng trnh, yu cu cn c b cha nc. Gii php cp nc bn trong cng trnh:S phn phi nc c thit k theo tnh cht v iu kin k thut ca nh cao tng, h thng cp nc c th phn vng tng ng cho cc khi. i vi h thng cp nc c thit k, tnh ton cc v tr t b cha nc, kt nc, trm bm trung chuyn cp nc y cho ton cng trnh.Thot nc bn:- Nc t b t hoi, nc thi sinh hot, c dn qua h thng ng ng thot nc cng vi nc ma vo h thng thot nc c sn ca khu vc.- H thng thot nc trn mi, yu cu m bo thot nc nhanh, khng b tc nghn.- Bn trong cng trnh, h thng thot nc bn c b tr qua tt c cc phng, l nhng ng nha ng c hp che chn chng va p.Vt liu chnh ca h thng cp thot nc:+ Cp nc:t mt trm bm nc tng k thut, mt trm bm c 2 3 my bm m bo cung cp nc thng xuyn cho cc phng, cc tng.Nhng ng cp nc, dng ng st trng km c D =(15- 50)mm, nu nhng ng c ng knh ln hn 50mm, dng ng PVC p lc cao.+ Thot nc: d dng thot nc bn, dng ng nha PVC c ng knh 110mm hoc ln hn, i vi nhng ng i di t dng ng b tng hoc ng snh chu p lc. Thit b v sinh tu theo iu kin m p dng cc trang thit b cho ph hp, c th s dng thit b ngoi hoc ni c cht lng tt, tnh nng cao. Gii php giao thng:- S dng h thng hnh lang phc v cho hot ng giao thng theo phng ngang.- Theo phng ng ta s dng h thng thang my. Bn cnh , phng trng hp mt in, vi lu lng ngi kh ln ta s dng 2 cu thang b, ng thi t cc h thng bo ng, cp cu i vi h thng thang my phng trng hp mt in xy ra. Gii php thng tin, tn hiu:- Cng trnh c lp t mt h thng tng i in thoi phc v thng tin, lin lc quc t v trong nc. Cp ng dy in thoi c dn ngm trong tng t phng tng i n tng phng trong cng trnh.- Mi phng s c trang b 1 ng dy truyn hnh cp phc vic thng tin gii tr ca ngi dn. ng tn hiu ny s c chn ngm trong tng.. Gii php chng st v ni t:- H thng chng st gm : kim thu li, h thng dy thu li, h thng dy dn bng thp, cc ni t ,tt c c thit k theo ng qui phm hin hnh.- Ton b trm bin th, t in, thit b dng in t c nh u phi c h thng ni t an ton, hnh thc tip t : dng thanh thp kt hp vi cc tip t. Gii php thng gi:- Cng trnh c m bo thng gi t nhin nh h thng hnh lang, ca s c kch thc, v tr hp l.- Cng trnh c h thng qut y, qut trn, iu tit nhit v kh hu m bo yu cu thng thong cho lm vic, ngh ngi.- Ti cc bung v sinh c h thng qut thng gi. Gii php phng chy cha chy:Gii php phng chy, cha chy phi tun theo tiu chun phng chy-cha chy cho nh cao tng ca Vit Nam hin hnh. H thng phng chycha chy phi c trang b cc thit b sau:- Hp ng ng mm v vi phun nc c b tr cc v tr thch hp ca tng tng.- My bm nc cha chy c t tng k thut.- B cha nc cha chy.- H thng chng chy t ng bng ho cht.- H thng bo chy gm : u bo khi, h thng bo ng.

PHN II

KT CU

(45%)

GING VIN HNG DN 1 : ON QUNH MAI GING VIN HNG DN 2 : NGUYN HNG CNGSINH VIN THC HIN : TRNG CNG MSSV : 0132018 LP : B18KX

Nhim v thit k:1. Tm hiu cc gii php kt cu chnh cho cng trnh v phm vi ng dng2. Phn tch v la chn gii php kt cu cho cng trnh, la chn s b tit din3. Lp phng n kt cu4. Tnh ton ti trng thng ng (Tnh ti v hot ti) sn5. Tnh ton ti trng gi, vng gi6. S tnh ton khung ngang7. Tnh ton thit k khung8. Tnh ton thit k sn9. Tnh ton thit k mng10. Lp bn v MB kt cu, MB mng, chi tit khung, chi tit thp sn, chi tit mng11. Lp thuyt minh tnh ton kt cu

Bn v km theo:KC 01: Bn v kt cu khung trc 5 tng hm v 1,2,3,4,5KC 02: Bn v kt cu khung trc 5 tng 6,7,8,9 v miKC 03: Bn v kt cu sn tng 3KC 04: Bn v kt cu mng khung trc 5

I. C S TNH TON Cc ti liu s dng trong tnh ton:- TCXDVN 356:2005. Kt cu b tng ct thp. Tiu chun thit k.- TCVN 2737-1995 Ti trng v tc ng. Tiu chun thit k. Cc ti liu tham kho:- Hng dn s dng chng trnh SAP 2000.- Sn sn BTCT ton khi ThS Nguyn Duy Bn, ThS Mai Trng Bnh, ThS Nguyn Trng Thng.-Kt cu btng ct thp ( phn cu kin c bn) Pgs.Ts Phan Quang Minh, Gs. Ts Ng Th Phong, Gs. Ts Nguyn nh Cng.- Kt cu btng ct thp (phn kt cu nh ca) Gs.Ts Ng Th Phong, Pgs. Ts L Trn Cng, Ts Trnh Thanh m, Pgs. Ts Nguyn L Ninh.- Khung btng ct thp ton khi Pgs.Ts L B Hu,ThS Phan Minh Tun

II. PHN TCH LA CHN GII PHP KT CU CNG TRNH2.1. Cc gii php v vt liu:Vt liu dng cho kt cu nh cao tng thng s dng l btng ct thp v thp (btng ct cng). Cng trnh bng thp:u im: C cng vt liu ln dn n kch thc tit din nh m vn m bo kh nng chu lc. Ngoi ra kt cu thp c tnh n hi cao, kh nng chu bin dng ln nn rt thch hp cho vic thit k cc cng trnh cao tng chu ti trng ngang ln.Nhc im: Vic m bo thi cng tt cc mi ni l rt kh khn, mt khc gi thnh cng trnh bng thp thng cao m chi ph cho vic bo qun cu kin khi cng trnh i vo s dng l rt tn km. c bit vi mi trng kh hu nhit i nng m gi ma ca Vit Nam, cng trnh bng thp km bn vi nhit , khi xy ra ho hon hoc chy n th cng trnh bng thp rt d chy do dn n sp do khng cn cng chng c cng trnh. Nn s dng thp cho cc kt cu cn khng gian s dng ln, chiu cao ln (nh siu cao tng H > 100m), nh nhp ln nh cc bo tng, sn vn ng, nh thi u, nh ht.v.v. Cng trnh bng b tng ct thp:u im: Khc phc c mt s nhc im ca kt cu thp nh thi cng n gin hn, vt liu r hn, bn vi mi trng v nhit . Ngoi ra nh s lm vic chung gia 2 loi vt liu ta c th tn dng c tnh chu nn tt ca b tng v chu ko tt ca ct thp.Nhc im: Kch thc cu kin ln, ti trng bn thn ca cng trnh tng nhanh theo chiu cao khin cho vic la chn cc gii php kt cu x l l phc tp. Nn s dng b tng ct thp cho cc cng trnh di 30 tng (H < 100m). La chn vt liu kt cu: T cc gii php vt liu trnh by chn vt liu b tng ct thp s dng cho ton cng trnh do cht lng bo m v c nhiu kinh nghim trong thi cng v thit k. Cc thng s k thut ca b tng theo tiu chun 356-2005.+Btng c khi lng ring 2500 daN/m3.+ Cp bn ca btng dng trong tnh ton cho cng trnh l B25. Cng v nn Rb = 14,5 MPa = 1450 T/m2 Cng v ko Rbt = 1,05 MPa = 105T/m2Mun n hi ca b tng: xc nh theo iu kin b tng nng, kh cng trong iu kin t nhin. Vi cp bn B25 th Eb = 2,9*106 T/m2.Thp lm ct thp cho cu kin btng ct thp dng loi thp si thng thng theo tiu chun TCVN 356 - 2005. Ct thp chu lc cho cc dm, ct dng nhm AII, ct thp ai, ct thp gi, ct thp cu to v thp dng cho bn sn dng nhm AI.Cng ca ct thp nh sau: Ct thp chu lc nhm AII: Rs = 280MPa. Ct thp cu to d 10 AII: Rs = 280MPa.d< 10 AI : Rs = 225MPa. M un n hi ca thp:Es=21*104MPaCc loi vt liu khc:- Gch c M75- Ct vng - Ct en - Sn che ph - Bi tum chng thm.Mi loi vt liu s dng u phi qua th nghim kim nh xc nh cng thc t cng nh cc ch tiu c l khc v sch.Khi t tiu chun thit k mi c a vo s dng.

2.2.Cc gii php v h kt cu chu lcc im ch yu ca nh cao tng l yu t ti trng ngang v trng lng bn thn ca nh.Chng nh hng trc tip n chuyn v, n nh ca nh.Cn c vo cc nhn t cng nng kin trc ca nh, ta c th c cc gii php kt cu cho nh nh sau:

H kt cu khung chu lc:Cu to: Bao gm cc dm ngang ni vi cc ct dc thng ng bng cc nt cng.

u im: Vic thit k tnh ton h kt cu thun khung c nghin cu nhiu, thi cng nhiu nn tch ly c lng ln kinh nghim. Cc cng ngh, vt liu li d kim, cht lng cng trnh v th s c nng cao.Nhc im: Chu ti trng ngang km, tnh lin tc ca khung cng ph thuc vo bn v cng ca cc lin kt nt khi chu un, cc lin kt ny khng c php c bin dng gc. Kh nng chu lc ca khung ph thuc rt nhiu vo kh nng chu lc ca tng dm v tng ct. H kt cu ny thch hp cho cc nh di 20 tng. H kt cu khung -tng:H kt cu khung -tng (Khung v vch cng ) c to ra bng s kt hp h thng khung v h thng vch cng.H thng vch cng thng c to ra ti khu vc cu thang b,cu thang my,khu v sinh hoc khu tng bin,l cc khu c tng lin tc nhiu tng.H thng khung c b tr ti nhng khu vc cn li ca ta nh.H thng khung v vch c lin kt vi nhau qua h kt cu sn.Trong trng hp ny h sn lin khi c ngha rt ln.Thng trong h kt cu ny vch thng ng vai tr chu ti trng ngang,h khung ch yu c thit k chu ti trng ng.S phn r chc nng ny to iu kin ti u ha cc cu kin,gim bt kch thc ct dm,p ng yu cu ca kin trc.

S khung tng chu lc

H kt cu li:Cu to:Li c dng v hp rng,tit din kn hoc h,nhn cc loi ti trng tc dng ln cng trnh v truyn chng xung nn t.Cc sn c bi h dm cng xn vn ra t li cng.

S kt cu li

u im:Kt cu li cng c kh nng chu lc ngang tt.Nhc im:Kh nng chu ti trng ng hn ch.Vi cc sn rng th cc dm cng xn vn ra sn phi c kch thc ln,nh hng n yu cu kin trc. H kt cu khung li:Cu to: L kt cu pht trin thm t kt cu khung di dng t hp gia kt cu khung v li cng. Li cng lm bng btng ct thp.Chng c th dng li kn hoc vch h thng b tr ti khu vc thang my v thang b.H thng khung b tr cc khu vc cn li.Hai h thng khung v li c lin kt vi nhau qua h thng sn.Trong trng hp ny h sn lin khi c ngha rt ln.

S kt cu khung li

u im: Thng trong h thng kt cu ny h thng li ng vai tr ch yu chu ti trng ngang, h khung ch yu chu ti trng ng. S phn chia r chc nng ny to iu kin ti u ho cc cu kin, gim bt kch thc ct dm, p ng yu cu kin trc.Trong thc t h kt cu khung-li t ra l h kt cu ti u cho nhiu loi cng trnh cao tng.Loi kt cu ny s dng hiu qu cho cc ngi nh n 40 tng. La chn h kt cu chu lc:Qua phn tch cc u nhc im ca nhng gii php a ra, cn c vo thit k kin trc, c im c th ca cng trnh, ta s dng h kt cu khung tng chu lc.H thng khung-tng bao gm cc hng ct bin, ct gia, dm chnh, dm ph, chu ti trng ng v li chu phn ln ti trng ngang.Vic thi cng cng n gin hn h kt cu li.

2.3. S lm vic ca cng trnh di tc dng ca ti trng ngang S ging:L s lm vic ca nh nhiu tng,m trong khung ch chu phn ti trng thng ng tng ng vi din tch truyn ti ca n,cn ton b ti trng ngang v mt phn ti trng thng ng do cc kt cu c bn khc chu(li,tng,hp...).Trong s ny tt c cc nt khung u c cu to khp hoc tt c cc ct u c cng chng un b v cng.

S khung ging:L s lm vic ca nh nhiu tng,m khi khung cng tham gia chu ti trng ng v ngang vi cc kt cu chu lc c bn khc.Trng hp ny khung c lin kt cng ti cc nt.

La chn s lm vic cho cng trnh:Ta chn s lm vic ca khung l s Khung- ging,h thng khung chu ti trng ng v ngang.Cng trnh thit k c chiu di 40,4m v chiu rng 19,2 m, cng theo phng dc nh ln hn rt nhiu theo phng ngang nh. Do khi tnh ton n gin v thin v an ton ta tch mt khung theo phng ngang nh tnh nh khung phng c bc ct l l= 4,5 m.

2.4. Cc gii php v kt cu snPhng n kt cu sn:Cng trnh ny c bc ct ln nht l 4,5m nn xut mt s phng n kt cu sn nh sau:+ Sn sn: -Sn sn c bn dm -Sn sn c bn k bn cnh -Sn dy sn (sn c)+ Sn khng dm(sn nm) Sn sn c bn dm:

Cu to: Sn sn c bn dm l sn gi ln dm,tng m t l cnh di v cnh ngn ca bn

u im:Chiu dy bn thng mng,tit kim vt liu, cng mt phng sn ln. L thuyn tnh ton v kinh nghim tnh ton kh hon thin, thi cng n gin, c s dng ph bin nc ta vi cng ngh thi cng phong ph nn thun tin cho vic la chn phng tin thi cng. Cht lng m bo do c nhiu kinh nghim thit k v thi cng trc y. Nhc im:Chiu cao kt cu thng ln v ph thuc chiu cao dm chnh,khng to c trn phng v cng tc vn khun phc tp.Chiu cao dm v vng ca bn sn rt ln khi vt khu ln, phi s dng h dm ph b tr nh l.Vi nhng cng trnh khng c h thng ct gia, dn n chiu cao thng thu mi tng thp hoc phi nng cao chiu cao tng khng c li cho kt cu khi chu ti trng ngang. Sn sn c bn k bn cnh:

Cu to:Sn sn c bn k bn cnh l sn gi ln dm,tng m t l cnh di v cnh ngn ca bn

u im:Nu khng b tr dm ph,vic lp t vn khun v to trn phng d dng v mt phng sn rng. L thuyn tnh ton v kinh nghim tnh ton kh hon thin, thi cng n gin, c s dng ph bin nc ta vi cng ngh thi cng phong ph nn thun tin cho vic la chn phng tin thi cng. Cht lng m bo do c nhiu kinh nghim thit k v thi cng trc y.Nhc im:Chiu cao dm v vng ca bn sn rt ln khi vt khu ln, phi s dng h dm ph b tr nh l. Vi nhng cng trnh khng c h thng ct gia, dn n chiu cao thng thu mi tng thp hoc phi nng cao chiu cao tng khng c li cho kt cu khi chu ti trng ngang Sn dy sn: Cu to: H kt cu sn bao gm h dm vung gc vi nhau theo hai phng, chia bn sn thnh cc bn k bn cnh c nhp b, theo yu cu cu to khong cch gia cc dm vo khong 3m. Cc dm chnh c th lm dng dm bt tit kim khng gian s dng trong phng. u im: Gim c s lng ct bn trong nn tit kim c khng gian s dng v c kin trc p, thch hp vi cc cng trnh yu cu thm m cao v khng gian s dng ln nh hi trng, cu lc b. Kh nng chu lc tt, thun tin cho b tr mt bng. Nhc im: Thi cng phc tp v gi thnh cao. Mt khc, khi mt bng sn qu rng vn cn phi b tr thm cc dm chnh. V vy, n cng khng trnh c nhng hn ch do chiu cao dm chnh phi ln gim vng. Vic kt hp s dng dm chnh dng dm bt gim chiu cao dm c th c thc hin nhng chi ph cng s tng cao v kch thc dm rt ln. Sn khng dm (sn nm): Cu to:L sn khng c dm,bn sn ta trc tip ln ct

u im:Dng sn nm s gim c chiu cao kt cu,vic lm vn khun n gin v d dng b tr ct thp.Sn nm c mt di phng nn vic chiu sng v thng gi tt hn sn c dm.Nu xy ra ha hon th vic thot nhit cng thun li.Ngoi ra vic ngn chia cc phng trn mt sn linh hot v rt thch hp vi cc bc tng di ng. Nhc im:Chiu dy sn ln s lm tng ti trng bn thn ca kt cu.Do nh hng n chuyn v ngang v n nh cng trnh. La chn phng n kt cu sn:c im ca cng trnh: Nhp ct 8,2 m v 2,8m, chiu cao tng 3,4m vi tng in hnh, ta chn phng n sn sn c bn dm v bn k bn cnh.Phng n ny c l thuyt tnh ton , kinh nghim tnh ton kh hon thin, thi cng n gin, c s dng ph bin nc ta vi cng ngh thi cng phong ph nn thun tin cho vic la chn phng tin thi cng. Cht lng m bo do c nhiu kinh nghim thit k v thi cng trc y.

2.5. Phng n thi cng sn Sn b tng ct thp lin khi:Sn ton khi l sn s dng bin php b tng lin khi vi dm.u im:Bo m lin kt ti cc v tr giao gia sn v dm.Hin nay c cng ngh thi cng hin i nn vic thi cng sn thun li. Nhc im:Vic tho lp cc ct chng,vn khun sn lm tng thi gian thi cng.Vic thi cng cn ph thuc vo thi tit thi tit. Sn lp ghp:Cu to: gm cc tm panel c sn c xp li vi nhau.u im:Thi gian thi cng rt ngn v khng cn n h thng dn gio,vn khun v c th thi cng lin tc,khng ngt qung.Nhc im:Nhc im ln nht ca sn lp ghp l thc hin lin kt ti cc mi ni kh khn.Khi sn phi chu lc ngang th cc v tr mi ni phi m bo cng . La chn phng n thi cng sn:Chn phng n thi cng sn ton khi. m bo lin kt gia sn v dm l lin kt cng, lm tng cng ca nh.

2.6. Trng thi ng sut sn Sn ng lc trc:Cu to: H kt cu sn trng thi ng lc trc gm c cc bn sn d LT lin kt cu khung.u im: Chiu cao kt cu nh nn gim c chiu cao cng trnh. Tit kim c khng gian s dng v d phn chia.Tin thi cng sn LT (6 - 7 ngy/1tng/1000m2 sn) nhanh hn so vi thi cng sn BTCT thng. Do c thit k in hnh khng c dm gia sn nn cng tc thi cng ghp vn khun cng d dng v thun tin t tng ny sang tng khc do vn khun c t hp thnh nhng mng ln, khng b chia ct, do lng tiu hao vt t gim ng k, nng sut lao ng c nng cao. Khi btng t cng nht nh, thp ng lc trc c ko cng v n s chu ton b ti trng bn thn ca kt cu m khng cn ch btng t cng 28 ngy. V vy thi gian tho d ct pha s c rt ngn, tng kh nng lun chuyn v to iu kin cho cng vic tip theo c tin hnh sm hn. Do sn phng nn b tr cc h thng k thut nh iu ho trung tm, cung cp nc, cu ho, thng tin lin lc c ci tin v em li hiu qu kinh t cao. Nhc im: Tnh ton tng i phc tp, m hnh tnh mang tnh quy c cao, i hi nhiu kinh nghim v phi thit k theo tiu chun nc ngoi. Thi cng phc tp i hi qu trnh gim st cht lng nghim ngt. Thit b v my mc thi cng chuyn dng, i hi th tay ngh cao. Gi c t v nhng bt n kh lng trc c trong qu trnh thit k, thi cng v s dng. B tng thng:L trng thi lm vic bnh thng ca sn,khng c ng sut trc.u im:L thuyt tnh ton kh hon thin,s dng ph bin rng ri nn c nhiu kinh nghim thi cng.Thit b thi cng sn c.Nhc im: vt nhp ln phi tng b dy sn,lm tng trng lng kt cu.So vi sn ULT th tin thi cng sn B Tng thng chm hn. La chn trng thi ng sut sn:Chn trng thi ng sut B tng thng.Do nhp ca sn khng ln, do c s dng rng ri nn c nhiu kinh nghim tnh ton v thi cng, my mc v thit b thi cng sn c trn th trng.

III. LA CHN S B CC CU KIN CHU LC3.1. Chn s b tit din dmCng thc chn s b : Trong : md = (1012) vi dm chnhmd= (1220) vi dm ph Dm chnh D1,D2, D3, , D4Nhp dm chnh l l1= 8,2 m.

h = ()l = ()*8200 = 1025683,33 mm Chn h = 700 mm.Chn b theo iu kin m bo s n nh ca kt cu:

b = =210350 mm, Chn b = 300m.Kch thc dm chnh theo nhp ln 8,2m l bxh =30x70cm. (D1)Kch thc dm theo nhp b 2,8m l bxh= 30x40cm. (D2)Kch thc dm chnh theo nhp 2200 ti cu thang l bxh= 30x40cm. (D3)Kch thc dm chnh theo nhp 6000 l bxh= 30x70cm. (D4) Dm ph D5 :

Nhp dm ph theo phng trc 1-10 l = 4,5m.

h = ()l = ()*4500 = 375225 mm Chn h = 400 mmChn b theo iu kin m bo s n nh ca kt cu: b = (0,30,5)h=(0,30,5)*400= 120-200mm Chn b = 3000mm Kch thc dm ph theo phng trc 1-9 l bxh = 30x40cm. (D5)Chn kch thc dm s n mi bxh = 22x30 cmKch thc dm bo s n mi bxh=15x30cm

3.2. Chn kch thc tng Tng bao:c xy chung quanh chu vi nh, do yu cu chng thm, chng m nn tng dy 22cm xy bng gch c M75. Tng c hai lp trt dy 2x1,5cm. Ngoi ra tng 22cm cng c xy lm tng ngn cch gia cc phng vi nhau. Tng ngn:Dng ngn chia khng gian gia cc khu trong mt phng vi nhau. Do ch lm nhim v ngn cch khng gian nn ta ch cn xy tng dy 11cm v c hai lp trt dy 2x1,5cm.

3.3. Chn s b tit din snChiu dy bn sn sn ton khi c thit k theo cng thc s b sau:

Trong : D: l h s ph thuc vo ti trng, ly D=1

vi bn k bn cnh lm vic 2 phng.

vi bn k bn cnh lm vic 1 phng.l: l nhp ca bn.- Vi sn S1: kch thc 6x4,5 m. L2/L1=1,33< 2. Nn tnh theo bn k 4 cnh lm vic theo 2 phng:

Chn hb=120mm vi sn S1

Bng thng k nhp,trng thi lm vic v chiu dy cc snTn snl1(m)l2(m)l2/l1Trng thi lm vicChiu dy sn(mm)

S1;S24,56,01,33Lm vic 2 phng120

S4;S52,24,52Lm vic 1 phng120

S7;S82,84,51,6Lm vic 2 phng120

S34,46,01,36Lm vic 2 phng120

S62,24,42Lm vic 1 phng120

S92,84,41,57Lm vic 2 phng120

3.4. Chn s b tit din ctTit din ca ct c chn theo nguyn l cu to kt cu btng ct thp, cu kin chu nn.

Din tch tit din ct c xc nh theo cng thc :N = n*q*S Vi q Ti trng tc dng ln ct. Ly theo kinh nghim tnh s b kch thc ct, q ly bng 1.2T/m2 snn: H s truyn ln ctk: H s k n nh hng ca mmen, ly t 1-1.5. y chn k=1Rb: Cng nn b tongT ta c cc bng tnh kch thc s b ca cc ct nh sau:

SVTH: TRNG CNG MSSV: 0132018 LP: B18KX249

3.5.Lp mt bng kt cu:

IV. THIT K KHUNG TRC 54.1. S cu to khung chu lc 4.2. S kt cu khung chu lcM hnh ha kt cu thnh cc thanh ng (ct) v cc thanh ngang (dm)vi trc ca h kt cu c tnh n trng tm tit din ca cc thanh. Nhp tnh ton ca dm:Nhp tnh ton ca dm ly bng khong cch gia cc trc ct- Xc nh nhp tnh ton ca dm AB v CD:

( y ly trc ct l trc ca cc ct tng 3-8) - Xc nh nhp tnh ton ca dm BC:

( y ly trc ct l trc ca cc ct tng 2-8)- Xc nh nhp tnh ton ca dm CC:

- Xc nh nhp tnh ton ca dm CD:

Chiu cao ca ct:Chiu cao ca ct ly bng khong cch gia cc trc dm.Do dm khung thay i tit din nn ta s xc nh chiu cao ca ct theo trc dm hnh lang(dm c tit din nh hn).-Xc nh chiu cao ca ct tng hm:

-Xc nh chiu cao ca ct tng 1:

- Xc nh chiu cao ca ct tng 2-8:

Ta c s kt cu c th hin nh hnh v:

4.3.Xc nh ti trng4.3.1.Ti trng n v

TNH TI MI Gm (daN/m2)

STTCu to cc lp vt liuH s vt tiKLR daN/m3Chiu dy (m)Ti trng tiu chun (daN/m2)Ti trng tnh ton (daN/m2)

1Hai lp gch l nem (200x200x20)1.118000.047279.2

2Lp va xi mng lt.1.318000.023646.8

32 lp gch thng tm nghing1.215000.2300360

4B tng chng thm B201.123000.05115126.5

5Sn BTCT ti ch B25 dy 12cm1.125000.12300330

6Trn thch cao1.311000.011114.3

Gm=956.8

TNH TI SN CC TNG V HNH LANG Gs (daN/m2)


1Lt granit (600x600)1.122000.00715.416.94

2Lp va xi mng lt1.318000.035470.2


4Trn thch cao1.311000.011114.3

Gs=431.44

TNH TI SN V SINH CC TNG Gvs (daN/m2)


1Lt granit (600x600)1.122000.00715.416.94

2Lp va xi mng lt1.318000.035470.2


4Lp va chng thm1.320000.024052

5Thit b v sinh1.15055

5Trn thch cao1.311000.011114.3

Gs=538.44

TNH TI TNG 110 Gt1 V 220 Gt2 (daN/m2)


1Khi xy gch1.118000.11198217.8

2Lp va trt 2 bn dy 15x21.318000.035470.2

Gt1=288

1Khi xy gch1.118000.22396435.6

2Lp va trt 2 bn dy 15x21.318000.035470.2

Gt2=505.8

TNH TI S N MI Gsn (daN/m2)


1B tng chng thm1.123000.05115126.5


3Va trt trn dy 15 mm1.318000.0152735.1

Gsn=491.6

TNH TI CU THANG Gth (daN/m2)


1Lt granit.1.123000.024650.6

2Lp va xi mng lt dy 20mm1.325000.023648.8

3Bc gch.1.118000.15270297

4Bn sn BTCT dy 12 cm1.125000.12300330

4Va trt trn dy 15 mm1.318000.0152735.1

Gth=761.5

TNH TI CHIU NGH CU THANG Gcn (daN/m2)

STTCu to cc lp vt liuH s vt tiKLR daN/m3Chiu dy (m)Ti trng Tc(daN/m2)Ti trng tt(daN/m2)

1Lt granit1.120000.012022

2Lp va xi mng lt dy 20 mm1.318000.023646.8

3Bn sn BTCT dy 10 cm1.125000.1250275

4Va trt dy 15 mm1.318000.0152735.1

Gcn = 378.9

s

HOT TI NG SN (daN/m2)

STTCu to cc lp vt liuH s vt tiTi trng tiu chun (daN/m2)Ti trng tnh ton (daN/m2)

1Hot ti mi khng s dng1.37597.5

2Hot ti trong phng1.2150180

2Hot ti hnh lang1.2300360

3Hot ti phng v sinh1.2200240

4Hot ti cu thang1.2300360

4.3.2. Tnh ti khung trc 5 tng in hnh

Tnh ti phn b (daN)1

2

3

4

5

6Do trng lng tng 220 xy trn dm cao: 3,4 0,7 = 2,7 gt1 = 505,8 x 2,7Do trng lng tng 220 xy trn dm thang my cao: 3,4-0,4=3; gt2 = 505,8 x 3Do trng lng sn hnh lang truyn vo di dng tam gic : gtg = 431,4 x (2,8-0,3)Do trng lng sn phng truyn vo di dng hnh thang 1: Ght1 = 431,4 x (4,5-0,3)Do trng lng sn phng truyn vo di dng hnh thang 2: Ght2 = 431,4 x (4,5-0,3)x0,5Do trng lng cu thang truyn vo di dng hcn: Ghcn = 672,4x[2,9-0,3]x0,5Cng v lm trn

1365,7

1517,4

1078,5

1811,9

905,9

874,1

7553,5

Tnh ti tp trung (daN)TTLoi ti trng v cch tnhKt qu

1

2

3

G1 Do trng lng sn phng truyn vo dm di dng tam gic: Gtg = 431,4 x [0,5x(4,5-0,3)x(4,5-0,3)x0,5]Do trng lng tng xy 220 trn dm dc cao 3,4 0,4 =3 m vi h s gim l ca 0,7. Gt = 505,8 x0,7x3x4,5Do trng lng bn thn dm dc 0,3x0,4: Gdd = 2500x1,1x0,3x0,4x4,5Cng v lm trn1902,5

4779,8

1485

8167,3

1

2

3

4

G2Do trng lng sn v sinh truyn vo di dng ch nht: Ght = 538,44x[(4,5-0,3)x(2,2-0,3/2-0,11/2)x0,5]Do trng lng sn trong phng truyn vo di dng tam gic: Gtg = 431,4x[0,5x(4,5-0,3)x(4,5-0,3)x0,5]Do trng lng bn thn dm dc 0,11x0,3: Gdd = 2500x1,1x0,11x0,3x4,5Do trng lng tng 110 xy trn dm dc cao 3,4-0,3=3,1 vi h s gim l ca 0,7 gt = 288 x 3,1x4,5x0,7

Cng v lm trn 2255,8

1902,5

408,4

2812,3

7379

1

2

3

4G3Do trng lng sn hnh lang truyn vo di dng hnh thang: Ght1 = 431,4x[(4,5-0,3)+(4,5-2,8)]x0,5x(2,8-0,3)x0,5Do trng lng sn v sinh truyn vo di dng hcn: Ght2 = 538,44x[(4,5-0,3)x(2,2-0,3/2-0,11/2)x0,5]Do trng lng bn thn dm dc 0,3x0,4: Gdd = 2500x1,1x0,3x0,4x4,5Do trng lng tng xy 220 trn dm dc cao 3,4 0,4 =3 m vi h s gim l ca 0,7. Gt = 505,8 x0,7x3x(4,5+4,4)x0,5Cng v lm trn1590,8

2255,8

1485

4726,7

10058,3

1

2

3

4G4Do trng lng sn hnh lang truyn vo di dng hnh thang: Ght1 = 431,4x[(4,5-0,3)+(4,5-2,8)]x0,5x(2,8-0,3)x0,5Do trng lng sn phng truyn vo di dng tam gic: Ght2 = 431,4x[0,5x(4,5-0,3)x(4,5-0,3)/2]x0,5Do trng lng bn thn dm dc 0,3x0,4: Gdd = 2500x1,1x0,3x0,4x4,5Do trng lng tng xy 220 trn dm dc cao 3,4 0,4 =3 m vi h s gim l ca 0,7. Gt = 505,8 x0,7x3x(4,5+4,4)x0,5Cng v lm trn1590,8

951,2

1485

4726,7

8753,7

1

2

3

4

5

G5Do trng lng chiu ngh cu thang truyn vo dm dc di dng hcn: Ghcn = 1/4x378,9x[(6-0,3)x(1,5-0,3)x0,5] Do trng lng cu thang truyn vo dm dc di dng hcn: Ghcn = 1/4x672,4x[(6-0,3)+(2,9-0,3)x0,5]Do trng lng bn thn dm dc 0,3x0,4: Gdd = 2500x1,1x0,3x0,4x(4,5+4,4)x0,5Do trng lng tng xy 220 trn dm dc cao 3,4 0,3 =3,1 m vi h s gim l ca 0,7. Gt = (505,8+288)x0,5x0,7x3,1x(4,5+4,4)x0,5Do trng lng bn thn dm chiu ngh 0,3x0,4 truyn vo dm dc: Gdd = 1/4x2500x1,1x0,3x0,4x6

Cng v lm trn324

1176,7

1468,5

3832,7

495

7296,9

1

2

3

4

5

6G6Do trng lng sn phng truyn vo di dng tam gic : Gtg = 431,4x[(4,5-0,3)x(4,5-0,3)/2x0,5]x0,5Do trng lng chiu ngh cu thang truyn vo dm dc di dng hcn: Ghcn = 1/4x378,9x[(6-0,3)x(1,5-0,3)x0,5]Do trng lng cu thang truyn vo dm dc di dng hcn : Ghcn = 1/4x672,4x[(6-0,3)+(2,9-0,3)x0,5]Do trng lng bn thn dm chiu ngh 0,3x0,4: Gdd = 1/4x2500x1,1x0,3x0,4x6Do trng lng bn thn dm dc 0,3x0,4: Gdd = 2500x1,1x0,3x0,4x(4,5+4,4)x0,5Do trng lng tng xy 220 trn dm dc cao 3,4 0,4 =3 m vi h s gim l ca 0,7 Gt = 505,8x0,7x3x(4,5+4,4)x0,5Cng v lm trn951,2

324

1176,7

495

1468,5

4726,7

8642,1

4.3.3. Tnh ti khung trc 5 tng 1,2,9

Tnh ti phn b (daN/m)TTLoi ti trng v cch tnhKt qu

1

2

3

4

5

Tng

Do ti trng sn phng truyn vo di dng hnh thang 1: Ght1 = 431,4 x (4,5-0,3)Do ti trng sn phng truyn vo di dng hnh thang 2: Ght2 = 431,4 x (4,5-0,3)x0,5Do ti trng sn hnh lang truyn vo di dng tam gic: Gtg2 = 431,4 x (2,8-0,3)Do trng lng tng 220 xy trn dm ca thang my cao 3,4-0,4=3m gt2 = 505,8 x 3Do trng lng bn thang truyn vo di dng hcn Ghcn = 672,4 x(2,9-0,3)/2

1811,9

905,9

1078,5

1517,4

874,1

6187,8


1

2

3

G1 Do trng lng sn truyn vo dm di dng tam gic: Gtg = 431,4 x [0,5x(4,5-0,3)x(4,5-0,3)x0,5]Do trng lng tng xy 220 trn dm dc cao 3,4 0,4 =3 m vi h s gim l ca 0,7. Gt = 505,8 x0,7x3x4,5Do trng lng bn thn dm dc 0,3x0,4: Gdd = 2500x1,1x0,3x0,4x4,5Cng v lm trn1902,5

4779,8

1485

8167,3

1

2

3

G2Do trng lng sn hnh lang truyn vo di dng hnh thang: Ght1 = 431,4x[(4,5-0,3)+(4,5-2,8)]x0,5x(2,8-0,3)x0,5Do trng lng sn trong phng truyn vo di dng tam gic: Gtg = 431,4x[0,5x(4,5-0,3)x(4,5-0,3)x0,5]Do trng lng bn thn dm dc 0,3x0,4: Gdd = 2500x1,1x0,3x0,4x4,5Cng v lm trn 1590.8

1902,5

1485

4978,3

1

2

3

4G3Do trng lng sn hnh lang truyn vo di dng hnh thang: Ght1 = 431,4x[(4,5-0,3)+(4,5-2,8)]x0,5x(2,8-0,3)x0,5Do trng lng sn phng truyn vo di dng tam gic: Ght2 = 431,4x[0,5x(4,5-0,3)x(4,5-0,3)x0,5]x0,5Do trng lng bn thn dm dc 0,3x0,4: Gdd = 2500x1,1x0,3x0,4x4,5Do trng lng tng xy 220 trn dm dc cao 3,4 0,4 =3 m vi h s gim l ca 0,7. Gt = 505,8 x0,7x3x(4,5+4,4)x0,5x0,5Cng v lm trn1590,8

752,8

1485

2363,4

6192

1

2

3

4G4Do trng lng chiu ngh cu thang truyn vo dm dc di dng hcn: Ghcn = 1/4x378,9x[(6-0,3)x(1,5-0,3)x0,5] Do trng lng cu thang truyn vo dm dc di dng hcn : Ghcn = 1/4x672,4x[(6-0,3)+(2,9-0,3)x0,5]Do trng lng bn thn dm dc 0,3x0,4: Gdd = 2500x1,1x0,3x0,4x4,5x0,5Do trng lng tng xy 220 trn dm thang my cao 3,4 0,4 =3 m vi h s gim l ca 0,7. Gt = 505,8 x0,7x3x4,4Cng v lm trn324

1176,7

742,5

4673,6

6916,8

1

2

3

4

5

6

G5Do trng lng sn phng truyn vo di dng tam gic: Gtg = 431,4x[(4,5-0,3)x(4,5-0,3)/2x0,5]x0,5Do trng lng chiu ngh cu thang truyn vo dm dc di dng hcn: Ghcn = 1/4x378,9x[(6-0,3)x(1,5-0,3)x0,5] Do trng lng cu thang truyn vo dm dc di dng hcn : Ghcn = 1/4x672,4x[(6-0,3)+(2,9-0,3)x0,5]Do trng lng bn thn dm chiu ngh 0,3x0,4: Gdd = 1/4x2500x1,1x0,3x0,4x6Do trng lng bn thn dm dc 0,3x0,4: Gdd = 2500x1,1x0,3x0,4x(4,5+4,4)x0,5Do trng lng tng xy 220 trn dm dc cao 3,4 0,4 =3 m vi h s gim l ca 0,7. Gt = 505,8x0,7x3x(4,5+4,4)x0,5Cng v lm trn951,2

324

1176,7

495

1468,5

4726,7

9142,1

4.3.4. Tnh ti khung trc 5 tng mi


1

2

3

4

5

Tng

Do ti trng sn phng truyn vo di dng hnh thang 1: Ght1 = 431,4 x (4,5-0,3)Do ti trng sn phng truyn vo di dng hnh thang 2: Ght2 = 431,4 x (4,5-0,3)x0,5Do ti trng sn hnh lang truyn vo di dng tam gic: Gtg2 = 431,4 x (2,8-0,3)Do trng lng tng 110 xy trn dm ca thang my cao 3,4-0,4=3m Gt2 = 288 x 3Do ti trng thang truyn vo di dng hcn: Ghcn = 672,4 x(2,9-0,3)/2

1811,9

905,9

1078,5

864

874,1

5534,4


1

2

3

Tng

G1Do ti trng s n truyn vo di dng hcn: Gtg=491,6x[(4,5-0,3)/2x(1,5-0,3/2-0,15/2)/2]Do ti trng bn thn tng thu hi 110 xy cao 1m: Gt = 288 x(4,5+4,4)/2x1Do trng lng bn thn dm bo s n 0,15x0,3: Gbsn = 2500x1,1x0,15x0,3x(4,5+4,4)/2

1316,3

1281,6

550,7

3148,6

1

2

3

G2Do ti trng sn truyn vo di dng tam gic : Gtg = 956,8 x [(4,5-0,3)x(4,5-0,3)/2]x0,5Do ti trng s n truyn vo di dng hnh ch nht: Ght = 491,6 x [(4,5-0,3)/2x(1,5-0.3/2-0.15/2)]Do trng lng bn thn dm dm dc 0,3x0,4: Gdd = 2500x1,1x0,3x0,4x4,5Cng v lm trn4219,5

1316,3

1485

7020,8

1

2

3G3Do ti trng sn hnh lang truyn vo di dng hnh thang Ght1 = 956,8 x [(4,5-0,3)+(4,5-2,8)]x0,5x(2,8-0,3)x0,5Do ti trng sn trong phng truyn vo di dng tam gic : Gtg = 956,8 x [(4,5-0,3)x(4,5-0,3)/2]x0,5Do trng lng bn thn dm dm dc 0,3x0,4 : Gdd = 2500x1,1x0,3x0,4x4,5Cng v lm trn3528,2

4219,5

1485

9232,7

1

2

3G4Do ti trng sn hnh lang truyn vo di dng hnh thang Ght1 = 956,8 x [(4,5-0,3)+(4,5-2,8)]x0,5x(2,8-0,3)x0,5Do ti trng sn trong phng truyn vo di dng tam gic : Gtg = 956,8 x [(4,5-0,3)x(4,5-0,3)/2]x0,5x0,5Do trng lng bn thn dm dm dc 0,3x0,4 : Gdd = 2500x1,1x0,3x0,4x4,5

Cng v lm trn3528,2

2109,8

1485

7123

1

2

3

G5Do trng lng bn thn dm dm dc 0,3x0,4: Gdd = 2500x1,1x0,3x0,4x4,4Do trng lng chiu ngh cu thang truyn vo dm dc di dng hcn: Ghcn = 1/4x378,9x[(6-0,3)x(1,5-0,3)x0,5] Do trng lng cu thang truyn vo dm dc di dng hcn: Ghcn = 1/4x672,4x[(6-0,3)+(2,9-0,3)x0,5]Cng v lm trn

1452

324

1176,7

2952,7

1

2

3

4

5G6Do ti trng sn phng truyn vo di dng tam gic: Gtg = 956,8 x [(4,5-0,3)x(4,5-0,3)/2]x0,5x0,5Do ti trng s n truyn vo di dng hcn : Ghcn=491,6x[(4,5-0,3)/2x(1,5-0,3/2-0,15/2)]Do trng lng bn thn dm dm dc 0,3x0,4 : Gdd = 2500x1,1x0,3x0,4x4,5Do trng lng chiu ngh cu thang truyn vo dm dc di dng hcn: Ghcn = 1/4x378,9x[(6-0,3)x(1,5-0,3)x0,5] Do trng lng cu thang truyn vo dm dc di dng hcn: Ghcn = 1/4x672,4x[(6-0,3)+(2,9-0,3)x0,5]Cng v lm trn2109,7

1316,3

1485

324

1176,7

6411,7

4.3.5. Tnh ti tng tum cu thang khung trc 5

Tnh ti phn b (daN/m)TTLoi ti trng v cch tnhKt qu

1

Do ti trng sn truyn vo di dng hnh thang: Ght = 956,8 x (4,4-0,3)x0,5 1961,4


1

2

G1Do ti trng sn truyn vo di dng tam gic: Gtg = 956,8 x [(4,4-0,3)x(4,4-0,3)/2]x0,5x0,5Do trng lng bn thn dm dm dc 0,3x0,4: Gdd = 2500x1,1x0,3x0,4x4,4Cng v lm trn2015,5

1452

3467,5

4.3.6. Hot ti 1 tng 3,5,7 khung trc 5

Hot ti phn b (daN/m)TTLoi ti trng v cch tnhKt qu

1

2

3Do ti trng sn truyn vo di dng hnh thang 1: Pht1 =180x(4,5-0,3)Do ti trng sn truyn vo di dng hnh thang 2: Pht2 =360x(4,5-0,3)x0,5Do ti trng thang truyn vo di dng hcn Phcn =360x(2,9-0,3)/2Tng756

756

468

1980

Hot ti tp trung (daN)TTLoi ti trng v cch tnhKt qu

1

P1Do ti trng sn phng truyn vo di dng tam gic: Ptg =180x[(4,5-0,3)x(4,5-0,3)x0,5]x0,5

793,8

1

2

P2Do ti trng sn phng truyn vo di dng tam gic : Ptg =180x[(4,5-0,3)x(4,5-0,3)x0,5]x0,5Do ti trng sn v sinh truyn vo di dng hcn: Phcn =240x[(4,5-0,3)x(2,2-0,3/2-0,11/2)]Cng v lm trn793,8

2011

2804,8

1

P3Do ti trng sn v sinh truyn vo di dng hcn: Phcn =240x[(4,5-0,3)x(2,2-0,3/2-0,11/2]2011

1P4Do ti trng sn truyn vo di dng tam gic: Phcn =360x[0,5x(4,5-0,3)x(4,5-0,3)/2]x0,5793,8

1

2

3

P5Do trng lng chiu ngh cu thang truyn vo dm dc di dng hcn: Ghcn = 1/4x360x[(6-0,3)x(1,5-0,3)x0,5] Do trng lng cu thang truyn vo dm dc di dng hcn: Ghcn = 1/4x360x[(6-0,3)+(2,9-0,3)x0,5]Tng307,8

630

937,8

1

2P6Do trng lng sn truyn vo di dng tam gic Ptg = 360x[(4,5-0,3)x(4,5-0,3)/2]x0,5x0,5Do trng lng chiu ngh cu thang truyn vo dm dc di dng hcn: Ghcn = 1/4x360x[(6-0,3)x(1,5-0,3)x0,5] Do trng lng cu thang truyn vo dm dc di dng hcn: Ghcn = 1/4x360x[(6-0,3)+(2,9-0,3)x0,5]Tng793,8

307,8

630

1731,6



1

PtgDo ti trng hnh lang truyn vo di dng tam gic: Ptg =360x(2,8-0,3)

900


1

P1Do ti trng hnh lang truyn vo di dng hnh thang : Pht =360x[(4,5-0,3)+(4,5-2,8)]x0,5x(2,8-0,3)x0,51327,5

4.3.8. Hot ti 1 tng 2 khung trc 5


1


900


1


4.3.9. Hot ti 1 tng 1,9 khung trc 5


1

2

3Do ti trng sn phng truyn vo di dng hnh thang1: Pht1 =180x(4,5-0,3)Do ti trng sn phng truyn vo di dng hnh thang2: Pht1 =360x(4,5-0,3)x0,5Do ti trng thang truyn vo di dng hcn Phcn =360x(2,9-0,3)/2Cng v lm trn756

756

468

1980


1

P1Do ti trng sn phng truyn vo di dng tam gic : Ptg1 =180x[(4,5-0,3)x(4,5-0,3)/2]x0,5793,8

1

P2Do ti trng sn phng truyn vo di dng tam gic : Ptg2 =180x[(4,5-0,3)x(4,5-0,3)/2]x0,5x0,5396,9

1

2

3


630

937,8

1


307,8

630

1731,6

4.3.10. Hot ti 1 tng mi khung trc 5


1

Do ti trng sn truyn vo di dng tam gic : Ptg =97,5x[(2,8-0,3)x(2,8-0,3)/2]x0,5

152.3


1

P1Do ti trng sn truyn vo di dng hnh thang: Ptg=97,5x[(4,5-0,3)+(4,5-2,8)]x(2,8-0,3)x0,5x0,5

341,3

4.3.11. Hot ti 1 tng tum cu thang khung trc 5


1

PhtDo ti trng sn mi truyn vo di dng hnh thang : Pht =97,5x(4,4-0,3)x0,5199,9


1

P1Do ti trng sn mi truyn vo di dng tam gic : Ptg =97,5x(4,4-0,3)x(4,4-0,3)x0,5x0,5x0,5204,9



1


900


1




1

2

3Do ti trng sn truyn vo di dng hnh thang 1: Pht1 =180x(4,5-0,3)Do ti trng sn truyn vo di dng hnh thang 2: Pht2 =360x(4,5-0,3)x0,5Do ti trng thang truyn vo di dng hcn Phcn =360x(2,9-0,3)/2Tng756

756

468

1980


1

P1Do ti trng sn phng truyn vo di dng tam gic: Ptg =180x[(4,5-0,3)x(4,5-0,3)x0,5]x0,5

793,8

1

2

P2Do ti trng sn phng truyn vo di dng tam gic : Ptg =180x[(4,5-0,3)x(4,5-0,3)x0,5]x0,5Do ti trng sn v sinh truyn vo di dng hcn: Phcn =240x[(4,5-0,3)x(2,2-0,3/2-0,11/2)]Cng v lm trn793,8

2011

2804,8

1

P3Do ti trng sn v sinh truyn vo di dng hcn: Phcn =240x[(4,5-0,3)x(2,2-0,3/2-0,11/2]2011

1P4Do ti trng sn truyn vo di dng tam gic: Phcn =360x[0,5x(4,5-0,3)x(4,5-0,3)/2]x0,5793,8

1

2

3


630

937,8

1


307,8

630

1731,6

4.3.14. Hot ti 2 tng 2 khung trc 5


1

2

3Do ti trng sn phng truyn vo di dng hnh thang1: Pht1 =180x(4,5-0,3)Do ti trng sn phng truyn vo di dng hnh thang2: Pht1 =360x(4,5-0,3)x0,5Do ti trng thang truyn vo di dng hcn Phcn =360x(2,9-0,3)/2Cng v lm trn756

756

468

1980


1

P1Do ti trng sn phng truyn vo di dng tam gic : Ptg1 =180x[(4,5-0,3)x(4,5-0,3)/2]x0,5793,8

1

P2Do ti trng sn phng truyn vo di dng tam gic : Ptg2 =180x[(4,5-0,3)x(4,5-0,3)/2]x0,5x0,5396,9

1

2

3


630

937,8

1


307,8

630

1731,6

4.3.15. Hot ti 2 tng 1,9 khung trc 5


1

PtgDo ti trng hnh lang truyn vo di dng tam gic : Ptg =360x(2,8-0,3)

900


1


4.3.16. Hot ti 2 tng mi khung trc 5


1

2

3Do ti trng sn truyn vo di dng hnh thang1: Pht1 =97,5x(4,5-0,3)Do ti trng sn truyn vo di dng hnh thang2: Pht1 =97,5x(4,5-0,3)x0,5Do ti trng thang truyn vo di dng hcn Phcn =360x(2,9-0,3)/2Cng v lm trn409,5

204,8

468

1082,3


P1Do ti trng s n truyn vo di dng hcn Ptg1 =97,5x[0,5x(4,5-0,22)x(1,5-0,3/2-0,15/2)]266

1

P2Do ti trng sn truyn vo di dng tam gic : Ptg1 =97,5x[(4,5-0,3)x(4,5-0,3)/2]x0,5Do ti trng s n truyn vo di dng hcn Ptg1 =97,5x[0,5x(4,5-0,22)x(1,5-0,3/2-0,15/2)]Tng430

266

696

1P3Do ti trng sn truyn vo di dng tam gic : Ptg2 =97,5x[(4,5-0,3)x(4,5-0,3)/2]x0,5430

1P4Do ti trng sn truyn vo di dng tam gic : Ptg2 =97,5x[(4,5-0,3)x(4,5-0,3)/2]x0,5x0,5215

1

2

3


630

937,8

1

2

3

4P6Do trng lng sn truyn vo di dng tam gic Ptg = 360x[(4,5-0,3)x(4,5-0,3)/2]x0,5x0,5Do trng lng chiu ngh cu thang truyn vo dm dc di dng hcn: Ghcn = 1/4x360x[(6-0,3)x(1,5-0,3)x0,5] Do trng lng cu thang truyn vo dm dc di dng hcn: Ghcn = 1/4x360x[(6-0,3)+(2,9-0,3)x0,5]Do ti trng s n truyn vo di dng hcn Ptg1 =97,5x[0,5x(4,5-0,22)x(1,5-0,3/2-0,15/2)]Tng793,8

307,8

630

266

1997,6

4.3.17. Ti trng ngang- Ti trng gi c xc nh theo tiu chun Vit Nam TCVN 2737-95. V cng trnh c chiu cao khng ln (H < 40 m), do cng trnh ch tnh ton n thnh phn gi tnhCng trnh c xy dng ti thnh ph Thanh Ha, thuc vng gi III.B, c plc gi n v: W0=125 daN/m2=1,25 KN/m2. Cng trnh c xy dng trong thnh ph c che chn mnh nn c a hnh dng B Cng trnh cao di 40 m nn ta ch xt n ti trng tnh ca gi Tng p lc gi vo cc khung ngang xc nh theo cng thc:

Ta c bng tnh ton ti trng gi:BNG TI TRNG GI TC DNG LN KHUNG TRC 5

TngHt (m)Z (m)Wo (daN/m2)nkCChB (m)P(daN)Ph(daN)

14.54.51251.20.860.80.64.5464.4348.3

23.47.91251.20.950.80.64.5513384.75

33.411.31251.21.020.80.64.5550.8413.1

43.414.71251.21.0750.80.64.5580.5435.38

53.418.11251.21.1110.80.64.5599.94449.96

63.421.51251.21.1440.80.64.5617.76463.32

73.424.91251.21.1750.80.64.5634.5475.88

83.428.31251.21.2050.80.64.5650.7488.03

93.431.71251.21.23020.80.64.5664.31498.23

mi2.534.21251.21.2450.80.64.5672.3504.23

BNG TI TRNG GI TC DNG LN KHUNG TRC 5

TngHt (m)Z (m)Wo (daN/m2)nkCChB (m)P(daN)Ph(daN)

14.54.51251.20.860.80.64.5464.4348.3

2,33.44.5-11.31251.21.020.80.64.5550.8413.1

4,53.411.3-18.11251.21.1110.80.64.5599.94449.96

6,73.418.1-24.91251.21.1750.80.64.5634.5475.88

8,93.424.9-31.71251.21.23020.80.64.5664.31498.23

mi2.534.21251.21.2450.80.64.5672.3504.23

Ti trng gi trn mi qui v lc tp trung u ct:+ Pha gi y: S=125*1,2*1,245*0,8*4,5*0,6 = 677,7 daN + Pha gi ht: Sh=125*1,2*1,245*0,6*4,5*0,6 = 508.3 daN

4.4. Tnh ton v b tr ct thp ct cho khung trc 54.4.1. Vt liu s dng- Cp bn ca b tng s dng l: B25Rb=14,5 MPa; Rbt=1,05 MPa- Ct thp dc nhm AIII c : Rs= Rsc= 365MPa

Tra bng ph lc ta c: - Ct thp ai nhm AI c : Rs=225MPa; Rsc= 175MPa

4.4.2. Tnh ton ct thp cho phn t ct C1: bxh=30x50cm S liu tnh ton:

+ Chiu di tnh ton: V nh l nh nhiu tng bng phng php ton khi nn chiu di tnh ton c ly theo cng thc = 248.5(cm)+ Chn lp b tng bo v dy: a=a= (0,080,12)h= (0.08 0,12)x50=46 cm Chn a=a=4cm

+ mnh

B qua nh hng ca un dc Chn + lch tm ngu nhin:

Bng ni lc c chn t bng t hp ni lc phn t 1Cp ni lcK hiu bng t hpc im ca cp ni lcM(KN.m)N(KN)

(cm)ea(cm)e0=max(e1,ea)(cm)

14,7

147,631767,558,351,678,35

24,5,6,8Nmax179,722718,006,611,676,61

34,8M,N ln190,472417,067,881,677,88

Tnh ton ct thp i xng cho cp 1:M= 147,63 KN.m= 1476300 daN.cmN=1767,55 KN= 176755 daN

+

+

Nn lch tm b.+ Xc nh li x theo cch sau bng phng php gii phng trnh bc 3:

Trong :

+ Din tch ct thp cn thit:

Tnh ton ct thp i xng cho cp2:M= 179,72 kN.m =1797200 daN.cmN=2718 kN = 271800 daN

+

+ S dng b tng cp bn B25, ct thp AII c

+


Trong :


=>chn 230+128 c A=20,295 cm2 Tnh ton ct thp i xng cho cp3:M= 190,47 kN.m =1904700 daN.cmN=2417,06 kN = 241706 daN

+

+ S dng b tng cp bn B25, ct thp AII c

+


Trong :


Chn 228+125 c A = 17,224cm2Nhn xt: m bo an ton chn 230+128 c A=20,295 cm2+ Chn v b tr ct thp hm lng ti thiu l:

4.4.3. Tnh ton ct thp ai cho ct C1: bxh=30x50cm+ ng knh ct ai:

Ta chn ct ai nhm AI+ Khong cch ct ai: s

S P=Vy sc chu ti ca cc l [P]=68 T5.5.3. Chn s lng cc v b tr i cc

Trong :N0 gi tr thit k tc dng ln mng cao trnh mt t. y ta ly ti mt mng:N0= 298,1 T

l h s nh hng ca m men v trng lng i. Chn =1,3[P]=77T sc chu ti ca cc

Vy cc Chn 6 cc.T kch thc cc v s lng cc ta b tr cc trong i nh hnh v vi nguyn tc: Khong cch gia cc cc trong i m bo iu kin (vi D l ng knh ca cc). y vi cc D=300mm Khong cch t mp ngoi cc bin n mp i gn nht sD/2=0.5x300=150mm. Chn s=250mm. Chiu cao i h =1,2 m. Lp btng lt di y i rng hn mp i 100mm.i cc b tr nh hnh v di y:Kch thc s b ca i chn : 1,5x2,5x1,2 m.

5.5.4. Ti trng phn phi ln cc Do chiu su chn i ln h=1,2m>hmin,nn t t y i tr ln tip nhn phn ti trng ngang,cc trong mng ch chu ti trng ti trng thng ng.Trng lng ca i cc 1,8x2,7x1,2m v t trn i:

G=Fhm=1,5*2,5*1,2*20=90 kN

Ti trng tc dng ln cc c xc nh nh sau:Ti trng trng vi t hp tiu chun ti y i:M=200 kNm; Q=10,33 kN; N=2592,2+90=2682,2 kNVy ti trng tc dng ln cc nh sau:

Pmax=497.03KN=49,7T; Pmin=397,03KN=39,7TTt c cc cc u chu nn.

5.5.5. Tnh ton kim tra cc Kim tra cc trong giai on thi cng:+) Khi vn chuyn cc:

Ti trng phn b:Trong : n l h s ng, n=1,5

.Chn a sao cho:

+) Trng hp treo cc ln gi ba:

Tr s mmen dng ln nht:

Ta thy: dng tnh ton.Ly lp bo v ca cc l a=2cm

Chiu cao lm vic ca ct thp:

Ct thp dc chu mmen un ca cc l c

Cc kh nng chu ti khi vn chuyn v cu lp. Tnh ton ct thp lm mc cu:

Lc ko mc cu trong trng hp cu lp cc:

Lc ko mt nhnh, gn ng:

Din tch ct thp ca mc cu:

Chn thp mc cu c Trong giai on s dng:

cc cc u chu nn

kim tra:

Trng lng tnh ton ca cc: (n=1,1 l h s vt ti)

Vy tt c cc cc u kh nng chu ti v b tr nh trn l hp l.

5.5.6. Tnh ton kim tra i cc

i cc lm vic nh bn conson cng, pha trn chu lc tc dng di ct ,pha di l phn lc u cc cn phi tnh ton hai kh nng Kim tra cng trn tit din nghing iu kin m thng:

i cc lm vic nh bn conson cng, pha trn chu lc tc dng di ct ,pha di l phn lc u cc cn phi tnh ton hai kh nng.Kim tra ct m thng i theo dng hnh thp:

Trong :

: lc m thng bng tng phn lc ca cc nm ngoi phm vi ca y thp m thng:

: lc chng m thng: (Tnh theo gio trnh BTCT II)

cc h s c xc nh nh sau:

: kch thc tit din ct

chiu cao lm vic ca i

Chiu cao i tha mn iu kin chng m thng.Kim tra kh nng hng cc chc thng i theo tit din nghing:

y

Tha mn iu kin chc thng.Kim tra kh nng cc gc chc thng i:

iu kin kim tra:

:Gi tr trung bnh s hc ca chu vi pha trn v pha di thp m thng

Tha mn iu kin khng chc thng.Kt lun: Chiu cao i tha mn iu kin chng m thng v chc thng theo tit din nghing.

Tnh ton cng trn tit din thng ng tnh ton ct thp i.Vi gi thit: i tuyt i cng, coi i lm vic nh bn conson ngm ti mp ct. Mmen ti mp ct theo mt ct I I :

Vi

Ct thp yu cu (ch t ct n):

Chn 1218a130 c As=30,54cm2

Mmen ti mp ct theo mt ct II II :

Vi

Chn 1516a180 c =30,165 cm2

5.5.7 Kim tra tng th mng ccGi thit coi mng cc l mng khi quy c Kim tra p lc di y khi mng:- iu kin kim tra:

- Xc nh khi mng quy c:

+ Chiu cao khi mng quy c tnh t mt t ln mi cc .+ Gc m: do lp t 1,2 v lp t 3 l nhng lp t yu, khi tnh b qua nh hng ca cc lp t ny.

+ Chiu di ca y khi mng quy c:

+ B rng khi mng quy c:

- Xc nh ti trng tiu chun di y khi mng quy c (mi cc):+ Trng lng ca t v i t y i tr ln

+ Trng lng khi t t mi cc ti y i:

+ Trng lng cc:

Ti trng ti mc y mng quy c:

- p lc ti y khi mng quy c:

- Cng tnh ton ca t y khi quy c (Theo cng thc ca Terzaghi):

Lp 5 c tra bng ta c:

(b qua cc h s hiu chnh).

Ta c:

Nh vy nn t di mi cc kh nng chu lc. Kim tra ln cho mng cc:ng sut bn thn di y khi mng quy c

(KN/m2)ng sut gy ln ti y khi mng quy c

509,61 -383,08=126,53 (KN/m2) ln ca mng cc c tnh gn ng nh sau:

Vi Lm/Bm=8/7=1,14

Kt lun:Vy cng trnh tho mn iu kin v ln.

5.6. Tnh ton mng cc M2 trc C, C5.6.1. Phn tch la chn phng n c im cng trnh:

- c im kt cu: Kt cu nh khung b tng ct thp, thi cng ton khi. Tit din ct .- Ti trng tnh ton ti chn ct ly theo kt qu bng t hp(4,5,6,8):Trc C: N=1741,25KN ; M=96,57KNmTrc C: N=2102,94KN; M=90,25KNm

Tn

Tn

T hp ti trng tiu chun:

n: l h s vt ti; gn ng n=1,11,2

chn n=1,15

Xc nh sc chu ti ca cc:a. Sc chu ti ca cc theo t nn-Xc nh theo kt qu ca th nghim trong phng:Sc chu ti ca cc theo nn t c xc nh theo cng thc :Pgh=Qc+Qs

Sc chu ti tnh ton: P=

Qs Ma st gia cc v t xung quanh cc

Qc Lc khng u mi cc Trong :

-H s iu kin lm vic ca t vi cc vung h bng phng php p nn F=0,3*0,3=0,09m2ui-Chu vi cc.ui=1,2mR-Sc khng gii hn t mi cc .Vi cc di 21m; mi cc t lp ct trung cht va su 25m tra bng c R=5200 KN/m2Lc ma st trung bnh ca lp t th i quanh mt cc.Ta tra c i (theo gi tr su trung bnh li ca mi lp v loi t ,trng thi t)

Pgh=Qc+Qs=1,2*(66,4+16+16+16+6,4+106,2+110,2+114,2+118,2+47,84+122.4+55.89)+ 5200*0,3*0,3=1422,9 kNSc chu ti ca cc theo t nn:

P=b.Xc nh theo kt qu ca th nghim xuyn tiu chun SPT:

P=Trong :+ QC =m*Nm*Fc : Sc cn ph hoi ca t u mi cc.Nm=40m: H s ph thuc loi t v loi cc tra bng c m=400kPa=400KN/m2 QC =400*40*0,09=1440 kN

+ Sc khng m st ca t thnh cc.n=2

=>

=> P=Vy sc chu ti ca cc l [P]=72 T

5.6.2. Thit k i ccV khong cch gia 2 ct C v C l b nn ta thit k i cc chung cho 2 ct.Tnh ton sc chu ti ca cc theo vt liu, theo t nn, theo phng php xuyn tiu chun SPT tnh trn. Chn s lng cc v b tr i cc:S cc trong mng c xc nh theo cng thc sau:

Trong :n- L s lng cc trong mngN- l tng lc ng tc dng ln cng trnh tnh n cao trnh y iP- l sc chu ti tnh ton ca mi cc

- l h s kinh nghim k n nh hng ca ti trng ngang v mmen ly t

ccChn 8 cc b tr nh hnh v:

T vic b tr cc nh trn:

Kch thc i:

Chn 5.6.3. Ti trng phn phi ln cc- Theo cc gi thit gn ng coi cc ch chu ti dc trc v cc ch nn hoc ko.+) Trng lng ca i v t ln i.

+) Ti trng tc dng ln cc c tnh theo cng thc:

+) Ti trng tnh vi t hp ti tiu chun ti y i l:

Vi:

+) Ti trng truyn ln cc khng k trng lng bn thn cc v lp t ph t y i tr ln tnh vi ti trng tnh ton:

Vi

Bng s liu ti trng cc u cc.

,

Tt c cc cc u chu nn.

5.6.4. Tnh ton kim tra cc Kim tra cc trong giai on thi cng:+) Khi vn chuyn cc:

Ti trng phn b:Trong : n l h s ng, n=1,5

.Chn a sao cho:

+) Trng hp treo cc ln gi ba:

Tr s mmen dng ln nht:

Ta thy: dng tnh ton.Ly lp bo v ca cc l a=2cm

Chiu cao lm vic ca ct thp:

Ct thp dc chu mmen un ca cc l c

Cc kh nng chu ti khi vn chuyn v cu lp.

Tnh ton ct thp lm mc cu:

Lc ko mc cu trong trng hp cu lp cc:

Lc ko mt nhnh, gn ng:

Din tch ct thp ca mc cu:

Chn thp mc cu c Trong giai on s dng:

cc cc u chu nn

kim tra:

Trng lng tnh ton ca cc: (n=1,1 l h s vt ti).

Vy tt c cc cc u kh nng chu ti v b tr nh trn l hp l.

5.6.5. Tnh ton kim tra i cc Tnh ton cng trn tit din thng ng tnh ton ct thp i:Vi gi thit: i tuyt i cng, coi i lm vic nh bn conson ngm ti mp ct. Mmen ti mp ct theo mt ct I I :

Vi:

Ct thp yu cu (ch t ct n):

Chn 1218a130 c As=38,175cm2

Mmen ti mp ct theo mt ct II II :

Vi

Chn 2016a160 c =40,22 cm2

5.6.6. Kim tra tng th mng ccGi thit coi mng cc l mng khi quy c Kim tra p lc di y khi mng:- iu kin kim tra:

- Xc nh khi mng quy c:

+ Chiu cao khi mng quy c tnh t mt t ln mi cc .+ Gc m: do lp t 1,2 v lp t 3 l nhng lp t yu, khi tnh b qua nh hng ca cc lp t ny.

+ Chiu di ca y khi mng quy c:

+ B rng khi mng quy c:

- Xc nh ti trng tiu chun di y khi mng quy c (mi cc):+ Trng lng ca t v i t y i tr ln

+ Trng lng khi t t mi cc ti y i:

+ Trng lng cc:

Ti trng ti mc y mng quy c:

- p lc ti y khi mng quy c:

- Cng tnh ton ca t y khi quy c (Theo cng thc ca Terzaghi):

Lp 5 c tra bng ta c:

(b qua cc h s hiu chnh).

Ta c:

Nh vy nn t di mi cc kh nng chu lc. Kim tra ln cho mng cc:ng sut bn thn di y khi mng quy c

(KN/m2)ng sut gy ln ti y khi mng quy c

559,64 -385,08=174,56 (KN/m2) ln ca mng cc c tnh gn ng nh sau:

Lm/Bm=9,1/7,1=1.28

Kt lun:Vy cng trnh tho mn iu kin v ln. Kim tra chnh ln gia hai mng cc:iu kin:

Kt lun:m bo s chnh lch ln gia cc mng.Mng cc thit k nh vy l hp l.

VI. THIT K CT THP SN TNG 3Phng php tnh :Cn c vo s hng dn ca ging vin hng dn n; sn c tnh theo s khp do.6.1. Vt liu s dng+ S dng B tng cp bn B25 c:

+ Ct thp AI c

6.2. Xc nh ni lc v b tr ct thp Sn phng S1 (hs=12cm): Ti trng tnh ton ca bn :+Tnh ti: xc nh phn ti trng gs= 431.44 dan/m2

+Hot ti: Tng ti trng tnh ton Ni lc tnh ton ca bn :Nhp tnh ton ca bn c xc nh nh sau:

T s kch thc gia 2 cnh bn: , Vy bn lm vic theo 2 phng v tnh theo bn k bn cnh

D kin b tr ct thp u theo mi phng. Ta c phng trnh:

Vi: : m men m gi theo phng L1 : m men m gi theo phng L2 M1: m men dng gia bn theo phng L1 M2: m men dng gia bn theo phng L2

1,340,31,50,8

Thay vo phng trnh ta c:

M1= 266 dan.mM2= 0,3xM1= 0,3x266 =79,8 (dan.m)MI=MI =1,5x266 =399 (dan.m)MII=MII=0,8x79,8 = 63,84(dan.m) Tnh ton v b tr ct thp: Tnh ton theo phng cnh di:

Thp chu moomen m:

Chiu cao lm vic:

: Chiu cao lm vic

: b dy bn

: chiu dy lp bo v b tng a= 1,5cm+Xc nh am theo cng thc :

Ta c:+Xc nh din tch ct thp cn thit theo cng thc :

V hm lng ct thp qu nh ta chn theo cu to c

Thp chu mmen dng :+Xc nh am theo cng thc :


V hm lng ct thp qu nh ta chn theo cu to c Tnh ton theo phng cnh ngn:

Thp chu moomen m:

Chiu cao lm vic:

: Chiu cao lm vic

: b dy bn



Chn thp c

Hm lng ct thp:

Thp chu moomen dng:

Chiu cao lm vic:

: Chiu cao lm vic

: b dy bn

: chiu dy lp bo v b tng a=1,5cm+Xc nh am theo cng thc :


Chn thp c

Hm lng ct thp:

Sn hnh lang S3=12cm: Ti trng tnh ton ca bn :+Tnh ti: xc nh phn ti trng gs= 431,44 dan/m2


T s kch thc gia 2 cnh bn: , Vy bn lm vic theo 2 phng v tnh theo bn k bn cnh:

D kin b tr ct thp u theo mi phng. Ta c phng trnh:

Vi: : m men m gi theo phng L1 : m men m gi theo phng L2M1: m men dng gia bn theo phng L1M2: m men dng gia bn theo phng L2

1,680,151,00, 3

Thay vo phng trnh ta c:

M1= 179 dan.m M2= 0,3xM1= 53,7 (dan.m)MI=MI =1,5xM1 = 268,5 (dan.m)MII=MII=0,8xM2= 43(dan.m) Tnh ton v b tr ct thp: Tnh ton theo phng cnh di:

Thp chu moomen m:

Chiu cao lm vic:

: Chiu cao lm vic

: b dy bn



V hm lng thp qu nh ta chn thp theo cu to c

Thp chu mmen dng :+Xc nh am theo cng thc :


V hm lng ct thp qu nh ta chn theo cu to c Tnh ton theo phng cnh ngn:

Thp chu moomen m:

Chiu cao lm vic:

: Chiu cao lm vic

: b dy bn



Chn thp c

Hm lng ct thp:

Thp chu moomen dng:

Chiu cao lm vic:

: Chiu cao lm vic

: b dy bn



V hm lng ct thp qu nh ln b tr theo cu to c

Sn v sinh S4, S5 (hs=12cm): Ti trng tnh ton ca bn :+Tnh ti: xc nh phn ti trng gs=431,44 dan/m2


T s kch thc gia 2 cnh bn: ,vy bn lm vic theo 1phng v tnh theo bn loi dm. Ct mt di bn rng b=1m vung gc vi dm ph v xem di bn lm vic nh mt dm lin tc.

M men un ti nhp v ti gi:

Mnh =

Mg =

Tnh ton v b tr ct thp:Ti nhp gia:

Chiu cao lm vic:

: Chiu cao lm vic

: b dy bn




Ti gi:

Chiu cao lm vic:

: Chiu cao lm vic

: b dy bn




PHN III

THI CNG

(45%)

GING VIN HNG DN 1 : ON QUNH MAIGING VIN HNG DN 2 : NGUYN HNG CNG SINH VIN THC HIN : TRNG CNG MSSV : 0132018 LP : B18KX

Ni dung thit k:I. Lp bin php thi cng phn thn: Thit k vn khun ct, dm, sn, cu thang b v thang my bng vn khun thp Lp bin php thi cng phn b tng s dng my bmII. Lp tin thi cng phn thn s dng Project (s ngang)III. Tng mt bng thi cng Thit k tng mt bng thi cng phn hon thin Lp bin php m bo an ton lao ng v v sinh mi trng

Bn v thit k:

TC 01: Thi cng phn thn TC 02: Thi cng dm, sn, cu thang b TC 02: Tin thi cng TC 04: Tng mt bng thi cng

I. C IM CNG TRNH V IU KIN THI CNG1.1. c im cng trnh Tn cng trnh v a im cng trnh:Tn cng trnh:Cng trnh l k tc x trng i hc Hng c.Quy m cng trnh:Cng trnh gm c 1 tng hm, 9 tng thn v 1 tng tum cu thang, vi chiu cao 34,2m tnh t mt t t nhin.a im cng trnh:a im xy dng cng trnh: Thanh HaCng trnh c mt bng thi cng kh thun li, nhng do cng trnh c xy dng trong thnh ph nn i hi phi c bin php thi cng thch hp, trnh nh hng ti kt cu cc cng trnh lin k, m bo tun th cc yu cu v an ton, v sinh, trnh nhim mi trng. H thng kt cu cng trnh:Kt cu phn thn:- Kt cu phn thn l h khung chu lc. Ton b h thng sn tng l sn sn btng ct thp ton khi, khng ng lc trc. Sn dy 12cm cho cc tng.1.2. iu kin thi cng H thng giao thng, in, nc:-Giao thng: C bn l thun li cho vic chuyn my mc, tp kt vt liu,Cng trnh nm trong vng quy hoch xy dng sn nn khng gp kh khn v giao thng v cc vn khc. Cc ngun cung cp vt liu nh btng, ct thp, vn khun, cc phng tin vn chuyn gn v d huy ng. Do lun m bo cung cp vt liu, thit b phc v thi cng ng tin .-in, nc:S dng mng li cung cp in v nc sch ca thnh ph do c s h tng c sn. Ngoi ra, m bo cho vic thi cng lin tc v c lp c th b sung thm mt trm pht in nu nh tnh ton thy cn thit. My mc, thit b, vt t:- Gi thit y l c th trang b y my mc, thit b, k thut tt nht theo yu cu ca thi cng nh cc my p cc, my o t, vn chuyn t, cn trc, my bm btngCc loi my mc y la chn ch yu da trn nhng yu cu v k thut m t ch n vn kinh t v iu kin kh nng cung cp my mc thit b ca mt cng trng hay doanh nghip trong iu kin thc t. Cc vn c lin quan khc:-An ninh- x hi: Cng trnh nm trong vng quy hoch sn c, nn vn an ninh-x hi l rt tt. Mt khc cn che chn cng trnh cch ly khng ngi khng c phn s i vo cng trng.-Thi tit, kh hu: Kh hu vng c 2 ma l ma ma v ma kh.Thi gian thi cng cng trnh vo ma kh.- Do cng trnh nm khu vc thnh ph, st vi khu dn c v cc trc ng giao thng nn ch trong qu trnh s dng cc phng tin thi cng gim thiu cc nhim v mi trng. - Qu trnh thi cng thng c kh nng gy ra cc tai nn cho ngi thi cng v vy cn c bit ch ti cc bin php an ton lao ng. Thun li:iu kin a cht tt, khng c nc ngm nn khng nh hng n iu kin thi cng phn ngm.Khu vc xy dng gn vi ng giao thng thun li cho vn chuyn nguyn vt liu v vic i li ca cn b v cng nhn thi cng trn cng trnh.in nc xem nh c p ng nh mng in nc thnh ph.Mt bng thi cng rng ri tng i bng phng.Th trng cung ng nguyn vt liu gn vi cng trnh xy dng p ng cc u cu cn thit, gi c hp l. Kh khn:Cng trnh nm vng ni thnh nn thi gian vn hnh chuyn tr nguyn vt liu ra vo cng trng b khng ch, cn tun th thi gian quy nh ca S giao thng cng chnh cng tc thi cng b tng din ra lin tc, khng b gin on, cn ch trng cc cng tc an ton lao ng khi b tng. Cng trnh trong khu quy hoch cm dn c nn cn m bo cng tc an ton v sinh, ting n trong qu trnh thi cng m bo gim thiu ti a c th c khng lm nh hng n sinh hot ca cc cng trnh k bn.

II. THIT K BIN PHP K THUT THI CNG PHN THN2.1 Thit k vn khun dm, sn, thang b2.1.1 La chn vn khun- Cc phng n vn khun c th xem xt la chn:+ Vn khun g thng: Khi lng nh, d dng tho lp, gi thnh r.S ln lun chuyn thp, kh kim sot cht lng vn khun do sn xut th cng, nhanh xung cp.Khng dng c khi cn vt nhp ln hoc cu kin c kch thc tit din ln, mt nhiu cng tho lpKh to b mt b tng nh .+ Vn khun g pKhi lng tng i nh, d dng tho lp do kch thc tm ln.Kim sot cht lng d dng do sn xut trong nh my, s ln lun chuyn ln hn cp pha g thng.To c b mt b tng nhn, chng mt nc va b tng tt. S dng ph hp vi cc kt cu sn c nhp ln hay ct, dm, li thang my c kch thc tit din ln.Gi thnh cao+ Vn khun thpD dng tho lp, t hp do c nhiu modul c ch to sn km theo cc chi tit kin kt.S ln lun chuyn ln hn hai loi cp pha trn, cht lng vn khun c m bo.Cng trnh l nh cao tng nn yu cu lun chuyn vn khun ln, s dng vn khun thp nh hnh l ph hp.=> So snh cc phng n trn ta la chn phng n vn khun thp nh hnh vi h gio chng tam gic cho dm, sn v h sn thp gia cng cho vn khun ct.c tnh k thut ca vn khun thp:

b(mm)l(mm)h(mm)J(cm4)W(cm3)

1006005515.684.08

1507505517.634.3

1508005517.634.3

1509005517.634.3

20010005520.024.42

20012005520.024.42

20013005520.024.42

20015005520.024.42

22012005521.024.57

25012005522.465.94

30015005528.466.55

30018005528.466.55

2.1.2 La chn cy chnga. Chn cy chng sn:S dng gio PAL do hng Ho Pht ch to. u im ca gio PAL:Gio PAL l mt chn chng vn nng bo m an ton v kinh t.- Gio PAL c th s dng thch hp cho mi cng trnh xy dng vi nhng kt cu nng t cao cao.- Gio PAL lm bng thp nh, n gin, thun tin cho vic lp dng, tho d, vn chuyn nn gim gi thnh cng trnh.Cu to gio PAL: Gio PAL c thit k trn c s mt h khung tam gic c lp dng theo kiu tam gic hoc t gic cng cc ph kin km theo nh:- Phn khung tam gic tiu chun. - Thanh ging cho v ging ngang.- Kch chn ct v u ct.- Khp ni khung.- Cht gi khp ni.

Trnh t lp dng:- t b kch (gm v kch), lin kt cc b kch vi nhau bng ging nm ngang v ging cho.- Lp khung tam gic vo tng b kch, iu chnh cc b phn cui ca khung tam gic tip xc vi ai c cnh. - Lp tip cc thanh ging nm ngang v ging cho.- Lng khp ni v lm cht chng bng cht gi. Sau , chng thm mt khung ph ln trn.- Lp cc kch pha trn.Ton b h thng ca gi khung tam gic sau khi lp dng xong c th iu chnh chiu cao nh h kch di trong khong t 0 n 750 mm.Trong khi lp dng chn chng gio PAL cn ch nhng im sau:+ Lp cc thanh ging ngang theo hai phng vung gc v chng chuyn v bng ging cho. Trong qu trnh dng lp khng c thay th cc b phn v ph kin ca gio bng cc vt khc.+ Ton b h chn chng phi c lin kt vng chc v iu chnh cao thp bng cc ai c cnh ca cc b kch.+ Phi iu chnh khp ni ng v tr lp c cht gi khp ni.b. Chn cy chng dm sn:S dng cy chng n bng kim loi do hng Ho Pht ch to. Cc thng s v kch thc c bn cy chng

2.1.3 Thit k vn khun cta. T hp vn khun:- Kch thc ct tng 3 in hnh c:+ Ct trc B: 30x50cm+ Chiu cao mi ct l: 3,4 0,6 = 2,8 m.S dng 4 tm 300x1500 + 8 tm 250x1500 v 8 thanh thp gc 1500 lm VK ct.+ Ct trc A, C, C, D: 30x40cmS dng 4 tm 300x1500 + 8 tm 200x1500 v 8 thanh thp gc 1500 lm VK ct.b. Tnh ton ti trng phn b ln chiu di vn khun:Theo tiu chun thi cng b tng ct thp TCVN 4453 - 95 th p lc ngang tc dng ln VK ct xc nh theo cng thc: - p lc ngang ti a ca va b tng ti:

q=n..H = 1,3.2500.0,75 = 2438 kG/mVi H= 1,5r = 1,5x50 = 75cm= 0,75m (r = 50 cm: bn knh hot ng ca m di).

- p lc do b tng: q=1,3.400 = 520 kG/m.

- p lc do m b tng: q=1,3.200 = 260 kG/m.c Ti trng phn b theo chiu di mt tm vn khun l:qtt = qt1 + qtt2 + qtt2 + qtt3= 2438+ 520 + 260 = 3218 (kG/m) Tng ti trng ngang tc dng vo tm vn khun theo (h=50cm)/1m di:qtt = 3218x0,5 = 1609 (kG/m)qc = (2500x0,75+400+200)x0,5 = 1237,5 (kG/m)

c. Tnh khong cch gia cc gng ct:Coi vn khun nh dm lin tc, gi ta l cc sn ng :Gi khong cch gia cc gng ct l L:(Gng gm 4 thanh thp L75x25x5 c J = 24,52cm4)- Theo iu kin bn ca tm vn khun:Ta c s tnh:M men trn nhp ca dm lin tc l:

iu kin bn ca vn khun:

Trong [] = 2100 (KG/m2) l cng ca vn khun kim loiW =6,55 cm3l m men khng un ca vn khun vi b = 30cm

S gng ct cn thit cho mi ct:

m bo iu kin chu lc v n nh chn 7 gng cho ct c tit din 30x50, khong cch gia cc gng l 60cm- Kim tra vng ca vn khun ct:- vng f c tnh theo cng thc:

Trong :M un n hi ca thp E = 2,1x106 (KG/cm2)M men qun tnh ca b rng vn J=28,46cm4- vng cho php: =>f=0,021cm60cm nn cc dm c thanh st chng phnh cho vn khun thnh dm.- Ct chng dm l nhng gio chng PAL c kch u v kch chn iu chnh cao kt hp vi cy chng n bng thp c ng trong v ng ngoi c th trt ln nhau thay i chiu cao ng.- Gia cy chng c ging lin kt.

a. Tnh vn khun y dm:Vn khun y dm s dng vn khun kim loi, dng cc tm (300x1500) c ta ln cc thanh g ngang ca h chng y dm ( ngang, dc, gio PAL ).Cu to vn y dm: C b=300 mm, l=6000-300=5700 mmTa chn v dng 4 tm 300x1200 v 1 tm 300x900

Ti trng tc dng ln vn khun y dm gm c:+Trng lng vn khun: q1tc = 20 kG/m q1tt = 1,1.20 = 22 kG/m +Trng lng b tng ct thp dm cao h = 60 cm :q2tc =.h.b =2500.0,6 = 1500 kG/mq2tt =n..h.b =1,3.2500.0,6 = 1950 kG/m+ Ti trng btng dm : q3 = n . bd . PdTrong :H s tin cy : n =1,3 Hot ti btng bng my : Pd = 400kG/m2q3tc = 400 kG/mq3tt = 1,3 . 400 = 520 kG/m+ Ti trng m nn :q4 = n . bd . qtcTrong :H s tin cy : n =1,3 p lc m nn tiu chun: qtc = 200kG/m2q4tc = 200 kG/mq4 tt= 1,3 . 200 = 260 kG/m+ Ti trng dng c thi cng: q5 = n . bd . qtcTrong :H s tin cy : n =1,3 Hot ti thi cng tiu chun: q5tc = 250kG/m2q5tt = 1,3 . 250 = 325 kG/m* Tng ti trng phn b tc dng ln vn y dm ;qtc = q1tc + q2tc + q3tc + q4tc + q5tc= 20 + 1500 +400 + 200 + 250 = 2370 kG/m qtt = q1tt + q2tt + q3tt + q4tt + q5tt= 22 + 1950 +520 + 260 + 325 = 3077 kG/m Ti trng tnh ton tc dng trn 1m di vn y dm l:q =1xqttxb= 3077x0,3 = 923,1 kG/m* Xc nh khong cch gia cc g:Coi vn khun y dm nh dm n gin k ln cc g. Gi khong cch gia cc g l lTa c s tnh:

Theo iu kin cng : Mmax=[M] =[].WTrong :+ Cng ca vn khun kim loi [] = 2100 (KG/cm2)+ M men khng un ca vn khun:Vi b = 30cm, l=120cm ta c W=6,55 (cm3)

* Kim tra vng ca vn khun y dmVi vn khun thp ta c: E = 21.105 kg/cm2; J=28,46 kg/cm2+ Theo iu kin bin dng: fmax [f]

Vy iu kin v cng v vng c tha mn, ta chn khong cch gia 2 x g l 90cm X g vn y dm chn g nhm V* B tr cho y dm b tr nh sau

b. Tnh vn khun thnh dm:Tit din dm khung nhp 6m: bxh = 300x700 mm* Cu to vn thnh: ht = 700 120 = 580 mm lt = 6000 300 = 5700 mmTa chn v dng 4 tm 300x1200 + 1 tm 300x900

* Ti trng tc dng ln vn thnh bao gm:- p lc ngang ca b tng:q1tc =2500x0,6=1500 KG/m2q1tt = n1xxh = 1,3x2500x0,6=1950 KG/m2- Ti trng do dm rung:q2tc = 200 KG/m2q2tt = n2x200 = 1,3x200=260 KG/m2- Ti trng do b tng:q3tc =400 KG/m2q3tt = n3x400 = 1,3x400=520 KG/m2* Tng ti trng phn b tc dng ln vn y dm ;qtc = q1tc + q2tc + q3tc + q4tc + q5tc= 20 + 1500 +400 + 200 + 250 = 2370 kG/m qtt = q1tt + q2tt + q3tt + q4tt + q5tt= 22 + 1950 +520 + 260 + 325 = 3077 kG/m Tng ti trng tc dng trn 1m di vn thnh dm:qtc =2370x0,3 = 711 KG/m qtt = 1x (1950+260+520)x0,3 = 819 KG/m

* Xc nh khong cch gia cc np ng:Coi vn khun thnh dm nh dm n gin k ln cc np ng.Gi khong cch gia cc np ng l l.Theo iu kin cng : Mmax=[M] =[].WTrong :+ Cng ca vn khun kim loi [] = 2100 (KG/cm2)+ M men khng un ca vn khun:Vi b = 30cm, l=120cm ta c W=6,55 (cm3)

* Kim tra vng ca vn khun y dmVi vn khun thp ta c: E = 21.105 kg/cm2; J=28,46 kg/cm2+ Theo iu kin bin dng: fmax [f]

Vy iu kin v cng v vng c tha mn, ta chn khong cch gia 2 x g l 90cm Np ng chn g nhm V.B tr np ng thnh dm:

* Xc nh tit din x g ngang:X g bng g nhm V c:g = 700 (KG/cm3); Eg = 1,1.105 (KG/cm3); g = 110 (KG/cm3)* Ti trng tc dng ln l lc tp trung nm gia nhp:Ti trng dng trn 1m di vn y dm l:qtc= 2370x0,3 = 711qtt = qttxb = 3077x0,3=923,1 KG/mTi trng tnh ton tc dng gia vi din chu ti 0,6mq = 923,1x1,0 = 923,1 KGCc x lm vic nh mt dm n gin vi nhp l khong cch gia hai u kch gio chng.Ta c s tnh

Theo iu kin cng : Mmax [M]

Gi s h = 1,4xb

=>h = 1,4x8,6 = 12,04 (cm)Chn tit din x g 10x14cm

Theo iu kin bin dng: fmax [f]

Vy tit din x g chn m bo tha mn c iu kin v cng v iu kin v bin dng.* Xc nh tit din x g dc:- Ti tp trung t ti gia thanh x g dc l:P = qttxl = 923,1x1,2= 923,1 (KG)Ta c s tnh

Nhp tnh ton 2 x g dc c khong cch l 1,2m (bng kch thc gio PAL)X g c xem nh mt dm lin tc:C M = 0,156xPxl = []xW

Mt khc:

Gi s h = 1,4xb

=>h = 1,4x7,4 = 10,4 (cm)Chn tit din x g 10x14cm


Vy tit din x g chn m bo tha mn c iu kin v cng v iu kin v bin dng.

* Cu to vn khun cc dm cn li:Tit din dm nhp 2,2m: bxh = 30x40cm+ Chiu cao vn thnh: ht = 400-120 = 280mmlt = 2200-300 = 1900mm Ta chn v dng 1 tm 300x1000 + tm 300x900+ Vn y dm c: b = 300mm, l = 1900mm Ta chn v dng 1 tm 300x1000 + tm 300x900

2.1.5. Thit k vn khun cho sna. Cu to vn khun sn in hnh: 4,5mx6ml01 = 6000-300/2 110/2 = 5795l02 = 4500-300 = 4200Ta chn v dng 23 tm 250x1500; 23 tm 250x1500; 23 tm 250x1200Theo phng cnh di: 23x250=5750mmTheo phng cnh ngn: 1500+1500+1200 =4200mm

b. Cu to vn khun cc sn cn li: sn nhp 2200: 2,2mx4,5ml01 = 2200-300/2 110/2 = 1995l02 = 4500-300 = 4200Theo phng cnh di: 23x250=5750mmTheo phng cnh ngn: 1500+1500+1200 =4200mmCn thiu c b bng vn g hoc tn c gia c cn thn.B tr vn sn:

c. Kim tra bn v vng ca vn khun snTi trng tc dng ln vn khun sn gm:+Trng lng vn khun: q1tc = 20 kG/m q1tt = 1,1.20 = 22 kG/m +Trng lng sn b tng ct thp dy 12cm :q2tc =2500.0,12 = 300 kG/m q2tt =1,3.2500.0,12 = 390 kG/m+ Ti trng do ngi v dng c thi cng: q3tc = 250 KG/ m2q3tt = 1,3x250 = 325KG/ m2+ Ti trng m rung :q4tc = 200 KG/ m2q4tt = 1,3x200 = 260 KG/ m2+ Ti trng do b tng: q5tc = 400 KG/ m2q5tt = 1,3x400 = 520 KG/ m2* Tng ti trng tnh ton tc dng trn 1m2 vn sn l: qtc = q1tc + q2tc + q3tc + q4tc + q5tc = 20 + 300+ 250 +200 + 400 = 1170 kG/ m2qtt = q1tt + q2tt + q3tt + q4tt + q5tt = 22 + 390+ 325 +260 + 520 = 1517 kG/ m2* Xc nh khong cch gia cc x g:Coi vn khun sn nh mt dm lin tc c gi ta l cc x g g:Ta chn trc khong cch gia cc x g ngang vn l 60cm+ Ct ra mt di bn rng b = 25cm tnhTa c s tnh:

Theo iu kin cng : Mmax=[M] =[].WTrong :+ Cng ca vn khun kim loi [] = 2100 (KG/cm2)+ M men khng un ca vn khun: W = 5,94 cm3Vi b = 30cm, l=120cm ta c W=6,55 (cm3)

Vy tha mn iu kin* Kim tra vng ca vn khun y dmVi vn khun thp ta c: E = 21.105 kg/cm2; J=22,46 kg/cm2+ Theo iu kin bin dng: fmax [f]

Vy iu kin v cng v vng c tha mn, khong cch gia 2 x g ngang l 60cm tha mn. X g vn y dm chn g nhm V* Kim tra x g ngang:Coi x g ngang l dm lin tc Theo iu kin cng : Mmax [].

Chn tit din x g 10x12m


Vy tit din x g chn m bo tha mn c iu kin v cng v iu kin v bin dng.* Xc nh tit din x g dc:X g bng g nhm V c:g = 700 (KG/cm3); Eg = 1,1.105 (KG/cm3); g = 110 (KG/cm3)t cch nhau 120cm theo phng dc nh, cc x g ngang.+ Ti trng tp trung t ti gia thanh x g dc l:P = qttxl = 1517x0,6 = 910,2 KG/mNhp tnh ton ca x dc l 1,2mGi s trng hp c mt x ngang t vo gia nhp x dc:Ta c s tnh

M = 0,156xPxl + Theo iu kin cng : Mmax [M] = []xW

Mt khc:




2.1.6. Thit k vn khun cu thang ba. Tnh ton cho bn thang:Gc nghing ca bn thang so vi phng ngang l: = 28oDng 8 tm 300x1800 + 1 tm 150x1800, 8 tm 300x800 + 1 tm 150x800

* Kim tra bn v vng ca vn khun bn thang:Ti trng tc dng ln vn sn gm:- Trng lng bn thn ca vn khun:q1tc = 20 (KG/m2)q1tt =1,1x 20 = 22 (KG/m2)- Trng lng sn BTCT dy 12cm:q2tc = 2500x0,12 = 300 (KG/m2)q2tt =1,3x 2500x0,12 = 390 (KG/m2)- Ti trng do ngi v dng c thi cng:q3tc = 250 (KG/m2)q3tt =1,3x 250 = 325 (KG/m2)- Ti trng m rung:q4tc = 150 (KG/m2)q4tt =1,3x 150 =195 (KG/m2)- Trng lng do b tng:q5tc = 400 (KG/m2)q5tt = 1,3x400 = 520 (KG/m2)- Ti trng tnh ton tng cng trn 1m2 theo phng vung gc vi bn thang:qtc = (20+300+250+150+400)xcos28o = 988,9 (KG/m2)qtt = (22+390+325+195+520)x cos28o = 1282 (KG/m2)* Xc nh khong cch gia cc x g:Coi vn khun bn thang nh mt dm n gin k ln cc x g g:+ Ti trng tnh ton trn 1m di vn khun bn thang l: 1282 (KG/m)

+ Tnh khong cch x g theo iu kin:

Trong :+ Cng ca vn khun kim loi [] = 2100 (KG/cm2)+ M men khng un ca vn khun: W=6,55 (cm3)

=> Theo phng ngang: l = 95,3xcos280 = 84,1 (cm)* B tr x g:Vy tha mn iu kin ta chn khong cch gia cc x g vn khun bn thang nh sau:Vi tm di 1,8m: l = 0,8mVi tm di 0,8m: l = 0,5m

=> Khong cch theo phng ngang ln lt l:l1: 0,8xcos280 = 0,7m; l1: 0,5xcos280 = 0,4mChn tit din x g vn khun bn thang 8x10cm* Kim tra theo iu kin cng : Mmax [M] = []xW

Vy iu kin cng c tha mn* Kim tra theo iu kin bin dng: fmax [f]

Vy iu kin bin dng c tha mn.* Xc nh khong cch gia cc ct chng: Chn s b khong cch ct chng l 800mm* Kim tra theo iu kin cng : Mmax [M] = []xW

Vy iu kin cng c tha mn* Kim tra theo iu kin bin dng: fmax [f]

Vy iu kin bin dng c tha mn.b. Tnh ton chiu ngh:Kch thc chiu ngh: 1,5x5,7m* T hp vn khun:Dng 19 tm vn khun thp c kch thc 300x1500

* Tnh ti trng: Tnh ton nh trn, phn bn thang- Ti trng tnh ton tng cng trn 1m2 theo phng vung gc vi bn chiu ngh:qtc = 20+300+250+150+400 = 1120 (KG/m2)qtt = 22+390+325+195+520 = 1452 (KG/m2)* Xc nh khong cch gia cc x g:Coi vn khun sn nh mt dm lin tc c gi ta l cc x g g:Ta chn trc khong cch gia cc x g ngang vn l 60cm+ Ct ra mt di bn rng b = 15cm tnhTa c s tnh:

Theo iu kin cng : Mmax=[M] =[].WTrong :+ Cng ca vn khun kim loi [] = 2100 (KG/cm2)+ M men khng un ca vn khun: W = 6,55 cm3

Vy tha mn iu kin* Kim tra vng ca vn khun y dmVi vn khun thp ta c: E = 21.105 kg/cm2; J=28,46 kg/cm2+ Theo iu kin bin dng: fmax [f]

Vy iu kin v cng v vng c tha mn, khong cch gia 2 x g ngang l 60cm tha mn. X g vn y dm chn g nhm V* Kim tra x g ngang:Coi x g ngang l dm lin tc Theo iu kin cng : Mmax [].



Vy tit din x g chn m bo tha mn c iu kin v cng v iu kin v bin dng.* Xc nh tit din x g dc:X g bng g nhm V c:g = 700 (KG/cm3); Eg = 1,1.105 (KG/cm3); g = 110 (KG/cm3)t cch nhau 120cm theo phng dc nh, cc x g ngang.+ Ti trng tp trung t ti gia thanh x g dc l:P = qttxl = 1452x0,6=871,2 KG/mNhp tnh ton ca x dc l 1,2mGi s trng hp c mt x ngang t vo gia nhp x dc:Ta c s tnh

M = 0,156xPxl + Theo iu kin cng : Mmax [M] = []xW

Mt khc:




2.2. Bin php thi cng b tng s dng my bm2.2.1 Cc yu cu k thut chunga. Yu cu i vi va b tng:- B tng s dng b tng thng phm c ch n cng trng bng cc xe chuyn dng. Khi nhn b tng phi c ngi c trch nhim c giao nhim v.- B tng c nhn ch khi m bo cc yu cu:+ C chng nhn ca n v chu trch nhim cung cp b tng.+ Cc giy t chng nhn: cp phi b tng, mac b tng( hoc cp bn), st b tng, thi gian xut xng, loi ph gia s dng, tn n v cung cp b tng+ Th ngim kim tra st ti cng trng t yu cu.b. Yu cu khi b tng:Vic b tng phi m bo: - Khng lm sai lch v tr ct thp, v tr cp pha v chiu dy lp bo v ct thp. - Khng dng m di dch chuyn ngang b tng trong cp pha.- B tng phi c lin tc cho n khi hon thnh mt kt cu no theo quy nh ca thit k. - trnh s phn tng,chiu cao ri t do ca hn hp b tng khi khng c vt qu 2.5 m.- Khi b tng c chiu cao ri t do ln hn 2.5 m phi dng mng nghing hoc ng vi voi.Khi b tng cn lu :- Gim st cht ch hin trng cp pha gio v ct thp trong qu trnh thi cng.- Mc dy b tng vo cp pha phi ph hp vi s liu tnh ton cng chu p lc ngang ca cp pha do hn hp b tng mi gy ra..- Chiu dy mi lp b tng phi cn c vo nng lc trn, c ly vn chuyn, kh nng m, tnh cht dnh kt v iu kin thi tit quyt nh, nhng phi theo quy phm.- b tng ct:cng trnh khng c ct hay tng chiu cao qu ln( 3 ngy.e. Mch ngng thi cng b tng :- Mch ngng thi cng phi t v tr m lc ct v mmen un tng i nh ng thi phi vung gc vi phng truyn lc nn vo kt cu.- Mch ngng thi cng nm ngang:dng thanh g hoc x g thp hoc vn khun to tng ngn b tng. Trc khi b tng phn khu tip theo cn lm nhm, lm m b mt b tng c bng nc xi mng sau phi m ln sao cho lp b tng mi bm chc vo b tng c m bo tnh lin khi ca kt cu.- Mch ngng thi cng ng: Mch ngng thi cng theo chiu ng hoc nghing cu to bng li thp vi mt li 5 10mm. Trc khi lp b tng mi cng cn ti nc lm m lp b tng c khi cn m k m bo tnh lin khi cho kt cu.- V tr mch ngng c m mt trnh mt nc b tng.

2.2.2. Lp bin php k thut thi cng phn b tng cta. Cng tc nh v tim ct.Cng tc ny do t trc c thc hin, yu cu truyn tim ct , vch v tr ghp vn khun cho tng ct, li bng mc trn mt sn lm c s cho cng nhn ghp vn khun.b. Thit k sn cng tc cho thi cng b tng ct:Sn cng tc c dng h thng gio Minh Khai trnh by trn lin kt thnh h . Bc cc tm sn thp ngang qua h lm sn cng tc phc v vic thi cng btng.c. Ct thp ct: Ct thp sau khi gia cng a vo lp dng.*Bin php lp dng:- Xc nh v tr trc v tim ct: m bo ct tng mi khng b sai lch khi thi cng sau khi b tng sn tng 1 xong ta tin hnh kim tra li tim ct bng my kinh v trn c s mc chun ban u. t my trn mt bng song song vi trc ngang nh ngm dc trc ct xc nh v tr trc ct theo 1 phng, sau chuyn my ti v tr dc nh ngm my vung gc vi phng xc nh trc, giao ca 2 tia ngm ny chnh l trc ct. Ch cn xc nh tim ct cho cc ct bin ca cng trnh t cc ct ny ta s xc nh c v tr ca cc tim ct khc . Sau khi xc nh xong tim ct ta phi nh du bng mc son theo c 2 phng ln mt sn.Gia cng lp dng ct thp ct: + Sau khi xc nh trc, tim ct ta tin hnh lp dng ct thp ct. Ct thp c gia cng, lm sch v ct un trong xng theo ng hnh dng, kch thc c thit k. Vi ct thp c 10 dng vam, ba nn thng gia cng xong ct thp c buc thnh tng b theo tng chng loi v kch thc. Ct thp c vn chuyn ln cao bng cn trc thp, ngi cng nhn ni cc thanh thp ny vi thp ch. Khi ni phi m bo ng yu cu theo quy phm. lp dng ct thp c thun tin ta buc chng thnh khung trc khi lp dng. Khi lp dng xong ta tin hnh buc cc con k bng b tng dy 2,5cm, khong cch gia cc con k = 40-50cm. Tin hnh iu chnh li khung thp bng dy di v dng cy chng xin n nh tm.+ V sinh ct thp.+ Kt thc cng tc ct thp cn thi sch vn b tng d do c nhm chn ct. * Nghim thu ct thp:Trc khi btng, phi tin hnh lp bin bn nghim thu ct thp. Bin bn nghim thu phi ghi r cc im sau y: Mc v ng knh ct thp; S lng v khong cch ct thp; V tr im t ca ct thp; Chiu dy lp btng bo v (cc vin k); Cc chi tit chn sn trong btng... Sau , tin hnh lp dng coffa ct.d. Coffa ct:- Gia cng lp dng vn khun ct:Sau khi lp t xong ct thp ct ta tin hnh lp dng vn khun ct. Vn khun ct c gia cng ti xng theo ng kch thc thit k v phi p ng c cc yu cu k thut. Vn khun sau khi c gia cng xong ta tin hnh vn chuyn ln cao bng cn trc thp. Vn khun ct c ng trc 3 mt trc khi cho vo v tr sau ng nt mt cn li. Trc khi lp t vn khun mt trong ca vn khun phi c qut du chng dnh. - Cu to coffa ct: S dng vn khun thp nh hnh c t hp. Ch cn 1 b hp vn khun l c th thi cng tt c cc ct trong 1 tng v ton cng trnh. - Cc yu cu k thut vi vn khun ct ni ring v vn khun ni chung trnh by trong phn yu cu k thut chung* Thi cng lp dng coffa ct:- Ct thp ct cng nh coffa ct c vn chuyn ln cao (cc tng trn ca cng trnh) bng cn trc thp. Sau khi lp dng ct thp ct ( c gia cng cng xng) vo v tr thit k, cn kim tra li tim ct ct theo hai phng ri mi lp dng coffa ct.- Dng cc tm vn khun c lin kt thnh mng vo v tr. C nh tm cc tm vn p vo thp ch. t cc thp gc.- Tin hnh lp dng gng ct theo thit k (khong cch cc gng l 80cm).- Sau khi tin hnh cn chnh v tr v tim ct, tin hnh gng, neo ct vo cc v tr thp ch chn sn trn sn (thi cng khi b tng sn) bng cc thanh chng v dy neo.- Kim tra thng ng,

Engineering

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