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2. Molecular Biology – 2.7 DNA replication, transcription, & translation Name: Understandings, Applications and Skills (This is what you maybe assessed on) Statement Guidance 2.7.U1 The replication of DNA is semi-conservative and depends on complementary base pairing. 2.7.U2 Helicase unwinds the double helix and separates the two strands by breaking hydrogen bonds. 2.7.U3 DNA polymerase links nucleotides together to form a new strand, using the pre- existing strand as a template. The different types of DNA polymerase do not need to be distinguished. 2.7.U4 Transcription is the synthesis of mRNA copied from the DNA base sequences by RNA polymerase. 2.7.U5 Translation is the synthesis of polypeptides on ribosomes. 2.7.U6 The amino acid sequence of polypeptides is determined by mRNA according to the genetic code. 2.7.U7 Codons of three bases on mRNA correspond to one amino acid in a polypeptide. 2.7.U8 Translation depends on complementary base pairing between codons on mRNA and anticodons on tRNA. 2.7.A1 Use of Taq DNA polymerase to produce multiple copies of DNA rapidly by the polymerase chain reaction (PCR). 2.7.A2 Production of human insulin in bacteria as an example of the universality of the genetic code allowing gene transfer between species. 2.7.S1 Use a table of the genetic code to deduce which codon(s) corresponds to which amino acid. 2.7.S2 Analysis of Meselson and Stahl’s results to obtain support for the theory of semi- conservative replication of DNA. 2.7.S3 Use a table of mRNA codons and their corresponding amino acids to deduce the sequence of amino acids coded by a short mRNA strand of known base sequence. http://bioknowledgy.weebly.com/ (Chris Paine)

BioKnowledgy DP Notes 2.7 DNA replication, transcription, and translation

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Page 1: BioKnowledgy DP Notes 2.7 DNA replication, transcription, and translation

2. Molecular Biology – 2.7 DNA replication, transcription, & translation

Name:

Understandings, Applications and Skills (This is what you maybe assessed on)

Statement Guidance

2.7.U1 The replication of DNA is semi-conservative and depends on complementary base pairing.

2.7.U2 Helicase unwinds the double helix and separates the two strands by breaking hydrogen bonds.

2.7.U3 DNA polymerase links nucleotides together to form a new strand, using the pre-existing strand as a template.

The different types of DNA polymerase do not need to be distinguished.

2.7.U4 Transcription is the synthesis of mRNA copied from the DNA base sequences by RNA polymerase.

2.7.U5 Translation is the synthesis of polypeptides on ribosomes.

2.7.U6 The amino acid sequence of polypeptides is determined by mRNA according to the genetic code.

2.7.U7 Codons of three bases on mRNA correspond to one amino acid in a polypeptide.

2.7.U8 Translation depends on complementary base pairing between codons on mRNA and anticodons on tRNA.

2.7.A1 Use of Taq DNA polymerase to produce multiple copies of DNA rapidly by the polymerase chain reaction (PCR).

2.7.A2 Production of human insulin in bacteria as an example of the universality of the genetic code allowing gene transfer between species.

2.7.S1 Use a table of the genetic code to deduce which codon(s) corresponds to which amino acid.

2.7.S2 Analysis of Meselson and Stahl’s results to obtain support for the theory of semi-conservative replication of DNA.

2.7.S3 Use a table of mRNA codons and their corresponding amino acids to deduce the sequence of amino acids coded by a short mRNA strand of known base sequence.

2.7.S4 Deducing the DNA base sequence for the mRNA strand.

Recommended resources:

http://bioknowledgy.weebly.com/27-dna-replication-transcription-and-translation.html

Allott, Andrew. Biology: Course Companion. S.l.: Oxford UP, 2014. Print.

http://bioknowledgy.weebly.com/ (Chris Paine)

Page 2: BioKnowledgy DP Notes 2.7 DNA replication, transcription, and translation

Review questions

1. State during which phase of the cell cycle DNA replication occurs.

2. State the function of DNA replication.

3. Which of the following is the end product of DNA replication in a human somatic cell?a. 23 chromosomesb. 46 chromosomesc. 23 pairs of chromosomesd. 23 pairs of sister chromatids

2.7.U2 Helicase unwinds the double helix and separates the two strands by breaking hydrogen bonds.

4. Outline the molecular structure of Helicase.

5. Label and annotate the diagram below to describe the function of helicase.

2.7.U3 DNA polymerase links nucleotides together to form a new strand, using the pre-existing strand as a template.

6. Outline the molecular structure of Helicase.

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Page 3: BioKnowledgy DP Notes 2.7 DNA replication, transcription, and translation

7. Label and annotate the diagram below to describe the function of DNA Polymerase.

2.7.U1 The replication of DNA is semi-conservative and depends on complementary base pairing.

8. Explain the importance of complementary base pairing in conserving the base-sequence during DNA Replication.

9. Explain why DNA replication of this kind of referred to as being semi-conservative.

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Page 4: BioKnowledgy DP Notes 2.7 DNA replication, transcription, and translation

2.7.A1 Use of Taq DNA polymerase to produce multiple copies of DNA rapidly by the polymerase chain reaction (PCR).

10. polymerase chain reaction (PCR) is a key technique in DNA manipulation and analysis.a. State the main uses of PCR.

b. State the name of the specialised apparatus needed to support this process.

c. Complete outline of the three keys steps in the process of PCR.

Denaturation:

Annealing:

Elongation:

d. If one cycle of PCR yields two identical copies of the DNA sequence. Calculate how many copies 20 cycles would yield.

2.7.S2 Analysis of Meselson and Stahl’s results to obtain support for the theory of semi-conservative replication of DNA.

The image to the right details the three possible methods of DNA replication.

Review your understanding of Meselson and Stahl’s experiments by using using the presentation, the McGraw and Hill animation (clear and accessible) or the Scitable article (Nature education) (more detailed).

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https:// upload.wikimedia.org /wikipedia/commons/a/a2/DNAreplicationModes.png

Page 5: BioKnowledgy DP Notes 2.7 DNA replication, transcription, and translation

11. At the start of a Meselson and Stahl experiment (generation 0) a single band of DNA with a density of 1.730 g cm-3 was found. After 4 generations two bands were found, but the main band had a density of 1.700 g cm-3.

a. Explain why the density of the main band changed over four generations. (2)

b. After one generation only one DNA band appeared, but the density had changed.i. Estimate the density of the band. (1)

ii. Which (if any) mechanisms of DNA replication are falsified by this result? (1)

iii. Explain why the identified mechanism(s) are falsified. (1)

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Page 6: BioKnowledgy DP Notes 2.7 DNA replication, transcription, and translation

c. Describe the results after two generations and which mechanisms and explain the identified mechanism(s) (if any) are falsified as a consequence. (3)

d. Describe and explain the result found by centrifuging a mixture of DNA from generation 0 and 2. (2)

Nature of Science: Obtaining evidence for scientific theories—Meselson and Stahl obtained evidence for the semi-conservative replication of DNA. (1.8)

12. Define the term theory as it is used in science.

13. If evidence does not exist to support a scientific idea then the idea cannot be described as being a theory. Without evidence outline the term used to describe a scientific idea.

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Page 7: BioKnowledgy DP Notes 2.7 DNA replication, transcription, and translation

Review questions

14. Transcription and translation is also known as protein synthesis, and is the expression of genes. The genetic code determines the amino acid sequence of a polypeptide, and the properties of the amino acids give the final structure and function of the protein. Other than membrane proteins, state four functions of proteins in the cell.

2.7.U4 Transcription is the synthesis of mRNA copied from the DNA base sequences by RNA polymerase.

15. Outline the process of transcription in the nucleus, including the roles of RNA polymerase, ribonucleoside triphosphates and complementary base pairing.

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Page 8: BioKnowledgy DP Notes 2.7 DNA replication, transcription, and translation

2.7.U5 Translation is the synthesis of polypeptides on ribosomes.

16. Complete the table to compare and contrast the processes of transcription and translation.

Transcription Translation

Begins with… mRNA

Ends with…

Location

Uses… RNA polymerase

17. Ribosomes are the cell components that carry out the process of translation. Outline the structure of the ribosome and explain how it is adapted to carry out translation.

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http:// www.hartnell.edu /tutorials/biology/ translation.html

Page 9: BioKnowledgy DP Notes 2.7 DNA replication, transcription, and translation

2.7.U6 The amino acid sequence of polypeptides is determined by mRNA according to the genetic code. 2.7.U7 Codons of three bases on mRNA correspond to one amino acid in a polypeptide.

18. Define mRNA in terms of it’s function

19. Suggest why the length of mRNA molecules varies.

20. Describe what is meant by the term ‘genetic code’.

21. Define the term codon.

22. Calculate the number of different codons combinations.

23. State the number of amino acids that can be translated by ribosomes.

24. Explain what is meant by the term degenerate. Refer to the last two questions in your answer.

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Page 10: BioKnowledgy DP Notes 2.7 DNA replication, transcription, and translation

2.7.U8 Translation depends on complementary base pairing between codons on mRNA and anticodons on tRNA.

25. State the molecule on which anti-codons, which are complementary to codons, can be found.

26. Complete the steps to outline the process of translation.

a. mRNA binds to the ________________ of the ribosome.

b. The mRNA contains a series of ___________________ each of which codes for an amino acid.

c. tRNA molecules contain ____________which are complementary to the ________ on the

_______.

d. tRNA molecules bind to a _____________________ that corresponds to the anticodon

e. The _____________ binds to the small subunit of the ribosome.

f. There are ____ binding sites on the ________________ of the ribosome, but only _____ can

contain tRNA molecules at a time

g. The _____________ moves along the mRNA and presents codons in the first two

________________.

h. ______ with anticodons ________________ to the codons bind (the bases are linked by the

formation of ________________ )

i. A ________________ is formed between the two amino acids (carried by the tRNAs)

j. As the ________________ moves along ______ a tRNA moves to the ______ binding site and

________________.

k. Another ______ carrying an amino acid binds to the ______ site and a second

________________ is formed.

l. The process (i.e. the last two steps) repeats forming a ________________.

Extension: sketch diagrams below to show translation and use the steps above as annotations.

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Page 11: BioKnowledgy DP Notes 2.7 DNA replication, transcription, and translation

2.7.S1 Use a table of the genetic code to deduce which codon(s) corresponds to which amino acid. 2.7.S3 Use a table of mRNA codons and their corresponding amino acids to deduce the sequence of amino acids coded by a short mRNA strand of known base sequence.2.7.S4 Deducing the DNA base sequence for the mRNA strand.

Use the genetic code table to help answer the questions below.

27. Deduce the codon(s) that

translate for Aspartate.

28. If mRNA contains the base sequence CUGACUAGGUCCGGAa. deduce the amino acid sequence of the polypeptide translated.

b. deduce the base sequence of the DNA antisense strand from which the mRNA was transcribed.

c. If mRNA contains the base sequence ACUAAC deduce the base sequence of the DNA sense strand.

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The genetic code – how mRNA codons translate to amino acids

http://www.ib.bioninja.com.au/_Media/genetic_code.jpeg

Page 12: BioKnowledgy DP Notes 2.7 DNA replication, transcription, and translation

29. Transcribe and translate this DNA sequence.

DNA T A C G G G C C C G T G A C A G C C A C T

mRNA

Amino acid

30. An mRNA strand has 76 codons. How many amino acids will be in the polypeptide?

31. A polypeptide contains 103 amino acids. What is the length of the gene (unit = base pairs)?

32. A gene is 105kbp (kilobase pairs). How many amino acids are in the polypeptide?

2.7.A2 Production of human insulin in bacteria as an example of the universality of the genetic code allowing gene transfer between species.

33. Diabetes in some individuals is due to destruction of cells in the pancreas that secrete the hormone insulin. It can be treated by injecting insulin into the blood. Despite the differences in the amino acid sequence between animal and human insulin, they all bind to the human insulin receptor and cause lowering of blood glucose concentration. However, some diabetics develop an allergy to animal insulins, so it is preferable to use human insulin. In 1982 human insulin became commercially available for the first time. It was produced using genetically modified E. coli bacteria. Since then methods of production have been developed using yeast cells and more recently safflower plants.

a. Describe what is meant by the term ‘universality of the genetic code’

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Page 13: BioKnowledgy DP Notes 2.7 DNA replication, transcription, and translation

b. Complete the table to outline the keys steps in the process of gene transfer.

Diagrams Notes

Citations:

Allott, Andrew. Biology: Course Companion. S.l.: Oxford UP, 2014. Print.

Taylor, Stephen. "Essential Biology 03.4 DNA Replication.docx." Web. 1 Oct. 2014. <http://www.slideshare.net/gurustip/essential-biology-34-dna-replication-core>.

Taylor, Stephen. "Essential Biology 03.5 DNA Transcription and Translation.docx." Web. 1 Oct. 2014. <http://www.slideshare.net/gurustip/essential-biology-35-transcription-translation-core>.

Taylor, Stephen. "4.4 Genetic Engineering and Biotechnology.pptx" Web. 1 Oct. 2014. <http://www.slideshare.net/gurustip/genetic-engineering-and-biotechnology-presentation>.

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